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Global Temperature Change – Student Guide




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A. The weight of the mass on the earth is 117.6 N

A. The weight of the mass on the moon is 19.56 N

Weight is defined as follow:

Weight (W) = mass (m) × Acceleration due to gravity (g)

W = mg

Now we shall determine the weight. Details below:

A. Weight on earth

Weight (W) = mass (m) × Acceleration due to gravity (g)

Weight (W) = 12 × 9.8

Weight on earth = 117.6 N

B. Weight on moon

Weight (W) = mass (m) × Acceleration due to gravity (g)

Weight (W) = 12 × 1.63

Weight on moon = 19.56 N

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Complete question:

The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth (b) on the moon

Answer:

   a = 8.4 m / s²

Explanation:

The mean acceleration is defined by

          a = (v_f- v₀) / (t_f - t₀)

where v are the final and initial velocities, respectively and t is the time interval

Let's apply this equation to our case

the final velocity is 99 m / s and the initial velocity is 57 m / s

         a = (99 - 57) / (15 - 10)

         a = 8.4 m / s²

a) The cost of using the microwave oven for one hour is 6 cents.

b) The cost of using the microwave oven for 20 minutes in a day is 2 cents.

c) The cost of using the microwave oven for 20 minutes a day for a month of 30 days is 59 cents.

a) The microwave oven draws 0.8 kWh of electricity for one hour. The cost of electricity per kWh is 7.5 cents. Therefore, the cost of using the microwave oven for one hour can be calculated as follows:

Cost = 0.8 kWh x $0.075/kWh = $0.06

b) If the microwave oven is used for 20 minutes in a day, the energy consumed can be calculated as follows:

Energy consumed = Power x Time

Power = Energy consumed / Time

We know that the microwave oven draws 0.8 kWh of electricity for one hour. Therefore, the power can be calculated as:

Power = 0.8 kWh / 1 hour = 0.8 kW

The time for which the microwave is used is 20 minutes, or 0.33 hours. Therefore, the energy consumed can be calculated as:

Energy consumed = Power x Time = 0.8 kW x 0.33 hours = 0.264 kWh

The cost of using 0.264 kWh of electricity can be calculated as:

Cost = 0.264 kWh x $0.075/kWh = $0.02

c) If the microwave oven is used for 20 minutes a day for a month of 30 days, the energy consumed can be calculated as:

Energy consumed = Power x Time x Number of days

Power = Energy consumed / Time

Using the same values of power and time as in part b, the energy consumed for 30 days can be calculated as:

Energy consumed = 0.8 kW x 0.33 hours x 30 days = 7.92 kWh

The cost of using 7.92 kWh of electricity can be calculated as:

Cost = 7.92 kWh x $0.075/kWh = $0.59

In summary, the cost of using a microwave oven for electrical energy consumption depends on the power rating of the oven and the cost of electricity per kWh. By calculating the energy consumed and multiplying it by the cost per kWh, one can determine the cost of using the microwave for a particular period of time.

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Explanation:

The de broglie wavelength is given by :

\(\lambda=\dfrac{h}{p}\)

Here,

h is Planck's constant

p is momentum

Momentum and De-Broglie wavelength has inverse relationship. If momentum of an electron double, its wavelength gets half.

Answer:

1) 1256.02 kJ

2)76.20 lb

3)2336.30 lb

Explanation:

The kinetic energy of a 4,934 pound pickup truck going 55 mph is:

First, we need to convert the mass of the truck from pounds to kilograms:

4,934 lb = 2,236.17 kg

The kinetic energy is given by the formula: KE = 0.5 * m * v^2

where m is the mass of the object and v is the velocity.

Plugging in the values, we get:

KE = 0.5 * 2,236.17 kg * (55 mph)^2 = 1,256,024.47 J

Converting to kJ, we get:

KE = 1,256,024.47 J / 1000 = 1256.02 kJ

A 4,992 lb car has a rolling resistance coefficient of 0.015. How much force, in lb, will it take to push this car at 30 mph?

The force required to overcome rolling resistance is given by the formula:

F = Crr * W

where Crr is the rolling resistance coefficient and W is the weight of the car.

First, we need to convert the weight of the car from pounds to Newtons:

4,992 lb = 22,612.88 N

Plugging in the values, we get:

F = 0.015 * 22,612.88 N = 339.19 N

Converting to pounds, we get:

F = 339.19 N / 4.45 = 76.20 lb

The 2022 Hummer EV comes with a 212 kWh battery. How much will this battery weigh in lbs?

We cannot directly convert from kilowatt-hours to pounds, as they are two different units. However, we can use the energy density of the battery to estimate its weight.

Assuming an energy density of 200 Wh/kg for the battery, we can calculate the mass of the battery as:

212 kWh * 1000 Wh/kWh / 200 Wh/kg = 1060 kg

Converting to pounds, we get:

1060 kg * 2.205 lb/kg = 2336.30 lb

a ) The energy absorbed by the eardrum per second = 5 * \(10^{-12}\) W

b ) At this rate, it would take the eardrum 6341.96 years to receive a total energy of 1.0 J

P = I A

P = Power

I = Intensity

A = Surface area

β = 10 log I / Io

log I / Io = β / 10

I / Io = 10 ^ ( β / 10 )

I = Io * 10 ^ ( β / 10 )

A = 5 * \(10^{-5}\) m²

Io = 1 * \(10^{-12}\) W / m²

β = 50 dB

I = 1 * \(10^{-12}\) * 10 ^ ( 50 / 10 )

I = \(10^{-7}\) W / m²

P = 5 * \(10^{-5}\) * \(10^{-7}\)

P = 5 * \(10^{-12}\) W

P = W / t

W = Work done

t = Time

W = 1 J

t = W / P

t = 1 / 5 * \(10^{-12}\)

t = 0.2 * \(10^{12}\) s

t = 6341.96 years

Therefore,

a ) The energy absorbed by the eardrum per second = 5 * \(10^{-12}\) W

b ) At this rate, it would take the eardrum 6341.96 years to receive a total energy of 1.0 J

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The examples of elements with similar properties in the same group are fluorine, chlorine, bromine and iodine.

The groups in periodic table is the same as vertical columns in the periodic table

These groups represent a group or family of elements that have the same number of valence electrons by having similar electron configurations elements in the same group have similar properties.

Examples of elements found in the same group with similar chemical properties include;

group 7 elements.

The valence electron of elements found in the group 7 of periodic table is negative 1 (-1).

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We have that the absolute pressure at the bottom of the tank is mathematically given as

Pabs=209.21Kpa

Question Parameters:

A 3-m-diameter vertical cylindrical tank is filled

with water to a depth of 11 m.

Generally the equation for the Absolute Pressure  is mathematically given as

Pabs=Patm+pgh

Therefore

Pabs=101.3e3+(1000*9.81*11)

Pabs=209.21Kpa

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Answer:

4.4 x 10^-12 N right

Explanation:

The equation which represent the velocity, if the satellite is moved to an orbital radius of 5r is V = V/\(\sqrt\\5\).

Orbital velocity or orbital speed is the minimum velocity a body must maintain to stay in an orbit. Due to the inertia of a moving body, the body has the tendency to move on in a straight path.

It is given that the radius is 5r

To find out the equation which represent the velocity if the satellite is moved to an orbital radius of 5r.

Mathematically, the orbital velocity is calculated by the formula:

V = \(\sqrt{GM}\)/r

where, V = orbital velocity,

G = gravitational constant

M = mass of a satellite

r = radius

Substituting the value of r in this equation, we have:

V = \(\sqrt{GM}\)/r

V = 1/ \(\sqrt{5}\) ×  \(\sqrt{GM}\)/r

V = \(\sqrt{GM}\)/r

Therefore,

V = 1/ \(\sqrt{5}\)  × V

V = V/\(\sqrt{5}\)

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0.965 mililΩ

The resistance of a metal rod depends on resistivy, length and temperature, it can fe found usign the formula

sp

Step 1

a) let

b) find the transversal area (A)

use the area of a circle

c) now, replace in the formula

finally, to convert into milliOhms, Multiply by 1000

therefore, the answer is

0.965 miliΩ

I hope this helps you

Answer:

h=4+85*time - 1/2 32*time^2

16time^2-85*time-106=0

use the quadratic formula to solve for time (notice two solutions, one going up, one going back down).

time=(85+-sqrt(85^2+4*16*106) )/32

Explanation:

Recheck my work just in case I'm not good at this type of class but I wanted to help.

a. At maximum height h, the baseball has zero vertical velocity, so that with initial velocity v we have

\(0^2-v^2 = -2gh \implies h = \dfrac{v^2}{2g}\)

Given that \(v = 30 \frac{\rm m}{\rm s}\), the ball reaches a height of

\(h = \dfrac{\left(30\frac{\rm m}{\rm s}\right)^2}{2g} \approx \boxed{46\,\mathrm m}\)

b. At max height, the baseball's vertical velocity is such that

\(0=v-gt\)

For \(v = 30 \frac{\rm m}{\rm s}\), we find

\(gt=30\dfrac{\rm m}{\rm s} \implies t = \dfrac{30\frac{\rm m}{\rm s}}g \implies t \approx 3.1 s\)

which is half the time it spends in the air, making the total time about 6.1 s.

c. We saw in part (a) that

\(h = \dfrac{v^2}{2g}\)

If we halve the initial speed and replace \(v\) with \(\frac v2\), we get

\(h = \dfrac{\left(\frac v2\right)^2}{2g} = \dfrac14 \cdot \dfrac{v^2}{2g}\)

which means the max height is reduced by a factor of 1/4.

In part (b), we found the time to max height is

\(t = \dfrac{v}{g}\)

and halving the initial speed gives

\(t = \dfrac{\frac v2}g = \dfrac12 \cdot \dfrac{v}{g}\)

That is, the time to max height is reduced by a factor of 2 when the speed is halved, and so the overall time in the air is reduced by a factor of 2.

Sarah uses an inclined plant to load a chest into her truck. If she does 84 Joules of work, and the inclined plane is 3 meters long, she expend the amount of force is (F)= 252N.

Force is a physical phenomena. When some mass is affected by the external phenomena and moved a distance that means the phenomena is called the force. It can be measured in Newton, Dyne.

To calculate the amount of force we are using the formula here,

F= wd

Here we are given,

w= The work done by Sarah. = 84J

d= The distance of inclined plane.= 3m.

We have to calculate the amount force.= F N

Now we are going to put the values in above equation,

F= wd

Or, F= 84*3

Or, F=252N

Now we can say that, she expend the amount of force is (F)= 252N.

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Answer:

Therefore, the GPE of the fish from the given height is 26.19 J.

Explanation:

The gravitational potential energy (GPE) of an object at a height h is given by the formula:

GPE = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

In this case, the mass of the fish is 0.3 kg, the height from which it was dropped is 9 meters, and the acceleration due to gravity on Earth is approximately 9.81 m/s². Thus, the GPE of the fish can be calculated as:

GPE = (0.3 kg) × (9.81 m/s²) × (9 m) = 26.19 J

Therefore, the GPE of the fish from the given height is 26.19 J.

I like puffins

The total volume of the piece of wood is 1.33\(cm^3\).

To calculate the total volume of the piece of wood, we can use the principle of displacement.

1. First, we need to find the difference in volume between the two water levels. The initial volume is 17.7 \(cm^3\), and the final volume is 18.5 cm^3. The difference is 18.5 \(cm^3\) - 17.7 \(cm^3\) = 0.8 \(cm^3\).

2. Now, we need to find the volume of water displaced by the piece of wood. Since the relative density of the wood is 0.60, it means that the wood is 0.60 times denser than water.

3. The volume of water displaced by the wood is equal to the difference in volume divided by the relative density of the wood. So, the volume of water displaced is 0.8 cm^3 / 0.60 = 1.33 \(cm^3\).

4. Finally, the total volume of the piece of wood is equal to the volume of water displaced. Therefore, the total volume of the piece of wood is 1.33 \(cm^3\).

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Answer:

what's the question ,so I can answer it right ?

If no action is taken to address the issues evaluate whether the impact of light pollution radio interference and space debris on the field of astronomy is then a. likely to worsen

Astronomers already have a serious problem with light pollution from cities and other sources, which makes it more challenging to detect dim objects in the night sky. Light pollution is predicted to get worse unless action is taken to stop it as urbanisation grows and more artificial lights are installed.

Astronomical observations can be affected by radio interference from telecommunications, and unless steps are taken to reduce the issue, the issue is only going to become worse as the number of radio-emitting devices rises. In addition, astronomers' instruments and spacecraft are increasingly in danger from space debris. The probability of collisions and other accidents is anticipated to rise as the amount of trash in space continues to rise.

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Complete Question:

If no action is taken to address the issues evaluate whether the impact of light pollution radio interference and space debris on the field of astronomy is then -

a. likely to worsen

b. lessen or remain the same during the next 50 years

Answer:

force=12000

Explanation:

F=m*a aka force equals mass times acceleration so 800*15=12000

Answer:

12000 N

Explanation:

The equation for Force is:

\(Force=mass*acceleration\)

We can plug in the given values into the equation:

\(Force=800kg*15m/s^2\\Force=12000N\)

The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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The vector product of A and B is -3i - 5j - 9k.

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

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The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.

The formula for net torque acting on an object is given as;

T(net) = Ia

where;

The  moment of inertia of an object is given as;

I ∝ MR²

where;

So mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.

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The magnitude of the force and the impulse applied to the car are  85714 N and  30000 N-s respectively.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

The magnitude of the force applied to the car = change in momentum/time interval

= (1200 kg × 25 m/s - 1200 kg×0)/0.35 second

= 85714 N.

The impulse applied to the car = change in momentum

= (1200 kg × 25 m/s - 1200 kg×0)

= 30000 N-s.

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Answer:

The initial velocity of this shark is \(8.0\; \rm m \cdot s^{-1}\). (Assuming that the unit of the acceleration in this question is \(\rm m\cdot s^{-2}\).)

Explanation:

Let \(a\) denote the acceleration of this shark.

Let \(v_0\) denote the initial velocity of this shark.

Assume that the acceleration \(a\) of this shark is constant (as it is in this question.) Over a period of time \(t\), the shark would have travelled a distance of:

\(\displaystyle x = \frac{1}{2}\, a\, t^2 + v_0\, t\).

This question states that:

This question is asking for \(v_0\), the initial velocity of this shark at the beginning of this \(0.8\)-second period. Substitute the three known values into the equation:

\(\displaystyle 11.52 = \frac{1}{2}\times 16\times (0.8)^2 + 0.8\, v_0\).

Solve for \(v_0\):

\(v_0 = \displaystyle \frac{11.52 - (1/2) \times 16 \times (0.8)^2}{0.8} = 8.0\; \rm m \cdot s^{-1}\).

The final volume of the gas, when the pressure changes from 80.8 kPa to 101.3 kPa at constant temperature, is approximately 652.9 cm³.

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law can be represented by the equation: P₁V₁ = P₂V₂

Where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.

Given:

Initial volume, V₁ = 817 cm³

Initial pressure, P₁ = 80.8 kPa

Final pressure, P₂ = 101.3 kPa

We need to find the final volume, V₂.

Using Boyle's Law equation, we can rearrange it to solve for V₂:

V₂ = (P₁V₁) / P₂

Plugging in the given values:

V₂ = (80.8 kPa * 817 cm³) / 101.3 kPa

Simplifying the expression:

V₂ ≈ 652.9 cm³

Therefore, the final volume of the gas, when the pressure changes from 80.8 kPa to 101.3 kPa at constant temperature, is approximately 652.9 cm³.

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The wave function of the resultant wave, Y1 + Y2 is Y = 4.95sin[π(3.80x - 1180t - 0.206)].

The wave function Y1 describes a sinusoidal wave with an amplitude of 4.95 meters, a wavelength of λ = 2π/3.8 ≈ 1.65 meters, and a frequency of f = 1180/3.8 ≈ 310 Hz. The phase of the wave is such that the maximum displacement occurs at x = 0 and t = 0, and the wave is moving in the negative x direction.

The wave function Y2 also describes a sinusoidal wave with the same amplitude and wavelength as Y1, but with a phase difference of 0.25 seconds. This means that Y2 is shifted to the left (negative x direction) by a distance of Δx = λΔφ/2π = λ(0.25)/2π ≈ 0.206 meters. The frequency and speed of Y2 are the same as Y1.

To determine the resultant wave Y, we add the two wave functions: Y = Y1 + Y2. Using the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b), we can simplify the expression for Y:

Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t)cos(0.25) + cos(π/2)sin(0.25)]

Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t + 0.25)]

Y = 4.95sin[π(3.80x - 1180t - 0.206)]

The resultant wave Y is a sinusoidal wave with the same amplitude and wavelength as Y1 and Y2, but with a phase shift and a different waveform due to interference. The frequency and speed of Y are also the same as Y1 and Y2.

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-- The given question is incomplete, the complete question is

"Two traveling sinusoidal waves are described by the wave functions

Y1 : 4.95sin[π(3.80x-1180t)]

Y2 : 4.95sin[π(3.80x-1180t-0.250)]

Where x , y1 and y2 are in meters and t is in seconds. Find the wave function of the resultant wave (Y1 + Y2)." --

Answer:

Gravity

Explanation:

Based on Hooke's law, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

The spring constant or stiffness constant of an elastic spring is constant which describes the extent a bit forceapplied to an elastic spring will extend it.

Assuming, a body's muscle mechanism is a spring obeying Hooke's law, the effective mass of the spring with mass m is 1/3 of the mass of the spring = m/3

The potential energy that can be stored = ke^2 / 2

where K is spring constant and e is the extension produced.

Therefore, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

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The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Answer:

nice question but I don't know please forgive me

Answer:

Nice and very

Complicated question

Explanation:

I dont know