y’all I would rlly appreciate if y’all gave me the answers to all my questions. My cousin has over 200 assignments she hasn’t done so I’m trying to help her and tbh I don’t know this stuff bc I’ve never done it in school.

No, the object's displacement and distance traveled will be equal; however, because the object's initial position is unknown, the object's position may differ from its displacement and distance traveled.

Because the initial position is not provided, we cannot assert that the displacement or distance equals the position. We might have arrived at a different conclusion if the starting point had been zero, because the distance from zero equals the position.

What precisely do you mean by position, displacement, and distance?

The location of an object (whether a person, a ball, or a particle) at a given point in time is referred to as its position. The displacement of an object is the difference in its position from one time to the next. Distance is the total amount the object has traveled in a certain period of time.

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1. Astronomical observational patterns are used to determine the history of the universe by studying the light emitted or absorbed by celestial objects. Scientists analyze the patterns in the electromagnetic spectrum, such as the distribution of wavelengths, intensity, and spectral lines, to gather information about the composition, temperature, motion, and evolution of celestial bodies.

Astronomical observational refers to the act of observing celestial objects and phenomena in the field of astronomy. It involves the use of telescopes, detectors, and other instruments to collect data and study various aspects of the universe.

2. Mount Wilson and Mount Palomar Observatories were used to observe and collect data about space due to several reasons. Firstly, the locations of these observatories provide advantages for astronomical observations.

3. The NASA Mission Statement is: "To pioneer the future in space exploration, scientific discovery, and aeronautics research." This mission statement reflects NASA's commitment to advancing human knowledge, technological innovation, and exploration beyond Earth's boundaries. NASA aims to push the boundaries of scientific understanding, develop and test new technologies, explore the cosmos, and inspire the next generation of scientists and engineers.

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The main advantage of a no-contact voltage indicator is that it is fast and safe to use. It can be used to detect live electrical circuits without touching the wires. They have an advanced internal circuitry that does not require physical contact with the live wire being tested.

They also work up to several hundred volts and are cost-effective. The no-contact voltage indicator, unlike the solenoid-type voltage tester, is ideal for quickly locating live wires or insulation flaws in electrical wiring. The use of a no-contact voltage indicator over a solenoid-type voltage tester offers great safety advantages.

A no-contact voltage indicator is a device that uses a sensing tip to detect the presence of AC voltage by either an LED indicator, audible alarm, or both. This type of voltage tester does not require physical contact with the surface being tested, making it a much safer testing method.

With no contact required, it eliminates the possibility of a shock should the solenoid-type tester contacts a live wire. In addition, this type of voltage indicator is able to determine if an outlet is wired correctly without having to insert a plug or other conductive device. This feature is not available with a solenoid-type voltage tester.

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Answer:

Transformers

Explanation:

Transformers are things that changer the amount of voltage in an electric line.

Answer:

In the surface of the moon, gravitational acceleration is 1.63 m/s*2.

Explanation:

An object of mass M will accelerate gravitationally at a distance R if it is at the following distance:

g = G*M/R^2

Where the gravitational constant is G.

G = 6.67*10^(-11) m^3/(kg*s^2)

At the surface of a moon, the distance between its surface and its center will be equal to its radius, since a moon's mass is concentrated at its center, thus:

R = 1740 km

It's important to remember that we need meters in order to work:

1 km = 1000 m

so:

1740 km = (1740)*1000 m = 1740000 m

R =  1740000 m

Basically, the mass consists of:

M = 7.4x10^22 kg

Incorporating all that into the gravitational acceleration equation, we get:

g = (6.67*10^(-11) m^3 / (kg*s^2))*(7.4x10^22 kg) / ( 1740000 m)^2

g = 1.63 m / s^2

In the surface of the moon, gravitational acceleration is 1.63 m / s*2.

(1) First compute the linear speed of the mass. If it completes 1 revolution in 0.5 seconds, then the mass traverses a distance of 2π (1.0 m) ≈ 2π m (the circumference of the circular path), so that its speed is

v = (1/0.5 rev/s) • (2π m/rev) = 4π m/s ≈ 12.57 m/s

Then the centripetal acceleration a is

a = v² / (1.0 m) = 16π² m/s² ≈ 160 m/s²

(where r is the path's radius).

(2) By Newton's second law, the tension in the string is T such that

T = (0.50 kg) a = 8π² N ≈ 79 N

(a) The centripetal acceleration of the mass is 158 m/s².

(b) The tension in the string at the given mass is 79 N.

The given parameters;

The angular speed of the attached mass is calculated as follows;

\(\omega = \frac{1 \ rev}{0.5 \ s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 12.57 \ rad/s\)

The centripetal acceleration of the mass is calculated as follows;

\(a_c = \omega ^2 r\\\\a_c = (12.57)^2 \times 1\\\\a_c = 158 \ m/s^2\)

The tension in the string is calculated as follows;

\(T = ma_c\\\\T = 0.5 \times 158\\\\T = 79 \ N\)

Thus, the tension in the string at the given mass is 79 N.

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According to the second law of Newton, the acceleration is directly proportional to the net force acting on the object:

From this formula, we can also see that the acceleration is inversely proportional to the mass: For the same force, if the mass increases, the acceleration decreases.

Therefore the correct option is d.

The magnitude of the impulse encountered by the ball is 10.406 Ns (since magnitude is always positive).

To determine the magnitude of the impulse encountered by the ball, we first need to find the change in momentum, which can be calculated using the following formula:
Impulse = Change in Momentum = Final Momentum - Initial Momentum
Since momentum (p) is given by the product of mass (m) and velocity (v), we can write the formula as:
Impulse = m * (Final Velocity - Initial Velocity)
Given the mass of the rubber ball (m) = 1.10 kg,

initial velocity (Vi) = 6.82 m/s,

and final velocity (Vf) = -2.64 m/s

(rebounding in the opposite direction),

we can plug in these values into the formula:
Impulse = 1.10 kg * (-2.64 m/s - 6.82 m/s)
Impulse = 1.10 kg * (-9.46 m/s)
Impulse = -10.406 kg*m/s
The magnitude of the impulse encountered by the ball is 10.406 Ns (since magnitude is always positive).

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Answer:

I think its the second law..

Explanation:

Answer:

its the second law.

hope this helps! :)

Answer:

velocity is a vector- its the rate at which an object changes position

acceleration is the rate of change of velocity

Explanation:

hope this helps

take care, stay safe, and live

-kenma kozume #3

A nuclear of 208pb has 82 protons with a sphere of radius 6.34 * \(10^{-15}\)m. The electric field at the surface of the nucleus is 2.24 x \(10^{11}\) N/C.

The electric field at the surface of a nucleus can be calculated using Coulomb's law, which states that the electric field produced by a point charge is proportional to the charge and inversely proportional to the square of the distance from the point charge.

E = k * q / \(r^{2}\)

where,

E = the electric field in N/C

k = the Coulomb constant, equal to 8.99 x \(10^{9}\) N \(m^{2}\) / \(C^{2}\)

q = the charge on the nucleus, equal to 82 times the charge on a proton, or 82 * 1.60 x \(10^{-19}\) C

r is the radius of the nucleus, equal to 6.34 x \(10^{-15}\)m

Plugging in these values, we get:

E = 8.99 x \(10^{9}\) N \(m^{2}\) / \(C^{2}\) * 82 * 1.60 x \(10^{-19}\) C / 6.34 x \(10^{-15}\)m ^2

E = 2.24 x \(10^{11}\) N/C.

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There are three orders of magnitude difference between 0.0012 grams and 0.0012 kilograms.

What is magnitude?
The definition of magnitude is "how much of a quantity." In order to compare the speeds of an automobile and a bicycle, for example, the magnitude can be utilised. It can also be used to describe how far an object has travelled or how much an object weighs in terms of its magnitude. What then is magnitude in the field of physics? Magnitude is a term used in physics to describe an object's maximal size and direction. Scalar and vector quantities both use magnitude as a common factor. We are aware that scalar quantities are those that have just magnitude by definition. Those quantities with both magnitude and direction are considered vector quantities.

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To calculate the magnitude of the acceleration of the sofa in units of m/s2, we need to use Newton's Second Law of Motion, which states that the force acting on an object is equal to the mass of the object times its acceleration, F = ma.

We also need to account for the force of friction, which opposes the motion of the sofa and is equal to the coefficient of kinetic friction times the normal force, or Ff = μkFN.

Since the sofa is sliding across a horizontal floor, the normal force is equal to the weight of the sofa, or FN = mg. Therefore, the force of friction is Ff = μkmg.

Now we can plug in the given values and solve for the acceleration of the sofa:

F - Ff = ma

486.99 N - (0.23)(83.47 kg)(9.8 m/s2) = (83.47 kg)a

Solving for a, we get:

a = (486.99 N - (0.23)(83.47 kg)(9.8 m/s2))/(83.47 kg)

a = 3.82 m/s2

Rounding to two decimal places, the magnitude of the acceleration of the sofa is 3.82 m/s2.

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If the pulling is done parallel to the ground, we have by Newton's second law

8 N + (-f ) = (2 kg) (2.5 m/s²)

where f is the magnitude of the friction force. Solve for f :

8 N - f = 5 N

f = 3 N

The given statement "Average velocity can be expressed as (Δs/Δt) where s(t) is the position function." is True. Average velocity is defined as the change in position over a given time interval.

This can be expressed mathematically as (Δs/Δt), where Δs is the change in position and Δt is the change in time. The position function, s(t), gives the position of an object at any given time t. By calculating the difference in position over a specific time interval, we can determine the average velocity of the object during that interval. This calculation is a fundamental concept in calculus and physics, as it allows us to understand how objects move and change over time. Therefore, it is true that average velocity can be expressed as (Δs/Δt) where s(t) is the position function.

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Answer:

its A

Explanation:

White dwarf, Sun, red supergiant shows the stars in the correct order, from smallest in size to largest.

More than 1.4 million kilometers span our Sun. However, not every star is the same size. They range in size from that of a metropolis to that of our solar system's half!

The mass of neutron stars is concentrated into a very compact area. Even though they are frequently only 20 to 40 km in diameter, they may hold the mass of one or two Suns. White dwarf stars are a little larger and frequently resemble the size of the Earth.

Compared to our Sun, the greatest supergiant stars can be more than 1500 times bigger. They are now more than 2,000 million kilometres across. Supergiants don't, however, have thousands of times the mass of the Sun. The reason for this is that as supergiants become older, their interiors become considerably more dispersed. Betelgeuse, a red giant in Orion's constellation, is nearly 1000 times broader than the Sun yet only has around 15 times as much mass.

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Answer:

7.656 m/s

Explanation:

El sonido viaja a cierta velocidad y tiene una frecuencia y longitud de onda. La relación entre la velocidad del sonido (V), su frecuencia (f) y la longitud de onda (λ) es la misma que para todas las ondas, está dada por la ecuación:

V = fλ

pero f = 1/T

∴ V = λ/T

donde T es el período

Dado que:

período (T) es el tiempo necesario para subir y bajar = 3.2 s

La distancia entre dos crestas es la longitud de onda (λ) = 24.5 m

V =  λ/T = 24.5 / 3.2 = 7.656 m/s

V = 7.656 m/s

The work done by the applied force on the block against the frictional force is 15.75 J.

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is a 4 kg block is pushed 2m at an acceleration of 0.2 meter per second square up a vertical wall by constant force f applied at an angle of 37 degree with the horizontal if the coefficient of kinetic friction, μ between the block and the wall is 0.30.

From the equilibrium of forces acting on the block, we have

F - f = ma

where, F is applied force, f is frictional force, m is the mass and a is the acceleration.

Frictional force f =  μmgsinθ

Substitute the values, we get

Fcos(37) - μmgsin(37) = ma

Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)

0.799F - 7.077 = 0.8

F = 9.86 N

Work done by the applied force is

W = Fdcosθ

W = 9.86 x 2 x cos(37)

W = 15.75 J

Thus, the work done by the applied force on the block against the frictional force is 15.75 J.

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Consider a certain object A, the following is an example of its internal energy is B. Elastic energy due to stretched bonds between different parts of object A

Internal energy is the sum of the kinetic and potential energy of the particles that make up an object. Internal energy is therefore a property of the object that depends on the internal state of its constituent particles. Elastic energy due to stretched bonds between different parts of object A is an example of its internal energy. Internal energy is a property of a system, which is the sum of the kinetic and potential energies of the molecules that make up the system.

It's a result of the motion of particles within a system that is not related to the motion of the system as a whole. Internal energy of an object is the total of its kinetic energy, potential energy, and internal potential energy. Therefore, Elastic energy due to stretched bonds between different parts of object A is an example of its internal energy. In conclusion, Elastic energy due to stretched bonds between different parts of object A is an example of its internal energy, so the correct answer is B. Elastic energy due to stretched bonds between different parts of object A

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Answer:Examples of input devices include keyboards, mouse, scanners, cameras, joysticks, and microphones.

pls mark brainliest

Explanation:

A simple pendulum is suspended from the ceiling of an elevator. The elevator is accelerating upwards with acceleration a. The period of this pendulum, in terms of its length L, g and a is    \(2\pi \sqrt{\frac{L}{g+a}}\).

The period of a simple pendulum is given by the formula:

T = \(2\pi \sqrt{\frac{L}{g}}\)

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

In the case of the pendulum in an accelerating elevator, we need to consider the effective acceleration experienced by the pendulum. Since the elevator is accelerating upwards with acceleration a, the net acceleration acting on the pendulum will be the sum of the acceleration due to gravity (g) and the acceleration of the elevator (a).

Therefore, the effective acceleration (g') experienced by the pendulum can be calculated as:

g' = g + a.

Using this effective acceleration, the period of the pendulum in terms of L, g, and a becomes:

T = \(2\pi \sqrt{\frac{L}{g'}}\) = \(2\pi \sqrt{\frac{L}{g+a}}\)

So, the period of the pendulum in an accelerating elevator is given by \(2\pi \sqrt{\frac{L}{g+a}}\).

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Answer:

q = 0.384 C

Explanation:

The total charge present at the head can be easily found out by multiplying the charge on a single electron with the total number of electrons present on the head:

\(q = ne\)

where,

q = total charge on head = ?

n = total no. of electrons on the head = 2.4 x 10¹⁸

e = charge on 1 electron = 1.6 x 10⁻¹⁹ C

Therefore,

\(q = (2.4\ x\ 10^{18})(1.6\ x\ 10^{-19}\ C)\)

q = 0.384 C

Distance is the physical length travelled. While the displacement is the shorter distance between any two given points.

Distance is a numerical representation of the distance between two objects or locations.

Distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

Displacement is defined as the shortest distance between the two points.

Sam determines the distance by doing the calculation as;

distance = speed × time

Hence, the Sam determines the distance and displacement by the respective formulas.

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By using vector

a. the distance traveled is 12 kilometres

b. the resultant displacement is (7 i + 5 j) kilometres

We need to know about vectors to solve this problem. Vector has magnitude and also direction. Displacement is included in vector. It can be written as

s = sx i + sy j + sz k

where s is displacement, sx is displacement on x-axis, sy is displacement on y-axis and sz us displacement on z-axis.

From the question above, we know that

east = positive x

south = negative y

west = negative x

north = positive y

s1 = 7 j

s2 = 5 j

The distance traveled is

s = s1 + s2

s = 7 + 5

s = 12 kilometres

The resultant displacement is

s = s1 + s2

s = 7 i + 5 j

s = (7 i + 5 j) kilometres

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For the safe negotiation of the car, the speed limit should be 16.19 m/s².

What is Centripetal Force?

The equation for Centripetal Force, \(F=\frac{mv^{2} }{r}\)  ----(1)

From the given problem, we have:

Radius, r = 40 m;

Mass, m = 1,423 kg; and

Centripetal Force, F = 9,327 N

Rearranging equation (1), we get the equation for speed as

\(v=\sqrt{\frac{F \times r}{m} }\)

Substituting the given values, we get

\(v=\sqrt{\frac{9327 \times 40}{1423} } \\\implies \sqrt{\frac{373080}{1423} } \\\implies =16.19 m/s^{2}\)

Hence, for the safe negotiation of the car, the speed limit should be 16.19 m/s².

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Answer:

periscope, an optical instrument used in land and sea warfare, submarine navigation, and elsewhere to enable an observer to see his surroundings while remaining under cover, behind armor, or submerged.

Explanation:

Answer:

united states

Explanation:

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