You throw a baseball (mass 0.145 kg) vertically upward. It leaves your hand moving at 12.0 m/s. Air resistance can be neglected.
A. At what height above your hand does the ball have half as much upward velocity?
B. At what height above your hand does the ball have half as much kinetic energy as when it left your hand?

Answers

Answer 1

Answer:

Explanation:

A ) initial velocity u = 12 m /s

final velocity v = 6 m /s

height = h

acceleration = - g = - 9.8 m /s²

v² = u² - 2gh

6² = 12² - 2 x 9.8 x h

h = 5.51 m

B )

Let the final velocity when energy becomes half be V at height H

kinetic energy at height h = 1/2 m V²

Given ,

.5 x 1 / 2 m x 12² = 1/2 m x V²

V² = 12² / 2

V = 8.486 m /s

V² = u² - 2 gH

8.486² = 12² - 2 x 9.8 x H

H = 3.67 m .  


Related Questions

How much work is done to push a car 20m using a 200 N force?

W =
J

How much power did you developed in pushing the car in 30 s?

P =
W

Answers

Answer:

F=200N d=20m t=30s

W=F*d

W=200*20

W=4000J

P=W/t

P=4000/30

P=400/3

P=133.333333334 W

HELP ME OUT PLS!!!!!!!!!!!!!!!!​

HELP ME OUT PLS!!!!!!!!!!!!!!!!

Answers

Answer:

Netwon's first law: The little girl will not move until she uses her leg to apply a force forward.

Newton's second law: The greater the push of the skater's foot against the ice, the faster he will accelerate.

Newton's third law: The skates are pushing on the ice and the ice is pushing back on the skates

Explanation:

Newton's first law is that a body at rest will remain at rest until a force is acted upon it. So, the correct example would be the little girl because she needs to push off her leg to start going forward. She is at rest until she does so.

Newton's second law is that the force acting upon an object is equal to the mass of the object times the acceleration. The more force the more acceleration, so the correct example would be the skater pushing against the ice in order to accelerate faster. The more force he exerts the faster acceleration.

Newton's third law is for every action there will be an equal and opposite reaction. The correct example would be the skater pushing down on the ice and the ice exerting the same force to the skate. Both are exerting the same force on each other, like the law says.

Hope this helps!!

Two springs are attached to two hooks. Spring A has a greater force constant than spring B. Equal weights are suspended from both. Which statement is true?

Question 6 options:

Spring A will have more extension than spring B.


Spring B will have more extension than spring A.


Both springs are equally stiff.


Both springs will have equal extension.

Answers

In a case whereby two springs are attached to two hooks and Spring A has a greater force constant than spring B. Equal weights are suspended from both then Spring B will have more extension than spring A.

What is force constant ?

Force constant or spring constant  serves as the measure of the stiffness of a spring which can be explained as the force per unit deformation of the spring.

In the case above, we can see that since Equal weights are suspended from both, then there will be more extension at the side of  Spring B  since A has a greater force constant.

Therefore, option B is correct.

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a) a drone flies 150 m to southwest (directly between south and west), then flies 85 m directly south, and finally flies 550 m in the direction 35 degrees north of east. Use the analytical method to find the resultant displacement of the drone (magnitude and direction)

you can help with a​

a) a drone flies 150 m to southwest (directly between south and west), then flies 85 m directly south,

Answers

The resultant of the displacement is 336.5m

What is resolution of vectors?

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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A detailed graph of angular velocity versus time is shown. What is the angular displacement, in radians, during the time interval from 0.75 s to 14.2 s?

Answers

0.116 rad/s is the angular speed in radians, during the time interval from 0.75 s to 14.2 s

ω=Δθ/Δt

Δθ= 90° = 1.571rad

Δt=13.45

ω=1.571/13.45

ω=0.116 rad/s

The rate of change of angular displacement, or the angle a body travels along a circular path, is the definition of angular speed. Calculating angular speed involves dividing the quantity of rotations or revolutions made by a body by the amount of time required. Omega is a Greek letter that represents angular speed. The SI's angular speed unit is rad/s.

As is well known, angular speed is determined by dividing the rate of displacement change by the time. As a result, the angular speed equation is = /t. Despite the procedure stated above, a different and more well-liked formula is used to determine angular speed in competitive testing. As ω = θ/t

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How do I describe the movement of a student walking at fore say 10 M/S on a velocity time graph from 5-10s? So like starting at 5 seconds to 15 seconds the student is at 10 meters and stays there until after 15 seconds. how do i describe that? How far did the student walk? Please answer

Answers

velocity=10m/sTime=10-5=5s

It means The student walked for 5s with a velocity of 10m/s

Distance=Velocity(Time)

\(\\ \rm\longmapsto Distance=10(5)\)

\(\\ \rm\longmapsto Distance=50m\)

Answer:

\(\sf\longmapsto \: 50 \: metres\)

Explanation:

Given,

Velocity is 10m/s

Let us find the time:

\(\sf\longmapsto \: 10 - 5\)

\(\sf\longmapsto \: 5 \: seconds\)

Now,We know that Distance = Velocity × Time

\(\sf\longmapsto \: 10 \times 5\)

\(\sf\longmapsto \: 50 \:metres\)

A book on a 2-meter high shelf has a mass of 0.4 kg. What is its potential energy?

Answers

Answer:

\(\boxed {\boxed {\sf 7.84 \ Joules}}\)

Explanation:

The formula for potential energy is:

\(PE=m*g*h\)

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass of the book is 0.4 kilograms. The gravitational acceleration on Earth is 9.8 m/s². The height of the book is 2 meters.

\(m=0.4 \ kg \\g=9.8 \ m/s^2 \\h=2\ m\)

Substitute the values into the formula.

\(PE=(0.4 \ kg)(9.8 \ m/s^2)(2 \ m)\)

Multiply the first two numbers.

0.4 kg*9.8 m/s²= 3.92 kg*m/s²If we convert the units now, the problem will be much easier later on. 1 kg*m/s² is equal to 1 Newton. So, our answer of 3.92 kg*m/s² is equal to 3.92 N

\(PE=(3.92 \ N )(2 \ m)\)

Multiply.

3.92 N* 2 m=7.84 N*m1 Newton meter is equal to 1 Joule (this is why we converted the units). Our answer is equal to 7.84 Joules.

\(PE=7.84 \ J\)

Answer:

7.84 is your answer ok bye

Kinetic energy is the energy an object has due to its

Answers

The kinetic energy of an object is the energy it has because of its motion. ... When we double the mass, we double the energy; however, when we double the velocity, energy increases by a factor of four.

Kinetic energy is the energy an object has due to its Motion.

Kinetic energy is a characteristic of a moving particle. It is a type of energy that a matter or particle possesses due to its motion.

It is expressed:

\(K_E = \frac{1}{2}mv^2\)

Where m is the mass of the particle and v is velocity.

Hence, Kinetic energy is the energy an object has due to its Motion.

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a hiker walks westward 2 meters and then eastward 7 meters. for this motion the distance moved is?​

Answers

Answer:

d = 9 [m]

Explanation:

This is a problem where we must be clear about the concept of distance, which tells us that it is a measure of the space traveled on a trajectory.

Therefore:

d = 2 + 7

d = 9 [m]

The directions are not taken into account, as it is the sum of the displacements traveled, regardless of their directions.

A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material, which forms a hollow tube, has an inner radius a and an outer radius b, and the insulator provides a resistance R between the conductors. If a second insulator, made of the same material and having the same length, is made with double both the inner radius and the outer radius of the first, what resistance would it provide between the conductors

Answers

This question is incomplete, the complete question is;

A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material, which forms a hollow tube, has an inner radius a and an outer radius b, and the insulator provides a resistance R between the conductors. If a second insulator, made of the same material and having the same length, is made with double both the inner radius and the outer radius of the first, what resistance would it provide between the conductors

a) (In2)R

b) 4R

c) R/(In2)

d) 2R

e) R

Answer: Option e) R is the correct answer.

Explanation:

Given that;

Inner radius = a

Outer radius = b

Conical Cylinder

∫dR = ∫(edr/2πrL)

R = e/2πL In e |ᵇₐ

R = e/2πL In(b/a) ------------- let this be equation 1

Taking a look at the second cone

a' = 2a

b' = 2a

R' = e/2πL In(2b/2a)

{L = L'}

R' = e/2πL In(b/a) -------let this be equation 2

now lets compare the two equation

R = e/2πL In(b/a)

R' = e/2πL In(b/a)

so R' = R

Therefore Option e) R is the correct answer.

A high-resistance material is used as an insulator between the conductors of a length of coaxial cable.

What is the resistance of five 10Ohm resistors in parellel?

Answers

Answer:

The equivalent resistance is 2 ohms.

Explanation:

let the first resistance = R₁ = 10 ohm

let the second resistance = R₂ = 10 ohm

let the third resistance = R₃ = 10 ohm

let the fourth resistance = R₄ = 10 ohm

let the fifth resistance = R₃ = 10 ohm

The equivalent resistance is calculated as;

\(\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} + \frac{1}{R_5} \\\\\frac{1}{R_T} = \frac{(R_2R_3R_4R_5)+(R_1R_3R_4R_5)+(R_1R_2R_4R_5) +(R_1R_2R_3R_5)+(R_1R_2R_3R_4)}{R_1R_2R_3R_4R_5} \\\\R_T = \frac{R_1R_2R_3R_4R_5}{(R_2R_3R_4R_5)+(R_1R_3R_4R_5)+(R_1R_2R_4R_5) +(R_1R_2R_3R_5)+(R_1R_2R_3R_4)} \\\\R_T = \frac{(10^5)}{(10^4)+(10^4)+(10^4)+(10^4)+(10^4)} \\\\R_T = \frac{10^5}{5(10^4)} \\\\R_T = \frac{10}{5} \\\\R_T = 2 \ ohms\)

Therefore, the equivalent resistance is 2 ohms.

A 6.0-kg rock is dropped from a height of 9.0 m. At what height is the rock's kinetic energy twice its potential energy?

Answers

Answer:

When the rock is dropped from a height of 9.0 m, its initial potential energy is given by

PE = mgh = (6.0 kg)(9.8 m/s^2)(9.0 m) = 534 J

We can solve for the height at which the kinetic energy of the rock is twice its potential energy by setting the kinetic energy equal to twice the potential energy and solving for h.

KE = 1/2 mv^2 = (1/2)(6.0 kg)(v^2)

2 * PE = 2 * (6.0 kg)(9.8 m/s^2)(h)

Substituting and solving for h yields

h = 15 m

you made $100,000 this year. you have $0 in adjustments, $11,500 in deductions and $7,300 in exemptions. What is your taxable increase?

Answers

The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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represent the reading of a vernier caliper with a diagram showing the reading 45.75mm

Answers

The reading on a vernier caliper can be represented as 45.75mm.

1. Understand the components of a vernier caliper: A vernier caliper consists of two main scales - the main scale and the vernier scale. The main scale is typically graduated in millimeters, while the vernier scale is a smaller scale that slides along the main scale.

2. Locate the main scale: Identify the main scale on the vernier caliper. The main scale is usually marked on the fixed jaw of the caliper and extends in a linear fashion.

3. Identify the vernier scale: The vernier scale is attached to the movable jaw of the caliper. It slides along the main scale and consists of smaller divisions.

4. Align the zero marks: Close the jaws of the caliper and ensure that the zero marks on both the main and vernier scales are aligned.

5. Determine the main scale reading: Read the main scale value that aligns with the zero mark on the vernier scale. In this case, the main scale reading will be 45mm.

6. Locate the vernier scale reading: Examine the vernier scale and identify the division on the vernier scale that lines up perfectly with a division on the main scale. This will give you the additional measurement beyond the main scale reading.

7. Determine the vernier scale reading: Find the division on the vernier scale that aligns with a division on the main scale. The value of this vernier division corresponds to the additional measurement. In this case, the vernier scale reading will be 0.75mm.

8. Add the main scale and vernier scale readings: Combine the main scale reading and the vernier scale reading to get the final measurement. In this case, the final reading will be 45.75mm.

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the resultant force acting on the whale is 18000 the mass of the whale is 4100 kg

Answers

The resultant force acting on the whale is 18000 the mass of the whale is 4100 kg is 4.39 \(m/s^{2}\)

The resultant force acting on an object is the net force acting on the object, which is the vector sum of all the individual forces acting on the object. In this case, we have a whale with a resultant force of 18000 N acting on it, and a mass of 4100 kg.

The relationship between force, mass, and acceleration is given by Newton's Second Law of Motion, which states that the net force acting on an object is equal to the product of its mass and acceleration:

F_net = m * a

where F_net is the net force, m is the mass of the object, and a is the acceleration of the object.

Rearranging this equation, we can solve for the acceleration of the whale:

a = F_net / m

Substituting the given values, we get:

a = 18000 N / 4100 kg

a ≈ 4.39 \(m/s^{2}\)

This means that the whale is accelerating at a rate of approximately 4.39 \(m/s^{2}\) due to the resultant force acting on it. The direction of this acceleration will depend on the direction of the resultant force.

It is important to note that a force alone does not determine the motion of an object. The motion of an object depends on the net force acting on it and the object's initial velocity. If the whale was already moving before the resultant force was applied, then the motion of the whale would depend on the interaction between the force and the object's initial velocity.

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Two loudsspeakers emit identical sound waves along the x axis. THe osund at a point on the axis has maximum intensity when the speakers are 40 cm apart. The sound intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 50 cm. If the distance between the speakers continuse to increase, at what separation will the sound intensity again be a maximum?

Answers

Answer: 30 cm.

Solving

The situation described is that of two sources of sound waves that are separated by some distance. The two waves interfere with each other constructively at some points and destructively at others. When they interfere constructively, the amplitude (and intensity) of the sound wave is greater than when they interfere destructively.

When the speakers are 40 cm apart, the waves that they produce are in phase at some points on the axis, leading to constructive interference and a maximum in the intensity of the sound. As the distance between the speakers is increased beyond 40 cm, the points of constructive interference move farther apart, and the intensity of the sound decreases. When the speakers are 50 cm apart, the waves that they produce are exactly out of phase at some points on the axis, leading to complete destructive interference and a minimum in the intensity of the sound.

If the separation between the speakers continues to increase, the points of constructive interference will move closer together again, and the intensity of the sound will increase. The separation between the speakers at which the intensity of the sound will again be a maximum can be found using the following equation:

d = λ/2 + nλ

where d is the separation between the speakers, λ is the wavelength of the sound wave, and n is an integer that represents the number of half-wavelengths between the speakers.

At the maximum, the separation is an even multiple of half the wavelength, so we can use the formula above with n = 1. The wavelength can be found from the distance between the speakers at the minimum, which is 50 cm, and the distance at the maximum, which is 40 cm:

λ = 2(d_max - d_min) = 20 cm

Substituting λ and n into the formula gives:

d = λ/2 + nλ = 10 cm + 20 cm = 30 cm

Therefore, the sound intensity will be a maximum again when the separation between the speakers is 30 cm.

Riker and Pickard measure the enterprise in space dock and find that it is 100 m wide and 700 m long. While Riker studies for his next physics exam, Pickard climbs into the enterprise and travels at a speed of 0.4c toward the planet Zandar which is 5 light years away to stop the evil Borgs. a. How far is the planet Zandar according to Riker

Answers

This question is incomplete, the complete question;

Riker and Pickard measure the enterprise in space dock and find that it is 100 m wide and 700 m long. While Riker studies for his next physics exam, Pickard climbs into the enterprise and travels at a speed of 0.4c toward the planet Zandar which is 5 light years away to stop the evil Borgs. a. How far is the planet Zandar according to Riker, b. how long does pickard to get to zandar according to Riker

Answer:

a) distance = 4.7305 × 10¹³ km

b) pickard will get to zandar in 12.5 years

Explanation:

Given that the data in the question;

we know that; speed of light c = 1080000000 km/hr

travel speed v = 0.4c = ( 0.4 × 1080000000 km/hr) = 432,000,000 km/hr

Also we know that;

1 light year = 9.461 × 10¹² km

distance of planet d = 5 light years = (9.461 × 10¹² × 5) = 4.7305 × 10¹³ km

a) Therefore; According to Ricker; the planet zandar is 5 light years away;

distance of planet d = 5 light years = (9.461 × 10¹² × 5)

d = 4.7305 × 10¹³ km

Now, time travel according to Riker

Tr = d/v

we substitute

Tr = 4.7305 × 10¹³ km / 432,000,000 km/hr

Tr = 109,502.3148 hr

convert to years

Tr = 109,502.3148 / ( 24hrs × 365 days)    

Tr = 12.5 years

Therefore; pickard will get to zandar in 12.5 years

If the man and woman are taken to a planet where the acceleration due to gravity is twice that of earth repeat the woman mass was 25kg on earth and the man was 300N on another planet

If the man and woman are taken to a planet where the acceleration due to gravity is twice that of earth

Answers

The mass of the woman is 25 kg because the mass is constant.

The mass of the man can be found using the formula: W = mg, where g is double Earth's gravity.

\(\begin{gathered} m=\frac{W}{g} \\ m=\frac{300N}{2\cdot9.8\cdot\frac{m}{s^2}} \\ m=\frac{300}{19.6}kg \\ m\approx15.3\operatorname{kg} \end{gathered}\)

The mass of the man is 15.3 kg.

The weight of the man on Earth can be found with the same formula but using Earth's gravity.

\(\begin{gathered} W=15.3\operatorname{kg}\cdot9.8\cdot\frac{m}{s^2} \\ W=149.94N \end{gathered}\)

The weight of the man on Earth is 149.94 N.

At last, the weight of the woman on Earth can be found using the same method before.

\(\begin{gathered} W=25\operatorname{kg}\cdot9.8\cdot\frac{m}{s^2} \\ W=245N \end{gathered}\)

The weight of the woman on Earth is 245N.

tunneling is a variation of techniques used to achieve higher degrees of privacy for browsing on the internet

Answers

Tunneling is a variation of techniques used to achieve higher degrees of privacy for browsing on the internet. This is true.

What is privacy?

The right to privacy is a fundamental component of human rights that also supports equality before the law and the freedoms of association, expression, and thought. But defining it is difficult. Different individuals and nations have various points of view. In general, the right to privacy includes the freedom from interference and invasion.

This acknowledges that each person has a domain of existence and activity that rightfully belonged to that person alone, where he or she ought to be unrestricted by coercion or even unwanted observation.

Packets can be moved between networks using tunneling. Encapsulation is how tunneling functions: A tunneling protocol in computer networks is a communication protocol that permits the transfer of data between networks. It entails using a technique called encapsulation to allow private network communications to be sent across a public network.

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Complete question

tunneling is a variation of techniques used to achieve higher degrees of privacy for browsing on the internet

true or false.

Which conversion can take place in a transformer
A. An electric current into a magnetic field
B. Electric energy into mechanical energy
C. Mechanical energy into electric energy
D. A lower voltage into a higher voltage

Answers

Answer:

D. A lower Voltage into a higher

 which of the following questions may be difficult to test scientifically?

What is the average flight speed of an African swallow?

how was Hawaii formed?

why is cheating wrong?

is there evidence of water on other planets?

Answers

When conducting a scientific experiment, it will be difficult to test why cheating is wrong. Thus, (c) is the correct answer.

Scientific experiment is an experiment or study conducted by researchers to verify the authenticity of a test or hypothesis scientifically or assess the possibility or effectiveness of something that has not been attempted before. Scientific experiments show what happens when a certain component is modified, which sheds light on cause-and-effect relationships.

Controlled, field and natural experiments are three essential types of scientific experiments.

Keeping in mind that a successful scientific experiment typically evaluates one independent variable at a time, it is crucial to utilize a control group and to hold all other possible variables constant.

Therefore, it is difficult to test scientifically why cheating is wrong.

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Answer: why is cheating wrong?

Explanation: may be difficult to test scientifically is why is cheating wrong

Several motorboats with the same mass are used in an experiment. the forces of the different motors versus their accelerations are graphed. what is the y-intercept of this graph?

Answers

The y-intercept of a graph is the point at which the graph crosses the y-axis. In this case, the y-intercept of the graph showing the relationship between the motor's force and the boat's acceleration would represent the force required to produce zero acceleration.

In this scenario of the boats being used in an experiment, if the boats have the same mass and the motors are producing force, and the forces are graphed against the acceleration, this will give us a straight line, and the y-intercept of this graph will be the force required to keep the boat at a zero acceleration, this force is known as "friction force" which includes the friction force of the water and the friction force of the bearings in the motor and other mechanical parts in the boats and motor.

It's worth noting that, in practice, getting the y-intercept in this experiment might be very hard as it's very rare to get zero acceleration. Still, one can aim for the lowest possible acceleration, and the force measured can be considered as an approximation for the friction force.

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12. The distance an object has traveled when starting at an initial velocity is given by the equation:
d = vit +at². In the equation, vi represents the initial velocity, t represents the time traveled, and
a represents the acceleration. Solve the equation for a.

Answers

The equation for acceleration is:

a = (d - vi*t) / t²

The distance an object  traveled when starting at an initial velocity isd = vit +at². represents the initial velocity

The distance an object has traveled when starting at an initial velocity is given by the equation:

d = vit + at²

To solve for acceleration, we need to isolate the term with "a" on one side of the equation. Let's begin by subtracting the first term on the right-hand side of the equation from both sides:

d - vit = at²

Next, we can divide both sides by t² to isolate "a":

a = (d - vit) / t²

Therefore, the equation for acceleration is:

a = (d - vi*t) / t²

an object has the mass of 5.7kg what is the force of gravity acting on the object on earth

Answers

Answer:

55.68

Explanation:

A rubber ball is dropped onto a ramp that is tilted at 20 ∘ , as shown in the figure(Figure 1) . A bouncing ball obeys the "law of reflection," which says that the ball leaves the surface at the same angle it approached the surface. The ball's next bounce is 3.0 m to the right of its first bounce.

Answers

The ball rebound speed on its first bounce will be 4.79 m/s.

How to calculate the speed?

It should be noted that based on the information given the launch angle will be:

= 70° - 20°

= 50°

Therefore, vy/vx = tan 50

vx = vy/tan 50 = 3/t

-1.09 = vy + 0.5gt²

= 3tan50 + 4.9t²

0.95 = t²

t = ✓0.95

t = 0.97.

vx = 3/0.97

vx = 3.06m/s

vy = 3.68m/s

Therefore, the speed will be:

= ✓(3.06)² + (3.68)²

= 4.79m/s

Complete question:

A rubber ball is dropped onto a ramp that is tilted at 20° as shown in the figure(Figure 1) . A bouncing ball obeys the "law of reflection," which says that the ball leaves the surface at the same angle it approached the surface. The ball's next bounce is 3.0 m to the right of its first bounce. What is the ball rebound speed on its first bounce?

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Consider a particle of mass m acted on by a force F in an inertial frame.Prove that dK=F× ( d×r), where d×r is the change in position vector of a particle in a time d×t, and d×K is the corresponding change in the kinetic energy K=1÷2(mv²)

Answers

From the change in the kinetic energy of the particle, the force that acted on the particle from an inertial frame is proved as F(dr) = dK.

Kinetic energy of the particle

The kinetic energy of the particle is given as;

K.E = ¹/₂mv²

dK/dv = mv

m = dK/vdv

Force on the particle

The force on the particle is given by Newton's second law of motion;

F = ma

a = dv/dt

F = m(dv/dt)

F = (dK/vdv) (dv/dt)

F = dK/vdt

F(vdt) = dK

v = dr/dt

F (dr/dt) x (dt) = dK

F(dr) = dK, proved

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A race car traveling at 12 m/s is uniformly accelerated to a velocity of 100 m/s over a
30 second interval. What is its acceleration during this time?
(Please provide your answer to 2 decimal places)

Answers

Answer:

using the formula -- V=u+at

u=12m/s, v=100m/s, t=30s, a=?

100=12+a(30)

100-12=a(30)

88=a(30)

88/30=a(30)/30

2.93=a

a=2.93m/s²

The center of mass of an object does not have to be located within the object.Select one:O TrueO False

Answers

True.

As an example think of a donut, the center of mass of the donut it's at the center of the whole (assuming the density is uniform

If you could cut the paper in half 20 times, would the paper be bigger or smaller than the following: 1 hair--------------------, a germ-------------------- and an atom---------------------.

Do you think you could keep cutting the paper forever?-----------------------------------------

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Science

Answers

Answer:

Maybe???

Explanation:

but how big is the paper?

but I think even the paper is super big, the ending result will still be too small to observe …

1) How many joules of heat are required to raise the temperature of 550 g of water from
12.7 °C to 28.8°C ? Specific heat of liquid water is 4.184 J/g °C.

Answers

Answer:

Explanation:

You can use \(Q = mc\Delta T=(550)(4.184)(28.8-12.7)=37049.32\) joule.

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