Yo im lost as hell I have no clue​

Answer:

\({ \sf{ \frac{dy}{dx} = y( {x}^{2} + 1)}} \\ \\ { \sf{ \frac{dy}{y} = ( {x}^{2} + 1)dx}} \\ \\ { \sf{ \int \frac{1}{y} dy = \int ( {x}^{2} + 1) \: dx}} \\ \\ { \sf{ ln(y) = \frac{ {x}^{3} }{3} + x + c }}\)

Answer:

\(\large\text{$y& = e^{\frac{1}{3}x^3+x+\text{C}}$}\)

Step-by-step explanation:

Given differential equation:

\(\dfrac{\text{d}x}{\text{d}y}=\dfrac{1}{y(x^2+1)}\)

Rearrange the equation so that all the terms containing y are on the left side, and all the terms containing x are on the right side:

\(\begin{aligned}\implies \dfrac{\text{d}x}{\text{d}y}&=\dfrac{1}{y(x^2+1)}\\\\(x^2+1)\;\dfrac{\text{d}x}{\text{d}y}&=\dfrac{1}{y}\\\\(x^2+1)\;\text{d}x}&=\dfrac{1}{y}\;\text{d}y\\\\\dfrac{1}{y}\;\text{d}y&=(x^2+1)\;\text{d}x}\end{aligned}\)

Integrate both sides:

\(\begin{aligned}\implies \displaystyle \int \dfrac{1}{y}\;\text{d}y &= \int (x^2+1)\;\text{d}x}\\\\\int \dfrac{1}{y}\;\text{d}y &= \int x^2\;\text{d}x}+\int 1\;\text{d}x}\\\\\ln y & = \dfrac{1}{3}x^3+x+\text{C}\\\\e^{\ln y} & = e^{\frac{1}{3}x^3+x+\text{C}}\\\\y& = e^{\frac{1}{3}x^3+x+\text{C}}\\\\\end{aligned}\)

Therefore, the solution to the given differential equation is:

\(\large\text{$y& = e^{\frac{1}{3}x^3+x+\text{C}}$}\)

Integration rules used:

\(\boxed{\begin{minipage}{3.5 cm}\underline{Integrating $\frac{1}{x}$}\\\\$\displaystyle \int \dfrac{1}{x}\:\text{d}x=\ln |x|+\text{C}$\end{minipage}}\)

\(\boxed{\begin{minipage}{3.5 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}\)

\(\boxed{\begin{minipage}{5 cm}\underline{Integrating a constant}\\\\$\displaystyle \int n\:\text{d}x=nx+\text{C}$\\(where $n$ is any constant value)\end{minipage}}\)

Answer:

it's a 0.1 seconds per copy

Answer:

P is 12

Step-by-step explanation:

It is just 20-8, which is 12

The solution of the system is then given by:

x = t[1 -1 1 0.5 0.5 0.33] + s[0 -2 1 1 -2 1]

This is the general solution of the system in the form of a sum of scalar multiples of fixed column vectors.

The system of linear equations can be written in matrix form as:

[1 0 1 2 1 3 | 1]

[2 1 2 4 0 10| 5]

[3 1 3 6 6 15| 8]

where the augmented matrix is [A | B].

To solve the system using the method of specifying appropriate free variables, we first convert the coefficient matrix into reduced row echelon form using Gaussian elimination.

In reduced row echelon form, the first non-zero element of each row (known as the leading entry) is 1, and the leading entries of lower rows are to the right of the leading entries of higher rows.

Applying Gaussian elimination to the coefficient matrix, we get:

[1 0 1 2 1 3 | 1]

[0 1 0 2 -2 7| 0]

[0 0 0 0 0 0| 0]

We can see that there are two non-zero rows, indicating that the system has two independent equations.

We can choose two of the variables to be free variables, and express the other variables in terms of the free ones.

Let's choose x1 and x3 as the free variables.

We can find x2 as follows:

x2 = -x1 - 2x3 + 7

And we can find x4, x5 and x6 as follows:

x4 = (1 - x1 - x3)/2

x5 = 1 - x1 - 2x3 + 2x4

x6 = (1 - x1 - x3 - 2x4)/3

So the general solution of the system can be expressed as a sum of scalar multiples of fixed column vectors:

x1 = t

x2 = -t - 2s + 7

x3 = s

x4 = (1 - t - s)/2

x5 = 1 - t - 2s + (1 - t - s)/2

x6 = (1 - t - s)/3

where t and s are scalars.

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The margin of error for a 95% confidence interval assuming the previous study enrolled 600 individuals is C . E = ± 4.00

Based on the information, the following can be deduced:

n = 600

mean = 490.

standard deviation = 50.

At 95% confidence interval, z will be:

= 1 - 95%

= 0.05

Using the distribution table, the value will be Z(0.05/2) = Z value of 0.025 = 1.96

Therefore, the margin of error for a 95% confidence interval assuming the previous study enrolled 600 individuals will be:

= ± 1.96 × 50/✓n

= ± 4.00

In conclusion, the correct option is C.

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K + 233= t

this is the equation.

Answer:

4 cups

Step-by-step explanation:

The average rate of change for the interval from x =  7 to x =  8 is 35.  

To calculate the average rate of change for the interval from x =  7 to x =  8, we need to find the difference in y- values and divide it by the difference inx-values within that interval.

Let's calculate it step by step using the given table  

For the interval from x =  7 to x =  8  x1 =  7, y1 = -37  x2 =  8, y2 = -2   Difference in y- values Δy =  y2- y1 = -2-(- 37) =  35  

Difference inx-values Δx =  x2- x1 =  8- 7 =  1  

Average rate of change =  Δy/ Δx =  35/ 1 =  35  

Thus, the average rate of change for the interval from x =  7 to x =  8 is 35.   Note: It's important to mention that the values calculated then are grounded solely on the given data. Please  insure you  corroborate the  delicacy of the  handed data and  environment before using the answer in any important or critical  operations.

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Solution :

The test is distributed normally with mean of 72.8 and the standard deviation of 7.3

Finding numerical limits for the D grade.

D grade : Scores below the top 80% and above the bottom 10%.

Let the bottom limit for D grade be \($D_1$\) and the top limit for D grade be \($D_2$\).

First find the bottom numerical limit for a D grade is :

\($P(X<D_1)= 0.10$\)

\($P(X\leq D_1)= 0.10$\)

\($P\left(\frac{X-\mu}{\sigma} \leq \frac{D_1-\mu}{\sigma}\right) = 0.10$\)

\($P\left(Z \leq \frac{D_1-72.8}{7.3}\right) = 0.10$\)    ..........(1)

From (1)

\($\frac{D_1 - 72.8}{7.3} = -1.28$\)

\($D_1 = -1.28(7.3)+72.8$\)

      = 63.45

       ≈ 64

Now the top numerical limit for D grade :

\($P(X>D_2)= 0.80$\)

\($1-P(X\leq D_2)= 0.80$\)

\($P(X\leq D_2)= 1-0.80$\)

\($P(X\leq D_2)= 0.20$\)

\($P\left(\frac{X-\mu}{\sigma} \leq \frac{D_2-\mu}{\sigma}\right) = 0.20$\)

\($P\left(Z \leq \frac{D_2-72.8}{7.3}\right) = 0.20$\)    ..........(2)

From (2)

\($\frac{D_2- 72.8}{7.3} = -0.84$\)

\($D_12= -0.84(7.3)+72.8$\)

      = 66.668

       ≈ 67

Therefore, the numerical limit for a D grade is 64 to 67.

Answer:

y = x + 3

Step-by-step explanation:

1 + 3 = 4

2 + 3 = 5

3 + 3 = 6

And so on

Answer:

1.255 seconds

Step-by-step explanation:

We can use the formula:

time = distance ÷ speed

to find the driver's time. Here, the distance is 200 miles and the speed is 159.5 miles per hour. Substituting these values into the formula, we get:

time = 200 miles ÷ 159.5 miles per hour

time = 1.255 seconds

True statements about the procedure implement a linear search, So the correct option is, ii only.

Linear search, also known as sequential search, is a simple search algorithm that iterates through an array or a list of elements one by one, starting from the first element, until the desired element is found.

The basic steps of linear search are:

The time complexity of the linear search is O(n), where n is the number of elements in the array/list.

This means that the algorithm takes n steps in the worst-case scenario to find the desired element in an array/list of n elements. Linear search is generally less efficient than other search algorithms like binary search for large data sets.

Linear search can be used on unsorted arrays/lists as well as on sorted arrays/lists. It is a simple and easy-to-implement algorithm and is suitable for small data sets or when the data is not sorted and the data changes frequently.

In addition, a linear search algorithm can also be used to find the index of the element in the array/list if the element is found.

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The angle between the ground and the steepest slope on the real rollercoaster is approximately 89.998°.

A model rollercoaster is built to a scale of 1:32. In the model rollercoaster, the angle between the ground and the steepest slope is 110°.What is the angle between the ground and the steepest slope on the real rollercoaster?

To determine the angle between the ground and the steepest slope on the real rollercoaster, you need to consider the scale of the model rollercoaster.To find the real rollercoaster angle, you should use a scale factor that relates the model rollercoaster to the real one.

The scale factor should multiply the model angle to obtain the real one. Since the scale factor relates the model length to the real length, it should relate the horizontal distance and the vertical height.

The horizontal and vertical lengths are in a ratio of 32:1 for the model. This means that for every 32 units in the model, there is one unit in the real rollercoaster. Therefore, we can say that the horizontal length of the real rollercoaster is 32 times the horizontal length of the model rollercoaster.

That is:h(real) = 32h(model)Similarly, the vertical height of the real rollercoaster is 32 times the vertical height of the model rollercoaster. That is:v(real) = 32v(model)

The tangent of an angle equals the vertical height divided by the horizontal distance. Therefore, the tangent of the real angle equals the tangent of the model angle times the scale factor.

That is:tanθ(real) = 32tanθ(model)By substitution,θ(real) = arctan(32tanθ(model))For the given model angle of 110°,

the corresponding real angle is:θ(real) = arctan(32tan110°)θ(real) = arctan(32(-2.74747741945462))θ(real) = arctan(-87.91927694142864)θ(real) ≈ -89.998°

The negative sign indicates that the angle is measured below the horizontal line.

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Answer:

(<) is the correct symbol

Step-by-step explanation:

6.534 is greater than 6.53

6.53 < 6.534

9514 1404 393

Answer:

  perpendicular: undefined

  parallel: zero

Step-by-step explanation:

The line y = -6 is a horizontal line. Between any two points on the line, the difference in y-values is zero, and the difference in x-values is non-zero. The slope of this horizontal line is the ratio of these differences:

  slope = 0/(non-zero) = 0

Any parallel line will have the same slope. The slope of a parallel line is 0.

__

A line perpendicular to a horizontal line is a vertical line. It will have the equation x = constant. Between any two points on the line, the difference in y-values is non-zero, and the difference in x-values is zero. The slope of this vertical line is the ratio of these differences:

  slope = (non-zero)/0 = undefined

The slope of the perpendicular line is undefined.

Answer: E

A number n is at least 17

This means n is greater than or equal to 17. n >= 17

Answer:

C 1/3

Step-by-step explanation:

out of the 6 possible moves you have the possibility of landing on question mark twice. 2/6 -> 1/3

Answer:

  y = {-1/2x +7 for x < 6; 1/2x +1 for x ≥ 6}

Step-by-step explanation:

You want y = 1/2|x -6| +4 written as a piecewise function.

The absolute value function changes its definition when its argument is negative:

  y = |x|   ⇒   y = -x for x < 0, and y = x for x ≥ 0

This means our piecewise function will have one definition for (x-6) < 0 and another for (x -6) ≥ 0.

The argument is negated in this domain, so we have ...

  y = -1/2(x -6) +4

  y = -1/2x +3 +4

  y = -1/2x +7

The absolute value function is an identity function in this domain:

  y = 1/2(x -6) +4

  y = 1/2x -3 +4

  y = 1/2x +1

Combining these descriptions into one, we have ...

  \(\boxed{y=\begin{cases}-\dfrac{1}{2}x+7&\text{for }x < 6\\\\\dfrac{1}{2}x+1&\text{for }x\ge6\end{cases}}\)

<95141404393>

Answer:

  17 bars

Step-by-step explanation:

Peter wants to compute the maximum number of bars he can load safely if the load limit of 1200 kg and the bar weight of 60 kg are each rounded to the number of significant digits those numbers have.

The error in a rounded number is assumed to be as much as half of the least significant digit of the number.

Peter's load limit may actually be as low as ...

  1200 kg - (1/2)(100 kg) = 1150 kg . . . . . . . 1200 is rounded to nearest 100

Peter's bar weight might be as high as ...

  60 kg + (1/2)(10 kg) = 65 kg . . . . . . . . . . . 60 is rounded to nearest 10

If Peter has maximum-weight bars and does not want to exceed the minimum his load limit might be, the number of bars he can load is ...

  (1150 kg) / (65 kg/bar) ≈ 17.7 bars

The greatest number of bars Peter can load safely is 17.

Answer:  15 percent

Step-by-step explanation:

If of the 2440 respondents to a survey. 1050 claimed to be worried about their health. The likelihood that a person selected at random will not be worried about their health is D. 56.97%.

The number of respondents who did not claim to be worried about their health is 2440 - 1050 = 1390.

So, the likelihood that a person selected at random will not be worried about their health is:

= 1390/2440 ×100

= 56.97%

Therefore there is a 56.97% chance that a person selected at random will not be worried about their health.

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(a) 40 unit have to be the number of units sold that will yield maximum revenue.

(b) The price per unit that will yield maximum revenue, will be $1.195.

(a) We have to find the number of units sold that will yield maximum revenue

Given demand function is

D(x)=130e^{-0.025x}

where is the number of units sold each week

Revenue function R(x) = xD(x)

R(x) = x∙130e^{-0.025x}

To find maximum revenue put,

R’(x) = 0

⇒d/dx(x∙130e^{-0.025x}) = 0

⇒130 d/dx(x∙e^{-0.025x}) = 0

⇒130[e^{-0.025x}+xe^{-0.025x} ∙(-0.025x)]=0

⇒130e^{-0.025x} ∙(1-0.025x)=0

⇒1 - 0.025x=0

⇒0.025x = 1

⇒x = 1/0.025

⇒x = 40units

R''(x) = 130d/d[x(e^{-0.025x}-0.025xe^{-0.025x} )]

R''(x) = 130[-0.025e^{-0.025x}-0.025e^{-0.025x}+0.00625xe^{-0.025x}]

R''(x)|x=40 = 130-0.025*40[0.050+0.00625*40]

R''(x)|x=40 = 130/e ∙(-0.025)

R''(x)|x=40 = (130*(-0.025))/e < 0

At x= 40 units, the revenue will maximize.

$0 units will yield maximum revenue.

(2) Now we have to find the price per unit that will yield maximum revenue.

D(x) = 130e-0.025x

D(40) = 130e^{-0.025*40}

D(40) = 130e^{-1}

D(40) = 130/e

D(40) = 47.82(in dollar)

Price per unit = d(40)/40

Price per unit = 47.82/40

Price per unit = $1.195

The price per unit that will yield maximum revenue, will be $1.195.

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Step-by-step explanation:

The ONE  solution to this system of two lines is the point where the two lines cross   at   (1,4)

Answer:

3/5=360 mph 11/12=550 4/15=160

Step-by-step explanation:

Answer:

2.204×\(10^{9}\)

Step-by-step explanation:

Convert to scientific notation.

156

Step-by-step explanation:

90+24+y=180

114+y=180

-114 -114

y = 66

66 + 90 = 156

The given percentage scores are:

80 , 92 , 91 , 75 , 89 , 84 , 0 , 85

A. Calculate the average

So, the average = (sum of the scores)/(number of the scores)

Sum of the scores = 80 + 92 + 91 + 75 + 89 + 84 + 0 + 85 = 596

The number of the scores = 8

So,

The average = 596/8 = 74.5%

Does the average score really represent her abilities ?

No, because there is outlier which is ( 0 ) which mean it may be absent this test

the other scores are within 75 and 92

Which mean the average is less than the reasonable minimum score

====================================================================

B. Brandee received 78% at the missed test

so, we will find the new mean:

The new sum of the scores = 80 + 92 + 91 + 75 + 89 + 84 + 78 + 85 = 674

The new mean = 674/8 = 84.25%

====================================================================

C. What different did 0% score make ?

So, 0% give us not accurate representation of the student abilities

Does this new mean represent her abilities accurately ?

Yes

Triangle ONM is congruent to Triangle CBA