You can answer all if you would like but only a few would be fine as well

The probability is 7/72 that each of the final three rolls is at least as large as the roll preceding it.

Let \(N_{i}\) represent the number appearing on die when die is rolled ith time,

i=1,2,3,4

Given that \(N_{1}\)≤\(N_{2}\)≤\(N_{3}\)≤\(N_{4}\)

Each time when a die is rolled, six options are there.

Let we have four equal sets

{1,2,3,4,5,6}, now we have to select four numbers such that, exactly one number is selected from each set

Case 1: All four are same

Number of ways:⁶C₁ =6

Case 2: Three are same but one is different

Number of ways: ⁶C₁ ⁵C₁ =30

Case 3: Two are same of one kind and two are same of second kind

Number of ways: \(\frac{1}{2}\) ⁶C₁ ⁵C₁=15

Case 4: Two are same and two are different

Number of ways: ⁶C₁ ⁵C₂=60

Case 5: All four are different

Number of ways: ⁶C₄=15

Required probability:

=\(\frac{6+30+5+60+15}{6*6*6*6}\)

=\(\frac{126}{36*36}\)

=\(\frac{72}{7}\)

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Answer:

ar some point pattern A will have the same numbers as pattern B as it moves along like if you add 3 for 2 more times in pattern A it will have 24 and so on..

Answer:

The answer is A

Step-by-step explanation:

A proportional function is a function where the output = constant x input

Let's make each of these situations into an equation

A) y = 3.5x

B) y = 40x + 25

C) y = 2x + 56

D) y = 2x + 5

because A is the only one that follows the output = constant x input rule it is the example of a proportional function

Answer:

do you have answer choices or is this just fill in the blanks ?

Answer:

I think it's this 62.13 in↑3.

I hope it's right!

Answer:

answer is C

Step-by-step explanation:

The y values will only go to ∞ no matter the x values

Answer:

The equation to represent the situation is \(10 = \frac{k}{4}\)

Step-by-step explanation:

It is given that:

Amount of gas left in tank varies inversely with the amount of the time.

Let,

g represents the gas

t represents the time

g ∝ 1/t

\(g = \frac{k}{t}\)

Here, k represents the constant of proportionality.

Putting g = 10 and t = 4 in the equation

\(10 = \frac{k}{4}\)

Therefore,

The equation to represent the situation is \(10 = \frac{k}{4}\)

The predicted number of plants with aphids is 109.

The predicted number of plants with aphids is the ratio of the random plants with aphids to total number of random plants selected multiplied by the number of plants in the nursery.

Predicted number = (7/50) x 780 = 109.

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In the case of Alicia, The single net increase is 5.821% of the original price.

Alicia is buying shoes at a department store that offers a 15% discount on all shoes. Additionally, she has a store card that gives her another 5% discount. However, at checkout, the cashier tells her that there will be two increases, one of 2% for commissions and another of 18% for general sales tax. To determine if there is a net discount or increase, we need to calculate the total discount and total increase separately and compare them.

First, let's calculate the total discount:

Next, let's calculate the total increase:

If the total discount is greater than the total increase, then there is a net discount. If the total increase is greater than the total discount, then there is a net increase.

Therefore, we need to compare:

Simplifying both expressions, we get:

Since 1.0506 x Original Price is greater than 0.20 x Original Price, we can conclude that there is a net increase.

To calculate the amount of the single net increase, we can subtract the discounted price from the increased price:

Simplifying the expression, we get:

Therefore, the single net increase is 5.821% of the original price.

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Complete Question:

Alicia will buy shoes in a department store that advertises a 15% discount on all shoes, plus she has the store card and therefore they will give her another 5% discount. When paying: the cashier tells you that they will make 2 increases, one of 2% for commissions and the other of 18% for general sales tax. Determine if it is the case, how much is the discount or single increase?

To compare the two quantities, divide the number of giraffes by the number of penguins There are 5 times as many giraffes as penguins at the zoo.

To compare the two quantities, you need to divide the number of giraffes by the number of penguins.

30 giraffes / 6 penguins = 5

This means that there are 5 times as many giraffes as penguins at the zoo.

There are 5 times as many giraffes as penguins at the zoo. To compare the two quantities, divide the number of giraffes by the number of penguins (30/6 = 5). This means that there are 5 times more giraffes than penguins at the zoo.

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Answer:

-1

Step-by-step explanation:

-100x-100=0

-100x=100

x/-100=100/-100

x=-1

When you are solving for a variable your goal is to get the variable by it seff.

x = -1

- 100x = 100

Step-by-step explanation:

\( - 100x - 100 = 0\)

Move the constant to the right side and change the sign

\( - 100x = 100\)

Change the sign of both side of the equation

\(100x = - 100\)

Divide both side by the same number

\(x = - 1\)

\( - 100x\)

\( - 100 \times - 1\)

Remove the ( - ) sign since negative number are multiplied by even number...

\(100 \times 1 \\ 100\)

Total subscribers that Netflix must sample to obtain the interval to estimate the proportion of their current subscribers who would pay extra for a premium membership including access to more movies and TV shows are 385 subscribers.

For the Wald-type confidence interval, the confidence limits are:

\(p-\)\(z_{\alpha /2}\)\(\sqrt{\frac{p(1-p)}{n} }\) , \(p+\)\(z_{\alpha /2}\)\(\sqrt{\frac{p(1-p)}{n} }\)

Where p is the sample proportion attended, n is the sample size, and z∗α/2 is the upper α/2 quantile of the standard normal distribution for a 100 (1−α) % confidence interval. If a 95% CI is needed, this corresponds to α = 0.05, thus

\(z_{\alpha /2}\) ≈ 1.96

And, the quantity

ME = \(z_{\alpha /2}\)\(\sqrt{\frac{p(1-p)}{n} }\)

is studied as the margin of error. Since we also need ME ≤ 0.05, we solve for n to acquire

n ≥ p (1 − p) \((\frac{z \alpha /2}{ME} )^{2}\)

The only undetermined quantity is p; but since p (1 − p) ≤ 1/4 for all p ∈ [0,1], we identify that a sample size of at least

n ≥ \((\frac{z \alpha /2}{2ME} )^{2}\)

undertakes the Wald interval will have a margin of error less than the needed margin no matter the sample proportion checked. Alternating the given values results in

n ≥ \((\frac{1.96}{2(0.05} )^{2}\) = 384.16

for that we need to round up to guarantee the sample size is enough, thus n = 385.

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The standard deviation is 19.1204 which means that the values are quite spread out from the mean of 50.55.

The range, variance, and standard deviation for the given sample diets are:

Range: \(86 - 22 = 64\)

Variance: To calculate the variance, we use the formula,σ² = Σ ( xi - μ )² / N

where σ² = variance, Σ = sum of, xi = each value, μ = the mean of all the values and N = total number of values.

We first calculate the mean,

\(μ = Σ xi / N\\= (58 + 80 + 38 + 52 + 86 + 22 + 29 + 49 + 66 + 64 + 54) / 11\\= 556 / 11\\= 50.55\)

Next, we find the difference between each value and the mean.

\(( xi - μ )²58 - 50.55 \\= 7.45, (7.45)² = 55.502, 80 - 50.55 \\= 29.45, (29.45)² \\= 867.9025, 38 - 50.55 \\= -12.55, (-12.55)² \\= 157.5025, 52 - 50.55\)

\(= 1.45, (1.45)² \\= 2.1025, 86 - 50.55 \\= 35.45, (35.45)² \\= 1255.2025, 22 - 50.55 \\= -28.55, (-28.55)² = 817.5025, 29 - 50.55 \\= -21.55, (-21.55)² \\= 466.0025, 49 - 50.55 = -1.55, (-1.55)² \\= 2.4025, 66 - 50.55 = 15.45, (15.45)²\)

\(= 238.1025, 64 - 50.55 \\= 13.45, (13.45)² \\= 180.9025, 54 - 50.55 \\= 3.45, (3.45)² \\= 11.9025Σ ( xi - μ )² \\= 55.502 + 867.9025 + 157.5025 + 2.1025 + 1255.2025 + 817.5025 + 466.0025 + 2.4025 + 238.1025 + 180.9025 + 11.9025\)

\(= 4025.05σ² \\= Σ ( xi - μ )² / N\\= 4025.05 / 11\\= 365.0045\)

Standard deviation:

To find the standard deviation, we take the square root of the variance.\(σ = √σ²\\= √365.0045\\= 19.1204\)

The range, variance, and standard deviation for the given sample data are:

Range: 64

Variance: 365.0045

Standard deviation: 19.1204

The results tell us the following:

The range is the difference between the highest and lowest values in the dataset. Here, the range is 64 which means that the highest value is 64 more than the lowest value.

Variance measures how much the values in a dataset vary from the mean of all the values.

Here, the variance is 365.0045 which means that the values in the dataset are quite spread out.

Standard deviation is the square root of variance. It gives an idea of how spread out the values are from the mean.

Here, the standard deviation is 19.1204 which means that the values are quite spread out from the mean of 50.55.

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Answer:

i have a couple examples for you, MPN and RPQ are vertical angles where as SPQ and QPO are adjacent angles

-Todo<3

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

6 divided by 2 = 3

12 times 3  = 36

A. The Utilization rate is 0.5714 or 57.14%, B. The average number of students in line is 0.9 students and C. The average time of waiting in line was 4.57 minutes.

The utilization rate refers to the proportion of time Judy Gumshoes spends processing student requests.

To calculate this rate, divide the average service time by the average time between arrivals. In this case, the average service time is 8 minutes, and students arrive every 14 minutes on average.

a) Utilization rate: 8 minutes / 14 minutes = 0.5714 or 57.14%

b) To determine the average number of students in line,

we can use the formula L = λW, where L represents the average number of students in the system, λ is the arrival rate (1 student per 14 minutes), and W is the average time a student spends in the system (waiting and being served). Since we know the utilization rate,

we can calculate the average waiting time (Wq) using the formula,

Wq = (U^2) / (1 - U), where U is the utilization rate.

In this case, Wq = (0.5714^2) / (1 - 0.5714) = 0.3265 or 32.65% of 14 minutes = 4.57 minutes.

W = Wq + service time

= 4.57 minutes + 8 minutes

= 12.57 minutes.

Finally, L = λW = (1 student / 14 minutes) * 12.57 minutes

= 0.9 students.

c) The average time of waiting in line is the same as the average waiting time in the system (Wq), which we calculated as 4.57 minutes.

In summary, the utilization rate of the service counter is 57.14%, the average number of students in line is 0.9, and the average waiting time in line is 4.57 minutes.

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Answer:

3 because you always know your answer by the smalest number which has a digit of 3

Step-by-step explanation:

Kermit will likely enjoy Peggy's iced tea as it has the same concentration as his favorite iced tea.

Let's compare the ratios of tea bags to water in Kermit's favorite iced tea and Peggy's iced tea to determine what Kermit might think of Peggy's iced tea.

1. Kermit's favorite iced tea ratio:
Kermit uses 15 tea bags in every 2 liters of water. So, the ratio is 15:2.

2. Peggy's iced tea ratio:
Peggy made a 12-liter batch of iced tea with 90 tea bags. So, the ratio is 90:12.

Now, let's simplify both ratios:

1. Kermit's ratio:
15:2 can be simplified to 7.5:1 by dividing both numbers by 2.

2. Peggy's ratio:
90:12 can be simplified to 7.5:1 by dividing both numbers by 12.

Both iced tea recipes have the same ratio of 7.5:1 (tea bags to water), and the tea bags are in the water for the same amount of time. Therefore, Kermit will likely enjoy Peggy's iced tea as it has the same concentration as his favorite iced tea.

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Answer:

x.=6 y=7

Step-by-step explanation:

glad glad I could help

Answer:

x = 6

y = 7

Step-by-step explanation:

Side AB and side DC is equal so let's put it in a equation.

2y - 8 = y - 1

Use APE or Additive Property of Equality\

2y - y = 8 - 1

y = 7

So the value of y is 7.

Now substitute it to line BC.

y + 6

7 + 6

= 13

Since line BC and line AD has equal sides, let's put it in a equation.

2x + 1 = 13

2x = 13 - 1

2x = 12

Use DPE or Division Property of Equality

2x/2 = 12/2

x = 6

The probability of getting at least one head is 15/16.

What is probability?

The ratio of positive outcomes to all possible outcomes of an event is known as the probability.

Formula for probability = favourable outcomes/ total outcomes

Main body:

if 4 coins are tossed , total no. of outcomes = 2⁴ = 16

In a toss there are 2 outcomes T or H

so, Probability of getting Head = 1/2

The probability of getting at least 1 head = 1- probability of getting no heads

⇒1 - Probability of getting tail in 4 tosses

⇒ 1 - (1/2)⁴

⇒ 1 - 1/16

⇒ 15/16

So the probability of getting at least one head is 15/16.

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Answer:

D

Step-by-step explanation:

The range of the function is all possible y-values of an function or an output.

In conclusion the equation in function form to show the amount of trash removed each week is:

B. f(x) = -2.6x + 68

How to solve?

We can use the slope-intercept form of a linear function to write the equation. The slope is found by taking the difference in the y-coordinates divided by the difference in the x-coordinates:

slope = (42 - 55)/(10 - 5) = -13/5

We can use the point-slope form of a linear function to find the equation:

y - 55 = (-13/5)(x - 5)

Simplifying, we get:

y = (-13/5)x + 68

Therefore, the equation in function form to show the amount of trash removed each week is:

B. f(x) = -2.6x + 68

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Answer:

8994.16

Step-by-step explanation:

formula:

\(PV(1+\frac{i}{n})^{nt}\\7500(1+\frac{.0365}{4})^{5*4}\\8994.16\)

Answer:

\(A = P(1+\frac{r}{n})^{nt}\)

P = $7500

r = 3.65% = .0365

n = 4 (because compounded quartely)

t = 5years

\(A = 7500(1+\frac{0.0365}{4})^{4*5}\\\\\)

    =\(7500(1+0.09125)^{20} = 8994.16\)

Answer = $8994.16

IN THE PLACE OF Y PLUG IN 0

\( = \frac{( {0})^{2}}{5} \\ = \frac{0}{5} \\ = 0\)

The answer is 0