Work out the coordinates of B

The simplified expression using De Morgan's law are  a)x'y'z'u  b)x'y'u c): x'y'u and d)x'y'z'+xy'z'+xyz.

The main idea is to simplify each Boolean expression by repeatedly applying De Morgan's law until each complement operation operates on a single variable.

Then, apply the double complement law to simplify the expression further. In the end, the simplified expression should contain only AND and OR operations without any complement operators acting on multiple variables.

a. 1/ x + yz + u can be simplified using De Morgan's law to: (x'y'z')u'. Then, applying the double complement law, we get the simplified expression as: x'y'z'u.

b. 1/x(y + 2)u can be simplified using De Morgan's law to: x'(y'+2')u'. Then, applying the double complement law, we get the simplified expression as: x'y'u.

c. 1/(x + y)(uv + xy) can be simplified using De Morgan's law to: (x'y')(u' + x'y'). Then, applying the double complement law, we get the simplified expression as: x'y'u.

d. 1/xy + yz + xz can be simplified using De Morgan's law to: (x'+y')(y'+z')(x'+z'). Then, applying the double complement law, we get the simplified expression as: x'y'z'+xy'z'+xyz.

In summary, to simplify Boolean expressions, we can apply De Morgan's law repeatedly and then use the double complement law to remove complement operators acting on a single variable twice.

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Answer:

1/2 or .5

Step-by-step explanation:

you find 2 points that the line goes through, then you find the rise/run. lastly you simplify if you can, then you have the answer

The magnitude of the resultant force upon the piling is 3710 pounds.

To find the resultant force, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. In this case, the forces exerted by the bulldozers form the two sides of a right triangle.

The force exerted by the first bulldozer in the westerly direction is 1850 pounds, and the force exerted by the second bulldozer in the northerly direction is 3250 pounds.

Using the Pythagorean theorem, we can calculate the magnitude of the resultant force as follows:

Resultant force =\(√(1850^2 + 3250^2)= √(3422500 + 10562500)= √(13985000)≈ 3710 pounds.\)

Therefore, the magnitude of the resultant force upon the piling is approximately 3710 pounds.

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Answer:

-8.9 is x and y is -25.1

Step-by-step explanation:

The expression x²y - 2xy - 24y can be factored by first factoring out a common factor of y, After the common factor is removed, the remaining factors are,  (x - 6) & (x - 4)

An expression is a sentence with at least two numbers or variables having mathematical operation. Math operations can be addition, subtraction, multiplication, division.

For example, 2x+3

Given that,

The expression  x²y - 2xy - 24y

Now taking common factor y from all the terms,

⇒ y(x² - 2x - 24)

Now considering another factor (x² - 2x - 24)

⇒ (x² - 2x - 24)

⇒ x² - 6x + 4x -24

⇒ x(x - 6) + 4(x - 6)

⇒ (x - 6)(x - 4)

Hence, rest two factors are  (x - 6) & (x - 4)

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Answer:

trinomial that is not a perfect square

Step-by-step explanation:

edgeeeeeeeeeeeeee

Answer:

y=18-5x

Step-by-step explanation:

Answer:

\(\dfrac{c}{2}\)

Step-by-step explanation:

We can simplify the given expression by canceling like terms.

Remember that anything divided by itself is 1.

ex:

\(\dfrac{2x}{x} = 2 \cdot \dfrac{x}{x} = 2 \cdot 1 = 2\)

Applying this logic to the given expression:

\(\dfrac{a}{2b} \cdot \dfrac{bc}{a}\)

↓ simplify multiplication of fractions

\(\dfrac{a \cdot bc}{2b \cdot a}\)

↓ rewrite to align like variables

\(\dfrac{a \cdot b \cdot c}{a \cdot b \cdot 2}\)

↓ separate out variables that are divided by each other

\(\dfrac{a}{a} \cdot \dfrac{b}{b} \cdot \dfrac{c}{2}\)

↓ represent them as 1

\(1 \cdot 1 \cdot \dfrac{c}{2}\)

↓ rewrite without unnecessary 1's

\(\dfrac{c}{2}\)

Answer:

Look down!

Step-by-step explanation:

1. 1/4*1/4*1/4

2. 1/4*1/2*1/2*1/4

Answer:

\(6\)

Step-by-step explanation:

We see that the triangle is a right triangle. We need to find the lengths of the two legs to find the area, then. Let's start with AB.

\(AB=\sqrt{(3-1)^2+(0-(-2))^2}=\sqrt{2^2+2^2}=\sqrt{8}=2\sqrt{2}\)

Now, we do the other leg.

\(\sqrt{(1-4)^2+(-2-(-5))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}\).

That will make the area \(b*h/2=2\sqrt{2}*3\sqrt{2}/2=6*2/2=6\)

Answer:

$1,391.25

Step-by-step explanation:

Noon would be 12:00 PM which would be 4 hours ahead of 8:00 AM

We subtract $8,821 by $3,256 to get the amount earned between 8:00 AM and 12:00 PM

$8,821 - $3,256

= $5,565

The find the average taken in within those 4 hours we will have to divide the money earned by the hours

$5,565/4

= $1,391.25

Answer: 51 degrees

Step-by-step explanation:

Answer:

\((a^{2}+b^{2})^{1/3}\)

Step-by-step explanation:

(a² + b²)^1/3

Any number to the power 1/2 means to square root the number

Any number to the power 1/3 means to cube root the number etc.

Answer:

x-intercept(s):

None

y-intercept(s):

(0,7+√11),(0,7−√11)Step-by-step explanation:

Answer:

a)$235.20

b) $67.20

Step-by-step explanation:

Stefan sells Jin a bicycle for $151 and a helmet for $17.

a) How much did Stefan spend originally?

Total cost for Jin = $151 + $17

= $168

The total cost for Jin is 140% of what Stefan spent originally to buy the bike and helmet.

Hence,

140% of $168 = $235.20

b) How much money did he make by selling the bicycle and helmet to Jin?

This is calculated as:

$235.20 - $168

= $67.20

= ​

The number of trees more than 10m tall but not more than 20m tall is 18 trees.

0 < h ≤ 5 = 5

height greater than 0m less than or equal to 5m

5 < h ≤ 10 = 9

height greater than 5m less than or equal to 10m

10 < h ≤ 15 = 13

height greater than 10m less than or equal to 15m

15 < h ≤ 20 = 5

height greater than 15m less than or equal to 20m

20 < h ≤ 25 = 1

height greater than 20m less than or equal to 25m

The number of trees that are more than 10m tall but not more than 20m tall are;

10 < h ≤ 15 = 13

15 < h ≤ 20 = 5

So,

13 + 5 = 18 trees

Therefore, the total number of trees which are 10m tall but not more than 20m tall is 18 trees.

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The solution to the inequality is x ≥ 2, given that x is not equal to -3/2, and the solution is x ∈ [2, ∞).

To find the domain of the inequality (3x - 1)/(2x + 3) ≥ 1, we need to look for values of x that make the denominator 2x + 3 equal to zero, since division by zero is undefined. We can set the denominator equal to zero and solve for x:

2x + 3 = 0

2x = -3

x = -3/2

Therefore, x cannot equal -3/2.

To solve the inequality, we can start by multiplying both sides by 2x + 3 to clear the denominator:

\((3x - 1)\div(2x + 3) \times (2x + 3) \geq1 \times (2x + 3)\)

3x - 1 ≥ 2x + 3

x ≥ 2

Therefore, the solution to the inequality is x ≥ 2, but we need to check that this solution is within the domain of the inequality. Since x cannot equal -3/2, the solution is:

x ∈ [-3/2, ∞) ∩ [2, ∞) = [2, ∞)

The domain of the inequality is x ∈ (-∞, -3/2) ∪ (-3/2, ∞).

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Answer: 151,515

Step-by-step explanation:

555+333= 888

333÷888 = .375

.375 × 404040 = 151,515

Answer:

its 15

Step-by-step explanation:

Answer:

the x intercept is the y and x combined together crossing each other

Answer:

y = 50x + 40

50 = slope

40 = intercept

The differential equation that matches the provided general solution is a nonhomogeneous equation expressed as y'' - 4y' + 12y = 4x + 2.

The nonhomogeneous differential equation that corresponds to the given general solution is:

y'' - 4y' + 12y = 4x + 2

This equation has a nonhomogeneous term (4x + 2) on the right-hand side, which leads to the presence of the particular solution (x² + 2x) in the general solution. The homogeneous part of the equation corresponds to the complementary solution \((c1e^{(-2x)} + c2e^{(6x)})\).

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The domain and range of f(x) are the domain is {-5, -6, 3, 4} and the range is {-2}

From the question, we have the following parameters that can be used in our computation:

Set of ordered pairs {(5,-2), (-6, -2), (3,-2), (4, -2)}.

The domain is the set of x values

So, we have

Domain = {-5, -6, 3, 4}

The range is the set of y values

So, we have

Range = {-2}

Hence, the domain is {-5, -6, 3, 4} and the range is {-2}

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a. The expected time until departure from the system when arriving to find all three servers busy and no one waiting can be calculated as (3/2(mu_1+mu_2+mu_3)).

b. The expected time until departure from the system when arriving to find all three servers busy and one person waiting can be calculated as (5/2(mu_1+mu_2+mu_3)).

a. In order to calculate the expected time until departure from the system when arriving to find all three servers busy and no one waiting, we can use the following formula:

E(T) = 1/3 * [1/mu_1 + 1/mu_2 + 1/mu_3 + (1/(mu_1+mu_2+mu_3))]

where E(T) represents the expected time until departure and mu_1, mu_2, and mu_3 represent the service rates of each server.

By substituting the given values into the formula, we get:

E(T) = 1/3 * [1/mu_1 + 1/mu_2 + 1/mu_3 + (1/(mu_1+mu_2+mu_3))]

= 1/3 * [1/μ_1 + 1/μ_2 + 1/μ_3 + (1/(μ_1+μ_2+μ_3))]

= (1/μ_1 + 1/μ_2 + 1/μ_3 + (1/(μ_1+μ_2+μ_3)))/3

Simplifying this expression gives us:

E(T) = (3/2(mu_1+mu_2+mu_3))

Therefore, the expected time until departure from the system when arriving to find all three servers busy and no one waiting is (3/2(mu_1+mu_2+mu_3)).

b. When one person is already waiting in the system, the expected time until departure can be calculated using the following formula:

E(T) = 1/2(mu_1+mu_2+mu_3) + 1/μ_min

where μ_min is the smallest service rate among the three servers.

The reasoning behind this formula is that the customer who has been waiting the longest will begin service immediately when a server becomes free, while the customer who arrived most recently will wait until all the other customers ahead of them have been served.

Therefore, the expected time until departure in this case is the expected waiting time for the customer who has been waiting the longest plus the expected service time for the next customer in line.

Since the service times are exponentially distributed, the expected service time for a server with rate mu is 1/mu. Therefore, the expected service time for the customer who is next in line is 1/μ_min.

By substituting the given values into the formula, we get:

E(T) = 1/2(mu_1+mu_2+mu_3) + 1/μ_min

= (μ_min/2(μ_1+μ_2+μ_3)) + (1/μ_min)

Therefore, the expected time until departure from the system when arriving to find all three servers busy and one person waiting is (μ_min/2(μ_1+μ_2+μ_3)) + (1/μ_min), or equivalently, (5/2(mu_1+mu_2+mu_3)) if we substitute μ_min = min(μ_1, μ_2, μ_3).

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Answer: 8*8=64

               6*6*=216

64-216+21=0

Step-by-step explanation:

Answer:

GCF = 8

Step-by-step explanation:

The correct option is B. a fixed rate for each item produced or action performed.

A piece rate employee is paid a set amount for each item produced or action performed.

Employees paid on the a piece rate or piecework reason are typically paid per task completed or the number of units produced. Here are a few examples of piece-rate contracts:

Pay rate during nonproductive work hours

Some companies may be forbidden by state law from paying employees on a piece-rate basis. In California, for example, employers are generally prohibited from paying labourers on a piece-rate basis.

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Information is needed to evaluate the project's financial viability, considering factors such as the initial investment, expected cash flows, cost of capital, and project duration.

To calculate the year 1 operating cash flows (OCF), we need to subtract the year 1 costs from the year 1 revenues:

OCF = Year 1 Revenues - Year 1 Costs

OCF = $192,000 - $125,000

OCF = $67,000

To find the depreciation expense in year 3, we need to determine the depreciation method. The provided information is incomplete regarding the depreciation method, so we cannot calculate the depreciation expense in year 3 without knowing the specific method.

The change in Net Working Capital (NWC) in year 2 can be determined by multiplying the Net Working Capital percentage (given as a percentage of t+1 revenues) by the year 1 revenues and subtracting the result from the year 2 revenues:

Change in NWC = (Year 2 Revenues - Net Working Capital percentage * Year 1 Revenues) - Year 1 Revenues

Without the specific Net Working Capital percentage or Year 2 Revenues values, we cannot calculate the exact change in NWC in year 2.

The net cash flow from salvage (ATSV) is calculated by multiplying the Salvage Value percentage by the Initial Cost:

ATSV = Salvage Value percentage * Initial Cost

ATSV = 28% * $390,000

ATSV = $109,200

To calculate the project's NPV, we need the cash flows for each year, the cost of capital, and the project duration. Unfortunately, the information provided does not include the cash flows for each year, so we cannot calculate the project's NPV.

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The complete question is:

Below are your numerical inputs for the problem: 4 & Initial Cost (\$) & 390000 5 & Year 1 Revenues (\$) & 192000 6 & Year 1 Costs (\$) & 125000  7 & Inflation & 2.75% 8 & Project Duration (years) & 6 9 & Depreciation Method & 10 & Tax Rate & 11 & Net Working Capital (\% oft+1 Revenues) & MACRS 12 & Salvage Value (\$) & 28.00% 13 & Cost of Capital & 15.00% & 245000 How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.