why must samples of 2-acetylpyridine be kept in a hood at all times?

Answer:

it is ductile

Explanation:

i took the test

Answer:

b

Explanation:

Total number of valence electrons in the Lewis structure of XeO4 is 32.

Valence electrons are electrons that located in the outermost electron shell of an atom. These electrons, being the furthest from the nucleus and thus the least tightly held by the atom, are the electrons that participate in bonds.

Lewis structure - A Lewis Structure is a very simplified representation of the valence shell electrons in a molecule. It is used to show how the electrons are arranged around individual atoms in a molecule.

Lewis structure of XeO4 is made up of one xenon and four oxygen atom, the xenon is in a central position, and all oxygen is at the surrounding position. There are four double bonds(Xe=O) present in the XeO4 lewis structure. The lewis structure of XeO4 contains 8 pairs of nonbonding electrons and 8 pairs of bonding electrons.

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The heat released by reaction : C) -8870 J

Given

1.008 g of hydrogen

500.00 g water

The temperature rises 25.00 °C to 29.24 °C

Required

energy required

Solution

Q absorbed by water :

Q = m.c.Δt

Q = 500 g x 4.18 J/g C x (29.24-25)

Q = 8870.08 J

The reaction to produce HCl is an exothermic reaction (releasing heat), so that Q is negative

Q water = -Q HCl = -8870.08 J

Answer:

ammonia molecules. Similar factors may be derived for any pair of substances in any chemical equation. Example 4.8. Moles of Reactant Required in a Reaction.

Explanation:

Answer:

The letters are a one- or two-letter symbol assigned to each element.

Explanation:

NH3 and (NH4)2SO4 of the following combinations cannot produce a buffer solution.

The correct option is C.

A mixture of weak acid and its conjugated base, or weak base and its conjugated acid, is called a buffer solution. A weak acid and its salt or a weak base and its salt are combined to form the buffer, according to another definition.

A) is a weak acid that has salt as its conjugated base.

B) is a weak acid that has salt as its conjugated base.

C) Strong acid and salt, not a buffer

D) A weak base and its conjugated acid (optional)

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Answer:

Answer: Reaction Rate

Explanation:

reaction rate, in chemistry, the speed at which a chemical reaction proceeds. It is often expressed in terms of either the concentration (amount per unit volume) of a product that is formed in a unit of time or the concentration of a reactant that is consumed in a unit of time.

Answer:

i believe it is strong acids, strong bases, and salts.

Explanation:

Hope this helps : )

The solution to the equation and value of variable 21(3d - 4) + 100 = 58 is d = 2/3.

Solve the equation 21(3d - 4) + 100 = 58, we can begin by simplifying and isolating the variable:

21(3d - 4) + 100 = 58

Distribute 21 to the terms inside the parentheses:

63d - 84 + 100 = 58

Combine like terms:

63d + 16 = 58

Subtract 16 from both sides:

63d = 42

Divide both sides by 63:

d = 42/63

Simplifying the fraction gives:

d = 2/3

The solution to the equation is d = 2/3.

The solution to the equation 21(3d - 4) + 100 = 58 is d = 2/3. By simplifying the equation, we find that dividing both sides by 63 results in the solution of d = 2/3, which satisfies the original equation.

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The mass of NaHCO₃ needed to produce 2.659 moles of CO₂ is 446.712 g

We'll begin by writing the balanced equation for the reaction. This can be obtained as follow:

2NaHCO₃ —> Na₂CO₃ + CO₂ + H₂O

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 84 g/mol

Mass of NaHCO₃ from the balanced equation = 2 × 84 = 168 g

From the balanced equation above,

168 g of NaHCO₃ decomposed to produce 1 mole of CO₂.

With the above information, we can obtain the mass of NaHCO₃ needed to produce 2.659 moles of CO₂. This can be obtained as follow:

From the balanced equation above,

168 g of NaHCO₃ decomposed to produce 1 mole of CO₂.

Therefore,

Xg of NaHCO₃ will decompose to produce 2.659 moles of CO₂ i.e

Xg of NaHCO₃ = 168 × 2.659

Xg of NaHCO₃ = 446.712 g

Thus, 446.712 g of NaHCO₃ is needed to produce 2.659 moles of CO₂.

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Ag⁺ + 2NH₃ → [Ag(NH₃)2]²⁺

Ni²⁺ + 4CN⁻ → [Ni(CN)4]²⁻

The formulas for the complexes formed between Ag⁺ and NH₃, with a coordination number of 2, is [Ag(NH₃)2]²⁺and Ni²⁺ and CN⁻  with a coordination number of 4, is  [Ni(CN)4]²⁻.

Is the coordination number of the complexes are 2 and 4 respectively?

In first complex, two ammonia (NH₃) molecules act as ligands and coordinate with the central silver (Ag⁺) ion. The coordination number represents the number of ligands attached to the central metal ion.So, the coordination number of the complex  [Ag(NH₃)2]²⁺ between Ag⁺ and NH₃ is 2.

In second complex, Ni²⁺, interact with ligands, such as CN⁻, through coordinate bonds. In this case, the complex formed between Ni²⁺ and CN⁻ has a coordination number of 4, indicating that four CN⁻ligands surround the central Ni²⁺ ion.

Coordination complexes play a significant role in chemistry, particularly in fields such as coordination chemistry and bioinorganic chemistry. These complexes are formed when metal ions interact with ligands, which can be ions or molecules capable of donating electrons to the metal ion.

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Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 1 g

Mass of CO₂ = 3.14 g

Mass of H₂O = 1.29 g

Empirical formula =?

Next, we shall determine the mass of Carbon and hydrogen present in the compound. This can be obtained as follow:

For Carbon, C:

Mass of CO₂ = 3.14 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Molar mass of C = 12 g/mol

Mass of C =?

Mass of C = molar mass of C/ Molar mass of CO₂ × Mass of CO₂

Mass of C = 12/44 × 3.14

Mass of C = 0.86 g

For hydrogen, H:

Mass of C = 0.86 g

Mass of compound = 1 g

Mass of H =?

Mass of H = (Mass of compound) – (mass of C)

Mass of H = 1 – 0.86

Mass of H = 0.14 g

Finally, we shall determine the empirical formula of the cyclopropane. This can be obtained as follow:

Mass of C = 0.86 g

Mass of H = 0.14 g

Divide by their molar mass

C = 0.86 / 12 = 0.07

H = 0.14 / 1 = 0.14

Divide by the smallest

C = 0.07 / 0.07 = 1

H = 0.14 / 0.07 = 2

Thus, the empirical formula of cyclopropane is CH₂

Answer:

15.0°C

Explanation:

hope it helps

Heat Capacity

The heat capacity of a substance can be defined as the amount of heat required to change the temperature by a given amount the SI unit is joules per kelvin

The energy absorbed by the water is 105 joules

Given data:

mass of water = 5 grams

Change in temperature = 10 degrees from 15 degrees

The expression for the Quantity of heat is given by

Q = m x c x Δθ

Where m =mass

c = specific heat capacity and

Δθ = change in temperature

c = 4.2J/g/degrees

Q = 5 x 4.2 x (15 - 10)

Q = 5 x 4.2 x 5

Q = 105Joules

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KNO3 is dissolved in 100 g of water at 50 °C to prepare a saturated solution. Approximately 69 grams of KNO3 will precipitate out of the solution.

So, the amount of KNO3 precipitate out from the solution will be = Initial mass - Final mass

       Initial mass of KNO3 = 31 g KNO3/100 g water × 100 g

                                             = 31 g KNO3

Final mass of KNO3 = 100

Initial mass - Final mass

                                      = 100 - 31

                                  = 69 g

Therefore, approximately 69 grams of KNO3 will precipitate out of the solution.

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Answer:

decomposition

Explanation:

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Answer:

A polar covalent bond will have the electrons shifted more towards one side or the other; a nonpolar bond will have evenly distributed electrons.

Explanation:

  The basis for a polar bond is that the electrons are shared unevenly. Some elements are more electronegative than others; that is, they pull harder on the electrons and tend to have more electrons around them. Following the periodic trends, Fluorine is the most electronegative element, so it will likely have the most dense area of electrons in a molecule. All this means that in a polar molecule, the electrons will be spread out unevenly along the lengths of the bonds as some elements will pull on them more than others will.

  Nonpolar molecules do not have to worry about differences in electronegativity, and so the electron density will be pretty evenly distributed along the entire molecule.

Hope this helps! :)

The compound that will have the lowest freezing point when dissolved in water is 1.0M Mg(NO3)2. That is option 3.

To compare the freezing points of solution, the total concentration of all the particles when solutes are dissolved in water is determined.

This is an important step to consider because, the greater the concentration of particles, the lower the freezing point will be.

To determine the concentration of all the particles, ionic compounds are alway 2 while covalent compounds are always 1.

Therefore, since 1.0M Mg(NO3)2 contains the greater concentration of particles, it has lower freezing point.

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Answer:

Explanation:

Enertia is an integral part of Newton's first law of motion.

It is the tendency of an object to stay at rest or to continue moving until and unless any external unbalanced force, (like, applied force or force of tension or frictional force ) is applied to either move it from rest or change its speed(in other words, accelerate it!!).

Example below, is of ball at rest (fig1) and if this ball is moving straight on a frictionless surface(like ice) it will keep moving!! until, we push it or pull it.

The total mass of the products is 125 g

The law of conservation of mass, also known as the principle of mass conservation, states that the total mass of a closed system remains constant over time, regardless of the changes that may occur within the system. This means that the mass of the system can change form, but the total mass remains the same.

The law of conservation of mass is a fundamental principle in physics and is widely accepted as a basic law of nature. It is based on the idea that matter can be neither created nor destroyed, only transformed from one form to another.

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Answer:

ether

Explanation:

i got it right on edg 2020 and they use ether in pokemon games to heal PP so that makes logical sense lol

The class of organic compounds that are used in anesthetics is:

A. Ether

It is a functional group consisting of C and O.

Anesthetics are an assorted gathering of medications with especially unique synthetic designs, going from basic inorganic atoms like nitrous oxide to additional perplexing natural specialists.

Organic compound is one that contains a bond with a carbon particle. In ethers, the practical gathering that is available is C=O. Ether, as a fluid, discharges fumes that are breathed in. Another very powerful fluid sedative is propofol, controlled intravenously.

Thus, correct option is A.

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The change in Gibbs free energy (∆G) for the new reaction with halved enzyme concentration will be the same as the ∆G for the original reaction, which is -40 kcal/mol.

To determine the ∆G (change in Gibbs free energy) for the new reaction when you halve the amount of enzyme, we need to consider the relationship between the enzyme concentration as well as the equilibrium constant (K) of the reaction.

The ∆G for a reaction can be related to the equilibrium constant using the equation:

∆G = -RT ln(K)

Where;

∆G is change in Gibbs free energy

R is the gas constant

T is the temperature in Kelvin

ln(K) is natural logarithm of the equilibrium constant

Now, when you halve the amount of enzyme in the reaction, the concentration of the enzyme decreases by a factor of 2. Let's assume that the equilibrium constant remains the same (K1) for the original reaction with the initial enzyme concentration.

Now, let's consider the new reaction with halved enzyme concentration. The equilibrium constant for the new reaction will be denoted as K₂.

According to the relationship between ∆G and K, we can rewrite the equation as follows;

∆G = -RT ln(K)

For the original reaction;

∆G₁ = -RT ln(K₁)

For the new reaction with halved enzyme concentration:

∆G₂ = -RT ln(K₂)

Since we know that ∆G₁ = -40 kcal/mol, we can rewrite the equation as:

-40 kcal/mol = -RT ln(K₁)

Now, to determine the relationship between K₂ and K₁, we consider the enzyme concentration's effect on the equilibrium constant. The reaction rate of an enzyme-catalyzed reaction is directly proportional to the enzyme concentration. Therefore, if we halve the enzyme concentration, the reaction rate will also halve.

The equilibrium constant (K) is defined as the ratio of the forward rate constant (k₁) to the reverse rate constant (k⁻¹). Since the reaction rate decreases by a factor of 2 when the enzyme concentration is halved, both k₁ and k⁻¹ will decrease by the same factor.

Thus, the ratio k₁/k⁻¹ remains the same for the new reaction as it was for the original reaction. This means that the equilibrium constant K₂ for the new reaction will be equal to K₁ for the original reaction.

Therefore, we can write;

∆G₂ = -RT ln(K₂) = -RT ln(K₁) = ∆G₁ = -40 kcal/mol

Hence, the ∆G for the new reaction with halved enzyme concentration will be the same as the ∆G for the original reaction, which is -40 kcal/mol.

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The ground-state electron configuration of V is 1s22s22p63s23p63d3.

The ground-state electron configuration of an element refers to the arrangement of its electrons in the lowest energy state possible. In the case of vanadium (V), the ground-state electron configuration can be determined by referring to the periodic table and the number of electrons in each energy level.

The electron configuration of vanadium can be written as 1s2 2s2 2p6 3s2 3p6 4s2 3d3. This configuration indicates that vanadium has a total of 23 electrons, with two in the first energy level, eight in the second energy level, ten in the third energy level, and three in the fourth energy level.

The electrons in vanadium are arranged in a particular way based on the Aufbau principle, which states that electrons fill up the lowest energy levels first before occupying higher energy levels. In vanadium, the first two electrons occupy the 1s orbital, the next two occupy the 2s orbital, and the next six occupy the 2p orbital. The remaining electrons occupy the 3s, 3p, 4s, and 3d orbitals.

Therefore, the ground-state electron configuration of vanadium is 1s2 2s2 2p6 3s2 3p6 4s2 3d3.

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Explanation:

Elastic Potensial energy is what causes a ball to bounce or rebound because it is transformed into kinetic energy, which is then used to bring the ball back up.

Answer:

It's b

Explanation:

I had the same exact question

Answer:

c2h2 is it..........

Explanation:

lol

The reaction is an addition reaction.

Addition reactions are chemical reactions involving 2 or more reactants reacting to produce a single product.

Addition reactions are different from decomposition reactions. In the latter, a single reactant decomposes to give two or more products.

In the illustrated reaction, Cl₂O5 and H₂O react together to form a single product, HCIO3.

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