will mark brainlist need help
Hydrochloric acid (HCl) and sodium sulfide react by forming the gas Hydrogen sulfide and aqueous sodium chloride. Write the complete and net ionic equation for the reaction

Answer:

a is oxidation

b is reduction

c is reduction

d is oxidation

hope it helps you

Answer:

V₁ = 0.025 Liters = 25 ml

Explanation:

P₁ = 6 Atm      P₂ = 7800mm/760mm/Atm = 0.01 Atm

V₁ = ?              V₂ = 29 Liters

T₁ = 115 K        T₂ = 225 K

P₁V₁/T₁ = P₂V₂/T₂ => V₁ = P₂V₂T₁/P₁T₂

V₁ = (0.01 Atm)(29L)(115K)/(6 Atm)(225K) = 0.025 Liters = 25ml

Answer:

12.0 grams of hydrogen would produce 12.0 grams of water.

Explanation:

The reaction between hydrogen and oxygen to form water can be represented as follows:

2H2(g) + O2(g) -> 2H2O(l)

From the equation, it can be seen that for every 2 grams of hydrogen, 1 gram of oxygen is required to produce 2 grams of water. Therefore, if 12.0 grams of hydrogen reacts with oxygen, 12.0/2 = 6.0 grams of oxygen would be required. This amount of oxygen would produce 2 * 6.0 = 12.0 grams of water.

Answer:

Explanation:

the grams of water produced= 44 grames  

There are 5.79 x 10²¹ representative particles in 2.62g of the molecular compound.

Determine the number of moles of the molecular compound.

We can use the formula:

moles = mass / molar mass

where mass is 2.62g and molar mass is 273g/mol.

moles = 2.62g / 273g/mol

moles = 0.00961 mol

Use Avogadro's number to convert from moles to representative particles.

We can use the formula:

representative particles = moles x Avogadro's number

where Avogadro's number is 6.022 x 10²³.

representative particles = 0.00961 mol x 6.022 x 10²³

representative particles = 5.79 x 10²¹

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Each element is given its own chemical symbol, like H for hydrogen or O for oxygen. Chemical symbols are usually one or two letters long. Every chemical symbol starts with a capital letter, with the second letter written in lower case. For example, Mg is the correct symbol for magnesium, but mg, mG and MG are wrong...

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Answer:

a. the system is at equilibrium.

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

\(H_2+Br_2\rightleftharpoons 2HBr\)

Thus, the law of mass action is given by:

\(Keq=\frac{[HBr]^2}{[H_2][Br_2]} =57.6\)

Nonetheless, for the given point of 4.67 × 10^-3M bromine gas, 2.14 × 10^−3 hydrogen gas, and 2.40 × 10^−2M hydrogen bromide gas we should compute the reaction quotient in order to know whether the direction of the reaction is to left or to right, thus:

\(Q=\frac{[HBr]^2}{[H_2][Br_2]} =\frac{(2.40x10^{-2})^2}{(4.67x10^{-3})(2.14x10^{-3})} \\\\Q=57.6\)

Therefore, since Keq=Q, we say that the system is at equilibrium, for that reason, the answer is a.

Best regards.

Answer:

that they all dissolved went on watef

Q_w = 307.3 J

C_m = .233 J/g•K

%error = 39.95%

For simplicity's sake, I'm relabeling

Q_w as Q1

m_w as m1

C_w as c1

T_eq as T2

T_w as T1

Q_m as Q2

m_m as m2

C_m as c2

experimental value as exp

actual value as actual

Question 1

Q1 = m1•c1•(T2-T1)

Identify what you know

m1 = 124g

c1 = 4.13 J/g • K

T2 = Final temperature = 22.3°C

T1 = Initial temperature = 21.7°C

Convert Celsius to Kelvin (C+273.15=K)

T2 = 295.45 K

T1 = 294.85 K

Plug in

Q1 = 124g•(4.13 J/g•K)•(295.45K - 294.85K)

Solve

Q1 ≈ 307.3 J

Question 2

-Q1 = Q2 = m2•(c2)•(T2-100)

Ignore Q2 for a second, and you're left with

-Q1 = m2•(c2)•(T2-100)

which is the same thing.

Identify what you know

Q1 = 307.3 J

m2 = 17g

T2 = 22.3°C

Plug in

-(307.3J) = 17g • c2 • (22.3°C-100°C)

Solve

-307.3 J = (-1320.9 g•°C) • c2

c2 = .233 J/g•°C or J/g•K (I'll explain later)

Question 3

%err = ((exp - actual)/actual) • 100%

Identify what you know

exp = .233 J/g•K

actual = .388 J/g•K

Plug in

%err = ((.233 J/g•K - .388 J/g•K)/ .388 J/g•K) • 100%

Solve

%err = -39.95 %

Take the absolute value

%err = 39.95%

Referring to earlier change in units:

The reason we can not use the K value of T2 (295.45K) is because the formula provided (T2-100) does not account for T2 being in K. It only accounts for T2 being in °C.

Answer:

Commercially, 2-methylpentenal is synthesized by the aldol condensation of propanal in the presence of liquid base like KOH or NaOH in stoichiometric amount,,. Under optimum reaction conditions, 99% conversion of propanal is achieved with 86% selectivity of 2-methylpentenal using liquid base.

Explanation:

hope this helps

Answer:

HMM, what the person above said.

Answer:

Volume of stock solution needed = 6.0299 mL

Explanation:

Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.

This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.

Data:

M1 = 6.01 M stock solution concentration

M2 = 0.3624 M diluted solution concentration

V2 =100 mL diluted solution volume

V1 = ? stock solution volume

M1 * V1 = M2 * V2

\(V1=\frac{M2*V2}{M1} =\frac{0.3624M*100mL}{6.01M} =6.0299 mL\)

Answer:

HNO3 is a strong acid

HCl is also a strong acid

NaCl is a salt so it is neither a strong acid nor a strong base

Ca(OH)3 is a strong base

Explanation:

A diprotic weak base (B) has pb values of 3.722 (pb1) and 6.514 (pb2). The pH at which the dissociation of the first and second proton of a diprotic weak base is equal to its pKb1 and pKb2 values respectively. The pH at which the concentration of all the three forms of the base (B, BH+ and BH22+) is equal is given by the midpoint pH, pKb1 and pKb2, and is calculated using the equation:pH = 1/2 (pKb1 + pKb2)

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Answer:

Talc powder suspended in air

Answer:

165.385 g/mol

Answer:

न्द्न्द्ज्द्ज्फ्ज्फ्ज

Answer:

The image represents liquid

Answer:

First, we need to determine the molar mass of HCl.

The molar mass of HCl = the mass of hydrogen (1.008 g/mol) + the mass of chlorine (35.45 g/mol) = 36.45 g/mol.

Next, we can use Avogadro's number (6.02 x 10^23 molecules/mol) to convert the number of molecules to moles:

6.02 x 10^24 molecules / 6.02 x 10^23 molecules/mol = 10 moles

Finally, we can use the molar mass to convert moles to grams:

10 moles x 36.45 g/mol = 364.5 grams

Therefore, the mass of 6.02 x 10^24 molecules of HCl is 364.5 grams.

Answer:Nothing

Explanation:

The answer is nothing the tempatature isnt matched with the degrees this is false

The balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is 2S₈ + 16O₂ → 16SO₃.

Balancing chemical equations involves the addition of stoichiometric coefficients to the reactants and products.

The balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is determined as;

2S₈ + 16O₂ → 16SO₃

From the reactants side we can see that sulfur is 16 and also 16 in the product side. The number of oxygen in the reactant side is 32 and also 32 in the product side.

Thus, the balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is 2S₈ + 16O₂ → 16SO₃.

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Answer: The law of proportion states that elements combine in whole number ratios. The gram readings for K are multiples of each other, both in grams and moles.

Let us compare the ratios:

2.44 grams/1.22 grams = 2

4.89 grams/2.44 grams = 2

Therefore, Potassium always combines with Oxygen in a ratio of 2  is to 1.

The equilibrium concentrations of the gases are:

[H2] = 0.865 M, [CO2] = 0.865 M, [CO] = 1.135M ,[H2O] = 1.135 M.

The sum of the molar concentrations of the reactants (H2 and CO2) is equal to the sum of the molar concentrations of the products (CO and H2O), as expected for a reaction at equilibrium.

The equilibrium concentrations of the four gases can be determined using the equilibrium constant expression and the initial concentrations of the reactants.

The equilibrium constant expression for the reaction is:

K_eq = [CO][H2O]/[H2][CO2]

where the concentrations are in units of M (molarity).

We are given that K_eq = 0.771 at 650 degrees Celsius.

We start by setting up an ICE table (Initial, Change, Equilibrium) to determine the equilibrium concentrations:

                 H2         CO         CO  H2O

Initial 2.00 2.00 0 0

Change    -x            -x       +x     +x

Equil. 2.00-x 2.00-x x x

where "x" is the change in concentration from the initial state to the equilibrium state, and we assume that the reaction proceeds to equilibrium.

Substituting the equilibrium concentrations into the equilibrium constant expression and solving for "x", we get:

K_eq = [CO][H2O]/[H2][CO2] = x^2 / (2.00 - x)^2 = 0.771

Solving for "x" using the quadratic formula, we get:

x = 1.135 M

Therefore, the equilibrium concentrations of the gases are:

[H2] = 0.865 M

[CO2] = 0.865 M

[CO] = 1.135 M

[H2O] = 1.135 M

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The number of moles containing 2.66 × 10¹⁵ molecules of CO is

4.41 × 10 ⁻⁹. One mole of Co is 28 g. Hence, mass of CO 4.41 × 10 ⁻⁹ moles is 1.23 × 10⁻⁷ g.

Any substance  that contains   6.022 × 10²³ number of atoms is called ne mole of that substance. This number is called Avogadro number. Hence, one mole of every elements contains Avogadro number of atoms.

CO is a covalent compound formed from carbon and oxygen. The number of molecules  in one mole of CO is equal to Avogadro number. Mass of a compound  with one mole of amount is called its molar mass.

Number of molecules of CO in one mole  =  6.02 × 10²³  

Number of moles of 2.66 × 10¹⁵ molecules  = 2.66 × 10¹⁵/  6.02 × 10²³   = 4.41 × 10 ⁻⁹ moles.

Then mass of one mole of CO =  28 g/mol

mass of 4.41 × 10 ⁻⁹ moles of CO = 4.41 × 10 ⁻⁹ ×  28 = 1.23 × 10⁻⁷ g

Therefore, mass of CO in  2.66 × 10¹⁵ molecules of CO is 1.23 × 10⁻⁷ g.

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Hi. You did not provide any response options. However, a PCR reaction proceeds as follows.

After the primers are added to the test tube containing the PCR components. This tube is placed in a device called a thermocycler. At that moment, the stage called denaturation will begin, where the thermocycler increases the temperature to the point of breaking the hydrogen bonds that hold the two strands of DNA together. The thermal cycler increases the temperature up to 96°C.

After that, the second step of the reaction begins. At that moment, the thermal cycler lowers the temperature to 55º - 65ºC, which is the ideal temperature for the primers to be able to attach themselves to the DNA strands, preparing them for the presence of the polymerase.

After that, the thermocycler raises the temperature to 72ºC, which is the ideal temperature for the DNA polymerase to work. At this stage, the DNA polymerase will use the DNA strand and the primer to build a new DNA strand, which will be annealed to the DNA strand used as a template.

These three steps will be repeated about 35 times, generating many copies of DNA.

The partial charges on each fluorine atom are negative. Option B) The central O atom is the correct answer. Option B

The partial charges in a molecule are determined by the electronegativity values of the atoms involved. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond. In the case of \(F_2O\), fluorine (F) is more electronegative than oxygen.

Fluorine is the most electronegative element on the periodic table, meaning it has a high ability to attract electrons. Oxygen is also relatively electronegative but less so than fluorine. When fluorine atoms bond with oxygen, the shared electrons will be pulled more towards the fluorine atoms, creating a polar covalent bond.

In \(F_2O\), each fluorine atom will pull the shared electrons towards itself, resulting in a higher electron density around the fluorine atoms. This creates a region of partial negative charge around the fluorine atoms.

Conversely, the oxygen atom will have a region of lower electron density and, therefore, a partial positive charge. This is because the shared electrons spend more time around the fluorine atoms due to their higher electronegativity.

Option B

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Consider the equation : 2NOCl(g) --> 2NO(g) + Cl₂(g) , the relative rate for NO is Δ[NO] = 2Δ[Cl₂].

The chemical equation is as follows :

2NOCl(g) --> 2NO(g) + Cl₂(g)

The Rate = change in the concentration of the species or the change in the time.

The rate law for the equation is as :

The rate law = k[NO] [ Cl₂]²

The rate law  for the chemical reaction is the expression that will provides the relationship in between the reaction rate and the concentrations of the reactants that is participating in it.

The relative rate for NO is :

Δ[NO] = 2Δ[Cl₂].

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Answer:

16875 J

Explanation:

KINETIC ENERGY EQUATION = 1/2 m v^2

= 1/2 times mass times velocity of metres per second^2 (speed)

= 1/2 times 150 times by 15^2

= 16875 J (joules)