write a tail recursive function sumtailrec : tree −> int that sums up the node values. (hint: use an auxiliary function of type int −> tree list −> int ).

Answer:

approaching a lady or a man

Answer:false

Explanation:

Bc

Answer: Cleaning of mechanical parts is necessary to remove contaminants, and to avoid clogging of wastes which could restrict the functioning of the machine.

Explanation:

There are different agents used for cleaning different machine instruments to prevent their corrosion and experience proper cleaning.

Backing plates must be dry cleaned using a cotton cloth to remove the dirt, dust or any other dry contaminant.

Struts can be wet cleaned by applying alcoholic solvent.

Levers can be cleaned using a mineral spirit.

Metallic plates can be cleaned using water based solution or water.

Answer:

Electric shock

Explanation:

hope this helps

p.s. the next question is Flexible

Answer:

C . . . . . . . . . . . . . . . . . . . . . .

(a) The column height of mercury in a mercury barometer is 7.32 meters, or 24.0 feet, or 95.2 inches.

(b) The column height of water in a water barometer is 995 meters, or 3268 feet, or 33.9 feet.

(c) A water barometer is not very practical because it would need to be very tall to measure atmospheric pressure.

(d) Ignoring the practicality issue, a mercury barometer would be more precise because mercury is denser than water.

Mercury barometer: 7.32 m, 24 ft, 95.2 in

Water barometer: 995 m, 3268 ft, 33.9 ft

Water barometer not practical because it would be too tall

Mercury barometer more precise because mercury is denser

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Answer:

The correct answer is "1020 K".

Explanation:

The given values:

\(n_{th} = 0,25\)

\(n_2=0.50\)

Now,

⇒ \(n_{th}(rev) = \frac{n_{th}}{n_2}\)

By putting the values, we get

                 \(=\frac{0.25}{0.50}\)

                 \(=0.50\)

As we know,

⇒ \(n_{th} (rev)=1-\frac{TL}{TH}\)

or,

⇒ \(TH=\frac{TL}{1-n_{th} (rev)}\)

          \(=\frac{510}{1-0.50}\)

          \(=\frac{510}{0.5}\)

          \(=1020 \ K\)  

Economics related to consumption is also known as consumer economics, which is concerned with the ways in which households allocate their resources, including time and money, in the satisfaction of their wants and needs.

This branch of economics deals with the problems of resource allocation among consumers with limited resources. It attempts to provide an understanding of the consumer’s decision-making process when choosing between different goods and services. The data required to prepare the cost estimate are as follows:

1. Price data: The price data is the cost of inputs and other resources required to produce the product or service that is being analyzed.2. Historical data: This data is used to determine past trends and patterns that may help in forecasting future demand and costs.

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Answer:

Explanation:I will bring the drawing of the skyscraper on my laptop, which will be equipped with a CAD software package. I will use an adaptor to project the drawings to a screen. The reasons I chose this is because CAD enables me to make the drawing efficiently and accurately. The software package will help avoid human error. Another advantage is that I can use layers to add new columns to the drawing so that I will not lose the original drawing. After I add the columns, we can view the structure in a three-dimensional view so that the structural engineer can check the location and dimensions of the column. The main advantage of CAD in this setting is that I can make immediate changes in the drawing, without having to change the entire drawing. This would not be possible if I used a paper-based presentation. Because I have my laptop at the meeting, I can also take notes about important points that arise during the meeting on a word processing program. I will be able to link the electronic document to the CAD file for further reference.

At the end of the meeting, I will be able to complete my drawings for the first floor of the skyscraper. The structural engineer can immediately approve the drawings and the mechanical engineer can then begin the preparation to start the build. The built-in features of the CAD software package enable the efficiency of this process.

Answer:

C

Explanation:

Answer: False

Explanation:

The given statement "In some expensive cookware, the pot is made of copper but the handle is made of stainless steel" is True because, in some expensive cookware, the pot is made of copper while the handle is made of stainless steel.

Copper is an excellent conductor of heat and provides even heat distribution, making it a popular choice for cookware. However, copper is a reactive metal and can react with acidic foods, causing a metallic taste and discoloration. To avoid this, cookware manufacturers use a non-reactive material such as stainless steel for the handles, which is durable and does not react with food.

Stainless steel also provides a good grip and stays cool to the touch even when the pot is heated. The combination of copper and stainless steel in cookware provides the best of both worlds – excellent heat distribution and a durable, non-reactive handle. This type of cookware is often more expensive due to the use of high-quality materials and craftsmanship.

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(a) The active part of the inflow expands its cross-section as it passes the tidal turbine due to conservation of mass and energy.

(b) Several reasons contribute to the theoretical maximum efficiency not being achieved in practical tidal turbine deployments, including turbulence, non-uniform flow, and mechanical losses.

(c) Estimating the total fluid loading on the Alstom 1.4 MW OceadeTM turbine requires considering the flow velocity, rotor and tower dimensions, and making assumptions about the flow characteristics and structural properties.

(d) The estimates of forces obtained from the fluid loading calculations are essential for designing the turbine and tower structure by ensuring that they can withstand the anticipated loads and stresses.

(a) The active part of the inflow expands its cross-section as it passes the tidal turbine due to the principle of conservation of mass and energy. As the tidal flow encounters the turbine rotor, some of the kinetic energy of the flow is converted into mechanical energy to drive the turbine. To satisfy the conservation of mass, the cross-sectional area of the flow must increase to compensate for the reduction in flow velocity caused by energy extraction.

(b) Achieving the theoretical maximum efficiency in practical tidal turbine deployments is challenging due to several reasons. First, tidal flows are often characterized by turbulence, which disrupts the uniformity of the flow and reduces overall efficiency. Second, tidal flow itself is not uniformly distributed, and the flow characteristics vary with tidal cycles, further impacting efficiency. Lastly, mechanical losses in the turbine's components, such as friction and resistance, reduce the efficiency of energy conversion.

(c) Estimating the total fluid loading on the Alstom 1.4 MW OceadeTM turbine involves considering the flow velocity, rotor diameter, and tower dimensions. Assuming a tidal flow velocity of 3 m/s, the fluid loading can be estimated by considering the momentum change and forces acting on the rotor and tower surfaces. Assumptions may include a simplified flow model, neglecting factors such as turbulence and non-uniform flow, and assuming a stationary tower. These assumptions simplify the calculation while providing a reasonable estimate of the fluid loading.

(d) The estimates of forces obtained from the fluid loading calculations are crucial for designing the turbine and tower structure. These estimates help engineers determine the required structural strength, material selection, and design considerations to ensure that the turbine and tower can withstand the anticipated fluid forces and mechanical stresses. By considering the estimated forces, designers can optimize the structural integrity, stability, and reliability of the turbine and tower, ensuring safe and efficient operation in tidal environments.

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Answer:

The answer is A. Compound Planetary Gearset.

Explanation:

The Compound Planetary Gear block represents a planetary gear train with composite planet gears. Each composite planet gear is a pair of rigidly connected and longitudinally arranged gears of different radii. One of the two gears engages the centrally located sun gear while the other engages the outer ring gear.

Compound planetary gear sets have at least two planet gears attached in line to the same shaft, rotating and orbiting at the same speed while meshing with different gears. Compounded planets can have different tooth numbers, as can the gears they mesh with.

A concurrent schedule is made up of two or more separate schedules that are presented at the same time and lead to different reinforcers.

Parallel schedule A reinforcement process where the participant can select their response from one of two or more accessible simple reinforcement schedules at once. The assessment of choice between straightforward schedule alternatives is possible with concurrent schedules.

The reinforcement schedules that are in place when two or more behaviors are reinforced simultaneously on various schedules. An illustration would be watching TV while on the phone and browsing the internet.

Two stimuli are pitted against one another in a concurrent schedule of reinforcer assessment to see which will result in a larger increase in responding when presented as a reward for responding. The reinforcer with more responses is the more potent one.

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a. The power factor is 0989

b. The average power from the source is 2.125 kW

Power factor is the ratio of the real power absorbed by the load to the apparent power.

a. What is the power factor.

To find the power factor, we nedd to find the equivalent impedance of the circuit.

First, the the 8Ω resistor and -j6 Ω capacitor impedance are in series, their equivalent impedance is Z₁ = 8 Ω+ (- j6) Ω = (8 - j6)Ω.

Now, Z₁ is parallel to the Z₂ = j4 Ω impedance.

So, their equivalent inpedance is

Z₃ = Z₁Z₂/(Z₁ + Z₂)

= (8 - j6)j4 Ω/(8 - j6 + j4)

= (32 - j24)/(8 - j2)

Rationalizing the denominator, we have that

=  (32 - j24)/(8 - j2) × (8 + j2)/(8 + j2)

= [32 × 8 + 32 × j2 - j24 × 8 + (-j42 × -j2)]/(8² + 2)²

= [256 + j64 - 192j + j²84)]/(8² + 2²)

= [256 + j64 - 192j - 84)]/(64 + 4)

= (172 - j128)/68

= (43 - j32)/17

Since the 10 Ω resistor is in series with Z₃, the equivalent impedance is

Z₄ = 10 Ω + (43 - j32)/17 Ω

= (10 + 43/17 - j32/17 )Ω

= (170 + 43)/17 - j32/17

= 213/17 - j32/17

We know that for an impedance Z = a + jb , tanФ = b/a

So, for Z₄, tanФ = b/a

= -32/17 ÷ 213/17

= -32/213

since the trigonometric identity

tan²Ф + 1 = sec²Ф

secФ = ±√(tan²Ф + 1)

So, substituting tanФ into the equation, we have that

secФ = ±√(tan²Ф + 1)

secФ = ±√[(-32/213)² + 1)

= ±√[(1024 + 45369)/45369)]

= ±√[46393/45369)]

= ±215.39/213

Now, the power factor P.F = cosФ

Since secФ = 1/cosФ

cosФ = ±213/215.39

= ±0.989

Since tanФ is negative, Ф is in the fourth quadrant.

So, cosФ = 0.989

So, the power factor is 0989

b. The average power

The average power P = I²R where

Now, I = V/Z₄ where

We know that for an impedance Z = a + jb , tanФ = b/a

So, for Z₄ = , tanФ = b/a

= -32/17 ÷ 213/17

= -32/213

Ф = tan⁻¹(-32/213)

= -8.544

Also, the magnitude of impedance, Z = √(a² + b²)

So, the magnitude of Z = √[(213/17)² + (-32/17)²]

= √[(213)² + (-32)²]/17

= √[45369 + 1024]/17

= 215.39/17

= 12.67

So, Z = 12.67 ∠-8.544

So, the current I = V/Z

= 165 ∠ 0°/ 12.67 ∠-8.544

= 165/12.67 ∠ 0°- (-8.544)

= 13.02 ∠ 8.544° A

So, the average power P = I²R where

so, P = (13.02 A)² × 213/17 Ω

= 169.60 A² × 213/17 Ω

= 36123.754/17 A²Ω

= 2124.93 W

= 2.125 kW

The average power is 2.125 kW

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Answer:

sa china po

Explanation:

sana makatulong ako

The required MTBF (in hours) for the new generator (assuming exponential and 8760 hours/year) will be 8760 hours.

7. Total test hours should be allocated for the new generator (assuming 1 failure is allowed) at 50% confidence should be 688 hours.

8. The demonstrated MTBF (ΘL) at 50% confidence if no failures were observed will be 43,800 hours. Yes, the requirement was demonstrated.

9. The static reliability of the system for this situation can be determined by calculating the probability of no failure. The probability of no failure will be 0.85 * 0.95 * 0.98 * 0.99 = 0.764. Therefore, the static reliability of the system for this situation will be 0.764.10.

Probability of the top-level event (system failure) can be calculated by adding the probabilities of all the paths leading to the top-level event. The probability of the top-level event (system failure) will be:

P(system failure) = P(Gen A failure) + P(Gen B failure) + P(Gen C failure) + P(Tie Bus failure) * P(No load shedding) + P(Tie Bus failure) * P(Load shedding)

P(Gen A failure) = 1 - e^(-8760/30000) = 0.215

P(Gen B failure) = 0.85 * (1 - e^(-8760/18000)) = 0.37

P(Gen C failure) = 0.95 * (1 - e^(-8760/30000)) = 0.276

P(Tie Bus failure) = 0.98

P(No load shedding) = 0.99

P(Load shedding) = 0.01

P(system failure) = 0.215 + 0.37 + 0.276 + 0.98 * 0.99 + 0.98 * 0.01 * (1 - P(Gen A failure)) * (1 - P(Gen B failure)) * (1 - P(Gen C failure)) * P(Tie Bus failure)P(system failure) = 0.215 + 0.37 + 0.276 + 0.98 * 0.99 + 0.98 * 0.01 * (1 - 0.215) * (1 - 0.37) * (1 - 0.276) * 0.98P(system failure) = 0.9644

Therefore, the probability of the top-level event (system failure) will be 0.9644.

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Answer:

i need points 425677

Explanation:

yurrrrrr  awnser C

The dynamic viscosity of the oil in poise is 13.625 pois

The kinematic viscosity of the oil in strokes is 14.34

F viscous is given as n*  ΔFr / Δy

where n = F * Δy / A * ΔVn

We have to define the terms of the formula

Δy = 12.5 x 10⁻³

ΔVr = 2.5m /s

A = 60 x 60 cm² = 0.36m

F = 98.1 n

We have to put the values in the formula

98.1 n *  12.5 x 10⁻³ /  0.36m * 2.5m /s

n = 1.3625  ns / m²

The kinematic viscosity of the oil in strokes if the specific gravity of the oil is 0.95

y = n / e

n =  1.3625  

e = 0.95 x 10³

y = 1.3625  / 0.95 x 10³

= 1.434 x 10⁻³

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Answer:

The most accurate reading for an analog meter is a pointer position between 2/3 of full scale and full scale. Typically, dc voltage measurements use the full count capability of the ADC, since signal conditioning is rather straight forward: it uses resistive dividers and filters.

The rotation rate required to cast the copper sleeve is 92.2 revolutions per minute.

The speed of the required rotation of a cylinder in centrifugal casting is given. What is centrifugal casting? Centrifugal casting is the process of producing parts by pouring molten metal into a cylindrical mould rotating about a horizontal or vertical axis.

This can be achieved using two different methods, depending on the axis of rotation: horizontal or vertical. The horizontal method is commonly used for casting pipes, as well as many other structures, and is often referred to as spinning.In order to eliminate bubbles and provide high structural stability, each bit of metal must be subjected to a centripetal acceleration of 119g.

We must determine the necessary rotation rate to achieve this acceleration. The formula for calculating centripetal acceleration is as follows: a = v^2/r. Where a is the centripetal acceleration, v is the velocity of the particle, and r is the distance from the particle to the axis of rotation.

We can use this formula to solve for the rotation rate (in RPM) as follows: \(v^{2}\) = arv = \(\sqrt{ar}\) The rotational velocity required to produce a centripetal acceleration of 119g can be calculated by substituting a = 119g, r = 2.25 cm (the average radius of the sleeve), and g = 9.81 m/s2 (the acceleration due to gravity) into the formula:v = \(\sqrt{(119g * 0.0225 m)}\) = 25.9 m/s

Now that we have the velocity required for the centripetal acceleration, we must convert it to RPM. We can do so using the formula:v = rω where ω is the angular velocity. ω = v/r = 25.9 m/s / 0.0225 m = 1151.1 rad/s The rotational speed in RPM can now be calculated by dividing the angular velocity by 2π and converting it to minutes: rpm = 1151.1 rad/s / 2π rad/rev / 60 s/min = 92.2 RPM. Therefore, the answer is 92.2 revolutions per minute.

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Answer:

up up down down

Explanation:

left right left right b a select start

The sensors for a side sonar system are typically located on the sides of the vehicle, usually near the bottom. These sensors use sound waves to detect obstacles and provide the driver with a warning.

The side sonar system is designed to detect objects on the sides of the vehicle, and can provide visual and/or audible alerts to the driver if an object is detected in the blind spot.

Overall, the placement of the sensors may vary depending on the make and model of the vehicle, but they are usually located in areas that provide optimal coverage for detecting objects.

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Answer:

External diameter = 158.15 mm mm

Internal diameter = 59.31 mm

Explanation:

We are given;

Diameter ratio; d_i = ⅜d_o

Where d_i is internal diameter and d_o is external diameter

Power;P = 375 KW = 375000 W

Rotational speed;N = 100 rpm

Max torque is 20% greater than mean torque; T_max = 1.2T_avg

Shear stress;τ = 60 N/mm²

Length; L = 4m = 4000 mm

Angle of twist; θ = 2° = 2π/180 radians

Modulus of rigidity;G = 0.85 X 10^(5) N/mm²

Formula for the power transmitted by the shaft is;

P = 2πNT_avg/60

Plugging in the relevant values, we have ;

375000 = 2π × 100T_avg/60

T_avg = (375000 × 60)/(2π × 100) = 35809.862 N.m = 35809862 N.mm

Since T_max = 1.20T_avg

Thus, T_max = 1.20(35809862) = 42971834.4 N.mm

Checking for strength, we'll use;

τ = Tr/J_p

Or since r = d/2

It can be written as;

τ = T(d_o)/2J_p - - - (1)

Where T is T_max

But Polar moment of inertia of hollow shaft is;

J_p = [π(d_o)⁴ - π(d_i)⁴]/32

Now, we are told that d_i = ⅜d_o

Thus;

J_p = [π(d_o)⁴ - π(⅜d_o)⁴]/32

J_p = (π/32) × d_o⁴(1 - 3⁴/8⁴)

J_p = 0.0926 d_o⁴

Plugging this for J_p in eq 1,we have;

τ = T(d_o)/2(0.0926d_o⁴)

Making d_o the subject gives;

d_o³ = T/(2 × 0.0926τ)

Plugging in the relevant values to give;

d_o³ = 42971834.4/(2 × 0.0926 × 60)

d_o³ = 3867155.7235421166

d_o = ∛3867155.7235421166

d_o = 156.96 mm

Thus, d_i = ⅜ × 156.96 = 58.86 mm

Checking for stiffness, we'll use;

T/J_p = Gθ/L

Again T is T_max

Plugging in the relevant values, we have;

42971834.4/0.0926 d_o⁴ = (0.85 × 10^(5) × 2π/180)/4000

464058686.825054/d_o⁴ = 0.7417649321

d_o⁴ = 464058686.825054/0.7417649321

d_o⁴ = 625614216.5028806

d_o = ∜625614216.5028806

d_o = 158.15 mm

d_i = ⅜ × 158.15 = 59.31 mm

So we will pick the highest valies.

Thus;

d_o = 158.15 mm

d_i = 59.31 mm

When a level 1 technician is unable to solve an issue, they should escalate the problem to a higher level of support or a more experienced technician for further assistance.

Level 1 technicians typically handle basic technical issues and provide initial troubleshooting and support. However, there are cases where they may encounter complex or challenging problems that go beyond their expertise. In such situations, it is important for the level 1 technician to recognize their limitations and escalate the issue to a higher level of support. This can involve seeking assistance from a more experienced technician, a specialized team, or a supervisor. By escalating the problem, the level 1 technician ensures that the issue is addressed by someone with the necessary skills and knowledge to effectively resolve it. This helps prevent prolonged downtime, minimizes potential mistakes, and ensures the problem is handled by the appropriate resources, ultimately leading to a more efficient and effective resolution.

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To determine the height of a half-wave transmitting antenna like the KVCU antenna, we need to calculate the wavelength and then divide it by two.

The formula to calculate the wavelength is:

Wavelength = Speed of Light / Frequency

Assuming we know the frequency at which the antenna operates, we can substitute the values into the formula to find the wavelength.

For example, if the frequency is 100 MHz (100,000,000 Hz), and the speed of light is approximately 3 x 10^8 meters per second, the calculation would be:

Wavelength = (3 x 10^8) / (100 x 10^6) = 3 meters

Once we have the wavelength, we divide it by two to determine the height of the half-wave antenna:

Height = Wavelength / 2 = 3 meters / 2 = 1.5 meters

Therefore, for a half-wave transmitting antenna like the KVCU antenna, it should have a height of approximately 1.5 meters when oriented vertically with respect to the ground.

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Answer:

The answer is below

Explanation:

Case hardening is a form of steel hardening that is applied on mild steel with a high temperature of heat.

It results in material forming a hard surface membrane, while the inner layer is soft.

It is mostly used for universal joints, construction cranes, machine tools, etc.

On the other hand, Through hardening is a form of steel hardening in engineering that involves heat treatment of carbon steel.

It increases the hardness and brittleness of the material.

It is often used for axles, blades, nuts and bolts, nails, etc.

Answer:

The Border Patrol of the United States analyzes the purchase of a new helicopter for the aerial surveillance of the border of New Mexico and Texas with the Mexican Republic. 4 years ago a similar helicopter was purchased at a cost of $ 140,000.00. with an interest rate of 7% per year. Calculate the single payment factor and the present value factor with the above data with the table and formula. Draw the flow chart.

Explanation:

Answer:

a) The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm

b) The change in diameter of the specimen is  - 0.015 mm

Explanation:

Given the data  in the question;

(a) The amount by which this specimen will elongate in the direction of the applied stress.

First we find the area of the cross section of the specimen

A = \(\frac{\pi }{4}\) d²

our given diameter is 20.5 mm so we substitute

A = \(\frac{\pi }{4}\) ( 20.5 mm )²

A = 330.06 mm²

Next, we find the change in length of the specimen using young's modulus formula

E = σ/∈

E = P/A × L/ΔL

ΔL = PL/AE

P is force ( 46300 N), L is length ( 201 mm ), A is area ( 330.06 mm² ) and E is  elastic modulus (60.5 GPa) = 60.5 × 10⁹ N/m² = 60500 N/mm²

so we substitute

ΔL = (46300 N × 201 mm) / ( 330.06 mm² × 60500 N/mm² )

ΔL =  0.466 mm

Therefore, The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm

(b) The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number.

Using the following relation for Poisson ratio

μ = -  Δd/d / ΔL/L

given that Poisson's ratio of the metal is 0.33

so we substitute

0.33 = -  Δd/20.5 / 0.466/201

0.33 = -  Δd201 / 20.5 × 0.466

0.33 = - Δd201  / 9.143

0.33 × 9.143 =  - Δd201

3.01719 = -Δd201

Δd = 3.01719 / - 201

Δd  = - 0.015 mm

Therefore, The change in diameter of the specimen is  - 0.015 mm

Answer:

Computer programming is where you learn and see how computers work. People do this for a living as a job, if you get really good at it you will soon be able to program/ create a computer.

Explanation:

Hope dis helps! :)