Who's a les bian here? Can we be friends?

Answer:

WY = 8

Step-by-step explanation:

We solve for above question using the Trigonometric function of Sine

sin θ = Opposite/Hypotenuse

Opposite = WY = x

Hypotenuse = 9

θ = 63°

Hence,

sin 63° = x/9

Cross Multiply

x = sin 63° × 9

x = 8.0190587177

Approximately x = 8

Therefore, WY = 8

The domain is the set with the first values of each pair, the range is the set with the second value of each pair.

A relation maps elements from a set, the domain, into another set, the range.

Such thar a relation is represented by pairs (a, b), where it means that the element a is being mapped into the element b. (So, a is in the domain, and b in the range)

In this case, our relation is represented by:

{(-3, 2), (-2, 1), (-1,0), (0, -1)}

The domain is the set with the first values of each pair, the range is the set with the second value of each pair.

So the correct option is A.

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For the first system of equations, we can use Gaussian elimination to solve for the variables:

-2y - z = -2x - 2

5y + 2z = -9

2y + 3z = x

We can then use the determinant of the matrix of coefficients to determine if the system has a unique solution. Since the determinant is -3, which is nonzero, the system has a unique solution.

We can then use back-substitution to solve for the variables, starting with the last equation:

2y + 3z = x

Substituting this into the second equation gives:

5y + 2z = -9

Solving for y gives:

y = - (2/5)z - (9/5)

Substituting this into the first equation gives:

-2y - z = -2x - 2

Substituting for y gives:

-2(-(2/5)z - (9/5)) - z = -2x - 2

Simplifying gives:

(4/5)z + 2 - z = -2x - 2

Solving for z gives:

z = -3

Substituting this into the equation for y gives:

y = - (2/5)(-3) - (9/5) = -5/3

Therefore, the value of y in the solution set is y = -5/3.

For the second system of equations, we can again use Gaussian elimination to solve for the variables:

8x - 2y + z = 1

2x - y + 6z = 3

6x + y + 4z = 3

Adding the first and second equations gives:

10x - 3y + 7z = 4

Adding the first and third equations gives:

14x - y + 5z = 4

Subtracting the second equation from this gives:

12x + 5z = 1

Substituting this into the third equation gives:

6(-1/6) + y + 4z = 3

Simplifying gives:

y + 4z = 4

Substituting for z gives:

y + 4(-1/12) = 4

Simplifying gives:

y = 17/3

Therefore, there is no value of z in the solution set that satisfies the system of equations. The correct answer is none of the above.

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Answer:

Triangle WRD's angles are all 60 degrees, angle W and angle R and angle D.

Triangle WRD is an equiangular, equilateral triangle. It is also an acute triangle, as all angles are less than 90 degrees.

Step-by-step explanation:

You are told that WRD has all equal sides, each 3 inches long.

In a triangle, if sides are equal, then the opposite angles are also equal. So if ALL the sides are equal, then ALL the angles are equal.

The sum of the interior angles in a triangle is always 180 degrees. Since the trhee angles are all equal and they must add up to 180 degrees, 180/3 =60, so the angles must all be 60 degrees.

Triangle are classified by sides as

*** scalene = no equal sides

*** isosceles = two equal sides

*** equilateral = all equal sides

Triangles are classified by angles as

*** right triangle = one 90 degree angle

*** obtuse triangle = one angle larger than 90 degrees

*** acute triangle  = all angles less than 90 degrees

*** equiangular = all angles equal

There can be overlap in the categories, like an acute triangle also being equiangular.

The equation which may be used to find the cost of 3.5 pounds of grapes according to the price per pound of grape given in the task content is; Cost = 3.5 × $1.55.

It follows from the task content that the given relationship is that; 1 pound of grapes cause $1.55.

Hence, it follows from the concept of ratios and proportions that the cost of 3.5 pounds of grapes can be evaluated as follows;

Cost = 3.5 × $1.55

Ultimately, the equation which describes the cost is; Cost = 3.5 × $1.55.

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Answer:

? = 5

Step-by-step explanation:

You use cross-multiplying. Let's say ? is x.

First step:  \(\frac{30}{x}=\frac{48}{8}\)

Second step: You cross them so 30(8)= 280. 48(x)= 48x.

Third step: \(\frac{280}{48x}\)= 5

To double check this:

30/5= 6

48/8= 6

42/7= 6

I hope this helps.

I did this while struggling with my homework too lol.

Answer:

x = 6

x = -  3/2

Answer:

The Anwser Is 390 Because Add It All Up And You Got The Anwser

Answer:

390

Step-by-step explanation:

130 and then twice as much pasta, 130+130=260

Then add the vegetables: 130+260=390

390 is the total mass in grams

Here, to find the minimum radius of convergence R of power series solutions about the ordinary point x = 0 and x = 1, for the differential equation (x^2 - 2x + 10)y" + xy' - 4y = 0, we can use the formula R = 1/limsup |an|^1/n.

Step:1 At x = 0, the power series solution is y = c_0 + c_1x + c_2x^2 + c_3x^3 + ... + c_nx^n + ... , and the coefficients an are given by c_n = (-1)^(n-1)*(n-1)!/[(x^2-2x+10)n!]. Thus, the minimum radius of convergence R at x = 0 is R = 1/limsup |c_n|^1/n.
Step:2 Similarly, at x = 1, the power series solution is y = c_0 + c_1(x-1) + c_2(x-1)^2 + c_3(x-1)^3 + ... + c_n(x-1)^n + ..., and the coefficients an are given by c_n = (-1)^(n-1)*(n-1)!/[((x-1)^2-2(x-1)+10)n!]. Thus, the minimum radius of convergence R at x = 1 is R = 1/limsup |c_n|^1/n.

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Answer:

Each game cost $ 7.

Step-by-step explanation:

Given that the value $ 42 included rental of shoes at $ 3.50 per pair, knowing that Patrick bowled 2 games, and Cameron bowled 3 games, to determine how much did each game cost the following calculation must be performed:

(42 - (2 x 3.50)) / (2 + 3) = X

(42 - 7) / 5 = X

35/5 = X

7 = X

Therefore, each game cost $ 7.

The expressions given in option A and option C on solving will have same value 3/2 or 1.5.

Numeric values can be obtained through the evaluation of numeric expressions, which consist of a mixture of numeric components including variables, numbers or functions, and operators. A blend of arrays and mathematical operators can be present within an expression to derive a numeric solution.

Now solving numerical expressions in the problem (refer to image attached)

A. \(\frac{1}{6} +(\frac{5}{6}+\frac{3}{6} ) = \frac{1+5+3}{6} = \frac{9}{6} =\frac{3}{2} =1.5\)

B. \(\frac{1}{3}+ \frac{5}{3}+ \frac{2}{3} =\frac{1+5+2}{3} =\frac{9}{3} =3\)

C. \(\frac{3}{5} +(\frac{1}{2} +\frac{2}{5} )=\frac{15}{10} =\frac{3}{2} =1.5\)

D. \(2+\frac{1}{2} =\frac{4+1}{2} =\frac{5}{2} =2.5\)

Hence, expressions in option A and option C have same values

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The solution for the given equation is C) \(x=\frac{-1+-\sqrt{33} }{4}\)

What does a quadratic function mean?

A polynomial function with one or more variables, where the largest exponent of the variable is two, is referred to as a quadratic function. In other words, a "polynomial function of degree 2" is a quadratic function.

The formula for the solution of a quadratic equation \(ax^{2} +bx+c=0\) is

\(x=\frac{-b+-\sqrt[2]{b^{2}-4ac } }{2a}\).

So, the solution for the equation \(2x^{2} +x-4=0\) is

\(x=\frac{-1+-\sqrt[2]{1^{2}-4*2*(-4) } }{2*2}\\x=\frac{-1+-\sqrt[2]{1+32 } }{4}\\x=\frac{-1+-\sqrt{33} }{4}\)

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To compute the values of (r) and (x) for the different states of the harmonic oscillator, we need to consider the wavefunction solutions for each state.

The wavefunctions for the harmonic oscillator are given by Hermite polynomials multiplied by a Gaussian factor. The energy eigenvalues for the harmonic oscillator are given by (n + 1/2) * h * ω, where n is the quantum number and ω is the angular frequency of the oscillator. (a) Ground State: The ground state of the harmonic oscillator corresponds to n = 0. The wavefunction for the ground state is: ψ₀(x) = (mω/πħ)^(1/4) * exp(-mωx²/2ħ), where m is the mass of the oscillator. In this state, the energy (E₀) is equal to 1/2 * h * ω. Therefore, for the ground state: (r) = 0 (since n = 0). (x) = √(ħ/(2mω)). (b) First Excited State:The first excited state corresponds to n = 1. The wavefunction for the first excited state is: ψ₁(x) = (mω/πħ)^(1/4) * √2 * (mωx/ħ) * exp(-mωx²/2ħ), where m is the mass of the oscillator. In this state, the energy (E₁) is equal to 3/2 * h * ω. Therefore, for the first excited state: . (r) = 1. (x) = √(ħ/(mω)). (c) Second Excited State:The second excited state corresponds to n = 2. The wavefunction for the second excited state is: ψ₂(x) = (mω/πħ)^(1/4) * (2(mωx/ħ)^2 - 1) * exp(-mωx²/2ħ)  where m is the mass of the oscillator. In this state, the energy (E₂) is equal to 5/2 * h * ω.

Therefore, for the second excited state: (r) = 2. (x) = √(ħ/(2mω)). In summary: (a) Ground State: (r) = 0, (x) = √(ħ/(2mω)). (b) First Excited State: (r) = 1, (x) = √(ħ/(mω)). (c) Second Excited State: (r) = 2, (x) = √(ħ/(2mω)).

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The sets that are equal are A = {1, 2, 3} and B = {2, 1, 3}

The order of elements does not matter when determining the equality of sets. Both sets A and B contain the same elements, namely 1, 2, and 3, even though their order is different. Therefore, we can say that A and B are equal sets.

The other sets mentioned, A = {1, 2} and B = {1}, A = {1, 2, 4} and B = {1, 2, 3}, and A = {1, 2} and B = {1, 2, 3}, are not equal because they have different elements. In the first case, set A has two elements, while set B has only one element.

In the second case, set A contains the element 4, which is not present in set B.

In the third case, set A has two elements, while set B has three elements, including the element 3, which is not present in set A.

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Answer:

10  

Step-by-step explanation:

1. AB

2 BC

3. CD

4. DE  

5. AC  

6. B D

7.CE

8.AD

9.BE

10. A E

the Jacobian determinant for the transformation \(x = 6u\sin(5v), y = 6u\cos(5v)\) is \(J = -180u\).

To find the Jacobian determinant of the transformation \((x, y) \rightarrow (u, v)\) for the given equations, we need to compute the partial derivatives of x and y with respect to u and v, respectively, and then calculate the determinant.

Transformation 1: \(x = 6u\cos(5v), y = 6u\sin(5v)\)

We start by finding the partial derivatives:

\[\frac{\partial x}{\partial u} = 6\cos(5v)\]

\[\frac{\partial x}{\partial v} = -30u\sin(5v)\]

\[\frac{\partial y}{\partial u} = 6\sin(5v)\]

\[\frac{\partial y}{\partial v} = 30u\cos(5v)\]

Now, we can calculate the Jacobian determinant:

\[J = \frac{\partial (x, y)}{\partial (u, v)} = \begin{vmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{vmatrix} = \begin{vmatrix} 6\cos(5v) & -30u\sin(5v) \\ 6\sin(5v) & 30u\cos(5v) \end{vmatrix}\]

Simplifying the determinant:

\[J = (6\cos(5v))(30u\cos(5v)) - (-30u\sin(5v))(6\sin(5v))\]

\[J = 180u\cos^2(5v) + 180u\sin^2(5v)\]

\[J = 180u(\cos^2(5v) + \sin^2(5v))\]

\[J = 180u\]

Therefore, the Jacobian determinant for the transformation \(x = 6u\cos(5v), y = 6u\sin(5v)\) is \(J = 180u\).

Transformation 2: \(x = 6u\sin(5v), y = 6u\cos(5v)\)

We repeat the same process for the second transformation:

\[\frac{\partial x}{\partial u} = 6\sin(5v)\]

\[\frac{\partial x}{\partial v} = 30u\cos(5v)\]

\[\frac{\partial y}{\partial u} = 6\cos(5v)\]

\[\frac{\partial y}{\partial v} = -30u\sin(5v)\]

The Jacobian determinant:

\[J = \begin{vmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{vmatrix} = \begin{vmatrix} 6\sin(5v) & 30u\cos(5v) \\ 6\cos(5v) & -30u\sin(5v) \end{vmatrix}\]

Simplifying the determinant:

\[J = (6\sin(5v))(-30u\sin(5v)) - (30u\cos(5v))(6\cos(5v))\]

\[J = -180u\sin^2(5v) - 180u\cos^2(5v)\

]

\[J = -180u(\sin^2(5v) + \cos^2(5v))\]

\[J = -180u\]

Therefore, the Jacobian determinant for the transformation \(x = 6u\sin(5v), y = 6u\cos(5v)\) is \(J = -180u\).

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The sum of the numbers 3+6+9+12+....+150 is 3825. To find the sum of an arithmetic series, you can use the formula:

Sum = (n * (a1 + an)) / 2

where n is the number of integers, a1 is the first integer, and an is the last integer.

In this case, the series is 3, 6, 9, ..., 150, and it's an arithmetic series with a common difference of 3. To find the number of integers (n) in the series, use the formula:

n = ((an - a1) / common difference) + 1

n = ((150 - 3) / 3) + 1 = (147 / 3) + 1 = 49 + 1 = 50

Now, use the sum formula:

Sum = (n * (a1 + an)) / 2
Sum = (50 * (3 + 150)) / 2
Sum = (50 * 153) / 2
Sum = 7650 / 2
Sum = 3825

So the sum of the given series is 3825.

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Answer:

Step-by-step explanation:

a^6 = a * a * a * a * a * a You can break this into groups of 2 and groups of three.

Groups of 3

a^6 = a * a * a * a * a * a

what that means is that you have 2 groups of 3 which can be written as (a^3)^2 which means that this number is a perfect square.

Groups of 2

a^6 = a * a * a * a * a * a

What this means is that you have (a^2)^3 which is three groups of 2 members. The answer is that you have a perfect cube each member of which is a^2

Answer:

multiply the original coordinate by 3 so its c

Step-by-step explanation:

multiply the original coordinate by 3

The image with the dilation of scale factor of 1/3 is P'Q'R'S' are (-2. 3),(1, 2),(0, -3) and (-3, -2)respectively.

Dilation of a figure will leave its sides get scaled (multiplied) by same number. That number is called the scale factor of that dilation. Also If the Dilation is from the center of the rectangle, then the distance of all the points of the rectangle from its center will get scaled by that one dilation factor.

The dilation with scale factor of 1/3 with the origin as the center of dilation,

Let the coordinates are (x, y) -- (kx, ky); where k is the scale factor i.e, 1/3.

This can be written as; (1/3x, 1/3y).

For the point   P(- 6, 9)

The image of P' = (-2. 3)

For the point Q(3, 6)

The image of Q' (1, 2)

For the point R(0, - 9)

The image of R' (0, -3)

For the point S(- 9, - 6)

Image = (-3, -2)

Therefore, the image with the dilation of scale factor of 1/3 is P'Q'R'S' are (-2. 3),(1, 2),(0, -3) and (-3, -2)respectively.

Part a) the reflection in the line y = -x then image triangle P'Q'R'S';

P' = (-2, 2)

Q' = (1, -1)

R' = (0,3)

S' = (-3,3)

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The mathematical model of an abstract syntax tree (AST) for a programming language's block (BL) statement typically involves representing the syntax of the statement using a tree structure.

This tree structure consists of nodes that correspond to different components of the statement, such as keywords, variables, operators, and expressions. The AST provides a way to parse and interpret the syntax of the statement, allowing for efficient compilation and execution of the code.

The model can be represented using various algorithms and data structures, such as recursive descent parsing or top-down parsing. Ultimately, the AST serves as a tool for developers to analyze, optimize, and debug their code, and is an essential component of many modern programming languages.

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Answer:

p=1

Step-by-step explanation:

p(6+1.5n)=18+4.5n

6p+1.5np = 18+4.5n

18p+4.5np=18+4.5n

p=1

:]

The crucial value (z) relies on the desired level of confidence and is predicated on a normal distribution when creating a confidence interval for a proportion (p) with a confidence level of 93%.

A 93% confidence level in this instance translates to an alpha level of 0.07 (1 - 0.93 = 0.07) that is split evenly between the two tails. In the usual normal distribution table, we search for the value that falls within the range of 0.07 to find the proper z-value. A 93% confidence level corresponds to a z-value of roughly 1.81. The confidence interval for the proportion p may be calculated using this number and provides a range where the genuine proportion is like to fall.

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The solution to the given Inequality is a > 12 and the graph is as attached.

We are given the Inequality as;

8a - 30 > 66

Now, use addition property of equality to add 30 to both sides to get;

8a - 30 + 30 > 66 + 30

8a > 96

Now, use division property of equality to divide both sides by 8 to get;

8a/8 > 96/8

a > 12

The graph of this is as attached.

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Answer:

The answer is c) 44 cm

Step-by-step explanation:

480= 20+b/2 x 15

480 x 2 = 20 + b x 15

960/15 = 20 + b

64 = 20+ b

64- 20 = b

44 = b

Hence the other parallel side is 44 cm

Answer:

Step-by-step explanation:

5x(1)=5x

Answer:

The answer is A

Step-by-step explanation:

The multiplicative identity property is applied to numbers in the operation of multiplication. The property states that when a number is multiplied by the number 1 (one), the product will be the number itself. This property is applied when numbers are multiplied by 1. Here, 1 is known as the multiplicative identity element because when we multiply any number with 1, the obtained result will be the same number. This property can be applied to real numbers, complex numbers, integers, rational numbers, and so on. The multiplicative identity property is expressed as: a × 1 = a, where 'a' is any real number.

Example:

44 × 1 = 44, where 44 is the number on which we applied the multiplicative identity.

Note: The multiplicative identity is not applied when any number is multiplied by -1 because the result will not be the same number.

For example, 23 × -1 = -23

A firm experiences increasing returns to scale if inputs are doubled and output more than doubles.

When the firm's output grows at a faster rate than the growth in inputs, increasing returns to scale result. In this case, the company experiences economies of scale, which makes it more effective as it grows its production.

The firm is able to boost productivity and efficiency as it expands its scale of operations if inputs are doubled and output more than doubles.

This can be ascribed to a number of things, including specialisation, labour division, the use of capital-intensive technology, discounts for bulk purchases, and spreading fixed costs over a higher output. Lower average costs per unit of output result in higher profitability and competitiveness for the company.

The firm gains a number of benefits from growing returns to scale. First off, it lets the company to benefit from cost savings brought about by economies of scale, allowing it to manufacture goods or services for less money per unit. This may enable more competitive pricing on the market or result in larger profit margins.

Second, raising returns to scale can result in better operational effectiveness and resource utilisation. As the company grows in size, it will be able to use resources more wisely and profit from production volume-related synergies.market prices that are competitive.

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