Why does a sound come out when you blow into a bottle?

When does the jet of air convert to vibrations?​

Answer:

Explanation: 5

The time that is taken is 18.4 s

Centripetal acceleration is a type of acceleration that acts towards the center of a circular path. It is the result of a change in the direction of an object's velocity as it moves along a curved path.

We have to note that we can be able to obtain the time that has been taken by the use of the formula;

θ = (ω1 + ω2/2)t

Let the angle turned by 5.00 revolutions or 31.4 rad

Thus;

31.4 = (2.3 + 1.11/2) t

t = 31.4/ (2.3 + 1.11/2)

t = 18.4 s

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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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The equivalent resistance between points A and B is 0.837Ω.

Resistors in series are connected end-to-end so that the current flows through them in sequence. The equivalent resistance of resistors in series is the sum of their individual resistances.

The formula for equivalent resistance of resistors in series: R_eq = R_1 + R_2 + ... + R_n

Resistors in parallel are connected across each other so that the voltage is the same across each resistor. The equivalent resistance of resistors in parallel is the reciprocal of the sum of the reciprocals of their individual resistances.

The formula for equivalent resistance of resistors in parallel: 1/R_eq = 1/R_1 + 1/R_2 + ... + 1/R_n

Here in the Fig.

we can simplify the second set of resistors in parallel (4.8 Ω, 3.3 Ω, and 8.1 Ω) using the same formula:

1/Req1 = 1/4.8 + 1/3.3 + 1/8.1

Req1=1.575Ω

This Req1 connected series with 6.3Ω, then Req of this two resistance given by:

Req2= 1.575Ω+ 6.3Ω

Req2=7.875Ω

Once again this req2 makes the parallel with the other two resistance i. e 1.5Ω and 2.5Ω

Their equivalent resistance  is given by,

1/Req3=1/1.5 + 1/2.5 + 1/7.875

Req3=0.837Ω

Hence, The equivalent resistance between points A and B is 0.837Ω

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The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

A concave mirror has a reflective surface that is curved inward and away from the light source.

Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.

Apply mirrors formula as shown below;

1/f = 1/v + 1/u

where;

when image height = object height, magnification = 1

u/v = 1

v = u

Substitute the given parameters and solve for the distance of the object from the mirror's vertex

1/f = 1/v + 1/v

1/f = 2/v

v = 2f

v = 2(19.5 cm)

v = 39 cm

Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

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1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.

5.Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA = (-2, -2, -1)

1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.

The direction vector BA is given by:

BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)

To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:

|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3

Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)

2.The angular velocity (ω) of the body is given as 3 radians per second.

3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.

4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.

5.The position vectors of points A and B are:

Position vector of point A: (4, 1, 1)

Position vector of point B: (2, -1, 0)

The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:

BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Nuclear power is a clean energy source that emits no emissions. Fission, which is the splitting of uranium atoms to release energy, is how it generates energy.

The operational risks and safety concerns that go along with them, risks associated with uranium mining, financial and regulatory risks, unresolved waste management issues, concerns about nuclear weapons proliferation, and unfavorable public perception are all obstacles to and risks associated with an increase in the use of nuclear energy.

The generation of radioactive wastes such spent (used) reactor fuel, uranium mill tailings, and other radioactive wastes is a significant environmental hazard associated with nuclear power.

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Answer:

\(Velocity = 1306.76\)m/s

Explanation:

Given

\(r = 7.79 * 10^{10}m\)

\(Time = 4333 days\)

Required

Determine Jupiter's velocity

First, we calculate the circumference (C) of Jupiter:

\(C = 2\pi r\)

Substitute values for r and \(\pi\)

\(C = 2 * 3.14 * 7.79 * 10^{10}m\)

\(C = 489212000000m\)

Next, convert time to seconds:

\(Time = 4333 days\)

\(Time = 4333 * 60 * 60 * 24s\)

\(Time = 374371200s\)

The velocity is then calculated as:

\(Velocity = \frac{Circumference}{Time}\)

\(Velocity = \frac{489212000000m}{374371200s}\)

\(Velocity = 1306.76\)m/s

Hence, Jupiter's velocity is 1306.76m/s

Answer:

1307 also works for acellus

Explanation:

Answer:

The form of energy that can move from place to place across the universe is electromagnetic energy.

Electromagnetic energy is a form of energy that is produced by the movement of electrically charged particles. It is characterized by its wavelength or frequency and can range from gamma rays, X-rays, ultraviolet (UV) rays, visible light, infrared radiation, microwaves, to radio waves.

Answer:

I would assume a force of gravitational pull.

Explanation:

Answer:  How powerful the pull is or how many magnetic things it can pick up at one time, or a heavy magnetic object.

Explanation:

Try watching Demon Slayer on Netflix. It's a new series, and it's very entertaining to watch!! :)

(Brainliest please!)

The final temperature of the water is approximately 19.8°C.First, we need to calculate the heat lost by the water as it cools down from 80°C to the final temperature.

We can use the formula: Q = m × c × ΔT where Q is the heat lost, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

The mass of water in the calorimeter is:

90 ml = 90 g

The heat lost by the water is:

Q1 = 90 g × 4.18 J/g°C × (80°C - T)

Q = m × Lf + m × c × ΔT

The mass of ice added to the water is 10 g. The heat gained by the ice is:

Q2 = 10 g × 334 J/g + 10 g × 4.18 J/g°C × (T - (-20°C))

where 334 J/g is the heat of fusion of water.

Since the calorimeter is insulated, we know that the heat lost by the water must equal the heat gained by the ice. Therefore:

Q1 = Q2

90 g × 4.18 J/g°C × (80°C - T) = 10 g × 334 J/g + 10 g × 4.18 J/g°C × (T - (-20°C))

Simplifying and solving for T, we get:

T = 19.8°C

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Answer:

From 0.75 to 1.25 hours

Explanation:

Given

See attachment for graph

Required

Point where they didn't move

This means that we identify the point where the distance didn't change.

Given that the distance is plotted on the y-axis, we simply check for the end points of any horizontal line on the graph

The horizontal line on the graph represents 30km and the time interval is: 0.75 to 1.25 hours.

Hence, (c)  is correct

The statement included in the hypothesis are as follows:

Hypothesis in an experiment is a tentative conjecture explaining an observation, phenomenon or scientific problem that can be tested by further observation, investigation and/or experimentation.

A hypothesis in an experiment is also referred to as an educated guess because it predicts the outcome of an observation that can be tested via experimentation.

According to this question, a hypothesis was given in the IF, THEN format as follows:

IF a solution is an acid, THEN it will have a pH below 7, and if the solution is a base, it will have a pH above 7 since the pH value is determined by the concentration of H+ and OH– ions.

The above hypothesis connects pH of a solution to the acidic or alkaline nature of the solution. The IF part explains the characteristics of the solution while the THEN part throws more light on the measurable variable, which is the pH.

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Answer:

b

Explanation:

The use  lead was stopped due to health risk to users. Option D

Lead is a heavy metal. We know that heavy metals are used for various purposes and that they pose health risks for the users of such metals. Lead is know to cause  anemia, weakness, and kidney and brain damage.

The major concern in the use of a substance must be if the stated compound has an adverse effect on the users of the compound. The toxicity of the lead leads us to the fact that there are some health concerns that pertains to the use of lead as a component during the painting of homes.

Now, given the fact that there are some health concerns that surround the stoppage of the use of lead, we can say that the use  lead was stopped due to health risk to users.

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Missing parts:

Decades ago, most of the paint used in the US was lead-based because it was cheap, long lasting, and widely available. When scientists recognized that this was polluting the air with toxic lead, laws banned lead-based paint, and the paint industry developed more cost-effective paints that do not contain lead.

What was most likely the type of problem lead-based paint had that was solved by using paints without lead?

A. limited availability

B. ineffective for most uses

C. lack of durability

D. health risk to users

The lead based Paint is defined as the coatings which contains lead which should be equal to 1.0 milligram per square centimeter.

What are the problems when we use lead-based paint?

Lead-based paint can be dangerous when it is found on surfaces of the floor or ground because the children can chew. That adults which are mostly are in contact with the lead based can suffer from b pressure, headaches, dizziness, diminished motor skills, fatigue and memory loss. So it is quite harmful to use lead based paint in our homes or in our surrounding.

So we can conclude that: The lead based Paint is defined as the coatings which contains lead which should be equal to 1.0 milligram per square centimeter.

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a) Magnitude of the resistance force is -24N.

b) We cannot calculate the work done without additional information about the distance or displacement of the bullet within the block.

a) To find the magnitude of the resistance force, we can use the equation of motion:

F = (mv - mu) / t

where F is the force, m is the mass of the bullet, v is the final velocity (0 m/s in this case), u is the initial velocity (20 m/s), and t is the time taken for the bullet to come to rest (0.1 s).

Plugging in the values:

F = (0.12 kg × 0 - 0.12 kg × 20 m/s) / 0.1 s

F = (-0.12 kg × 20 m/s) / 0.1 s

F = -24 N

Since the force is acting in the opposite direction of the bullet's initial velocity, we take the negative sign to indicate that.

b) The work done is given by the equation:

Work = Force × Distance

Since the bullet comes to rest in the block, the distance over which the resistance force acts is not given. Therefore, we cannot calculate the work done without additional information about the distance or displacement of the bullet within the block.

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Answer:

i think its 2.5 as well

Explanation:

a. Her x position at t = 0.80 s is 0.0832 m

b. Her y position at t = 0.80 s is -28.8 m

c. Her x velocity component at t = 0.80s is 2.08 m/s

d. her y velocity component at t = 0.80s is -3.6 m/s

Since the skateboarder travels on a horizontal surface with an initial velocity of 3.6 m/s toward the south and a constant acceleration of 2.6 m/s² toward the east.

Now since she starts from the origin, to find her x position after 0.80 s, using the equation of motion for the x - components of motion,

x = ut + 1/2at² where

So, substituting the values of the variables into the equation, we have

x = ut + 1/2at²

x = 0 m/s × 0.8 s + 1/2 × 2.6 m/s² × (0.8 s)²

x = 0 m + 1.3 m/s² × 0.64 s²

x = 0 m + 0.832 m

x = 0.832 m

So, her x position at t = 0.80 s is 0.0832 m

Using the equation of motion for her y - components of motion, her y position is y = ut + 1/2at² where

So, substituting the values of the variables into the equation, we have

y = ut + 1/2at²

y = -3.6 m/s × 0.8 s + 1/2 × 0 m/s² × (0.8 s)²

y = -3.6 m × 0.8 s + 0

y = -28.8 m

So, her y position at t = 0.80 s is -28.8 m

Using the equation of motion for her x - component of motion, her x velocity compoent after t = 0.8 s is

v = u + at where

So, we have

v = u + at

v = 0 m/s + 2.6 m/s² × 0.8 s

v = 0 m/s + 2.08 m/s

v = 2.08 m/s

So, her x velocity component at t = 0.80s is 2.08 m/s

Using the equation of motion for her y - component of motion, her xyvelocity compoent after t = 0.8 s is

v = u + at where

So, we have

v = u + at

v = -3.6 m/s + 0 m/s² × 0.8 s

v = -3.6 m/s + 0 m/s

v = -3.6 m/s

So, her y velocity component at t = 0.80s is -3.6 m/s

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A procedure known as magnetic separation can be used to extract magnetic elements from coal.

This method makes use of the magnetic characteristics of some materials to distinguish them from non-magnetic materials like coal. A description of how magnetic separation can be used to remove magnetic components from coal is given below:

Putting a magnetic field around the coal and magnetic material mixture is the first step in the magnetization process. This can be achieved by creating an electromagnetic field or by putting the mixture close to a powerful magnet.

Magnetism: Magnetic materials, such as iron atoms or magnetite that are frequently found in coal, will be drawn to the magnetic field and become magnetized. They line up their magnetic moments with the magnetic field's direction.

Separation: The magnetic coal components can be physically separated from the non-magnetic coal once they have been magnetized. To create this separation, there are numerous techniques:

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Answer:

Below

Explanation:

1. To find the ball's acceleration we can use this formula :

     vf = vi + at

Because the ball comes to a stop, the vf is 0 :

     0 = 12 + a(36)

  - 12 = a36

  - 0.33 m/s^2 [ forward ] = a

^^note that this is negative acceleration because it is slowing down!

2. We can use that same formula for this question :

     vf = vi + at

     45 = 85 + a(4.5)

    - 40 = a4.5

    - 8.9 m/s^2 [ up ] = a

3. It is all of the above!

     Well, when a plane is moving, this means that it will have both speed and velocity. But on the runway, the plane is also accelerating because it is getting faster due to the force of the engines!

4.  This one is an example of speed!

     Because there was no direction given, this means that this is a scalar quantity! Velocity and acceleration are both vector quantities that have both magnitude and direction. Speed is a scalar quantity that only has magnitude.

Hope this helps! Best of luck <3

The tension force being supplied by the rope is 245 N.

The tension force on the given rope due to the weight of the lamp hanging from the rope is calculated by applying Newton's second law of motion as shown below;

T = mg

where;

T = 25 x 9.8

T = 245 N

Thus, the tension force being supplied by the rope is 245 N.

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The balanced nuclear equation for the formation of polonium-215 through alpha decay is:

\(At_{211} +4He - > Po_{ 215}+ 2 n\)

Polonium-215 is an isotope of the element polonium that is formed through alpha decay. In alpha decay, a parent atom loses an alpha particle, which is a helium nucleus, to form a daughter atom. In the case of polonium-215, the parent atom is astatine-211, which loses an alpha particle (4He) to form polonium-215 (215Po) and also two neutrons (2n). The process is represented by the equation 211At + 4He → 215Po + 2n. This equation shows that the total atomic number and mass number are conserved on both sides of the equation. It's important to note that alpha decay is one of the common types of decay in the heavy elements but not all elements can decay by alpha emission.

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When work is done on a system, the internal energy of the system increases.

This results in the increase of temperature of the system.

Thus, temperature increases when work is done on a system.

If a radio station broadcasts at 9.23 x 10⁷Hz and the velocity of the waves is 3  x 10⁸m/s, the wavelength of these waves is 3.25m.

According to the question,

Frequency of the FM radio = 9.23 x 10⁷Hz

Velocity of the waves = 3  x 10⁸m/s

The wavelength of the wave =?

To find the wavelength of the wave, we conclude the velocity equation;

Velocity = frequency x wavelength.

Since to find unknown is the wavelength, we have to solve for it:

       3  x 10⁸  = 9.23 x 10⁷ x wavelength

      wavelength =    3  x 10⁸/ 9.23 x 10⁷

      wavelength = 3.25m

Therefore, the wavelength of these waves is 3.25m.

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The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?