Write the chemical formula for each:
ammonium nitrate
iron(II) sulfide
magnesium hydroxide
titanium(II) chloride
cobalt(III) oxide
potassium sulfide
barium acetate
magnesium bromide
lithium carbonate
potassium permanganate

A trust may be dissolved under a variety of circumstances, including the completion of its purpose, the agreement of all parties involved, or a court order. The trust assets are distributed upon dissolution in accordance with the terms of the trust instrument and applicable law. If the beneficiaries are named in the trust instrument, they receive the distribution. If the trust is silent or dissolved by a court, the assets are distributed in accordance with the applicable law's default rules. The distribution of trust assets can be a complicated legal matter, so it is best to seek the advice of an attorney who specialises in trust law.

When a trust is dissolved, the assets of the trust are distributed according to the terms of the trust document. Typically, the trustee will distribute the assets to the beneficiaries or to their designated heirs.

A trust may face dissolution under certain conditions, including:

Termination date: A trust may be established with a specific termination date. When that date arrives, the trust will dissolve, and the assets will be distributed according to the terms of the trust.

Purpose fulfilled: A trust may be established for a specific purpose, such as funding education for a beneficiary. Once the purpose of the trust is fulfilled, the trust may dissolve.

Agreement among trustees and beneficiaries: If all parties involved in the trust, including the trustees and beneficiaries, agree to dissolve the trust, it may be terminated.

Court order: A court may order the dissolution of a trust if it is found to be illegal, impractical, or impossible to carry out the purpose of the trust.

When a trust is dissolved, the assets of the trust are distributed according to the terms of the trust document.

Typically, the trustee will distribute the assets to the beneficiaries or to their designated heirs. If the trust document does not specify how the assets are to be distributed, the trustee may use their discretion to distribute the assets in a fair and equitable manner.

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Explanation:

1. Cotton (B)

2. It needs to go through a chemical reaction. (C)

3. A chain of repeating compounds found in both natural and synthetic materials. (D)

4. Oil and natural gas are chemically broken down into small compounds that combine to form plastic.

At STP, a mole of pure gas is closest in size to a marble. As a tiny, solid material, a gram of gas at the STP is considerably smaller than a marble. D is the correct response.

At Standard Pressure and Temperature, 22.4 L of any gas will be required to hold 1 mole (STP). The Ideal Gas Law and a balanced chemical equation can be used to determine the amount or mass of gas consumed or created in a chemical process. In other words, the gas that has the greatest number of molecules of a certain gas at a given temperature will occupy the largest volume.

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Question: From the following items, which is closest in size to one mole of gas at STP?

A) A car

B) An elephant

C) A microwave

D) A marble

The 85th percentile of blood pressure readings is approximately 137.64. a. To calculate the z-score for a blood pressure reading of 140, we can use the formula:

z = (x - μ) / σ

where x is the value (140 in this case), μ is the mean (121), and σ is the standard deviation (16).

Substituting the values into the formula:

z = (140 - 121) / 16

z ≈ 1.19 (rounded to two decimal places)

b. To find the proportion of Canadians with high blood pressure, we need to calculate the area under the normal distribution curve for values above 140. This can be done by finding the cumulative probability using the z-score.

Using a standard normal distribution table or a calculator, we can find that the cumulative probability corresponding to a z-score of 1.19 is approximately 0.881.

Therefore, the proportion of Canadians with high blood pressure is approximately 0.881 (rounded to four decimal places).

c. To find the proportion of Canadians with systolic blood pressure in the range from 100 to 140, we need to calculate the area under the normal distribution curve between these two values.

Using the z-scores corresponding to 100 and 140, we can find the cumulative probabilities for each value. The cumulative probability for a z-score of -1.25 (corresponding to 100) is approximately 0.105, and the cumulative probability for a z-score of 1.19 (corresponding to 140) is approximately 0.881 (as calculated in part b).

The proportion with systolic blood pressure between 100 and 140 is the difference between these two probabilities:

Proportion = 0.881 - 0.105 ≈ 0.776 (rounded to four decimal places)

d. The 85th percentile represents the value below which 85% of the blood pressure readings fall. To find the 85th percentile, we need to determine the z-score that corresponds to an area of 0.85 under the normal distribution curve.

Using a standard normal distribution table or a calculator, we can find that the z-score corresponding to an area of 0.85 is approximately 1.04.

To find the actual blood pressure reading at the 85th percentile, we can use the z-score formula:

x = μ + (z * σ)

Substituting the values:

x = 121 + (1.04 * 16)

x ≈ 137.64

Therefore, the 85th percentile of blood pressure readings is approximately 137.64.

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The ground state electron configuration [kr]5s²4d¹⁰5p³ belongs to the element antimony (Sb). By combining all the subshells, we have [kr]5s²4d¹⁰5p³, which corresponds to the electron configuration of antimony (Sb).

The electron configuration given is composed of two parts: the noble gas core notation [kr] and the valence electrons (5s²4d¹⁰5p³). The noble gas core notation indicates that the element's electron configuration is the same as the noble gas krypton (Kr) up to the 4th energy level (4d).

To determine the element, we need to count the number of valence electrons. In this case, the valence electrons are in the 5s, 4d, and 5p orbitals.

5s² represents two electrons in the 5s orbital.

4d¹⁰ represents ten electrons in the 4d orbital.

5p³ represents three electrons in the 5p orbital.

Adding up the electrons from each orbital, we have:

2 (5s) + 10 (4d) + 3 (5p) = 15 valence electrons.

The element with the ground state electron configuration [kr]5s²4d¹⁰5p³ is antimony (Sb).

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All the living organisms need water to survive in the earth. It is very important to preserve water. Waste water treatment is used to purify water.

The process which is used to remove all the contaminants from the waste water and thereby converting it to an effluent which can be returned to the environment is defined as the waste water treatment.

The main goal of waste water treatment is to minimize the scarcity of water by supplying with fresh and healthy drinking water. This process also conserves the life of all aquatic organisms, humans and ecosystem from the toxic elements present in the waste water.

This process of removing wastes from the waste water also helps to reduce the spread of diseases like cholera, typhoid etc. If the chemicals like nitrogen, and phosphate enters into the water bodies causes sudden plant growth which releases toxins and thereby results in oxygen depletion.

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Answer:

it would be B

Explanation:

so, p(OH)+ p(H) = 14, with some simple re-arrangement you get p(OH)=14-p(H).

The pH and pOH is related as pOH = 14 - pH

So, option B is correct one.

Evaluation,

Since, pOH + pH = 14,

By re-arrangement we get,

pOH = 14 - pH

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Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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Answer:

distance and time

Answer:

d. Distance and time

Explanation:

Why was the American Federation of

Labor a different type of labor union

(compared to the Knights of Labor)

and why did it grow during the 20th

century?

False, Asbestos is a naturally occurring mineral fiber that was commonly used in various industries due to its heat resistance, strength, and insulating properties.

Asbestos does not necessarily need to be removed if it will not be disturbed or pose a risk to human health. Asbestos-containing materials that are in good condition and undisturbed are generally considered safe. However, if asbestos-containing materials are damaged, deteriorating, or will be disturbed during renovation or demolition activities, it is necessary to take appropriate precautions, which may include professional removal or encapsulation, to prevent the release of asbestos fibers into the air. The decision to remove asbestos should be based on an assessment of its condition, potential for disturbance, and adherence to local regulations and guidelines.

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The naturally occurring the element x exists in three isotopic forms. The average atomic weight of x 28.544 amu.

Given that :

x- 28, Abundance % = 67.14 % = 0.6714

The atomic mass = 27.343 amu

x-29, Abundance % = 10.50 % = 0.1050

The atomic mass = 28.889 amu

x- 32, Abundance %  = 22.36 % = 0.2236

The atomic mass = 31.993 amu

The average atomic weight = ( 27.343 × 0.6714 ) + ( 28.889 × 0.1050) +

                                                          ( 31.993 × 0.2236)

                                                 = 18.358 + 3.0333 + 7.153

                                                 = 28.544 amu

Thus, the average atomic weight of naturally occurring element x exists in three isotopic forms 28.544 amu.

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Answer:

B. Coal has fewer emissions than petroleum and natural gas.

Explanation:

The coal combustion process is more carbon-intensive than, say, burning natural gas or petroleum. Coal emissions are almost double those of petroleum.

Answer:

there is rainbow after the rain goes away because there is sun in the sky and that's why there is rainbow in the sky

Explanation:

Explanation:

Rainbow is formed due to dispersion of sunlight by tiny water droplets suspended in the atmosphere after a rain shower .....After rain shower the sun is visible to us again and the rain water droplets are suspended in the atmosphere therefore they disappear sunlight and and rainbow is formed

The major alkene  product that results when n,n-dimethylhexan-2-amine undergoes cope elimination is hexene or hex-1-ene.

The reaction in which an amine is oxidize to an intermediate called an N-oxide which , when heated , acts as base in an intramolecular elimination reaction. The oxidation of tertiary amine into N-oxide is called cope reaction.

This elimination gives the less substituted alkene along with more substituted alkene which is Zaitsev product.

Example: Cope elimination of  n,n-dimethylhexan-2-amine form hexene.

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Answer:

B)group or family

Explanation:

Because of their similar chemical behavior

Answer:

I kinda think it's 2.popular convalent bonding

If the threshold energy of the reaction 2016O(n, γ) 170 is 15.6 MeV, then the atomic mass of 170Ol can be calculated.

Given:Atomic mass of Ol (15.996415 amu)Atomic mass of neutron (1.008665 amu)M (Ol) = 15.996415 amuM (neutron) = 1.008665 amu Threshold energy of the reaction, E = 15.6 MeV The threshold energy (E) is the minimum amount of energy that an incoming neutron must have to trigger the nuclear reaction or the amount of energy that is needed to supply for the reaction to proceed.

The atomic mass of 170Ol can be calculated as follows:E = [M (n) + M (2016O) - M (170O)] x c²Where c = speed of light, M (n) = mass of neutron, M (2016O) = mass of oxygen-16M (170O) = mass of the oxygen-17, the product of the reaction.Rearranging the above equation:  M (170O) = [M (n) + M (2016O) - E/c²]Thus, M (170O) = [1.008665 + 15.994915 - (15.6 x 10⁶ eV/ (3.0 x 10⁸ m/s)²)] amuM (170O) = 16.98803 amuTherefore, the atomic mass of 170Ol is 16.98803 amu.

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Student 2 explains why the water only condensed on the top part of the test tube using sound scientific reasoning. The process through which a gas transforms into a liquid is called condensation. Therefore, choice B is right.

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The nuclear equation for the alpha decay of Uus-294 is

\(^{294}{117} Uus\) →\(^{4}{2}He + ^{290}_{115}Mc\)

To complete the nuclear equation for the alpha decay of Uus-294, we need to determine the missing product.

During alpha decay, the emission of an alpha particle, composed of two protons and two neutrons, leads to the formation of a new nucleus.

The balanced nuclear equation for the alpha decay of Uus-294 can be represented as follows:

\(^{294}{117} Uus\) → \(^{4}{2}He +\)_____(missing product)

In this equation, the atomic number of the missing product must be two less than the atomic number of Uus-294 (117 - 2 = 115), and the mass number of the missing product must be four less than the mass number of Uus-294 (294 - 4 = 290).

Based on this information, the missing product can be identified as:

\(^{290}_{115}Mc\)

Mc stands for Moscovium, which has an atomic number of 115. By subtracting two from the atomic number of Uus, we obtain the atomic number of Mc. The mass number of Mc-290 is obtained by subtracting four from the mass number of Uus-294.

Therefore, the  nuclear equation for the alpha decay of Uus-294 is:

\(^{294}{117} Uus\)→ \(^{4}{2}He + ^{290}_{115}Mc\)

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The complete question is :

Complete this nuclear equation for the alpha decay of Uus-294 by writing a

notation for the missing product:

\(^{204} {117} Uns\)→\(^{4} _{2} He +\)_____

When chlorine forms an ion then it gains an electron and has an octet in its outer shell as  chlorine atom holds 7 electrons in its valence shell and might achieve an octet configuration through gaining an electron.

The outermost shell of sodium has one electron. Cl- has eight electron in its outer shell (it obeys octet rule of 8 valence in outer shell. Chlorine consequently has 7 valence electron consequently it advantage 1 electron to shape Cl- (ion).The electron configuration of chlorine is 1S2 2S2 2P6 3S2 3P5.

Again, it's extra energy-green for chlorine to benefit one electron than to lose seven. Therefore, it has a tendency to benefit an electron to create an ion with 17 protons, 17 neutrons, and 18 electrons, giving it a negative (–1) charge. It is now called a chloride ion.

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The equilibrium constant for the following reaction is 5.0×10⁸ at 25∘C. N₂(g)+3H₂(g)⇌2NH₃(g) The value of ΔG∘ for this reaction is  -68.17 kJ/mol. The equilibrium constant for the following reaction is at . The value of for this reaction is -50 .(D)

The given chemical reaction is N₂(g) + 3H₂(g) ⇌ 2NH₃(g).

The equilibrium constant of the given reaction is 5.0×10⁸ at 25∘C. We have to calculate the value of ΔG∘ for this reaction.

Now, the formula to find ΔG∘ is given below:ΔG∘ = - RT ln K

= - (8.314 J/K/mol)(298 K) ln (5.0×10⁸)

= - (8.314 × 298) ln (5.0×10⁸)

= - 68,172.344 J/mol

= - 68.17 kJ/mol.

So The value of ΔG∘ for the given reaction is -68.17 kJ/mol.(D)

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Given the following equation: 2N2 + 5O2 → 2N2O5, the number of moles of N2O5 produced by reacting 6.0 moles of O2 is 2.4moles.

The number of moles of a substance can be calculated stoichiometrically as follows:

2N2 + 5O2 → 2N2O5

Based on the above chemical equation, 5 moles of oxygen gas (O2) produces 2 moles of N2O5.

This means that if 6.0 moles of O2 reacts, 6 × 2/5 moles of N2O5 will be produced.

= 12/5 = 2.4moles of N2O5

Therefore, given the following equation: 2N2 + 5O2 → 2N2O5, the number of moles of N2O5 produced by reacting 6.0 moles of O2 is 2.4moles.

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Answer:

2 HNO3 + CaCO3 = Ca(NO3)2 + H2O + CO2

Explanation:

Given Equation :

\(HNO_3 + CaCO_3 = Ca(NO_3)_2 + H_2O + CO_2\)

Balanced Equation

\(2 HNO_3 + CaCO_3 = Ca(NO_3)_2 + H_2O + CO_2\)

The reaction is exergonic. that is the free energy change delta G for a reaction is -46.11 kJ/mol, the reaction is exergonic.

Chemical thermodynamics, exergonic reactions are chemical reactions in which the change in free energy is negative (there is a net release of free energy).

This shows the spontaneous reaction when the system is closed and the initial and final temperatures are the same.

Reactions can be endergonic or exergonic. Endergonic reactions require heat or energy input. The exergonic reaction is the opposite. it gives off heat. Answer and Explanation:

Reactions with negative values of G are exergonic, meaning they release heat.

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Answer:

C₃H₅N₃O₉

Explanation:

Molar mass of nitroglycerin (Ratio of mass and moles of the compound) is:

1.00g / 0.0041mol = 226.8g/mol

We can write the equations:

0.6H = C (1)

-60% as many carbon atoms as hydrogen atoms-

3N = O (2)

C = N

Using as basis the atoms of Carbon:

Carbon = 1

Nitrogen = 1

Oxygen = 3

Hydrogen = 1/0.6 = 1.67

A molecular formula has just whole numbers. This ratio of atoms times 3:

Carbon = 3

Nitrogen = 3

Oxygen = 9

Hydrogen = 5

C₃H₅N₃O₉. Molar mass of this formula is:

C = 12.01g/mol*3 = 36.03g/mol

H = 1.01g/mol*5 = 5.05g/mol

N = 14g/mol*3 = 42g/mol

O = 16g/mol*9 = 144g/mol

Molar mass:

36.03g/mol + 5.05g/mol + 42g/mol + 144g/mol = 227g/mol ≈ 226.8g/mol

That means molecular formula of nitroglycerin is:

The molecular formula of nitroglycerin is C₃H₅O₉N₃

Mass of nitroglycerin = 1.00 g

A number of moles of nitroglycerin =  0.0041 mol

It is required to calculate the molecular formula of nitroglycerin.

An empirical formula tells us the relative ratios of different atoms in a compound.

The molecular formula of nitroglycerin can be estimated with the help of empirical formula.

The molar mass of nitroglycerin (Ratio of mass and moles of the compound) is:

1.00g / 0.0041mol = 226.8 g/mol

We can write the equations:

0.6H = C (1)

-60% as many carbon atoms as hydrogen atoms-

3N = O (2)

C = N

Using as basis the atoms of Carbon:

Carbon = 1

Nitrogen = 1

Oxygen = 3

Hydrogen = 1/0.6 = 1.67

A molecular formula has just whole numbers. This ratio of atoms times 3:

Carbon = 3

Nitrogen = 3

Oxygen = 9

Hydrogen = 5

C₃H₅N₃O₉.

Molar mass of this formula is:

C = 12.01g/mol*3 = 36.03g/mol

H = 1.01g/mol*5 = 5.05g/mol

N = 14g/mol*3 = 42g/mol

O = 16g/mol*9 = 144g/mol

Molar mass:

36.03g/mol + 5.05g/mol + 42g/mol + 144g/mol = 227g/mol ≈ 226.8g/mol

That means molecular formula of nitroglycerin is:

C₃H₅N₃O₉

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This means the molar mass of CH is

\(12.011+1.00794=13.01894 \text{ g/mol}\)

Dividing the given molar mass by this,\(\frac{104.1}{13.01894} \approx 8\)

This means the molecular formula is \(\boxed{\text{C}_{8}\text{H}_{8}}\)

The forward reaction in this case is formed in an exothermic reaction. Option A

The use of the term equilibrium has been found to be very much common in the field of science. We have to note that in chemistry, the point of equilibrium is the point where the rate of the forward reaction is equal to the rate of the reverse reaction.

Given the fact that when the temperature was raised the equilibrium was pushed to the left hand side and we had the dark brown gas formed, the implication is that the  forward reaction is exothermic.

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pCO2 is an important factor that affects various aspects of water chemistry and the impacts of ocean acidification. When pCO2 increases, the concentration of total CO2 dissolved in water also increases. This leads to changes in pH, which decreases due to increasing atmospheric CO2 concentration.

When pCO2 rises, the concentration of only CO2 dissolved in water increases. The dissolved CO2 forms carbonic acid, which contributes to the acidification of the ocean. This increase in CO2 affects the equilibrium between CO2, HCO3-, and CO3^2-, shifting it towards higher levels of dissolved CO2 and H+ ions, resulting in a lower pH.

In terms of the impacts of ocean acidification on different organisms, the effects can vary depending on their specific needs. An organism that requires CO2 is likely to fare better under ocean acidification since the increase in dissolved CO2 can provide them with a favorable environment. However, organisms that rely on HCO3- or CO3^2- may fare worse under ocean acidification, as the lower pH interferes with the availability of these carbonate ions, which are essential for shell formation and calcification in some marine organisms.

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