Write a valid conclusion using the Law of Detachment or Law of Syllogism given the statements below.
1. If you drive above 55mph you will get a ticket
2. Kate is driving 60 mph.

Answer:

x=8

Step-by-step explanation:

The figure is shown in the attached figure.

We have, LK║OM. We need to find the value of x.

It is based on side-splitter theorem. If a line is parallel to third side of a triangle, then the points that intersects the two lines, it divides proportionally.

Using it in given problem. So,

\(\dfrac{\text{NK}}{\text{KM}}=\dfrac{\text{NL}}{\text{LO}}\)

Nk = x+2, KM = x-3, NL = x and LO = x-4

So,

\(\dfrac{x+2}{x-3}=\dfrac{x}{x-4}\)

Cross multiplying, we get :

\((x+2)(x-4)=x(x-3)\\\\x^2-4x+2x-8=x^2-3x\\\\-2x+3x=8\\\\x=8\)

So, the value of x is 8.

Answer:   D     x=8

Step-by-step explanation:

Answer:

d is the answer

Step-by-step explanation:

perimeter of rect = 2(7+3) = 20

perimeter of square = 4 a =20

a = 5

Answer:

20\(c^{6}\)

Step-by-step explanation:

using the rule of exponents

\(a^{m}\) × \(a^{n}\) = \(a^{(m+n)}\)

given

(- 4c³)(- 5c³) ← remove parenthesis

= - 4 × c³ × - 5 × c³

= - 4 × - 5 × c³ × c³

= 20 × \(c^{(3+3)}\)

= 20\(c^{6}\)

A mathematics topic that van be looked into is how linear algebra, graph theory and optimization can be used on the airline industry.

In this case, to solve the scheduling issues faced by airlines such as planning flights, assigning planes and crews to routes - mathematical techniques can be employed.

By leveraging Linear Algebra, operators can simulate the flow of aircrafts and passengers while Graph Theory can help model flight schedules and aircraft routes.

Simultaneously using Optimization techniques in the problem-solving process can work to streamline various operations resulting in reduced costs and improved efficiency which can increase profit margins.

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Answer:

sss

Step-by-step explanation:

Answer:

Your answer

85 dollar 4 cent

Mark it as Brainlist answer. Follow me to get more answer

Step-by-step explanation:

Answer:

16 =2^4

Step-by-step explanation:

16

16 = 4*4

but 4 is not prime

4 = 2*2

16 = 2*2*2*2

Rewriting with exponents

16 =2^4

Answer:

→ Prime factorization of 16 :

According to the information, the event C, getting heads when flipping a coin, is considered neither likely nor unlikely.

In probability, an event is considered likely if its probability is high, and it is considered unlikely if its probability is low. An event is considered neither likely nor unlikely if its probability is close to 0.5 or 50%. In this case we have to consider the probability of each option to establish a conclusion. Here is the analysis:

According to the above, the event C, getting heads when flipping a coin, is considered neither likely nor unlikely because its probability is exactly 0.5 or 50%.

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Answer:

5y + 12x

Step-by-step explanation:

Let's simplify step-by-step.

5y+3x+9x

Combine Like Terms:

=5y+3x+9x

=(3x+9x)+(5y)

=12x+5y

Answer:

5y + 12x

Step-by-step explanation

Simplify step-by-step.

5y+3x+9x

Combine like terms:

=5y+3x+9x

=(3x+9x)+(5y)

=12x+5y

( a , b ) → R ( x , y )

as x and b ∈ y

(a) A relation R in a set A is not reflexive if there be at least one element a ∈ A such that (a, a) ∉ R. Consider, for example, a set A = {p, q, r, s}. The relation R1 = {(p, p), (p, r), (q, q), (r, r), (r, s), (s, s)} in A is reflexive, since every element in A is R1-related to itself.

(b) Now {a}∩{b}=∅ and {b}∩{a}=∅ but {a}∩{a}≠∅. So the relation on any such R is not transitive.

Given that,

A relation on Z by setting x R y if xy is even,

A relation R in a set A is not reflexive if there be at least one element a ∈ A such that (a, a) ∉ R. Consider, for example, a set A = {p, q, r, s}. The relation R1 = {(p, p), (p, r), (q, q), (r, r), (r, s), (s, s)} in A is reflexive, since every element in A is R1-related to itself.

The empty relation is the subset ∅. It is clearly irreflexive, hence not reflexive. To check symmetry, we want to know whether aRb⇒bRa for all a, b ∈ A.

R is reflexive if for all x A, xRx. R is symmetric if for all x,y A, if xRy, then yRx. R is transitive if for all x,y, z A, if xRy and yRz, then xRz. R is an equivalence relation if A is nonempty and R is reflexive, symmetric and transitive.

That is: don't use more than two elements; and don't use any particular elements. Be generic. Now {a}∩{b}=∅ and {b}∩{a}=∅ but {a}∩{a}≠∅. So the relation on any such S is not transitive.

Remember that the domain of R in this instance refers to the subset of X for which R is defined. The error occurs when we think that the domain R encompasses the entire set X, yet it is possible that R is not defined for all of X's components.

Remember the following instance:

X = {2,4,6}.

R can be defined as follows: (2,2, 4, 4, 2, 4, 2). Since we lack the element (6,6), we can easily verify that this relation is transitive and symmetric, but it is not reflexive.

Therefore,

( a , b ) → R ( x , y )

as x and b ∈ y

(a) A relation R in a set A is not reflexive if there be at least one element a ∈ A such that (a, a) ∉ R. Consider, for example, a set A = {p, q, r, s}. The relation R1 = {(p, p), (p, r), (q, q), (r, r), (r, s), (s, s)} in A is reflexive, since every element in A is R1-related to itself.

(b) Now {a}∩{b}=∅ and {b}∩{a}=∅ but {a}∩{a}≠∅. So the relation on any such R is not transitive.

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To describe the temperatures for the week, we can apply the following statistical tools:

a) Find the mean, median, mode, and range.

c) Construct a line graph.

d) Construct a stem and leaf plot.

We can describe temperatures using measures of central tendencies (especially the mean, median, and mode).

The mean temperature is the average, which shows the overall trend in temperature changes.  It is computed by adding up the temperatures for the period and diving by the number of data values.

In addition, the median gives the middle value when the data set is ordered in ascending or descending orders. Similarly, the mode gives the highest temperature occurrence within the period. It may not be useful here.

We can estimate the difference between the highest and lowest temperature for the week with the range.

A line graph (showing connecting lines) and a stem-and-leaf plot (like a bar graph) can graphically describe the temperatures for the week.

Thus, we can use Options A, C, and D to describe the temperature.

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What could you do to describe the following data, showing temperatures for the week? (Check all that apply.)

Mon - 65°

Tues - 67°

Wed - 66°

Thur - 70°

Fri - 72°

Sat - 68°

Sun - 69°

a) Find the mean, median, mode, and range.

b) Survey people about the weather.

c) Construct a line graph.

d) Construct a stem-and-leaf plot.

By trigonometric functions, the length of the hypotenuse is approximately equal to 131.571.

In this problem we find the measure of an angle and its opposite side from a right triangle, whose representation is shown in the image attached below.

Trigonometric functions are transcendent expression that relates an angle of the right triangle with two sides of the same. We can find the measure of the hypotenuse by the definition of the sine function:

sin θ = h / r

Where:

If we know that h = 45 and θ = 20°, then the length of the hypotenuse is:

r = h / sin θ

r = 45 / sin 20°

r ≈ 131.571

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In a connected weighted graph, the maximum weight edge is never in the minimum spanning tree, is a subset of A weighted undirected graph that connects all vertices together does so without cycles and with the lowest possible total edge weight.

Minimum Spanning Tree:

Given a weighted graph, we want to find the spanning tree of the graphs with the smallest total weight.

The total weight of a spanning tree is the sum of its edge weights. If T' is another spanning tree in the graph, we want to find a spanning tree T whose sum of T's weights is less than of T''s weights.

Connected Weighted Graph:

A weighted graph is a graph in which each branch is given a numerical weight. A weighted chart is therefore a special type of labeled chart in which the labels are numeric (usually considered positive).

A directed graph is a set of vertices (nodes) connected by edges, and each node has an associated direction.

Edges are usually represented by arrows pointing in the directions in which the graph can be traversed.

In the example on the right, the graph can be traversed from node A to B, but not from node B to A.

An Undirected Graph:

An undirected graph is a graph, that is, a set of interconnected objects (called vertices or nodes) in which all edges are bidirectional. Undirected graphs are sometimes called undirected networks. In contrast, a graph whose edges point in one direction is called a directed graph.

In an undirected graph, edges are bidirectional and have no associated direction. Therefore the graph can be traversed in both directions. The lack of arrows indicates that the graph is undirected.

In the left example, the graph can be traversed both from node A to B and from node B to A.

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Answer:

Mary has two friends over, she wants to split half of a cake she has left over into thirds for her and her friends. 1/2 ÷ 3 is 1/6. This means that each friend will get 1/6 of the full cake.

Step-by-step explanation:

I make up stories and know how to divide fractions. To solve a division problem like this you want to take the 3 and turn it into 3/1. then, flip the 1/2 around to it is 2/1. Then, multiply the two together.

The interest for Part 1 is approximately $385.10.

The interest for Part 2 is approximately $709.31.

The formula is as follows:

Interest is calculated as follows: Principal * Rate * Time

Where

Part 1:

$132,000 is the principal.

(Decimal) Rate = 12% = 0.12

Time = 8 days/365 days.

How much interest is there in Part 1?

Interest is calculated as follows : $132,000 * 0.12 * (8/365) = $385.10

Therefore, the interest for Part 1 is approximately $385.10.

Part 2:

$106,750 as the principal

(Decimal) Rate = 12% = 0.12

Time = 20 days / 365 days.

How much interest will there be in Part 2

Interest is calculated as follows : $106,750 * 0.12 * (20/365) = $709.31

Therefore, the interest for Part 2 is approximately $709.31.

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Answer:

yea we all love you $^)

some will deny it but don't believe that. lolll

The solution that is the closest estimate of the amount of glass Maria will need to construct her pyramid would be =5289.25 cm squared. That is option C.

To calculate the area of a square based pyramid, the formula that should be used would be given below as follows:

\(area = {a}^{2} + 2a \sqrt{ \frac{a2}{4} } + {h}^{2} \)

Where:

a= 44cm

height= 44²-22²= 38.1cm

Area= 44²+ 2(44) × √44²/4 + 38.1²

= 1936+88 × √ 484+1452

= 2024× √1936

= 5807.61 cm².

Therefore the closest estimate to the final answer would be 5289.25 cm squared

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Answer: 11x+4

(simplify?)

Step-by-step explanation:

Remove parentheses.

9x−8+x+10+x+2

Add 9x and x

10x−8+10+x+2

Add 10x and x.

11x−8+10+2

Add −8 and 10.

11x+2+2

Add 2 and 2.

11x+4

Step-by-step-explanation:

Evaluate:

\(9x - 8 + x + 10 + x + 2\)

Add the first two terms:

\(10 + 2 + x + 2\)

Evaluate:

\(10x + x + 2 + 2\)

Add the terms:

\(11x + 2 + 2\)

Solution:

\(11x + 4\)

ANSWER:

\(11x + 4\)

The answer is B

believe me im great at math. I won 52 mathmatician competitions in only 1 month

Answer:

A.

Step-by-step explanation:

Let's think of this as a clock.  We can see that the 2 lines start in the same place, around 3 o'clock.  Next, one of the line segments shifts down to around 6 o'clock.  Next, it shifts to about 9 o'clock.  Logically, the next step (in a clock) would be 12 o'clock, making A the correct choice.

We can also just use a regular circle, with one of the line segments moving 90 degrees each time.

Hope this helps! :)

If there are 25 new centenarians , then the best representation of the standard deviation for the  ages of new centenarians will be (c) 0 .

The standard deviation is defined as the measure of the spread of a data set.

In this case, the data set consists of the ages of the 25 new centenarians. also given that  all of the new centenarians are exactly 100 years old,

They invited 25 persons who recently turned 100 years old, that means  majority of attendees will be between the ages of 100 and 102.

Since the majority of the data is centered around 100, the standard deviation will be zero or very close to it.

Therefore  , the standard deviation of the data set is zero(0)  .

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The given question is incomplete , the complete  question is

A large retirement community wants to host a birthday party for its residents who recently became centenarians (a centenarian is someone who has lived 100 years). There are 25 new centenarians.

Which of the following best represents the standard deviation for the ages of the new centenarians ?

(a) 100

(b) 4

(c) 0

Answer:

\(f^{-1}(x)=\frac{x-4}{5}\)

Step-by-step explanation:

1. replace f(x) with x, and x with y:  x=5y+4

2. solve for y: x=5y+4

                 ⇒  x-4=5y

                 ⇒  (x-4)/5=y

3. replace y with f⁻¹(x)

A line with angles that is not straight is called a curved line.

A geometrical entity which has at least one angle and deviates from the nature of a straight line is known as a curve. A curve is a non-linear geometric construct that does not exhibit a uniform directionality. The characteristic features of the object in question may manifest in either a smoothly contoured or a ruggedly uneven appearance, and may further be either enclosed or exposed.

In the realm of mathematics, various concepts can be represented by the application of curves. One illustrative instance is employing the curve of a graph for depicting the correlation between two variables. Curvilinear structures may also be utilized as a mathematical technique to arrive at solutions for problems. One illustrative instance pertains to the utilization of the parabolic curve in the determination of the peak or nadir point of a given function.

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Answer:

2 tens or 20

9 millions or 9000000

4 ten thousandths or 0.0004

Answer:

Difference, D = 40

Step-by-step explanation:

This question requires options. Since there's none, I'll answer generally.

Represent the distances with d1 and d2

d1 = 527 Meters

d2 = 487 Meters

Required

Determine the absolute difference

The absolute difference (D) of the given distances can be calculated using the following expression

D = |d1 - d2|

Substitute values for d1 and d2

D = |527−487|

D =|40|

D = 40

Hence, Twyla traveled 40 meters.

Answer:

    2x^2-7x+6!

Step-by-step explanation:

Just use the FOIL method. FOIL stands for First, Outer, Inner, Last. You will add the results of each piece, keeping in mind that a subtraction sign should be seen as adding a negative. So you have:

First: 2x times x

Outer: 2x times -2

Inner: -3 times x

Last: -3 times -2

Add all these together to get 2x^2+ -4x+ -3x+6

or 2x^2-4x-3x+6

simplified to 2x^2-7x+6!

Answer:

It's actually A, because the US population got doubled ever year

The component form of the following vectors is Option A. V = (38.3, 32.1).

To find the component form of a vector given its magnitude and direction angle, we can use trigonometry.

The component form of a vector in two dimensions is represented as (x, y), where x is the horizontal component and y is the vertical component.

In this case, the magnitude of the vector is given as 50, and the direction angle θ is 50°. We can use this information to calculate the horizontal and vertical components.

The horizontal component (x) can be found using the formula x = magnitude * cos(θ), and the vertical component (y) can be found using y = magnitude * sin(θ).

Let's calculate the components:

x = 50 * cos(50°) ≈ 38.3

y = 50 * sin(50°) ≈ 32.1

Rounding the answers to the nearest tenth, we get the component form of the vector V as (38.3, 32.1).

Therefore, the correct answer is A. V = (38.3, 32.1).

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The question is incomplete. Find the full content below:

Find the component form of the following vectors. Round your answers to the tenth.

Magnitude of v = 50, direction angle θ = 50°

A. V = (38.3, 32.1)

B. V = (33.8, 31.2)

C. V = (32.1, 38.3)

D. V = (31.2, 33.8)

Answer:

502.4 square inches

Step-by-step explanation:

To find the area of the shaded region, you first need to find the area of the smaller circle with diameter 12, and then subtract that from the area of the larger circle. Since the diameter of a circle is twice the radius, the radius of the smaller circle is 6, and its area is therefore:

\(\pi \cdot 6^2 = 3.14\cdot 36=113.04\)

The area of the larger circle, which has radius 6+8=14, is:

\(\pi \cdot 14^2= 3.14 \cdot 196=615.44\)

Subtracting the area of the smaller circle from his, you get an area of 502.4 square inches for the shaded area. Hope this helps!

Answer: 502.40 in²

Step-by-step explanation:

the diameter of the big circle is 2(8) + 12 = 28

divide the diameter by 2 to get the radius (r) = 14

Area (A) = π·r²

            = π(14)²

            = 196π

The diameter of the small circle is 12

divide the diameter by 2 to get the radius (r) = 6

Area (A) = π·r²

            = π(6)²

            = 36π

The area of the shaded region is the difference between the big circle and the small circle.

\(Area_{shaded}=Area_{big}-Area_{small}\)

                = 196π - 36π

                = 160π

                = 160(3.14)

                = 502.40

Answer:

\(x = \frac{(1 + \sqrt{11})( \sqrt{3 } - 1) }{2 } \)