Write the equation for photosynthesis.​

Each of the 11 body systems depends on others to function. So, the correct option is Option B.

The human body is actually an amazing combination of many different systems that work together to keep everything functioning correctly. For example, some systems handle food and energy, while others focus on taking in oxygen and moving it around the body. By learning about the different systems working inside the body, we can understand how everything works together to keep you healthy, growing, and strong. The various systems of our body are interconnected and are dependent upon each other. The circulatory system includes the heart the heart does not beat unless the nervous system including the brain tells the heart to beat. The skeletal system is also connected to our digestive system for an increase in the size and strength of the muscles, bones, and cartilage.  It takes all the body systems for the proper growth and development of the human body.

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Answer:

IMA = 2.5 metres

EFFICIENCY = 80%

Explanation:

The AMA of a machine is referred to as the Actual Mechanical Advantage of a machine, calculated as the ratio of the output to the input force.

The Ideal Mechanical Advantage is the ratio of the input distance to the output distance.

From the diagram, the input distance which is also the distance moved by effort  = 5metres

The load distance (output distance) = 2 metres

IMA = INPUT DISTANCE / OUTPUT DISTANCE

IMA = 5metres / 2 metres = 2.5 meters

Efficiency is the ratio of AMA TO IMA

AMA = 2, IMA = 2.5

EFFICIENCY = AMA / IMA

EFFICIENCY = (2 / 2.5) × 100%= 0.8 × 100%

EFFICIENCY = 80%

Answer:

67.56kg

Explanation:

Fapp+mg = ma

Fapp= applied force

mg = reactional force

g = acceleration due to gravity

Where g = 9.8m/s^2 a= 5 m/s2, Fapp= 1000N.

1000N = ma + mg

1000N = m( a+g )

1000N = m ( 5+9.8)

1000N = m×14.8

m = 1000÷14.8

m = 67.56kg.

Hence the mass of the wagon will be 67.56kg

Answer:

c = 0.4356 J/gK

Explanation:

Given the following data;

Mass = 450 grams

Initial temperature, T1 = 150°C

Final temperature, T2 = 53°C

Quantity of heat = 34500 Joules

To find the specific heat capacity of the metal;

Heat capacity is given by the formula;

\( Q = mcdt\)

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 53 - 150

dt = -97°C

Converting the temperature in Celsius to Kelvin, we have;

dt = 273 + (-97) = 176 Kelvin

Making c the subject of formula, we have;

\( c = \frac {Q}{mdt} \)

Substituting into the equation, we have;

\( c = \frac {34500}{450*176} \)

\( c = \frac {34500}{79200} \)

c = 0.4356 J/gK

Answer:

Sound gets produced when something makes noise, which in turn creates what's called a pressure wave. Then, the pressure wave causes the surrounding particles to vibrate. As those particles vibrate, they make other particles vibrate too, pushing the sound forward through the sound medium. Hope this helps!

Explanation:

Answer:

Explanation:

because it is a function of physics that will always be true, hope this helps :)

The frequency of the sound wave is 1.07 × 10⁹ Hertz

Wavelength is simply the distance over which the shapes of waves are repeated.

From the wavelength, frequency and speed relation,

λ = v ÷ f

Where λ is wavelength, v is velocity/speed and f is frequency.

Given that:

Plug values into the above formula.

λ = v ÷ f

f = v / λ

f = ( 343 m/s ) / ( 3.2 × 10⁻⁷ m )

f = 1.07 × 10⁹ Hz

Therefore, the frequency is 1.07 × 10⁹ Hz.

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The vertical distance between the trough and crest of a wave is called the wave height.

The wave height refers to the vertical distance between the lowest point of the wave, known as the trough, and the highest point of the wave, known as the crest. It measures the amplitude of the wave in the vertical direction.

When a wave propagates through a medium, it creates a pattern of oscillations. The wave height represents the maximum displacement of the particles or the surface of the medium from their equilibrium position.

The wave height is an important parameter in describing the size and intensity of waves. In the context of ocean waves, for example, larger wave heights indicate more significant wave energy and potential for stronger impacts, such as coastal erosion or wave damage to structures.

The wave height is the vertical distance between the trough and crest of a wave. It provides information about the amplitude and intensity of the wave and is a crucial factor in analyzing wave behavior and its effects on the surrounding environment.

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The maximum kinetic energy with which the same radiation ejects electrons from another metal with a work function of 2.19 eV is 1.31 eV.

When radiation of a certain wavelength falls on a metal surface, it can eject electrons from the surface if the energy of the radiation is greater than the work function of the metal. The work function is the minimum energy required to remove an electron from the metal surface. The maximum kinetic energy of the ejected electrons depends on the difference between the energy of the radiation and the work function of the metal. If the maximum kinetic energy of the ejected electrons is 0.60 eV for one metal with a work function of 2.90 eV, then the energy of the radiation can be calculated as 3.50 eV. Using this same radiation, the maximum kinetic energy of the ejected electrons for another metal with a work function of 2.19 eV can be calculated as 1.31 eV. This is because the difference between the energy of the radiation and the work function of the second metal is 3.50 eV - 2.19 eV = 1.31 eV.

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Answer:

i think its a load to move a object,

Explanation:

im taking this to and it isnt in the lesson

Answer:

2.345 would be the most precious because you have more numbers to work with and exact numbers

The farthest away a target could be hit by a shell is approximately 1000 yards (rounded to the nearest whole number).

To solve the problem, we need to find the total distance that the shell can travel before it bursts.

The distance that the shell can travel is:

distance = rate × time

We are given that the shell can travel 500 yards in 1.5 seconds, so its speed is:

rate = distance ÷ time = 500 yards ÷ 1.5 seconds = 333.33 yards/second

Now we need to take into account the time it takes for the fuse to go off. Since it takes 3 seconds for the fuse to go off, the shell will have traveled:

distance = rate × time = 333.33 yards/second × (1.5 seconds + 3 seconds) = 999.99 yards

Therefore, the farthest away a target could be hit by a shell is approximately 1000 yards (rounded to the nearest whole number).

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Answer:

does not have a definite shape or volume=gas

has a definite volume but has no shape=liquid

has a definite shape and volume=solid

changes to liquid on heating=melting

changes to solid on cooling=freezes

changes to liquid on cooling=condensation

An object with greater charge will exert a greater force on an object than an object with smaller charge would. However, if you consider two charges that exert a force on each other, regardless of the magnitude of charge, both charges will exert an equal force on each other because of Newton's third law.

Answer:

An article written by a scientist .

Explanation:

Primary sources information are those that contain first  hand information probably from the place of the activities or by the original contact of the information (source ) .

So primary information is normally contained in artifact , journals , letter , dissertations manuscripts  , videos and audio recordings .

The fact that the article is written by the scientist means he is the one who has the original information hence he is the first person to access the information , meaning he is the original owner .

Answer:

Explanation:

it's B)  or the question right above the one you've marked.   The planets do form a plane almost exactly :0   but not a sphere.  

Answer:

The trees are blocking the sunlight.

Explanation:

B is obviously not the answer because fertilizer wouldn't have that effect. For C, shade doesn't change the temperature that much that it would inhibit plant growth. For D, even if the tree blocks the water, the surrounding ground will still be wet and therefore the grass should still have a sufficient amount of water to grow.  Sunlight can't be gotten from somewhere else, unlike water, so this would inhibit plant growth.

Answer: The graph will look like a simple linear equation. It is diagonal and trends upward

Explanation:

Out of the given statements about conductors under electrostatic conditions, option C is true. The electric potential inside a conductor is always zero. This is because in electrostatic conditions, charges on a conductor are in static equilibrium and there is no electric field inside the conductor.

Any excess charge on the conductor resides on its surface, and the electric field inside the conductor is zero. Due to this, the electric potential inside a conductor is constant and equal to zero.

Option A is false as positive work is not required to move a positive charge over the surface of a conductor. This is because the charge on a conductor is free to move, and the electric field inside a conductor is zero.

Option B is false as the charge that is placed on the surface of a conductor may not always spread evenly over the surface. This is because the shape and geometry of the conductor can affect the distribution of charges on its surface.

Option D is false as the electric field at the surface of a conductor is always perpendicular to the surface. This is because if the field were tangent to the surface, there would be a component of the field along the surface, which would cause charges to move along the surface, resulting in a non-static equilibrium.

Option E is false as the surface of a conductor is not always an equipotential surface. This is because the distribution of charges on a conductor's surface can be uneven, leading to variations in the electric potential on its surface.

Hence, Option C is correct.

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The 5-volt reading we can expect between the two test points if the reference lead is on the lowest voltage.

The given data is as follows:

The first test marked voltage = 5 volts

The second test marked voltage = -3.3 volts

Let us assume that the two test points are there is a conductive track between them, the voltage between the two points can be calculated using the voltage difference between the two test points.

The voltage difference between the  two test points is calculated as:

5 volts - (-3.3 volts) = 8.3 volts

If the reference lead is on the lowest voltage, It means that the negative side of the voltmeter is attached to the test point with the lower voltage which is -3.3 volts.

The voltage difference between the  two test points is

8.3 volts - 3.3 volts = 5 volts

Therefore we can conclude that the 5-volt reading we can expect between the two test points.

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The pressure at point B is 622.5 kPa.

Based on the information provided, we can determine the velocity of the water through the 40-mm-diameter elbow using the formula Q = Av, where Q is the volumetric flow rate (0.012 m³/s), A is the cross-sectional area of the elbow (πr², where r is the radius of the elbow), and v is the velocity of the water.

We can rearrange the formula to solve for v:

v = Q / A

The radius of the elbow can be determined by dividing the diameter by 2:

r = 40 mm / 2 = 20 mm = 0.02 m

The cross-sectional area of the elbow can then be calculated using the formula A = πr²:

A = π(0.02 m)² = 0.00126 m²

Substituting these values into the formula for velocity:

v = 0.012 m³/s / 0.00126 m² = 9.52 m/s

Now that we know the velocity of the water, we can use Bernoulli's equation to determine the pressure at point B:

P₁ + 0.5ρv₁² + ρgh₁ = P₂ + 0.5ρv₂² + ρgh₂

Where P₁ is the pressure at point A (170 kPa), ρ is the density of water (1000 kg/m³), g is the acceleration due to gravity (9.81 m/s2), h₁ and h₂ are the heights of points A and B above a reference level (we can assume they are the same), and P₂ is the pressure at point B (what we want to find).

Rearranging the equation and substituting in the known values:

P₂ = P₁ + 0.5ρ(v₁² - v₂²)

P₂ = 170 kPa + 0.5(1000 kg/m³)(9.522 - 02) = 170 kPa + 452.5 kPa

P₂ = 622.5 kPa

Therefore, the pressure at point B is 622.5 kPa.

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Since there is no friction, the normal force must be equal in magnitude and opposite in direction to the weight. Therefore, the magnitude of the normal force is also 46.06 N or 46.1 N.

The normal force is the force exerted by a surface perpendicular to the object in contact with the surface. In this case, the cart is rolling down the ramp, and the normal force is exerted by the ramp on the cart. Since the ramp is inclined, the normal force will be less than the weight of the cart, which is given by:

\(W = m*g\)

where m is the mass of the cart and g is the acceleration due to gravity.

In this problem, the mass of the cart is given as 4.7 kg, and the acceleration due to gravity is approximately \(9.8 m/s^2.\)

Therefore, the weight of the cart is:

\(W = 4.7 kg * 9.8 m/s^2 = 46.06 N\)

Since there is no friction, the normal force must be equal in magnitude and opposite in direction to the weight. Therefore, the magnitude of the normal force is also 46.06 N.

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In order to form a hypothesis that would illustrate the relationship between mass and kinetic energy, we first need to understand what kinetic energy and mass are and how they are related. Kinetic energy is the energy that an object possesses due to its motion, and is given by the formula KE = 0.5mv², where m is the mass of the object and v is its velocity. Mass, on the other hand, is a measure of the amount of matter in an object.

The relationship between mass and kinetic energy is direct, meaning that as mass increases, so does kinetic energy, provided that velocity remains constant. Similarly, if velocity increases, then kinetic energy will increase as well, provided that mass remains constant.

The hypothesis that illustrates this relationship can be stated as follows:If the mass of an object is increased, then the kinetic energy of the object will also increase, because kinetic energy is directly proportional to mass, assuming velocity remains constant.In other words, if the mass of an object is doubled, then its kinetic energy will also double, assuming that its velocity remains constant. This hypothesis can be tested through experiments that involve measuring the kinetic energy of objects with different masses, but with the same velocity.

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If the mass of an object increases, then its kinetic energy will increase proportionally because mass and kinetic energy have a linear relationship when graphed.

Answer:

yes

Explanation:

A thermometer is a device that measures temperature. Clinical and non-clinical thermometers are two types of thermometers with different purposes.

A clinical thermometer is designed to measure the human body temperature. It usually has a range from 95°F to 110°F or 35°C to 43°C. Clinical thermometers have a narrow range of measurement and high sensitivity. They are typically made of glass and contain a liquid (usually mercury) that expands as temperature increases, causing the level of mercury to rise up the calibrated tube. These thermometers may have a bend in the tube called a kink to prevent the mercury from returning to the bulb after measurement.

On the other hand, non-clinical thermometers are designed for industrial or laboratory use. They measure a wider range of temperatures than clinical thermometers, ranging from -200°C to over 1000°C. Non-clinical thermometers can be made of various materials, such as glass, metal, or plastic. Some common types of non-clinical thermometers include bimetallic thermometers, digital thermometers, infrared thermometers, and thermocouples.

In summary, clinical thermometers are designed for measuring human body temperature and have a narrow range of measurements, while non-clinical thermometers are used for a wider range of temperature measurements in industrial or laboratory settings.

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A particular reflecting telescope has an objective mirror with a focal length of 1.2 m and an eyepiece of focal length 6mm. Hence the magnifying power of this telescope would be 2 meter.

The magnifying power of the telescope is the ratio of the focal length of the object to the focal length of the eyepiece, that is, m = \(\frac{fo}{fe}\)

Given, the focal length of a objective mirror = 1.2 m,

First, we will convert it to centimeters for ease,

∴ Now, the focal length of objective mirror is 120 centimeters, and,

the focal length of an eyepiece is 6mm which is also 0.6 centimeters.

For a telescope, the magnification is given as:

∵ m = \(\frac{fo}{fe}\)

⇒ m = \(\frac{120}{0.6}\)

⇒ m = 200 centimeters or 2 meter.

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​

Answer:

 V = 2.52 10³ V

Explanation:

The electric potential for a point charge is

       V = k ∑ \(\frac{q_i}{r_i}\)

In this case the formula is

       V = k (\(\frac{q_1}{r_1} + \frac{q_2}{r_2}\))

distances are the absolute value

       r₁ =√ (7.1 -0)² = 7.1 m

       r₁ =√ (7.1 - 14.3)² = 7.2 m

we substitute

       V = 9 10⁹ (q₁ / 7.1 + q₂ / 7.2)

we have two possibilities

* different charges

         V = 9 10⁹ (q₁ / 7.1 + q₂ / 7.2)

* equal charges and same sign

          q₁ = q₂ = q

         V = 9 10⁹ q (1 / 7.1 + 1 / 7.2) = p 9 10⁹   0.2797

         V = 2.52 10⁹ q

if we assume a value of the charge, for example q = 1 10⁻⁶ c

           V = 2.52 10⁹ 1 10⁻⁶

            V = 2.52 10³ V

Answer:

\( \green{ \sf \: \: 1.6 \: m {s}^{ - 2} \: \: \: is \: the \: correct \: answer}\)

Explanation:

\( \sf \: \huge{g } _{ \small{moon}} = \frac{ {\huge{g}}_{earth}}{6} \\ \\ \sf \implies \: \sf \: \huge{g } _{ \small{moon}} = \frac{ 9.8}{6} = 1.6 \: \: m {s}^{ - 2} \)

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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The direction and magnitude of the electric field that generates a charge of -6. 3 µC at 0. 50cm and 2. 75mm is 226.5 × 10³ N/C and 7490 × 10⁶ N/C. In the direction towards the charge.

The electric field created by a particular electric charge Q is defined as the space surrounding the charge in which another charge q can experience electrostatic attraction or repulsion caused by the charge Q.

As a result, E is a vector quantity that moves together with the test charge +q in the direction of the force.

The electric field E is given by,

E = q/4π∈r²

where q is charge, ∈ is permittivity of free space, r is distance.

For 50 cm = 0.5 m

Electric field E is,

E = -6. 3 × 10⁻⁶ C/4π × 8.85×10⁻¹² m⁻³kg⁻¹ s⁴ A² × 0.5²

E = 226.5 × 10³ N/C

For 2.75 mm = 0.00275 m

Electric field E is,

E = -6. 3 × 10⁻⁶ C/4π × 8.85×10⁻¹² m⁻³kg⁻¹ s⁴ A² × 0.00275²

E = 7490 × 10⁶ N/C

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