Within working memory, "helpers" like the visuospatial buffer and articulatory rehearsal loop
provide short-term storage of items likely to be needed soon by the central executive.

The best explanation for the ability of carbon to form four bonds with other atoms is option A, which states that carbon has 4 valence electrons.

Valence electrons are the outermost electrons in an atom and are involved in chemical bonding. Carbon has 6 electrons in total, with 2 in the inner shell and 4 in the outer shell. These 4 valence electrons are available for bonding with other atoms, allowing carbon to form up to four covalent bonds, either with other carbon atoms or with other elements such as hydrogen, nitrogen, and oxygen. This ability to form multiple bonds and complex structures is fundamental to the chemistry of life, allowing for the creation of diverse and complex organic molecules necessary for life processes.

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During the light reactions water is oxidized to O2. hydrogen go to Used in the reduction of NADP+.

The photolysis process, sometimes referred to as the light reaction, occurs when light is present. Typically, it occurs in the chloroplasts' grana. Pigment molecules are present in photosystems. One of the key pigments in plants that actively participates in light-related processes like photosynthesis is chlorophyll. In the chloroplast of the mesophyll cells of the leaves, a light-dependent process takes place. The stacked disc-like structures known as thylakoids make up the double-membraned cell organelles known as chloroplasts. The membrane of these thylakoids contains the pigment chlorophyll, which is necessary for the process and is where the light reaction takes place.

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Element “X” belongs to family 2A, meaning it is part of the family that includes elements such as Be and Mg. These elements will all have 2 valence electrons and can be represented by the following Lewis diagram:

Element “Y” belongs to family 5A, meaning it is part of the family of elements that includes elements such as N and P. These elements will all have 5 valence electrons and can be represented by the following Lewis diagram:

Atoms from these two families will usually react with each other by losing or gaining valence electrons to create stable ions (an ion is what we call an atom/particle that has a charge). These stable ions form by the atoms either losing or gaining electrons until they have the same number of valence electrons as the nearest Noble Gas. This means that each ion will have a full valence shell (usually consisting of 8 electrons), often referred to as a “stable octet”, and this process of creating stable ions is often called the “octet rule”.

Atoms with fewer that 4 valence electrons will normally have a weak hold on their valence electrons and will tend to lose their valence electrons when forming ions.

Atoms with 4 or more valence electrons will normally have a strong hold on their valence electrons and will tend to gain electrons when forming ions.

The charge on the ion arises from the fact that, initially, the atom is electrically neutral because it has the same number of electrons (negative charges) as protons (positive charges). By losing electrons, the atom will end up with more protons (positive charges) than electrons (negative charges) and will form an ion with an overall positive charge. By gaining electrons, the atom will end up with more negative electrons than positive protons becoming an ion with an overall negative charge.

So, an atom of element “X”, with only 2 valence electrons, must lose its 2 valence electrons (which will be gained by element “Y”) to form a stable ion with a 2+ charge (losing two electrons leaves the ion with 2 more positive charges (protons) than negative charges, so a net charge of 2+).

An atom of element “Y”, with 5 valence electrons, must gain 3 electrons (from element “X”) to form a stable ion with a 3- charge (gains 3 extra negative charges).

We can show this process using Lewis diagrams:

From this set of diagrams you can see that in order to create stable ions of both “X” and “Y” we need these atoms to react with each other in a 3:2 ratio (we need 3 atoms of X for every 2 atoms of Y). This means that the resulting chemical formula of the compound will be:

Now, we will look at a short cut that can help you figure this out without having to draw Lewis diagrams.

Compounds are electrically neutral, meaning they must contain equal numbers of positive and negative charges. For compounds consisting of oppositely charged ions, this means that the total charge of the negative ions must be equal to the total charge of the positive ions. In other words the ions must combine in a ratio that makes their charges add to zero.

If we look at the compound we just made, X3Y2, we can confirm this:

So, now you can you predict the formula of simple ionic compounds:

from the family of elements, determine the number of valence electrons each element has

determine the charge of the ions that each atom will form using the octet rule (or look on the periodic table, most will tell you the stable ionic charges that each element can form)

determine the ratio of positive ions to negative ions that results in an overall charge of zero

Example,

What is the formula of a compound produced when an element from family 3A combines with an element from family 7A?

At 25°C, the vapor phase is enriched in \(CS_2\) by an enrichment factor of 6.4.

To determine the enrichment factor of the vapor phase in \(CS_2\), we first need to calculate the mole fraction of \(CS_2\) in the mixture.

The moles of \(CS_2\) can be calculated as:

moles of \(CS_2\) = mass of \(CS_2\) / molar mass of \(CS_2\)

moles of  \(CS_2 = \frac{45.68}{76.13}\)

moles of \(CS_2\) = 0.6 mol

The moles of \(CH_3CN\) can be calculated as:

moles of \(CH_3CN\) = mass of \(CH_3CN\) / molar mass of \(CH_3CN\)

moles of \(CH_3CN\) \(= \frac{16.43}{41.06}\)

moles of \(CH_3CN\) = 0.4 mol

The total moles of the mixture can be calculated as the sum of the moles of \(CS_2\) and \(CH_3CN\):

total moles = moles of \(CS_2\) + moles of \(CH_3CN\)

total moles = 0.6 mol + 0.4 mol

total moles = 1.0 mol

The mole fraction of \(CS_2\) can be calculated as the moles of \(CS_2\) divided by the total moles:

mole fraction of \(CS_2\) = (moles of \(CS_2\)) ÷ (total moles)

mole fraction of \(CS_2\) \(=\frac{0.6}{1.0}\)

mole fraction of \(CS_2\) = 0.6

Now, we need to determine the vapor pressure of each component in the mixture at 25°C. The vapor pressure of \(CS_2\) at 25°C is 320 mmHg and the vapor pressure of \(CH_3CN\) at 25°C is 75 mmHg.

The partial pressure of \(CS_2\) in the vapor phase can be calculated using Raoult's law:

partial pressure of \(CS_2\) = (mole fraction of \(CS_2\)) * (vapor pressure of \(CS_2\))

partial pressure of \(CS_2\) = \(0.6*320\)

partial pressure of \(CS_2\) = 192 mmHg

The partial pressure of \(CH_3CN\) in the vapor phase can be calculated similarly:

partial pressure of \(CH_3CN\) = (mole fraction of \(CH_3CN\))*(vapor pressure of \(CH_3CN\))

partial pressure of \(CH_3CN\) \(= 0.4*75\)

partial pressure of \(CH_3CN\) = 30 mmHg

Therefore, the enrichment factor of the vapor phase in \(CS_2\) can be calculated as:

enrichment factor = (partial pressure of \(CS_2\)) ÷ (partial pressure of \(CH_3CN\))

enrichment factor \(= \frac{192}{30}\)

enrichment factor = 6.4

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1. The equilibrium constant for the reaction given that [H₂O] = 1 M and [H₂] = 4.5 M is 91.125

2. The equilibrium constant lies to the right

The following data were obtained from the question:

The equilibrium constant for the raection can be obtained as illustrated as follow:

Equilibrium constant = [Product]ᵐ / [Reactant]ⁿ

Equilibrium constant  = [H₂]³ / [H₂O]³

Equilibrium constant = 4.5³ / 1³

Equilibrium constant = 91.125

From the above calculation, we can see that the equilibrium constant (i.e 91.125) is far greater than one. Thus, the equilibrium constant lies to the right.

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Answer:

Because it is made of a hardened liquid that is extremely sensitive to heat

Explanation:

Brainliest?

The concentration after 3.00 hours is 2.88 m.

To solve this problem, we will use the formula for the rate of a first-order reaction:

rate = k[A]

where k is the rate constant and [A] is the concentration of the reactant. We are given k = 0.02911(m/hr) and [A] = 3.13 m. We want to find the concentration after 3.00 hours, which we'll call [A'].

We can use the integrated rate law for a first-order reaction:

ln[A'] = -kt + ln[A]

where ln is the natural logarithm. Plugging in the given values, we get:

ln[A'] = -0.02911(m/hr) * 3.00 hr + ln[3.13 m]

Simplifying, we get:

ln[A'] = -0.08733 + 1.147

ln[A'] = 1.059

To solve for [A'], we'll take the inverse natural logarithm of both sides:

[A'] = e^(1.059)

[A'] = 2.884

Rounding to three significant figures, we get:

[A'] = 2.88 m

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Answer:

2.3 L

Explanation:

A change in pressure-volume at constant temperature is described by the Boyle's law. The mathematical relationship between initial pressure and volume (P₁ and V₁) and final pressure and volume (P₂ and V₂) is given by:

P₁V₁ = P₂V₂

We have the following data:

initial pressure: P₁= 2.5 atm

initial volume: V₁ = 9.1 L

final pressure: P₂= 9.8 atm

Thus, we introduce the data in the mathematical expression and calculate the final volume V₂, as follows:

V₂ = P₁V₁/P₂ = (2.5 atm x 9.1 L)/9.8 atm = 2.3 L

Therefore, the volume of the canister is 2.3 L.

Answer:

22,600 J or 22.6 kJ

Explanation:

Answer:

3.2 MJ or 3200KJ or 3200000J

Explanation:

To calculate the Kinetic energy, we use the following formula:

\( \alpha ke \: = \frac{1}{2} m {v}^{2} \)

Where, ∆KE = change in kinetic energy

m = mass

v = velocity

From our question, we have

m = 16000 kg

v = 20 m/s

Substitute the values into the equation gives,

\(ke \: = \: \frac{1}{2} \: \times \: 16000 \: \times \: {20}^{2} \\ = 3200000 \: joules\)

Therefore, the Kinetic energy of the car

∆KE = 3200000 J = 3200 KJ = 3.2 MJ

And we have the solution to our problem.

Rn-220 undergoes sequential decays of α, α, β, α. Here is the partial decay series:

Rn-220 (Radon-220) undergoes α decay, producing:

Rn-216 (Radon-216) and He-4 (Helium-4) as the α particle.

Rn-216 (Radon-216) undergoes α decay, producing:

Rn-212 (Radon-212) and He-4 (Helium-4) as the α particle.

Rn-212 (Radon-212) undergoes β decay, producing:

Po-212 (Polonium-212) and an electron (β particle).

Po-212 (Polonium-212) undergoes α decay, producing:

Pb-208 (Lead-208) and He-4 (Helium-4) as the α particle.

So, the partial decay series for Rn-220 undergoing the sequential decays α, α, β, α is:

Rn-220 → Rn-216 + He-4 → Rn-212 + He-4 → Po-212 + β + νe → Pb-208 + He-4

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Answer:

D. P

Hope it works!

Explanation:

Lactose is a disaccharide carbohydrate molecule, composed of two monosaccharide units, glucose and galactose, linked by a β(1→4) glycosidic bond. It is commonly found in dairy products and serves as an energy source for organisms capable of digesting it. In order to be broken down and utilized, lactose must be hydrolyzed by the enzyme lactase into its individual monosaccharides. Lactose intolerance occurs when individuals lack sufficient lactase activity, leading to difficulty digesting lactose and subsequent gastrointestinal symptoms.

Lactose is complete molecule classified as a disaccharide, consisting of two simple sugar units, glucose and galactose, joined together by a beta-glycosidic bond. It is commonly found in milk and dairy products and is responsible for the sweet taste of milk. Lactose is an important source of energy and nutrition for infants and young animals. However, some people are unable to digest lactose due to a deficiency of the enzyme lactase, which breaks down lactose into its component sugars. This can lead to lactose intolerance, which can cause digestive symptoms such as bloating, gas, and diarrhea.

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Answer:

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

Atomic Structure

Stoichiometry

Explanation:

Step 1: Define

Identify

[Given] 10.1 g Ne

[Solve] atoms Ne

Step 2: Identify Conversions

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne

Protein synthesis is a process that is generated within cells where different organelles and genetic components are involved through which proteins are generated.

The biosynthesis of proteins will be given by different parts, beginning with the translation of the genetic material. It will be given by different steps:

1. mRNA binds to ribosomes and the aminoacyl-tRNA to be associated to the first codon of the mRNA is associated.

2. The elongation of the polypeptide chain occurs, in which the amino acids are joined

3. The elongation is finished when the termination codons are reached.

4. The translation components are released and post-translational modifications are started.

5. The folding, glycosylation and modification of amino acids occur

6. Finally, the protein is released to generate its function

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Answer:

B

Explanation:

Most of these are opinions. the reason that it is not d is because it is not something that can be scientifically proven. b can be proven by facts. hope this helps!

The pH of a 10.00 mL H2SO4 solution with an average concentration of 0.1 M is 0.70.

To calculate the pH of a 10.00 mL H2SO4 solution, we need to know the concentration of the H2SO4 solution. Assuming that the H2SO4 solution dissociates 100% twice, the concentration of H+ ions will be twice the concentration of H2SO4.

Let's assume that the average concentration of the H2SO4 solution is 0.1 M. Then, the concentration of H+ ions will be 0.2 M.

Now we can use the formula for pH:

pH = -log[H+]

pH = -log(0.2)

pH = 0.70

Therefore, the pH of a 10.00 mL H2SO4 solution with an average concentration of 0.1 M is 0.70.

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Answer:

Non-zero digits are always significant.

Any zeros between two significant digits are significant.

A final zero or trailing zeros in the decimal portion ONLY are significant. If a number ends in zeros to the right of the decimal point, those zeros are significant.

Explanation:

1.138 has 4 significant figures, which are 1, 1, 3 and 8. The numbers after the decimal point are decimals and are significant figures.

The number of mole of Al₂O₃ formed when 4.0 moles of O₂ reacts, given the reaction is 2.67 moles

From the given stoichiometry of the reaction (i.e 6.0 moles of Al reacts with 4.0 moles of O₂ to form Al₂O₃), we can see that O₂ is the limiting reactant.

Knowing that O₂ is the limiting reactant we can easily determine the number of moles of Al₂O₃ formed when 4.0 moles of O₂ reacts as follow:

4Al + 3O₂ -> 2Al₂O₃

From the balanced equation above,

3 moles of O₂ reacted to produce 2 moles of Al₂O₃

Therefore,

4 moles of O₂ will react to produce = (4 moles × 2 moles) / 3 moles = 2.67 moles of Al₂O₃

Thus, we can conclude from the above calculation that the number of moles of Al₂O₃ formed is 2.67 moles

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Answer: 2.67

Explanation:

Answer:

The answer is

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume of copper = 14.75 cm³

Density = 8.96 g/cm³

The mass is

mass = 8.96 × 14.75

We have the final answer as

Hope this helps you

The wavelength of light absorbed by [Co(NH3)6]3 can be determined by looking at its absorption spectrum. The absorption spectrum is a graph that shows the amount of light absorbed by a substance at different wavelengths.

In this case, the wavelength of light absorbed by [Co(NH3)6]3 falls between 2.90×102 nm and 7.70×102 nm. This range corresponds to the visible region of the electromagnetic spectrum, meaning that [Co(NH3)6]3 absorbs visible light. The exact wavelength of light absorbed by [Co(NH3)6]3 depends on the specific electronic transitions that occur in the complex. However, based on the available information, we can conclude that the wavelength falls within the range of 2.90×102 nm and 7.70×102 nm. The wavelength of light absorbed by [Co(NH3)6]3+ can be determined using the available hints. As the hint suggests, the wavelength lies between 2.90×10² nm and 7.70×10² nm. This indicates that the compound absorbs light in the visible spectrum, resulting in its characteristic color. To determine the exact wavelength, you would need to perform a spectroscopic analysis or consult a reference source with the specific data. However, based on the given range, it can be concluded that [Co(NH3)6]3+ absorbs light with a wavelength between 290 nm and 770 nm.

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Answer:

creo que es el gas natural

Answer:

When ions are made of a single atom, such as Li+1, they are called monatomic ions

Explanation:

Any atom or molecule with a net charge, either positive or negative, is known as an ion. An ion consisting of a single atom is a monoatomic ion; an ion consisting of two or more atoms is referred to as a polyatomic ion.

Answer:

Your Answer is Option A that is Gas.

there are 12 atoms of mg in the following equations

Answer:

\(\boxed {\boxed {\sf 12 \ Mg \ atoms }}\)

Explanation:

We are given this formula:

\((Mg_3N_2)_4\)

We want to find the number of magnesium atoms. We can see that there is a subscript of 3 after the magnesium, so there are 3 magnesium atoms in 1 molecule of the compound.

However, there is a subscript of 4 that comes after the entire compound, so there are actually 4 molecules, with each molecule containing 3 magnesium atoms. Multiply 4 and 3.

There are 12 magnesium atoms.

Answer:

18 electrons

Explanation:

Answer:

18 electrons

Explanation:

Ca has 20 electrons. Ca^2+ has 18 electrons

Resonance is defined as the delocalization of the electrons within the molecules. The molecules can be represented by the more than one lewis structure.

The  resonance structure is delocalization of the electrons in the molecule. The difference in lewis structure is in the position that is occupied by the pi bond and the p orbital electrons.

In the left lewis structure of the nitro methane the negative charge that is the extra p orbital electron on the lower oxygen will migrate to form the pi bond to the nitrogen atom and the electron are in the pi bond in between the nitrogen and the upper oxygen will migrates to the extra p orbital electron to the upper oxygen atom. The opposite will occurs in the right lewis structure.

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This question is incomplete, the complete question is :

Add curved arrows to both structures of nitromethane to show the delocalization of electron pairs needed to form the other resonance contributor.

Answer:

D

Explanation:

Pressure is the force that you produce by the gas or liquid in a place or a container