Write an equation in slope-intercept form for the line that passes through (2,4) and is parallel to the line given by y=7.

The value of x is 14.

We know in an isosceles triangle an isosceles polygon is a polygon with at least two sides of equal length.

We have two sides measured 2x-9 and x+ 5.

From the figure the length of sides are equal then

2x-9 = x+ 5

2x- 9- x = 5

x-9 = 5

Add 9 to both sides of the equation:

x - 9 + 9 = 5 + 9

x= 14

Thus, the value of x is 14.

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well, how much is 15% of 850?

\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{15\% of 850}}{\left( \cfrac{15}{100} \right)850}\implies 127.5\)

\( \sf \longrightarrow \: 5 \bigg( \: n - \frac{1}{10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: 5 \bigg( \: \frac{n}{1} - \frac{1}{10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: 5 \bigg( \: \frac{10 \times n - 1 \times 1}{1 \times 10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: 5 \bigg( \: \frac{10n - 1}{ 10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: \: \frac{50n - 5}{ 10} = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: \: 2(50n - 5) =1(10) \\ \)

\( \sf \longrightarrow \: \: 2(50n - 5) =10 \\ \)

\( \sf \longrightarrow \: \: 100n - 10=10 \\ \)

\( \sf \longrightarrow \: \: 100n =10 + 10\\ \)

\( \sf \longrightarrow \: \: 100n =20\\ \)

\( \sf \longrightarrow \: \:n = \frac{2 \cancel{0}}{10 \cancel{0}} \\ \)

\( \sf \longrightarrow \: \:n = \frac{1}{5} \\ \)

Answer:-

To solve the equation \(\sf 5(n - \frac{1}{10}) = \frac{1}{2} \\\) for \(\sf n \\\), we can follow these steps:

Step 1: Distribute the 5 on the left side:

\(\sf 5n - \frac{1}{2} = \frac{1}{2} \\\)

Step 2: Add \(\sf \frac{1}{2} \\\) to both sides of the equation:

\(\sf 5n = \frac{1}{2} + \frac{1}{2} \\\)

\(\sf 5n = 1 \\\)

Step 3: Divide both sides of the equation by 5 to isolate \(\sf n \\\):

\(\sf \frac{5n}{5} = \frac{1}{5} \\\)

\(\sf n = \frac{1}{5} \\\)

Therefore, the solution to the equation \(\sf 5(n - \frac{1}{10})\ = \frac{1}{2} \\\) is \(\sf n = \frac{1}{5} \\\), which corresponds to option (d).

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The two solutions of the trigonometric equation, in the range 0  ≤ x ≤ 2pi, are:

For the sine and cosine functions, we define the inverses Asin and Acos such that:

Cos( Acos(x)) = x

Acos( cos(x)) = x

Now, let's look at our trigonometric equation:

cos(x) = √3/2

If we apply the inverse cosine function to both sides, we will get:

Acos(cos(x)) = Acos(√3/2)

x = 0.524 rad.

Bow we want to find two solutions on the range, the other solution will be:

x = -0.524 rad + 2*3.14 rad = 5.756 rad

The two solutions of the trigonometric equation, in the range 0  ≤ x ≤ 2pi, are:

x =  0.524 rad.

x =  5.756 rad

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Answer:

46

Step-by-step explanation:

520-355 = 165

165/355 = 0.46

0.46 x 100 = 46

The equivalent expression to the expression (a⁻⁷ × b⁻²)⁻⁹ is (a⁷ × b²)⁹.

Some common rules of exponents are

xᵃ×xᵇ = xᵃ⁺ᵇ.

xᵃ/xᵇ = xᵃ⁻ᵇ.

Addition and subtraction of exponents are only possible for the same base value and when the base is different and both have the same exponent we just multiply the bases and write the exponent.

The given expression is (a⁻⁷ × b⁻²)⁻⁹.

= a⁻⁷ˣ⁻⁹ × b⁻²ˣ⁻⁹.

= a⁶³ × b¹⁸.

= (a⁷ × b²)⁹.

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The set of prime numbers greater than 11 with the cardinality of 5 is {13, 17, 19, 23, 29}

From the question, we have the following parametes that can be used in our computation:

Set = prime numbers

Cardinality = 5

The cardinality implies that the number of elements in the set is 5

5 prime numbers greater than 11 are 13, 17, 19, 23, 29

Hence, the set is {13, 17, 19, 23, 29}

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Answer:

Annette should plan to spend 2.25 hours walking back.

Step-by-step explanation:

To solve this problem, we can use the formula:

Time = Distance / Speed

Let's assume the distance of the race is D miles.

Annette spends her time running the distance of the race, which takes:

Time running = D / 9 hours

She then walks back the same distance, which we need to find the time for:

Time walking = D / 3 hours

Since Annette has a total of 3 hours for her training, the sum of the running time and walking time should equal 3 hours:

D / 9 + D / 3 = 3

To simplify the equation, we can multiply all terms by 9 to eliminate the denominators:

D + 3D = 27

Combining like terms:

4D = 27

Dividing both sides of the equation by 4:

D = 6.75

So, the distance of the race is 6.75 miles.

To find the time Annette should spend walking back, we substitute the distance into the time-walking formula:

Time walking = D / 3 = 6.75 / 3 = 2.25 hours

Therefore, Annette should plan to spend 2.25 hours walking back.

9514 1404 393

Answer:

  m∠QPR = 94°

Step-by-step explanation:

Given:

  m∠QPS = 180°

  m∠QPR = 7x -4°

  m∠RPS = 9x -40°

Find:

  m∠QPR

Solution:

  m∠QPR + m∠QPR = 180°

  (7x -4°) +(9x -40°) = 180°

  16x = 224° . . . . . . . . . . . . . add 44°

  x = 14° . . . . . . . . . . . . . divide by 16

  m∠QPR = 7x -4° = 7(14°) -4°

  m∠QPR = 94°

Answer:

It's Angle ABC because an inscribed angle is the angle formed in the interior of a circle when two chords intersect on the circle

Answer:

Step-by-step explanation:

Thx for the points bbg

The least number of colors needed to correctly color in the sections of the given picture so that no two touching sections have the same color is 5.

Let's say we begin with a single triangle. This triangle will be the first of a series of seven subsequent triangles, none of which will have any portions contact. If a square were the initial shape, then there are five shapes—three of which are squares and the other two are triangles—that don't have any touching portions. Given that a square takes up twice as much room, this value is probably lower, but location also matters. Therefore, for the given figure, the least number of colored areas you can color in that yet meet the required criteria is 5.

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Answer:

Q13)A man is four times as old as his son. After 20 years, he will be twice as old as his son at that time. Find their present ages. Present age of the father is = 4 x = 4 × 10 = 40 4x=4\times10=40 4x=4×10=40 years.

Cost of jacket = $20

No. Of jackets = 1

Let the cost of shirt be x

No of shirts = 5

ATQ

5x + 1(20) = 95

5x + 20 = 95

5x = 95 - 20

5x = 75

x = 75/5

x = 15

Therefore cost of each shirt was $15

Answered by Gauthmath must click thanks and mark brainliest

The way the flashback in these paragraphs advance the plot is C. It introduces Evan's motivation for working in the garden with Grandfather.

The technique of flashback in storytelling involves interrupting the chronological order of events to depict an earlier event or scene. It uses time travel to furnish the audience with necessary backstory, context, or a deeper understanding of the characters.

The technique of flashbacks is frequently employed as a means of divulging previous occurrences, recollections, or incidents that hold significance to the present narrative being conveyed.

Hence, it can be seen from the given text that the use of flashback helps show the motivation which Evans had for working in the garden with Grandfather

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Answer:

\(1(x {}^{8} + x {}^{4} + 1)\)

Step-by-step explanation:

\(x {}^{8} + {x}^{4} + 1 =1( x {}^{8} + x {}^{2} + 1)\)

Hope this helps ;) ❤❤❤

Let me know if there is an error in my answer.

Answer:

-3

Step-by-step explanation:

11-3=8

8-3=5

5-3=2

hope this helps!!

The coordinates in the solution to the systems of inequalities graphically is (6, 2)

From the question, we have the following parameters that can be used in our computation:

x + y > 3

x - 3y < 2

Next, we plot the graph of the system of the inequalities

See attachment for the graph

From the graph, we have solution to the system to be the shaded region

The coordinates in the solution to the systems of inequalities graphically is (6, 2)

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Step-by-step explanation:

the third Statement is true, fourth statement is trueand the fifth statement is also true because basically we need to find linear scale factor

Options 2nd, 3rd and 4th are correct options.

Two objects are similar if they have the same shape, or one has the same shape as the mirror image of the other.

Given that, Quadrilateral ABCD is similar to quadrilateral A'B'C'D'.

As we know, in similar objects, the ratio of corresponding sides are equal.

Therefore, AB/A'B' = BC/B'C' = CD/C'D' = AD/A'D'

Hence, Options 2nd, 3rd and 4th are correct options.

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Answer:

34.3

Step-by-step explanation:

Answer:  The answer is  (34.3)

Step-by-step explanation:

Since you're rounding to the nearest tenth,  you gotta look at the hundreds place which is 8. 8 rounds up so therefore, 2 rounds up and becomes 3. Which gives you the answer (34.3)

~ Hope this helps you out, have a gr8 day/night my friend!~

Answer:

angle 1 is equal to angle 4 ( vertically opposite angles)

if angle 1 is congruent to angle 8

then angle 4 is also congruent to angle 8

then slope of line L and n is equal

that is L is parallel to n

Answer:

i think it is 18 but i may be wrong

Step-by-step explanation:

3 every 10 minutes

10 x 6 is an hour so you have to multiply 3 by 6 as well

3 x 6 is 18

Answer:Rate of 3 every 10 minutes.

In 10 minutes there are 3 buses.

In  1 minute    it is        (3/10).     For 1 hour = 60 minutes.

For 60 minutes  =  3/10  * 60  =  18.

18 buses.

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Step-by-step explanation:

Answer:

(7, 3)

Step-by-step explanation:

We can solve this system using elimination. In this scenario, we can eliminate x by subtracting the two equations:

x-3y=-2

x+3y=16

-3y-3y=-2-16

-6y=-18

Divide both sides by -6

y=3

Plug 3 back in for y to solve for x:

x-3(3)=-2

x-9=-2

Add 9 to both sides

x=7

(x, y) = (7, 3)

\(\text{Given that,}~ f(x) =2x^2 -3x +1~ \text{and}~ g(x) = x+1\)

\(f(g(x))\\\\=f(x+1)\\\\=2(x+1)^2 -3(x+1) +1\\\\=2(x^2 +2x +1) -3x -3 +1\\\\=2x^2 +4x +2-3x -2\\\\=2x^2 +x\\\\=x(2x+1)\)

Answer:

f(g(x)) = 2x² + x

Step-by-step explanation:

f(x) = 2x² – 3x + 1 and g(x) = x + 1

→substitute  g(x)  for  x + 1

f(g(x)) = f (x + 1)

→substitute x for x+1 into the f(x) equation

f(g(x)) = f (x + 1)  = 2(x+1)² – 3(x+1) + 1

→calculate

f(g(x)) =  2(x+1)² – 3(x+1) + 1 , square x+1

f(g(x)) = 2( x²+2x+1) -3(x+1) +1 , distribute in parenthesis

f(g(x)) = 2x²+4x+2 -3x -3 +1, combine like terms

f(g(x)) = 2x² + x

Answer: That is the answer

Step-by-step explanation:

Answer:

18 days

Step-by-step explanation:

Find how many days it can be expected to rain by finding 60 percent of 30

30(0.6)

= 18

So, one can expect it to rain for a total of 18 days out of the 30 days

Using the inverse of the function from the table, the value of f⁻¹(4) is 107/3

The inverse of a function is a new function that "undoes" the original function. It reverses the mapping of inputs and outputs, allowing you to find the original input value when you know the output value.

In this problem, we have to use the table to find the original function which is f(x) and use it to find the inverse of the function;

Taking two points from the table;

m = y₂ - y₁ / x₂ - x₁

m = 0 - (-3) / -9 - (-11)

m = 3 / 20

Using the slope and one point on the table;

y = mx + x

-3 = 3/20(-11) + c

-3 = -1.65 + c

c = -3 + 1.65

c = -1.35

Putting the slope and y - intercept together;

y = 3/20x - 1.35

y = 3/20x - 27/20

f(x) = 3/20x - 27/20

Taking the inverse of the function;

f⁻¹(x) = (20x + 27)/3

To find the value of f⁻¹(4), we just need to substituting the value of x in the function;

f⁻¹(4) = (20(4) + 27)/3

f⁻¹(4) = 107/3

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The graph of the function y = 5|x - 4| is added as an attachment

From the question, we have the following parameters that can be used in our computation:

y = 5|x - 4|

The above function is an absolute value function that has been transformed as follows

Next, we plot the graph using a graphing tool by taking not of the above transformations rules

The graph of the function is added as an attachment

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The distance of the run Will be 16miles and the Distance of the bicycle race will be 81 miles.

Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance.

Distance = average velocity × time

Let the time and distance of the run, respectively, be t₁ and.d₁

Let those of the bicycle race be t₂ and d₂

From the question,

t₁ + t₂ = 5

d₁ = 8t₁

d₂ = 27t₂

Total distance = 97

8t₁ + 27t₂ = 97

8 ( 5 - t₂ ) + 27t₂ = 97

40 - 8t₂ + 27t₂ = 97

40 + 19 t₂ = 97

19t₂ = 57

t₂ = 3 hours

t₁ + t ₂ = 5

t₁ = 5 - t₂

t₁ = 5 - 3 = 2 hours

Now the distances are calculated as:-

d₁ = 8t₁ = 8 x 2 = 16 miles

d₂ = 27t₂ = 27 x 3 = 81 miles

Therefore the distance of the run Will be 16miles and the Distance of the bicycle race will be 81 miles.

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