You have two cats. Each cat has a litter of K kittens. Write an expression that describes a total number of cats and kittens you have.
Answers
K=12
Hope that makes sense
Related Questions
Help with the Pythagorean Theorem
Answers
4^2 = 2^2 + b^2
b^2 = 4^2 - 2^2
b^2 = 16 - 4
b^2 = 12
b = square root of 12
b = square root of 4 x square root of 3
b = 2 x square root of 3
A = 2
B = 2 x square root of 3
C = 4
A textbook store sold a combined total of 288 history and psychology textbooks in a week. The number of history textbooks sold was two times the number of psychology textbooks sold. How many textbooks of each type were sold
Answers
Answer:
x=96 and y=192
Step-by-step explanation:
x+y=288 and 2x=y
plug y in and solve for x
x+2x=288
3x=288
x=96
plug x back in and solve for y
2(96)=y
y=192
Which answer choice correctly represents an algebraic expression for the sum of 15 and a number?
Answers
Let the number be x
Sum of 15 and the numberSum of 15 and xWe use addiition sign
x+15The expression is x+15
The article "Determination of Most Representative Subdivision" gave data on various characteristics of subdivisions that could be used in deciding whether to provide electrical power using overhead lines or underground lines. Data on the variable x = total length of streets within a subdivision are as follows.
1280 5320 4390 2100 1240 3060 4770 1050 360 3330 3380 340 1000 960 1320 530 3350 540 3870 1250 2400 960 1120 2120 450 2250 2320 2400 3150 5700 5220 500 1850 2460 5850 2700 2730 1670 100 5770 3150 1890 510 240 396 1419 2109
(a) Fill in a stem-and-leaf display for these data using the thousands digit as the stem. Do not truncate numbers. For example, number 2380 has stem-"2" and leaf-"380". (Enter solutions from smallest to largest. Separate the numbers with spaces.)
0 100 240 340 360 396 396 450 500 510 530 540 960 960
(b) Fill in the table below. (Round your answer to four decimal places if needed.)
Class Interval Frequency Relative Frequency
0 - <1000
2000 - < 3000
4000 - < 5000
5000 - < 6000
(c)
What proportion of subdivisions has total length less than 2000?
What proportion of subdivisions has total length between 2000 and 4000? (Round your answer to four decimal places if needed.)
Answers
a) The data is not symmetric
b) The complete table:
Class interval Frequency Relative Frequency
0-1000 12 0.255319151000-2000 11 0.234042552000-3000 10 0.212765963000-4000 7 0.148936174000-5000 2 0.04255319 5000-6000 5 0.10638298c) Proportion of subdivisions has total length less than 2000 is 0.49
Proportion of the subdivisions has total length between 2000 and 4000 is 0.36
a) To draw the stem and leaf plot we take the thousandth place digit as stem and the leaf is obtained by remaining digits.
Stem Leaf
0 360, 340, 960, 530, 540, 960, 450, 500, 100, 510, 240, 3961 280, 240, 050, 000, 320, 250, 850, 670, 890, 4192 100, 400, 120, 250, 320, 400, 460, 700, 730, 1093 060, 330, 380, 350, 870, 150, 1504 390, 7705 320, 700, 220, 850, 770The data is not symmetric
b) To draw the histogram first we form the frequency distribution and the relative frequency using the formula
Relative Frequencies are given by
Relative frequency = Frequency / Total frequency
Class interval Frequency Relative Frequency
0-1000 12 0.255319151000-2000 11 0.234042552000-3000 10 0.212765963000-4000 7 0.148936174000-5000 2 0.04255319 5000-6000 5 0.10638298= 47
Histogram attached at end of solution
The histogram is approximately positively skewed.
c) Proportion of lengths less than 2000 = sum of relative frequency from 0 to 2000
= 0.26 + 0.23
Proportion of subdivisions has total length less than 2000 = 0.49
Proportion of length between 2000 and 4000 = sum of relative frequency between 2000 and 4000
= 0.21 + 0.15
Proportion of the subdivisions has total length between 2000 and 4000 = 0.36
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Find the slope of the line passing through the points (6, 1) and (6,-4).
Answers
DI
A rectangle measures x cm
by (x + 4)cm.What are the width and length of the rectangle?
Answers
Answer:
gggghgbvbbnc niutuyyttttt
maggie has a ribbon that is 6ft long. how many 1/6 sections can she cut?
Answers
Ok so we know Maggie has a 6 feet ribbon. 1 ft of a ribbon is 6 sections so 6 ft of a ribbon is 36 sections.
Considering only the values of \(\beta\) for which \(\sin \beta \tan \beta \sec \beta \cot \beta\) is defined, which of the following expressions is equivalent to \(\sin \beta \tan \beta \sec \beta \cot \beta\)?
a. \(\sec \beta \cot \beta\)
b. \(\tan \beta\)
c. \(\cot \beta \tan \beta\)
d. \(\tan \beta \csc \beta \sec \beta\)
Answers
\(\large\boxed{Answer:}\)
We will use trigonometric identities to solve this. I will use θ (theta) for the angle.
First of all, we know that cotθ = 1/tanθ. This is a trigonometric identity.
We can replace cotθ in the expression with 1/tanθ.
\(sin\theta tan\theta sec\theta \frac{1}{tan\theta}\)
Simplify: 1/tanθ * tanθ = tanθ/tanθ = 1
So now, we have:
\(sin\theta sec\theta\)
Next, we also know that secθ = 1/cosθ. This is another trigonometric identity.
We can replace secθ with 1/cosθ in our expression.
\(sin\theta \frac{1}{cos\theta}\)
Simplify:
\(\frac{sin\theta}{cos\theta}\)
Our third trigonometric identity that we will use is tanθ = sinθ/cosθ.
We can replace sinθ/cosθ with tanθ.
Now we have as our final answer:
\(\large\boxed{b.\ tan\theta}\)
Hope this helps!
Answer:
\( \huge \boxed{ \boxed{ \red{b) \tan( \beta ) }}}\)
Step-by-step explanation:
to understand thisyou need to know about:trigonometryPEMDASgiven:\(\sin \beta \tan \beta \sec \beta \cot \beta\)tips and formulas:\( \tan( \theta) = \dfrac{ \sin( \theta) }{ \cos( \theta) } \)\( \cot( \theta) = \dfrac{ \cos( \theta) }{ \sin( \theta) } \)\( \sec( \theta) = \dfrac{1}{ \cos( \theta) } \)let's solve:\( \sf rewrite \: \tan( \beta ) \: as \: \dfrac{ \sin( \beta ) }{ \cos( \beta ) } : \\\sin (\beta ) \cdot\frac{ \sin( \beta ) }{ \cos( \beta ) } \cdot \sec (\beta ) \cdot\cot (\beta)\)\( \sf rewrite \: \sec( \beta ) \: as \: \dfrac{1 }{ \cos( \beta ) } : \\\sin (\beta) \cdot\frac{ \sin( \beta ) }{ \cos( \beta ) } \cdot \frac{1}{ \cos( \beta ) } \cdot\cot (\beta)\)\( \sf rewrite \: \cot( \beta ) \: as \: \dfrac{ \cos( \beta ) }{ \sin( \beta ) } : \\\sin (\beta) \cdot\frac{ \sin( \beta ) }{ \cos( \beta ) } \cdot \frac{1}{ \cos( \beta ) } \cdot \: \dfrac{ \cos( \beta ) }{ \sin( \beta ) }\)\( \sf \: cancel \: sin : \\\sin (\beta) \cdot\frac{ \cancel{\sin( \beta ) }}{ \cos( \beta ) } \cdot \frac{1}{ \cos( \beta ) } \cdot \: \dfrac{ \cos( \beta ) }{ \cancel{\sin( \beta ) }} \\ \sin (\beta) \cdot\frac{ 1 }{ \cos( \beta ) } \cdot \frac{1}{ \cos( \beta ) } \cdot \: \cos( \beta ) \\ \)\( \sf cancel \: cos : \\ \sin (\beta) \cdot\frac{ 1}{ \cos( \beta ) } \cdot \frac{1}{ \cancel{ \cos( \beta )} } \cdot \: \cancel{ \cos( \beta ) } \\ \\ \sin( \beta ) \: \cdot \: \dfrac{ 1 }{ \cos( \beta ) } \)\( \sf \: simplify \: multipication : \\ \dfrac{ \sin( \beta ) }{ \cos( \beta ) } \)\( \sf use \: \frac{ \sin( \beta ) }{ \cos( \beta ) } = \tan( \beta ) \: identity : \\ \therefore \: \tan( \beta ) \)Cellular phone usage grew about 22% each year from 1995 (about 34 million) to 2003. Write a function to model cellular phone usage over that time period. What is the cellular usage in 2003?
Answers
Answer:
Given the information you provided, we can model cellular phone usage over time with an exponential growth model. An exponential growth model follows the equation:
`y = a * b^(x - h) + k`
where:
- `y` is the quantity you're interested in (cell phone usage),
- `a` is the initial quantity (34 million in 1995),
- `b` is the growth factor (1.22, representing 22% growth per year),
- `x` is the time (the year),
- `h` is the time at which the initial quantity `a` is given (1995), and
- `k` is the vertical shift of the graph (0 in this case, as we're assuming growth starts from the initial quantity).
So, our specific model becomes:
`y = 34 * 1.22^(x - 1995)`
To find the cellular usage in 2003, we plug 2003 in for x:
`y = 34 * 1.22^(2003 - 1995)`
Calculating this out will give us the cellular usage in 2003.
Let's calculate this:
`y = 34 * 1.22^(2003 - 1995)`
So,
`y = 34 * 1.22^8`
Calculating the above expression gives us:
`y ≈ 97.97` million.
So, the cellular phone usage in 2003, according to this model, is approximately 98 million.
Jim saw that other bank offered the same rates but compounded the interest more often. Consider if he still put $15,000 into a saving account for 5 years that provided 2.8% annually but compounded it in each of the following ways match the following:
Weekly-
Daily-
Continuously-
Monthly-
Semi-annually-
Quarterly-
Answers
Answer:
See Picture. I made a 100.
Step-by-step explanation:
Weekly- $17253.46
Daily- $17254.01
Continuously- $17254.11
Monthly- $17251.29
Semi-annually- $17237.36
Quarterly- $17245.69
Compound interest is the addition of interest on the interest of the principal amount.
What is compound interest?Compound interest is the addition of interest on the interest of the principal amount. It is given by the formula,
\(A = P(1+ \dfrac{r}{n})^{nt}\)
As it is given that the principal amount is $15,000; while the rate of interest is 2.8%, and the amount is invested for a period of 5 years.
A.) When the interest is charged weekly,
As we know that there are 52 weeks in a year, therefore, n = 52, substitute the values,
\(A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{52})^{52 \times 5}\\\\A = \$17,253.46\)
B.) When the interest is charged daily,
As we know that there are 365 days in a year, therefore, n = 365, substitute the values,
\(A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{365})^{365 \times 5}\\\\A = \$19,554.55\)
C.) When the interest is charged Continuously,
As we know that the formula for continuous compounding is given as,
\(A = Pe^{rt}\)
Substitute the values, we will get,
\(A = 15000 \times (e^{0.024 \times 5})\\\\A= \$16,912.45\)
D.) When the interest is charged Monthly,
As we know that there are 12 months in a year, therefore, n = 12, substitute the values,
\(A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{12})^{12\times 5}\\\\A = \$15211.23\)
E.) When the interest is charged Semi-annually,
As we know that the interest is charged Semi-annually, therefore, n = 2, substitute the values,
\(A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{2})^{2\times 5}\\\\A = \$17,237.36\)
F.) When the interest is charged Quarterly,
As we know that the interest is charged Quarterly, therefore, n = 4, substitute the values,
\(A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{4})^{4\times 5}\\\\A = \$17,245.7\)
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Tricia made a 72% on her science test. if she got 18 problem correct, how many questions were on the test?
Answers
Answer: 25 questions
Step-by-step explanation:
Compare the numbers
0.4 and 0.19
<
>
+
Answers
Answer:
0.4 > 0.19
Step-by-step explanation:
you can view it as 40 and 19, so which is bigger 40 or 19?
Yo can someone help me out
Answers
Answer:
theres an black screen
Step-by-step explanation:
mark as brainliest!!
Answer:
Cant see the image
Please help
Picture inserted
Multiple choice
Will appreciate it if u help!
Answers
Answer: B) Linear; it can be written as y = -3x-6
We subtract 6 from both sides to go from the original equation to -3x-6 = y
Then we flip both sides to end up with y = -3x-6
This is in slope intercept form y = mx+b with m = -3 as the slope and b = -6 as the y intercept.
What is the area ,in square units ,of triangle KLM?
Answers
Given:
The triangle KLM is given.
To find:
The area of the triangle.
Explanation:
Using the formula,
\(Area\text{ of the triangle=Area of the rectangle-Area of the triangle 1 - Area of the triangle 2 - Area of triagnle 3.}\)Substituting the values we get,
\(\begin{gathered} A=lb-\frac{1}{2}b_1h_1-\frac{1}{2}b_2h_2-\frac{1}{2}b_3h_3 \\ A=6\times5-\frac{1}{2}\times5\times4-\frac{1}{2}\times2\times2-\frac{1}{2}\times3\times6 \\ A=30-10-2-9 \\ A=9square\text{ units.} \end{gathered}\)Final answer:
The area of the triangle is 9 square units.
Some parts of California are particularly earthquake- prone. Suppose that in one metropolitan area, 25% of all homeowners are insured against earthquake damage. Four homeowners are to be selected at random; let X denote the number among the four who have earthquake insurance. a. Find the probability distribution of X. [Hint: Let S denote a homeowner who has insurance and F one who does not. Then one possible outcome is SFSS, with proba bility (.25)(.75)(.25)(.25) and associated X value 3. There are 15 other outcomes.] b. Draw the corresponding probability histogram. c. What is the most likely value for X
Answers
Answer:
a. Binomial random variable (n=4, p=0.25)
b. Attached.
c. X=1
Step-by-step explanation:
This can be modeled as a binomial random variable, with parameters n=4 (size of the sample) and p=0.25 (proportion of homeowners that are insured against earthquake damage).
a. The probability that X=k homeowners, from the sample of 4, have eartquake insurance is:
\(P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{4}{k} 0.25^{0}\cdot0.75^{4}\)
The sample space for X is {0,1,2,3,4}
The associated probabilties are:
\(P(x=0) = \dbinom{4}{0} p^{0}(1-p)^{4}=1*1*0.3164=0.3164\\\\\\P(x=1) = \dbinom{4}{1} p^{1}(1-p)^{3}=4*0.25*0.4219=0.4219\\\\\\P(x=2) = \dbinom{4}{2} p^{2}(1-p)^{2}=6*0.0625*0.5625=0.2109\\\\\\P(x=3) = \dbinom{4}{3} p^{3}(1-p)^{1}=4*0.0156*0.75=0.0469\\\\\\P(x=4) = \dbinom{4}{4} p^{4}(1-p)^{0}=1*0.0039*1=0.0039\\\\\\\)
b. The histogram is attached.
c. The most likely value for X is the expected value for X (E(X)).
Is calculated as:
\(E(X)=np=4\cdot0.25=1\)
At Silver Gym, membership is $25 per month, and personal training sessions are $40 each. At Fit Factor, membership is $75 per month, and personal training sessions are $30 each. In one month, how many personal training sessions would Sarah have to buy to make the total cost at the two gyms equal?
Answers
Answer:
5
Step-by-step explanation:
You start with each membership for each gym as your starting point, then you add the personal sessions to that number.
Silver Gym: 25 65 105
Fit Factor: 75 105
As you can see, it will take Sarah 5 sessions to have both costs equal
Write a second degree polynomial with real coefficients and the given root; -2i
Answers
Answer: x^2+4
Work Shown:
x = -2i
x^2 = (-2i)^2
x^2 = 4i^2
x^2 = 4(-1)
x^2 = -4
x^2+4 = 0
Side note: Since -2i is one root, this means 2i is the other conjugate root.
\(\text{For quadratic equations, if one root is complex, the other root will be its conjugate.}\\\\\text{So, the roots of the second degree polynomial are}~ \alpha = -2i ~~ \text{and}~~ \beta =2i \\\\\text{The equation is,}\\\\~~~~~~~x^2-(\alpha + \beta) x +\alpha \beta = 0\\ \\\implies x^2 -(-2i+2i)x +(2i)(-2i)=0\\\\\implies x^2 -0\cdot x -4i^2 =0\\ \\\implies x^2 -4(-1)=0\\\\\implies x^2 +4=0\)
PLEASE DO NUMBER 1 SHOW WORK TOO PLEASE
Answers
Answer:
A) False - not a right angle
B) True - it is a right angle
C) True - it is a right angle
D) False-not a right angle
Step-by-step explanation:
A) a*a+b*b=c*c (Asquared+Bsquared=C squared)
2*2+ 3*3 = 4*4
4+9=16
13 does not equal 16
B) 5*5+12*12=13+13
25+144=169
169=169 - True
C) 3*3+4*4=5*5
9+16=25
25=25 (True)
D) 4+ Root of 3 = Root of 19
False - square root of a prime number is irrational
Someone please help, thank you
Answers
Step-by-step explanation:
everything can be found in the picture
Answers:
(a) \(n = 2(r+m)\)
(b) \(n = \frac{h^2}{9}\)
===========================================
Work Shown:
Part (a)
\(\frac{n}{2} - m = r\\\\\frac{n}{2} = r+m\\\\n = 2(r+m)\)
In the second step, I added m to both sides. Afterward, I multiplied both sides by 2 to fully isolate n.
------------------------
Part (b)
\(3\sqrt{n} = h\\\\\sqrt{n} = \frac{h}{3}\\\\n = \left(\frac{h}{3}\right)^2\\\\n = \frac{h^2}{3^2}\\\\n = \frac{h^2}{9}\\\\\)
First I divided both sides by 3. After that, I squared both sides. The (h/3) squares to (h^2)/9.
What ordered pairs are the solutions of the system of equations shown in the graph below?
Answers
Answer:
(4,0) & (9,5)
Step-by-step explanation:
Where the equations cross are the solutions!
Hope this Helps! :)
Happy Studies
At mayas house they gave out candy to trick-or-treaters
Answers
Answer:
whats the rest of the question
Step-by-step explanation:
6) Lily was going to have a party so she
bought some sweets.She bought some
cookies and brownies. Cookies were $2 and
brownies were $3. She spent $144 for a total
of 60 sweets. How many cookies and
brownies did she buy?
Answers
Let's assume the number of cookies Lily bought is represented by "C," and the number of brownies is represented by "B."
According to the problem, the cost of one cookie is $2, and the cost of one brownie is $3. Lily spent a total of $144.
We can set up two equations based on the given information:
C + B = 60 (equation 1, representing the total number of sweets)
2C + 3B = 144 (equation 2, representing the total cost in dollars)
To solve this system of equations, we can use substitution or elimination method. Here, we'll use the substitution method.
From equation 1, we can rewrite it as C = 60 - B.
Now substitute this value of C in equation 2:
2(60 - B) + 3B = 144
Simplify the equation:
120 - 2B + 3B = 144
Combine like terms:
120 + B = 144
Subtract 120 from both sides:
B = 144 - 120
B = 24
Now substitute the value of B back into equation 1 to find C:
C + 24 = 60
C = 60 - 24
C = 36
Therefore, Lily bought 36 cookies and 24 brownies.
A student spends 17/35 of his pocket money on transport. He spends 5/6 of the remainder on sweet, what fraction of his pocket money did he spend on sweet?
Answers
Answer:
Step-by-step explanation:
Let he have Rs . 1
spent on transport = 17/35
spent on sweet = 5/6 of 18/35
= 3/7
Select the closest answer. *
20 points
1. Find the surface area of a sphere with a radius of 4.2 centimeters.
A. 235.6 cm?
C. 121.4 cm
B. 310.3 cm
D. 221.7 cm
A
B
С
OD
Select the closest answer.
Answers
Answer:
D. 221.7 cm
Step-by-step explanation:
Surface area of a sphere is: \(SA=4\pi r^2\)
'r' - radius
We are given the radius of 4.2 centimetres.
\(SA=4\pi 4.2^2\\4 * \pi * 4.2^2\\\rightarrow 4.2^2 =17.64\\\text {Using 3.14 for pi: }\\4 * 3.14 *17.64\\12.56*17.64\\\boxed {221.5584}\)
221.5584 ≈ 221.6
The closest answer is Option D, therefore it should be the correct answer.
Find the quotient. 7/9÷4
Answers
Answer:
0.19444444444
Step-by-step explanation:
Answer:
7/36
Step-by-step explanation:
(7/9)/4
7/36
PLEASE HELP ME!!!!!!!!!!!!!
Answers
Answer:
Here are the answers:
\(a = \frac{b}{5} \)
\(y = 40x\)
Answer: y = 60x
Step-by-step explanation:
PLEASEEEEE HELP!!!!!!!
Answers
The area of shaded region is calculated as: 24π m²
The length of arc ADB is calculated as: 8π m.
How to Find the Area of the Shaded Region and the Length of the Arc?Recall the two formulas below:
Area of shaded region = ∅/360 * πr²
Length of arc = ∅/360 * 2πr.
Given the following:
∅ = 360 - 120 = 240°
radius (r) = 6 m
Plug in the values:
Area of shaded region = 240/360 * π * 6² = 24π m²
Length of arc = 240/360 * 2 * π * 6
Length of arc = 8π m
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How Do You get: 5(5x + 2x /5 x 8)<78
Answers
Answer:
x < 1.39285714286
Step-by-step explanation:
5(5x+2x/5x8)<78
x5 x5
5(5x+2x(8))<390
/8 /8
5(5x+2x)<48.75
5(7x)<48.75
/5 /5
7x < 9.75
/7 /7
x < 1.39285714286
Solve the system of equations -6x-y=-16 and -6x-5y=-8 by combining equations
Answers
Answer:
\(\left \{ {{y=-2} \atop {x=3}} \right.\)
Step-by-step explanation:
\(\left \{ {{-6x - y = -16} \atop {-6x - 5y = -8}} \right. <=> \left \{ {{4y= -8} \atop {-6x-5y =-8}} \right. <=> \left \{ {{y=-2} \atop {-6x-5y=-8}} \right. <=> \left \{ {{y=-2} \atop {-6x-5*(-2)=-8}} \right. <=> \left \{ {{y=-2} \atop {-6x=-18}} \right. <=> \left \{ {{y=-2} \atop {x=3}} \right.\)