you are boiling water to make pasta. How could you descibribe the pot, water, and pasta using physical properties?

Answer:

true

Explanation:

The half-life of hypothetical element  technetium-99 is 210,936 years.

Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.

Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.

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Answer:

the period of oscillation of the given object is 0.14 s

Explanation:

Given;

mass of the object, m = 3 kg

extension of the spring, x = 0.085 m

The spring constant is calculated as follows;

\(F = mg = \frac{1}{2} ke^2\\\\2mg = ke^2\\\\k = \frac{2mg}{e^2} \\\\k = \frac{2\times 3 \times 9.8}{(0.085)^2} \\\\k = 8,138.41 \ N/m\)

The angular speed of a 4 kg object is calculated as follows;

\(\omega = \sqrt{\frac{k}{m} } \\\\\frac{2\pi }{T} = \sqrt{\frac{k}{m} } \\\\T= 2\pi \sqrt{\frac{m}{k} } \\\\T = 2\pi \sqrt{\frac{4}{8138.41} }\\\\T = 0.14 \ s\)

Therefore, the period of oscillation of the given object is 0.14 s

Take into account that the Newton's second law is given by the following formula:

F = m·a

where:

F: force

m: mass

a: acceleration

when you solve the formula above for acceleration a, you obtain:

a = F/m

if the mass is quadruplied, you have:

a' = F/(4m) = 1/4 · F/m

a' = 1/4 · a

that is, the acceleation is reduced to one quarter of the initial acceleration.

The measure of the angle between three-dimensional vectors a and b; θ = acos(-0.5235) = 2.0463 radians, rounded to two decimal places.

In physics, vector is that quantity that has both direction and magnitude.

As, cos(θ) = (a · b) / (||a|| * ||b||)

Given, a = 3i - j - 2k, b = v + w where v = -2i - 3j + 2k and w = i +2k

So, a · b = (3i - j - 2k) · (v + w) = (3i - j - 2k) · (-2i - 3j + 2k + i + 2k)

a · b = (3i - j - 2k) · (-2i - 3j + 2k + i + 2k) = (-6i^2 + ji - 4ik) + (-3j - 2k + i + 2k) = -6 + 1 - 4 + (-3 - 2 + 1 + 2) = -4

||a|| = sqrt((3i - j - 2k) · (3i - j - 2k)) = sqrt(9 + 1 + 4) = sqrt(14) = 3.74166

||b|| = sqrt((v + w) · (v + w)) = sqrt((-2i - 3j + 2k + i + 2k) · (-2i - 3j + 2k + i + 2k)) = sqrt((-2i - 3j + 2k + i + 2k) · (-2i - 3j + 2k + i + 2k)) = sqrt((-4 - 6 + 4 + 1 + 4)) = sqrt(9) = 3

cos(θ) = (a · b) / (||a|| * ||b||) = -4 / (3.74166 * 3) = -0.5235

Hence, θ = acos(-0.5235) = 2.0463 radians, rounded to two decimal places.

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Answer:

The angle of elevation of the rocket is increasing at a rate of 48.780º per second.

Explanation:

Geometrically speaking, the distance between the rocket and the observer (\(r\)), measured in kilometers, can be represented by a right triangle:

\(r = \sqrt{x^{2}+y^{2}}\) (1)

Where:

\(x\) - Horizontal distance between the rocket and the observer, measured in kilometers.

\(y\) - Vertical distance between the rocket and the observer, measured in kilometers.

The angle of elevation of the rocket (\(\theta\)), measured in sexagesimal degrees, is defined by the following trigonometric relation:

\(\tan \theta = \frac{y}{x}\) (2)

If we know that \(x = 5\,km\), then the expression is:

\(\tan \theta = \frac{y}{5}\)

And the rate of change of this angle is determined by derivatives:

\(\sec^{2}\theta \cdot \dot \theta = \frac{1}{5}\cdot \dot y\)

\(\frac{\dot \theta}{\cos^{2}\theta} = \frac{\dot y}{5}\)

\(\frac{\dot \theta\cdot (25+y^{2})}{25} = \frac{\dot y}{5}\)

\(\dot \theta = \frac{5\cdot \dot y}{25+y^{2}}\)

Where:

\(\dot \theta\) - Rate of change of the angle of elevation, measured in sexagesimal degrees.

\(\dot y\) - Vertical speed of the rocket, measured in kilometers per hour.

If we know that \(y = 4\,km\) and \(\dot y = 400\,\frac{km}{h}\), then the rate of change of the angle of elevation is:

\(\dot \theta = 48.780\,\frac{\circ}{s}\)

The angle of elevation of the rocket is increasing at a rate of 48.780º per second.

Endothermic reactions are chemical processes that generate products by absorbing heat energy from the environment around the reactants.

One of the greatest illustrations of an exothermic reaction is the exploding of a firecracker, which emits a loud bang along with light and heat. Lighting a candle is an ongoing process in which the wax serves as fuel and sustainably produces a flame.

Exothermic reactions are those that release heat energy through chemical processes. C(g)+O2(g)+CO2(g)+Heat Energy is an example. Endothermic reactions are the ones that involve the absorption of heat energy. For instance, CaO+CO2Heat CaCO3.

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Answer:

condensation and deposition

Explanation:

when something gets cooler it's molecules lose kinetic energy and that applies only in condensation and depostion

Explanation: For some reason, it would not let me click the "ADD YOUR ANWER" button, because it stated that my answer had some sort of "Inappropriate" word or something, so instead I attached two images of the answer that I had written down.

Flute, Clarinet, Saxophone, Piccolo, Tenor Sax oboe

Piccolo

Flute

Clarinet

Saxophone (all registers)

Oboe

English Horn

Bassoon

Answer:

It curves inward

Explanation:

Of the choices given it is the only one that makes sense

Considering the concave mirror to be a part of a large sphere and the outer surface polished, we can say it curves inward.

There are three types of mirrors: plain mirrors, convex mirrors, and concave mirrors.

The plain mirrors are the ones which we use in our houses. It has both the sides flat, front and back. With the back end polished to reflect light.

It is obvious that the back end of the mirror must be silvered or polished in order to reflect light.

In the case of concave mirrors, if we consider it a part of a large sphere, then the outer surface is silvered or polished and the inner surface is the surface that is used as a mirror,

So, we can say that a concave mirror curves inward.

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The total distance covered by the car is 300 miles.

The total displacement covered by the car is zero.

The average speed of the car is 17.88 m/s.

The average velocity of the car is also zero.

Distance between the points A and B, d = 150 miles

Time taken by the car to travel from A to B, t₁ = 3 hours

Time taken by the car to travel from B to A, t₂ = 5 hours

a) Given that the car travelled from A to B and then back to A.

Therefore, the total distance covered by the car is,

Distance = 2 x d

Distance = 2 x 150

Distance = 300 miles

Since the car is travelling from A to B and then returning back to the initial point A, the total displacement covered by the car is zero.

b) The speed with which the car travelled from A to B is,

v₁ = d/t₁

v₁ = 150/3

v₁ = 50 miles/hr

v₁ = 22.35 m/s

The speed with which the car travelled from B to A is,

v₂ = d/t₂

v₂ = 150/5

v₂ = 30 miles/hr

v₂ = 13.41 m/s

Therefore, the average speed of the car is,

v = (v₁ + v₂)/2

v = (22.35 + 13.41)/2

v = 17.88 m/s

As, the total displacement of the car is zero, the average velocity of the car is also zero.

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Shivering is a response of an organism when the temperature drops. In shivering,  muscles contract and expand quickly and the body temperature rises​.

Warm-blooded animals shiver (also known as shudder) as a physiological reaction to cold and acute fear. To preserve homeostasis, the shivering reaction is activated when the body's core temperature lowers.

Small skeletal muscle movements start, producing warmth as the muscles use up their energy. Another sign of a fever is shivering because the person may feel cold.

The hypothalamic set point for temperature rises during a fever. Up until the new set point is reached, the patient experiences cold until the increased set point raises body temperature (pyrexia).

Rigors are the medical term for extremely cold symptoms accompanied by ferocious shivering. Rigors happen as a result of the patient's body shivering in an effort to physiologically raise body temperature to the new set point.

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Explanation:

Given that,

The force between two charges, \(F=2.2\times 10^{-4}\ N\)

New force becomes, \(F'=4.4\times 10^{4} N\)

We see that, the new force is 2 times more than the initial force.

The force is directly proportional to the product of forces and inversely to the square of the distance between charges.

It means, one of the charges gets doubled and it results in the doubling of force.

The new charge is 2 ×10⁸ times the old charge.The force is directly proportional to the product of charge;

The electric force between the two charges is directly propotional to the product of the charge and inversly propotional to the square of the distance between them.

The given data in the problem is;

q₁ is the megnitude of charge 1

q₂ is the megnitude of charge 2

k is the proportionality constant = 9 x 10⁹ Nm² / C²

r is the separated distance

F is the electric force=2.2  x 10-4 N

F' is the new electric force= 4.4 X 104 N.

The force is directly proportional to the product of charge;

\(\frac{F'}{F} =2 \times 10^8 \\\\ \frac{q_1 q_2}{q_1'q_2'} = 2 \times 10^8\\\\ \frac{q_1}{q_1'}= 2 \times 10^8 \\\\ q_1=2 \times 10^8 q_1'\)

Hence the new charge is 2 ×10⁸ times the old charge.

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Answer:

False

Explanation:

Friction force is a force that opposes the relative lateral motion of two solid surfaces in contact.

Answer:

As thermal energy increases,there is more particle movement

X corresponds to 20 mm on the thermometer.

To calculate the value of X, we can use the concept of linear interpolation.We can estimate a value between two known points on a straight line using linear interpolation.

In this case, we have three data points: X corresponding to an unknown temperature, 60 °C corresponding to 52 mm, and 100 °C corresponding to 50 mm.

We can set up a proportion based on the relationship between temperature and the corresponding position on the thermometer:

(60 - X) / (100 - X) = (52 - 50) / (50 - X)

Simplifying the proportion:

(60 - X) / (100 - X) = 2 / (50 - X)

Cross-multiplying:

(60 - X)(50 - X) = 2(100 - X)

Expanding and simplifying:

3000 - 110X + X^2 = 200 - 2X

Putting all terms on the same side of the equation:

X^2 - 108X + 2800 = 0

Solving this quadratic equation yields two solutions: X = 20 and X = 88.

However, since the ice and steam points on a thermometer typically correspond to 0 °C and 100 °C, respectively, we can eliminate the X = 88 solution. As a result, the value of X is 20.

Therefore, X corresponds to 20 mm on the thermometer.

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Answer:

Explanation:

Since the stove is moving with a constant velocity, we know that the net force on the stove is zero. Therefore, the force of friction acting on the stove must be equal in magnitude and opposite in direction to the horizontal force being applied by the contractor. We can use Newton's second law to solve for the normal force and force of friction:

ΣF = ma

where ΣF is the net force, m is the mass of the stove, and a is the acceleration of the stove (which is zero in this case).

First, we need to convert the velocity to m/s and the forces to Newtons (N):

18 cm/s = 0.18 m/s

85 N [fwd] - force applied by contractor

447 N [down] - force of gravity on the stove

Now we can solve for the normal force:

ΣFy = 0 (since the stove is not accelerating in the y-direction)

FN - 447 N = 0

FN = 447 N

Therefore, the normal force acting on the stove is 447 N.

Next, we can solve for the force of friction:

ΣFx = 0 (since the stove is moving at a constant velocity)

Ff - 85 N = 0

Ff = 85 N [bkwd]

Therefore, the force of friction acting on the stove is 85 N [bkwd].

Finally, we can solve for the total force applied by the floor:

ΣF = ma = 0 (since the stove is not accelerating)

Ffloor - 85 N - 447 N = 0

Ffloor = 532 N [up]

Therefore, the total force applied by the floor on the stove is 532 N [up].

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Answer:

Third parties may also help voter turnout by bringing more people to the polls. Third party candidates at the top of the ticket can help to draw attention to other party candidates down the ballot, helping them to win local or state office.

Answer:

IM answering so you can give the other guy brain cuz he smart.

Explanation:

Answer:

λ = 0.4 x 10⁻⁶ m = 400 nm

Explanation:

The relationship between frequency, wavelength and speed of an electromagnetic wave is given as follows:

\(c = f\lambda\)

where,

c = speed of light = 3 x 10⁸ m/s

f = frequency of the light wave = 7.5 x 10¹⁴ Hz

λ = wavelength of the light = ?

Therefore,

\(3\ x\ 10^8\ m/s = (7.5\ x\ 10^{14}\ Hz)\lambda\\\\\lambda = \frac{3\ x\ 10^8\ m/s}{7.5\ x\ 10^{14}\ Hz}\)

λ = 0.4 x 10⁻⁶ m = 400 nm

Answer:

D

Explanation:

You are boiling more grams for more time because the more water the longer it takes which requires more calories to burn it.

The point through which this ray will pass, after refraction by the lens is point D.

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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Expression for the electric potential a distance z away from the center of rod on the line that bisects the rod is \(V = k * Q / L * \int\limits {cos\theta / z \sqrt{(1 + L^2/4z^2 * tan^2\theta)} d\theta} \, dx\).

The electric potential at a distance z from a point charge Q is given by:

V = k * Q / r

here

k is Coulomb constant and

r is distance from the point charge to the point.

For a thin rod of length L and charge Q, we can model it as a line of charge with linear charge density λ = Q/L. The electric potential at a distance z away from the center of the rod on the line that bisects the rod can be found by breaking the rod into infinitesimal charge elements and integrating the electric potential due to each element over the length of the rod.

Let's consider a small element of length dx located at a distance x from the center of the rod:-

\(dQ = \lambda * dx = Q/L * dx\)

The displacement element to pt.:-

\(r = \sqrt{(x^2 + z^2)}\)

The electric potential due to this element is:

\(dV = k * dQ / r = k * Q/L * dx / \sqrt{(x^2 + z^2)}\)

Integrating this expression over the length of the rod, we get the total electric potential at a distance z away from the center of the rod on the line that bisects the rod:

\(V = \int\limits^(^-^L^/^2^)_L_/_2 {k * Q/L * dx / √\sqrt{(x^2 + z^2)}} \, dx\)

To evaluate this integral,

\(u = x^2 + z^2, du/dx = 2x dx\),

This can be further simplified:-

\(u = z^2 * tan^2\theta + L^2/4 * sec^2\theta\)

\(V = k * Q / L * \int\limits {cos\theta / z \sqrt{(1 + L^2/4z^2 * tan^2\theta)} d\theta} \, dx\)

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Answer:

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 200 × 9.8 × 50

We have the final answer as

Hope this helps you

Answer:

Kinetic energy is energy an object possesses due to its motion.

Kinetic energy equation: \(KE = \frac{1}{2} mv^{2}\)

The faster and heavier an object is, the higher the kinetic energy.

Potential magnetic energy is the energy of an object that is able to do work because of its position in a magnetic field.