You need a 80% alcohol solution. On hand, you have a 90 mL of a 70% alcohol mixture. You also have 95% alcohol mixture. How much of the 95% mixture will you need to add to obtain the desired solution

Answer:

Explanation:

Melting and boiling point variations are not clear (do not have uniform pattern) in periodic table. But we can see, some elements have higher melting and boiling points and some have less. Here we study melting and boiling points of s, p, d blocks elements. IVAth group elements (C,Si) show high melting and boiling points because they have covalent gigantic lattice structures.

When magnesium (Mg) reacts with a halogen (R-Br), it undergoes oxidation. Oxidation is the process of losing electrons. In Mg's case, it loses two electrons to become a positively charged ion (Mg2+). When it loses these electrons, its oxidation state increases.

The oxidation state of an element reflects the number of electrons it has gained or lost to achieve a stable valence shell (or an octet in the case of Mg and other elements in the s-block of the periodic table).Mg(s) + R-Br → Mg2+ + 2R- + Br-The oxidation state of magnesium goes from 0 to +2 in this reaction. In other words, it undergoes a net loss of two electrons. Meanwhile, the oxidation state of bromine goes from 0 to -1 since it gains an electron to form Br-. Overall, the reaction is redox (reduction-oxidation) since Mg undergoes oxidation (loses electrons) while Br undergoes reduction (gains electrons). The reaction also generates two molecules of the R- anion, which remains unchanged in oxidation state.

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Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

Option C) "are digested by proteases into both opiate and non-opiate peptides" is the correct response.

Like all other propeptides, the opioid propeptides is a protein precursor that must be cut into a smaller form to become active. Proteases convert the opioid propeptides into opiate and non-opiate peptides, the latter of which may or may not be active. Enkephalins, endorphins, and dynorphins, which are opiate peptides, work by blocking secondary systems, such as those that affect how pain is perceived.

The opioid receptors are essential signalling molecules in the brain that the leucine-enkephalin binds to. They include four peptide bonds in total. These are naturally occurring ligands that function as neurotransmitters and have morphine-like properties.

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Answer: 2

Explanation: Every non-zero digit is a significant digit.

Answer:

2 significant figures.

Explanation:

38 contains 2 significant figures.

Gas molecules will move from an area of higher partial pressure to an area of lower partial pressure.

The partial pressure of a gas (e.g. carbon dioxide in the lungs) allows the movement of molecules during physiological processes.

For example, during gas exchange, oxygen and carbon dioxide move in the respiratory system and circulatory system due to differences in the partial pressure of these gases.

In conclusion, gas molecules will move from an area of higher partial pressure to an area of lower partial pressure.

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Answer:

a

Explanation:

The oxidation number of chromium is +6. In the reaction, it is reduced, meaning its oxidation number decreases. The final oxidation number of chromium is +3.

In the reaction represented by the Cr₂O₇²⁻ ion, the element chromium (Cr) is reduced. Its oxidation number changes from +6 to +3.

In the Cr₂O₇²⁻  ion, each oxygen (O) atom has an oxidation number of -2. The overall charge of the ion is 2-, which means the total oxidation numbers of all the atoms should add up to -2. Since there are seven oxygen atoms, their total oxidation number is (-2) × 7 = -14.

To determine the oxidation number of chromium (Cr), we can set up the following equation;

2(Cr) + 7(-2) = -2

Simplifying the equation, we have;

2Cr - 14 = -2

By solving for Cr, we get;

2Cr = 12

Cr = 6

Initially, the oxidation number of chromium is +6. In the reaction, it is reduced, meaning its oxidation number decreases. The final oxidation number of chromium is +3.

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Red 40 dye, which is typically used to absorbance colour orange drinks, has a lambda maximum that can be seen at 520 nm.

A substance will appear to be the complimentary colour if it absorbs light wavelengths from a certain region of the spectrum. As a result, the material will seem yellow, for example, if violet light with a wavelength of 400 nm is absorbed.

Visible light absorption will be used to determine concentration and distinguish between various dyes. If a solution's concentration is unknown, it can be calculated by counting how much light the solution absorbs.

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The molarity of a solution of 12.9 g fructose and 31.0 g water is 1.26 M.

Molarity is the number of moles of solute dissolved in one liter of a solution. The formula to calculate molarity is:

Molarity (M) = moles of solute / liters of solution

To find the molarity of the given solution, we first need to determine the number of moles of fructose present. We can do this using the molar mass of fructose.

Molar mass of fructose = (6 x 12.01 g/mol) + (12 x 1.01 g/mol) + (6 x 16.00 g/mol)= 180.18 g/mol

The number of moles of fructose present in 12.9 g can be calculated as:

Number of moles of fructose = mass of fructose / molar mass of fructose= 12.9 g / 180.18 g/mol= 0.0716 mol

Number of moles of water = mass of water / molar mass of water= 31.0 g / 18.02 g/mol= 1.722 mol

Now, we can calculate the total volume of the solution.

Total mass of the solution = mass of fructose + mass of water= 12.9 g + 31.0 g= 43.9 g

We can convert this to liters using the density of water.

Density of water = 1 g/mL= 1000 g/L43.9 g = 0.0439 L (volume of solution)

Now that we know the number of moles of fructose and water and the volume of the solution, we can calculate the molarity:

Molarity (M) = moles of solute / liters of solution= 0.0716 mol / 0.0439 L= 1.26 M

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decay rate of approximately 1.69x10^17 Bq (becquerels),

The decay rate of a radioactive sample is determined by the number  of radioactive atoms present and the decay constant, which represents the probability of decay per unit of time.

To calculate the decay rate, we multiply the number of atoms in the sample by the decay constant. In this case, the sample has 8.31x10^17 atoms and a decay constant of 0.203/s. Multiplying these values gives a decay rate of approximately 1.69x10^17 Bq (becquerels), which represents the number of decays per second in the sample.

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The term porosity describes how much of a rock consists of open pore spaces, while permeability describes how well-connected pore spaces allow gases and liquids to flow through the rock.

Porosity is the percentage of pore space in a rock to its overall volume, and it is defined as the total amount of void space in a rock divided by its overall volume. Porosity is represented as a percentage, and it indicates the rock's ability to hold fluids, including oil and gas. This refers to the fraction of the rock that is voids.

It's a physical property of sedimentary rocks that relies on the pore space between the particles.

Permeability refers to the ability of a rock to transmit fluids, typically water or hydrocarbons. It's determined by the number and size of open pore spaces and how well-connected they are in the rock. Permeability is affected by the orientation of the pore spaces and the shape of the rock particles.

The permeability of a rock is also influenced by how well the pore spaces are interconnected, with well-connected pores increasing permeability. It is a measure of a rock's ability to transmit fluids such as oil, water, or gas.

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Answer:

Organisms can be classified into one of three domains based on differences in the sequences of nucleotides in the cell's ribosomal RNAs (rRNA), the cell's membrane lipid structure, and its sensitivity to antibiotics. 3. The three domains are the Archaea, the Bacteria, and the Eukarya.

Explanation:

In a solution of KOH (potassium hydroxide), KOH dissociates into K+ (potassium ion) and OH- (hydroxide ion). Since KOH is a strong base, it completely dissociates in water.

The concentration of hydroxide ions (OH-) in a 3.4 x 10^-3 M solution of KOH is equal to the concentration of KOH because they have a 1:1 stoichiometric ratio. Therefore, the hydroxide ion concentration is 3.4 x 10^-3 M.

Now, since we know that water undergoes autoionization to produce equal concentrations of hydrogen ions (H+) and hydroxide ions (OH-), we can conclude that the hydrogen ion concentration is also 3.4 x 10^-3 M.

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Answer:

0.715 g

Explanation:

mass = 0.0013x550= 0.715 g

Answer:

marine biologist

Explanation:

marine biologist

Answer:

marine biologist a scientist who studies creatures that live in ocean water, from bacteria and shellfish to kelp and whales. mean One of several measures of the “average size” of a data set. .organism Any living thing, from elephants and plants to bacteria and other types of single-celled life.

Answer:he correct Newman projection would be:

O

/ \

C   C

\ /

 H

Explanation:

Answer:

O

/ \

C   C

\ /

H

Explanation:

Answer:

Willow is correct because as things age and mature more, usually the more better they are.

Explanation:

To elaborate, you can perceive the development of the modern day atomic model as one aging and maturing. There's usually a correlation between age/maturity and knowledge, the same is true for the atomic model and other scientific theories.

Answer:

Molar mass of (Fe(NO3)3)(H2O)9 is 403.9972 g/mole

Explanation:

the formula to find the mass of moles

Worked Example: molar mass = mass ÷ moles (M=m/n) Calculate the molar mass of a pure substance if 1.75 moles of the substance has a mass of 29.79 g.

i think it help you

A hydrate of cobalt(II) chloride had a mass of 238.0 g before heating. After heating, the anhydrous CoC1, weighed 130.7 g.

from above statement, we found that,

before heating cobalt(II) chloride  = 238.0g

Mass of hydrated  cobalt(II) chloride After heating = 130.7 g

Mass of water = (1238.0 - 130.7) g = 107.39g

moles H2O  = 107.39× 1 mole H2O÷18g H2O

= 5.96 mol H2O.

moles of anhydrous CoCl, remain = given mass of CoCl÷ molar mass of CoCl

=130÷94.5

= 1.375 mole

moles of CoCl₂ = given mass of  CoCl₂÷ molar mass of CoCl₂

= 130÷ 130

= 1 mole.

hydration number = moles of water÷ mole of compound

= 5.96 mol÷ 1

 = 5.96 hydration number

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Due to its very symmetric structure, BF3 (Boron Trifluoride) is non-polar. Because of its triangular planar structure, the three BF bonds' individual dipole moments cancel out, bringing the compound's overall dipole moment to zero.

Al-Cl, Si-Cl, Ni-P, Cu-Br

The difference in the electronegativity of the components determines the polarity of a bond. The propensity of an atom to gain an electron and form an anion or to have an electron nearby when in a covalent bond (sharing electrons) is known as this attribute.

The atom will find it more challenging to attract an electron the bigger the atomic radius since the attractive force will be less powerful. In the periodic table, the electronegativity rises from left to right and from bottom to top.

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The amount of work done is 450.0 atm L given that a system is compressed from 50.0 L to 5.0 L at a constant pressure of 10.0 atm.

To find the amount of work done when a system is compressed from 50.0 L to 5.0 L at a constant pressure of 10.0 atm, we can use the equation:

Work = Pressure x Change in Volume

The change in volume is calculated by subtracting the initial volume from the final volume:

Change in Volume = Final Volume - Initial Volume
Change in Volume = 5.0 L - 50.0 L
Change in Volume = -45.0 L

Since the change in volume is negative (indicating compression), we can use the absolute value of the change in volume in the calculation.

Plugging in the values into the equation, we have:

Work = 10.0 atm x |-45.0 L|
Work = 10.0 atm x 45.0 L
Work = 450.0 atm L

Therefore, the amount of work done is 450.0 atm L

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The volume of NH3 N H 3 formed at STP is 3.1L .

First convert g of H2O to mol NH3 using stoichiometry.  

From the balanced reaction, 6 moles of H2O reacts to form 2 moles of NH3.  The mole ratio of H2O to NH3 is 6:2.

7.5 g H2O x (1 mol H2O / 18.02 g H2O) x (2 mol NH3 / 6 mol H2O) = 0.14 mol NH3

Next, at STP, 1 mole of a gas occupies a volume of 22.4 L.

Vol. of NH3 produced = 0.14 mol x (22.4 L / 1 mol) = 3.1 L.

With the formula NH3, ammonia is a nitrogen and hydrogen inorganic chemical. Ammonia, the simplest pnictogen hydride and a stable binary hydride, is a colorless gas with a strong, pungent odor. It contributes considerably to the nutritional demands of terrestrial creatures by serving as a precursor to 45% of the world's food and fertilizers. Biologically, it is a common nitrogenous waste, especially among aquatic animals. Fertilizers  in a variety of shapes and compositions, including urea and diammonium phosphate, use around 70% of the ammonia produced. Additionally, pure ammonia is sprayed straight onto the ground.

Ammonia is also a key ingredient in many commercial cleaning solutions and is a building component for the manufacture of numerous medicinal medicines. It is mostly gathered through the displacement of both air and water downward.

Although ammonia is widely used and found in nature on Earth and on the outer planets of the Solar System, it is dangerous and caustic when it is concentrated. Facilities that produce, store, or utilise it in considerable quantities are subject to severe reporting requirements because it is categorized as a very dangerous material in many nations.

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Answer:

Examine the units: If the density is 1 g/mL, how many mL do you need to make 250 g?

X mL * 1 g/mL = 250 g

Solve for X

x mL = 250 g / 1 g/mL = 250 mL

Hope this helps :)

The volume of water = 250 L

\(density = \frac{mass}{volume}\)

Given, density = 1.0 g/L = 0.001 kg/L

           mass = 250 g = 0.25 kg

Putting the values in the equation

\(0.001 = \frac{0.25}{volume}\)

\(volume = \frac{0.25}{0.001}\)

\(volume = 250 L\)

Hence, the volume of the water is 250 L.

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Answer:

the solution becomes less concentrated... meaning there is a decrease in acidity ...hence the pH slightly increases as lesser ph

means more acidity

Answer:

Brainliest pls

Explanation:

Although the information for the trial was not given, we can offer a summed-up reply in that while playing out an analysis to accomplish outright zero temperatures, the worth won't ever match the specific worth.

What is absolute zero?

Absolute zero is the lower furthest reaches of temperature. Considered the coldest conceivable temperature that can exist. Nonetheless, any endeavor to arrive at this temperature in a controlled climate has fizzled, researchers don't think reproducing this temperature is conceivable.

In this way, we can affirm that the worth of indisputably the zero tests didn't match the acknowledged worth. Assuming the speculation was that it would be troublesome or difficult to accomplish, then the information would uphold the theory, if not, it would neglect to do as such.

In outline, outright zero is a temperature that can't be reproduced in a lab, so the worth in this analysis doesn't match the acknowledged worth and there could be no further investigation to be done on this.

the percent yield for the reaction = 83.5086

The substance(s) that are initially a part of a chemical reaction are referred to as reactants or reagents. A chemical change often characterizes chemical reaction, and they produce one or more products that typically have characteristics distinct from the reactants. The so-called elementary reactions are reactions that frequently consist of a series of discrete steps, and the information regarding the specific sequence of events is contained within the reaction mechanism. Chemical equations are used to describe chemical processes. These equations represent the initial substances, final products, and occasionally intermediate products as well as the reaction circumstances symbolically.

When a temperature and chemical concentration are known, chemical reaction proceed at a predictable rate. As temperature rises, reaction rates often increase as more thermal energy is available to reach the activation energy.

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Freezing point of a solution containing 1.25 g1.25 g of benzene (C6H6)(C6H6) in 100 g100 g of chloroform (CHCl3)(CHCl3) is -64.249°C.

To register a frozen edge for a plan, you must use the recipe for frozen edges for discouragement.

ΔTf = Kf * molality

where ΔTf is the freezing edge for despair and Kf is the freezing edge for despair. As can be expected for soluble substances, molality is the molal mixture of solutes.

First we have to deal with the molality of the plan.

molality = moles of solute/mass of solute (kg)

The mass of chloroform is 100 g, which is equivalent to 0.1 kg.

molarity = 0.016 mol/0.1kg = 0.16 mol/kg

The reliable freezing point of chloroform for rejection of

is 4.68 K*kg/mol.

ΔTf = 4.68K*kg/mol * 0.16mol/kg = 0.749 K

The freezing limit of pure chloroform is 63.5°C. So the game plan frozen edge is frozen edge = - 63.5°C - 0.749°C = - 64.249°C

So the freezing point of the plan is -64.249°C.

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