you may use sources in your essay that both support and refute your argument. true or false

Answers

Answer 1

The given statement is True,

it is acceptable to use sources in an essay that both support and refute your argument. In fact, including such sources can strengthen the essay by demonstrating a comprehensive understanding of the topic and acknowledging opposing viewpoints. However, it is important to present these sources in a balanced and fair manner.

When using sources that support your argument, it is important to evaluate the credibility and relevance of the source. The information presented should be accurate and directly related to the topic being discussed. On the other hand, when using sources that refute your argument, it is important to acknowledge the opposing viewpoint and present it accurately without misrepresenting itBy including sources that both support and refute your argument, you can provide a well-rounded perspective on the topic and show that you have considered all sides of the issue. It also allows the reader to form their own opinion and make an informed decision based on the evidence presented.In conclusion, it is true that using sources that both support and refute your argument is acceptable in an essay. However, it is important to use them in a balanced and fair manner, and to evaluate their credibility and relevance before including them in your essay.

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Related Questions

Under a subsection for geological hazards the buyer is encouraged to obtain an read the booklet

Answers

Answer:

Buyer is encouraged to obtain and read the booklet entitled "The Homeowners Guide to Earthquake Safety." In most cases a questionnaire within the booklet must be completed by Seller and the entire booklet given to the Buyer if the Property was built prior to 1960.

Consider the table: a) Build a decision tree for the training set given above. It's urgent help plz

Consider the table: a) Build a decision tree for the training set given above. It's urgent help plz

Answers

Explanation:

umm can you explain me what i have to answer

During gait the body is gaining speed:____.
a. during terminal stance
b. during mid stance
c. during initial swings
d. at mid stance event

Answers

During gait the body of a living organism is gaining speed: a. during terminal stance.

What is physical fitness?

Physical fitness can be defined as a measure of both the physical and mental soundness (wellness) or ability of an individual to engage in physical exercises, sports, work and other day-to-day activities.

For instance, one of the ways in which an individual can model good physical fitness to other individuals in their neighborhood is by:

Riding their bikes to school or work.Walking with a slow, stiff gait.

What is gait?

Gait can be defined as the way and manner in which an animal or individual walks or runs, thereby affecting and altering the shape of the body.

In this context, we can infer and logically deduce that during gait the body of a living organism is gaining speed, especially during terminal stance.

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DEVELOP CODE → TO TELL WHICH MECHANISM 17 IS BY SATISFYING (2), DEMONSTRATION OF MECHANISM (GRASHOF MAKE 360) →SHOW 6 CONFIGURATIONS IS MAKING 360 100/78 /00 PTS. CONDUCT CLASSIFICATION OF FOUR-BAR BY TESTING EQ. (2), SHOW ALL UNKAGES OF THIS CLASSIFICATIONS AND DEMONSTRATE THAT ONE OF THE LINKS CAN MAKE 360° USING SIX CONFIGURATIONS (FOR EX. 0,=0); 60, 120,...) (OR WING DYNAMICAL MOTION OF THE LINKAGE) not necessary THE INPUTS TO THE CODE SHOULD BE LO, L₁, L2, 43. ONE VET PER LINK. OPTIONAL DUE: LAST DAY OF LECTURE (MAX PTS. 200)→ WE ANY LANGUAGE (MATLAB)

Answers

Code example in MATLAB to classify and analyze four-bar linkages based on the input dimensions. The code will determine the mechanism type and show the possible configurations where one of the links can make a 360° rotation.

```matlab

function classifyFourBarLinkage(LO, L1, L2, L3)

   % Check mechanism type based on input dimensions

   if LO + L1 < L2 + L3

       mechanismType = "Grashof I";

   elseif LO + L1 > L2 + L3

       mechanismType = "Grashof III";

   else

       mechanismType = "Grashof II";

   end

   

   % Generate all possible configurations of the four-bar linkage

   theta = 0:60:300; % Angles in degrees

   numConfigurations = length(theta);

   

   % Check if one of the links can make a 360° rotation in each configuration

   configurations = [];

   for i = 1:numConfigurations

       A = [LO*cosd(theta(i)), LO*sind(theta(i))];

       B = [L1, 0];

       C = [L2, 0];

       D = [L3*cosd(theta(i)), L3*sind(theta(i))];

       

       % Check if one of the links completes a 360° rotation

       if isRotationPossible(A, B, C, D)

           configurations = [configurations; theta(i)];

       end

   end

   

   % Display results

   disp("Mechanism Type: " + mechanismType);

   disp("Possible Configurations with 360° Rotation:");

   disp(configurations);

end

function rotationPossible = isRotationPossible(A, B, C, D)

   % Check if one of the links completes a 360° rotation

   rotationPossible = false;

   

   % Calculate angles using dot product

   angleAB = acosd(dot(A, B) / (norm(A) * norm(B)));

   angleCD = acosd(dot(C, D) / (norm(C) * norm(D)));

   

   % Check if the sum of the angles is 360°

   if abs(angleAB + angleCD - 360) < 1e-5

       rotationPossible = true;

   end

end

```

To use this code, you can call the `classifyFourBarLinkage` function and provide the input dimensions `LO`, `L1`, `L2`, and `L3` as arguments. The function will classify the mechanism type based on the Grashof criteria and display the possible configurations where one of the links can make a 360° rotation.

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if citrus overlord is 200 (I'm offering for a lucid leaf) and shiny eternal contrast is 250, 450 so far and I'm also last thing offering for lucid (which is 100 secret value and I'm offering in shiny value and Lucid's shiny value is 500 but gets op's because it's a secret pet) is a shiny dark omen which is 100, I'm offering 550 for 500 but gets op's, w or l, I think w.

Answers

Answer: I'm pretty sure your taking a W.

your getting a W, lucid isn't that bad to trade, you can probably flip lucid for more shiny's and getting a better offer because omen has bad demand and you can tell someone to switch it for something better you can flip lucid and get better pets ok so accept and trade lucid unless you wanna keep it.

Explanation:

Answer:

gg's if you did it cause w

Explanation:

what are the design steps of surface dressing at urban street??​

Answers

Mark Brainliest please


For design, study long and hard, even without a civil engineering degree a few hundred hours of study on the internet can make you a pretty good roadway designer. The answer is not something you can write down in a paragraph and there is rarely if ever a situation where there is enough money to build the greatest road possible. Remain aware that if you wait till there’s enough money the road will probably never be built, work with the people with the money to get the road built. A road is better than no road.

A "calorie" is a unit of energy, defined as the amount of energy needed to raise the temperature of one gram of water by one degree Celsius. The nutritional labels on food products typically tell you how many calories of digestible energy are in one serving of food, where "digestible" means that the energy stored in the chemical bonds of the molecules comprising the food can be extracted by your body. (Water for example has energy, but that energy is not chemically accessible via digestion.) To simplify understanding for typical consumers, the "calories" reported on nutritional labels actually represent kilocalories: a 170 calorie can of beer actually contains 170,000 calories of digestible energy.

i) If a student foolishly decides to binge drink 21 beers on their 21t birthday, how many gallons of water could they have heated from room temperature (24 °C) to boiling (100 C) using an equivalent amount of digestible energy in the beer? Recall that one gallon of water is roughly 8 pounds.
ii) What is this energy equivalent to in BTU? A "BTU" or British Thermal Unit is also a unit of energy, defined as the amount of energy needed to raise the temperature of one pound of water by one degree Fahrenheit
iii) If you had purchased an equivalent amount of electrical energy in kW-hr from the utility company, how much would you have to pay? Is this cheaper than buying beer?

Answers

A "calorie" is a unit of energy that is defined as the usually inform you of the number of calories of digestible energy present in one serving of food. 21 beers times 17 calories per beer equals 357 calories.

What is "calorie"?Calories are units of energy that a food or drink provides. You can usually find calorie counts listed on food items, and wearables like the best fitness trackers allow you monitor how many calories you're burning by doing different activities. Certain foods, such as fatty, fried, or processed foods, tend to have more calories. Other foods, such as fresh fruit and vegetables, tend to have fewer calories. However, some healthy fruits and vegetables can be high in calories, while low-calorie foods, such as diet soda, don’t provide any nutritional value. We need calories to give us enough energy to move around, stay warm, grow, work, think, and play. Even our blood circulation and digestion need the energy gained from calories in order to function well.

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Choose one statement that best describes spalling failure in rigid pavements. Question 5 options: shallow hairline cracks due to over-finishing concrete depression of the shoulder loss of materials (often accompanied by cracks) at the joints due to a poor load transfer spalling can be restrained either by lowering asphalt content or by increasing friction among aggregates

Answers

Spalling results from excessive stresses at the joint or crack, caused by infiltration of incompressible materials or traffic loads.

Spalling can happen for a variety of reasons, including as freeze-thaw cycling, the expanding effects of the Alkali Silica Reaction, or exposure to fire. Nevertheless, corrosion of embedded steel reinforcement bars or steel sections is the most frequent cause of spalling. Spalling, also known as joint degeneration from excessive compressive stress, occurs. This might be connected to joint infiltration or pavement expansion brought on by reactive aggregates. Joint spalling can also be caused by poor concrete or construction methods. structural deficiencies Structural inadequacy: If the pavement system is structurally unsound due to issues like insufficient pavement thickness, bad subgrade soil, insufficient subgrade support, improper joint spacing, etc.,

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A 360 kg/min stream of steam enters a turbine at 40 bar pressure and 100 degrees of superheat. The steam exits the turbine as a 100% saturated vapor at a pressure of 5 bar. Write and simplify the appropriate energy balance and then determine the energy generated by the steam as it passes through the turbine in kW.

Answers

Answer:
skskkdkdkfkgkgkgkkgkgkgigooigigi lol
Explanation:
Oof

Tengo un problema con steam y es que sale como que no he comprado un juego pero en realidad si lo he comprado pero por una pagina alterna pero no me lo detecta que hago?

Answers

Answer:

Cómo forzar a Steam a reconocer los juegos instalados.

1) Vuelva a instalar los juegos sin descargar.

2) Agregue la carpeta Steam Library manualmente.

3) Reconocer juegos de una nueva unidad

4) Utilizar .acf Cache para forzar el reconocimiento de juegos de Steam .acf Cache para forzar el reconocimiento de juegos de Steam.

Explanation:

1) Vuelva a instalar los juegos sin descargar.

- Inicia Steam y ve a Juegos.

- Seleccione y haga clic en instalar para el juego que Steam no pudo reconocer.

- Steam comenzará a descubrir los archivos existentes para el juego.

2) Agregue la carpeta Steam Library manualmente.

- Lanzar Steam.

- Haga clic en Steam y seleccione Configuración.

- Haz clic en la pestaña Descargas.

- Haga clic en las carpetas de la biblioteca de Steam.

- En la ventana emergente, haz clic en Agregar carpeta de biblioteca y selecciona la ubicación donde se guardan todos los datos de tu juego Steam.

- Haga clic en Seleccionar y cerrar la configuración de Steam.

- Salga de la aplicación Steam y reinicie Steam.

- Steam ahora debería reconocer los juegos instalados nuevamente y enumerarlos en la carpeta de juegos.

3) Reconocer juegos de una nueva unidad

- Inicie la aplicación Steam desde el escritorio.

- Haz clic en Steam y selecciona Configuración.

- Haz clic en la pestaña Descargas.

- Haga clic en la carpeta de la biblioteca de Steam en la sección Bibliotecas de contenido.

- Haga clic en Agregar carpeta de biblioteca y navegue a la ubicación donde se mueven sus juegos (nuevo directorio) que es D: / games / your_subdirectory.

- Haga clic en Seleccionar y cerrar para guardar la carpeta de la biblioteca.

- Salga de Steam y reinícielo.

Steam escaneará la carpeta Biblioteca recientemente seleccionada y mostrará todos los juegos instalados.

4) Utilizar .acf Cache para forzar el reconocimiento de juegos de Steam .acf Cache para forzar el reconocimiento de juegos de Steam.

- Asegúrese de haber reinstalado Steam o tener la instalación existente.

- Mueva los datos del juego a C: >> Archivos de programa (x86) >> Steam >> carpeta Steamapps.

- Lanzar Steam.

- En este punto, Steam puede mostrar algunos juegos que están instalados correctamente.

- Para los juegos que se muestran como no instalados, seleccione y haga clic en el botón Instalar.

- Steam comenzará a descubrir todos los archivos existentes.

- Sin embargo, si Steam no reconoce los archivos existentes, comenzará a descargar los archivos y el progreso leerá 0%.

- Pausa la actualización de los juegos y sal de Steam. Vaya a C: >> Archivos de programa (x86) >> Steam >> Steamapps y encuentre todos los archivos .acf actuales.

¡¡¡Espero que esto ayude!!!

A gas turbine power plant operates on a simple thermodynamic cycle. The ambient conditions
are 100 kPa and 24 °C. The air at this condition enters the engine at 150 m/s whose diameter
is 0.5 m. The pressure ratio across the compressor is 13, and the temperature at the turbine
inlet is 1400 K. Assuming ideal operation for all components and specific heats for air and
products separately. In addition, neglect the mass of fuel burned. Do the followings:

a) Choose the suitable thermodynamic cycle “Brayton Cycle”

b) Draw pv and Ts diagram and label it

c) Calculate the power required by the compressor

d) Determine the pressure and the temperature at the turbine exit

e) Compute the power produced by the turbine

f) Available specific work

g) The thermal efficiency.

Answers

Answer:

Heat rate. 10,535 kJ/kWh. Turbine speed. 7,700 rpm. Compressor pressure ratio. 14.0:1. Exhaust gas flow. 80.4 kg/s. Exhaust gas temperature. 543 deg C.

Explanation:

20km on chili gram 7*2*8*4+457*958

entor" by
What type of signal word is used in this sentence?
need and
en who was
generalization
description
thought
feeling

Answers

Answer:

generalization

Explanation:

Please mark me brainliest I need to level up

How does the action of wind affect a rock’s appearance?

Answers

Answer:

Forces like wind and water break down rocks through the processes of weathering and erosion. ... Forces like wind and water move the rock pieces. They mix with matter like sand to become sediment. Weathering and erosion help shape Earth's surface.

Answer:

As an agent of erosion, the wind will quickly break the rock into different rock types.

Explanation:

The department of transportation regulations require which parameter to be recorded on the shipping paper for hazard class 2.2 nonflammable compressed gases?

Answers

The  shipping paper for hazard class 2.2 nonflammable compressed gases is for the Number of cylinders of each gas.

What are the hazard classes?

They are:

Class 1: Explosives.Class 2: Gases.Class 3: Flammable and Combustible Liquids.Class 4: Flammable Solids.

The classes of hazard are often made so that people will recognize them and follow the right steps so as to avoid those hazards.

Therefore,  The  shipping paper for hazard class 2.2 nonflammable compressed gases is for the Number of cylinders of each gas.

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what is time dependent​

Answers

Answer:

Adjective. time-dependent (not comparable) (mathematics, physics) Determined by the value of a variable representing time.

Explanation:

Plz mark brainliest thanks

Answer: Adjective. time-dependent (not comparable) (mathematics, physics) Determined by the value of a variable representing time

After a strong storm, a worker does not realize that a power transmission line has fallen on his car and is electrocuted while opening the car door. What is this an example of?.

Answers

Answer:

This is an example of the conduction of electricity through metal. Free moving electrons on the car will conduct a electric field when a voltage is applied to the car;  in this case the transmission line, and would flow through the metal to the door handle causing electrocution.

Positive correlations of handle steeper incline of bicycle is what? a. Light weight frame b. Suspension. C. More gears. D. Soft comfort seat. E. Lights. Give me answer from objectives

Answers

Positive correlations of handle steeper incline of bicycle is a. Light weight frame.

What is the Positive correlations?

A positive relationship implies that as one variable increments, the other variable moreover increments. Within the setting of cycling, handle steepness can influence the rider's pose and consolation level, which in turn can impact components such as speed, continuance , and generally performance.

Hence, Components which will influence the relationship between handle steepness and cycling execution might incorporate the rider's wellness level, the landscape being ridden on, the sort and quality of the bike components, and other person inclinations or variables.

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i) Describe the analysis concept used during the normalization process. ( If a data model is normalized to 3NF, can we always say the model is a good design for the business? Explain your answer. ( 2 points) What design process can help avoid having to resolve higher forms of normalization? ( 2 points)

Answers

i) The analysis concept used during the normalization process is to eliminate data redundancy and ensure data integrity.

ii) If a data model is normalized to 3NF, it does not guarantee that the model is a good design for the business.

Normalization is a process used in database design to structure data efficiently and eliminate redundancy. The concept behind normalization involves breaking down a data model into multiple related tables, each focusing on a specific entity or relationship.

By doing so, data redundancy is minimized, and data integrity is ensured. Redundancy leads to inconsistencies and anomalies when updating or deleting data, while normalization helps to maintain data consistency and accuracy by enforcing relationships and dependencies.

While normalizing a data model to the third normal form (3NF) is generally considered good practice, it does not automatically imply that the model is a perfect fit for the business. 3NF helps improve data organization, reduces redundancy, and minimizes data anomalies.

However, a good design for the business involves considering various other factors such as performance, usability, scalability, and specific business requirements. Therefore, while normalization is an essential step, additional considerations are necessary to determine if the design meets the specific needs and goals of the business.

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When the rod is circular, radial lines remain straight and sections perpendicular to the axis do not warp. In this case, the strains vary linearly along radial lines. Within the proportional limit, the stress also varies linearly along radial lines. If point A is located 12 mm from the center of the rod, what is the magnitude of the shear stress at that point

Answers

The question is incomplete. The complete question is :

The solid rod shown is fixed to a wall, and a torque T = 85N?m is applied to the end of the rod. The diameter of the rod is 46mm .

When the rod is circular, radial lines remain straight and sections perpendicular to the axis do not warp. In this case, the strains vary linearly along radial lines. Within the proportional limit, the stress also varies linearly along radial lines. If point A is located 12 mm from the center of the rod, what is the magnitude of the shear stress at that point?

Solution :

Given data :

Diameter of the rod : 46 mm

Torque, T = 85 Nm

The polar moment of inertia of the shaft is given by :

\($J=\frac{\pi}{32}d^4$\)

\($J=\frac{\pi}{32}\times (46)^4$\)

J = 207.6 \(mm^4\)

So the shear stress at point  A is :

\($\tau_A =\frac{Tc_A}{J}$\)

\($\tau_A =\frac{85 \times 10^3\times 12 }{207.6}$\)

\($\tau_A = 4913.29 \ MPa$\)

Therefore, the magnitude of the shear stress at point A is 4913.29 MPa.

Note for this problem that you will use cold air assumptions for cp, and estimate the change in enthalpy using cp*delta_T. Consider a Brayton cycle with a pressure ratio of 13, that receives 5.9 lbm/s of air at 85 ∘F. Assume that the maximum allowable temperature in the machinery is 2200°F. If the isentropic efficiency of the compressor and turbine is 93 % and 95 % respectively, then: (a) what is the net power output of this system? MMBTU/hr(check internet for this unit) (b) what is the thermal efficiency of this system? %

Answers

Given data:Pressure ratio = 13 Air mass flow rate = 5.9 lbm/s Initial temperature of air = 85°F Maximum allowable temperature = 2200°FCompressor isentropic efficiency = 93 %

Turbine isentropic efficiency = 95 %We can calculate the net power output and thermal efficiency of the system as follows:

a) Net power output of the system

The Brayton cycle consists of a compressor, a combustor, and a turbine. Therefore, the net power output of the system is given by the difference in the power output of the turbine and the power input to the compressor.We can assume that the cycle operates under steady-state conditions. Furthermore, we can assume that the combustor is perfectly insulated, and there is no heat transfer to or from the environment. Therefore, the net power output of the system can be expressed as:

Net power output = Power output of turbine - Power input to compressor

The power output of the turbine can be expressed as:

W_turbine = m_air * (h_4 - h_3)where, m_air = Air mass flow rateh_4 = Enthalpy at the turbine inleth_3 = Enthalpy at the turbine outletSimilarly, the power input to the compressor can be expressed as:

W_compressor = m_air * (h_2 - h_1)where, h_2 = Enthalpy at the compressor inleth_1 = Enthalpy at the compressor outletTo calculate the enthalpies, we need to calculate the temperatures and pressures at various points of the cycle. The following table summarizes the calculations:

PointStateT (°F)P (psia)sSpecific volume (ft^3/lbm)h (Btu/lbm)1Inlet to compressor8514.81.27492.24782.012After compression and before combustion 4753.61.274946.13463.883

After combustion and before expansion2050.01.274946.23234.924After expansion and before exhaust8514.81.274932.21914.045

b) Thermal efficiency of the systemThe thermal efficiency of the Brayton cycle is defined as the ratio of the net power output to the heat input. It can be expressed as:

Thermal efficiency = Net power output / Heat inputTo calculate the heat input, we can assume that the cycle operates under steady-state conditions, and there is no heat transfer to or from the environment. Therefore, the heat input to the cycle is equal to the heat released in the combustor. We can calculate it as follows:Q_in = m_air * (h_3 - h_2)Therefore, the thermal efficiency of the system can be expressed as

Therefore, the net power output of the system is 5.63 MMBtu/hr, and the thermal efficiency of the system is 41.23 %.

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The steel bracket is used to connect the ends of two cables. if the allowable normal stress for the steel is sallow = 30 ksi, determine the largest tensile force p that can be applied to the cables. assume the bracket is a rod having a diameter of 1.5 in.

Answers

The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb

The static equilibrium is given as:

F = P (Normal force)

Formula for moment at section

M = P(4 + 1.5/2)

= 4.75p

Solve for the cross sectional area

Area = \(\frac{\pi d^{2} }{4}\)

d = 1.5

\(\frac{\pi *1.5^{2} }{4}\)

= 1.767 inches²

Solve for inertia

\(\frac{\pi *0.75^4}{4}\)

= 0.2485inches⁴

Solve for the tensile force from here

\(\frac{F}{A} +\frac{Mc}{I}\)

30x10³ = \(\frac{P}{1.767} +\frac{4.75p*0.75}{0.2485} \\\\\)

30000 = 14.902 p

divide through by 14.902

2013.15 = P

The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb

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Lu Wong works in an automobile manufacturing company. Her employer invites innovative ideas from everybody to cut down waste in the production line. As a result, Wong offers a foolproof solution to manage the industrial waste, which gets accepted and implemented as well. Which agreement would make the employee’s invention Wong’s property?
A.
a trademark
B.
work for hire
C.
a copyright
D.
a trade secret

Answers

i believe it would be a B work for hire

A hydrogenation catalyst is prepared by soaking alumina particles (100-150 mesh size) in aqueous NiNO3 solution. After drying and reduction, the particles contain about 7 wt% NiO. This catalyst is then made into large cylindrical pellets for rate studies. The gross measurements for one pellet are: Mass, g 3.15 Diameter, mm 25 Thickness, mm 6 Volume, cm3 3.22 The alumina particles contain micropores, and the pelleting process introduces macropores surrounding the particles. If the macropore volume of the pellet is 0.645 cm3 and the micropore volume is 0.40 cm3 /g of particles, determine: i] The density of the pellet ii] The macropore volume in cm3 /g iii] The macropore void fraction in the pellet iv] The micropore void fraction in the pellet v] The solid fraction vi] The density of the particles

Answers

i] The density of the pellet is 0.977 g/cm^{3}. ii] The macropore volume in cm^{3}/g is 0.205 cm^{3}/g. iii] The macropore void fraction in the pellet is 25.1%.iv] The micropore void fraction in the pellet is 49.0%. v] The solid fraction of the pellet is 25.9%. vi] The density of the particles is 1.222 g/cm^{3}.

i] To determine the density of the pellet, we can use the formula:

Density = Mass / Volume

Given that the mass of the pellet is 3.15 g and the volume is 3.22cm^{3}, we can calculate the density as follows:

Density = 3.15 g / 3.22 cm^{3}≈ 0.977 \(g/cm^{3\)

ii] The macropore volume in cm3/g can be calculated by dividing the macropore volume of the pellet (0.645 cm3) by the mass of the pellet (3.15 g):

Macropore volume = 0.645 cm^{3} / 3.15 g ≈ 0.205 \(cm^{3} /g\)

iii] The macropore void fraction in the pellet can be calculated using the formula:

Macropore void fraction = Macropore volume / Total volume of the pellet

Total volume of the pellet = Volume - Macropore volume = 3.22 cm^{3}- 0.645 cm^{3} = 2.575 cm^{3}

Macropore void fraction = 0.645 cm^{3} / 2.575 \(cm^{3}\)≈ 0.251 or 25.1%

iv] The micropore void fraction in the pellet can be calculated using the given micropore volume of the particles (0.40 cm^{3} /g) and the mass of the pellet (3.15 g):

Micropore volume in the pellet = Micropore volume/g x Mass

Micropore volume in the pellet = 0.40 \(cm^{3} /g\) x 3.15 g = 1.26 cm3

Micropore void fraction = Micropore volume in the pellet / Total volume of the pellet

Micropore void fraction = 1.26 \(cm^{3}\) / 2.575 \(cm^{3}\) ≈ 0.490 or 49.0%

v] The solid fraction of the pellet can be calculated by subtracting the sum of macropore and micropore void fractions from 1:

Solid fraction = 1 - (Macropore void fraction + Micropore void fraction)

Solid fraction = 1 - (0.251 + 0.490) ≈ 0.259 or 25.9%

vi] The density of the particles can be determined using the mass of the pellet (3.15 g) and the total volume of the particles:

Total volume of the particles = Volume - Macropore volume = 3.22 \(cm^{3}\)- 0.645 \(cm^{3}\) = 2.575\(cm^{3}\)

Density of the particles = Mass / Total volume of the particles

Density of the particles = 3.15 g / 2.575\(cm^{3}\) ≈ 1.222 \(g/cm^{3}\)

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who is the strongest avenger i say hulk but who knows at this point

Answers

Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.

Serratia marcescens bacteria are used for the production of threonine. The maximum specific oxygen uptake rate of S. marcescens in batch culture is 4 mmol O2 g-1 h-1. It is planned to operate the fermenter to achieve a maximum cell density of 50 g l-1. At the fermentation temperature and pressure, the solubility of oxygen in the culture liquid is 8 × 10^-3 kg m^-3. The concentration of oxygen in the culture liquid is 0.5 × 10^-3 kg m^-3. At a particular stirrer speed, kLa is 0.17 s^-1.

Required:
Under these conditions, will the rate of cell metabolism be limited by mass transfer?

Answers

Answer:

The rate of cell metabolism is limited by mass transfer since the value of maximum cell concentration obtained (38 g/l) is lower than 50 g l-1, the value planed.

Explanation:

                                                     Data

kLa = 0.17/s

Solubility of oxygen =  8 × 10^-3 kg / m^3

The maximum specific oxygen uptake rate = 4 mmol O2 / g h.

Concentration of oxygen =  0.5 × 10^-3 kg/ m^3

**The maximum cell density = 50 g/l

___________________

The calculated maximum cell concentration:

xmax=  kLa · CAL*/ qo

CAL* is the solubility of oxygen in the broth and qo is the specific oxygen uptake rate

Replacing the data given

xmax= ( 0.17/s ) ·   (8 × 10^-3 kg / m^3)  /  4 mmol O2 / g h

4 mmol O2 / g h  to kg O2/ g s

\(4 \frac{mmol}{gh} \frac{1 gmol}{1000mmol}\frac{1h}{3600s}\frac{32 g}{gmol} \frac{1Kg}{1000g}\)

= 3.56 x 10^-3 kg O2/ g s

So then,

xmax= ( 0.17/s ) ·   (8 × 10^-3 kg / m^3)  / 3.56 x 10^-3 o kg O2/ g s

xmax= 3. 8 x 10^4 g/ m^3   = 38 g/l

_____________________

The monthly output of a certain product is Q(x)=2500x 5/2
where x is the capital investment in millions of dollars. Find dQ/dx, which can be used to estimate the effect on the output if an additional capital investment of $1 million is made. dQ/dx=

Answers

The monthly output of a certain product can be given by the function

\(`Q(x) = 2500x^(5/2)`\)

where x is the capital investment in millions of dollars.

differentiate the function Q(x) with respect to x.

\(dQ/dx = d/dx(2500x^(5/2))\)

Using the power rule of differentiation, we have:

\(dQ/dx = (5/2) * 2500 * x^(5/2 - 1)dQ/dx

= 6250x^(3/2) `dQ/dx

= 6250x^(3/2)`\)

which gives us the effect on the output if an additional capital investment of $1 million is made.

Note: To estimate the effect on the output if an additional capital investment of $1 million is made, we substitute x with x+1 in the expression for `dQ/dx`. This gives us the new output and the increase in output due to the additional investment.

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Type the correct answer in the box. Spell all words correctly.
Thomas is checking an electrical wire in a washroom with a wet floor. What in the electrical wire will help prevent electrical shock

Type the correct answer in the box. Spell all words correctly.Thomas is checking an electrical wire in

Answers

Thomas is checking an electrical wire in a washroom with a wet floor. Ground-fault circuit interrupters in the electrical wire will help prevent electrical shock.

What is Ground-fault circuit interrupters?

The ground-fault circuit interrupter, or GFCI, is a quick-response circuit breaker that may cut off electricity in as little as 1/40 of a second in the event of a ground fault.

It compares the current flowing into and out of the machinery along the conductors of the circuit.

Therefore, electrical shock can be avoided with the aid of ground-fault circuit interrupters in the electrical line.

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Select all the correct statements: The coefficient of consolidation of clay varies with a change in vertical effective stress. Secondary consolidation is negligible in organic soils. The coefficient of lateral earth pressure at-rest Ko for an over-consolidated sand cannot be greater than 1. Irrecoverable compression in clays is due to the relative motion of the particles under the applied load. | Lowering of ground water table is a source of overconsolidation in clays. A clay is overconsolidated and has an overconsolidation ratio (OCR) equal to 1 if it has never experienced a higher vertical effective stress than the one it currently experiences.

Answers

From the given statements regarding soil mechanics, the correct statements are a, d, e, and f.

a) The coefficient of consolidation of clay varies with a change in vertical effective stress.

d) Irrecoverable compression in clays is due to the relative motion of the particles under the applied load.

e) Lowering of the groundwater table is a source of over-consolidation in clays.

f) A clay is overconsolidated and has an over-consolidation ratio (OCR) equal to 1 if it has never experienced a higher vertical effective stress than the one it currently experiences.

What is the Coefficient of consolidation? The coefficient of consolidation is defined as the rate of consolidation of soil under a steady-state one-dimensional flow of water through it. It is affected by effective stress. The rate of consolidation will decrease with time. The coefficient of consolidation varies with a change in vertical effective stress.

What is Secondary consolidation? After the primary consolidation of soils, the excess pore pressure is dissipated, resulting in a decrease in the volume of the soil mass. This decrease is known as secondary consolidation. Secondary consolidation is negligible in organic soils.

What is Irrecoverable compression? Irrecoverable compression in clays is due to the relative motion of the particles under the applied load. Irrecoverable compression results in a reduction in the soil volume and is irreversible.

What is Overconsolidation? A soil is said to be overconsolidated if it has been subjected to higher stress in the past than it is currently experiencing. Lowering of the ground water table is also a source of over-consolidation in clays. The ratio of the pre-consolidation stress (sigma prime) to the present effective stress (sigma prime) is known as the overconsolidation ratio (OCR). The coefficient of lateral earth pressure at-rest Ko for over-consolidated sand cannot be greater than 1 is a false statement as Ko can be greater than 1 for overconsolidated sand.

So, the correct statements are a, d, e, and f.

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Joey has a car that uses the hand crank to open the windows. Joey is wondering where the energy comes from to open the windows.The sunHuman-powered energy from JoeyThe hand crankThe moving car

Answers

Explanation:

Joey has a car that uses the hand crank to open the windows. Joey is wondering where the energy comes from to open the windows.The sunHuman-powered energy from JoeyThe hand crankThe moving car

High-temperature refrigeration applications will normally provide box temperatures of?

Answers

High-temperature refrigeration applications will normally provide box temperatures of 47 to 60°F.

In the question, asked to specify the range of temperature for High-temperature refrigeration applications for the box.

What is refrigerant?

Refrigerants are the coolants used in refrigeration devices such as ac,  refrigerators, etc. Some examples of refrigerant CFCs.

Here, the required range of temperature for High-temperature refrigeration applications varies from  47 to 60°F.

Thus, high-temperature refrigeration applications will normally provide box temperatures of 47 to 60°F.

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