Answer:
y = x - 600
Step-by-step explanation:
y = mx + b , "m" is slope and "b" is y-intercept
y - \(y_{1}\) = m(x - \(x_{1}\))
~~~~~~~~~~~~~
y-intercept is (0, - 600) and x-intercept is (600, 0)
The slope is 1
y + 600 = x - 0
y = x - 600
A coin is flipped, then a number 1 - 10 is chosen at random. What is the probability of landing on heads then a number greater than 3
Answer: 3/8
Step-by-step explanation:
There is no effect between flipping a coin and chosing a number.
This situation is known as a independent event.
P(AnB) = P(A)*P(B)
The situation A = Heads or tails of money = 1/2
The situation B = 6/8
It can be calculated as below:
Probability = Desired / All Event
Desired || Numbers between 3 and 10 are : 4,5,6,7,8,9 = 6 pieces
All Event || Numbers between 1 and 10 are : 2,3,4,5,6,7,8,9 =8 pieces
Consequently product the fractions.
1/2 * 6/8 = 6/16 = 3/8
Please help ASAP
Frequency Distribution table
The answer is:
A frequency distribution for a collection of data is shown in the accompanying table.
The intervals or ranges of the data are displayed in the left column of the table, and the frequency or number of observations within each interval is displayed in the right column.
For instance, the first row demonstrates that 3 observations fall within the range of 10 to 19, the second demonstrates that 5 observations fall within the range of 20 to 29, and so on.
We only combine the frequencies to determine the total number of observations:
Total observations are equal to 3 + 5 + 7 + 4 + 1 = 20.
By averaging the bottom and upper interval bounds, we can also determine each interval's midpoint. As an illustration, the first interval's midway (10-19) is as follows:
Midpoint: (14.5) (10 + 19) / 2
This may be done for each interval, and to display the midpoints, we can add a third column to the table.
The cumulative frequency, which is the overall frequency as we progress from the shortest interval to the longest interval, can then be calculated. The cumulative frequency can be displayed in the table by using a fourth column.
The finished table is shown here:
Interval Frequency Midpoint Cumulative Frequency
Oct-19 3 14.5 3
20-29 5 24.5 8
30-39 7 34.5 15
40-49 4 44.5 19
50-59 1 54.5 20
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1.2.9. attempt to solve the system −x1 3x2 − 2x3 = 4, −x1 4x2 − 3x3 = 5, −x1 5x2 − 4x3 = 6, using gaussian elimination and explain why this system must have infinitely many solutions.
The system of equation have 0 = 0, so this system must have infinitely many solutions.
The system of equations are:
-x(1) + 3x(2) - 2x(3) = 4,
-x(1) + 4x(2) − 3x(3) = 5,
-x(1) + 5x(2) - 4x(3) = 6
An approach for resolving networks of linear equations is called Gaussian elimination, commonly referred to as row reduction. It comprises of a series of operations carried out on the relevant coefficients matrix.
\(\left [ \begin{matrix}-1 &3 & -2\\ -1 &4 &-3 \\ -1&5 & -4\end{matrix} \right ]\begin{bmatrix}x(1)\\ x(2)\\ x(3)\end{bmatrix}=\begin{bmatrix}4\\ 5\\ 6\end{bmatrix}\)
The matrix is in the form of
[A][X] = [D]
To solve the matrix we represent the matrix in the form of [A : D]
Now writing the augmented matrix
\(\left [ \left.\begin{matrix}-1 &3 & -2\\ -1 &4 &-3 \\ -1&5 & -4 \end{matrix}\right| \begin{matrix}4\\5 \\6 \end{matrix}\right ]\)
Now solving the matrix
R(2)→R(2) - R(1) and R(3)→R(3) - R(1)
\(\left [ \left.\begin{matrix}-1 &3 & -2\\ 0 &1 &-1 \\ 0&2 & -2 \end{matrix}\right| \begin{matrix}4\\1 \\2 \end{matrix}\right ]\)
R(1)→R(1) - R(3)
\(\left [ \left.\begin{matrix}-1 &1 & 0\\ 0 &1 &-1 \\ 0&2 & -2 \end{matrix}\right| \begin{matrix}2\\1 \\2 \end{matrix}\right ]\)
R(3)→R(3) - 2R(2)
\(\left [ \left.\begin{matrix}-1 &1 & 0\\ 0 &1 &-1 \\ 0&0 & 0 \end{matrix}\right| \begin{matrix}2\\1 \\0 \end{matrix}\right ]\)
Now we can see that the last every elements are zero, which shows
0 = 0
So the system of equation have infinitely many solutions.
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The complete question is:
Attempt to solve the system
-x(1) + 3x(2) - 2x(3) = 4,
-x(1) + 4x(2) − 3x(3) = 5,
-x(1) + 5x(2) - 4x(3) = 6,
using gaussian elimination and explain why this system must have infinitely many solutions.
HELP PLEASE
Choose the equation that Choose the equation that represents a line that passes through points (-6, 4) and (2,0)
A. x + 2y = 2
B. 2x - y = -16
C. x + 2y = -8
D. 2x + y = 4
Answer:
A
Step-by-step explanation:
m = (0 - 4) / [(2 - (-6)]
= -4 / 8
= -1/2
Use (-6, 4) to find for b:
y = mx + b
4 = -1/2 (-6) + b
4 = 3 + b
4 - 3 = b
1 = b
Therefore the equation is:
y = mx + b
y = -1/2 x + 1
or 2y = -x + 2
Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given frequency distribution. Also identify the number of individuals included in the summary.
Age (yr) when award was won Frequency
15-24 27
25-34 33
35-44 14
45-54 4
55-64 6
65-74 1
75-84 1
Lower class limits are 15, 25, 35, 45, 55, 65, 75, Upper class limits are 24, 34, 44, 54, 64, 74, 84, Class width are 10 (all classes have a width of 10), Class midpoints are 19.5, 29.5, 39.5, 49.5, 59.5, 69.5, 79.5, Class boundaries are [15, 25), [25, 35), [35, 44), [45, 54), [55, 64), [65, 74), [75, 84) and Number of individuals included in the summary is 76.
Here are the details for the given frequency distribution:
Lower class limits are the least number among the pair
Here, Lower class limits are 15, 25, 35, 45, 55, 65, 75 respectively.
Upper class limits are the greater number among the pair
Here, upper limit class are 24, 34, 44, 54, 64, 74, 84 respectively.
Class width is the difference between the Lower class limits and Upper class limits which is 10 (all classes have a width of 10).
Class midpoints is the middle point of the lower class limits and Upper class limits which is 19.5, 29.5, 39.5, 49.5, 59.5, 69.5, 79.5 respectively.
Class boundaries are the extreme points of the classes which are [15, 25), [25, 35), [35, 44), [45, 54), [55, 64), [65, 74), [75, 84) respectively.
Number of individuals = 27 + 33 + 14 + 4 + 6 + 1 + 1
= 76
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Rewrite 2/5 : 1/20
as a unit rate.
A. 8:1
B. 40:5
C. 5:40
D. 40:1
Answer:
A - 8:1
Step-by-step explanation:
2/5:1/20
cross multiply
40:5
8:1
Answer:
8:1
Step-by-step explanation:
Find the equation of the circle whose center and radius are given.
center ( -2, -5), radius = 1
Answer:
(x + 2)^2 + (y + 5)^2 = 1
Step-by-step explanation:
Since this circle is centered at (-2, -5), we have to add values within the squares. The standard form of a circle equation is:
(x - h)^2 + (y - k)^2 = r^2
So -2 is h and -5 is k. Substituting that in we get:
(x + 2)^2 + (y + 5)^2 = r^2
We are given the radius is 1, and one squared is one, so the final equation is:
(x + 2)^2 + (y + 5)^2 = 1
Suppose you have entered 79-mile biathlon that consists of a run and a bicycle race. During your run, your average velocity is miles 5per hour, and during your bicycle race, your average velocity is 23 miles per hour. You finish the race in 5 hours. What is the distance of the run? What is the distance of the bicycle race?
Answer:
The distance of the run is 10 miles
The distance of the bicycle race is 69 miles
Step-by-step explanation:
Let:
r = the distance for the run79 - r = the distance for the bicycle racet = the time of the run5 - t = the time of the bicycle raceThe run: r = 5t
The bicycle race: 79 - r = 23(5 - t)
Simplify the bicycle race:
79 - r = 115 - 23t-r = 36 - 23tr = 23t - 36Now we have two equations set up for r
r = 5tr = 23t - 36We know that r = r, so 5t must equal 23t - 36
5t = 23t - 365t + 36 = 23t36 = 18tt = 2Now we know that the run took 2 hours.
Plug it back into the equation for the run to find the distance for the run
r = 5tr = 5(2)r = 10The run is 10 miles
To solve for the bicycle race, we simply subtract 10 from 79, because we know that the two distances combined are 79.
79 - 10 = 69The bicycle race is 69 miles.
-Chetan K
Answer:
run: 10 milesbike race: 69 milesStep-by-step explanation:
Let r represent the distance run. Then 79-r is the distance biked. The total time is ...
time = distance/speed
5 = (r/5) +(79-r)/23 . . . . sum of time running and time biking
575 = 23r +5(79 -r) . . . . multiply by 115
180 = 18r . . . . . . . . . . . . . subtract 395
10 = r . . . . . . . . . . . divide by 18
79-r = 69 . . . . . . distance biking
The distance of the run is 10 miles; the bicycle race is 69 miles.
PLEASE PLEASE HELP I NEED TO ACE THIS
angle c = ___ degrees
Angle D = ABC arc / 2
x + 100 = ABC arc / 2
ABC arc = 2 × ( x + 100 )
ABC arc = 2x + 200 ( ♡ )
_________________________________
Angle B = ADC arc / 2
3x = ADC arc / 2
ADC arc = 2 × 3x
ADC arc = 6x ( ☆ )
_________________________________
ABC arc + ADC arc = 360
( ♡ ) , ( ☆ ) :
( 2x + 200 ) + ( 6x ) = 360
8x + 200 = 360
8x = 360 - 200
8x = 160
x = 160/8
x = 20
____________________________
Thus :
Angle A = 5(20) - 3 = 97 degrees
Angle B = 3(20) = 60 degrees
Angle D = 20 + 100 = 120 degrees
____________________________
Sum of the interior angles of any four-sides figures are equal 360 degrees ,
Thus :
Angle A+Angle B+Angle C+Angle D = 360
97 + 60 + Angle C + 120 = 360
Angle C + 120 + 157 = 360
Angle C + 277 = 360
Angle C = 360 - 270 - 7
Angle C = 90 - 7
Angle C = 83 degrees
this polygon has an area of 72 square centimeters what is the height of the parallelogram
Imogen bought number of invitations
Answer:
Step-by-step explanation:
I am sorry but please give detailed question
Solve the inequality below.
8p>p+63
Answer:
7
Step-by-step explanation:
8p + p = 63
9p = 63
p = 63/9 = 7
Answer:
the answer is "n>9" which means (10,infinity)
Step-by-step explanation:
8p>p+63
C.L.T
8p-p>63
7p>63
divide both sides by 7
p>9
Question, 40 points
What are the endpoint coordinates for the midsegment of △PQR that is parallel to PR¯¯¯¯¯?
Enter your answer, as a decimal or whole number, in the boxes.
( , ) and ( , )
Answer:
mPR = (-3.5, 0.5)
mQR= (-1,-0.5)
Step-by-step explanation:
Suppose your car has hhh liters of engine oil in the morning. During the day, some oil may have leaked, you may have added more oil, or both. The oil level in the evening is ggg liters.
Answer:
g = (h+a) - l
None of them
Step-by-step explanation:
Suppose your car has h liters of engine oil in the morning. During the day, some oil may have leaked, you may have added more oil, or both. The oil level in the evening is g liters. Which of the following expressions always represents how far away the new oil level is from the previous oil level? H+G lGl none of them
Let
h = liters of oil in the morning
l= liters that has leaked
a= liters that were added during the day
g= amount of liters at the end of the evening
Total liters of oil in the evening= (litres of oil in the morning + litres of oil added during the day) - litres of oil that leaked
Substituting each variable into the formula, we have
g = (h+a) - l
A line has a slope of -3/2 and has a y-intercept of 3.
What is the x-intercept of the line?
O-3
O-2
O 2
O 3
Answer:
c
Step-by-step explanation:
the answer is 2
Answer:Your answer would be C.2
The rate at which sand is poured into a bag is modeled by the function r given by r(t)=15t−2t2, where r(t) is measured in milliliters per second and t is measured in seconds after the sand begins pouring. How many milliliters of sand accumulate in the bag from time t=0 to time t=2 ?
74/5 milliliters of sand accumulate in the bag from time t=0 to time t=2.
Given that:
The rate at which sand is poured is r(t)
The function r(t) is defined as;
r(t) = 15t -\(2t^2\)
The accumulation in the bag from time t=0 to time t=2 is calculated as:
r = \(\int_0^2 ( 15t -2t^2) dt\)
Using the limits:
=\([\dfrac{15t^2}{2} - \dfrac{2t^3}{3}]_0^2\)
=\(\dfrac{15(2) ^2}{2} - \dfrac{2(2)^3}{3} - (0-0)\)
\(30 - \dfrac{16}{3}\)
= \(\dfrac{74}{3}\)
Thus, \(\dfrac{74}{3}\) milliliters of sand accumulate in the bag from time t=0 to time t=2.
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A customer in Indiana buys 4 bags of Gone Bananas treats for $8.99 each. The sales tax in Indiana is 7%. What is the total cost of the order?
4 x 8,99 x 1,07 = £38,48
Chris signed-up for an experiment. The experimenter indicated that Chris would be placed into a group with nineteen other students based on a random number Chris received from the experimenter. The experimenter was most likely conducting ________________________-.
The experimenter was most likely conducting a randomized controlled trial, also known as a randomized experiment.
In this type of experiment, participants are randomly assigned to different groups, such as an experimental group or a control group, to ensure that any observed effects can be attributed to the intervention being tested rather than other factors.
In this case, the experimenter is using a random number to assign Chris to a group with nineteen other students, which suggests that there may be multiple groups involved in the experiment. This type of design is often used in scientific research to test the effectiveness of a new treatment, intervention, or program.
Randomized controlled trials are considered the gold standard in research design because they provide strong evidence for causal relationships between variables. By randomly assigning participants to different groups, researchers can control for confounding variables and ensure that any observed differences between groups are due to the intervention being tested.
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i need help with finding the equations for each response
Answer:
The reason it doesn't is because it's parallel and vertical, which you should know
Step-by-step explanation:
A. y = -1
B .y=2x+3,‘cos k=2
C. X= 3
D. y=-\(\frac{1}{2}\)x-\(\frac{1}{2}\),'cos k * 2=-1,k = -1/2
write the prime factorization of 98
Answer:
2 * 7^2
Step-by-step explanation:
98 /2 = 49
49 / 7 = 7
2 * 7 * 7 = 98
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what is the value of expression below when x=2? 2x+6
Answer:
10
Step-by-step explanation:
2(2) + 6
4 + 6
10
Answer:
10
Step-by-step explanation:
let a ∈ rn×n be a symmetric nonsingular positive semi-definite matrix, b ∈ rn, and c ∈r. show that ∫ x∈rn exp{−1 2 xt ax −xt b −c}dx
The integral is to zero for a symmetric nonsingular positive semi-definite matrix A, and the expression is
∫ x∈\(R^n\) exp\((-1/2 x^T A x - x^T b - c) dx\) = 0.
The integral ∫ x∈R^n exp(-1/2 x^T A x - x^T b - c) dx, where A is a symmetric nonsingular positive semi-definite matrix, b ∈ R^n, and c ∈ R, can be evaluated.
To evaluate this integral, we can make use of the Gaussian integral formula for multi-dimensional integrals. The formula states that:
∫ exp\((-1/2 x^T C x) dx = ((2π)^(n/2)) / sqrt(det(C)),\)
where C is a positive definite matrix.
In our case, A is a symmetric positive semi-definite matrix. Since A is positive semi-definite, we can write it as A = Q^T D Q, where Q is an orthogonal matrix and D is a diagonal matrix with non-negative eigenvalues. As A is symmetric and positive semi-definite, its eigenvalues are non-negative.
Now, we can rewrite the integral as:
∫ exp\((-1/2 x^T A x - x^T b - c) dx = exp(-c) ∫ exp(-1/2 x^T A x - x^T b) dx.\)
Let's complete the square inside the exponent to further simplify the integral. We can rewrite the exponent as:
\(-1/2 x^T A x - x^T b = -1/2 (x^T A x + 2 x^T (A^-1 b)),\)
where A^-1 is the inverse of A.
Now, let's substitute y = x + A^-1 b. We have dy = dx, and the integral becomes:
exp(-c) ∫ exp(-1/2 y^T A y) dy.
At this point, we can apply the Gaussian integral formula mentioned earlier, with C = A. Therefore, the integral becomes:
exp(-c) ((2π)^(n/2)) / sqrt(det(A)).
Since A is positive semi-definite, its determinant is non-negative. So, we have sqrt(det(A)) = sqrt(0) = 0 for a positive semi-definite matrix A.
Therefore, the integral evaluates to zero for a symmetric nonsingular positive semi-definite matrix A, and the expression becomes:
∫ x∈R^n exp(-1/2 x^T A x - x^T b - c) dx = 0.
Thus, the integral is equal to zero.
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What does the difference scheme 2 [ƒ(z+3h) + ƒ(z − h) — 2ƒ(z)] approximate and give its error order?
The difference scheme 2 [ƒ(z+3h) + ƒ(z − h) — 2ƒ(z)] approximates the second derivative of ƒ(z) with respect to z, and its error order is O(h²).
The given difference scheme is an approximation of the second derivative of ƒ(z) using a finite difference method. By evaluating the scheme at different points, specifically z+3h, z − h, and z, and applying the corresponding coefficients, the second derivative can be approximated. The coefficient values in the scheme are derived based on the Taylor series expansion of the function.
The error order of the scheme indicates how the error in the approximation behaves as the step size (h) decreases. In this case, the error order is O(h²), which means that as the step size is halved, the error decreases by a factor of four. It implies that the approximation becomes more accurate as the step size becomes smaller.
It's important to note that the error order is an estimate and may vary depending on the specific properties of the function being approximated and the choice of difference scheme.
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A student can type 2 3 of a page in 1 5 hour. How many pages can the student type in an hour?
Need this asap
Answer:
2/15
Step-by-step explanation:
the mean of a distribution is defined as the data value where 50% of the data is above and 50% is below. group of answer choices true false
FALSE, it is not the mean but the median of a distribution which is defined as the data value where 50% of the data is above and 50% is below.
The median denotes the point at which 50% of data values are higher and 50% are lower. As a result, it is the data's midpoint. In a symmetrical distribution, the median is always the midpoint, resulting in a mirror image with the median in the center.
The median is the number in the middle of a sorted, ascending or descending list of numbers, and it might be more descriptive of the data set than the average.
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Is a graph a function or not?
chaslot, g., winands, m., herik, h., uiterwijk, j., and bouzy, b. progressive strategies for monte-carlo tree search. new mathematics and natural computation, 04: 343–357, 11 2008. doi: 10.1142/s1793005708001094.
The given citation is a reference to a research paper titled "Progressive Strategies for Monte-Carlo Tree Search" by Chaslot, G., Winands, M., Herik, H., Uiterwijk, J., and Bouzy, B.
The paper was published in the journal "New Mathematics and Natural Computation" in November 2008.
Here are the details of the citation:
Authors: G. Chaslot, M. Winands, H. Herik, J. Uiterwijk, and B. Bouzy
Title: Progressive Strategies for Monte-Carlo Tree Search
Journal:
Year: 2008
Volume: 04
Pages: 343–357
DOI: 10.1142/s1793005708001094
The DOI (Digital Object Identifier) provided is a unique identifier for the paper and can be used to access the paper online, usually through a database or publisher's website.
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PLEASE ANSWER FAST!!!
There are 3 blue marbles and 5 black marbles. Find the probability of drawing 2 blue
marbles.
Answer: 1/4 chance
Step-by-step explan1ation:
5+3=8
8 / 2 = 1/4
The parent function f(x) = W is translated 8 units left.
reflected across the x-axis, and stretched horizontally by a factor of 3.
The graph's curve "moves to the left/right/up/down," "expands or compresses," or "reflects" when a function is transformed. f(x) = 3x+8
What is meant by function?A function is defined as a relationship between a set of inputs that each have one output. A function is a relationship between inputs in which each input is related to exactly one output. Every function has a domain and a codomain, as well as a range.
The graph's curve "moves to the left/right/up/down," "expands or compresses," or "reflects" when a function is transformed. For example, the graph of the function f(x) = x2 + 3 is generated by simply pushing the graph of the function g(x) = x2 up by 3 units.
Therefore,
f(x) = |x|
y = f(x) + C C < 0 moves it down
y = |x| 8 for shifting down 8
y = f(x + C) C > 0 moves it left
y = Cf(x) C > 1 stretches it in the y-direction
y = 3x+8 to stretch it 2 vertically
y = −f(x) Reflects it about x-axis
y = 3x+8
Hence, The graph's curve "moves to the left/right/up/down," "expands or compresses," or "reflects" when a function is transformed. f(x) = 3x+8
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researchers examined the efficacy of 4 different treatments (a, b, c, and d) on the average change in c-reactive protein (crp) levels in a random sample of 120 adults (30 per treatment group). a crp change of 0 indicates no change in crp levels after treatment. a positive crp change ( > 0) indicates a decrease in crp levels after treatment and a negative crp change (< 0) indicates an increase in crp levels after treatment. they obtained the following results (some of the values have been hidden):
MAIN ANSWER :the total degree of freedom is (n-1)
120-1=119
SUPPORTING ANSWER:
Degrees of freedom refer to the maximum number of logically independent values in a data sample, which are values with the freedom to vary. If there is an outstanding requirement of the data sample, specific data sample items must be chosen once the degrees of freedom quantity has been selected.
BODY OF THE ANSWER
given that total no of patients are n=120
different types of treatement are 4
the total degree of freedom is (n-1)
120-1=119
final answer :therefore final answer is 119.
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The total degree of freedom is (n-1) that is 120-1=119
What is degree of freedom?
Degrees of freedom refer to the maximum number of logically independent values in a data sample, which are values with the freedom to vary. If there is an outstanding requirement of the data sample, specific data sample items must be chosen once the degrees of freedom quantity has been selected.
What is random sample?
In statistics, a simple random sample is a subset of people chosen at random from a larger group, all of whom were chosen with the same probability. It is a method of choosing a sample at random.
Given that total no of patients are n=120
Different types of treatment are 4
The total degree of freedom is (n-1)
120-1=119
Therefore final answer is 119.
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