You are managing a large feed lot. A pharmaceutical company wants you to try a new antibiotic to treat shipping fever in newly arrived cattle. The company claims that it is more effective at a lower cost than your current antibiotic.

Answer:

$474.30

Explanation:

23.25 × 102 = 2371.5 (total amount of money produced from pallets)

2371.5/5 = 474.3 (payout per worker)

The choice of solution has a concentration of 1.144 mol/kg molality.

Molarity corresponds to the moles of solvent divided by the amount of solution in litres, whereas molality is equal with the moles of solvent divided by the quantity of solvent in kilogrammes.

Since 1 mole of solute is present in 1 litre for the solution, which contains both the solute and the solvent, 1 molar aqueous solutions are more concentrated than one decays aqueous solutions.

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Answer:

See figure 1

Explanation:

For this reaction, we have the production of a carbanion as the first step. The base "ethoxide" can remove a hydrogen-producing a negative charge in the carbon (enolate anion 1). Then this negative charge can attack the carbon of the carbonyl group in the molecule acetaldehyde and the tetrahedral intermediate 2 is form. In the next step, we have the protonation of the oxygen to produce alcohol 3. A continuation we have the hydrolysis of the ester groups to produce the Dicarboxyamino alcohol and finally, we have a decarboxylation reaction we will produce the amino acid Threonine.

To further explanations see figure 1

I hope it helps!

Making a pesticide from a 5-atom alkane to an 18-atom molecule requires a complex process involving many steps and various reactions.

There are many different insecticides on the market, each with a unique chemical composition and mode of operation. The desired end product will determine the exact reactions and conditions needed to make a pesticide from the alkane. In general, making a pesticide from an alkene requires several important steps, including oxidation, halogenation, and cyclization. The first step is the oxidation or halogenation of the alkene to produce a more reactive intermediate.

Therefore, the correct option is D.

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Your question is incomplete, most probably the complete question is:

The processes which are used to convert alkane consists of 5 atoms to insecticide consists of (18) atoms are

a) strong heating then rapid quenching then halogenation then polymerization

b) polymerization then halogenation then strong heating then rapid quenching

c) strong heating then rapid quenching then polymerization then halogenation halogenation then rapid quenching then strong heating then polymerization​

d) The synthesis of an insecticide from an alkane with 5 atoms to a molecule with 18 atoms requires multiple steps and the specific reactions and conditions used will depend on the insecticide being synthesized.

Answer:

30, 50

Explanation:

Hello,

In this since an element's atomic number is equal to the number of protons in its atom, we can infer that selenium's atomic number is 30. Moreover, due to the fact the the neutrons are equal to the atomic mass minus the atomic number or the number of protons, by knowing the number of neutrons we compute the atomic as follows:

\(neutrons=mass-protons\\\\mass=neutrons+protons\\\\mass=30+20\\\\mass=50a.m.u\)

Thus, answer is 30, 50.

Best regards.

The pressure in the cylinder must have been 919.5 kPa.

The pressure in the cylinder is calculated by applying general gas equation as follows;

P₁V₁/T₁ = P₂V₂/T₂

where;

P₂ = (P₁V₁T₂/T₁V₂)

The initial temperature of the cylinder = 12⁰C = 285 K

The final temperature of the cylinder = 21⁰C = 294 K

P₂ = (95.5 x 14 x 294/285 x 1.5)

P₂ = 919.5 kPa

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Answer:

Difference between Contact and Non-Contact Forces

There is no field linked with the contact force. There is always a field linked with non-contact force. The frictional force is an example of a contact force. Gravitational force is an example of a non-contact force.

Explanation:

And it is physics not chem.

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Answer:

Copper will start to react with the oxygen in the air to form copper oxide. The copper oxide will continue reacting to oxygen over time. As the copper oxide continues to react with carbon dioxide and water in the air it coats the surface with that iconic blue-green patina colour

(a) The hazard quotient is:

HQ = Intake / RfD = 0.0002 mg/day / 0.02 mg/kg/day = 0.01

(b) The cancer risk is 1 in 10,000.

(c) The cancer risk is 1 in 1,000.

Hazard quotient (HQ) is a measure used in risk assessment to evaluate the potential health risk posed by exposure to a chemical or other hazard. It is calculated as the ratio of the dose or exposure level of the chemical to a reference dose (RfD) or reference concentration (RfC) established by regulatory agencies or scientific bodies as a safe level of exposure. If the hazard quotient is greater than 1, it suggests that the level of exposure is of potential concern and additional risk assessment may be needed.

(a) The hazard quotient (HQ) is calculated as the daily intake of a chemical divided by its reference dose (RfD). The RfD for 1,1-dichloroethylene is 0.02 mg/kg/day.

The daily intake of 1,1-dichloroethylene can be calculated as:

Intake = concentration × ingestion rate × body weight

Intake = 0.1 μg/L × 2 L/day × 70 kg = 14 μg/day = 0.0002 mg/day

The hazard quotient is:

HQ = Intake / RfD = 0.0002 mg/day / 0.02 mg/kg/day = 0.01

(b) The cancer risk from exposure to 1,1-dichloroethylene can be estimated using the unit risk factor (URF) for this chemical, which is 0.5 per mg/kg/day. The cancer risk is calculated as:

Risk = Intake × URF = 0.0002 mg/day × 0.5 per mg/kg/day = 0.0001

Therefore, the cancer risk is 1 in 10,000.

(c) If the individual drinks this water for 30 years, the total exposure would be:

Exposure = Intake × 365 days/year × 30 years = 2.19 mg

The new hazard quotient is:

HQ = Exposure / (RfD × body weight) = 2.19 mg / (0.02 mg/kg/day × 70 kg) = 1.57

The new cancer risk is:

Risk = Exposure × URF = 2.19 mg × 0.5 per mg/kg/day = 1.10

Therefore, the cancer risk is 1 in 1,000.

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The chemical formula for copper(II) sulfate is CuSO4.

Copper(II) sulfate is a chemical compound that is made up of copper, sulfur, and oxygen. It has the chemical formula CuSO4 and is commonly referred to as "blue vitriol" or "bluestone." Copper(II) sulfate can be prepared by reacting copper oxide or copper metal with sulfuric acid. It is a blue-colored crystalline solid that dissolves easily in water.

Copper(II) sulfate has many uses in industry and can be used as a fungicide, herbicide, pesticide, and in the manufacture of other chemicals. It is also commonly used in schools and laboratories as a reagent in chemical reactions and experiments.

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Answer:

\(\bold{Heya!}\)

Wowie- nice cat... plus, he or she is fluffy...

Have a great day!

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\(\underline{Answer :}\)

XxVioletXx

Answer: The answer is B,C,D

Explanation: Solar activity can affect satellite orbits, communication satellites, and the local power grids. It can also impact our spacecraft throughout the solar system, especially orbiters or landers on surfaces without an atmosphere.

therefore, Solar flares and coronal mass ejections can disrupt communications, damage satellites and can cause power outages on Earth.

During high periods of activity, the higher amount of heat radiating from the Sun will melt satellites, disrupting communications.

Coronal holes allow more of the Sun’s material to flow out into space.

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The options that apply are:

B. Solar flares and coronal mass ejections can disrupt communications, damage satellites, and can cause power outages on Earth.

D. Coronal holes allow more of the Sun’s material to flow out into space.

Coronal holes, mentioned in option D, allow more of the Sun's material to flow out into space. This primarily affects the solar wind, which consists of charged particles emitted by the Sun. The increased solar wind from coronal holes can impact spacecraft and satellites throughout the solar system.

Solar flares and coronal mass ejections, mentioned in option B, are intense bursts of energy and matter from the Sun. These events can release a large number of charged particles and electromagnetic radiation. When directed towards Earth, they can interfere with satellite communications, damage sensitive electronic equipment, and disrupt power grids, potentially causing power outages.

Option A, stating that coronal holes reduce the amount of material leaving the Sun, is incorrect. Coronal holes allow more material, particularly the solar wind, to flow out into space, as mentioned in option D.

Option C, suggesting that the higher amount of heat radiating from the Sun during high activity melts satellites, disrupting communications, is not accurate. While solar activity can increase radiation levels in space, it does not typically lead to satellite melting or disruption of communications due to excess heat.

Therefore, the correct options are B and D. Solar flares and coronal mass ejections can disrupt technology on Earth, and coronal holes allow more material from the Sun to flow into space.

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Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume = 62 mL

density = 1.02 g/mL

The mass of the water is

mass = 1.02 × 62

We have the final answer as

Hope this helps you

Answer:

all cells are produced from other preexisting cells through cell division

The gravimetric factor for Br- using silver bromide is 0.425.

The gravimetric factor is an expression that is used to convert grams of a compound into grams of a single element.

It is expressed as a ratio of the formula weight (FW) of the substance that is being determined to that of a second substance that is weighed.

For example formula of silver bromide is AgBr and the formula mass of silver bromide is 188 g/mol

Formula mass of bromide ion = 80 g/mol

Gravimetric factor = 80/1188

Gravimetric factor = 0.425

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Answer:

Amplitude

Explanation:

Answer:

0.10 amps

Explanation:

If an equation includes 7(CrO₄)₂, the numbers of Cr's and O's atoms that are there are 14 and 56 respectively.

The number of atoms present in a chemical compound can be calculated by multiplying the subscript of the particular element by any coefficient.

According to this question, 7 moles of chromate with the chemical formula; (CrO₄)₂ is given. The number of oxygen and chromium atoms in this compound can be calculated as follows:

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Answer:

Yes it is B,D.

Explanation:

Each box represents an element and contains its atomic number, symbol, average atomic mass, and (sometimes) name. The elements are arranged in seven horizontal rows, called periods or series, and 18 vertical columns, called groups.

Answer:

Boiling T° of solution  → 83.6°C

Explanation:

To solve this, we apply Elevation of boiling point, property

ΔT = Kb . m . i

As we talk about organic solute, i = 1. No ions are formed.

m = molality (moles of solute in 1kg of solvent)

We determine mass of solvent by density

D = m /V so D . V = m

950 mL . 0.877 g/mL = 833.15 g

We convert to kg → 833.15 g . 1 kg/ 1000g = 0.833 kg

Moles of solute (naphtalene): 150 g . 1 mol/ 128.16g = 1.17 mol

m = 1.17mol / 0.833 kg = 1.41 mol/kg

We replace data:

Boiling T° of solution - 80.1°C = 2.53°C/m . 1.41 m . 1

Boiling T° of solution = 2.53°C/m . 1.41 m . 1  +  80.1°C → 83.6°C

Answer:

The answer is c or 17.1 g

Answer:

Explanation:

CH₄ + 2O₂ = CO₂ + 2H₂O

1 mole + 2 moles  = 1 moles + 2 moles

10.1 gm of methane = 10.1 / 16 = .63 moles of methane

58 g of oxygen = 58 / 32 = 1.8125 moles of oxygen

1 moles of methane reacts with 2 moles of oxygen to make 1 mole of CO₂

.63 moles of methane reacts with 1.26 moles of oxygen to make .63 mole of

CO₂

so CO₂ formed = .63 moles

.63 x 44 = 27.7 grams of CO₂

The standard deviation of the sample is 0.579, rounded to the correct number of significant figures.

To calculate the standard deviation of the sample, we need to follow these steps:

To find the mean, we sum up all the data points and divide by the number of data points. Let's calculate it:

(3.09 + 4 + 2.775 + 2.5 + 3.80) / 5 = 16.165 / 5 = 3.233

To do this, we subtract the mean (3.233) from each data point and square the result:

(3.09 - 3.233)^2 = 0.020049

(4 - 3.233)^2 = 0.586489

(2.775 - 3.233)^2 = 0.209025

(2.5 - 3.233)^2 = 0.537289

(3.80 - 3.233)^2 = 0.323329

To find the variance, we sum up the squared differences from step 2 and divide by the number of data points:

(0.020049 + 0.586489 + 0.209025 + 0.537289 + 0.323329) / 5 = 1.676181 / 5 = 0.3352362

√0.3352362 = 0.579 (rounded to three significant figures)

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The reduction half-reactions for O, P, and Cu:

• O: O2 + 4 e- → 2 O2-

• P: HPO42- + 2 H+ + 2 e- → H3PO4

• Cu: Cu2+ + 2 e- → Cu+

To write the reduction half-reactions for O, P, and Cu, we need to determine the oxidation numbers for each element. The guidelines for assigning oxidation numbers are:

Using these guidelines, we can determine the oxidation numbers for O, P, and Cu:

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Answer:

B

Explanation:

took the test

D. It should have a half-life much longer than the age of the object being dated. When using isotopes for dating purposes, it is important to choose an isotope with a half-life that is significantly longer than the age of the object being dated.

The half-life is the time it takes for half of the radioactive isotopes in a sample to decay into stable isotopes. By measuring the ratio of the original radioactive isotope to the decay product, scientists can determine the age of the object.

The majority of the radioactive material would have decayed if the isotope had a half-life substantially less than the age of the artefact, making it challenging to precisely establish the age.

On the other hand, the dating procedure would become more challenging and unpredictable if the isotope in the object being dated (option C) has a half-life that varies over time.

As a result, an isotope with a long half-life offers a stronger basis for precise dating since it enables sufficient radioactive decay to take place, producing quantifiable and trustworthy data.

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Answer:

Atom

Explanation:

Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom Atom AtomAtom Atom Atom

Answer:

See Explanation

Explanation:

Both oxygen and dinitrogen (1) oxide are known to rekindle a glowing splint. However, oxygen is an odorless gas while dinitrogen (1) oxide has a faint smell and has an effect on the central nervous system.

Also, the combustion of dinitrogen (1) oxide produces brown fumes of nitrogen IV oxide.

Finally, when dinitrogen (1) oxide and oxgen are both heated with copper, residual nitrogen gas is left with dinitrogen (1) oxide while no residual gas is left with oxygen.

Answer:

True.

Explanation:

Since electromagnetic radiation travels in waves, we can assume that the more high energy the waves are, the faster they will go. So therefore, higher energy travels faster.

Hope that helps you!

Answer:

True

Explanation: