Ximena launches a toy rocket from a platform. The height of the rocket in feet is given by ℎ(�)=−16�2+40�+96h(t)=−16t 2 +40t+96 where �t represents the time in seconds after launch. What is the appropriate domain for this situation?

Answer:

1. C  2. A

Step-by-step explanation:

your welcome =0 (=

Answer:

The length of a is equal to 14.9.

The angle measure of b is equal to 71°.

The length of c is equal to 25.5.

General Formulas and Concepts:
Pre-Calculus

Law of Sines:
\(\displaystyle \bold{ \frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c} }\)

Step-by-step explanation:

Step 1: Define

Identify given from triangle.

Length corresponding with x°: 14.9

Other given angle: 71°

Length corresponding with 71°: 25.5

Step 2: Find Values

∴ we have completed the expression using Law of Sines.

---

Topic: Precalculus

Unit: Trigonometry

Answer:

J=17

Step-by-step explanation:

J/-2 + 7 = -12

multiply both sides by -2 to cancel out the J/-2 and turn it into J + 7 = 24

transfer the 7 to the other side to get J = 24 - 7

J = 17

hopefully this helps.

To find out how many cans of tennis balls the factory packs for the order, we can divide the total number of tennis balls by the number of tennis balls packed into each can.

Given: Total number of tennis balls = 94,500. Number of tennis balls packed into each can = 3. To determine the number of cans of tennis balls the factory packs for the order, we divide the total number of tennis balls by the number of tennis balls packed into each can. Calculation: Number of cans = Total number of tennis balls / Number of tennis balls packed into each can. Number of cans = 94,500 / 3. To find out how many cans of tennis balls the factory packs for the order, we can use the given information. First, we need to divide the total number of tennis balls by the number of tennis balls packed into each can. In this case, there are 94,500 tennis balls and each can contains 3 tennis balls. Dividing 94,500 by 3 gives us the number of cans required. Performing the calculation, we get: Number of cans = 94,500 / 3. Simplifying the expression, we find that the factory needs to pack 31,500 cans of tennis balls for the order.

The factory needs to pack a total of 31,500 cans of tennis balls for the order.

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Answer:g maybe

Step-by-step explanation:

Answer:

Hats cost $15, T-Shirts cost $25, Jackets cost $45

If this was helpful please mark brainliest, have a great day!

Reason:

An increase of 95% will involve the multiplier 1.95

Think of it like saying 100% + 95% = 1 + 0.95 = 1.95

Therefore,

1.95*3.50 = 6.825 = 6.83 dollars

Answer:33%

Step-by-step explanation:

Answer:

33%

Step-by-step explanation:

I hope it helps!!:)

Answer:14.7 games

Step-by-step explanation:

0.70 times 21 = 14.7

Answer:

Step-by-step explanation:

Answer:

B.

Step-by-step explanation:

The graph shows a linear function that is extending infinitely in both directions.

In other words, the domain is all real numbers.

As inequalities, this is:

\(-\infty< x<\infty\)

Therefore, the correct answer is B.

Answer:

Step-by-step explanation:

The forecast for the next period using the following weights: 0.3, 2, 0.5 is Option d. 421.

To compute the forecast for the next period, we'll use the weighted moving average (WMA) formula.WMA formula:

WMA = W1Yt-1 + W2Yt-2 + ... + WnYt-n

Where, WMA is the weighted moving average

W1, W2, ..., Wn are the weights (must sum to 1)

Yt-n is the demand in the n-th period before the current period

As we know Month 1 – 381, Month 2-366, and Month 3 - 348.

Weights: 0.3, 2, 0.5

We'll compute the forecast for the next period (month 4) using the data:

WMA = W1Yt-1 + W2Yt-2 + W3Yt-3WMA

= 0.3(381) + 2(366) + 0.5(348)WMA

= 114.3 + 732 + 174WMA

= 1020.3

Therefore, the forecast for the next period is 1020.3, which rounds to 421. Hence, option d is correct.

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The correct option regarding whether the table represents a proportional relationship is:

The relationship is proportional because the ratio of m to k is constant.

A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:

y = kx

In which k is the constant of proportionality.

In this problem, the ratio of m to km is given as follows:

k = 11/17.699 = 26/41.834 = 34/54.706 = 0.6215.

Since the values are equal, the correct option is:

The relationship is proportional because the ratio of m to k is constant.

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i. The Fourier transform of (t - 2) - 38(t - 3) is [(jw)^2 + 38jw]e^(-2jw). ii. The Fourier transform of e^(-2t)u(t) is 1/(jw + 2). iii. The Fourier transform of e^(-3t+12)u(t-4) can be obtained using the result of ii. as e^(-2t)u(t-4)e^(12jw). iv. The Fourier transform of e^(-2|t|)cos(t) is [(2jw)/(w^2+4)].

i. To find the Fourier transform of (t - 2) - 38(t - 3), we can use the linearity property of the Fourier transform. The Fourier transform of (t - 2) can be found using the time-shifting property, and the Fourier transform of -38(t - 3) can be found by scaling and using the frequency-shifting property. Adding the two transforms together gives [(jw)^2 + 38jw]e^(-2jw).

ii. The function e^(-2t)u(t) is the product of the exponential function e^(-2t) and the unit step function u(t). The Fourier transform of e^(-2t) can be found using the time-shifting property as 1/(jw + 2). The Fourier transform of u(t) is 1/(jw), resulting in the Fourier transform of e^(-2t)u(t) as 1/(jw + 2).

iii. The function e^(-3t+12)u(t-4) can be rewritten as e^(-2t)u(t-4)e^(12jw) using the time-shifting property. From the result of ii., we know the Fourier transform of e^(-2t)u(t-4) is 1/(jw + 2). Multiplying this by e^(12jw) gives the Fourier transform of e^(-3t+12)u(t-4) as e^(-2t)u(t-4)e^(12jw).

iv. To find the Fourier transform of e^(-2|t|)cos(t), we can use the definition of the Fourier transform and apply the properties of the Fourier transform. By splitting the function into even and odd parts, we find that the Fourier transform is [(2jw)/(w^2+4)].

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Therefore , the solution of the given problem of unitary comes out to be each asset class as part of the diversification plan.

By combining the information obtained using this nanosection technique with all variable additional data from two individuals who used a specific strategy, the task can be completed. Simply put, this mean that, if the desired outcome materialises, either the specified entity will be known or, actually, the colour from both enormous processes will be skipped. For forty pens, a refundable charge of Rupees ($1.01) might be required.

Here,

The next two are methods for reducing the danger associated with investing out of the four you offered:

Dollar-cost averaging is the term used to describe this method of spreading investments out over time. Regardless of the investment's price, it entails making a set amount of investments at regular intervals over a length of time.

Spread your investments across various asset classes (such as stocks, bonds, real estate, etc.) and/or various companies within each asset class as part of the diversification plan.

Since currency values can be influenced by a number of variables and are sometimes unpredictable, investing in a particular currency (such as the British pound) is not always a risk management plan.

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The task is to find the probability of both X being greater than 1 and Y being greater than 1. Additionally, we need to determine the marginal probability density functions fX(x) and fY(y) for the random variables X and Y. Finally, we need to determine whether X and Y are independent.

To find the probability P(X > 1 and Y > 1), we need to consider the joint probability distribution of X and Y. This involves determining the region of the joint probability density function where both X and Y are greater than 1 and calculating the probability within that region.

To find the marginal probability density function fX(x), we integrate the joint probability density function over the range of Y. Similarly, to find fY(y), we integrate the joint probability density function over the range of X.

If X and Y are independent, then the joint probability density function would be equal to the product of the marginal probability density functions, i.e., fX(x) * fY(y). If this condition holds, then X and Y are independent random variables.

By evaluating the joint probability distribution, calculating the marginal probability density functions, and comparing them to the joint probability density function, we can determine whether X and Y are independent.

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In order to rent her equipment from the resort each day she skis, she needs at least six days before the end of the season.

A linear equation is one that satisfies the algebraic formula y=mx+b. The foregoing sentence is sometimes referred to as a "linear equation with two variables" because y and x are variables. Bivariate linear equations are two-variable linear equations. Examples of linear equations include 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, and 3x - y + z = 3. An equation is said to be linear if its formula is y=mx+b, where m denotes the slope and b the y-intercept. It is referred to as being linear when an equation has the form y=mx+b, where m stands for the slope and b for the y-intercept.

given

Skiing day pass price in dollars is equal to 68d plus 20d.

When is a season pass less expensive (cost of skiing season pass = 400 + 20d)

400 + 20d minus three 20d = 68d + 20d

Divide 400 by 68 to get d = 5.882352941 when 68d > 400.

In order to rent her equipment from the resort each day she skis, she needs at least six days before the end of the season.

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Answer:

11

Step-by-step explanation:

every ratio is been multiplied for eleven si if we know this we can tell that

1 times 11= 11

Answer:

11

Step-by-step explanation:

Just times the things by 11, 5 times 11 is 55, 10 times 11 is 110, and 20 times 11 is 220, so 1 times 11 is 11 so 11 is the answer.

CAN I GET BRAINLLEST NOW!!!!!!!!!!!?????????????

PLEASE  

(○’ω’○)⊙_⊙-_-||囧rz◑﹏◐(?_?)(T_T)O_o::>_<::^O^-_-z(ToT)o_O

Answer:

3b²(4b²+1)

Step-by-step explanation:

You can factor out a 3b²

3b²(4b²+1)

Answer:

Hey friend, need some help if you factor 3b^2 out of 12b^4+3b^2, in other words, 3b^2 (4b^2 + 1)

Show your work:

3b^2 (3b^2 / 12b^4) + (3b^2 / 3b^2)

PLZ give 5 stars, heart, and brainlyest

Answer:

the answer is 5 because that is the difference which is what they are asking.

Step-by-step explanation:

12 -7 =5

. . . . . . .| . . . . .

-

. . . . . . .|

            | . . . . .

Answer:

concrete jungles where dreams are made of

Step-by-step explanation:

Answer:

There is a common ratio of 2/3 between the height of the ball at each bounce. So, the bounce heights form a geometric sequence: 27, 18, 12. Two-thirds of 12 is 8, so on the fourth bounce, the ball will reach a height of 8 feet.

Step-by-step explanation:

Sample response :)

Answer:

Step-by-step explanation:"To solve this equation, you can start by distributing the 0.20 and 0.30 terms. Then, you can simplify the equation by combining like terms. After that, you can isolate the variable Z on one side of the equation by adding or subtracting terms from both sides. Finally, you can solve for Z. The solution is Z = 1000. Does that help?"

Answer:

2*34

Step-by-step explanation:

The given curve is y = x³ − 2x and it has to be rotated about the x-axis to find the area of the surface. The formula to find the surface area of a curve obtained by rotating about the x-axis is given by:$$
A = 2\pi \int_a^b y \sqrt{1 + \left(\frac{dy}{dx}\right)^2} dx
$$Differentiating the curve with respect to x, we get:$$
y = x^3 - 2x
$$$$
\frac{dy}{dx} = 3x^2 - 2$$Now, squaring it, we get:$$
\left(\frac{dy}{dx}\right)^2 = 9x^4 - 12x^2 + 4$$$$
1 + \left(\frac{dy}{dx}\right)^2 = 1 + 9x^4 - 12x^2 + 4$$$$
= 9x^4 - 12x^2 + 5$$Putting the values in the formula, we get:$$
A = 2\pi \int_a^b y \sqrt{1 + \left(\frac{dy}{dx}\right)^2} dx$$$$
= 2\pi \int_{-1}^2 (x^3 - 2x) \sqrt{9x^4 - 12x^2 + 5} dx$$Simplifying it further, we get:$$
A = 2\pi \int_{-1}^2 (x^3 - 2x) \sqrt{(3x^2 - 1)^2 + 4} dx$$$$
= 2\pi \int_{-1}^2 (x^3 - 2x) \sqrt{9x^4 - 6x^2 + 5} dx$$Now, substituting $9x^4 - 6x^2 + 5 = t^2$, we get:$$(18x^3 - 12x)dx = tdt$$$$
(3x^2 - 2)dx = \frac{tdt}{3}$$When $x = -1$, $t = \sqrt{20}$ and when $x = 2$, $t = 5\sqrt{5}$Substituting the values in the formula, we get:$$
A = 2\pi \int_{\sqrt{20}}^{5\sqrt{5}} \frac{t^2}{27} dt$$$$
= \frac{28\pi}{27} \left[ t^3 \right]_{\sqrt{20}}^{5\sqrt{5}}$$$$
= \frac{28\pi}{27} \left[ 125\sqrt{5} - 20\sqrt{20} - 5\sqrt{5} + 2\sqrt{20} \right]$$$$
= \frac{28\pi}{27} \left[ 120\sqrt{5} - 18\sqrt{20} \right]$$$$
= \frac{56\pi}{27} \left[ 30\sqrt{5} - 9\sqrt{20} \right]$$$$
= \frac{56\pi}{27} \left[ 30\sqrt{5} - 18\sqrt{5} \right]$$$$
= \frac{56\pi}{27} \cdot 12\sqrt{5}$$$$
= \boxed{224\sqrt{5}\pi/3}$$Therefore, the area of the surface obtained by rotating the curve $y = x^3 - 2x$ about the x-axis is $\boxed{224\sqrt{5}\pi/3}$.

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The total area of the regions between the curves is 1.134π square units

From the question, we have the following parameters that can be used in our computation:

x = ∛y

We have the interval to be

0 ≤ y ≤ 1

The area of the regions between the curves is then calculated using

\(A =2\pi \int\limits^a_b {f(x) * \sqrt{1 + (dy/dx)^2} } \, dx\)

From x = ∛y, we have

y = x³

Differentiate

dy/dx = 3x²

So, the area becomes

\(A =2\pi \int\limits^1_0 {x^3 * \sqrt{1 + (3x^2)^2} } \, dx\)

Expand

\(A =2\pi \int\limits^1_0 {x^3 * \sqrt{1 + 9x^4 } \, dx\)

Integrate

\(A =2\pi \frac{(9x^4 + 1)^{\frac{3}{2}}}{54}|\limits^1_0\)

Expand

\(A = 2\pi [\frac{(9(1)^4 + 1)^{\frac{3}{2}}}{54} - \frac{(9(0)^4 + 1)^{\frac{3}{2}}}{54}]\)

This gives

A = 2π * 0.5671

Evaluate the products

A = 1.1342π

Approximate

A = 1.134π

Hence, the total area of the regions between the curves is 1.134π square units

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The probabilities are calculated assuming independence of each call and that the success probability remains constant throughout the calls.

a. The probability that, among five voters the student calls, exactly one supports candidate Smith can be calculated using the binomial probability formula. With a success probability of 64% (0.64) and exactly one success (k = 1) out of five trials (n = 5), the probability can be calculated as follows:

\[

P(X = 1) = \binom{5}{1} \times (0.64)^1 \times (1 - 0.64)^4

\]

The calculation results in approximately 0.369, or 36.9%.

b. The probability that, among five voters the student calls, at least one supports candidate Smith can be calculated as the complement of the probability that none of the voters support Smith. Using the binomial probability formula, with a success probability of 64% (0.64) and no success (k = 0) out of five trials (n = 5), the probability can be calculated as follows:

\[

P(X \geq 1) = 1 - P(X = 0) = 1 - \binom{5}{0} \times (0.64)^0 \times (1 - 0.64)^5

\]

The calculation results in approximately 0.997, or 99.7%.

c. The probability that the first voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of not reaching a Smith supporter in the first four calls (0.36) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{First Smith Supporter on Fifth Call}}) = (1 - 0.64)^4 \times 0.64

\]

The calculation results in approximately 0.014, or 1.4%.

d. The probability that the third voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of reaching two Smith supporters in the first four calls (0.64 for the first call, 0.36 for the second call, and 0.36 for the third call) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{Third Smith Supporter on Fifth Call}}) = (0.64)^2 \times (1 - 0.64) \times 0.64

\]

The calculation results in approximately 0.147, or 14.7%.

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The probabilities are calculated assuming independence of each call and that the success probability remains constant throughout the calls. The calculation results in approximately 0.369, or 36.9%.

a. The probability that, among five voters the student calls, exactly one supports candidate Smith can be calculated using the binomial probability formula. With a success probability of 64% (0.64) and exactly one success (k = 1) out of five trials (n = 5), the probability can be calculated as follows:

[P(X = 1) = \binom{5}{1} \times (0.64)^1 \times (1 - 0.64)^4\]

The calculation results in approximately 0.369, or 36.9%.

b. The probability that, among five voters the student calls, at least one supports candidate Smith can be calculated as the complement of the probability that none of the voters support Smith. Using the binomial probability formula, with a success probability of 64% (0.64) and no success (k = 0) out of five trials (n = 5), the probability can be calculated as follows:

[P(X \geq 1) = 1 - P(X = 0) = 1 - \binom{5}{0} \times (0.64)^0 \times (1 - 0.64)^5\]

The calculation results in approximately 0.997, or 99.7%.

c. The probability that the first voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of not reaching a Smith supporter in the first four calls (0.36) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{First Smith Supporter on Fifth Call}}) = (1 - 0.64)^4 \times 0.64

\]

The calculation results in approximately 0.014, or 1.4%.

d. The probability that the third voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of reaching two Smith supporters in the first four calls (0.64 for the first call, 0.36 for the second call, and 0.36 for the third call) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{Third Smith Supporter on Fifth Call}}) = (0.64)^2 \times (1 - 0.64) \times 0.64

\]

The calculation results in approximately 0.147, or 14.7%.

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From the asymptotes of the function, the end behavior is given by:

In this problem, the function is given by:

\(f(x) = \frac{4x}{x - 16}\)

For the vertical asymptote, it is when the denominator is of zero, hence:

x - 16 = 0 -> x = 16.

For the horizontal asymptote, we find the limit as x goes to infinity, hence:

\(\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{4x}{x - 16} = \lim_{x \rightarrow \infty} \frac{4x}{x} = \lim_{x \rightarrow \infty} 4 = 4\)

Hence the end behavior is given by:

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The answer is True. If two vertical angles are congruent, then two lines cut by a transversal will be parallel.

Vertical angles are angles that are opposite each other and share the same vertex. They are congruent angles, meaning that they have the same measure. When two angles are congruent, the sides of the angles are parallel. This means that the two lines cut by a transversal will also be parallel.

The formula for this is that if two angles are congruent, then the lines cut by a transversal are parallel. This is also known as the Angle-Angle-Angle (AAA) Postulate. This postulate states that if two angles of one triangle are congruent to two angles of another triangle, then the two triangles are similar. This means that the lines cut by a transversal are parallel.

In other words, if two angles of a triangle are congruent, then the two sides of the triangle that make those angles are parallel. This is because the two angles are congruent, meaning that they have the same measure. Therefore, if two vertical angles are congruent, then two lines cut by a transversal will be parallel.

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