Answer:
2 ki power 6
Step-by-step explanation:
\( \huge \boxed{\mathfrak{Question} \downarrow}\)
Work out the value of ⇨ (2³)²\( \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}\)
\( \tt \: ( 2 ^ { 3 } ) ^ { 2 } \\ \)
Use the rules of exponents to simplify the expression. To raise a power to another power, multiply the exponents.
\( \sf \: 2^{3\times 2} \\ \)
Multiply 3 times 2.
\( \sf \: 2^{6} \\ \)
Raise 2 to the power 6 to get 64.
\( \sf \: 2 \times 2 \times 2 \times 2 \times 2 \times 2 \\ = \sf8 \times 8 \\ = \boxed{\boxed{\bf \: 64}}\)
a square table has am area of 15476cm^2 find the perimeter of the square
Answer:
497.6 cm to 1 decimal place.
Step-by-step explanation:
→ Square root the area to find the length
√15476 = 124.4025723
→ Multiply the answer by 4 to get the perimeter
124.4025723 × 4 = 497.6102893
Answer:
497.6 cm
Step-by-step explanation:
Perimeter = 4 x a
Since area is given we must square root a
P = 4 x square root (\(\sqrt{15476}\))
P = 4 x (124.40)
P = 497.6 cm
3
Solve for n.
n + 1 = 4(n - 8)
O
n=1
On=8
O n= 11
O
n=16
Answer:
n = 11Step-by-step explanation:
n + 1 = 4(n - 8)
n + 1 = 4n - 32 [Multiply 4 times (n-8)]
1 = 3n - 32 [Subtract 1n from both sides]
33 = 3n [Add 32 to both sides]
3n = 33
n = 11CHECK:
Does n + 1 = 4(n - 8) when n = 11?
n + 1 = 4(n - 8)
11 + 1 = 4(11 - 8)
11 + 1 = 4(3)
12 = 12 YES
find the value of p and of q for which x-3 is a common factor of the expressions \(x^{2} + (p + q)x-q\) and \(2x^2 + (p-1)x + (p+2q)\)
WILL GIVE BRAINLIEST PLS ANSWER
Step-by-step explanation:
Use the Factor Theorem,
" if x-a is a factor of f(x), then f(a) =0,
So here, since x-3 is a factor then f(3)=0,
So first step, plug in 3 for x for the serperate equations.
\( {3}^{2} + ( p + q)3 - q = 0\)
\(2(3) {}^{2} + (p - 1)3 + (p + 2q) = 0\)
Simplify both equations,
\(9 + 3p + 2q = 0\)
\(15 + 4 p + 2q = 0\)
Isolate the constants,
\(3p + 2q = - 9\)
\(4p + 2q = - 15\)
We have a system of equations so let eliminate a variable, by subtracting the two equations.
\( - p = 6\)
\(p = - 6\)
Plug p back in for any one of the equations to find q.
\(3( - 6) + 2q = - 9\)
\( - 18 + 2q = - 9\)
\(2q = 4.5\)
So p is -6
q is 4.5
Annika's older cousin borrowed $800 to repair her car she will pay off the loan after 2 years by paying back the principal plus 4.5% simple interest for each year
A.how much will she pay in interest?
Annika will spend for the interest is $72.
Answer:
$72.
Step-by-step explanation:
diseases tend to spread according to the exponential growth model. in the early days of aids, the growth factor (i.e. common ratio; growth multiplier) was around 1.9. in 1983, about 1700 people in the u.s. died of aids. if the trend had continued unchecked, how many people would have died from aids in 2005?
The number of people died from aids in U.S. in 2005 are 2,30,68,96,671
Given, diseases tend to spread according to the exponential growth model.
In the early days of aids, the growth factor (i.e. common ratio; growth multiplier) was around 1.9.
In 1983, about 1700 people in the U.S. died of aids.
we have to find the number of people died from aids in 2005.
Let the exponential function, be
P(x) = AB^x
where, A is the initial population of people died of aids in U.S.
B is the growth factor of aids in U.S.
as, B = 1.9
In 1983, x = 0
P(0) = AB^0
1700 = A
Now, P(x) = 1700(1.9)^x
and the number of years from 1983 to 2005 are, 22 years
The number of people died from aids in 2005 be,
P(22) = 1700(1.9)^22
P(22) = 2,30,68,96,671
So, 2,30,68,96,671 people died from aids in 2005.
Hence, 2,30,68,96,671 people died from aids in 2005.
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identify the graph that represents the given system of inequalities. also, identify two ordered pairs that are solutions to the system. y ≤ x 5 y ≤ 2x 3
Ordered pair (0, 6) and (2, 7) satisfy both inequalities in the system and are solutions to the system.
To identify the graph that represents the given system of inequalities y > x + 5 and y ≥ 2x + 3, we need to graph the individual inequalities and find the region where they overlap.
When we plot the graph of inequality separately:
y > x + 5:Draw a dashed line y = x + 5 (not including the line).Shade the region above the line.2. y ≥ 2x + 3:
Draw a solid line y = 2x + 3 (including the line).Shade the region above the line.The overlapping shaded region represents the solution to the system of inequalities.
To find two ordered pairs that are solutions to the system, we can choose any points within the overlapping region. Let's select two points:
Ordered pair 1: (0, 6)
Ordered pair 2: (2, 7)
These two points satisfy both inequalities in the system and are solutions to the system.
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The correct question is given below -
Identify the graph that represents the given system of inequalities. Also identify two ordered pairs that are solutions to the system.
y > x + 5
y ≥ 2x + 3
-3x+7=-17 is it true
Answer:
Yes
Step-by-step explanation:
-3x+7=-17
-7 -7
-3x=-24
_______
x=8
A personnel director at a large company studied the eating habits of employees by watching the movements of a selected group of employees at lunchtime. The purpose of the study was to determine the proportion of employees who buy lunch in the cafeteria, bring their own lunches, or go out to lunch. If the director includes only the employees in the department nearest her office in her study, she is performing a(n)
The personnel director in this scenario is performing a convenience sampling.
Convenience sampling is a type of non-probability sampling method where the researcher selects participants based on their accessibility and proximity to the researcher. In this case, the personnel director chose employees from the department nearest her office for the study.
This approach may not provide a fully representative sample of the entire company's employee population, as it doesn't account for possible differences in eating habits across various departments. Therefore, the findings from this study might not accurately represent the proportion of employees who buy lunch in the cafeteria, bring their own lunches, or go out to lunch for the entire company.
To obtain more accurate results, the director might consider employing a probability sampling method, such as simple random sampling or stratified sampling, to ensure a more representative sample of the company's employees.
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Let Tn, be the number of dots in figure.
How many dots are there in figure 30?
Look at the picture (don't mind of the highlighted ones).
Answer:
4294967293 dots
Step-by-step explanation:
Figure 1 has 5 dots.
Figure 2 has 13 dots.
Figure 3 has 29 dots.
Subtract and find different of each term:
13-5 = 829-13 = 16Let \(\displaystyle \large{b_n}\) be sequence of difference (and the sequence appears to be geometric.)
So for \(\displaystyle \large{b_n}\), find the common ratio which is 2.
Hence, \(\displaystyle \large{b_n = 8(2)^{n-1}}\) - recall geometric sequence formula below:
\(\displaystyle \large{a_n = a_1r^{n-1}}\)
The sequence of difference \(\displaystyle \large{b_n=8(2)^{n-1}}\) can be simplified to:
\(\displaystyle \large{b_n=2^3(2)^{n-1}}\\\displaystyle \large{b_n=2^{n+2}}\)
Now to find the original sequence:
\(\displaystyle \large{a_n = a_1 + \sum_{k=1}^{n-1}b_k}\)
Hence:
\(\displaystyle \large{T_n=5+\sum_{k=1}^{n-1}8(2)^{k-1}}\)
Recall:
\(\displaystyle \large{\sum_{k=1}^{n-1} a_1r^{n-1} =a_1\left( \dfrac{1-r^{n-1}}{1-r}\right)}\)
Therefore:
\(\displaystyle \large{T_n=5+\sum_{k=1}^{n-1}8(2)^{k-1}}\\\displaystyle \large{T_n=5+8\left(\dfrac{1-2^{n-1}}{1-2}\right)}\\\displaystyle \large{T_n=5+8\left(\dfrac{1-2^{n-1}}{-1}\right)}\\\\\displaystyle \large{T_n=5+8(-1+2^{n-1})}\\\displaystyle \large{T_n=5-8+8(2)^{n-1}}\\\displaystyle \large{T_n=2^{n+2}-3}\)
Therefore, the sequence for 5,13,29 is \(\displaystyle \large{2^{n+2}-3}\).
Therefore, in figure 30:
\(\displaystyle \large{T_{30}=2^{30+2}-3}\\\displaystyle \large{T_{30}=2^{32}-3}\\\displaystyle \large{T_{30}=4294967293}\)
Therefore, there are 4294967293 dots in figure 30
Reflect (-5,-3) over the x axis then translate the result 2 units downwhat are the final cordinates
We reflect the point (-5, -3) over the x-axis to get (-5, 3), and then translate this point down by 2 units to get the final coordinates of (-5, 1).
To reflect a point over the x-axis, we keep the x-coordinate the same, but negate the y-coordinate. Thus, reflecting the point (-5, -3) over the x-axis gives us the point (-5, 3).
Next, we need to translate the result 2 units down. To do this, we subtract 2 from the y-coordinate of the reflected point. So, subtracting 2 from the y-coordinate of (-5, 3) gives us the final coordinates:
(-5, 3) translated 2 units down is (-5, 1).
In summary, we can reflect a point over the x-axis by negating the y-coordinate, and translate a point down by subtracting a value from its y-coordinate. So, we reflect the point (-5, -3) over the x-axis to get (-5, 3), and then translate this point down by 2 units to get the final coordinates of (-5, 1).
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9 – 4x = 2x whats the ancewer
Answer:
3/2 is the answer
Step-by-step explanation:
Answer:
x=1 1/2
Step-by-step explanation:
9-4x=2x
4x+2x=9
6x=9
x=9/6
x=3/2
x=1 1/2
Theres the answer hope this helps! :)
The cost of purchasing gasoline varies directly with the number of gallons purchased. Kali paid $52.90 for 23 gallons of gas. What is the direct variation equation that relates y, the cost of a gasoline purchase, to x the number of gallons?
Answer:
y = 2.3x
Step-by-step explanation:
y = kx
52.9 = 23x
52.9 ÷ 23 = x
x = 2.3
The purpose of a budget is to figure out how to use money in a way that best meets your wants and needs. TRUE OR FALSE. Brainly
Which is the graph of this line segment after it is translated units along the -axis and units along the -axis ?
By looking at the endpoints, we conclude that the correct graph is the one in the second option.
Which is the graph of the line after the translation?Notice that the original line ends at B = (7, 5)
And now we apply a translation of -5 on the x-axis and 3 on the y-axis, then the new coordinate of point B will be B' = (7 - 5, 5 + 3) = (2, 8)
Now let's look at the graphs, the only one with that coordinate of B' is the second option (counting from the top).
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Use f(x) = 3 - 2x2 - 2x and g(x) = 8x - 5 to determine (f-g)(x) then write in standard form
Here, we are given two functions and we want to find the difference between the two functions;
Looking at what we have;
(f-g)x
What this mean is that we are to subtract g(x) from f(x);
Mathematically;
\(\begin{gathered} (f-g)x\text{ = f(x) - g(x)} \\ \\ =3-2x^2-2x\text{ - (8x - 5)} \\ \\ =3-2x^2-2x-8x\text{ + 5} \\ \\ =3+5-2x-8x-2x^2 \\ \\ =8-10x-2x^2 \\ \\ (f-g)x=-2x^2\text{ - 10x + 8} \end{gathered}\)Answer please screenshot attached
Solve the polynomial
(ab ^ 2 +13b-4a) + (3ab ^ 2 + a)
Answer: 4ab2 - 3a + 13b
Step-by-step explanation: (a•(b2))+13b)-4a)+(3ab2+a)
Factoring 4ab2 - 3a + 13b
I NEED HELP ASAP!!!!!!!! Jason needs to buy a new sweater. The ticket price of the sweater was $89.00. After sales tax was included, the final cost was $94.79. What percent sales tax did Jason pay on his sweater? A.7.25% B.1.09% C.6.50% D.9.67
Answer:
C
Step-by-step explanation:
Find the difference between $94.79 and $89.00 then do (5.79/89)*100 which is 6.50561797753, then round the initial answer so you get 6.50
Have a great day <3
Name the pair of angle and find the measure of angle b
Let X 1 ,X 2 ,…,Xn be iid Bern(p) random variables, so that Y=∑ i=1n X i is a Bin(n,p) random variable. (a) Show that Xˉ =Y/n is an unbiased estimator of p. (b) Show that Var( Xˉ )=p(1−p)/n. (c) Show that E{ Xˉ (1− Xˉ )}=(n−1)[p(1−p)/n]. (d) Find the value of c such that c Xˉ (1− Xˉ ) is an unbiased estimator of p(1−p)/n.
a) X is an unbiased estimator of p. b) The Var(X) is p(1-p)/n. c) The E[X(1-X)] is (n-1)[p(1-p)/n]. d) The value of c is c = 1/(n-1).
(a) To show that X = Y/n is an unbiased estimator of p, we need to show that E[X] = p.
Since Y is a sum of n iid Bern(p) random variables, we have E[Y] = np.
Now, let's find the expected value of X:
E[X] = E[Y/n] = E[Y]/n = np/n = p.
Therefore, X is an unbiased estimator of p.
(b) To find the variance of X, we'll use the fact that Var(aX) = a^2 * Var(X) for any constant a.
Var(X) = Var(Y/n) = Var(Y)/n² = np(1-p)/n² = p(1-p)/n.
(c) To show that E[X(1-X)] = (n-1)[p(1-p)/n], we expand the expression:
E[X(1-X)] = E[X - X²] = E[X] - E[X²].
We already know that E[X] = p from part (a).
Now, let's find E[X²]:
E[X²] = E[(Y/n)²] = E[(Y²)/n²] = Var(Y)/n² + (E[Y]/n)².
Using the formula for the variance of a binomial distribution, Var(Y) = np(1-p), we have:
E[X²] = np(1-p)/n² + (np/n)² = p(1-p)/n + p² = p(1-p)/n + p(1-p) = (1-p)(p + p(1-p))/n = (1-p)(p + p - p²)/n = (1-p)(2p - p²)/n = 2p(1-p)/n - p²(1-p)/n = 2p(1-p)/n - p(1-p)²/n = [2p(1-p) - p(1-p)²]/n = [p(1-p)(2 - (1-p))]/n = [p(1-p)(1+p)]/n = p(1-p)(1+p)/n = p(1-p)/n.
Therefore, E[X(1-X)] = E[X] - E[X²] = p - p(1-p)/n = (n-1)p(1-p)/n = (n-1)[p(1-p)/n].
(d) To find the value of c such that cX(1-X) is an unbiased estimator of p(1-p)/n, we need to have E[cX(1-X)] = p(1-p)/n.
E[cX(1-X)] = cE[X(1-X)] = c[(n-1)[p(1-p)/n]].
For unbiasedness, we want this to be equal to p(1-p)/n:
c[(n-1)[p(1-p)/n]] = p(1-p)/n.
Simplifying, we have:
c(n-1)p(1-p) = p(1-p).
Since this should hold for all values of p, (n-1)c = 1.
Therefore, the value of c is c = 1/(n-1).
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for the x-values 1,2,3 and so on, the y values of a function form an arithmetic sequence that decreases in value what type of function is it
A. Decreasing linear
B. Exponential growth
C. Increasing linear
D. Exponential decay
The type of function that fits the given description is D. Exponential decay.
In an arithmetic sequence, the difference between consecutive terms remains constant. If the y-values of a function form an arithmetic sequence that decreases in value, it means that the difference between consecutive terms is negative.
Exponential decay functions exhibit a constant ratio between consecutive terms, resulting in a decreasing sequence. As the x-values increase, the y-values decrease at a consistent rate. This is represented by the formula y = ab^x, where b is a constant between 0 and 1.
In contrast, linear functions have a constant difference between consecutive terms, resulting in an arithmetic sequence. However, since the y-values are decreasing, the function cannot be linear.
Exponential growth functions, on the other hand, have a constant ratio between consecutive terms, but they result in an increasing sequence. The y-values of an exponential growth function increase as the x-values increase.
Therefore, based on the given information, the most appropriate type of function is D. Exponential decay.
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I need help with these four
Answer:
True, b), c), b)Step-by-step explanation:
Q1
TrueQ2
b) sin = opposite/hypotenuseQ3
Cos A = 0.1908A = arccos 0.1908A = 79° ⇒ Option c)Q4
tan A = 16/19A = arctan 16/19A = 40° ⇒ Option b)Let p: A number is greater than 25.
Let q: A.number is less than 35.
If p ^ q is true, then what could the number be? Select two options.
Answer:
Here we do not have the options, so I will answer in a general way.
We have two statements:
p = A number is greater than 25
q = A number is less than 35
We want to have:
p ^ q is true
This means:
p and q are true.
So, we need to find a number such that both conditions are meet, so we need to find a number N such that
The number N is greater than 25 (from p)
The number N is less than 35 (from q)
So N can be any number between 25 and 35
So, some of the possible values of N are:
N = 26
N = 27
N = 28.6
N = 33
N = 34
Concluding, any number N ∈ (25, 35) can be a solution.
(Note that N = 25 and N = 35 are not solutions)
Find the equation of the line perpendicular to 3y = 5-2x passing through the point (4,10)
Full explanation please and I will give you brainliest only if your explanation makes sense!
Two banks offer different choices for transaction fees, Bank A charges $0.20 for
each transaction while Bank B offers 25 free transactions a month but charges
$1.00 for each additional transaction. If you make 52 transactions a month how
much does each bank charge?
Answer:
Bank A charges 10.4 a month. Bank B charges 27.00 a month
Step-by-step explanation:
Bank A step by step-
0.20 x 52 = 10.4
Bank B step by step=
52-25 = 27
27 x 1.00 = 27.00
For x2 + 3x - 18 = (x - 3)(x + a), what value
of a would make this equation true?
in a bag of marbles, 1 2 are red, 1 4 are blue, 1 6 are green, and 1 12 are yellow. you pick a marble without looking. what color marble are you most likely to choose?
I WILL GIVE BRAINLEST PLEASE HELP!!!!!!!!
Write an equation to find the average number of yards gained per play if Howard and Vincent gained the same number of yards.
Answer: they are parallel so there is no solution.
Step-by-step explanation:
Brayden- y=5x-1 or y-5x= -1
Howard- y=5x+1 or y-5x= 1
Vincent- y=4x+5 or y-4x= 5
In summary, they are all parallel so there is no solution. or
5y - 1 = 5y + 1
(Braydon = Howard)
Hope this helps you :) pls BRAINLEST
Answer:
The expressions for the yards gained by Brayden and Howard are 5y − 1 and 5y + 1, respectively.
If Brayden and Howard gained the same number of yards, then the equation representing this situation would be
5y – 1 = 5y + 1.
Brainliest?
Solve the equation:
(11x-25) + (24x+10) =90
Answer:
x=3
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
In a right-angled triangle, the sum of the squares of the three side lengths is $1800.$ What is the length of the hypotenuse of this triangle
The length of the hypotenuse of this triangle is 30cm.
Let us assume that the length of base = a cm
the length of perpendicular = b cm
the length of hypotenuse = c cm
according to Pythagoras theorem we have
\(hypotenuse^{2} = base^{2} + perpendicular^{2}\)
\(c^{2} = a^{2}+ b^{2}\) equation 1
also given that
\(a^{2}+ b^{2} +c^{2} =1800\) equation 2
now putting the value from equation 1 in equation 2 we get
\(c ^{2} +c^{2} =1800\\2c^{2} = 1800\\c^{2} = 900\\c = 30\)
hence, the length of the hypotenuse of this triangle is 30cm
What is hypotenuse?The longest side of a right-angled triangle, or the side opposite the right angle, is known as the hypotenuse in geometry.
The Pythagorean theorem, which asserts that the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides, can be used to determine the length of the hypotenuse.
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