Write a sequence of transformations that maps quadrilateral abcd.

Answer: The equation is 16g+6 ,lmk if you need the answer :)

Step-by-step explanation:

The scale factor of TRAP to EZYD is 1.25.

Dilation is the increase or decrease in the size of a figure by a scale factor of k. If k > 1 it is an increase and if k < 1, it is a decrease.

To find the scale factor of TRAP to EZYD:

Scale factor = ZE / TR = 15 / 12 = 1.25

The scale factor of TRAP to EZYD is 1.25.

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Answer:

360 kilometers per 4 hours

Step-by-step explanation:

25 meters per second -> kilometers per hour

1000 meters per kilometer

60 seconds per minute

90 kilometers per hour

90 x 4 = 360 kilometers

The possible approximate lengths of b are: 2.3 units and 7.8 units

We know that the law of sines for triangle is:

The ratios of the length of all sides of a triangle to the sine of the respective opposite angles are in proportion.

This means, for triangle ABC,

\(\frac{sin~ A}{a} =\frac{sin~B}{b} =\frac{sin~ C}{c}\)

where a is the length of side BC,

b is the length of side AC,

c is the length of side AB.

For triangle ABC consider an equation from sine law,

\(\frac{sin~ A}{a} =\frac{sin~ C}{c}\)

here, c = 5.4, a = 3.3, and m∠A = 20°

\(\frac{sin~ 20}{3.3} =\frac{sin~ C}{5.4}\\\\\frac{0.3420}{3.3} =\frac{sin~ C}{5.4}\)

0.3420 × 5.4 = 3.3 × sin(C)

sin(C) = 0.5596

∠C = arcsin(0.5596)

∠C = 34.03°  OR 145.9°

∠C ≈ 34° OR 146°

We know that the sum of all angles of triangle is 180 degrees.

so, ∠A + ∠B + ∠C = 180°

when m∠C = 34°,

20° + ∠B + 34.03° = 180°

∠B = 125.97°

m∠B = 126°

when m∠C = 146°,

20° + ∠B + 146° = 180°

m∠B = 14°

Now consider equation,

\(\frac{sin~ A}{a} =\frac{sin~ B}{b}\\\\\frac{sin~20^{\circ}}{3.3} =\frac{sin~ 126^{\circ}}{b}\)

b × 0.3420 = 0.8090 × 3.3

b = 7.8 units

when m∠B = 14°,

\(\frac{sin~20^{\circ}}{3.3} =\frac{sin~ 14^{\circ}}{b}\)

b × 0.3420 = 0.2419 × 3.3

b = 2.3 units

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The complete question is:

Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction

In ΔABC, c = 5.4, a = 3.3, and measure of angle A = 20 degrees. What are the possible approximate lengths of b? Use the law of sines to find the answer.

2.0 units and 4.6 units

2.1 units and 8.7 units

2.3 units and 7.8 units

2.6 units and 6.6 units

Answer:

10,-0000 FRRS   LIKE IF ITS NOT THEN

Step-by-step explanation:

EEEEEE

Answer:

24/49

Step-by-step explanation:

There are no common factors to cancel out so just multiply the fractions.

Answer:

Step-by-step explanations:

The rate of the area of the circle, expressed in terms of the circumference C, is 0.1C square centimeters per second.

What is known as a circle?

C=2πr

A=πr²

dA/dr=2πr=C

dr/dt=-0.1 cm/sec

      dA/dt

= dA/dr * dr/dt

= 2πr (-0.1) cm²/s

= -0.1C cm²/s

As a result, a circle's radius is reducing at a steady rate of 0.1 centimeters each second. The rate of the area of the circle, expressed in terms of the circumference C, is 0.1C square centimeters per second.

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The value of x is 8.

A linear equation system is a collection of two or more linear equations involving the same set of variables. The goal of solving a linear equation system is to find a set of values for the variables that satisfy all of the equations simultaneously. In general, a linear equation can be written as:

a₁x₁ + a₂x₂ + ... + aₙxₙ = b

Given linear system:

2x - y + 5z = 16 ...(1)

y + 2z = 2 ...(2)

z = 2 ...(3)

From equation (3), we get z = 2. Substituting this value of z in equation (2), we get y + 4 = 2, which gives us y = -2.

Substituting the values of y and z in equation (1), we get:

2x - (-2) + 5(2) = 16

2x + 12 = 16

2x = 4

x = 2

Therefore, the value of x is 2.

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The unknown sides are a ≈ 48.35 and b ≈ 23.61.

A triangle ABC such that c=75, A= 43°, and B=20°.

To find the unknown values of the triangle,First we know that the sum of all angles of a triangle is 180°. Hence we can find C.

Using the angle sum property we have,

C = 180° - A - B= 180° - 43° - 20°= 117°

Now we know, A, B, and C,

we can find the unknown side lengths of the triangle using the Law of Sines.

The Law of Sines is given by: $$\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}$$

Thus, we have:

$$\frac{a}{\sin 43°}=\frac{b}{\sin 20°}=\frac{75}{\sin 117°}$$

Solving for a and b, we have;

$$a = 75 \cdot \frac{\sin 43°}{\sin 117°} ≈ 48.35$$ $$b = 75 \cdot \frac{\sin 20°}{\sin 117°} ≈ 23.61$$.

Hence, the unknown sides are a ≈ 48.35 and b ≈ 23.61.

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Answer:

Step-by-step explanation:

Second hand on a clock rotates at rate 360 degrees per 60 seconds.

360 degrees - 60 sec

x degrees - 15 sec

90 clockwise rotation (none hand of a clock rotates counter-clockwise :))

Answer:

90 degrees clockwise rotation

Step-by-step explanation:

A) The equation of the model is 20x=100.

B) Todd will take 50 days  to build his savings up to a total of $250.

An assertion that two expressions containing variables or numerical values are equivalent is known as an equation. The first step in resolving a variable equation is to identify the values of the variables that lead to the equality being true. The variables that must be changed in order to solve the equation are referred to as the unknowns, and the unknown values that satisfy the equality are referred to as the equation's solutions.

1 day ------ $5

20 days -------?

x=20×5

x=$100

A) Let the savings per one day =$5

For 20 days it will be $100

And it is given as 20x=100

Where x=time in days

B) Todd has $150 dollars for 20 days

Actual savings for 20 days=100

? --------250

x=(20×250)/100

x=50 days.

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The rate of change of demand is -221. This indicates that for every $1 increase in price, the demand for the product will decrease by 221 units.

The demand function is provided as follows: x = 800 − p −4pp + 3, p = $5The problem statement requires us to use the demand function to find the rate of change in demand (x) for a given price (p) and round the answer to two decimal places.

As per the problem statement, the price is given as $5. Therefore, we substitute the value of p in the demand function: x = 800 − (5) −4(5)(5) + 3x = 787We now differentiate the demand function to find the rate of change in demand.

Since the value of x can be a function of time, the differentiation results in the rate of change of x with respect to time. However, as per the problem statement, we are interested in the rate of change of x with respect to p.

Therefore, we use the chain rule of differentiation as follows: dx/dp = dx/dx * dx/dp Where dx/dx = 1, and dx/dp is the rate of change of x with respect to p.

dx/dp = 1 * d/dp [800 - p - 4p(p) + 3]dx/dp = -1 - 4p (1+2p)dx/dp = -1 - 4p - 8p²The rate of change of demand for p = $5 is given as follows: dx/dp = -1 - 4(5) - 8(5)²dx/dp = -1 - 20 - 200dx/dp = -221Therefore, the rate of change of demand is -221.

This indicates that for every $1 increase in price, the demand for the product will decrease by 221 units.

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Answer: -24

Step-by-step explanation:

\(\frac{x}{6} -18 = -22\)

\(\frac{x}{6} = -22 + 18\)

\(\frac{x}{6} = -4\)

\(x= -4*6\)

\(x= -24\)

check work

\(\frac{(-24)}{6} -18 = -22\)

\(-4 -18 = -22\)

\(-22 = -22\)

Using Chebyshev's theorem, at least 88.88% of the values will fall between 18 and 132 and at least 75% of the values will fall between 23 and 127.

Chebyshev's theorem states that for any given data set, a minimum proportion of the data points will lie within k standard deviations of the mean. For k = 1, the minimum proportion of data points is at least \(1 - 1/k^2\), which is 75% for this case.

For k = 2, the minimum proportion of data points is at least \(1 - 1/k^2\), which is 50% for this case. For k = 3, the minimum proportion of data points is at least \(1 - 1/k^2\), which is 89% for this case.

Now we are given a distribution with a mean of 75 and a standard deviation of 19. Therefore, we can use Chebyshev's theorem to determine what proportion of the data falls between a specified range.

Part 1 of 2

We need to find the percentage of data points that lie between 18 and 132.18 is 3 standard deviations below the mean. 132 is 3 standard deviations above the mean. Therefore, by Chebyshev's theorem, at least \(1 - 1/3^2\)= 1 - 1/9 = 8/9 = 0.8888 or 88.88% of the data falls within this range.

So, at least 88.88% of the values will fall between 18 and 132.

Part 2 of 2

We need to find the percentage of data points that lie between 23 and 127.23 is 2 standard deviations below the mean. 127 is 2 standard deviations above the mean. Therefore, by Chebyshev's theorem, at least \(1 - 1/2^2\) = 1 - 1/4 = 3/4 = 0.75 or 75% of the data falls within this range.

So, at least 75% of the values will fall between 23 and 127.

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Notice that:

Therefore the rule for the given transformation is:

The graph of the original points is:

The graph of the transformed points is:

Notice that the points are reflected over de x-axis and then translated 4 units to the right.

Answer:

The points are reflected over de x-axis and then translated 4 units to the right.

Step-by-step explanation:

We know that if (h,k) is the center of any circle and whose radius is = r then its equation is :

\( {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \)

Given, the equation of circle

\( {(x + 2)}^{2} + (y - 3) ^{2} = 25 = {5}^{2} \)

By comparing, we will get,

h = -2

k = 3

So, center of the circle is ( -2,3)

\(\large \green{ \: \: \: \: \boxed{\boxed{\begin{array}{cc} \bf\:Mark\\\bf\:me\:as\\\bf brainliest \end{array}}}} \\ \)

Answer:

-2;3

Step-by-step explanation:

we have a formular

(x-a)^2 +(y-b)^2=c

the center of the cirlce is (a;b)

so in this case it's (-2;3)

The factor of safety with respect to shear failure for the strip footing is approximately 0.049 when φ' = 0° and cu = 105 kN/m² is 0.049 and it is approximately 2.78 when φ' = 28° and cu = 10 kN/m² is 2.78.

The factor of safety with respect to shear failure for the given strip footing can be determined as follows:

(a) When cu = 105 kN/m² and φ' = 0:

The effective stress at the base of the footing can be calculated using the formula: qnet = q - γw ×  d, where q is the applied load, γw is the unit weight of water, and d is the depth of the footing. In this case, qnet = 430 - (21 ×  1) = 409 kN/m². The ultimate bearing capacity of the clay can be determined using Terzaghi's equation: qult = cNc + qNq + 0.5γBNγ, where c is the cohesion, Nc, Nq, and Nγ are bearing capacity factors, and γB is the bulk unit weight of the soil. For φ' = 0°, Nc = 5.4. Substituting the given values,

qult = (0 ×  5.4) + (409 ×  0) + (0.5 × 21 ×  2) = 21 kN/m²

The factor of safety (FS) is then calculated by dividing the ultimate bearing capacity by the applied load:

FS = qult / q = 21 / 430 ≈ 0.049.

(b) When cu = 10 kN/m² and φ' = 28°:

Using the given values of φ' = 28°, we can determine the bearing capacity factors from the provided data:

Nc = 26, Nq = 15, and Nγ = 13.

Substituting these values along with the net pressure

qnet = 430 - (21 × 1) = 409 kN/m² and the cohesion c = 10 kN/m² into Terzaghi's equatio× , we have

qult = (10 ×  26) + (409 ×  15) + (0.5 ×  21 ×  2 ×  13) = 1,197 kN/m²

The factor of safety is then calculated as FS = qult / q = 1,197 / 430 ≈ 2.78.

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(a) The factor of safety against shear failure when cu=105 kN/m² and ø'=0 is 1.

(b) The factor of safety against shear failure when cu=10 kN/m² and ø'=-28° is 0.004.

The factor of safety with respect to shear failure for a strip footing carrying a load of 430 kN/m can be determined as follows:

(a) When cu=105 kN/m² and ø'=0:

The factor of safety (FS) can be calculated as:

\(\[ FS = \frac{cu}{\gamma \times N_c \times B \times N_q} \]\)

Substituting the given values: cu=105 kN/m², γ=21 kN/m³, B=2 m, and Nc=5, we have:

\(\[ FS = \frac{105 \, \text{kN/m}^2}{21 {kN/m^2} \times 5 \times 2 \, \text{m}} = 1 \]\)

(b) When cu=10 kN/m² and ø'=-28°:

The factor of safety (FS) can be calculated as:

\(\[ FS = \frac{cu}{\gamma \times N_c \times B \times N_q} \]\)

Substituting the given values: cu=10 kN/m², γ=21 kN/m³, B=2 m, Nc=26, and Nq=15, we have:

\(\[ FS = \frac{10 \, {kN/m}^2}{21 \, {kN/m^3} \times 26 \times 2 \, \text{m} \times 15} = 0.004 \]\)

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Answer:

rise= -2 run= -4 slope= -1/2

Step-by-step explanation:

slope= rise/run

since rise=-2 and run=-4, slope=-2/4, but we have to simplify, so slope=-1/2

The interest rate your friend is charging you for the $20,000 loan is 20% per year.

The simple interest is expressed as;

A = P( 1 + rt )

Where A is accrued amount, P is principal, r is the interest rate and t is time.

Given that;

The Principal P = $20,000

Accrued amount A = $40,000

Elapsed time t = 5 years

Interest rate r =?

Plug these values into the above formula and solve for the interest rate r:

\(A = P( 1 + rt )\\\\r = \frac{1}{t}( \frac{A}{P} -1 ) \\\\r = \frac{1}{5}( \frac{40000}{20000} -1 ) \\\\r = \frac{1}{5}( 2 -1 ) \\\\r = \frac{1}{5}\\\\r = 0.2 \\\\\)

Converting r decimal to R a percentage

Rate R = 0.2 × 100%

Rate r = 20% per year

Therefore, the interest rate is 20% per year.

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Answer:

Changes in size and shape are examples of physical changes in matter

The correct label for the angle formed by line segments BC and BA measuring 65 degrees is ∠CBA.

In the given statement, line segments BC and BA are mentioned as the forming elements of the angle. When labeling an angle, the convention is to use three letters, with the middle letter representing the vertex of the angle. In this case, the vertex of the angle is point B. Therefore, the correct label for the angle would include B as the middle letter.

Among the options provided, ∠CBA correctly represents the angle formed by line segments BC and BA. It indicates that the vertex of the angle is B, with C and A being the endpoints of the two line segments. The order of the letters in the angle label follows a counter-clockwise direction, starting from the initial side (BC) and moving towards the terminal side (BA).

Options A (∠A), B (∠BCA), and C (∠b) do not accurately represent the given angle or follow the convention of labeling angles. Hence, the correct label for the angle formed by line segments BC and BA, measuring 65 degrees, is ∠CBA.

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The correct label for the angle formed by line segments BC and BA, measuring 65 degrees, is ∠CBA. The name of an angle starts at one ray, passes through the vertex, and ends at the other ray.

When we talk about angles, the label or name for an angle usually starts at one ray, passes through the vertex, and ends at the other ray. In this question, the angle is generated by the line segment BC (the one side of the angle), and line segment BA (the other side of the angle), with the vertex being at point B. Therefore, the correct label for this angle is ∠CBA or ∠ABC. The choice D.) ∠CBA is correct.

Note that the letters can be reversed (starting at A and ending at C) because angle measures are the same in both directions. The first and the last letters of the label name (C and A in this case) refer to the rays or line segments forming the angle, whereas the middle letter (B) refers to the vertex of the angle.

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The number that corresponds to the null hypothesis and the alternative hypothesis will be 3 and 6 respectively.

Specify the correct number from the list below that corresponds to the appropriate null and alternative hypotheses for this problem.

It should be noted that the null hypothesis suggests that there's no statistical relationship between the variables.

The alternative hypothesis is different from the null hypothesis as it's the statement that the researcher is testing.

In this case, the number that corresponds to the null hypothesis and the alternative hypothesis will be 3 and 6 respectively.

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When constructing a confidence interval for a population mean from a sample of size 28, the number of degrees of freedom (df) for the critical t-value is 27.

To construct a confidence interval for a population mean using a sample size of 28, we need to determine the number of degrees of freedom (df) for the critical t-value.

The number of degrees of freedom is equal to the sample size minus 1. In this case, the sample size is 28, so the number of degrees of freedom would be 28 - 1 = 27.

To find the critical t-value, we need to specify the confidence level. Let's assume a 95% confidence level, which corresponds to a significance level of 0.05.

Using a t-table or statistical software, we can find the critical t-value associated with a sample size of 28 and a significance level of 0.05, with 27 degrees of freedom.

Once we have the critical t-value, we can then construct the confidence interval for the population mean.

In conclusion, when constructing a confidence interval for a population mean from a sample of size 28, the number of degrees of freedom (df) for the critical t-value is 27.

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The derivative of g(x) is (-4x²-3x+1)cos(1+2x) - (2x³ - 2x^2 + x)tcos(1+2x) + t(1+2x)sin(1+2x) + C, where C is a constant of integration.

The derivative is a mathematical concept that represents the rate at which a function changes. It is essentially the slope of the tangent line to the curve of the function at a given point.

Integration is the process of finding the integral of a function, which involves calculating the area under its curve. It is the reverse of differentiation and is used in calculus and mathematical analysis.

According to the given information:

To find the derivative of g(x), we first need to evaluate the integral:

g(x) = ∫[1, 2x+1] (1-2t)sin(t) dt

Using the product rule of differentiation, we have:

g'(x) = (d/dx) [∫[1, 2x+1] (1-2t)sin(t) dt]

= (2-2x)sin(2x+1) - ∫[1, 2x+1] 2sin(t) dt

Simplifying the second term, we get:

g'(x) = (2-2x)sin(2x+1) - 2[cos(2x+1) - cos(1)]

Therefore, the derivative of g(x) is g'(x) = (2-2x)sin(2x+1) - 2[cos(2x+1) - cos(1)].

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Answer:

The scale factor is 18 to 1 for the painting

Step-by-step explanation:

Here we want to get the scale factor of the original to what is reproduced

Let us have same units first

Mathematically;

1 foot = 12 inches

3 feet = 36 inches

2 feet = 24 inches

So 36 to 2 and 24 to 1 1/3

That will be ratio 36/2 = 18 to 1

same as 25 divided by 1 1/3 = 18 to 1

Answer:

Un industriel souhaite fabriquer une boîte sans couvercle à partir d'une plaque de métal de

24

Step-by-step explanation:

3 is the slope, the "change in y over the change in x."

Using that "change in y over the change in x" idea, we can identify the unit of the slope as "y units over x unit" or "y units per x unit."  

In this situation, this means the unit would be "cost per minute."  Assuming you're in the U.S., this would be "dollars per minute."  If you're in England, you can use "pounds per minute."

Since the slope is positive, this tells you that the cost of the cab ride is increasing at a rate of 3 (monetary units) per minute.

To find the angle of the rise of a bridge, given that it rises 500 feet per one-half mile, we can use the trigonometric function tangent (tan).

The tangent of an angle is defined as the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle in a right triangle.

In this case, we can consider the height of the bridge (500 feet) as the side opposite the angle and the horizontal distance (one-half mile or 2640 feet) as the side adjacent to the angle.

Using the formula:

tan(θ) = opposite/adjacent

tan(θ) = 500/2640

To find the angle (θ), we can take the inverse tangent (arctan) of both sides:

θ = arctan(500/2640)

Using a calculator, we find that:

θ ≈ 11.22 degrees

Therefore, the angle of the rise of the bridge would be approximately 11.22 degrees.

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Answer:

A

Step-by-step explanation:

TX=XZ=ZU=3

XU=XZ+ZU=3+3=6

Answer:

D. 3

Step-by-step explanation: