You shake a bottle of soda and take off the cap. If the soda shoots out of the
bottle with a velocity of 17 m/s, how high will it go?
A. 16.9 m
B. 14.7 m
C. 10.6 m
D. 12.2 m

Answer:

a) 627840000 W

b) 0.9233

Explanation:

The rate at which energy flows through the dam for the generation of electricity is proportional to the volulme flow rate times the potential energy per unit volume.

Mathematically,

P = Q(ρgh)

Where, ρ is water density, g is accelaration due to gravity, h is height through which water falls over the turbine and Q is the discharge.

a) The power can be calculated as

P = 640(1000×9.81×221)

P = 627840000 W

b) The ratio = Calculated power / avarage power

= 62784×10^4/680×10^6

= 0.9233

Answer:

stop being an annoying child and appreciate everything your mother does for you because she cares for you

Explanation:

its the right thing to do

Be thankful for everything your mom does bc one day she wont be here any more! Love her while you can

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

The distance that is covered by the car in unit of kilometers is 37.5 km.

The term speed is defined as the ratio of the distance to the time of the movement of an object. We know that speed is a scalar quantity hence we do not look at the direction of the object when we are dealing with the speed.

We have the following;

Speed of the car = 100 km/h

Time taken = 22.5 minutes

To convert the time to hours;

22.5 minutes * 1 hour /60 minutes

= 0.375 hours

Distance = speed * time

= 100 km/h * 0.375 hours

= 37.5 km

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Missing parts;

The Nardo ring is a circular test track for cars. It has a circumference of 12.5km. Cars travel around the track at a constant speed of 100km/h. A car starts at the easternmost point of the ring and drives for 15 minutes at this speed.

What distance, in km, does the car travel?

Answer:

i will help what do you need help with

Answer:

what question is that?

Explanation:

make it english

The spring constant of the spring is 178.4 N/m.

In this problem, we are given a mass of 0.25 kg that is attached to a spring and set into vibration with a period of 0.22 s.

We can use the equation for the period of a mass-spring system, which relates the period of oscillation to the mass and spring constant, to calculate the spring constant.

We can use the equation for the period of a mass-spring system:

T = 2π√(m/k)

where T is the period, m is the mass, and k is the spring constant.

Rearranging this equation to solve for k, we get:

k = \((4\pi^2m) / T^2\)

Substituting the given values, we get:

k = \((4\pi^2 \times 0.25 \:kg) / (0.22 s)^2\)

k = 178.4 N/m

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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The scenario presented is an example of negative punishment.

Negative punishment involves the removal of a desirable stimulus or the addition of an aversive stimulus in response to a behavior, with the goal of decreasing the likelihood of that behavior occurring again in the future.

In this case, the desirable stimulus that was removed is the son's ability to engage in leisure activities like playing hockey, and the aversive stimulus that was added is the scolding from the parent. By experiencing this consequence, the son may be less likely to forget his chores in the future in order to avoid the negative outcome.

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Answer:

Which extended definition would be most helpful to add to this body paragraph?

Laughter Yoga, a new form of yoga, is becoming increasingly popular.

Laughter Yoga, which is becoming more and more popular, was created in the 1990s.

Laughter Yoga is modeled after traditional yoga but includes laughter exercises.

Laughter Yoga is a form of yoga that was created by Dr. Madan Kataria in the 1990s.

Explanation:

c

Since he runs a company in the US He exchanges goods and services with parties, Jack is engaged in international trade.

International trade is the exchange of goods and services between countries. It is a major driver of economic growth and prosperity. Jack's company can benefit from international trade in a number of ways. First, it can access new markets and customers. Second, it can source lower-cost inputs from other countries. Third, it can diversify its risk by selling to customers in multiple countries.

However, Jack's company also faces some challenges when engaging in international trade. First, it must deal with different languages, cultures, and legal systems. Second, it must comply with import and export regulations. Third, it must manage the risk of currency fluctuations.

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Across

2. opaque

4. hard

5. metal(s)

6. translucent

8. luster

Down

1. wood

3. transparent

7. soluble?

Happy to help, have a great day! :)

Answer:

1 friction

2 friction force

3 time

4 physical quantity

Answer:

1; Friction

4;force

3;Mass

Answer:

4:1

Explanation:

Given that the initial speed of the first car, u = 2v while the initial speed of the second car, u = v. To find the distance travelled, we are going to apply one of the equations of motion. The equation chosen is

v² = u² - 2as, where

s = the distance needed

a = acceleration due to gravity

u = initial velocity which is v & 2v

v = final velocity which is 0

For the first car with initial velocity, 2v, on substituting into the equation, we have

v² = u² - 2as(1)

0 = 4v - 2as(1)

4v = 2as(1)

2v = as(1), making s(1) subject of formula we have

s(1) = 2v/a

Taking the second car, we have u = v

v² = u² - 2as(2)

0 = v - 2as(2)

v = 2as(2), making s(2) subject of formula, we have

s(2) = v/2a

Not, ratio of s1 : s2 =

2v/a : v/2a

s1/s2 = 2v/a ÷ v/2a

s1/s2 = 2v/a * 2a/v

s1/s2 = 4av/av

s1/s2 = 4/1

Therefore, the ratio of the first car to the second car is 4:1

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Answer:

WORK DONE ON A BODY IS THE PRODUCT OF FORCE IN THE DIRECTION OF DISPLACEMENT AND DISPLACEMENT.

WORK ONLY HAS MAGNITUDE AND NO DIRECTION.

FORCE applied IN the direction of displacement × displacement = POSITIVE WORK DONE

FORCE applied OPPOSITE to the direction of displacement × displacement = NEGATIVE WORK DONE

FORCE applied PERPENDICULAR to the direction of displacement × displacement = ZERO WORK DONE

hope it helps

have a nice day

The formula for work done is:

\(w=Fd\)

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

Answer: MAGNITUDE AND DIRECTION OF A VECTOR

Explanation: Given a position vector →v=⟨a,b⟩,the magnitude is found by |v|=√a2+b2. The direction is equal to the angle formed with the x-axis, or with the y-axis, depending on the application.

Answer:

Hope this helps =)

Explanation:

The current in a short circuit may be very high because the resistance in the short circuit is probably less than the resistance in the original circuit.

The rotational equilibrium condition allows to find the result for the value of the force on the lid is:

The torque of a force is defined by the cross product of the force times the distance from the point of application.

             τ = F x r

where bold indicates vectors, tau is torque, F is force, and r is displacement.

Newton's second law for rotational motion establishes a relationship between the net torque, the moment of inertia, and the angular acceleration of the body, in the special case that the angular acceleration is zero, is called the rotational equilibrium condition.

             Σ τ = 0

In the attachment we can see a diagram of the forces in this system, we assume that the lid does not move, so we can use the rotational equilibrium condition, where we will assume that the counterclockwise rotations are positive.

They indicate the force F = 83.4 N su and the pivot point is l = 2 cm from the length of the screwdriver L = 23 cm.

The distance from the force to the pivot point is:

           r₁ = L - l

           r₁ = 23-2 = 21cm

Let us write the condition of rotational equilibrium.

          F₁ r₁ + F₂ l = 0

           \(F_2 = - \frac{r1}{l} \ F_1\)

Let's calculate.

            F₂ = -\(- \frac{21}{2}\ 83.4\)

            F₂ = -875.7 N

The negative sign indicates that the force is in the opposite direction to the applied force.

In conclusion using the rotational equilibrium condition we can find the result for the value of the force on the lid is:

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The force applied to the lid with the screwdriver is 875.7 N.

The given parameters:

The principle of moment states that the sum of clockwise moment is equal to sum of anticlockwise moment.

The sketch of the given question

----------2cm----------------------------------- 23cm

↓           Δ                                           ↓

F                                                          83.4 N

Take moment about the pivot as follows;

anticlockwise moment = clockwise moment

F(2cm) = 83.4(23cm - 2 cm)

\(F(2cm) = 83.4N(21cm)\\\\F = \frac{83.4N(21cm)}{2cm} \\\\F = 875.7 \ N\)

Thus, the force applied to the lid with the screwdriver is 875.7 N.

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The work done on 85 N boxes of books while carried horizontally 4m across a room is equal to zero. Therefore, option (C) is correct.

Work can be demonstrated as the energy used when a force is exerted to move an object through a definite displacement. The work done defines both the exerted force on the object and the distance moved by the object.

The applied force moves an object in a straight line in the direction of the exerted force over a displacement 'd'.

W= F × d

Where 'F' is the exerted force and 'd' is the displacement and W is work done.

Given, the weight of the box = 80 N

The displacement , d = 4 m

In order for to work to be done the box should move in the direction of exerted force as the books are moving forward direction and the applied force in an upward direction to carry the box.

Therefore, the distance moved in the direction of force is zero so the work done is also equal to zero.

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Answer:

1) Atmosphere

Explanation: because if you think about it the only real explaination is atmosphere.

Answer:

here is explanation

Explanation:

Proxima Centauri The closest star to our own Is still 40,208,000,000,000 km away.

(OR ABOUT 268,770 AU)

After all analysis, the following conclusion was reached:

a. The velocity of the basket ball is not constant.

a. Basketball acceleration is constant.

c. the basket ball's starting velocity is 0.6 m/sec

Step 1

Looking at the position time graph, we can claim that it is parabolic and that the equation that satisfies it is a quadratic equation at time t = 0 and time t = 0.6. Because the parabola opens on the negative y - axis, the coefficient of t2 must be negative (position axis).

It is to be noted that from t=0 to t= 0.6 is a positive progression. After t=0.6, the position of the ball's trajectory becomes negative.

From the foregoing, the graphs equation can be enumerated as follows:

X(t) = -t(t-0.6)

X(t) = -t² + 0.6t..............equation 1

We can test the two points by inserting arbitrary values into equation 1.

Step two : The velocity time graph:

V = Dx(t)/Dt

= (d/dt) (-t² + 0.6t)

= -2t + 0.6 m/sec.............equation 2

Note that the graph of velocity is usually a straight line with a negative slope. In this case, the y-axis intercept is 0.6. See the attached image. At t = 0.3 seconds, Velocity equals Zero.

A) The velocity of the basket ball is not constant as it depends on the amount of time elapsed.

V = -2t + 0.6 m/sec

B) acceleration of the basketball is given by,

a = Dv/Dt = -2 m/sec²

Step 3

As observed, acceleration id not dependent on time. Acceleration is constant.

C) to compute the initial velocity we have to insert

t = 0 int o the equation of velocity.

Vat t=0   =0.6m/sec

From the foregoing therefore, we can deduce that:

a. The velocity of the basket ball is not constant.

a. Basketball acceleration is constant.

c. the basket ball's starting velocity is 0.6 m/sec.

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This question involves the concept of  Newton's law of gravitation.

The force of gravity between the two spaceships is "1355.78 N".

According to Newton's Law of Gravitation:

\(F=\frac{Gm_1m_2}{r^2}\)

where,

Therefore,

\(F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(500\ kg)(498\ kg)}{(35\ m)^2}\\\\\)

F = 1355.78 N = 1.356 KN

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Two space ships traveling next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

It is given that the First spaceship's weight (\(m_{1}\)) is 500 kg,

The second spaceship's weight (\(\rm m_{2}\)) is 498 kg.

The distance between spaceships (r) is 35 meters.

It is required to find the Force of gravity between these spaceships.

It is defined as the force which attracts any two masses in the universe.

By Newton's law of Gravitation:

\(\rm F= \frac{Gm_1m_2}{r^2}\)  , Where

\(\rm F = The\ force \ of \ gravity \ between \ the \ spaceships\\\rm G= Universal\ Gravitational \ Constant = 6.67 \times 10^{-11} N.m^2/kg^2\)

Putting values in the above formula:

\(\rm F = \frac{(6.67\times 10^{-11} N.m^2/kg^2)(500kg)(498kg)}{(35m)^2}\)

F = 1355.78 N = 1.356  KN

Thus, Two spaceships travel next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

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By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life

From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.

The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.

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Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.

Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10

Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5

Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2

Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1

Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.

Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.

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Answer:

ix chemical elements that comprise Group 2 of the periodic table

Explanation:

Calcium, Magnesium, Barium, Beryllium, Strontium, and Radium are alkaline earth metals.