Life expectancy for all the different countries in the world ranges from a low of only 52.2 years (in sierra leone) to a high of 84.7 years (in hong kong). life expectancies are clustered at the high end, with about half of all the countries having a life expectancy between about 74 and the maximum of 84.7. a few countries, such as sierra leone, have a very low life expectancy.
a. what is the shape of the distribution of life expectancies for all countries?
a) symmetric.b) skewed to the right.c) skewed to the left.d) none of these.b. from the information given, estimate the median of the life expectancies.c. will the mean be larger or smaller than the median?
From the given distribution, we have that:
a) The distribution is skewed to the left.
b) The median is of 74.
c) The mean will be smaller than the median.
Figuring the skewness with the mean and the median:Mean greater than median: Positively(right) skewedMean less than the median: Negatively(left) skewedSince life expectancies are clustered at the high end, the outliers are small life expectancies, meaning that the mean will be smaller than the median and the distribution is skewed to the left.
The median of a data-set is the 50th percentile, the value that separates the bottom 50% of the data-set from the upper 50%.
In this problem, we have that about half of all the countries having a life expectancy between about 74 and the maximum of 84.7, meaning that 74 is the median.
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PLZ HELP ME ASAP PLZ PLZ WILL GIVE BRAINLEST
Answer:
25.13
Step-by-step explanation:
To find the diameter C = 2 π x r
A measurable quantity that is inherent in the problem is called a(n) B) uncontrollable variable. C) algorithm. E) enumeration variable. A) decision variable. D) parameter
The correct answer is D) parameter. A parameter is a measurable quantity that is inherent in the problem and is usually set by external factors. A measurable quantity that is inherent in the problem is called a D) parameter.
A parameter is a measurable and fixed value that characterizes a particular aspect of a problem, while a variable can change during the course of the problem-solving process. Decision variables are the unknowns that you need to find in order to optimize a problem, and uncontrollable variables are factors that cannot be controlled during an experiment or problem-solving process. An algorithm is a step-by-step procedure to solve a problem, and an enumeration variable is not a relevant term in this context. Parameters are used to define the boundaries of a problem and are often used in mathematical models to represent real-world situations. They differ from variables, which can change and are often used to represent unknowns in a problem, and from uncontrollable variables, which cannot be directly controlled or manipulated by the decision-maker.
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What is the slope of the line that passes through (2,3) and (2,11)
Answer:
the slope is unidentified
Step-by-step explanation:
x=2
there is no slope.
1 and 2 are complementary angles. The measure of 1 is 83. The measure of 2 is 7x-1. Find the value of x
Answer: 8/7
Step-by-step explanation:
How do you solve this equation? 3x^2 + x - 6 *
x = -3, 2
x = 3,-2
x = 1, 2
y = 1, 2
Answer:
that not a thing
Step-by-step explanation:
lou have earned 3 point(s) out of 5 point(s) thus far. The following data are the yields, in bushels, of hay from a farmer's last 10 years: 375,210,150,147,429,189,320,580,407,180. Find the IQR.
The Interquartile Range (IQR) of the given data set, consisting of the yields of hay from a farmer's last 10 years (375, 210, 150, 147, 429, 189, 320, 580, 407, 180), is 227 bushels.
IQR stands for Interquartile Range which is a range of values between the upper quartile and the lower quartile. To find the IQR of the given data, we need to calculate the first quartile (Q1), the third quartile (Q3), and the difference between them. Let's start with the solution. Find the IQR. Given data are the yields, in bushels, of hay from a farmer's last 10 years: 375, 210, 150, 147, 429, 189, 320, 580, 407, 180
Sort the given data in order.150, 147, 180, 189, 320, 375, 407, 429, 580
Find the median of the entire data set. Median = (n+1)/2 where n is the number of observations.
Median = (10+1)/2 = 5.5. The median is the average of the fifth and sixth terms in the ordered data set.
Median = (210+320)/2 = 265
Split the ordered data into two halves. If there are an odd number of observations, do not include the median value in either half.
150, 147, 180, 189, 210 | 320, 375, 407, 429, 580
Find the median of the lower half of the data set.
Lower half: 150, 147, 180, 189, 210
Median = (n+1)/2
Median = (5+1)/2 = 3.
The median of the lower half is the third observation.
Median = 180
Find the median of the upper half of the data set.
Upper half: 320, 375, 407, 429, 580
Median = (n+1)/2
Median = (5+1)/2 = 3.
The median of the upper half is the third observation.
Median = 407
Find the difference between the upper and lower quartiles.
IQR = Q3 - Q1
IQR = 407 - 180
IQR = 227.
Thus, the Interquartile Range (IQR) of the given data is 227.
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Put these numbers in order from greatest to least 21, -21/40, -3/8, 21 3/40, 21 3/8
Answer:
Step-by-step explanation:
Hey, I'm sorry I can't help but just know that it's going to be okay, school is also stressing me out. I'm so proud of you for staying alive. Have an amazing day :D
Answer:
21 3/8, 21 3/40, 21, -3/8,-21/40
Jose has a mask collection. He keeps some in a display case and the rest on the wall. 153 of his masks are on the wall, and 49% of his masks are in the display case. What is the total number of masks in Jose's collection?
Answer: 49% of 153 is 74.97
Find the distance (8,-7) (-4,-2)
Distance = 13 units
Point A: (8, -7)
Point B: (-4, -2)
\(\sqrt{(8 + 4)^{2} + (-7 + 2)^{2} }\)
\(\sqrt{(12)^{2} + (-5)^{2} }\)
\(\sqrt{144 + 25 }\)
\(\sqrt{169}\)
\(13\)
Answer:
\(\boxed {d = 13}\)
Step-by-step explanation:
Use the Distance Formula to help you find the distance between the two following points:
\(d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}\)
(where \((x_{1}, y_{1})\) represents the first point and \((x_{2}, y_{2})\) represents the second point)
-Apply the two following onto the formula:
\((x_{1}, y_{1}) = (8, -7)\)
\((x_{2}, y_{2}) = (-4, -2)\)
\(d = \sqrt{(-4 - 8)^{2} + (-2 + 7)^{2}}\)
-Solve for the distance:
\(d = \sqrt{(-4 - 8)^{2} + (-2 + 7)^{2}}\)
\(d = \sqrt{(-12)^{2} + 5^{2}}\)
\(d = \sqrt{144 + 25}\)
\(d = \sqrt{169}\)
\(\boxed {d = 13}\)
Therefore, the distance is \(13\).
If the blue radius below is perpendicular to the chord , which is 14 units long, what is the length of the segment ?
Answer:
The answer is 7 bc 7 is half of 14
Step-by-step explanation:
as part of video game, the point (5,2) is rotated counterclockwise about the origin through an angle of 5 degrees. find the new coordinates of this point
The new coordinates of the point (5, 2) after rotating counterclockwise about the origin through an angle of 5 degrees are approximately (4.993, 2.048).
To find the new coordinates of the point (5, 2) after rotating counterclockwise about the origin through an angle of 5 degrees, we can use the rotation formula:
x' = x * cos(theta) - y * sin(theta)
y' = x * sin(theta) + y * cos(theta)
Where (x, y) are the original coordinates, (x', y') are the new coordinates after rotation, and theta is the angle of rotation in radians.
Converting the angle of rotation from degrees to radians:
theta = 5 degrees * (pi/180) ≈ 0.08727 radians
Plugging in the values into the rotation formula:
x' = 5 * cos(0.08727) - 2 * sin(0.08727)
y' = 5 * sin(0.08727) + 2 * cos(0.08727)
Evaluating the trigonometric functions and simplifying:
x' ≈ 4.993
y' ≈ 2.048
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Find the quotient. Answer to the nearest hundredth. 437 ÷ 15
Answer:
29.13
Step-by-step explanation:
29.1333
29.13
The quotient of the given division nearest to the hundredth is 29.133
What is division?Division is defined as the splitting of a large group into smaller groups such that every group will have an equal number of items.
Now the given division is,
437 ÷ 15
Using long division method,
29.1333
15| 437
- 30
137
- 135
20
- 15
50
- 45
50
- 45
5
hence the quotient we get is 29.1333...
To round of to the nearest hundredth,
Since digit to the right of 3 is less than 5
So, the remainder nearest to the hundredth is 29.133.
Thus,The quotient of the given division nearest to the hundredth is 29.133.
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Jack took a test and got 10 out of 20 points. He took a make-up test and got 20 out of 25 points. The percent of increase in Jack's score is about _____.
Answer:
30%
Step-by-step explanation:
10 out of 20=50% since it is half and 20 out of 25=80% I know this because when your taking a test out of 20 1 answer=4%
10/25=40%
11/25=44%
12/25=48% Those are just some examples
15/25=60%
16/25=64%
20/25=80%
21/25=84%
22/25=88%
23/25=92%
24/25=96%
25/25=100%
The percent of increase in Jack's score is about 60%.
Given that, Jack took a test and got 10 out of 20 points.
What is percentage?Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".
Now, 10/20 = 0.5
He took a make-up test and got 20 out of 25 points.
= 20/25
= 4/5
= 0.8
So, difference = 0.8-0.5 =0.3
Here, the percentage = 0.3/0.5 ×100
= 0.6×100
= 60%
Hence, the percent of increase in Jack's score is about 60%.
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simplify the expression 8a-2b+4 for the value a=3 and b = -5
Answer:
38
Step-by-step explanation:
Simply plug in 3 where a is, and -5 where b is as such.
\(8(3) - 2(-5) +4\)
\(24 + 10 + 4\)
= \(38\)
Answer:
38
Step-by-step explanation:
Don't worry this is pretty easy! Simply plug in your given values into the expression. So if a=3 and b=-5, we would put this in the equation.
8(3)-2(-5)+4
24+10+4<--- -2(-5) would be 10 since negatives cancel out. Remember to first to parentheses, then multiply/divide next.
38
a paint can is 10 cm tall and holds approximately 535 cubic centimeters of paint. what is the approximate area of the base of the can? responses 5350 square centimeters 5350 square centimeters 53.5 square centimeters 53 point 5 square centimeters 100 square centimeters 100 square centimeters 5.35 square centimeters
the approximate area of the base of the paint can is 53.5 square centimeters.by using Volume formula is Base Area × Height
To find the approximate area of the base of the paint can, we can use the formula for the volume of a cylinder:
Volume = Base Area × Height
We are given the volume (535 cubic centimeters) and the height (10 cm). We need to solve for the Base Area. Rearranging the formula to solve for Base Area, we get:
Base Area = Volume ÷ Height
Now, substitute the given values:
Base Area = 535 cubic centimeters ÷ 10 cm
Base Area ≈ 53.5 square centimeters
So, the approximate area of the base of the paint can is 53.5 square centimeters.
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The approximate area of the base of the can is 53.5 square centimeters
How to determine the area of the base of the can?From the question, we have the following parameters that can be used in our computation:
Volume = 535 cubic centimeters of paint
Height of container = 10 cm
The area of the base of the can is calculated as
Base area = Volume/Height
Substitute the known values in the above equation, so, we have the following representation
Base area = 535/10
Evaluate
Base area = 53.5
Hence, the base area is 53.5 square centimeters
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URGENT :)) HELP PLS
(Q2)
The matrix equation represents a system of equations.
A matrix with 2 rows and 2 columns, where row 1 is 2 and 3 and row 2 is 1 and 2, is multiplied by matrix with 2 rows and 1 column, where row 1 is x and row 2 is y, equals a matrix with 2 rows and 1 column, where row 1 is 5 and row 2 is 4.
Solve for x and y using matrices. Show or explain all necessary steps.
Answer:
The given matrix equation can be written as:
[2 3; 1 2] * [x; y] = [5; 4]
Multiplying the matrices on the left side of the equation gives us the system of equations:
2x + 3y = 5 x + 2y = 4
To solve for x and y using matrices, we can use the inverse matrix method. First, we need to find the inverse of the coefficient matrix [2 3; 1 2]. The inverse of a 2x2 matrix [a b; c d] can be calculated using the formula: (1/(ad-bc)) * [d -b; -c a].
Let’s apply this formula to our coefficient matrix:
The determinant of [2 3; 1 2] is (22) - (31) = 1. Since the determinant is not equal to zero, the inverse of the matrix exists and can be calculated as:
(1/1) * [2 -3; -1 2] = [2 -3; -1 2]
Now we can use this inverse matrix to solve for x and y. Multiplying both sides of our matrix equation by the inverse matrix gives us:
[2 -3; -1 2] * [2x + 3y; x + 2y] = [2 -3; -1 2] * [5; 4]
Solving this equation gives us:
[x; y] = [-7; 6]
So, the solution to the system of equations is x = -7 and y = 6.
Circumference and Area questions look at the picture
Note that the formula for the circumference of a circle is πd, while the formula for the area of a circle is πr².
π≈3.14
A. C=πd
Simply plug in the numbers into the formula.
Diameter=Radius*2
17*2=34
C=34(π)
B. (π)(5²)
Plug in the numbers into the formula. Remember that half of the diameter is the radius.
C. (π)(4.5)
There are two possible formulas that could be used to calculate the circumference of a circle: πd and 2πr.
The expression above is simply multiplying the circle's radius times pi. Therefore, it is not a method that could be used to find the circumference of a circle.
D. (π)(6.5²)
Remember that the formula for calculating the area of a circle is πr².
Half of the diameter is 6.5 (13.5/2=6.5). 6.5 cm. is the radius. Now just plug the numbers into the formula.
(π)(6.5²)
Therefore, the last answer choice is the correct answer.
5. The value of a piece of land is growing at a rate of 2.5% annually. If the land was worth $99,000 when it was purchased, which equation could be used to determine the value of the property, y, x years after it was purchased? a) =99,000+2.5 c) =99,000(1.025) b) =99,000(0.025) d) =99,000(2.5)
Answer:
99,000.00 × 2.5 . answer d
Please check the attached picture, please answer thoroughly!
The selection depends on individual needs, preferences, and the intended use of the tiny house.
a) To find the amount of space inside each house, we need to calculate the volume for each design.
House on the left:
Volume = length x width x height = 2.5 m x 18 m x 2.8 m = 126 m³
Triangular house:
Volume of a triangular prism = (base area x height) / 2
Base area = (1/2) x base x height = (1/2) x 4 m x 10 m = 20 m²
Volume = (20 m² x 7 m) / 2 = 70 m³
b) When comparing the environmental impacts of each house, several factors need to be considered:
Positive impacts:
1. Material usage: Tiny houses use fewer materials, reducing resource consumption and waste generation.
2. Energy efficiency: Smaller living spaces require less energy for heating, cooling, and lighting, leading to lower energy consumption.
3. Land utilization: Tiny houses can be built on smaller plots of land, preserving green spaces and reducing urban sprawl.
Negative impacts:
1. Construction materials: Although tiny houses use less material overall, the environmental impact depends on the types of materials used. Sustainable and eco-friendly materials should be prioritized.
2. Water and waste management: Adequate provisions for water supply and waste disposal should be implemented to minimize environmental impacts.
3. Transportation: The transportation of tiny houses to their locations can contribute to carbon emissions if not done efficiently.
c) The choice of design for a tiny house depends on personal preferences and priorities. However, considering the provided information:
The house on the left offers a larger interior space of 126 m³, providing more room for living and storage. It may be suitable for individuals or couples who desire more space and functionality within their tiny house.
The triangular house has a smaller interior volume of 70 m³ but offers a unique design and aesthetic appeal. It may be preferred by individuals who prioritize a distinctive architectural style or who are looking for a minimalist and cozy living space.
Ultimately, the selection depends on individual needs, preferences, and the intended use of the tiny house. Factors such as lifestyle, desired amenities, and personal values regarding sustainability and resource conservation should be considered when making the final decision.
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Determine the constant different in this numeric pattern:5;9;13;17;21
Hi student, let me help you out!
..........................................................................................................................
-----------------------------------
Part 1. Sequence - Arithmetic or Geometric?If a sequence is arithmetic, we add or subtract the same amount to get to the following term.If a sequence is geometic, we multiply or divide by the same amount.✨
---------------------------------
Part 2. Common Difference or Ratio?In arithmetic sequences, the amount we add or subtract is the common difference.In geometric sequences, the amount we multiply or divide by is the common ratio.Please see Part 1 for explanation of arithmetic/geometric sequences.
✨
---------------------------------
Part 3. How to Find the C.D. or C.R.?What do we add/subtract from each term to get the following term? In the given sequence, we add 4.What do we multiply/divide by to get the next term?This given sequence doesn't have a common ratio; it's arithmetic.
A sequence can't be both arithmetic and geometric.
∴, the common difference is ✨4.
Hope this helped you out, ask in comments if any queries arise.
Best Regards!
\(\bigstar\underline{\overline{\underline{\overline{Reach\:Far,\:Aim\:high,\:Dream\:big!}}}}\)
Consider a simulation experiment in which the population distribution is quite skewed. The figure below shows the density curve for lifetimes of_a certain type of electronic control [this is actually a lognormal distribution with E(ln(X)) = 3 and V(ln(X)) = 0.16]. The statistic of interest is the sample mean X. The experiment utilized 500 replications and considered these sample sizes: n = 5, n = 10, n = 20, and n = 30. The resulting histograms along with a normal probability plot from MINITAB for the x values based on n = 30 are shown in the figures below. Density curve for the simulation experiment (E(A) = 21.7584, V(X) = 82.1449]
In this simulation experiment, the population distribution represents the lifetimes of a certain type of electronic control and the density curve in the figure represents the population distribution.
The distribution is skewed and follows a lognormal distribution with an expected value of ln(X) equal to 3 and a variance of ln(X) equal to 0.16. The experiment consisted of 500 replications and examined different sample sizes: n = 5, n = 10, n = 20, and n = 30.
The density curve in the figure represents the population distribution, with an expected value of E(A) equal to 21.7584 and a variance of V(X) equal to 82.1449. The histograms shown illustrate the distribution of sample means for the different sample sizes. Additionally, a normal probability plot from MINITAB is included for the x-values based on a sample size of n = 30, allowing for an assessment of the normality assumption for the sample means.
These visual representations provide valuable insights into the characteristics of the simulated experiment's population distribution, as well as the behavior of the sample means for different sample sizes.
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The complete question is:
Consider a simulation experiment in which the population distribution is quite skewed. The figure below shows the density curve for lifetimes of_a certain type of electronic control [this is actually a lognormal distribution with E(ln(X)) = 3 and V(ln(X)) = 0.16]. The statistic of interest is the sample mean X. The experiment utilized 500 replications and considered these sample sizes: n = 5, n = 10, n = 20, and n = 30. The resulting histograms along with a normal probability plot from MINITAB for the x values based on n = 30 are shown in the figures below. Density curve for the simulation experiment (E(A) = 21.7584, V(X) = 82.1449].
Using M&Ms once you find the probability of the colors out of a bag, how do you determine if all the colors are equally likely based on your probabilities, and why or why not?
To determine if all the colors are equally likely, compare the expected probabilities with the observed probabilities. If they are close, then the colors are likely equally likely.
To determine if all the colors in a bag of M&Ms are equally likely based on the probabilities, you need to compare the observed probabilities with the expected probabilities.
First, calculate the expected probability for each color by dividing the total number of M&Ms of that color by the total number of M&Ms in the bag. For example, if there are 10 red M&Ms out of 50 total M&Ms, the expected probability for red would be 10/50 = 1/5.
Next, compare the expected probabilities with the observed probabilities. If the observed probabilities are close to the expected probabilities for all the colors, then it suggests that the colors are equally likely. However, if there is a significant difference between the observed and expected probabilities, it indicates that the colors are not equally likely.
For example, if the observed probability for red is 1/10 instead of 1/5, it suggests that red is less likely compared to what would be expected if the colors were equally likely.
In summary, to determine if all the colors are equally likely, compare the expected probabilities with the observed probabilities. If they are close, then the colors are likely equally likely.
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Please help! Solve for x: 24+37+2x=76
Answer: X= 7.5
Step-by-step explanation:
You have to add the like terms 24+37 which gives you 61. Then subtract 76-61 which is 15. Then divide 15/2 which is 7.5
At noon, Trevor and Kim start running from the same point. Trevor runs east at a speed of 8 km/h and Kim runs west at a speed of 6 km/h. At what time will they be 21 km apart?
Trevor and Kim will be situated 21 kilometers apart from each other at 1:30 PM. They will be separated by a distance of 21 km when the clock strikes 1:30 in the afternoon.
To determine at what time Trevor and Kim will be 21 km apart, we can set up a distance-time equation based on their relative speeds and distances.
Let's assume that t represents the time elapsed in hours since noon. At time t, Trevor would have traveled a distance of 8t km, while Kim would have traveled a distance of 6t km in the opposite direction.
Since they are running in opposite directions, the total distance between them is the sum of the distances they have traveled:
Total distance = 8t + 6t
We want to find the time when this total distance equals 21 km:
8t + 6t = 21
Combining like terms, we have:
14t = 21
To solve for t, we divide both sides of the equation by 14:
t = 21 / 14
Simplifying, we find:
t = 3 / 2
So, they will be 21 km apart after 3/2 hours, which is equivalent to 1 hour and 30 minutes.
Therefore, Trevor and Kim will be 21 km apart at 1:30 PM.
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Ivan is getting ready for a long road trip. He wants to pack a few books from his collection of 5 novels and 7 collected short stories books. He asks his friend to select a book without showing. From the remaining books, Ivan then himself picks a random book, which turns out to be a novel. The third book that he randomly selects from the remaining ones is also a novel. Find the probability that Ivan will have 3 novels to read during the road trip.
Answer:
The probability that Ivan will have 3 novels to read during the road trip is 0.0455
Step-by-step explanation:
Given;
number of novels = 5
number of short stories = 7
total number of books = 12
The probability that Ivan's friend pick's a novel = 5 / 12
The probability of Ivan's first pick to be a novel = 4 / 11
The probability of Ivan's second pick to be a novel = 3 /10
The probability that Ivan will have 3 novels to read during the road trip is given by;
= p(Ivan's friend pick) and P(Ivan's first pick) and P(Ivan's second pick);
\(= \frac{5}{12}*\frac{4}{11}*\frac{3}{10}\\\\ = \frac{1}{22}\\\\ = 0.0455\)
Therefore, the probability that Ivan will have 3 novels to read during the road trip is 0.0455
IF ANYONE HELPS ME WITH THIS I WILL GIVE U BRAINLIEST AND 100 POINTS BTW ITS INTEGRALS FOR CALCULUS
Answer:
\(\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx = \frac{e^\bigg{\frac{1}{4}}}{8} - \frac{e^\bigg{\frac{1}{9}}}{8}\)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightAlgebra I
Terms/CoefficientsFactoringExponential Rule [Rewrite]: \(\displaystyle b^{-m} = \frac{1}{b^m}\)Calculus
Derivatives
Derivative Notation
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Integrals
Definite IntegralsIntegration Constant C
Integration Rule [Fundamental Theorem of Calculus 1]: \(\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)\)
Integration Property [Multiplied Constant]: \(\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx\)
U-Substitution
eˣ Integration: \(\displaystyle \int {e^u} \, dx = e^u + C\)
Step-by-step explanation:
Step 1: Define
\(\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx\)
Step 2: Integrate Pt. 1
Identify variables for u-substitution.
Set: \(\displaystyle u = 4x^{-2}\)[u] Differentiate [Derivative Rule - Basic Power Rule]: \(\displaystyle du = -8x^{-3} \ dx\)[du] Rewrite [Exponential Rule - Rewrite]: \(\displaystyle du = \frac{-8}{x^3} \ dx\)Step 3: Integrate Pt. 2
[Integral] Rewrite [Integration Property - Multiplied Constant]: \(\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^6_4 {\frac{-8}{x^3}e^{4x^{-2}}} \, dx\)[Integral] U-Substitution: \(\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{1}{9}}_{\frac{1}{4}} {e^u} \, dx\)[Integral] eˣ Integration: \(\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx = \frac{-1}{8}(e^u) \bigg| \limits^{\frac{1}{9}}_{\frac{1}{4}}\)Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: \(\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx = \frac{-1}{8} \bigg[ -e^\bigg{\frac{1}{9}} \bigg( e^\bigg{\frac{5}{36}} - 1 \bigg) \bigg]\)Simplify: \(\displaystyle \int\limits^6_4 {\frac{1}{x^3}e^{4x^{-2}}} \, dx = \frac{e^\bigg{\frac{1}{4}}}{8} - \frac{e^\bigg{\frac{1}{9}}}{8}\)Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e
Which line is wrong?
Students were given a sensation-seeking test and then divided into two groups based on their scores. A researcher observed how many times students in each group got out of their seats over the course of 2 hours. The dependent variable is:
The dependent variable in this study is the number of times the students got out of their seats over the course of 2 hours.
The independent variable is the variable that is being manipulated or controlled by the researcher.
It is the variable that is expected to cause a change in the dependent variable which is the variable being measured as the outcome or response to the manipulation of the independent variable.
In the given scenario, the independent variable is the group assignment based on the scores on the sensation-seeking test.
The researcher has divided the students into two groups based on their scores, and this grouping is being used as a way of manipulating or controlling the students' level of sensation-seeking behavior.
The researcher is interested in how this manipulation affects the students' behavior in terms of getting out of their seats.
The dependent variable is the number of times the students got out of their seats over the course of 2 hours.
This variable is expected to vary depending on the level of the independent variable, which is the group assignment based on the sensation-seeking test scores.
The researcher will measure the dependent variable for each group separately and then compare the results to determine if there is a significant difference between the two groups.
In summary,
The independent variable is the grouping of the students based on their scores on the sensation-seeking test and the dependent variable is the number of times the students got out of their seats over the course of 2 hours.
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Two-thirds of the people in a room are seated in three-fourths of the chairs. The rest of the people are standing. If there are 6 empty chairs, how many people are in the room?
Answer:
27 people
Step-by-step explanation:
If 6 chairs are empty, that means 1/4 of the chairs is 6.
6*4 = 24, the total amount of chairs.
24 - 6 = 18, the number of chairs occupied.
If 18 people is 2/3 of the amount of people, if we divide 18 by 2, getting 9, that is 1/3 of the amount of people.
9 * 3 = 27, the total amount of people.