Who is the dictator of USSR

Answer:The answer is 1040

Answer:

Okay so Basically I looked at all the answers people are given and I narrowed it down. Its either 1040 or 1019

Step-by-step explanation:

The probability that the red die shows a three and the blue die shows a number greater than three is 1/12

From the question, we have the following parameters that can be used in our computation:

Red die

Blue die

The sample space of a die is

{1, 2, 3, 4, 5, 6}

using the above as a guide, we have the following:

P(3) = 1/6

P(Greater than 3) = 1/2

So, we have

P = 1/2 * 1/6

Evaluate

P = 1/12

Hence, the probability of a three and and a number greater than three is 1/12

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If p > 5 is prime and p is divided by 10, then the remainders are 1, 3, 7, or 9

The given information, we know that p is a prime number greater than 5, and that p is divided by 10. This means that p must end in either 0 or 5. since those are the only digits that allow for a number to be divisible by 10.

However, we also know that p is prime, which means it cannot be divisible by any number other than 1 and itself. This rules out the possibility of p ending in 0. since any number ending in 0 is divisible by 10 (and therefore not prime).

Therefore, p must end in 5. This means that p can be written in the form:

p = 10n + 5

where n is some integer. Now, let's consider what happens when we divide p by 10:

p/10 = (10n + 5)/10 = n + 0.5

Since p/10 is not an integer (it has a decimal component of 0.5), we know that p cannot be evenly divided by 10. Therefore, when p is divided by 10, there must be a remainder.

To determine what possible remainders there could be, we can look at the possible values for the last digit of p. Since p ends in 5, the last digit can only be 1, 3, 7, or 9 (since these are the only digits that, when multiplied by 5 and added to 10n, result in a number ending in 5).

Therefore, if p > 5 is prime and p is divided by 10, the remainder must be either 1, 3, 7, or 9.

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The correct statement about the function represented by the table is:

It is an exponential function because the factor between each x and y value is constant.

Option D is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

In this case, we can see that the ratio between each x and y value is constant.

Specifically, the ratio is 7 between x = 1 and x = 2, 3 between x = 2 and

x = 3, 3 between x = 3 and x = 4, and 3 between x = 4 and x = 5.

Therefore,

The function is exponential.

Additionally, we can observe that the function has the form y = ab^x, where a is the initial value and b is the common ratio.

To find the values of a and b, we can use the first two data points.

y = a x b^x

7 = a x b^1

21 = a x b^2

Dividing the second equation by the first equation.

21 / 7 = (a x b²) / (a x b^1)

3 = b

Substituting b = 3 into the first equation.

7 = a x 3^1

a = 7 / 3

So,

The function represented by the table is:

y = (7/3) x 3^x

which is an exponential function with an initial value of a = 7/3 and a common ratio of b = 3.

Thus,

It is an exponential function because the factor between each x and y value is constant.

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The derivative of \(r\) with respect to \(\theta\) can be found using the chain rule. Let's proceed with the differentiation:

\frac{dr}{d\theta} = \frac{d}{d\theta}\left(\cos\left(\frac{\theta}{3}\right)\right)

To differentiate \(\cos\left(\frac{\theta}{3}\right)\), we treat \(\frac{\theta}{3}\) as the inner function and differentiate it using the chain rule. The derivative of \(\cos(u)\) with respect to \(u\) is \(-\sin(u)\), and the derivative of \(\frac{\theta}{3}\) with respect to \(\theta\) is \(\frac{1}{3}\). Applying the chain rule, we have:

\frac{dr}{d\theta} = -\sin\left(\frac{\theta}{3}\right) \cdot \frac{1}{3}

Now, let's evaluate this derivative at \(\theta = \pi\):

\frac{dr}{d\theta} \bigg|_{\theta=\pi} = -\sin\left(\frac{\pi}{3}\right) \cdot \frac{1}{3}

The value of \(\sin\left(\frac{\pi}{3}\right)\) is \(\frac{\sqrt{3}}{2}\), so substituting this value, we have:

\frac{dr}{d\theta} \bigg|_{\theta=\pi} = -\frac{\sqrt{3}}{2} \cdot \frac{1}{3} = -\frac{\sqrt{3}}{6}

Therefore, the slope of the tangent line to the polar curve \(r = \cos(\theta / 3)\) at the point specified by \(\theta = \pi\) is \(-\frac{\sqrt{3}}{6}.

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The interval of convergence for the power series is -20 < x < 30. The interval of convergence is (-infinity, infinity).

To find the interval of convergence for the power series ∑n=2[infinity] n(x−5)^n/(5^2n), we can use the ratio test:

|[(n+1)(x-5)^(n+1)/(5^2(n+1))]/[n(x-5)^n/(5^2n)]| = |(n+1)(x-5)/(25)|

Taking the limit as n approaches infinity, we get:

lim |(n+1)(x-5)/(25)| = |x-5| lim (n+1)/25

Since lim (n+1)/25 = infinity, the series diverges if |x-5| > 25, and the series converges if |x-5| < 25. We need to test the endpoints of the interval to determine if they converge:

When x = 5 - 25 = -20, we have:

∑n=2[infinity] n(-20-5)^n/(5^2n) = ∑n=2[infinity] (-1)^n n(25/400)^n

Using the ratio test, we have:

lim |[(n+1)(25/400)^n+1]/[n(25/400)^n]| = lim |(n+1)/25| = 0

Therefore, the series converges when x = -20.

When x = 5 + 25 = 30, we have:

∑n=2[infinity] n(30-5)^n/(5^2n) = ∑n=2[infinity] n(25/625)^nUsing the ratio test, we have:

lim |[(n+1)(25/625)^n+1]/[n(25/625)^n]| = lim |(n+1)/25| = infinity

Therefore, the series diverges when x = 30.

Therefore, the interval of convergence for the power series is -20 < x < 30.

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Where the above conditions exist,

The random variable T = L + C represents the total time it takes Lorelei and Chance to finish a randomly selected 3-layer wedding cake. Since L and C are independent and Normally distributed, T is also Normally distributed with mean:

Mu_T = Mu_L + Mu_C = 37 + 52 = 89

and variance:

Var(T) = Var(L) + Var(C) = 12^2 + 7^2 = 193

So the standard deviation of T is:

Sigma_T = sqrt(Var(T)) = sqrt(193) = 13.89

The shape of T is also Normally distributed, since it is a sum of two independent Normally distributed variables.

To find the probability that Lorelei and Chance finish a randomly selected 3-layer wedding cake in under 90 minutes, we need to calculate the z-score for this value and then find the corresponding probability from the z-table. The z-score is:

z = (90 - 89) / 13.89

= 0.072

From the z-table, we find that the probability of a Z-score less than or equal to 0.072 is 0.5287.

Therefore, the probability that Lorelei and Chance totally finish a randomly selected 3-layer wedding cake in under 90 minutes is 0.5287 or approximately 53%.

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Step-by-step explanation:

51 is not a prime number because it is divisible by 1,3 and 17

and we know prime number are only those number who arenot divisible by any other number except 1

Answer:

57 is divisible by 1,3,19 and 57

Step-by-step explanation:

A prime number is a number that is divisible only by 1 and itself; and 57 is not among the numbers like 2,3,5,7,11 etc

Answer: That would odd.

Answer:

Two triangles are similar if they have:

Step-by-step explanation:

all their angles equal

corresponding sides are in the same ratio

But we don't need to know all three sides and all three angles ...two or three out of the six is usually enough.

There are three ways to find if two triangles are similar: AA, SAS and SSS:

Answer: 80

Step-by-step explanation:

If you look at the top left and bottom right corner, you see that they are identical, so basically you would do the same to 80.

Well lets see...

Solution 1. The sum of angles of a quadrilateral is 360˚ 100˚+100˚+80˚=280 degrees 360˚-280˚=80˚.

Solution 2. Opposite angles on a parallelogram are equal so x=80˚.

HOPE THIS HELPED!!!!!!!!!!

Answer:

20

Step-by-step explanation:

240 divided by 12 = 20

The bearing of the plane is approximately 178.037°. \(\blacksquare\)

Let suppose that bearing angles are in the following standard position, whose vector formula is:

\(\vec r = r\cdot (\sin \theta, \cos \theta)\) (1)

Where:

That is, the line of reference is the \(+y\) semiaxis.

The resulting vector (\(\vec v\)), in miles per hour, is the sum of airspeed of the airplane (\(\vec v_{A}\)), in miles per hour, and the speed of the wind (\(\vec v_{W}\)), in miles per hour, that is:

\(\vec v = \vec v_{A} + \vec v_{W}\) (2)

If we know that \(v_{A} = 239\,\frac{mi}{h}\), \(\theta_{A} = 180^{\circ}\), \(v_{W} = 10\,\frac{m}{s}\) and \(\theta_{W} = 53^{\circ}\), then the resulting vector is:

\(\vec v = 239 \cdot (\sin 180^{\circ}, \cos 180^{\circ}) + 10\cdot (\sin 53^{\circ}, \cos 53^{\circ})\)

\(\vec v = (7.986, -232.981) \,\left[\frac{mi}{h} \right]\)

Now we determine the bearing of the plane (\(\theta\)), in degrees, by the following trigonometric expression:

\(\theta = \tan^{-1}\left(\frac{v_{x}}{v_{y}} \right)\) (3)

\(\theta = \tan^{-1}\left(-\frac{7.986}{232.981} \right)\)

\(\theta \approx 178.037^{\circ}\)

The bearing of the plane is approximately 178.037°. \(\blacksquare\)

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Answer:

It $29.75

Step-by-step explanation:

Answer:

Orignal Price: $35

Discount Price: $29.75

Step-by-step explanation:

The original price is $35 since it says 15% off of $35. To get the discount price you would use the equation 35-15%, which would give you $29.75. Your new price is $29.75.

Hope this is what you were looking for. :D

Answer:

Luna wanna play among us with me (sorry I’m bored) the code is: PXQMKF

Step-by-step explanation:

Answer:

Purchase rate of the house is $480000.

Step-by-step explanation:

Let the purchase rate of the house = $p

Current value of the house = $648000

If the current rate of the house has increased by 35% of the purchase rate,

Current rate = Purchase rate +  35% of the purchase rate

648000 = p + (35% of p)

648000 = p + \(p\times \frac{35}{100}\)

648000 = p + 0.35p

648000 = (1.35)p

p = \(\frac{648000}{1.35}\)

p = $480000

Therefore, purchase rate of the house is $480000.

Answer:

8 days

Step-by-step explanation:

We are told in the question:

Carlos has 4/5 of a tank of fuel in his car. He uses 1/10 of a tank per day.

How many days will his fuel last?

1/10 of fuel = 1 day

4/5 of fuel = x

Cross Multiply

1/10 × x = 4/5 × 1

x = 4/5 / 1/10

x = 4/5 ÷ 1/10

x = 4/5 × 10/1

x = 8 days

His fuel lasts for 8 days

Answer:

His fuel will last 8 days

Step-by-step explanation:

i got it right on khan academy

The equation that represents the sentence "28 is the quotient of a number and 4" is 28 = n/4.

In the given sentence, "28 is the quotient of a number and 4," we can break down the sentence into mathematical terms. The term "quotient" refers to the result of division, and "a number" can be represented by the variable "n." The divisor is 4.

1) Define the variable.

Let's assign the variable "n" to represent "a number."

2) Write the equation.

Since the sentence states that "28 is the quotient of a number and 4," we can write this as an equation: 28 = n/4.

The equation 28 = n/4 represents the fact that the number 28 is the result of dividing "a number" (n) by 4. The left side of the equation represents 28, and the right side represents "a number" divided by 4.

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Answer:

y =(-3/2)x

Step-by-step explanation:

(0,0) ; (2 , -3)

Slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

         \(= \frac{-3-0}{2-0}\\\\= \frac{-3}{2}\)

Equation: y - y1 =m(x-x1)

y - 0 = \(\frac{-3}{2}(x- 0)\\\)

\(y = \frac{-3}{2}x\)

This sum is known as the harmonic series, and it grows approximately as the natural logarithm of c. Therefore, we can approximate E(X) as c * ln(c).

To find the expected number of days that elapse before you have a full set of objects, we can use the concept of the coupon collector's problem.

In the coupon collector's problem, imagine you are collecting coupons from a set of c different types. Each day, you buy a package and receive one coupon, which is equally likely to be any of the c types. The goal is to collect at least one coupon of each type.

Let's denote the random variable X as the number of days it takes to collect a full set of objects. To find the expected value E(X), we need to sum up the probabilities of each possible number of days.

On the first day, you have no coupons, so the probability of getting a new type of coupon is 1. The probability of getting a duplicate coupon is 0 since you have none yet. So, on the first day, the expected number of new types collected is c/c = 1.

On the second day, the probability of getting a new type of coupon is (c-1)/c since you already have one type. The probability of getting a duplicate coupon is 1/c since any of the c types is equally likely. So, on the second day, the expected number of new types collected is (c-1)/c + 1/c.

Similarly, on the third day, the expected number of new types collected is (c-2)/c + 2/c, and so on.

Generalizing this pattern, on the k-th day, the expected number of new types collected is (c-k+1)/c + (k-1)/c.

To find the expected number of days until a full set is collected, we sum up the expected number of new types collected each day until we reach c. Therefore, we have:

E(X) = 1 + (c-1)/c + 1/c + (c-2)/c + 2/c + ... + 1/c

Simplifying this expression, we get:

E(X) = c(1/c + 2/c + ... + 1/c) = c(1 + 1/2 + ... + 1/c)

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a. null hypothesis \(H_0\): PRmean=non-PRmean

b. the sample mean lies in the interval, so we fail to reject null hypothesis

c. critical value z(0.05)=1.96 is less than calculated z=3.56 so we fail to accept null hypothesis.

A null hypothesis states that there is no statistical significance to be discovered in the set of presented observations. The validity of a theory is assessed through hypothesis testing on sample data. Sometimes known as the "null," it is represented by the symbol  \(H_0\).

(a)

null hypothesis  \(H_0\): PRmean=non-PRmean

(b).

i. \((1-\alpha)\times 100\%\) confidence interval for sample

\(mean=mean \pm z(\frac{\alpha }{2} )*SE(mean)\)

95% confidence interval for sample PRmean=PRmean±z(.05/2)*SE(mean)=69.5±1.96*1.9

=69.5±3.724=(65.776,73.224)

95% confidence interval for sample non-PRmean=non-PRmean±z(.05/2)*SE(mean)=61.2±1.96*1.7

=69.5±3.332=(57.868, 64.532)

ii. null hypothesis not be rejected

iii. since the sample mean lies in the interval, so we fail to reject null hypothesis

(c).

i. mean difference=69.5-61.5=8

ii. SE(difference)=\(\sqrt{SE(PR)^2+SE(non-PR)^2}\)

\(=\sqrt{1.9\times 1.9+1.2\times 1.2}\)

=2.2472

iii. we use z-test and z=(mean difference)/SE(difference)=8/2.2472=3.56

iv. here level of significance alpha is not mentioned,

let \(\alpha\) =0.05

critical value z(0.05)=1.96 is less than calculated z=3.56 so we fail to accept null hypothesis.

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Answer:

4y

Step-by-step explanation:

A coefficient is a number with a variable and no sign in between them.

The numerical coefficient in the polynomial 4y+ 6 is 4.

A mathematical expression is a phrase that has a minimum of two numbers or variables and at least one mathematical operation. Let's examine the writing of phrases. The other number is x, and a number is 6 greater than half of it. In a mathematical expression, this proposition is denoted by the equation x/2 + 6.

A mathematical operation such as subtraction, addition, multiplication, or division is used to combine terms into an expression. In a mathematical expression, the following terms are used:

Given expression:

4y + 6

As, A coefficient is a number that is multiplied by a variable in an expression.

here the term that contain variable is 4y.

So, the coefficient is 4.

Hence, the numerical coefficient in the polynomial 4y+ 6 is 4.

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Answer:

the answer would be 43 degrees.

Step-by-step explanation:

The partial derivative diffusivity equation for spherical flow is ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t, and for hemispherical flow, it is the same equation.

1. The partial derivative diffusivity equation for spherical flow is derived from the spherical coordinate system and applies to radial flow in a spherical geometry. It can be expressed as ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t.

2. The partial derivative diffusivity equation for hemispherical flow is derived from the hemispherical coordinate system and applies to radial flow in a hemispherical geometry. It can be expressed as ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t.

1. For the derivation of the partial derivative diffusivity equation for spherical flow, we consider a spherical coordinate system with the radial direction (r), the azimuthal angle (θ), and the polar angle (φ). By assuming steady-state flow and neglecting the other coordinate directions, we focus on radial flow. Applying the Laplace operator (∇²) in spherical coordinates, we obtain ∇²p = (1/r²) (∂/∂r) (r² ∂p/∂r). Simplifying this expression, we arrive at ∂²p/∂r² + (1/r) ∂p/∂r.

2. Similarly, for the derivation of the partial derivative diffusivity equation for hemispherical flow, we consider a hemispherical coordinate system with the radial direction (r), the azimuthal angle (θ), and the elevation angle (ε). Again, assuming steady-state flow and neglecting the other coordinate directions, we focus on radial flow. Applying the Laplace operator (∇²) in hemispherical coordinates, we obtain ∇²p = (1/r²) (∂/∂r) (r² ∂p/∂r). Simplifying this expression, we arrive at ∂²p/∂r² + (1/r) ∂p/∂r.

In both cases, the term ϕμC/k ∂p/∂t represents the source or sink term, where ϕ is the porosity, μ is the fluid viscosity, C is the compressibility, k is the permeability, and ∂p/∂t is the change in pressure over time.

These equations are commonly used in fluid mechanics and petroleum engineering to describe radial flow behavior in spherical and hemispherical geometries, respectively.

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Answer:

g(x) = \(\frac{1}{3}(x - 1) = \frac{x}{3} - \frac{1}{3}\)

Step-by-step explanation:

f(x) = 3x + 5

f[g(x)] = 3[g(x)] + 5

⇒  3[g(x)] + 5 = x + 4

⇒  3[g(x)] = x + 4 - 5

⇒  3[g(x)] = x - 1

⇒  g(x) = \(\frac{1}{3}(x - 1) = \frac{x}{3} - \frac{1}{3}\)

The expression for the length of the sail is x = 7( tan 50° ).

According to the given question.

The sail of a boat is in the shape of a right triangle.

And, the sail of a boat is a right triangle with an acute angle at the tip equal to 50 degrees and the side of the sail which is the hypotenuse to the right triangle is 7 meters long.

Now, the side that measures 7 meters would be the adjacent because its right next to the angle and its not the hypotenuse because its not the largest side

And, the side which we do not know the length to will be the opposite side because it is opposite from where the angle is.  

So, we have the the measure of the adjacent side and the angle of the tip. And we have to find the expression for the length of the sail.

Let the length of the sail be x meters.

Now, in the given right angled triangle

We can say that

tan A = Opposite side/Adjacent side

⇒ tan 50° = x/7

⇒ x = 7( tan 50° )

Hence, the expression for the length of the sail is x = 7( tan 50° ).

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(A - 3I)v = | -2  2 | | v1 | = | 0 |
           | -5 -4 | | v2 |   | 0 |
Solving the system of equations, we obtain v1 = 1 and v2 = 1. The general solution of the given system of equations is: x(t) = C1 * e^(3t) * [1, 1]^T
where C1 is an arbitrary constant and T denotes the transpose operation.

(b) As a question-answering bot, I am unable to draw images. However, I can guide you on how to draw the direction field and sketch the trajectories. Plot the vector field F(x, y) = Ax, where A is the given matrix, and observe the behavior of the field. The eigenvector [1, 1] will provide the direction for the trajectories. Since the eigenvalue is positive, the trajectories will be moving away from the origin along the direction of the eigenvector.

(c) As t → ∞, the solutions of the system will grow exponentially in the direction of the eigenvector [1, 1]. Since the eigenvalue is positive (λ1 = 3), the trajectories will move away from the origin along the line y = x.

The given system of equations can be expressed as x' = Ax, where A is the coefficient matrix:
A =1 2
−5 −1
(a) The general solution of the system can be found by solving for the eigenvalues and eigenvectors of the matrix A. The eigenvalues of A can be found by solving the characteristic equation:
det (A - λI) = 0
⇒ det (1-λ 2-5  -1-λ) = 0
⇒ (1-λ)(-1-λ) - 2(-5) = 0
⇒ λ^2 + λ - 9 = 0
⇒ λ = (-1 ± sqrt(37)i)/2
Since the eigenvalues are complex, the general solution of the system can be expressed in terms of real-valued functions using Euler's formula:
x(t) = c1 e^(αt) cos(βt) v1 + c2 e^(αt) sin(βt) v2
where α = -1/2, β = sqrt(37)/2, v1 and v2 are the real and imaginary parts of the eigenvector corresponding to the eigenvalue (-1 + sqrt(37)i)/2, and c1 and c2 are arbitrary constants determined by the initial conditions.

(b) To draw a direction field, we can plot arrows on a grid that indicate the direction of the vector x' = Ax at various points in the xy-plane. The direction of the vector at each point (x,y) can be found by evaluating Ax at that point and plotting an arrow with a slope equal to the components of Ax. To sketch a few trajectories, we can use the general solution and choose different initial conditions to plot several curves in the xy-plane. The trajectories will follow the direction of the arrows in the direction field.

(c) As t → infinity, the behavior of the solutions depends on the eigenvalues of A. Since the real part of the eigenvalue with a larger magnitude is negative (-1/2), the solutions will approach the origin as t → infinity. The imaginary part of the eigenvalue will cause oscillations in the trajectories, which become more and more damped as t increases.

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