Write the linear equation in slope-intercept form:
(-4 6); slope=-3/4

a. (x+7)(x-1)=33

b. x²+6x-7=33

c. x= -4 or 10

d. 11 by 3

Answer:

42.83

Step-by-step explanation:

add all the numbers and divide by how many their are

Answer: y = 15 - 3x

Step-by-step explanation:

Simply substract 2x from both sides and you will be left with y = 15 - 3x.

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Answer:

\( \fbox{y = - 3x + 15}\)

Step-by-step explanation:

Given:

\(3x+y=15 \)

To find:

y =?

Solution:

We have to solve for y so subtract 3x from both side,

\( \cancel{3x}+y -\cancel{ 3x}=15 - 3x \)

can be written in the form of y =mx+c

\(y = - 3x + 15\)

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Answer:

+

Step-by-step explanation:

++ = +

+- = -

-+ = -

-- = +

Example:

-1 x -1 = 1

1 x -1 = -1

As per the combination method, there are 1260 ways in which a team of 10 students with 6 boys and 4 girls can be formed from a middle school classroom containing 15 students with 9 boys.

To solve this problem, we need to use the concept of combinations. A combination is a way of selecting items from a larger group where the order of selection does not matter. In this problem, we are selecting a team of 10 students, and the order in which we select the students does not matter.

Using this formula, we can find the number of ways to select 6 boys from a group of 9 as:

⁹C₆ = 9! / (6! x (9-6)!) = 84

Similarly, the number of ways to select 4 girls from a group of 6 is:

⁶C₄ = 6! / (4! x (6-4)!) = 15

To find the total number of ways to form a team of 10 students with 6 boys and 4 girls, we need to multiply the number of ways to select 6 boys and 4 girls. This is because the selection of boys and girls is independent of each other, and we can choose them in any order.

Therefore, the total number of ways to form a team of 10 students with 6 boys and 4 girls is:

84 x 15 = 1260

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Answer:36.555

Step-by-step explanation:7.535+29.02=36.555

Answer:

36.555

Step-by-step explanation:

first off, let's notice that the y-coordinates are the same for both points, meaning is really just a horizontal line, and its slope is 0, however, let's go through the rigamarole

\((\stackrel{x_1}{5}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-3}-\stackrel{y1}{(-3)}}}{\underset{\textit{\large run}} {\underset{x_2}{8}-\underset{x_1}{5}}} \implies \cfrac{-3 +3}{3} \implies \cfrac{ 0 }{ 3 } \implies \text{\LARGE 0}\)

The correct choice for the sentence is option c: "Their, to lose."

In the sentence, referring to multiple museums, the possessive pronoun "their" is used to indicate ownership, and the phrase "to lose" appropriately conveys the risk faced by the museums.

The subject of the sentence is "Museums," which is a plural noun. Since the sentence is discussing multiple museums, the possessive pronoun "their" is the correct choice to show ownership. Using "their" indicates that the museums collectively possess something, in this case, their fickle goodwill.

Additionally, the phrase "to lose" accurately portrays the risk faced by the museums. It implies that the museums are at risk of losing their fickle goodwill due to factors like the fickleness of governments and the public. Therefore, option c, "Their, to lose," provides the appropriate usage of the possessive pronoun and conveys the intended meaning of the sentence.

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Answer:

88

Step-by-step explanation:

4 pints = 8 cups

3 cups = 3 cups

8 cups + 3 cups = 11 cups

11 cups = 88 fl oz

Answer:

64 + 24 = 88 oz

Step-by-step explanation:

1 pint = 16 oz  (4 x 16 = 64)

1 cup = 8 oz (3 x 8 =24)

\( - 5 {m}^{6} + ( {4m}^{6} - 6n)\)

\( - 5 {m}^{6} + {4m}^{6} - 6n\)

\( (- 5 {m}^{6} + {4m}^{6}) - 6n\)

\( - {m}^{6} - 6n\)

Answer:

c

Step-by-step explanation:

Since the figures are similar then the ratios of corresponding sides are equal, that is

\(\frac{AD}{WZ}\) = \(\frac{CD}{YZ}\) , substitute values

\(\frac{10}{46}\) = \(\frac{5}{YZ}\) ( cross- multiply )

10YZ = 230 ( divide both sides by 10 )

YZ = 23 → c

20+7x

just use the distributive property on 2(5+3x) then add x and 10

When we want to find all the points on a surface where the tangent plane is horizontal, we are essentially looking for the points where the surface has a horizontal slope. The points on the surface where the tangent plane is horizontal are the points (0, 0, 0).

To find these points, we can use the partial derivative test. First, we calculate the partial derivatives of the surface function with respect to x and y, and set them equal to zero. These equations will give us the x and y values of the points where the slope is zero.

Next, we plug these values back into the original surface function to obtain the z-coordinate of the points. These are the points on the surface where the tangent plane is horizontal.

For example, let's consider the surface function z = x^2 + y^2. To find the points on this surface where the tangent plane is horizontal, we need to find the x and y values where the partial derivatives of z with respect to x and y are equal to zero.

Taking the partial derivative of z with respect to x, we get:

∂z/∂x = 2x

Setting this equal to zero, we get: 2x = 0

Solving for x, we get x = 0.

Taking the partial derivative of z with respect to y, we get:

∂z/∂y = 2y

Setting this equal to zero, we get: 2y = 0

Solving for y, we get y = 0.

Therefore, the points on the surface where the tangent plane is horizontal are the points (0, 0, 0).

In summary, when we want to find all the points on a surface where the tangent plane is horizontal, we can use the partial derivative test and set the partial derivatives of the surface function with respect to x and y equal to zero. We can then plug these values back into the original surface function to obtain the z-coordinate of the points.

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Answer:

go to this it should explain to u

Step-by-step explanation:

https://www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-geometry/cc-7th-angles/v/complementary-and-supplementary-angles

a. To calculate the lower control limit, multiply the average range by the factor labeled "A3" in the table.
b. To compute the control chart limits (3 sigma) use the table "Factors for Computing Control Chart Limits".

First, you mentioned that Autopitch executive Neil Geismar takes samples of 8 devices at a time. This means that the sample size (n) is 8.

Next, you mentioned the term "average range". The range is the difference between the highest and lowest values in a sample. To calculate the average range, you need to take multiple samples and calculate the range for each sample. Then, you average the ranges together.

Once you have the average range, you can use the factors from the table to calculate the control chart limits. The control chart limits (3 sigma) are calculated by multiplying the average range by the appropriate factor from the table.

Since you mentioned the term "highest quality", I assume you want to calculate the upper control limit. To do this, you multiply the average range by the factor labeled "A2" in the table.

Similarly, to calculate the lower control limit, you multiply the average range by the factor labeled "A3" in the table.

Remember to use the 3 sigma limits for a control chart, which means you multiply the average range by 3.

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Answer: Factoring a polynomial is the process of decomposing a polynomial into a product of two or more polynomials.

Answer:

1 83/99

Step-by-step explanation:

This is how u do it

Answer:

\(\frac{183333333333}{100000000000}\)

Step-by-step explanation:

1.83333333333 as fraction

we need to divide the fraction by the number of digits it have before decimal point to convert it to fraction

here we have 11 digits before decimal point so we need to divide it by 100000000000

so

\(\frac{183333333333}{100000000000}\)

The solution of the given system of equations in question is a=-8,b=-8.

An equation usually consists of equality of two mathematical expressions. Let it be

A = B

. If we take them to be equal to third variable, then:

A = B = C

type of equation is obtained.

We can then take it as system of two equations as:

A = C\\ B=C

Solution to this system will give us the solution to the considered equation.

Solution to an equation is finding values of the variable included in the considered equation for which the equation considered evaluates to be true.

Given that;

6a-5b=-8...1

2a+5b=-16...2

Now, in equation 1

6a=-8+5b

a=-8+5b/6

Substituting the value of a in equation 2

2(-8+5b/6)+5b= -16

-8+5b/3=-16

-8+5b=-48

5b=-40

b=-8

6a-5*-8=-8

6a+40=-8

6a=-48

a=-8

Therefore, the answer of system of equations will be a=-8,b=-8

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Answer:

We found that translations have the following three properties: line segments are taken to line segments of the same length; angles are taken to angles of the same measure; and. lines are taken to lines and parallel lines are taken to parallel lines.

Step-by-step explanation:

Step-by-step explanation:

2x+3>4x-8

or, 3+8>4x-2x

or, 11>2x

or, 11/2 > x

or, x < 11/2

By applying the concept of the dependent events, it can be concluded that the probability of drinking alcohol or being over 21 years old is 0.24.

Independent events occur if the first event does not affect the second event.

P(A ∩ B) = P(A) * P(B)

Dependent events are those which depend upon what happened before. These events are affected by the outcomes that had already occurred previously.

P(A ∩ B) = P(A) * P(B|A)

A = event that a student is over 21 years old.

B = event that a student drinks alcohol.

Probability of a college student drinking alcohol = 0.6

Probability of event A: P(A) = 30% = 0.3

Given that the student is over 21 years old, the probability of drinking alcohol, P(B|A) = 0.8

The probability of drinking alcohol or being over 21 years old is a condition that makes events A and B dependent:

P(A ∩ B) = P(A) * P(B|A)

              = 0.3 * 0.8

              = 0.24

Thus, the probability of drinking alcohol or being over 21 years old is 0.24.

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The rate at which the height of the pile is increasing when it is 10 ft high is approximately 3.819 ft/min.

Given the following data: Gravel is being dumped from a conveyor belt at a rate of 30 ft3/min.

Its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal.

The pile is 10 ft high.

To determine how fast the height of the pile is increasing, we need to differentiate the formula for the volume of a cone with respect to time.

We know that the volume of a cone is given by: \(V = (1/3)πr²h\)

We are given that the base diameter and the height of the cone are always equal, so we can write: r = (d/2)and h = d

where d is the diameter of the base of the cone.

The volume of the cone is given by: V = (1/3)π(d/2)²d

Simplifying, we get:\(V = (1/12)πd³\)

Differentiating both sides with respect to time, we get:

dV/dt = (1/4)πd² (dd/dt)

We are given that dV/dt = 30 ft³/min, and we want to find dd/dt when h = 10 ft.

Substituting V = (1/3)π(10/2)²(10)

= (1/3)π(25)(10)

= (250/3)π and d = 10,

we get:

30 = (1/4)π(10²)(dd/dt)

Simplifying, we get:

dd/dt = 12/π

The rate at which the height of the pile is increasing when it is 10 ft high is approximately 3.819 ft/min.

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The value of x , y and z in the parallel line is 50 degrees.

When parallel lines are crossed by a transversal line, angle relationships are formed such as vertically opposite angles, alternate interior angles, alternate exterior angles, adjacent angles, corresponding angles etc.

Therefore, let's use the angle relationships to find the angle, x, y and z as follows:

Therefore,

x = 360 - 310(sum of angles in a point)

x = 50 degrees

Therefore,

x = y(alternate interior angles)

Alternate interior angles are congruent.

Hence,

y = 50 degrees

Therefore,

x = z(alternate interior angles)

z = 50 degrees.

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Based on the projected sales of 1,400 total vehicles for the next year, the demand for each season can be determined. The demand for each season is as follows: 350 vehicles in winter, 350 vehicles in spring, 175 vehicles in summer, and 525 vehicles in fall.

To calculate the demand for each season, we can use the past sales data as a reference. In the past, the dealership sold an average of 1,200 vehicles each year. However, in the past two years, the sales figures were 220 and 260 in winter, 350 and 300 in spring, 150 and 160 in summer, and 300 and 660 in fall.

To estimate the demand for each season based on the projected sales of 1,400 vehicles for the next year, we can calculate the proportion of each season's sales compared to the total sales in the past. This gives us the following estimates: 350 vehicles in winter (25% of 1,400), 350 vehicles in spring (25% of 1,400), 175 vehicles in summer (12.5% of 1,400), and 525 vehicles in fall (37.5% of 1,400).

These estimates are based on the assumption that the sales distribution in the future will be similar to the past trends. However, it's important to note that actual market conditions and other factors may influence the demand for each season, so these estimates should be used as a rough guide and may require adjustment based on specific circumstances.

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The sample size used to construct this interval is approximately 13.

To determine the sample size used to construct a 95% confidence interval, we need to use the formula:

n = (Z * σ / E)^2

Where:

n represents the sample size,

Z is the Z-score corresponding to the desired confidence level (in this case, for 95% confidence, Z = 1.96),

σ is the estimated standard deviation of the population, and

E is the margin of error.

In this case, since we are given a confidence interval for a proportion (p), we can use the formula for estimating the standard deviation of a proportion:

σ = sqrt[(p * (1 - p)) / n]

Here, we don't have the value of p, so we will assume the worst-case scenario where p is 0.5. This assumption ensures the maximum sample size needed.

Let's calculate the sample size:

σ = sqrt[(0.5 * (1 - 0.5)) / n]

Plugging in the values, we have:

1.96 * sqrt[(0.5 * (1 - 0.5)) / n] = 0.84 - 0.56

Simplifying further:

1.96 * sqrt[(0.5 * 0.5) / n] = 0.28

Squaring both sides:

3.8416 * [(0.5 * 0.5) / n] = 0.0784

Simplifying:

[(0.5 * 0.5) / n] = 0.0204

Multiplying both sides by n:

0.5 * 0.5 = 0.0204 * n

0.25 = 0.0204 * n

Dividing both sides by 0.0204:

n = 0.25 / 0.0204

n ≈ 12.25

Since the sample size must be a whole number, we round up to the nearest whole number.

Therefore, the sample size used to construct this interval is approximately 13.

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Answer:

-3g-4

Step-by-step explanation:

Let's simplify step-by-step.

−2g+7−(g+11)

Distribute the Negative Sign:

=−2g+7+−1(g+11)

=−2g+7+−1g+(−1)(11)

=−2g+7+−g+−11

Combine Like Terms:

=−2g+7+−g+−11

=(−2g+−g)+(7+−11)

=−3g−4

Answer:

6g

Step-by-step explanation:

ll + g = 11g

-2g + 7 = 5g

11g - 5g = 6g