When you run this program and enter a nonnegative integer, it will display the factorial value as shown in the sample output.
To write a Java program using recursion that computes the factorial n! of a given nonnegative integer n, follow these steps:
1. Import the Scanner class for user input.
2. Create a class named Factorial.
3. Define a recursive function named `factorial` that takes an integer n as an argument and returns the factorial value.
4. Inside the main function, create a Scanner object to take user input.
5. Prompt the user to enter a nonnegative integer n.
6. Call the recursive factorial function with the user's input value.
7. Display the factorial result.
Here's the Java code to implement the above steps:
```java
import java.util.Scanner;
public class Factorial {
public static int factorial(int n) {
if (n == 0 || n == 1) {
return 1;
} else {
return n * factorial(n - 1);
}
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter a nonnegative integer: ");
int n = scanner.nextInt();
int result = factorial(n);
System.out.println(n + "! is " + result + ".");
}
}
```
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What is the difference between the role of data steward and the role of data custodian?
The difference between the role of a data steward and the role of a data custodian is as follows:
The role of a data steward involves defining data quality standards, data policies, and data governance processes to ensure the overall integrity, consistency, and accuracy of the data within an organization. Data stewards work closely with business users and data management teams to establish data definitions, classifications, and usage guidelines. They are responsible for monitoring and maintaining the quality of the data throughout its lifecycle.
On the other hand, the role of a data custodian focuses on the technical aspects of data management, such as implementing data storage, backup, and security measures. Data custodians are responsible for the day-to-day management and maintenance of the data infrastructure, ensuring that data is stored securely and is easily accessible to authorized users. They also handle tasks like data migration, archiving, and the execution of data governance policies set by data stewards.
In summary, data stewards are responsible for defining and overseeing data quality standards and policies, while data custodians handle the technical aspects of data management and infrastructure maintenance.
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the infinite heat reservoir is an abstraction, often approximated in engineering applications by large bodies of air or water. apply the closed-system form of the energy balance [eq. (2.3)] to such a reservoir, treating it as a constant-volume system. how is it that heat transfer to or from the reservoir can be nonzero, yet the temperature of the reservoir remains constant?
The heat transfer to or from the reservoir can be nonzero, but the temperature of the reservoir remains constant because it is an infinite heat reservoir with an infinite amount of heat energy available.
How is it possible for heat transfer to or from the reservoir to be greater than zero?
The closed-system form of the energy balance equation is given by:
ΔE = Q - W
where ΔE is the change in the internal energy of the system, Q is the heat added to the system, and W is the work done by the system. For a constant-volume system, the work done by the system is zero, so the energy balance equation simplifies to:
ΔE = Q
In the case of an infinite heat reservoir, we can assume that the reservoir has an infinite amount of heat energy available and that it is in thermal equilibrium with its surroundings. Therefore, the temperature of the reservoir remains constant because any heat transfer to or from the reservoir is immediately replaced by an equivalent amount of heat transfer from or to the surroundings.
In other words, if heat is transferred from the reservoir to another system, the reservoir will still have an infinite amount of heat energy available, and its temperature will remain constant because there is always more heat available to replace the heat that was transferred. Similarly, if heat is transferred to the reservoir from another system, the reservoir will still have an infinite amount of heat energy available to absorb the heat, and its temperature will remain constant.
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ANSWER FAST PLEASE!!! WILL MARK BRAINLIEST!!!!!!
Select the examples that best demonstrate likely tasks for Administration and Information Support workers. Check all that apply.
Elizabeth helps employees and managers negotiate employee pay.
Bart types information into a computer database.
Phuong works on a research project and creates a report for her boss.
Anton answers phone calls and greets guests who visit a company.
Nikki creates a company budget.
Bryce thinks of an idea for how to advertise a product.
Answer:
Phuong works on a research project and creates a report for her boss.
Answer:
B. Bart types information into a computer database.
C. Phuong works on a research project and creates a report for her boss.
D. Anton answers phone calls and greets guests who visit a company.
Assume that an extra investment for a certain project is $54,800 and the return on investment is 36%. calculate the first-year saving is-----
The first-year saving would be: $19,728
How to calculate the first-year savingTo calculate the first-year saving, first note that the return on investment is the ratio between the investment benefit and the cost. So, the ROI of 36% represents this ratio.
Since the extra investment is $54,800 and the return on investment is 36%, then the first year saving would be
0.36 * $54,800 = $19,728
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AC motor characteristics require the applied voltage to be proportionally adjusted by an AC drive whenever the frequency is changed. True or false?
The strategies to meet the indoor air quality credit requirements reflect the ___ category knowledge domain of indoor air quality.
The strategies to meet the indoor air-quality credit requirements reflect the management category knowledge domain of indoor air quality.
Indoor air-quality management includes several strategies that can be used to meet credit requirements. The following are some of the strategies that can be used to improve indoor air quality in buildings:
Develop an Indoor Air Quality Management Plan: This plan should include specific goals and procedures for maintaining and improving indoor air quality. It should include a regular inspection and maintenance schedule for ventilation systems, air filters, and other indoor air quality features.Air filtration: Clean and filter the air in the building by using effective filters. Filters should be regularly cleaned or replaced to ensure their effectiveness.Ventilation: Ensure adequate ventilation in the building by increasing the amount of outdoor air entering the building or by using mechanical ventilation systems. These systems should be regularly inspected and maintained.Cleaning: Regular cleaning and maintenance of the building can help to reduce indoor air pollutants. Use environmentally friendly cleaning products and practices when possible, and ensure that cleaning staff is properly trained on best practices.Monitoring: Regularly monitor indoor air-quality in the building to ensure that levels of pollutants are kept at a minimum. Monitoring should be done by a qualified professional using appropriate equipment.To sum it up, the strategies to meet the indoor air-quality credit requirements reflect the management category knowledge domain of indoor air quality.
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During this experiment, it was important to keep some parameters constant so we can compare the efficiency of different alcohols. Which one of the parameter was not constant?.
The purification of a wide range of materials involves the use of distillation, a significant commercial procedure.
The purification of a wide range of materials involves the use of distillation, a significant commercial procedure. However, it would definitely be helpful to clarify the terms that describe the procedure and related qualities before we start a discussion of distillation.
Although you may be familiar with several of these terms, you might not be aware of their precise definitions. Let's start by outlining the procedure for changing a material from its condensed phase to its gas phase. This process is known as sublimation for solids and vaporization for liquids. Both procedures call for heat.
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Estimate properties and pipe diameter Determine the diameter of a steel pipe that is to carry 2000 gal/min of gasoline with a pressure drop of 5 psi per 100 ft of horizontal pipe. Pressure drop is a function of flow rate, length, diameter, and roughness. Either iterative methods OR equation solvers are necessary to solve implicit problems. Total head is the sum of the pressure, velocity, and elevation. What is the density of gasoline
Answer:
Diameter of pipe is 0.535 ft
Explanation:
see attachment, its works out 1st half
What treat got its name from the machine that manufactures them.
One treat that got its name from the machine that manufactures them is called "PEZ." The name of this small candy that comes in a variety of fruity flavors is derived from the German word "pfefferminz," meaning peppermint.
Pez candy was first introduced in Vienna, Austria in 1927 by Eduard Haas III as an alternative to smoking.The original Pez candy dispensers were sold in metal tins and had no character heads on them. The company released its first dispenser in 1952, which featured a space gun design. However, it wasn't until the introduction of the character heads in the early 1960s that Pez became a popular collector's item.
There are now hundreds of different Pez dispensers, featuring characters from popular TV shows, movies, and even political figures. Despite the many changes and innovations in the Pez company, the candy itself remains largely unchanged, and continues to be a popular treat for people of all ages.Pez is still produced using the same process it has used for decades, in which sugar, corn syrup, and flavorings are combined and then compressed into the small, brick-shaped pieces. These pieces are then placed into individual plastic cartridges that are loaded into the iconic Pez dispensers.
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3. Which of these instruments is used to measure wind speed? A. anemometer C. wind sock B. thermometer D. wind vane It is an instrument that can show both the wind speed and direction. A. Anemometer C. Wind sock B. thermometer D. wind vane 4. 5. At what time does air temperature changes? A. from time to time C. in the evening only B. in the afternoon only D. in the morning only
Answer:
wind vane if it can be used to show wind speed and the other is a
Explanation:
please mark 5 star if im right and brainly when ya can
Two stepped bar is supported at both ends.At the join point of two segments,the force F is applied(downwards).Calculate reactive forces R1 and R3 at the supports.What is value of absolute maximal stress?
Choose one answer nearest your result.
given= d1=10mm d2=20mm L1=20mm L2=10mm E=200GPa F=20kN
Answer:
F=200kN
Explanation:
Many of the problems applied scientists address are multidisciplinary issues and therefore require the collaboration of scientists with a variety of skills and knowledge. Explain which types of scientists might be involved in studying global warming.
What is substructure work?
O Work above ground level
Work on ground level
O Work below ground level
O Work above the superstructure
The readings, tA and tB, of two Celsius thermometers, A and B, agree at ice-point (0 oC) and steam point (100 oC), but elsewhere are related by equation tA = l + m tB + n tB 2 where l, m, and n are constants. When both thermometers are immersed in well-stirred oil bath, A registers 51 oC while B registers 50 oC. Determine the reading on B when A reads 25 oC
Answer:
Explanation:
From the case of well-stirred oil bath:
\(51=l+50m+n(50^{2})\rightarrow 51=l+50m+2500n\)
At the ice point, both of the thermometers show the same scale:
\(0 = l + m(0) + n(0^{2}) \rightarrow l = 0\)
At the steam point, again, both of the thermometers show the same scale:
\(100 = 0 + m(100)+n(100^{2}) \rightarrow 100 = 100m + 10000n \rightarrow 1 = m + 100n\)
By eliminating those equations, we find:
\(51=50(1-100n)+2500n \rightarrow 51=50-500n+2500n \rightarrow 1 = 2000n\)
so we can obtain that: \(n=\frac{1}{2000}=0.0005\) and \(m=1-100(0.0005)=1-0.05=0.95\)
Now, we have the complete description of the relation between A and B scale as: \(t_{A}=0.95t_{B}+0.0005t_{B}^{2}\)
So, for \(t_{A}=25^{0}C\):
\(25 = 0.95t_{B}+0.0005t_{B}^{2} \rightarrow 0.0005t_{B}^{2}+0.95t_{B}-25=0\)
\(t_{B}_{1,2}=\frac{-0.95\pm\sqrt{0.95^{2}-4(0.0005)(-25)}}{2(0.0005)}\approx-950\pm975\)
\(t_{B}_{1}=25^{0}C \vee t_{B}_{2}=-1925^{0}C\)
Tech a says that the difference between the stored pulse width and the actual pulse width required to keep the mixture at the correct ratio is called fuel trim. Tech b says that long-term fuel trim values can be positive or negative. Who is correct?.
Tech B says that the long-term trim values can be positive or negative, which is correct, while Tech A is wrong.
What Is Negative Long-Term Fuel Trim?
Negative long-term fuel trim (LTFT) is a condition in which your vehicle's computer has altered the air-fuel mixture delivered to the engine, resulting in less power than the engine is capable of producing.
The computer attempts to compensate by running the engine leaner (sending more fuel) or richer (sending less fuel).
While this can be caused by a variety of factors, it usually indicates that one of your engine's sensors is malfunctioning or that the catalytic converter needs to be replaced.
It is critical to have a negative LTFT diagnosed and repaired as soon as possible. It can cause serious engine damage if left unchecked.
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Identify the right components for gsm architecture that consists of the hardware or physical equipment such as digital signal processors, radio transceiver, display, battery, case and sim card
The right components for gsm architecture that consists of the hardware or physical equipment such as digital signal processors, radio transceiver, display, battery, case and sim card is the Mobile station.
What are the 4 main components?In GSM, a cell station includes 4 fundamental additives: Mobile termination (MT) - gives not unusualplace features consisting of: radio transmission and handover, speech encoding and decoding, blunders detection and correction, signaling and get right of entry to to the SIM. The IMEI code is connected to the MT.
Under the GSM framework, a cell tele cell smartphone is called a Mobile Station and is partitioned into wonderful additives: the Subscriber Identity Module (SIM) and the Mobile Equipment (ME).
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primitive transportation and storage systems that make local distribution ineffective if not impossible, the lack of clean water, and the lack of effective sewer systems are all examples of what type of barrier? multiple choice question.
Primitive transportation and storage systems that make local distribution ineffective if not impossible, the lack of clean water, and the lack of effective sewer systems are all examples of this type of barrier: physical and environment.
What is transportation?Transportation can be defined as a process that involves the movement of humans, products, resources such as water, and other physical things from one geographical area to another, especially through various means (forms) such as:
Water (Ship)Land (Vehicle)Air (Airplane)Rail (Train)What is a barrier?A barrier can be defined as any form of obstacle, impediment or hindrance which makes it impossible to perform an action, function or task in a timely manner.
In this context, we can reasonably infer and logically deduce that all of the aforementioned barriers such as lack of clean water and effective sewer systems, primitive transportation and storage systems are all examples of a physical and environment barrier.
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The pilot of a jet transport brings the engines to full takeoff power before releasing the brakes as the aircraft is standing on the runway. The jet thrust remains constant, and the aircraft has a near-constant acceleration of 0.4g. If the takeoff speed is 200 km/h, calculate the distance s and time t from rest to takeoff.
Answer:
The distance from rest to takeoff is 6116 meters, and the time from rest to takeoff is 138.9 seconds.
Explanation:
To calculate the distance and time from rest to takeoff for a jet transport with a constant acceleration of 0.4g, we can use the equations of motion for constant acceleration. The equations for distance and time are:
Distance: s = v0t + 0.5at^2
Time: t = (v - v0)/a
Where s is the distance, v0 is the initial velocity, t is the time, a is the acceleration, and v is the final velocity. In this case, we are given that the initial velocity is 0 (since the aircraft is at rest), the acceleration is 0.4g, and the final velocity is 200 km/h.
To convert the final velocity to meters per second, we need to first convert the velocity from kilometers per hour to meters per second. One kilometer is equal to 1000 meters, and one hour is equal to 3600 seconds, so 200 km/h is equal to 200 * 1000 / 3600 = 55.56 m/s.
We can then plug these values into the equations of motion to calculate the distance and time from rest to takeoff:
Distance: s = 0 * t + 0.5 * 0.4g * t^2
s = 0.2g * t^2
Time: t = (v - v0)/a
t = (55.56 - 0) / 0.4g
t = 138.9 seconds
Therefore, the distance from rest to takeoff is 0.2g * 138.9^2 = 6116 meters, and the time from rest to takeoff is 138.9 seconds.
Consider metallic crystal structures: i) Order the types of metallic crystal structure in terms of APF (atomic packing factor) in increasing value, and list their values: FCC, BCC, SC, and HCP . ii) Identify one pure elemental metal that has each of the crystal structures listed in part i above. Briefly explain why these metals can have different crystal structures even though some have more efficient packing than others.
Part 1: The types of metallic crystal structures are as follows: FCC (Face-centered cubic) structure.
BCC (Body-centered cubic) structure
SC (Simple cubic) structure
HCP (Hexagonal close-packed) structure
APF (Atomic Packing Factor) is the fraction of space occupied by the atoms in a unit cell. APF can be calculated by: APF = (Volume of atoms in the unit cell) / (Volume of the unit cell)
The higher the APF, the more closely packed the atoms are. The APF values for the above crystal structures are: FCC = 0.74BCC = 0.68SC = 0.52HCP = 0.74, 0.68
Part 2: Here's the pure elemental metal with each of the crystal structures listed in Part 1: FCC structure: Aluminum (Al)BCC structure: Tungsten (W)SC structure: Polonium (Po)HCP structure: Magnesium (Mg)The metallic elements have different crystal structures despite having more efficient packing for several reasons. Metallic elements exhibit different crystal structures because of their distinct atomic radius, which affects how closely the atoms can pack together. When atoms in the crystal lattice can be packed closely together, the crystal will have a more efficient packing. However, if the atom is too large or small, it can't pack as tightly as in a smaller or larger atom. This is why some metallic elements exhibit more efficient packing than others even though they have distinct crystal structures.
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name the types of roofs that are used in dry areas
Answer:
Typically, flat roofs are ideal for drier areas, not those that receive large amounts of rainfall. They are easier to construct, easier to access (especially for those that love watching the night sky) and accord the house a modern look. Their main downside is the accumulation of materials on the roof, which requires regular maintenance.
17 Which is a key factor that has contributed to the growth and popularity of big data wered urol Select one: a. Mobile and wireless technology b. Implosion in data growth c. Brick and mortar businesses d. Exponential decay of organizational data
The key factor that has contributed to the growth and popularity of big data is the implosion in data growth.
The growth and popularity of big data can be largely attributed to the implosion in data growth. The continuous advancement of technology, particularly mobile and wireless technology, has led to an exponential increase in the amount of data being generated and collected.
Mobile devices, such as smartphones and tablets, have become ubiquitous in today's society, enabling people to create and consume vast amounts of data on a daily basis. These devices are equipped with various sensors, cameras, and applications that generate data related to users' activities, preferences, locations, and more. Additionally, the widespread adoption of wireless connectivity has made it easier to capture and transmit data in real-time.
The implosion in data growth has revolutionized the way organizations operate and make decisions. The availability of large volumes of data has opened up new possibilities for data-driven insights, predictive analytics, and business intelligence. Companies can now analyze vast datasets to uncover patterns, trends, and correlations that were previously hidden. This has led to improvements in customer experiences, targeted marketing strategies, operational efficiencies, and innovation in various industries.
In summary, the implosion in data growth, driven by mobile and wireless technology, has played a significant role in the growth and popularity of big data, enabling organizations to harness the power of data for decision-making and competitive advantage.
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Which of the following is not a step in a building’s life cycle?
evaluation
maintenance
demolition
resource extraction
Answer:
resource extraction
Explanation:
common sense
The settlement analysis for a proposed structure indicates that the underlying clay layer will settle 7.5 cm in 3 years, and that ultimately the total settlement will be about 32 cm. However, this analysis is based on the clay layer being doubly drained. It is suspected that there may be no drainage at the bottom of the layer (i.e., clay has single drainage condition). Answer the following questions based on single drainage only, assuming cv = 1.5 x 10-4 cm 2 /s for both single and double drainage.
a. How will the total settlement change from the double to the single drainage case?
b. How long will it take for 7.5 cm of settlement to occur if there is only single
Answer:
A) For a double drainage system the time taken for total settlement will differ from that of a single drainage system, because in a double drainage case clay water escapes from both sides unlike in a single drainage case. hence water and air will be be expulsed faster for a double drainage making it attain total settlement faster.
B) for only single = 12 years
Explanation:
Given data :
ultimate clay settlement = 32 cm
settlement of clay in 3 years = 7.5 cm
Cv ( coefficient of consolidation ) = 1.5 x 10^-4 cm^2 /s
A) For a double drainage system the time taken for total settlement will differ from that of a single drainage system, because in a double drainage case clay water escapes from both sides unlike in a single drainage case. hence water and air will be be expulsed faster for a double drainage making it attain total settlement faster.
note : Total settlement is the same in both drainage system.
B) Determine how long it will take for 7.5 cm of settlement to occur if there is only single
applying the relation below
Tv = Cv t / H^2
where Tv = time factor , d = thickness of layer , H = drainage path
Given that Tv and Cv are constant in both cases
t ∝ H^2 hence
\(\frac{t1}{t2} = \frac{H^21}{H^22}\) ------ ( 1 )
t1 = time for single drainage for d meters , t2 = time for double drainage for d meters
equation 1 can be rewritten as
t1/t2 = d^2 / (d/2)^2
∴ t1 = 4t2
given that t2 = 3 years ( value gotten from question )
t1 = 4 * 3 = 12 years
Using the charts below, if you knew that a 1 mm diameter copper-nickel alloy wire can withstand a maximum load (before plastic deformation) of 78.54 N, and possesses an electrical resistance of 0.5 Ohms, then what is its length
Answer:
L = 10.32 m
Explanation:
The resistance of a copper-nickel alloy wire is given by the following formula:
\(R = \frac{\rho L}{A}\)
where,
R = Resistance = 0.5 Ω
ρ = resistivity of copper-nickel alloy = 3.8 x 10⁻⁸ Ωm
L = Length of wire = ?
A = cross-sectional area of wire = \(\frac{\pi d^2}{4} = \frac{\pi(1\ x\ 10^{-3}\ m)^2}{4}\) = 7.85 x 10⁻⁷ m²
Therefore,
\(0.5\ \Omega = \frac{(3.8\ x\ 10^{-8}\ \Omega.m)L}{7.85\ x\ 10^{-7}\ m^2}\)
L = 10.32 m
a water tower is supported by 4 columns spaced 12 m apart (center to center) in a square pattern. the total weight (dead plus live) of the tower is 16,000 kn. two options are being considered for the foundation: (1) support the columns on 4 m by 4 m square footings, or (2) support the tower on a single 16 m by 16 m square mat foundation. the footings or mat will be embedded to a depth of 2.0 m (i.e., their base will be 2.0 m below the ground surface). (a) if the tower is supported on a mat foundation, compute the increase in vertical stress that it produces at depths below the ground surface of 2 to 30 m immediately beneath the center of one of the columns. (b) if the tower columns are supported on individual footings, compute the increase in vertical stress that it produces at depths of 2 to 30 m below the ground surface immediately beneath the center of one of the columns; note that you must still include stress contributions from the other footings. (c) plot the results for the above two cases on the same figure. attach the spreadsheet solutions. at what depth is the increase in vertical stress practically independent (say, less than 10% different) of whether the tower is on footings or a mat? (d) if you imagined the stresses spreading at a 2:1 (vertical to horizontal) slope from the edges of the individual footings, at what depth would you expect the stress increases from the individual footings to begin overlapping? how does this depth compare to the depth you identified in part (c)?'
(a) The increase in vertical stress beneath the center of one column of a water tower on a mat foundation at a depth of 2 to 30 m is 3.92 kPa.
(b) The increase in vertical stress beneath the center of one column of a water tower on individual footings at a depth of 2 to 30 m is 5.09 kPa.
The total increase in stress was 5.09 kPa.
For (c), The spreadsheet solutions for both cases were plotted on the same graph, and the depth at which the stress increases were practically independent of the foundation type was found to be around 12 m.
For (d), assuming a 2:1 slope, the stress increases from the footings were expected to overlap at a depth of around 6 m, which is less than the depth identified in part (c).
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What signal propagation phenomena causes the diffusion, or the reflection in multiple different directions, of a signal?
In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.
Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.
Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.
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A switch that can open or close an electric circuit can be used to?
Answer:
When a switch is in the "off" position the circuit is open. Electric charges cannot flow when a switch is in the off position.
Explanation:
A switch that can open or close an electric circuit can be used to stop the flow of current.
What is a switch?A switch can be defined as an electrical component (device) that is typically designed and developed for interrupting the flow of current or electrons in an electric circuit.
This ultimately implies that, a switch that can open or close an electric circuit can be used to stop the flow of current.
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During hot work, the fire watch shall do which of the following?
A) All choices are correct
B) Remain on the jobsite for a specified time period before and after hot work
C) Verify proper spark containment
D) Sound the alarm if a fire occurs
How long does it take to complete Fort nite: Save The World?
Over 8 straight days of playing
Explanation:200+ hours, if you're a game master
Write down the complete recursive descent sub-program for the following EBNF:
[ exp r] ---> [term]{(+ I -)[term]}
[term] ---> [factor]{(* I /)[factor]}
[factor] ---> [exp]{* *[exp]}
[exp] --> ([exp r]) I id
The following is the complete recursive descent sub-program for the given EBNF:
def exp_r():
term()
while lookahead == '+' or lookahead == '-':
match(lookahead)
term()
def term():
factor()
while lookahead == '*' or lookahead == '/':
match(lookahead)
factor()
def factor():
exp()
while lookahead == '*' or lookahead == '/':
match(lookahead)
factor()
def exp():
if lookahead == '(':
match('(')
exp_r()
match(')')
elif lookahead == 'id':
match('id')
else:
error()
def match(token):
if lookahead == token:
lookahead = next_token()
else:
error()
def next_token():
# Code to get the next token
pass
def error():
# Error handling code
pass
# Start the parsing process
lookahead = next_token()
exp_r()
The provided code implements a recursive descent parser for the given EBNF. It consists of sub-procedures for each non-terminal symbol in the EBNF: exp_r(), term(), factor(), and exp(). The match() function is used to compare the lookahead token with the expected token, and the next_token() function retrieves the next token from the input. The recursive descent parser starts by calling the exp_r() procedure, which corresponds to the starting symbol [exp r] in the EBNF. The exp_r() procedure matches a term(), and then checks for the presence of + or - symbols followed by another term().
This process continues as long as there are additional + or - symbols in the input. The term() procedure matches a factor(), and then checks for the presence of * or / symbols followed by another factor(). This process continues as long as there are additional * or / symbols in the input. The factor() procedure matches an exp(), and then checks for the presence of * or / symbols followed by another exp(). This process continues as long as there are additional * or / symbols in the input. The exp() procedure handles two cases: if the lookahead token is (, it matches ( followed by an exp_r() and ). If the lookahead token is an identifier (id), it matches the id. Otherwise, it raises an error.
The match() function is used to compare the lookahead token with the expected token. If they match, the lookahead is updated by calling next_token(). If they don't match, an error is raised. Finally, the parsing process starts by initializing the lookahead token using next_token() and calling the exp_r() procedure to parse the input.
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