Answer:
First one Or Last. I think the last one though
Step-by-step explanation:
can someone help me with this sum please
Answer:
See below...
Step-by-step explanation:
v * 7x = 7vx
8c * 6e = 48ec
3a * 4a = 12a^2
8xw * 2w = 18xw^2
8mn * 3m^2n = 24m^3n^2
4acx * 5ax^2 * 6c = 120a^2c^2x^3
4m * 4n = 16mn
3x * 4x = 12x^2
5w * 3wx = 15w^2x
6c * 5ac^2 = 30ac^3
9wx^2 * 6w^2x = 54w^3x^3
9a^2c * 4ac^2e^3 = 36a^3c^3e^3
A project under consideration has a 10-year projected life. The initial investment for the project is estimated to have a mean of $10,000 and a standard deviation of $1,000. The annual receipts are independent, with each year’s expected return having a mean of $1,800 and a standard deviation of $200. MARR is 12 percent. Assuming that initial investment and annual receipts are independent and normally distributed, estimate the probability that the present worth is negative using NORM.INV function in excel.
This value represents the present worth below which the probability is 0.5, indicating a negative present worth.
To estimate the probability that the present worth is negative using the NORM.INV function in Excel,
we need to calculate the present worth of the project and then determine the corresponding probability using the normal distribution.
The present worth of the project can be calculated by finding the sum of the present values of the annual receipts over the 10-year period, minus the initial investment. The present value of each annual receipt can be calculated by discounting it back to the present using the minimum attractive rate of return (MARR).
Using the given information, the present value of the initial investment is $10,000. The present value of each annual receipt is calculated by dividing the expected return of $1,800 by \((1+MARR)^t\),
where t is the year. We then sum up these present values for each year.
We can use the NORM.INV function in Excel to estimate the probability of a negative present worth. The function requires the probability value, mean, and standard deviation as inputs.
Since we have a mean and standard deviation for the present worth,
we can calculate the corresponding probability of a negative present worth using NORM.INV.
This value represents the present worth below which the probability is 0.5. By using the NORM.INV function,
we can estimate the probability that the present worth is negative based on the given data and assumptions.
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a poll of $100$ eighth-grade students was conducted to determine the number of students who had a dog, a cat or a fish. the data showed that $50$ students had a dog, $40$ students had a cat, and $20$ students had a fish. further, $19$ students had only a dog and cat, $2$ students had only a cat and a fish, $3$ students had only a dog and a fish, and $12$ students had only a fish. how many students had none of these pets?
14 students had none of the pets mentioned in the problem.
Given Question is related to Sets and Function
By using the principle of inclusion-exclusion,
D = set of students who had a dog
C = set of students who had a cat
F = set of students who had a fish
Let's determine the sizes of the sets and their intersections:
|D| = 50
|C| = 40
|F| = 20
|D ∩ C| = 19
|C ∩ F| = 2
|D ∩ F| = 3
|D ∩ C ∩ F| = 0
|D ∪ C ∪ F| = ?
The size of the union of the sets as follows:
|D ∪ C ∪F| = |D| + |C| + |F| - |D ∩ C| - |C ∩ F| - |D ∩ F| + |D ∩ C ∩ F|
|D ∪ C ∪ F| = 50 + 40 + 20 - 19 - 2 - 3 + 0 = 86
Therefore, there were 86 students who had at least one of these pets.
To find the number of students who had none of these pets, we can subtract this number from the total number of students:
100 - 86 = 14
Therefore, 14 students had none of the pets mentioned in the problem.
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Allison traveled a distance of 130 miles in 2 hours. What was Allison's average driving speed
Answer:
65
Step-by-step explanation:
We just need to divide 130 by 2 to find her average.
Which of the following statements have the same result? Explain each step in solving each one.
I. f(2) when f(x) = 3x + 4
II. f−1(4) when f(x) = 3x - 4 over 5
III. 3y − 6 = y + 10
Answer:
I don't think that there is two same results. sorry I couldn't help
Step-by-step explanation:
for I the answer should be 10 if you replaced each x by 2. f(2) = 3(2) + 4
and for II it will be f-1(4) = 3-1(4) - 4 /5 the answer will be -1.
for III it should be y = 8 or 4
please help me with this!!!
Answer:
126 m^2
Step-by-step explanation:
We can use the formula of the area of a parallelogram:
Area = base x height Area = 14 x 9Area = 126 m^2Hope this helps!!
Answer:126m^2
Step-by-step explanation:
The area of a parallelogram is the same as a rectangle. You must do 9*14=126.
Draw a box and whisker plot for the data set:
The box and whisker plots and the IQR for each of the data set is given below.
How to Draw a Box and Whisker Plot?A box and whisker plot has a rectangular box and two lines that connect from it on both sides, where:
The minimum value of the data is at the beginning of the left whisker.The value at the beginning of the box is the Q1.The value at the center of the box is the median.The value at the end of the box is the Q3.The maximum value of the data is at the end of the left whisker.The above stated values are referred to as the five-number summary of a data.
What is the Interquartile Range (IQR)?The interquartile range (IQR) = Q3 - Q1.
6. The five-number summary for the data set, 32, 34, 36, 37, 36, 37, 38, 37, 38 are:
Minimum: 32First Quartile: 35Median: 37Third Quartile: 37.5Maximum: 38The IQR is: 37.5 - 35 = 2.5
7. The five-number summary for the data set, 52, 52, 55, 55, 53, 56, 57, 57, 58 are:
Minimum: 52First Quartile: 52.5Median: 55Third Quartile: 57Maximum: 58The IQR is: 57 - 52.5 = 4.5
8. The five-number summary for the data set, 50, 51, 52, 58, 58, 59, 49, 50, 49 are:
Minimum: 49First Quartile: 49.5Median: 51Third Quartile: 58Maximum: 59The IQR is: 58 - 49.5 = 8.5
9. The five-number summary for the data set, 18, 16, 15, 19, 11, 14, 12, 14, 16 are:
Minimum: 11First Quartile: 13Median: 15Third Quartile: 17Maximum: 19The IQR is: 17 - 13 = 4
The box and whisker plot for each of the data set given is shown in the diagram below.
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lan's car can go 117 miles on 3 gallons of gas. During a drive last weekend, ian used 4
gallons of gas. How far did he drive? Use pencil and paper. Explain how the problem changes if you were given the distance iandrove last weekend instead of how much gas used.
Answer:
156 miles
Step-by-step explanation:
First of all we got,
3 gallons of gas used to drive 117 miles
that mean's
1 gallons of gas =117/3 miles
that is 39 miles
we need to find how far Ian's car can go with 4 gallons of gas
that is 4*39 which gives us 156 miles..
A rectangular painting is 2 feet long and 56 foot wide. Which is the area of the painting?
A. 1 2/3
B. 2 5/6
C. 3 1/3
D. 5 2/3
Answer:
I'm pretty positive it should actually be 112.
Step-by-step explanation:
You find the area of a rectangle by multiplying length times width. I don't know how else to explain that all of the answers are incorrect.
exercise 2.3.9. are ,x, ,x2, and x4 linearly independent? if so, show it, if not, find a linear combination that works.
To determine if, x, x2, and x4 are linearly independent, we need to see if there exists a non-trivial linear combination of these vectors that equals the zero vector.
Let's suppose there are scalars a, b, and c such that a*x + b*x2 + c*x4 = 0.
We can rewrite this as:
a*x + b*x^2 + c*x^4 = 0*x + 0*x^2 + 0*x^4
This gives us a system of equations:
a = 0
b = 0
c = 0
Since the only solution to this system is a = b = c = 0, we can conclude that ,x, x2, and x4 are linearly independent.
Therefore, there is no non-trivial linear combination of these vectors that equals the zero vector.
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A study of a local high school tried to determine the mean amount of money that each student had saved. The study surveyed a random sample of 55 students in the high school and found a mean savings of 2900 dollars with a standard deviation of 1300 dollars. Determine a 95% confidence interval for the mean, rounding all values to the nearest whole number.
A 95% confidence interval for the mean is (3193, 2607).
What is Confidence Interval?Confidence interval in simple words is the range of values that the specific parameter lies within.
Confidence interval for mean is found by the formula,
CI = Х ± t \(\frac{s}{\sqrt{n} }\)
where X is sample mean, s is the standard deviation and n is the sample size.
Sample mean = 2900
s = 1300
n = 55
Degree of freedom = n - 1 = 54
t value of degree of freedom 54 with the probability of exceeding the critical value as 1 - 95% = 5% = 0.05 is 1.674.
CI = 2900 ± (1.674)\(\frac{1300}{\sqrt{55} }\)
= 2900 ± 293.44
= (3193.44, 2606.56)
= (3193, 2607)
Hence the confidence interval is (3193, 2607).
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one band was paid $14000 for a concert
Answer:
cool, but what is the question?
Which of the following numbers can be expressed using negative exponents? Select one: a. .0005216 b. 5,216 c. -5,216 d. 52.16
Answer:
black people
Step-by-step explanation:
Part A Joseph runs 4 miles on Monday. Each day after that he runs the same 2 mile route every morning. His goal is to run at least 10 miles by the end of the week. What inequality represents the least number of days after Monday that Joseph needs to run to reach his goal
Part B what is the least number of days after Monday that Joseph needs to run to reach his goal
Answer: 2x + 4mi >=10 , 3
Step-by-step explanation:
x=days after monday
Since Joseph ran 4 miles the first day, that number stays constant. The 2miles depends on the amount of days he runs for so that is the coefficient. Atleast means greater than or equal to. Using the inequality, we can solve that x >= 3.
2x+4>=10
-4 -4
2x>=6
/2 /2
x>=3
how is this scientific notation: 12,050,000 = 1.25×107 wrong
Answer:
1.205 x 10⁷
Step-by-step explanation:
help me can you help with the second part
Answer:
12 packages with 2 toothbrushes and 3 soaps each
Step-by-step explanation:
Two of Maxwell's equations contain a path integral on the left side and an area integral on the right. The directions of the infinitesimal path element ds and infinitesimal area element dA are:
The directions of the infinitesimal path element d Vector s and infinitesimal area element d Vector A is none of the given option.
The directions of the infinitesimal path element d Vector s and infinitesimal area element d Vector A in Maxwell's equations are not fixed or predetermined to always be in the same direction, always in opposite directions, or always perpendicular to each other.
The orientations of these elements depend on the specific geometry and configuration of the electromagnetic field being considered. The direction of d Vector s is determined by the chosen path or curve along which the integration is performed.
The direction of d Vector A is determined by the orientation of the surface over which the integration is carried out. These orientations can vary depending on the specific problem and the shape of the path or surface involved.
Therefore, the correct answer is E. none of the above, as there is no fixed relationship between the directions of d Vector s and d Vector A in general.
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The question attached here seems to be incomplete, the complete question is:
Two of Maxwell’s equations contain a path integral on the left side and an area integral on the right. The directions of the infinitesimal path element d Vector s and infinitesimal area element d Vector A are: A. always in the same direction B. always in opposite directions C. always perpendicular to each other D. never perpendicular to each other E. none of the above
If the initial condition is for what values of is finite? answer (as an interval):
For option A Y = 0, 3, 5; while for B Y(o) E [0,5]. The limit of Sdⁿ is Limited. See the definition of equilibrium solution below.
What is Equilibrium Solution?A solution to a DE whose derivative is zero everywhere is an equilibrium solution.
A horizontal line represents an equilibrium solution on a graph.
You can identify equilibrium solutions given a slope field by locating every place where a horizontal line fits into the slope field.
What is the justification for the above answer?Note that The Equilibrium solutions when Y' = 0 is:
⇒ y (y-3) (y-5) = =
⇒ Y = 0, y = 3, y = 5
hence,
Y = 0,3,5
For section B:
Given the stated Direction field, we know that:
If y(0) ∈ (0,5), then \(\lim_{x \to \infty }\) y is 3
If y(0) ∈ (3,5), then \(\lim_{x \to \infty }\) y is 3
With regards to values existing beyond the intervals, the result is divergent.
Therefore,
For y (0) ∈ [0,5], limit of Sdⁿ is Limited.
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Full Question:
Consider The Direction Field Below For A Differential Equation Y'=Y(Y?3)(Y?5).
Use The Graph And Equation To Answer The Following Questions.
1) Find The Equilibrium Solutions For The Differential Equation. Answer (Separate By Commas): Y=
2. If The Initial Condition Is Y(0)=C, For What Values Of C Is Limit??Y(T) Finite? Answer (As An Interval): See attached for related Image.
I need help finding the function.
Answer:
-2
Step-by-step explanation:
I hope it helps
HELPPPPP
7 8 ÷ 1 4
A) 3 1 2
B) 4
C) 7 16
D) 7 32
Answer:
A) 3 1/2
Explanation:
\(\hookrightarrow \sf \dfrac{7}{8} \div \dfrac{1}{4}\)
rewrite the following
\(\hookrightarrow \sf \dfrac{7}{8} * \dfrac{4}{1}\)
join both fractions
\(\hookrightarrow \sf \dfrac{7*4}{8}\)
multiply
\(\hookrightarrow \sf \dfrac{28}{8}\)
simplify the following
\(\hookrightarrow \sf \dfrac{7}{2}\)
turn into mixed fraction
\(\hookrightarrow \sf 3\dfrac{1}{2}\)
Answer:
\(\dfrac{7}{2}\)
Step-by-step explanation:
Given expression:
\(\dfrac{7}{8} \div \dfrac{1}{4}\)
Simplify the expression:
\(\implies \dfrac{7}{8} \div \dfrac{1}{4}\)
\(\implies \dfrac{7 \div 1}{8 \div 4}\)
\(\implies \dfrac{7}{2}\)
-4 + 5x -7 = 10 + 3x - 2x
Answer:
X = 21 / 4 (21 over 4)
Step-by-step explanation:
First, we combine like terms:
5x−11=x+10
Step 2: Subtract x from both sides.
5x−11−x=x+10−x
4x−11=10
Step 3: Add 11 to both sides.
4x−11+11=10+11
4x=21
Step 4: Divide both sides by 4.
4x/4 = 21/4
x= 21 / 4
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A cubic die is biased, so that for each integer n,1≤n≤6 , the probability of the event {n} is p({n})=2p if n=3 or n=4 and p({n})=p , otherwise a) What is the expected number of times the die comes up 6 , when it is rolled 32 times? b) What is the expected number of times the die must be rolled until the first 6 comes up?
Hence, the answers are a) 9.14 and b) 7.
a) What is the expected number of times the die comes up 6, when it is rolled 32 times?b) What is the expected number of times the die must be rolled until the first 6 comes up?Solutions:Part a) Let X be the number of times the die comes up 6 when it is rolled 32 times.To find the expected number of times the die comes up 6, we'll apply the formula E(X) = np, where n is the number of trials and p is the probability of success on any given trial.If we look at the bias in this particular cubic die, we see that when the event is {6}, then p({6}) = p = 2p/4. This implies that p = 2/7, therefore: E(X) = np = 32*2/7 = 9.14285714286 = 9.14Part b) Let Y be the number of times the die must be rolled until the first 6 comes up.Let's use the geometric distribution to calculate the expected number of rolls E(Y).Since the event "6" has a probability of 1/7, then p = 1/7. Thus, the expected number of times the die must be rolled until the first 6 comes up is given by E(Y) = 1/p, which is 7 rolls.Hence, the answers are a) 9.14 and b) 7.
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Find x round your answer to the nearest tenth of a degree
Answer:
x = 49.4
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp /adj
tan x = 14/12
Taking the inverse tan of each side
tan ^-1 ( tan x) = tan ^-1 (14/12)
x =49.39870535
x = 49.4
Answer:
x = 49.4
Step-by-step explanation:
It's right triangle , so we can use trigonometry functions
tan θ = opposite side / adjacent side
tan x = 14 / 12
Taking inverse tan of each side
\( \small \sf \leadsto \: tan { }^{ - 1} (tan \: x \: ) = tan \: {}^{ - 1} ( \frac{14}{12}) \\ \)
x = 49.39870535
Round nearest tenth of degree = 49.4
Evaluate the following integral using the trapezoidal rule (use only one interval) and Gauss- Quadrature (n=2). Compare your results with the exact values. Take gp1=-gp2 = 0.5773 and w1 = w2 = 1. 1 = ₀∫π/² Sin²x dx Exact: x/2 – sin(2x)/4
The given integral is ₁∫₀^(π/2) sin²(x)dx.
The trapezoidal rule is given by:(b - a) [(f(a) + f(b))/2]And, the Gauss-Quadrature formula for n = 2 is: ∫ᵇₐ f(x) dx = (b - a) [ w₁ f( [ (b - a)/2 ] gp₁ + (b + a)/2 ) + w₂ f( [ (b - a)/2 ] gp₂ + (b + a)/2 ) ]
Here, a = 0, b = π/2, gp₁ = -0.5773, gp₂ = 0.5773, w₁ = w₂ = 1.
(i) Trapezoidal Rule: The trapezoidal rule with one interval is given by:(b - a) [(f(a) + f(b))/2] = π/4 [sin²(0) + sin²(π/2)] = 0.7854
(ii) Gauss-Quadrature: Using the Gauss-Quadrature formula with n = 2, we get:∫ᵇₐ f(x) dx = (b - a) [ w₁ f( [ (b - a)/2 ] gp₁ + (b + a)/2 ) + w₂ f( [ (b - a)/2 ] gp₂ + (b + a)/2 ) ]= π/2 [ sin²( [ (π/2)/2 ] (-0.5773) + π/4 ) + sin²( [ (π/2)/2 ] (0.5773) + π/4 ) ]= 0.7853Comparing the above two methods, the trapezoidal rule and Gauss-Quadrature method are nearly the same and are close to the exact value.
Exact value = (π/2)/2 - sin(π)/4 = 0.7854Conclusion:Thus, it can be concluded that the given integral using the trapezoidal rule (using only one interval) and Gauss- Quadrature (n=2) is approximately equal to 0.7854.
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6,615 for divisibility by 2,3,5,9 and 10
Answer:
92.9
Step-by-step explanation:
what is the perimeter of this rectangle
18 yd
19 yd
please help
Answer:
= 74cm²
Step-by-step explanation:
Perimeter of a rectangle
\( = 2(l) + 2(w)\)
therefore
= 2(18) + 2(19)
= 36 + 38
= 74cm².
please solve this
20×10=
Answer:
20 × 10 = 200
Step-by-step explanation:
Multiply 2 × 1 = 2 and then add the two zeros onto the end to get 200.
which of the following can be used to find the slope between two points? response area what is the rate of change between (3, 2) and (6, 10)?response area
Answer:
the slope of these points is 8/3
The diagram shows two proportional right triangles.
What is the perimeter of the larger triangle?
The perimeter of the possible larger triangle with possible side lengths of 24, 32 and 40 is 96 units
What is the perimeter of a plane figure?The perimeter of a figure is the length of the boundary surrounding the figure.
Two triangles that have proportional dimensions are similar triangles
The dimensions (arranged in the order of corresponding sides) of the possible similar right triangles in the question, obtained from a related question, having two similar right triangles, posted online are;
First (larger) triangle side lengths; 24, 32, and xSecond (smaller) triangle side lengths; 9, 12, and 15The similarity of the triangles (proportional corresponding sides, indicates that we get;
\(\dfrac{24}{9} = \dfrac{32}{12} = \dfrac{x}{15}\)
Therefore, by cross multiplication, we get;
32 × 15 = 12 × x
x = 32 × 15 ÷ 12 = 40
The perimeter of the larger triangle is; 24 + 32 + 40 = 96
The perimeter of the larger triangle is 96 units.Please find attached the possible diagram of proportional right triangles, created with MS Word, obtained from a question with regards to proportional right triangles online.
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-x = 5
what is the answer for x?
Answer:
Answer:
x= -5
.........
Answer: x = -5
Step-by-step explanation: