you have two iron bars and a ball of string in your possession; one iron bar is magnetized, and one iron bar is not. how can you determine which iron bar is magnetized?

\(\huge\underline\mathtt\colorbox{cyan}{G=}\)

\(6.673 \times {10}^{ - 11} \)

And unit is Nm^2/kg^2

Explanation:

The attractive force between two bodies when multiplied by the product of the masses of two bodies and divided by the square of the distance between them.

Answer:

This is a Upside down Glass of Water Experiment

Explanation:

Explanation:

if I interpret the graphic correctly, then there is a basin fully filled with water on the left, then a piece of paper of a piece of glass, where the paper is in contract with the water on the left, and some water is delivered to the right.

then i suspect this shows the capillary effect of very narrow channels of water. like in the very tiny spaces between the fibers of the paper. as long as the paper is in contact with the water on the left, and the level of water is there higher than on the right, the surface tension of water kind of propels itself further along these narrow channels in the paper and supported by gravity and air pressure it drops even into the other side.

Option A

Answer:

d) Calcium is malleable, Sulfur is not malleable.

Explanation:

Calcium is a metal and shows property of malleability. Sulfur is a non metal and it does not shows property of malleability. Hence, option (d) is the correct answer.

Answer:

See below

Explanation:

Mass   3.05 x 10^6  

  convert to weight in Newtons by multiplying by acceleration of gravity (9.81 m/s^2)

3.05 * 10^6  kg    * 9.81  m/s^2 =      30.0 x 10^6 N

force up =  34.0 x 10^6   N      <======given

force down = 30.0 x 10^6 N    <==== just calculated above

 difference =    4 x 10^6 N

Remember  F= ma    

    or re-arranged to   F/m = a

                      4 x 10^6 N  / (3.04 x10^6kg) = 1.32 m/s^2

The stopping distance of d2 expressed in terms of d2 be 18d1.

According to Newton's Second Law of Motion, acceleration (gaining speed) occurs whenever a force acts on a mass (object). This law of motion is best demonstrated by riding a bicycle. The mass is your bicycle. Your leg muscles pushing against the bicycle pedals is the force.

In fact, the formula F=ma states that force is equal to mass times acceleration. This also implies that a ball will travel farther the harder you kick it.

According to newton's second law of motion, F = ma.

By using kinematic equation, we get

v²= u² + 2as

substituting the values in the above equation, we get

0 = 2ad + 2Fd/m

d = v² m/ 2F

Similarly, we can write this equation as

v²₂= u² ₂+ 2as

simplifying the above equation, we get

d₂ =(3v)² m  /F

d₂/d1 = (3v)² m /F/ 2f/ v² m

d₂/d1 = 9v² m/ v²

d₂ = 18 d1

Therefore, the stopping distance of d2 expressed in terms of d1 d2= 18d1.

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Answer:

When a body is released from a height, it has potential energy due to its position in the earth's gravitational field. As the body falls towards the ground, its potential energy is converted into kinetic energy, which is the energy of motion. We can use the law of conservation of energy to determine the energy changes of the body during its fall.

a) The potential energy of the body, when it reaches the ground is equal to 100J.

This statement is false. When the body reaches the ground, it has zero potential energy because it is at ground level. All the potential energy the body had at the top of its fall has been converted into kinetic energy as it falls.

b) The kinetic energy of the body, in the middle of the path is equal to 100J.

This statement is false. The kinetic energy of the body depends on its velocity. As the body falls, its velocity increases, and so does its kinetic energy. At the midpoint of the fall, the body has only half of its total kinetic energy.

c) The mechanical energy of the body, just before it reaches the ground is equal to 100J.

This statement is true. The mechanical energy of the body is the sum of its kinetic and potential energy. At the moment just before it hits the ground, the body has zero potential energy and maximum kinetic energy, which is equal to its initial potential energy of 100J.

d) The potential energy of the body, in the middle of the path is equal to 100J.

This statement is false. The potential energy of the body is proportional to its height above the ground. At the midpoint of the fall, the body has fallen halfway, so its height is half of its initial height. Therefore, its potential energy is half of its initial potential energy, which is 50J.

e) The kinetic energy of the body, when it reaches the ground is equal to 100J.

This statement is false. The kinetic energy of the body just before it hits the ground is equal to its total mechanical energy, which is 100J. However, as soon as the body hits the ground, some of its kinetic energy is dissipated as heat and sound, and it comes to a stop. Therefore, its kinetic energy at the moment it reaches the ground is zero.

In summary, the true statement is c) The mechanical energy of the body, just before it reaches the ground is equal to 100J

Explanation:

pls correct me if wrong

(I would appreciate a Brainliest rating if this helped you)

Answer:

FALSE: a) The potential energy of the body, when it reaches the ground is equal to 100j

FALSE: b) The kinetic energy of the body, in the middle of the path is equal to 100j

TRUE: c) The mechanical energy of the body, just before it reaches the ground is equal to 100j

FALSE: d) The potential energy of the body, in the middle of the path is equal to 100j

TRUE: e) The kinetic energy of the body, when it reaches the ground is equal to 100j​

Explanation:

When an object is dropped from a height or released from the ground, it starts moving downward due to the force of gravity. The potential energy of the object is converted into kinetic energy as it gains speed.

a) The potential energy of the body, when it reaches the ground is equal to 0j. This is because all of the potential energy has been converted to kinetic energy as the object falls.

b) The kinetic energy of the body, in the middle of the path is less than 100j. This is because some of the potential energy has been converted into kinetic energy as the object falls, but it has not yet reached its maximum speed.

c) The mechanical energy of the body, just before it reaches the ground is equal to 100j. This is because the mechanical energy of the object (potential energy + kinetic energy) remains constant, and all of the potential energy has been converted to kinetic energy.

d) The potential energy of the body, in the middle of the path is less than 100j. As explained in (b), some of the potential energy has been converted into kinetic energy as the object falls, but it has not yet reached its maximum speed.

e) The kinetic energy of the body, when it reaches the ground is equal to 100j. This is because all of the potential energy has been converted to kinetic energy as the object falls, and it has reached its maximum speed just before hitting the ground.

Answer:

440kgm/s

Explanation:

Momentum= mass × velocity

= 110× 4

= 440kgm/s

Answer:

Explanation:

The mass of the car can be found by using the formula

\(m = \frac{2k}{ {v}^{2} } \\ \)

From the question we have

\(m = \frac{2 \times 300000}{ {20}^{2} } = \frac{600000}{400} = \frac{6000}{4} \\ \)

We have the final answer as

Hope this helps you

Answer:

C

Explanation:

Am increase in velocity?

Answer:

change in mass is not acceleration

Answer:

(i) Please see graph of the motion of the particles created with MS Excel and the calculations in the following sections

(ii) The time of collision is approximately 1.0 seconds

(iii) The common horizontal distance of point collision from the point of projection is approximately 25.2 meters

Explanation:

The velocity with which the first projectile was fired, v₁ = 21 m/s

The angle to the horizontal the particle is launched = 53.1°

The time at which the other particle was launched = 1 second later

The location from which the other particle was projected = 0.3 m below the first particle

The initial velocity of the second particle = 31.5 m/s

The angle to the horizontal at which the second particle was projected, θ = 36.9°

(i) The height reached, by each of the particle is given as follows;

y = u·t - 1/2·g·t²

For the first projectile, we have;

y = 21·(t₁+1)×sin(53.1°) - 9.81·(t₁+1)²/2 + 0.3

For the second projectile, we have;

y= 31.5·(t₁)×sin(36.9°) - 4.905·(t₁)²

If the two projectiles collide, we get;

21·(t₁+1)×sin(53.1°) - 9.81·(t₁+1)²/2 + 0.3  = 31.5·(t₁)×sin(36.9°) - 4.905·(t₁)²

Using a graphing calculator for simplifying, we get;

-11.93·t₁ + 12.2 = 0

t₁ = 12.2/11.93 ≈ 1.02

Therefore, at time t₁ = 1.02 seconds, after the launch of the second particle, the two particle will be at the same vertical height

However, whereby at the time, t₂, the particles collide, the horizontal distance travelled, 'x', will be equal;

We have;

x = u·cos(θ)·t₁

For the first particle, we have;

x₁₁ = 21 × cos (53.1°) × (t₂ + 1)

For the second particle, we have;

x₂₂ = 31.5 × cos (36.9°) × t₂

At the point of collision, we have;

x₁ = x₂

∴ 21 × cos (53.1°) × (t₂ + 1) = 31.5 × cos (36.9°) × t₂

31.5 × cos (36.9°) × t₂ - 21 × cos (53.1°) × t₂ = 21 × cos (53.1°)

t₂ = 21 × cos (53.1°)/(31.5 × cos (36.9°)  - 21 × cos (53.1°) ) = 1.00219236871

t₂ ≈ 1.0 seconds

Given that t₁ ≈ t₂, the particles reach the same height and the same horizontal distance at the same time, t₂ ≈ 1.0 and therefore, they collide.

(ii) The time of collision is found above as t₁ ≈ t₂ ≈ 1.0 seconds

(iii) The horizontal distance of the point of collision from the starting point, 'x', is given as follows;

x = 21 × cos (53.1°) × (1.0 + 1) ≈ 25.2

The horizontal distance of the point of collision from the starting point, x ≈ 25.2 meters

The vertical distance of the point of collision from the starting point of the second particle, 'y', is given as follows;

y = 21 × (1+1)×sin(53.1°) - 9.81 × (1+1)²/2 + 0.3 ≈ 14

The vertical distance of the point of collision from the starting point of the second particle, y ≈ 14 meters

The magnitude of the distance from the starting point of the second particle, r = √(25.2² + 14²) ≈ 28.8

The magnitude of the distance from the starting point of the second particle, r ≈ 28.4 meters.

Visible light , The process by which plants convert carbon dioxide, water, and sunshine into oxygen and sugar-based energy is known as photosynthesis.

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To find the electric field between the two points, we can use the formula. So, the electric field between the two points is approximately 10.57 V/m.

Electric field = Potential difference / Distance between the points
Plugging in the given values, we get:
Electric field = 44.4 V / 4.2 m
Electric field = 10.57 V/m
Therefore, the electric field between the two points is 10.57 V/m.

To find the electric field between two points with a potential difference, you can use the formula:
Electric Field (E) = Potential Difference (V) / Distance (d)
In this case, the two points are 4.2 meters apart and the potential difference between them is 44.4 V. Plugging these values into the formula, we get:
E = 44.4 V / 4.2 m
E ≈ 10.57 V/m
So, the electric field between the two points is approximately 10.57 V/m.

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The distance traveled by a person is 78 m, and the angle made by the path of the person with the positive x-axis is 158 degrees. To find: The x-component of displacement of the person.

We have the distance traveled by a person, let's call it 'd'.d = 78 m. Next, we will find the x-component of displacement using the given angle. We know that:x-component = d * cos(angle)We need to convert the angle to radians because the cos function expects an angle in radians. So, let's convert the given angle to radians.1 degree = π/180 radians.So, 158 degrees = 158 * π/180 radians= (79π/90) radians. Now, let's substitute the values in the formula of the x-component of displacement:

x-component = d * cos(angle)x-component = 78 * cos(79π/90)x-component = 78 * (-0.3420)x-component = -26.676 m

Therefore, the x-component of displacement is -26.676 m.

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Solving for v2, we find that the canister must be shot at approximately 0.599c relative to the first spaceship to approach the second ship at 0.999c as seen by the second ship.

To find the speed at which the canister must be shot from the first spaceship to approach the second ship at 0.999c, we can use the relativistic velocity addition formula:
\(v = (v1 + v2) / (1 + (v1 * v2 / c^2))\)
Here, v1 is the relative velocity of the two spaceships (0.800c), v2 is the speed of the canister relative to the first spaceship, and v is the desired speed of the canister relative to the second spaceship (0.999c).
Solving for v2, we get:
\(v2 = ((v * (1 + (v1 * v2 / c^2))) - v1) / (1 - (v1 * v / c^2))\)
Plugging in the values, we get:
v2 = ((0.999c * (1 + (0.800c * v2 / c^2))) - 0.800c) / (1 - (0.800c * 0.999c / c^2))

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The answer is W = 1.06 MJ.

Now develop and express of Force required:

                                            F = p*V*g

                                            F = 1000*(2*0.5*x*8*dx)*g

                                            F = 78480*x*dx

- Now, the work done is given by:

                                   W = F.s

Where s is the distance from the top of the hose to the differential volume:

                                        s = (5 - x)

We have the work as follows:

                              dW = 78400*x*(5-x)dx

Now integrate the following express from 0 to 3 till the tank is empty:

 W = 78400*(2.5*x^2 - (1/3)*x^3)

 W = 78400*(2.5*3^2 - (1/3)*3^3)

 W = 78400*13.5 = 1058400 J

To find the weight of water, begin by way of finding the density(1 kg/L at 39.2°) and the extent of water. Convert the volume of water to liters after which multiply by way of the density to discover the burden.

Density is useful in calculating the load of materials which can be tough to weigh. you may decide its weight without a doubt with the aid of multiplying the density by using the dimensions, or quantity, of the item.

The unique weight, additionally called the unit weight, is the weight in keeping with the unit quantity of cloth. A typically used value is the precise weight of water in the world at 4 °C (39 °F), which is nine.807 kilonewtons consistent with cubic meters or 62. 43 pounds-force in keeping with cubic foot.

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This happens at Sun 's inside

This denotes to

It releases lots of solar energy which can be used to create electricity

Answer:

V= in square root 2KE/M=2(143.3J)/0.047kg=6097.8723 in square root around 78.1 approxmete

Explanation:

Answer: The velocity of the bird is 7m/s

Explanation: Since momentum is the total quantity of the motion which is contained in the body.

It is defined as the multiply of mass and velocity of the body

It is given in the question that mass of bird is 2.5 kg and momentum is 17.5 kg/s.

This question involves the concept of Colomb's Law and electrostatic force.

The electrostatic force will be "0.2 N".

According to Colomb's Law, every charge exerts an electrostatic force on the other charge, which is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them.

\(F=\frac{kq_1q_2}{r^2}\)

where,

In case of +2 C charges:

Therefore,

\(0.1\ N = \frac{(9\ x\ 10^9\ N.m^2/C^2)(2\ C)(2\ C)}{r^2}\\\\r^2=\frac{(9\ x\ 10^9\ N.m^2/C^2)(2\ C)(2\ C)}{0.1\ N}\\\\r^2=3.6\ x\ 10^{11}\ m^2\)

Now, for the second case:

Therefore,

\(F=\frac{(9\ x\ 10^9\ N.m^2/C^2)(2\ C)(4\ C)}{3.6\ x\ 10^{11}\ m^2}\)

F = 0.2 N

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Thr only way living things can slow down the process of entropy is through anabolic processes.

Entropy is the degree of disorderliness or randomness of a substance.

According to the second law of thermodynamics, the entropy of a system always tends to increase.

Metabolism in living things involves two processes:

Catabolism increases entropy whereas anabolism decreases entropy.

Therefore, the only way living things can slow down the process of entropy is by anabolic processes.

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Answer:

The zone of which g (gravity) decreases with depth below the Earth's surface is the mantle, which is the layer of Earth in between the crust and the core. The mantle makes up around 84% of the Earth's volume, and extends from around 5 km below the Earth's surface to a depth of 2900 km.

The mantle is composed of solid rock, with the outermost parts of it being composed of more dense, rigid rock. As we go deeper into the mantle, the rock becomes increasingly less dense. The decrease in density along with the increase in pressure creates a decrease in g-force with depth. The decrease in g-force has been measured to continue down to a depth of 2,900 km, at which point the g-force levels off.

Answer:

C.

Explanation:

c. the source is written by the person who conducted the experiment. A primary source is an original piece of information created at the time under study. It can be a diary, a letter, a photograph, a recording, or any other type of artifact. It provides firsthand information about an event or topic, and is created by a person who was directly involved or witnessed it.

Answer:

57.885.8 kg   weight of the container

Explanation:

The volume of the balloon * density of water = buoyant force of balloon

 volume of a sphere = 4/3 pi r^3

                                   = 4/3 pi * (1.5)^3 = 14.14 m^3   <===balloon volume

Now,   find the buoyant force on the container ALONE ....

             5.8 * 2.6 * 2.8  * 1027  = 43 364  kg   <=====  buoyant force

Now add the buoyant force of the balloon to find the weight

             43 364  +   14.14 * 1027 = 57885.8   kg

There are 90 degrees directly overhead. Barnard is at 74 degrees at Sam's position, 1300.0 kilometers south. The part of the 360 degree circle that corresponds to Hua's circumference is the difference between 90 and 74, or 16 degrees. 1300.0 km is therefore 16/360 of the circle, or 0.044 times the circumference. 29.250 km is the circumference (1300 divided by 0.044). Radius divided by two gives the circumference equation. Therefore, 2r=29250 and the radius of Hua=4655.3 km

Astronomy is a scientific science that examines celestial objects and phenomena (from the Ancient Greek "o" (astronoma), "science that investigates the laws of the stars"). In order to describe their creation and evolution, it makes use of mathematics, physics, and chemistry. Planets, moons, stars, nebulae, galaxies, and comets are among the interesting celestial bodies. Supernova explosions, gamma ray bursts, quasar, blazar, pulsar, and cosmic microwave background radiation are examples of relevant phenomena. Astronomy is the study of everything that comes from outside the atmosphere of the Earth. Astronomical cosmology is the study of the cosmos as a whole.

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The speed of man when the length of his shadow on the building decreases when he is 4 m from the building will be 0.6 m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

Distance from spot shines =  12 m away

Height of man,h=2 m tall

Speed of man +1.6 m/s,

Distance from the building = 4 m

Let the height of shadow= y,

CD=x

Height of man=2 m

Speed of man:

\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)

As the triangle ABD and ECD are similar. The property of the similarity is found as;

\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24\)

Differentiate the above question with respect to x;

\(\rm x \frac{dy}{dt}+y\frac{dx}{dt}=0 \\\\ x\frac{dy}{dt}= -y\frac{dx}{dt}\)

From the given conditions the man is 4 m from  the building the value of the remaining distance x is;

x=12-4

x=8 m

Speed of man:

\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)

On putting all the values we get;

\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24 \\\\ 8y = 24 \\\\ y= 3\)

The speed of man when the  length of his shadow on the building decreases when he is 4 m from the building;

\(\rm \frac{dy}{dt} = - \frac{3}{8} \times 1.6 \ m/sec \\\\\ \frac{dy}{dt} = 0.6 \ m/sec.\)

Hence the value of the speed for the given conditions willl be 0.6 m/sec.

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MRI systems are generally thousands of times stronger than a refrigerator magnet. The strength of a magnet is measured in units called Tesla (T). A typical refrigerator magnet has a magnetic field strength of around 0.001 Tesla or 1 milliTesla (mT).

In contrast, MRI systems used in medical imaging operate at much higher field strengths, typically ranging from 1.5 Tesla to 3 Tesla or even higher.To put it into perspective, a 1.5 Tesla MRI scanner is approximately 1500 times stronger than a refrigerator magnet, while a 3 Tesla MRI scanner is approximately 3000 times stronger. These high magnetic field strengths are necessary for producing detailed and high-quality images of the body's tissues and organs during an MRI examination.It's worth noting that the strength of an MRI system can vary depending on the specific model and technology used. Advanced MRI systems with even higher field strengths, such as 7 Tesla or 9.4 Tesla, are also available for specialized research and clinical applications. These extremely high-field MRI systems are significantly stronger than a refrigerator magnet, often by tens of thousands of times.

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Answer:

C. 540 N

Explanation:

Let suppose that system formed by the athlete and the load are in equilibrium. By Newton's Laws of Motion, we use the moment equation with respect to the feet of the athlete to determine the upward force exerted by his two arms:

\(\Sigma M = -F\cdot r_{1} + m_{L}\cdot g \cdot r_{2} + m_{A}\cdot g \cdot r_{3} = 0\)

\(F = \frac{(m_{L}\cdot r_{2} + m_{A}\cdot r_{3})\cdot g}{r_{1}}\) (1)

Where:

\(m_{L}\) - Mass of the load, in kilograms.

\(m_{A}\) - Mass of the athlete, in kilograms.

\(g\) - Gravitational acceleration, in meters per square second.

\(r_{1}\), \(r_{2}\), \(r_{3}\) - Distances with respect to the feet, in meters.

\(F\) - Upward force exerted by his two arms, in newtons.

If \(m_{L} = 6\,kg\), \(r_{2} = 1.20\,m\), \(m_{A} = 70\,kg\), \(r_{3} = 0.90\,m\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(r_{1} = 1.30\,m\), then the upward force is:

\(F = \frac{[(6\,kg)\cdot (1.20\,m)+(70\,kg)\cdot (0.90\,m)]\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{1.30\,m}\)

\(F = 529.578\,N\)

The upward force exerted by his two arms is 529.578 newtons. (Right answer: C)