Answer:
1. Evaporation
2. Filtration
3. Distillation
4. Chromatography
Explanation:
\(.\)
Give the systematic name for the following coordination compound or complex ion:
please leave an explanation and not just the answer. i'd like to understand why!!
The systematic name for the coordination compound or complex ion cannot be provided without specific information about its composition and structure.
The systematic naming of coordination compounds follows a set of rules established by the International Union of Pure and Applied Chemistry (IUPAC). The name is determined based on the type and number of ligands, the central metal ion, and any necessary prefixes or suffixes. To provide an accurate systematic name, we need to know the identity and number of ligands attached to the central metal ion, the coordination number of the metal ion, the charge of the complex ion, and any other relevant information about the compound's structure. Without this information, it is not possible to provide a specific systematic name. However, if you can provide the composition and structure of the coordination compound, I can guide you through the process of naming it using the IUPAC rules.
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What is the molality of a solution made by dissolving 2 moles of NaOH in 10
kg of water?
Answer:
0.2mol/kg
Explanation:
molality is the concentration of a solution in moles of solute per kilogram of solvent
moles of solute (NaOH) = 2moles
mass of solvent in kg. =10kg
Therefore molality. = 2moles/10 kg
=0.2mol/kg
Which of the following atoms will have the
most similar properties to the atom shown
below?
Atoms that have the same number of valence electrons (belong to the same group of the periodic table) have similar properties. Hydrogen and Helium are exceptions. The first shell is filled with 2 electrons which makes Helium a Noble Gas and Hydrogen is a gas thus not a Group 1 metal.
The given atom has 2 valence electrons (a group 2 element).
∴ the atoms with similar properties to that of the given atom would also have 2 valence electrons:
I - filled 1st shell thus noble gas ❌
II - 3 valence electrons ❌
III - 4 valence electrons ❌
IV - 2 valence electrons ✅
∴ atom IV has similar properties to the given atom.Checking my answer:
If we check the periodic table, the atom given is Be (Alkali Earth Metal)
I is He (Noble Gas)
II is Bo (Group 13)
III is C (Group 14)
IV is Magnesium (Alkali Earth Metal)
11. Samantha was asked to measure out 10 g of salt in a lab. She mistakenly measures out 15 g instead. Calculate
the percent error. Make sure your answer has the correct number of significant figures!
Answer:
50%
Explanation:
Expected measurement required = 10g
Actual measurement observed = 15g
The percentage error is given as proportion the difference between the actual and expected measurement or values and the expected value value expressed as a percentage.
[(Actual - Expected) / Expected] × 100%
[(15 - 10) / 10)] × 100%
(5 / 10) × 100%
0.5 × 100%
50%
Therefore, the percentage error in the measurement is 50%
The general format AB+CD→AD+BC represents a ____________ reaction.
A. exchange
B. replacement
C. decomposition
D. synthesis
Answer:
D aka synthesis
Explanation:
Got question and got it right :) have a good rest of your day
calculate n (in 2008) for carbon-14 in charred plant remains for two different eruptions of mt. vesuvius, 472 ad and 512 ad. (t1/2 for 14c = 5730 yr)a. 472 AD, n = _______ b. 512 AD, n = _________
The amount of carbon-14 remaining in charred plant remains from the 472 AD eruption was 0.57 ppt, and the amount remaining from the 512 AD eruption was 0.59 ppt, both calculated using the radioactive decay equation and assuming an initial amount of carbon-14 equal to the present-day level.
To calculate the amount of carbon-14 (n) in charred plant remains for the two different eruptions of Mt. Vesuvius in 472 AD and 512 AD, we need to use the radioactive decay equation:
n = n0 (1/2)^(t/T)
Where n0 is the initial amount of carbon-14, t is the time elapsed since the eruption (in years), T is the half-life of carbon-14 (5730 years), and n is the amount of carbon-14 remaining.
For the 472 AD eruption, we can assume that the charred plant remains had an initial amount of carbon-14 equal to the present-day level, which is 1 part per trillion (1 ppt). Thus, n0 = 1 ppt.
To calculate n, we need to know how much time has passed since the eruption. In 2008, the time elapsed since 472 AD is 2008 - 472 = 1536 years. Plugging in these values into the equation, we get:
n = 1 ppt * (1/2)^(1536/5730) = 0.57 ppt
Therefore, in 2008, the amount of carbon-14 remaining in the charred plant remains from the 472 AD eruption was 0.57 parts per trillion.
For the 512 AD eruption, we can use the same approach. Assuming an initial amount of carbon-14 equal to the present-day level (1 ppt), the time elapsed since the eruption in 2008 is 2008 - 512 = 1496 years. Plugging in these values into the equation, we get:
n = 1 ppt * (1/2)^(1496/5730) = 0.59 ppt
Therefore, in 2008, the amount of carbon-14 remaining in the charred plant remains from the 512 AD eruption was 0.59 parts per trillion.
In summary, the amount of carbon-14 remaining in charred plant remains from the 472 AD eruption was 0.57 ppt, and the amount remaining from the 512 AD eruption was 0.59 ppt, both calculated using the radioactive decay equation and assuming an initial amount of carbon-14 equal to the present-day level.
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3. What is the name for the items in this group as a whole: protons,
electrons, and neutrons? *
O A. Atomic Particles
B. Atomic Pieces
O C. Subatomic Particles
O D. Subatomic Charge
Answer: C
Explanation:
Because it just is and i got it right on my science test :D
the transfer of energy by waves is also known as _______
Answer:
wave
Explanation:
'Wave' is a common term for a number of different ways in which energy is transferred: In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields.
i hope this helps and your welcom
explain how your experimental procedure would change if you had a known concentration of acid and unknown concentration of base? use specific examples.
When you have a known concentration of acid and an unknown concentration of base, you can use an acid-base titration to determine the concentration of the base.
The experimental procedure for this would be as follows:Procedure:1. Measure a known volume of the acid (let's say 25 mL) into a flask using a pipette.2. Add a few drops of an indicator (phenolphthalein, for example) to the flask.3. Fill a burette with the base solution and record the initial volume of the base.4. Slowly add the base solution to the acid while stirring the flask.
The base solution should be added dropwise once you are close to the equivalence point. The point at which the indicator changes color (from colorless to pink) indicates the endpoint of the titration.5. Record the final volume of the base.6. Repeat the titration two more times.7.
Calculate the concentration of the base solution based on the volume of the base solution and the known concentration of the acid.
To calculate the concentration of the base solution, you would use the following formula: Molarity of base solution = (mL of base used x molarity of acid) / mL of acid used
For example, if you used 10 mL of base and 25 mL of acid with a concentration of 0.1 M, the molarity of the base would be:Molarity of base solution = (10 mL x 0.1 M) / 25 mL= 0.04 M
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Question 3 (True/False Worth 4 points)
(01.06 LC)
Steel is an example of a pure substance because it is made up of two different metals melted together.
O True
O False
Answer:
True
Explanation:
It forms a pure element, which I'm guessing is the same as pure substance
Make a prediction about why it has been useful for chemists and physicists to categorize elements on the periodic table of elements based on similar attributes.
The elements are categorized based on similar attributes so that it could be easier to collectively study the properties of the elements.
What is the periodic table?The periodic table is arrangement of the elements based on the atomic number of the elements. This implies that the elements are arranged in the order of increasing atomic numbers of the elements. The atomic numbers of the elements therefore tend to increase from left to right. This is how the Mendeleev table of elements was arranged.
Now, let us know that the periodic table is arranged in groups and periods. The elements in the same group have similar chemical properties while the elements in the same period only have the same number of shells or the same highest energy level.
Having said this, the elements are categorized based on similar attributes so that it could be easier to collectively study the properties of the elements.
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The molecule H2O can be correctly described as a?
1) compound.
2) compound and a molecule.
3) molecule.
If a solution had a pOH of 7. 39 then it has a pOH of?
The relationship between pH, pOH, and the concentration of hydroxide ions in a solution is given by:
pH + pOH = 14
If a solution has a pOH of 7.39, we can find its pH by subtracting the pOH from 14:
pH = 14 - pOH
pH = 14 - 7.39
pH = 6.61
Therefore, the solution has a pH of 6.61.
The pH scale, which describes the connection between pH, pOH, and the quantity of hydroxide ions, is an essential concept in chemistry. A pH of 7 is regarded as neutral, whereas values below 7 are acidic and those over 7 are basic (also called alkaline).
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Add 92.2 km to 9426 m and report the answer in
km.
92.2 km + 9426 m =
km
Help me plz
to convert m into km we have to divide it by 1000.so,
9426/1000=9.426km
92.2km+9.426km=101.626km.
Answer:101.6
Explanation:
PLSSS HELP WITH THIS ASAP
Answer:
the property of air shown in the figure describe A.mass
The following questions refer to the gas-phase decomposition of ethylene chloride.
C2H5Cl products
Experiment shows that the decomposition is first order.
The following data show kinetics information for this reaction:
Time (s) ln [C2H5Cl] (M)
1.0 – 1.625
2.0 –1.735
47. What is the rate constant for this decomposition?
A) 0.29/s
B) 0.35/s
C) 0.11/s
D) 0.02/s
E) 0.22/s
The rate constant of the reaction can be obtained as 0.11 s-1. Option C
What is the rate constant?We know that the rate constant that we have for the reaction would have to do with the speed with which there is the conversion of the reactants into the products as well as the disappearance of the reactants.
We can see that the table that shows how the reaction is progressing can be shown in the reaction that we have here and we need to show that the information that we have can be used to obtain the rate constant of the reaction as have been shown in the kinetics.
Using the formula;
ln[A] = ln[A]o - kt
[A] = concentration at time t
[A]o = initial concentration
k = rate constant
t = time taken
We have;
–1.735 = – 1.625 - k(1)
k = – 1.625 + 1.735
k = 0.11 s-1
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A solution of NaCl was prepared in the following manner: 0.0842 g of NaCl is massed out on an analytical balance. The solid is transferred to a 25.00 mL volumetric flask. Deionized water is added to the flask such that the bottom of the meniscus is at the line. A 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask using a volumetric pipet and diluted to volume. 6. Calculate the concentration of NaCl in the resulting solution in mg/L NaCl. (answer = 67.4 mg/L) 7. Calculate the concentration of NaCl in the resulting solution using propagation of error through the calculation. Use the manufacturer's tolerance values as the absolute error. The tolerances can be found in Chapter 2 of the Harris text. Assume a Class 1 balance and Class A glassware. Treat the tolerances as random error. (answer = 67.4+0.4 mg/L) 8. Identify 2 possible sources of random (indeterminate) error. Identify 2 possible sourses of systematic (determinate) error.
Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl
To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7. Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.
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The term half-life represents the time it takes Multiple Choice to dissolve half of the atoms in the lattice. for the Sun to decrease its size by 50 percent. for the parent atoms to decay into atoms half their original size. for half of the parent atoms to decay into daughter atoms.
The term half-life represents the time it takes for half of the parent atoms to decay into daughter atoms.
Half-life is the time needed for half of the parent atoms to decay into daughter atoms. Half-life is used to define the decay rate of radioactive materials, which is used to estimate the age of geological samples and archaeological artifacts and to establish the duration of radiation therapy for cancer patients.
The half-life of a radioactive element is fixed and is a feature of the substance. The following formula calculates the remaining amount of a radioactive element after a certain number of half-lives have passed: Remaining amount = Starting amount × (0.5)^(number of half-lives)The term "parent" refers to the original, undecayed radioactive substance, whereas the term "daughter" refers to the stable substance formed after radioactive decay. Half-life measurements are used in numerous fields, such as nuclear physics, biology, and medicine.
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How many moles are in 85.62 g of K,C03?
From the following items, which is closest in size to one mole of gas at stp?
At STP, a mole of pure gas is closest in size to a marble. As a tiny, solid material, a gram of gas at the STP is considerably smaller than a marble. D is the correct response.
At Standard Pressure and Temperature, 22.4 L of any gas will be required to hold 1 mole (STP). The Ideal Gas Law and a balanced chemical equation can be used to determine the amount or mass of gas consumed or created in a chemical process. In other words, the gas that has the greatest number of molecules of a certain gas at a given temperature will occupy the largest volume.
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Question: From the following items, which is closest in size to one mole of gas at STP?
A) A car
B) An elephant
C) A microwave
D) A marble
How is the polarity of a bond different from the polarity of a molecule?
Answer:
A polar bond is one where the charge distribution between the two atoms in the bond is unequal. A polar molecule is one where the charge distribution around the molecule is not symmetric. It results from having polar bonds and also a molecular structure where the bond polarities do not cancel.
Explanation:
The law of original horizontality explains:
A why rocks harden
B why rocks appear in layers
C how sedimentary rock forms
D why rock layers are always flat
EARTH SCIENCE
Answer:
c) how sedimentary rock forms
What are all of the ways can use the atomic number to find information about an atom?
Answer:
The symbol for an atom can be written to show its mass number at the top, and its atomic number at the bottom. To calculate the numbers of subatomic particles in an atom, use its atomic number and mass number: number of protons = atomic number. number of electrons = atomic number.
Question 5
The atomic number of an element tells you the number of ______
o Electrons & neutrons
O Electrons & Proton
O Protons & Neutrons
The atomic number of an element tells you the number of Electrons & Proton
What is a proton?
A stable subatomic particle with the symbol P, H+, or 1H+, a proton has an electric charge of +1 e. Its mass is 1,836 times greater than that of an electron and only slightly less than that of a neutron. Nucleons are the collective name for protons and neutrons, which have masses of roughly one atomic mass unit apiece.
The positively charged particles called protons are found in the atom's nucleus. The strong force, which is stronger at short distances, pulls the protons together while the electromagnetic force pushes them apart.
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A chemist dissolves 551. mg of pure barium hydroxide in enough water to make up 180. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits.______.
The pH of the solution of 551 mg of Barium Hydroxide and 180 mL water is 12.6.
What is a solution?A solution in chemistry is a specific kind of homogenous mixture made up of two or more components.
A solute is a material that has been dissolved in the solvent in such a combination.
The first step is to calculate the molarity of the barium hydroxide solution. We can use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
The molar mass of barium hydroxide [Ba(OH)²] is 171.34 g/mol. Therefore, the number of moles of Ba(OH)² in 551 mg (0.551 g) can be calculated as:
moles of Ba(OH)² = mass / molar mass = 0.551 g / 171.34 g/mol = 0.003214 mol
The volume of the solution is 180 mL, which is equivalent to 0.180 L. Therefore, the molarity of the barium hydroxide solution is:
Molarity = 0.003214 mol / 0.180 L = 0.01786 M
Barium hydroxide is a strong base that completely dissociates in water to give barium ions (Ba²) and hydroxide ions (OH⁻):
Ba(OH)²⁺ (s) → Ba²⁺ (aq) + 2OH⁻ (aq)
In an aqueous solution, the hydroxide ions can react with water to produce hydroxide ions and hydronium ions (H₃O⁺):
OH⁻ (aq) + H₂O (l) → H₃O⁺ (aq) + OH⁻- (aq)
Since the concentration of OH- ions in the solution is twice the concentration of Ba(OH)₂, we can use the following equation to calculate the hydroxide ion concentration:
[OH-] = 2 x Molarity of Ba(OH)₂ = 2 x 0.01786 M = 0.0357 M
Now, we can use the equation for the ion product constant of water to calculate the hydronium ion concentration:
Kw = [H₃3O⁺][OH⁻] = 1.0 x 10⁻¹⁴
[H₃O⁺] = Kw / [OH⁻] = 1.0 x 10⁻¹⁴ / 0.0357 = 2.801 x 10⁻¹³ M
Finally, we can calculate the pH of the solution using the equation:
pH = -log[H₃O⁺] = -log(2.801 x 10⁻¹³) = 12.552
Therefore, the pH of the solution is 12.6 (rounded to one decimal place).
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What is the ionic equation of water? (even though water is covalent)
A chemical equation known as an ionic equation expresses the electrolytes in aqueous solution as dissociated ions. Similar to a molecular equation, it expresses substances as molecules.
The ionic species are denoted in the equation by the letters (aq) to show that they are in an aqueous solution. Typically, this is a salt that has been dissolved in water.On both the reactant and product sides of the equation, some ions in an entire ionic equation may not undergo chemical change.
A spectator ion is not represented by an ionic equation. When an alkali and an acid are mixed together, water is created when the hydrogen ions from the acid join with the hydroxide ions from the alkali.
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What is the percent sodium in sodium chloride?
The total mass of sodium chloride is 58.44 g/mol.
The mass of sodium is 22.99 g/mol.
To find the percent sodium in sodium chloride can be found by dividing the amounts.
\(\frac{22.99}{58.44}\approx0.39\)Therefore, the percent sodium is 39%.
propose two different combinations of bonding features to account for an ihd of 5 in a molecule consisting of c and h atoms and one o atom only
Intermolecular forces are the forces that exist between molecules. These forces are responsible for the interactions between molecules, and they determine the physical and chemical properties of matter. Without intermolecular forces, matter would not exist as we know it.
Intermolecular forces are classified into four main types: dispersion forces, dipole-dipole forces, hydrogen bonding, and ion-dipole forces. Dispersion forces are the weakest of the four, but they are also the most common. Dispersion forces exist between all molecules, and they are responsible for the forces of attraction between molecules. Dipole-dipole forces are slightly stronger than dispersion forces, and they exist between molecules that have dipoles. Hydrogen bonding is the strongest of the intermolecular forces, and it exists between molecules that have hydrogen atoms bonded to nitrogen or oxygen atoms. Ion-dipole forces are the strongest of the intermolecular forces, and they exist between molecules that have an ionic charge.
Intermolecular forces are important because they determine the physical and chemical properties of matter. Without these forces, matter would not exist as we know it.
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why is OH on the outside of the lewis structure for methanol?
In the Lewis structure of methanol (CH3OH), the OH group is placed on the outside because it is an important functional group that influences the chemical properties and reactivity of the molecule.
The Lewis structure is a representation of a molecule that shows the arrangement of atoms and valence electrons. In methanol, carbon (C) is the central atom bonded to three hydrogen (H) atoms and one oxygen (O) atom. The oxygen atom forms a single bond with carbon and also has two lone pairs of electrons.
The placement of the OH group (hydroxyl group) on the outside of the Lewis structure is significant because it determines the chemical behavior of methanol. The OH group consists of an oxygen atom bonded to a hydrogen atom and represents the presence of an alcohol functional group.
In organic chemistry, functional groups are specific arrangements of atoms within a molecule that give rise to characteristic chemical reactions and properties. The presence and position of functional groups can greatly influence the behavior and reactivity of a compound. In the case of methanol, the hydroxyl group provides the molecule with its characteristic properties.
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soft drink bottles are made of polyethylene terephthalate (pet), a polymer composed of carbon, hydrogen, and oxygen. if 1.9022 g pet is burned in oxygen it produces 0.6585 g h2o and 4.0216 g co 2. what is the empirical formula of pet?
If 1.9022g pet is burned in oxygen it produces 0.6585 g h2o and 4.0216 g Co2. The empirical formula of PET is \(C_{10}\)\(H_{8}\)\(O_{5}\).
We are told that 1.250 g of PET is burned to produce 0.4328 g \(H_{2}\)O and 2.643g C \(O_{2}\).
By using percentage composition we can determine the masses of carbon dioxide and hydrogen from pet.
% composition = \(\frac{molar mass of element in compound }{molar mass of compound }\) x 100%
Now for Carbon.
% composition C = \(\frac{12.01 g/mole}{12.01 g/mole + (2 x 16.00 g/mol)}\) x 100% = 27.29%
Now multiplying the mass of carbon dioxide by percentage composition we can get the mass of C.
2.643g x 27.29% = 0.7213g
% composition H = \(\frac{2 x 1.01 g/mol }{16.00 g/mol + ( 2 x 1.01 g/mol)}\) x 100%
Now multiplying the mass of water by percentage composition of hydrogen we can get the mass of H.
0.4328 g × 11.21 % = 0.04852 g
By subtracting the mass of carbon and hydrogen from the mass of the PET i.e. 1.250 g we can get the mass of oxygen in PET.
1.250 g − 0.04852 g − 0.7213 g = 0.4802 g
Let's calculate the moles of each component.
Moles of carbon = 0.7213/ 12.01 g/mol = 0.06006 mol
Moles of hydrogen = 0.0485/ 1.01 g/mol = 0.04804 mol
Moles of oxygen = 0.4802/ 16.00 g/mol = 0.03001 mol
Now, to get the subscripts for the empirical formula, lets divide the moles of each element with the lowest number of moles.
Carbon = 0.06006/0.03001 = 2
Hydrogen = 0.04804/0.03001 = 1.6
Oxygen = 0.03001/0.03001 = 1
We see that 1.6 is not a whole integer and is equivalent to the fraction 8/5. So the empirical formula become \(C_{2}\)\(H\frac{8}{5}\)O which seems inappropriate as our empirical formulas do not include fractions. So, to fix this problem, let's multiply all the subscripts with the fraction 5.
The final empirical formula is \(C_{10}\)\(H_{8}\)\(O_{5}\).
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