you are testing a jet back pack on a dummy. you start it rising with an upward acceleration of 3 m/sec/sec. after 9 seconds the jetpack fails (upward acceleration stops, gravity takes over). how fast is the dummy moving when it hits the ground?

Answer:

Final momentum after a head on collision is -2kgm/

Explanation:

  One ball moves to the right and the other moves opposite  and momentum is a vector quantity so that considering the direction

Initial momenta are        P₁=2x3=6kgm/s        P₂=4x(-2)=-8kgm/s      

Final momentum is the vector sum of P(final)= 6-8= -2 kgm/s

The equation to obtain the vertical distance cobered by the object is,

The acceleration due to gravity on saturn is 0.066 m/s2.

Plug in the known values,

Thus, the time taken by object to fall is 17.4 s.

The work done in stretching the spring from its natural length to 10 inches beyond its natural length is 112 lb·in.

The work done in stretching a spring is given by the formula:

\(\[ W = \frac{1}{2} k (x_f^2 - x_i^2) \]\)

In this case, the spring is stretched 4 inches beyond its natural length, so the initial displacement is 4 inches. The force required to hold the spring at this displacement is 16 lb. We can use Hooke's Law to find the spring constant:

\(\[ k = \frac{F}{x_i} = \frac{16 \, \text{lb}}{4 \, \text{in}} = 4 \, \text{lb/in} \]\)

Now, we can calculate the work done in stretching the spring to 10 inches beyond its natural length:

\(\[ W = \frac{1}{2} (4 \, \text{lb/in}) \left( (10 \, \text{in})^2 - (4 \, \text{in})^2 \right) = 112 \, \text{lb·in} \]\)

Therefore, the work done in stretching the spring is 112 lb·in.

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Answer:

C?

Explanation:

Recall, Newton's gravitational law states that any particle of matter in the universe attracts any other particle with a force varying directly as the product of their masses and inversely as the square of the distance between them. It is expressed as

F = Gm1m2/r^2

where

F is the force in Newton

G is gravitational constant = 6.673 x 10^-11 Nm^2/kg^2

m1 and m2 are the masses in kg

r is the distance in meters

From the information given,

r = 1.5

acceleration = 2cm^2/s

Recall, 100 cm = 1m

2 cm = 2/100 = 0.02m

Thus,

acceleration = 0.02m/s^2

Since the masses are identical, then m1 = m2

Each of them is accelerating at 0.02m/s^2

Recall,

Force = mass x acceleration

Force = m1 x 0.02 = 0.02m1 N

By substituting the given values into the formula, we have

0.02m1 = (6.673 x 10^-11 x m1 x m1)/1.5^2

m1 on the left cancels out one m1 on the right. It becomes

0.02 = (6.673 x 10^-11 x m1)/1.5^2

By crossmultiplying,

0.02 x 1.5^2 = 6.673 x 10^-11 x m1

0.045 = 6.673 x 10^-11 x m1

m1 = 0.045/6.673 x 10^-11

m1 = 6.74 x 10^8 kg

The mass of each ball is 6.74 x 10^8 kg

The arrow leaves the bow at a speed of 40.47 m/s.

When the arrow is released from its bow, the arrow will move and accelerate. Newton's second law of motion applies to the arrow. The formula F = ma

\(a \:=\: \frac{F}{m}\)

\(a \:=\: \frac{89.0}{0.0850}\)

a = 1,047.059 m/s²

When the object has acceleration, the object will move in a non-uniform motion. The formula

v² = u² + 2ad

v² = 0² + (2×1,047.059×0.782)

v² = 1,637.6

\(v_t \:=\: \sqrt{1,637.6}\)

\(v_t\) = 40.47 m/s

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Answer:

176.4 m

Explanation:

To calculate the distance, the equation would be:

distance = acceleration X time² / 2

Assuming the stone is held at a complete stop before dropping, the acceleration would be equal to gravity which is 9.8m/s².  So:

d = (9.8m/s²)( 6s)² / 2

   = (9.8m/s²)(36s²) / 2

   = 176.4 m

The reactance of the 260 mH radio coil connected to the 240 V (rms) 10.0 kHz AC line is approximately 1633.6 Ω, and the RMS current flowing through the circuit is approximately 0.147 A.

To calculate the reactance (X) of the 260 mH radio coil and the RMS current (I) in the circuit, we can use the following formulas:

Reactance (X) = 2πfL,

RMS current (I) = V / X,

where f is the frequency, L is the inductance, V is the voltage, and X is the reactance.

Given:

Inductance (L) = 260 mH = 0.260 H,

Voltage (V) = 240 V,

Frequency (f) = 10.0 kHz = 10,000 Hz.

Calculating the reactance:

X = 2πfL = 2π(10,000 Hz)(0.260 H) ≈ 1633.6 Ω.

To calculate the RMS current, we can use Ohm's law:

I = V / X = 240 V / 1633.6 Ω ≈ 0.147 A (rounded to three significant digits).

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Answer: B) 100N

Explanation:usatestprep

Answer:

4 m/s south

Explanation:

This is a pretty easy one.

Assume that the car has a reference point ragged x

We also know that the car starts moving at a point 10 m North of X. It moves steadily at a uniform velocity and ended at a position 10 m south of X.

If x is the reference point, we can infer that the car moves a total distance of, 10 m + 10 m.

Thus, the total distance moved by the car is 20 m.

It is also stated that it achieves that distance in 5 seconds.

Velocity is defined as the ratio of distance with respect to the tome taken, i.e V = d/t

Then, the velocity is

V = 20 / 5 = 4 m/s

Considering the fact that the car left and moved towards the south. We can say that it moved 4 m/s South.

Answer:

The bottom line

That's because our internal clocks tend to use up the most calories from 4 p.m. to 6 p.m. and the least from 4 a.m. to 6 a.m., researchers concluded. If we're up late and eating when our bodies are using up fewer calories, those calories get stored instead, which can result in weight 

Explanation:

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I can try to help if you speak English

Answer:

π/2 radians.

Explanation:

Angular Displacement

It's the angle expressed in radians, degrees, revolutions, etc. through which a point revolves around a point called the center.

To find the angular displacement, we must recall a full revolution, or turn around the center measures 360 degrees, or 2π radians.

The Earth completes a turn every 24 hours. This means that in 6 hours, it has given 6/24 = 1/4 of a turn.

This means that, measured in radians, the angular displacement of a person during 6 hours is:

1/4*2π radians

Simplifying:

π/2 radians.

The maximum energy stored in the spring bumpers is given as ¹/₂kx².

The maximum energy stored in a spring is given by the following equations;

E = ¹/₂kx²

where;

Thus, the maximum energy stored in the spring bumpers is given as ¹/₂kx².

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Rightward acceleration is 16.5 m/s² and the net force is 165 N. The acceleration of an object is determined by its mass divided by the net force acting on it, in accordance with Newton's second law of motion.

The total of all forces exerted on an object is known as the net force. A mass can accelerate due to net force. A body is subject to another force whether it is at rest or in motion.

A moving item accelerates due to resultant force. Always moving in the same manner as the net force is acceleration. When something is being pushed to the right with more force than resists and its resultant torque is to the right, it will accelerate to the right.

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The Doppler Effect in Physics is a phenomenon that occurs when there is a change in the frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source.

The Doppler effect occurs when there is relative motion between a source or receiver of sound or electromagnetic waves, resulting in a change in the observed frequency of the waves.

This effect is commonly observed in the change in pitch of a siren as it moves towards or away from an observer. As the siren moves towards the observer, the sound waves are compressed, causing the frequency to increase and the pitch to become higher. Conversely, as the siren moves away from the observer, the sound waves are stretched, causing the frequency to decrease and the pitch to become lower.

The Doppler Effect also applies to light waves, causing the color of an object to shift towards the blue end of the spectrum as it moves towards an observer, and towards the red end of the spectrum as it moves away.

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Answer:

an atom with 3 protons and 4 neutrons

Explanation:

Answer:

a) v₂ = 4.2 m/s

b) v₂ = 5 m/s

Explanation:

a)

We will use the law of conservation of momentum here:

\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0.8 m/s

v₂ = speed of second after before collsion = ?

Therefore,

\((1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s\)

v₂ = 4.2 m/s

b)

We will use the law of conservation of momentum here:

\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0 m/s

v₂ = speed of second after before collsion = ?

Therefore,

\((1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)\)

v₂ = 5 m/s

To determine the new force of gravity in the first scenario, we can use the formula for gravitational force:

\(Fg = (G * m1 * m2) / r^2,\)

where G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers.

If we triple the mass of one object and double the distance between their centers, the new force of gravity can be calculated as follows:

New \(Fg = (G * (3m) * m) / (2r)^2.\)

Simplifying this expression, we get:

New Fg = (G * 3m * m) / (4r^2).

Since (3m * m) / (4r^2) is equivalent to (3/4) * (m * m) / (r^2), we can rewrite the equation as:

New \(Fg = (3/4) * (G * m * m) / r^2.\)

Comparing this to the original force of gravity, Fg, we see that the new force is (3/4) times the original force. Therefore, the answer is C) 0.75 Fg.

Regarding the second scenario, for objects in stable orbit, the orbital period is determined by the formula:

\(T = 2π * sqrt(r^3 / (G * M)),\)

where T is the orbital period, r is the distance between the center of the object and the center of the Earth, G is the gravitational constant, and M is the mass of the Earth.

If Satellite B is twice as far from the Earth's center compared to Satellite A, we can say that r_B = 2 * r_A.

Let's compare the orbital periods of the two satellites:

T_B = 2π * sqrt((2r_A)^3 / (G * M)) = 2π * sqrt(8r_A^3 / (G * M)).

T_A = 2π * sqrt(r_A^3 / (G * M)).

Dividing T_B by T_A, we get:

T_B / T_A = (2π * sqrt(8r_A^3 / (G * M))) / (2π * sqrt(r_A^3 / (G * M))).

Simplifying this expression, we find:

T_B / T_A = sqrt(8r_A^3 / (r_A^3)) = sqrt(8) = 2.83.

Therefore, the answer is a) 2.83 times larger.

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When two objects are experiencing gravitational attraction, if you triple the mass of one of the objects and double the distance between their centers, the new force of gravity compared to the old will be 0.75 times the original force (0.75 Fg).The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

This is because the force of gravitational attraction between two objects is inversely proportional to the square of the distance between their centers of mass. If you double the distance between two objects, the force of gravitational attraction decreases by a factor of 4 (2^2). On the other hand, if you triple the mass of one of the objects, the force of gravitational attraction increases by a factor of 3.

Therefore, combining these effects, the new force of gravity will be 3/4 or 0.75 times the original force.

Satellite A and Satellite B are both in stable orbit around the Earth, but Satellite B is twice as far from the Earth's center as Satellite A. The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

This is because the orbital period of an object in circular motion is dependent on the radius of the orbit. The further an object is from the center of the orbit, the longer it takes to complete one full orbit. Since Satellite B is twice as far from the Earth's center as Satellite A, its radius is also twice as large. The orbital period is directly proportional to the radius, so Satellite B's orbital period will be 2.83 times larger than Satellite A's orbital period.

Therefore, the correct statement is:

The new force of gravity compared to the old will be 0.75 Fg.

The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

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The work done on the ball by the 10 N tension force is zero ( 0 Joules).

Given that:

The circumference(displacement d) of the ball = 3 m

the tension force of the ball = 10 N

the angle θ between the tension force and the displacement =90°

∴Using the work equation;

W = F × d cos θ

W = 10×3× cos (90)

W = 10 × 3 × 0

W = 0 Joules

The definition of work done includes both the forces applied to the body and the total displacement of the body. A constant force F is present before to this block. The goal of this force is to move the body d meters in a straight line in the force's direction.

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The displacement of the ball is zero.

What is displacement?

The smallest distance between the initial and final position of an object.

What are the equations of motion?

There are three equations of motion that completely describes the motion of an object.

The first equation of motion gives the relationship between the initial velocity, final velocity, acceleration, and time.

The second equation of motion gives the relationship between the initial velocity, displacement, acceleration, and time.

The third equation of motion gives the relationship between the initial velocity, final velocity, acceleration, and displacement.

Given time, initial velocity, and acceleration, the displacement can be calculated using the second equation of motion. The second equation of motion is,

s=u*t+(1/2)*a*t^2

Here, u=25 m/sec, a=-25 m/sec and t=2.0 sec.

Put the values in the formula and calculate the displacement.

s= (25)*(2.0)+(1/2)*(-25)*(2.0)^2

s=50-50

s=0 m.

Hence the displacement of the ball is zero.

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Answer:

Explanation:

Since we are looking at speed over a time unit, we have an acceleration graph. The definition of acceleration mathematically is:

\(a=\frac{v_f-v_0}{t}\) (that's the change in velocity over the change in time). The slope of any line in this graph wil represent the acceleration. Slope is rise over run, or y over x. Therefore, if acceleration is velocity over time, then the y axis is the velocity axis and the x axis is the time axis. It makes perfect, beautiful sense!!

Answer:

no

Explanation:

the moon's force of gravity is not strong enough to pull you down compared to earth, so you will just float

The speed of the wave of wavelength 0.21 m is 23.1 m/s. And the correct answer is 0A. 23.1 m/s.

The speed of a wave is calculated by multiplying the wavelength and the frequency of the wave.

To calculate the speed of the wave, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the speed of the wave is 23.1 m/s.

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Chloroplasts are responsible for absorbing the solar energy during the light reactions.

Chloroplasts are the cellular organelles of plants and green algae that are responsible for carrying out photosynthesis.

Photosynthesis is the process of metabolism that allows certain organisms to synthesize organic substances using sunlight as an energy source.

Chloroplasts have vesicles called thylakoids that house molecules capable of transforming light energy from the sun's rays into chemical energy.

One of these storage molecules is chlorophyll, a green photosynthetic pigment that absorbs light energy.

Each chlorophyll molecule has:

Therefore, Chloroplasts are responsible for absorbing the solar energy during the light reactions, chlorophyll being, specifically, an essential biomolecule for the development of photosynthesis.

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Answer:1.36078

Explanation:

At rest, hydrogen has a spectral line at 163 nm. If this line is observed at 157 nm for the star proxima, how fast is proxima moving in km/s is as follow:

The change in wavelength of a spectral line due to the Doppler effect is given by

Δλ/λ=ν/c

where Δλ is the change in wavelength, λ is the wavelength of the spectral line, ν is the velocity of the object towards or away from the observer, and c is the speed of light.

Using this equation, the velocity of Proxima can be found.

Δλ/λ = ν/c

where λ = 163 nm(spectral line for hydrogen), and Δλ = 163 nm - 157 nm = 6 nm (since the spectral line is observed at 157 nm instead of 163 nm)

ν = Δλ * c / λ

= 6 nm * 3.00 x 10^8 m/s / 163 nm

= 1.1 x 10^7 m/s

Now, to convert this velocity into km/s, divide by

1000:1.1 x 10^7 m/s ÷ 1000 m/km

= 11,000 km/s

Therefore, Proxima is moving away from us at a velocity of 11,000 km/s.

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