Wich is faster this is for a project so pls don't guess
1.328m/s
or
1.351 m/s

Answer: The sum of protons and neutrons in the nucleus

Explanation: The Formula For Atomic Mass or Mass Number is

                           Atomic mass= Protons + Neutrons

The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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The wellbeing of a human body encompasses the fitness of the body:

We take good care of the body to maintain proper health conditions and be free from disease, by doing so, we perform some fitness exercises and some of the following terms are defined below.

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Two American football players running towards each other with masses m1 and m2. Let m1 = 70 kg and m2 = 100 kg, respectively. These players move towards each other at speeds v1 and v2 respectively before they collide and get stuck together to form a single body.

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Answer:

Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789

The total energy at each point in the path of the skier is constant as the

skier travels down the slope.

Reasons:

1) Given that the total mechanical energy, M.E. is constant, we have;

M.E. = Kinetic Energy, K.E. + Potential Energy, P.E. = Constant

M.E. = K.E. + P.E.

At the start, we have;

P.E. = 25,000 J

K.E. = 0 J

Therefore;

M.E. = 25,000 J + 0 J = 25,000 J

At point 1A, we have, K.E = 10,000 J

P.E. = M.E. - K.E.

Therefore;

P.E. = 25,000 - 10,000 = 15,000

The potential energy at point 1A, P.E. = 15,000 J

At point 1B, we have; PE = 6000 J

K.E. = M.E. - P.E.

Therefore;

K.E. = 25,000 J - 6,000 J = 19,000 J

At 1B, K.E. = 19,000 J

At point 1C, we have; K.E. = 25,000 J

Therefore;

P.E. = 25,000 J - 25,000 J = 0 J

At 1C P.E. = 0 J

2) The Law of Conservation of Energy states that the energy in a closed

system is constant.

The energy transformation follows the Law of Conservation of energy

given that the total mechanical energy is constant at all points along the

path.

3) The energy of a system is not conserved when a external force is

applied.

If the skier experiences friction, the force of friction does work to reduce

the speed of the skier, thereby reducing the kinetic energy at a point

downslope, where the potential energy has already been reduced,

resulting in an reduction in the mechanical energy of the system.

Therefore, if the skier experiences friction, the total energy of the system is

not conserved, as energy will be consumed in the work done by friction

which is converted to heat and sound energies.

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Answer:

Explanation:Quantity  

Dimension

Unit  

SI Symbol

Formula

Base units:    

length  

[L]

meter  

m

mass  

[M]

kilogram  

kg

temperature  

[Q]

kelvin  

K

time  

[T]

second  

s

Derived units:    

area  

[L2]

square meter  

m2

volume  

[L3]

cubic meter  

m3

velocity  

[L T-1]

meter per second  

m s-1

acceleration  

[L T-2]

meter per second squared  

m s-2

density  

[M L-3]

kilogram per cubic meter  

kg m-3

force  

[M L T-2]

newton  

N

kg m s-2

pressure  

[M L-1 T-2]

pascal  

Pa

N m-2

stress  

[M L-1 T-2]

pascal  

Pa

N m-2

energy  

[M L2 T-2]

joule  

J

N·m

quantity of heat  

[M L2 T-2]

joule  

J

N·m

work  

[M L2 T-2]

joule  

J

N·m

power  

[M L2 T-3]

watt  

W

J s-1

viscosity, dynamic  

[M L-1 T-1]

pascal-second  

Pa·s

viscosity, kinematic  

[L2 T-1]

square meter per second  

m2 s-1

specific heat  

[L2 Q-1 T-2]

joule per kilogram-kelvin  

J kg-1 K-

Answer:

D

Explanation:

I'm not sure but I think so haha

Answer:

a = 2 m/s²

Explanation:

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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A boy pushes a lever down 2 meters with a force of 75 newtons. The box at the other end with a weight of 50 newtons move up 2.5 meters. The efficiency of this machine is 83.33%.

The energy  lost during a machine's operation due to heat and friction is measured as the machine's efficiency. Given that work is the transformation of kinetic energy, a machine's efficiency can be expressed as the ratio of output work divided by input work less work wasted due to friction and heat. It is unitless.

Using the formula:

Efficiency=\(\frac{O}{I}\)×100

where,

O is output work and,

I is the input work.

Work done= Force × displacement

Output work = 50 × 2.5 = 125J

Input work = 75 × 2 = 150J

Substituting the values and solving for efficiency:

Efficiency = 83.33%

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Complete question:

A boy pushes a lever down 2 meters with a force of 75 Newtons. The box on the other end weighs 50 Newtons and moves up 2.5 meters. What is the efficiency of this machine?

Answer: when the ground is very hot and the air is cool. The hot ground warms a layer of air just above the ground. When the light moves through the cold air and into the layer of hot air it is refracted (bent). A layer of very warm air near the ground refracts the light from the sky nearly into a U-shaped bend.

Explanation:

To calculate the volume of a parallelepiped given the sides, we can use the scalar triple product. The formula for the volume of a parallelepiped with sides a, b, and c is:

Volume = |a · (b × c)|

where · represents the dot product and × represents the cross product.

Using the given sides:

a = (7, 2, 4)

b = (4, 7, 6)

c = (3, 4, 7)

First, calculate the cross product of b and c:

b × c = (7*7 - 4*4, 6*3 - 7*7, 4*4 - 2*3)

      = (49 - 16, 18 - 49, 16 - 6)

      = (33, -31, 10)

Next, calculate the dot product of a and the cross product (b × c):

a · (b × c) = 7*33 + 2*(-31) + 4*10

           = 231 - 62 + 40

           = 209

Finally, take the absolute value of the result to obtain the volume:

Volume = |209| = 209 cubic units

Therefore, the correct answer is:

209 cubic units

Answer:

La fuerza del resorte es directamente proporcional a la extensión del resorte. En otras palabras, si jalas mucho de la masa, la fuerza será intensa; si jalas poco de la masa, la fuerza será débil.

Explanation:

THERE ARE COMMONLY THREE SYSTEMS OF UNIT. THEY ARE:-

• CGS System- (Centimeter-Gram-Second system) A metric system of measurement that uses the centimeter, gram and second for length, mass and time.

• FPS System- (Foot–Pound–Second system).

The system of units in which length is measured in foot , mass in pound and time in second is called FPS system. It is also known as British system of units.

• MKS System- (Meter-Kilogram-Second system) A metric system of measurement that uses the meter, kilogram, gram and second for length, mass and time. The units of force and energy are the "newton" and "joule."

Answer:

Explanation:

Pressure will expand a gas, enlarging its volume and reducing its density and concentration of particles. Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles.

Increasing the pressure of a gas is exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume. If you have the same mass in a smaller volume, then its concentration is higher.

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{10}{25} = \frac{2}{5} \\ \)

We have the final answer as

Hope this helps you

Answer:

0.4 m/s²

Explanation:

hope this helps

Answer:

1.84 hours

I hope it's helps you

Answer:

19.284

or

9.33

Explanation:

Answer:

1.66

Explanation:

Found answer on chegg. Works for acellus

The correct drills that can be used to practice digging in volleyball are b. shuffle steps and c. knock out drill.

b. Shuffle steps: Shuffle steps are an essential footwork drill for improving defensive movements, including digging.

In this drill, players shuffle laterally in a low defensive stance, simulating the movements required to dig a ball. It helps players develop quick and efficient footwork, enabling them to react and move quickly to reach the ball for a dig.

c. Knock out drill: The knock out drill focuses on improving a player's reaction time and defensive skills. In this drill, players form a line and take turns receiving rapid hits or "knocks" from a coach or teammate.

The objective is to successfully dig each hit and keep the ball in play.

This drill helps players develop their reflexes, positioning, and technique when digging in various directions and angles.

a. Double decker and 1. toss catch drill are not specific drills for practicing digging in volleyball. Double decker is a term used to describe a defensive formation, while the toss catch drill is more focused on developing ball control and setting skills rather than digging.

By incorporating shuffle steps and the knock out drill into practice sessions, players can enhance their digging abilities, improve their defensive movements, and develop the necessary skills to successfully retrieve hard-driven balls in a game situation.

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To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:

Lenses:

Place an object at different distances to the left of a lens with a focal length (f).

a) Object placed beyond 2f:

In this case, the object is placed far beyond twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.

SALTS:

Size: The image will be smaller than the object.

Attitude: The image will be inverted.

Location: The image will be located between the focal point and twice the focal length.

Type: The image will be real.

b) Object placed at 2f:

In this case, the object is placed at twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens at twice the focal length.

SALTS:

Size: The image will be the same size as the object.

Attitude: The image will be inverted.

Location: The image will be located at twice the focal length.

Type: The image will be real.

c) Object placed between f and 2f:

In this case, the object is placed between the focal point and twice the focal length of the lens.

In this case, the object is placed far beyond twice the focal length of the mirror.

Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.

Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.

Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.

The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.

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Answer:

8.45 m

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 90 Kg

Initial velocity (u) = 13 m/s

Final velocity (v) = 0 m/s

Height (h) =?

NOTE: Acceleration due to gravity (g) = 10 m/s²

The height of the hill can be obtained as follow:

v² = u² – 2gh (since the cart is going against gravity)

0² = 13² – (2 × 10 × h)

0 = 169 – 20h

Rearrange

20h = 169

Divide both side by 20

h = 169/20

h = 8.45 m

Therefore, the height of the hill is 8.45 m

Answer:

the scientific study of natural forces such as light, sound, heat, electricity, pressure, etc.

Explanation:

mark as brainliest

No

because that is a light

The light travel faster in fresh water as compare to sea water.

Hence, the light travel faster in fresh water as compare to sea water.

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Answer:

the total magnetic force on the 2 sides of the wire is 0.30 N

Option a) 0.30 N is the correct answer

Explanation:

Given the data in the question;

both the sides of the right angled triangle is the same and the magnetic is in the plane of the  triangle and is perpendicular to the hypotenuse.

hence, angle between the magnetic field and both the sides of the triangle is 45 degrees.

∅ = 45°

I = 2.0 A

L = 15 cm = 0.15 m

B = 0.7 T

Total magnetic force on the 2 sides of the wire will be;

F = 2BILsin∅

we substitute

F = 2 × 0.7 × 2.0 × 0.15 × sin(45°)

F = 0.42 × 0.70710678

F = 0.2970 ≈ 0.30 N

Therefore, the total magnetic force on the 2 sides of the wire is 0.30 N

Option a) 0.30 N is the correct answer

Answer: At such high frequencies it is very difficult for a sound wave to propagate efficiently; indeed, above a frequency of about 1.25 × 1013 hertz it is impossible for longitudinal waves to propagate at all, even in a liquid or a solid

Answer:

Inside an atom are protons, electrons and neutrons. The protons are positively charged, the electrons are negatively charged, and the neutrons are neutral. Therefore, all things are made up of charges. For example, if you rub your shoe on the carpet, your body collects extra electrons.

Explanation:

The increase or decrease in the number of positive or negative charges changes the overall charge of the body.

Electric charge is the physical property of matter that causes them to experience a force in the presence of the electric field.

The net charge of a body is neutral when a number of positive and negative charges is equal in the body.

Therefore, the increase or decrease in the number of positive or negative charges changes the overall charge of the body.

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Answer:

14.1seconds approx

Explanation:

Given data

Distance= 59.1m

Your velocity= 2.35m/s

Walkway velocity= 1.85m/s

Total velocity= 2.35+1.85= 4.2m/s

We know that

Velocity= distance/time

time= distance/velocity

substitute

time= 59.1/4.2

time= 14.07

time=14.1seconds approx

Hence the time is 14.1seconds approx

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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The speed of the second marble must be 14.8 m/s so that the two marbles reach the ground at the same time.

The time taken by the first stone to reach the ground is calculated using the formula below:

h = ut + ¹/₂gt²

where:

From the data provided;

h = 30, u = 10m/s, g = 9.8 m/s

30 = 10t  + 0.5 * 9.8t²

30 = 10t + 4.9t²

4.9t² + 10t - 30 = 0

t = 1.65 s

For the second marble, time taken = 1.65 - 0.50

t = 1.15 s

Initial velocity, u will be:

30 = u(1.15)  + 0.5 * 9.8 * 1.15²

1.15u = 30 - 12.96

u = 14.8 m/s

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