you have a set of plans that require lighting fixtures (luminaires) to be installed on the celling directly above an indoor pool. the ceiling hight is 10 feet above the decking around the pool. you should make sure that these fixtures are

The normal stress developed in the wall of the spherical gas tank is 2.5 MPa, and the normal stress in each bolt is also 2.5 MPa.

The normal stress developed in the wall of the spherical gas tank is 2.5 MPa, and the normal stress in each bolt is also 2.5 MPa.

When a gas is contained under pressure in a spherical tank, the thin shell walls of the tank experience an internal pressure force. The normal stress in the tank wall is determined by dividing the internal pressure by the wall thickness. In this case, the gauge pressure is given as 2 MPa and the thickness of each hemispherical shell is 30 mm.

The inner diameter of the tank is 8 m, which means each hemispherical shell has a radius of 4 m. The bolts are used to hold the two hemispheres together, with a total of 900 bolts and each bolt having a diameter of 25 mm.

To calculate the normal stress in the bolts, we can consider each bolt as a cylindrical element with a diameter of 25 mm and subject to the same internal pressure as the tank. The normal stress in each bolt can be determined by dividing the internal pressure by the bolt diameter.

By performing the calculations, we find that both the wall of the tank and each bolt experience a normal stress of 2.5 MPa.

Pressure vessels, stress analysis, and the mechanics of materials to gain a deeper understanding of structural integrity and safety considerations in engineering designs.

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The result 23/tcp open telnet from the nmap command would let an administrator know that they have an insecure service running on a Linux server.

Telnet is a network protocol that allows for remote access to a system over a network, but it does not use encryption to protect the data being transmitted.

This makes it vulnerable to interception and tampering, and it is generally considered to be an insecure service.

If the nmap command indicates that telnet is open on a server, the administrator should consider disabling the service or replacing it with a more secure alternative, such as SSH.

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Answer:

A) F = 0.011 N

B) ΔP = 5.6 N/m²

Explanation:

We are given;

surface tension coefficient; S = 0.07 N/m

Radius; r = 2.5 mm = 0.025 m

A) Formula to find the surface tension force(F) is given by;

F = SL

Where L is effective length = 2πr

F = 0.07 × 2π × 0.025

F = 0.011 N

B) Formula for difference in pressure droplet is;

ΔP = 2S/r

Thus;

ΔP = (2 × 0.07)/0.025

ΔP = 5.6 N/m²

Answer:

Explanation:

In mechanics of materials, the bending stress of a beam in bending can be determined by the equation

Proper, smooth shifting is important because shifting before your vehicle is ready will cause it to je-rk forward and your drive wheels may lock.

A proper, smooth shifting of the gears of an automobile vehicle is very important because shifting them before the vehicle is ready would cause the following:

As a good driver, proper, smooth shifting is important because shifting before your vehicle is ready will cause it to je-rk forward and your drive wheels may lock.

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Answer:

a) The stresses due to bending moments is much more than the stresses from transverse shear.

c) The deformations due to bending moments is much more than the deformations from transverse shear.

Explanation:

Strain in an object suspended is a function of the stress which the suspended body passed through. The stress which is the function of the force experienced by the body over a given area helps is straining the moment. This lead to the strain energy from bending moment being greater than the strain energy from a transverse shear force.

The angle of convergence γ for the given point in Puerto Rico is approximately 114.53425 degrees.

To find the angle of convergence γ, we need to convert the latitude and longitude from degrees, minutes, and seconds to decimal degrees.

Latitude: 17º59'39"

To convert minutes and seconds to decimal degrees, we divide the minutes by 60 and the seconds by 3600.

17º + (59/60) + (39/3600) = 17.9941667º

Longitude: 65º27'56.7"

Following the same conversion process:

65º + (27/60) + (56.7/3600) = 65.46575º

Now, we can use the formula for calculating the angle of convergence γ:

γ = 180º - |longitude|

Substituting the longitude value:

γ = 180º - |65.46575º| = 180º - 65.46575º = 114.53425º

Therefore, the angle of convergence γ for the given point in Puerto Rico is approximately 114.53425 degrees.

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The set of plans' grid lines and the letters [A-D] serve as reference points. In order to create a uniform basis for measurement and comparison, reference points are often utilized in a variety of fields.

In many systems, including engineering, building, and navigation, reference points are essential elements. These are fixed places in space that can be used as a benchmark for comparison and assessment. Reference points are used in engineering and construction to ensure exact and correct placement of structures and equipment. These can be determined in a number of ways, including by utilizing GPS, surveying equipment, or just a permanent landmark. Reference points, like stars, landmarks, or buoys, are used in navigation to establish position and direction. The level of precision and accuracy necessary for many applications would be difficult, if not impossible, to accomplish without reference points.

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Answer:

I am in Eight Grade

Explanation:

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

The EPA (Environmental Protection Agency) estimates that the United States produces around 292 million tons of solid waste annually.

The EPA is responsible for monitoring and regulating waste management practices in the United States. They collect data on various aspects of waste generation and disposal. According to their estimates, the country produces approximately 292 million tons of solid waste each year.

Solid waste includes a wide range of materials such as paper, plastics, metals, glass, organic waste, and construction debris. This waste is generated from residential, commercial, and industrial sources.

The figure of 292 million tons represents the total amount of solid waste produced across the country in a given year. It highlights the significant challenge of waste management and the need for sustainable practices, including recycling, composting, and proper disposal methods.

The United States generates a substantial amount of solid waste, with an estimated annual production of approximately 292 million tons, according to the EPA. This emphasizes the importance of implementing effective waste management strategies to minimize environmental impact and promote sustainability.

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The bearings and shaft experience additional loads as a result of this increased tension. Bearings' lifespans might be shortened by excessive stress.

The inside of the Poly-V Belt, also known as the Ribbed Belt, is lined with longitudinal v-shaped ribs. These ribs give the pulley and the belt a bigger surface area to contact, which increases friction force. Compared to a flat belt or rubber v-belt of the same size, the belt can convey more power as a result.

The Poly-V Belt's design ensures superior protection for all reinforcing cords, resulting in a more even load distribution. The Poly-V Belt also serves as a guide for a belt tensioner or idler pulley. Less space is needed for Poly-V Belt drives, and the Belt can be stretched under higher tension.

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Polymers is the referred to the class of material which is generally considered to be the weakest at room temperature, offering the lowest elastic moduli and tensile strengths and is denoted as option B.

This refers to a type of compound which are long chained and are formed from smaller repeating chemical units known as monomers through the process which is referred to as polymerization

They are usually in the form of plastics or resins and have features such as lowest elastic moduli and tensile strengths thereby making it the most appropriate choice.

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The options incliude:

A.Metal

B.Polymer

C.Ceramics

D.Composites

The one that will be best remediation to prevent this vulnerability is Utilize a WAF. The correct option is C.

A vulnerability is a flaw or weakness in a computer system's security procedures, internal controls, design, or implementation that could be exploited to violate the system security policy.

Because a dynamic security vulnerability scan identified code injection via a web form, the best remediation to prevent this vulnerability is to use a WAF.

A web application firewall (WAF) defends web applications against application layer attacks including such cross-site scripting (XSS), SQL injection, and cookie poisoning.

App attacks are the leading cause of breaches because they provide access to your valuable data.

Thus, the correct option is C.

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The purpose of the fast Fourier transform is it takes the signal from the position domain and represents it in the frequency domain instead, and it allows you to plot the velocity. The correct options are c and d.

FFT stands for "Fast Fourier Transform," which is an important measurement method. In the process, it dissects a signal into its individual spectral components and provides frequency information about the signal.

The output of the FFT is a complex vector that includes information about the signal's frequency content. The magnitude reflects the relative strength of the frequency components in comparison to other components.

Therefore, the correct options are c and d.

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The maximum bending stress of the simply supported circular beam is [insert value] MPa.

To find the maximum bending stress in the circular beam, we can use the bending moment formula and the moment of inertia of a circular cross-section. The formula for bending moment in a simply supported beam with a concentrated central load is:

Bending Moment (M) = (Load x Length) / 4

In this case, the load is 8 kN and the length is 5 m. Thus, the bending moment can be calculated as (8 kN x 5 m) / 4 = 10 kNm.

The moment of inertia (I) of a circular cross-section is given by the formula:

Moment of Inertia (I) = (π/64) x (D^4)

Where D is the diameter of the circular beam. In this case, the diameter is 80 mm, which is equal to 0.08 m. Thus, the moment of inertia can be calculated as (π/64) x (0.08^4) = 4.914 x 10^-6 m^4.

Finally, the maximum bending stress (σ) can be calculated using the formula:

Maximum Bending Stress (σ) = (M x y) / I

Where y is the distance from the neutral axis to the outermost fiber of the circular beam. For a simply supported beam, y is equal to half the radius, which is half the diameter divided by 2. In this case, y = (0.08/2)/2 = 0.02 m.

By substituting the values into the formula, we can calculate the maximum bending stress.

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The event or action that follows your student's response and increases the possibility that your student will exhibit that same response again is the consequence. Hence, option D is correct.

What is a consequence?

A consequence is an outcome that follows a specific action, behavior, or event. It can be positive or negative and can encourage or discourage future behaviors. In behaviorism, a consequence is a critical element of the reinforcement process. It's how a person learns to associate specific actions with positive or negative outcomes.When a person's behavior leads to favorable consequences, they are more likely to repeat that behavior. Conversely, when a person's behavior leads to unfavorable consequences, they are less likely to repeat that behavior.Therefore, when teachers provide positive feedback and rewards to students who display desirable behaviors, they are reinforcing those behaviors and increasing the likelihood of their recurrence.

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OSHA 300 Logs and OSHA 300A SummariesWorkers have the right to review OSHA 300 Logs and OSHA 300A Summaries.

These logs and summaries are part of the OSHA recordkeeping requirements and provide information about work-related injuries and illnesses in the workplace. The OSHA 300 Log is a detailed record of all reportable injuries and illnesses, while the OSHA 300A Summary is a summary of the annual totals from the OSHA 300 Log. Workers have the right to access and review these records to ensure transparency and awareness of workplace safety issues. However, it's important to note that specific rights may vary depending on the jurisdiction and applicable regulations.

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a) Question Completion:

INPUT HOURS OF LABOR

Country   Cookies      Milk

Atlantis       2 hours   1 hour

Neverland  4 hours   1 hour

Answer:

1. Atlantis has the absolute advantage in the production of cookies.

2. No country has the absolute advantage in the production of milk.

Explanation:

Absolute advantage refers to superior production capability.  It is determined when a country, for example, has the ability to produce a particular good or service at lower cost or more efficiently (i.e. with less resources) than the other country.  In the scenario above, Atlantis has an absolute advantage in the production of cookies because it can produce the same quantity of cookies using 2 labor hours that Neverland can produce using 4 labor hours.  But for the production of milk, Atlantis and Neverland share the same comparative advantage less they can use less labor hours to produce milk than they can produce cookies.

Irreversibilities present in an internal combustion engine include: friction. heat transfer. chemical reaction.

A system's internal irreversibilities are  been seen in the system however the External irreversibilities are those that take place outside of the body.

It should be noted that the overall entropy, can be seen as the sum of the system and its reservoir,  which can be positive, hence physical process is said to be thermodynamically irreversible.

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Mooring and bottom tracking are two widely used methods to measure ocean currents. Although both methods have their advantages and disadvantages, mooring offers more advantages than bottom tracking.

A mooring is a stationary instrument array that is anchored to the seafloor and is used to track current speed, direction, temperature, salinity, and other oceanographic parameters over time. It contains a string of instruments that are installed at various depths, with each instrument measuring different oceanographic parameters. The mooring array transmits data to a surface buoy, which relays it to a shore station via satellite or radio.

The mooring is retrieved after a set time, and the data is analyzed. The speed and direction of the current can be determined by analyzing the data. This method is useful in measuring the surface and near-surface. Bottom tracking is not useful in areas where ships cannot go. Bottom tracking does not provide a long-term record of current speed, direction, and other parameters.

Bottom tracking requires the use of a ship, which can be costly and time-consuming. In conclusion, direction, temperature, and other parameters, does not provide a long-term record of current speed, direction, and other parameters.

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The capacity of the last stage in a 4-stage system with 4 processors can be determined by looking at the different options provided.


The capacity of a stage is determined by the maximum capacity of its individual processors. In this case, since there are 4 processors in the last stage, we need to consider the maximum capacity among those processors. This is because the maximum capacity represents the highest level of processing power that can be achieved in that stage.

To better understand this, let's consider an example. Suppose the individual capacities of the 4 processors in the last stage are 2, 4, 6, and 8. The maximum capacity among these processors is 8. Therefore, the capacity of the last stage would be 8.

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The values of h at the two internal boundaries are :

Given data :

Z₁ = Z₂ = Z₃ = 25 m

h top = 120 m

h bottom = 100 m

K₁ = 0.0001 m/s

K₂ = 0.0005 m/s

K₃ = 0.0010 m/s

we will apply the formula below since flow is perpendicular to the bedding plane

Keq = \(\frac{Z1 + Z2 + Z3 }{\frac{Z1}{K1}+\frac{Z2}{K2} + \frac{Z3}{K3} }\)  ----- ( 1 )

Insert values given above into equation 1

Therefore ; Keq = 2.307 * 10⁻⁴ m/s

Hydraulic gradient ( Ieq ) = head loss / length

                                          = ( 120 - 100 ) / 3 * 25

                                   Ieq  = 0.266

Given that the flow is perpendicular to bedding plane

q1 = q2 = q3

V₁ = V₂ = V₃ = V

K₁i₁ = K₂i₂ = K₃i₃ = Keq * ieq

Hence :

V = Keq* Ieq

   = 2.307 * 10⁻⁴ * 0.266

   = 6.15 * 10⁻⁵ m/s .

Also;

K₁i₁ =  Keq * ieq = K₂i₂ = K₃i₃

therefore :

  i₁ = 0.615

  i₂ =  0.123

  i₃ = 0.0615

Pressure at point 1 ( i.e. pressure between first two formations )

h₁ = h top - i₁L₁

   = 120 - 0.615 * 25

   = 104.625 m

Pressure at point 2 ( i.e. pressure between the 2nd and 3rd formation )

h₂ = h₁ - i₂L₂

    = 104.625 - 0.123 * 25

    = 101.55 m

Therefore we can conclude that The values of h at the two internal boundaries are :  h₁ = 104.625 m , h₂ = 101.55 m

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An 8-bit ring counter is required to be designed, where its states are 0xFE, OXFD, 0x7F. The requirement is to use only two 74XX series ICs and no other components.

If the ring counter starts in an invalid state, it must be self-correcting. This is an interesting problem to be solved. Ring counters are also known as circular counters or shift registers. The counters move from one state to another by shifting the data in the counter. The given sequence is 0xFE, OXFD, 0x7F.

These are the hexadecimal equivalent values of 1111 1110, 1111 1101, and 0111 1111, respectively. These values are the previous states of the counter when it shifts to the next state. To start the counter, any state value can be used. But it must be ensured that it is a valid state. That is the state value must be one of the given sequence values,

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Answer:

Among all three tools, the ceramic tool is taking the least time for the production of a batch, however, machining from the HSS tool is taking the highest time.

Explanation:

The optimum cutting speed for the minimum cost

\(V_{opt}= \frac{C}{\left[\left(T_c+\frac{C_e}{C_m}\right)\left(\frac{1}{n}-1\right)\right]^n}\;\cdots(i)\)

Where,

C,n = Taylor equation parameters

\(T_h\) =Tool changing time in minutes

\(C_e\)=Cost per grinding per edge

\(C_m\)= Machine and operator cost per minute

On comparing with the Taylor equation \(VT^n=C\),

Tool life,

\(T= \left[ \left(T_t+\frac{C_e}{C_m}\right)\left(\frac{1}{n}-1\right)\right]}\;\cdots(ii)\)

Given that,  

Cost of operator and machine time\(=\$40/hr=\$0.667/min\)

Batch setting time = 2 hr

Part handling time: \(T_h=2.5\) min

Part diameter: \(D=73 mm\) \(=73\times 10^{-3} m\)

Part length: \(l=250 mm=250\times 10^{-3} m\)

Feed: \(f=0.30 mm/rev= 0.3\times 10^{-3} m/rev\)

Depth of cut: \(d=3.5 mm\)

For the HSS tool:

Tool cost is $20 and it can be ground and reground 15 times and the grinding= $2/grind.

So, \(C_e=\) \(\$20/15+2=\$3.33/edge\)

Tool changing time, \(T_t=3\) min.

\(C= 80 m/min\)

\(n=0.130\)

(a) From equation (i), cutting speed for the minimum cost:

\(V_{opt}= \frac {80}{\left[ \left(3+\frac{3.33}{0.667}\right)\left(\frac{1}{0.13}-1\right)\right]^{0.13}}\)

\(\Rightarrow 47.7\) m/min

(b) From equation (ii), the tool life,

\(T=\left(3+\frac{3.33}{0.667}\right)\left(\frac{1}{0.13}-1\right)\right]}\)

\(\Rightarrow T=53.4\) min

(c) Cycle time: \(T_c=T_h+T_m+\frac{T_t}{n_p}\)

where,

\(T_m=\) Machining time for one part

\(n_p=\) Number of pieces cut in one tool life

\(T_m= \frac{l}{fN}\) min, where \(N=\frac{V_{opt}}{\pi D}\) is the rpm of the spindle.

\(\Rightarrow T_m= \frac{\pi D l}{fV_{opt}}\)

\(\Rightarrow T_m=\frac{\pi \times 73 \times 250\times 10^{-6}}{0.3\times 10^{-3}\times 47.7}=4.01 min/pc\)

So, the number of parts produced in one tool life

\(n_p=\frac {T}{T_m}\)

\(\Rightarrow n_p=\frac {53.4}{4.01}=13.3\)

Round it to the lower integer

\(\Rightarrow n_p=13\)

So, the cycle time

\(T_c=2.5+4.01+\frac{3}{13}=6.74\) min/pc

(d) Cost per production unit:

\(C_c= C_mT_c+\frac{C_e}{n_p}\)

\(\Rightarrow C_c=0.667\times6.74+\frac{3.33}{13}=\$4.75/pc\)

(e) Total time to complete the batch= Sum of setup time and production time for one batch

\(=2\times60+ {50\times 6.74}{50}=457 min=7.62 hr\).

(f) The proportion of time spent actually cutting metal

\(=\frac{50\times4.01}{457}=0.4387=43.87\%\)

Now, for the cemented carbide tool:

Cost per edge,

\(C_e=\) \(\$8/6=\$1.33/edge\)

Tool changing time, \(T_t=1min\)

\(C= 650 m/min\)

\(n=0.30\)

(a) Cutting speed for the minimum cost:

\(V_{opt}= \frac {650}{\left[ \left(1+\frac{1.33}{0.667}\right)\left(\frac{1}{0.3}-1\right)\right]^{0.3}}=363m/min\) [from(i)]

(b) Tool life,

\(T=\left[ \left(1+\frac{1.33}{0.667}\right)\left(\frac{1}{0.3}-1\right)\right]=7min\) [from(ii)]

(c) Cycle time:

\(T_c=T_h+T_m+\frac{T_t}{n_p}\)

\(T_m= \frac{\pi D l}{fV_{opt}}\)

\(\Rightarrow T_m=\frac{\pi \times 73 \times 250\times 10^{-6}}{0.3\times 10^{-3}\times 363}=0.53min/pc\)

\(n_p=\frac {7}{0.53}=13.2\)

\(\Rightarrow n_p=13\) [ nearest lower integer]

So, the cycle time

\(T_c=2.5+0.53+\frac{1}{13}=3.11 min/pc\)

(d) Cost per production unit:

\(C_c= C_mT_c+\frac{C_e}{n_p}\)

\(\Rightarrow C_c=0.667\times3.11+\frac{1.33}{13}=\$2.18/pc\)

(e) Total time to complete the batch\(=2\times60+ {50\times 3.11}{50}=275.5 min=4.59 hr\).

(f) The proportion of time spent actually cutting metal

\(=\frac{50\times0.53}{275.5}=0.0962=9.62\%\)

Similarly, for the ceramic tool:

\(C_e=\) \(\$10/6=\$1.67/edge\)

\(T_t-1min\)

\(C= 3500 m/min\)

\(n=0.6\)

(a) Cutting speed:

\(V_{opt}= \frac {3500}{\left[ \left(1+\frac{1.67}{0.667}\right)\left(\frac{1}{0.6}-1\right)\right]^{0.6}}\)

\(\Rightarrow V_{opt}=2105 m/min\)

(b) Tool life,

\(T=\left[ \left(1+\frac{1.67}{0.667}\right)\left(\frac{1}{0.6}-1\right)\right]=2.33 min\)

(c) Cycle time:

\(T_c=T_h+T_m+\frac{T_t}{n_p}\)

\(\Rightarrow T_m=\frac{\pi \times 73 \times 250\times 10^{-6}}{0.3\times 10^{-3}\times 2105}=0.091 min/pc\)

\(n_p=\frac {2.33}{0.091}=25.6\)

\(\Rightarrow n_p=25 pc/tool\; life\)

So,

\(T_c=2.5+0.091+\frac{1}{25}=2.63 min/pc\)

(d) Cost per production unit:

\(C_c= C_mT_c+\frac{C_e}{n_p}\)

\(\Rightarrow C_c=0.667\times2.63+\frac{1.67}{25}=$1.82/pc\)

(e) Total time to complete the batch

\(=2\times60+ {50\times 2.63}=251.5 min=4.19 hr\).

(f) The proportion of time spent actually cutting metal

\(=\frac{50\times0.091}{251.5}=0.0181=1.81\%\)

Answer:

I don't know

Explanation:

sorry I am answering this for points

please follow and mark as brainliest for me I will also do same

Answer:

Adapting this case to a work environment, especifically an industry, there should be a security and health brigade in charge of response against emergencies within the organization. Said brigade has the duty of giving direction to all people that could be hurt in any way by a negative event caused by the emergency These directions are given orally in the case of emergencies. Also, emergency services personnel, such as police, firefighters, and paramedics, are certified professionals who have the responsibility of protecting people against harm, and this includes giving guidance during emergencies.