Answer:
C) The work is negative on the way up and positive on the way down.
Explanation:
The general formula for the work done on an object is given as follows:
W = F d Cosθ
where,
W = Work Done
F = force applied
d = displacement covered
θ = angle between direction of motion force
So, when the baseball goes up, the gravitational force acts upon it in downward direction. And the motion of the ball is in upward direction. So, the motion and force are both in opposite directions. This means θ = 180°. Hence,
(W)up = F d Cos 180° = F d(-1)
(W)up = - F d
Thus, the work done on baseball during upward motion is negative
Now, when the baseball goes down, the gravitational force acts upon it in downward direction. And the motion of the ball is also in downward direction. So, the motion and force are both in same directions. This means θ = 90°. Hence,
(W)up = F d Cos 90° = F d(1)
(W)up = F d
Thus, the work done on baseball during downward motion is positive
So, the correct option is:
C) The work is negative on the way up and positive on the way down.
in the sun and seasons simulation in module 2, you observed that, at the equator, there are 12 hours of daylight year-round, because the angle between the apparent path of the sun across the sky and the horizon is always
There are always 12 hours of daylight at the equator because the apparent path of the sun across the sky and the horizon are always perpendicular to one another.
The "almost" equal lengths of day and night are caused by the sun's rays being bent or refracted, making it appear that the sun is above the horizon when it is actually below it. In addition, because the sun rises and sets later at higher latitudes (those farthest from the equator), the days become a little longer there. As a result, the length of the day will vary from around 12 hours to several days before and after the equinox and six and one-half minutes at the equator.
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You can transfer energy from one object to another by doing _.Units of energy are the same as work which are called _.
You can transfer energy from one object to another by doing work.
Units of energy are the same as work which are called Joules.
please help answering A,B,C in screenshots thank you!
The slope of the graph is 0.5 m/s² and when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.
To plot the velocity vs. time graph, we'll use the given data points:
Duration, At (s): 2.0, 4.0, 6.0, 8.0, 10.0, 12.0
Velocity, v (m/s): 6.0, 7.0, 8.0, 9.0, 10.0, 11.0
Let's plot these points on a graph:
Time (s) [x-axis] | Velocity (m/s) [y-axis]
--------------------------------------------
2.0 | 6.0
4.0 | 7.0
6.0 | 8.0
8.0 | 9.0
10.0 | 10.0
12.0 | 11.0
After plotting the points, we can connect them with a straight line to represent the motion of the object. This line represents the velocity vs. time relationship.
Now, let's calculate the slope of this line. The slope of a line represents the rate of change of the dependent variable (velocity) with respect to the independent variable (time). In this case, it gives us the acceleration of the object.
Using the formula for calculating the slope of a line:
Slope (k) = (Change in velocity) / (Change in time)
For the first two points:
Change in velocity = 7.0 - 6.0 = 1.0 m/s
Change in time = 4.0 - 2.0 = 2.0 s
Slope (k) = 1.0 m/s / 2.0 s = 0.5 m/s²
Therefore, the slope of the graph is 0.5 m/s².
Now, to answer part B, the physical significance of the slope value is that it represents the object's acceleration. In this case, the constant acceleration experienced by the object is 0.5 m/s².
Moving on to part C, we are given the equation d = kt, where d represents the displacement and t represents time. Since the object is experiencing constant acceleration, the equation can be rewritten as d = 0.5t, where 0.5 is the acceleration (k).
To predict the value of "d" when t = 1.5 s, we can substitute the value of t into the equation:
d = 0.5 * 1.5 = 0.75 meters
Therefore, when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.
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The probable question may be:
An object is subjected to a constant acceleration along a frictionless track. A student measures its velocity (v) after specific durations (At). The student uses a graph to analyze the truck's motion.
Duration, At, (s) :- 2.0,4.0,6.0,8.0,10.0,12.0.
Velocity, v, (m/s) :- 6.0,7.0,8.0,9.0,10.0,11.0
A. Plot the velocity (in meters/sec) vs. time (seconds). The velocity is the y-axis and time is the x-axis. Use any graphing software you like or graph this data in pencil on graph paper. Excel has a nice graphing package. Calculate the slope of this graph. You will
B. What is the physical significance of the slope value computed in part A?
C. Having determined the slope of the line, you can now write d = kt. Use this equation to predict a value of "d" when t = 1.5 s.
Explain how the energy from the sun is transferred to fossil fuel?
Answer:
Fossil fuels are energy sources that come directly from nature. First, the sun's radiant energy is stored as chemical energy in plants by photosynthesis. When the plants die, they start decaying. After many years, the plants are turned into fossil fuels.
Explanation:
Fossil fuels rely on the Sun's energy because the energy in fossil fuels came from plants and algae as they performed photosynthesis, which requires sunlight.
When sunlight strikes a plant, some of the energy is trapped through photosynthesis and is stored in chemical bonds as the plant grows.
(u should paraphrase it)
6. As distance increases, gravitational force *
(10 Points)
increases
decreases
1.How are elements arranged on the periodic table in terms of valence electrons?
2. Show some evidence using data tables
3. Explain how the evidence supports your claim. Explain how the evidence from your data table shows the trends for valence electrons for both groups and periods on the periodic table.
Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.
1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.
2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:
Element | Electron Configuration | Group | Period |
--------------------------------------------
Hydrogen | 1s^1 | 1 | 1 |
Lithium | [He] 2s^1 | 1 | 2 |
Carbon | [He] 2s^2 2p^2 | 14 | 2 |
Oxygen | [He] 2s^2 2p^4 | 16 | 2 |
Neon | [He] 2s^2 2p^6 | 18 | 2 |
--------------------------------------------
3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.
- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.
- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.
By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.
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A man runs 300 m West in 60 seconds. He then runs 100 m
North-west in 20 seconds.
What is his average velocity in metres per second?
Answer:
5 m/s
Explanation:
Total distance = 300 + 100 = 400m
Total time = 60 + 20 = 80s
Velocity = 400/80 = 5m/s
Average velocity of man is 5 meter per second.
To find the average speed of an object we divide the total distance travelled by the total time time taken by object.
Total distance travelled by man = 300 + 100 = 400 m
Total time taken by man = 60 + 20 = 80 seconds
Average velocity,\(=\frac{400}{80} =5m/s\)
Thus, Average velocity of man is 5 meter per second.
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A dog walks 14 meters to the east and then 20 meters back
to the west.
For this motion, what is the distance moved?
Dis ance (m) =
What is the magnitude and direction of the
displacement?
Magnitude (m) =
Dir'n =
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answer using our built-in
number pad.
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The distance is 34m , magnitude of the displacement is 6m and direction of displacement is towards west.
As per question, a dog walks 14 meters to the east and then 20 meters back to the west.
The distance moved for this motion is given below,
Distance = 14 + 20 m = 34m
The magnitude of the displacement and its direction are given below:
Displacement = 14 - 20 m = - 6m
negative sign indicates that the direction of displacement is towards west.
Magnitude of the displacement = 6m
Thus, the distance is 34m ,direction of displacement is towards west and magnitude of the displacement is 6m.
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discuss how devastating a 7.7 - magnitude earthquake is.
Answer:
Explanation:
It’s devastating because when a earthquake is 7.7 magnitude the
The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds
3)Is there any time interval in which no force acts on object.Justify
1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.
2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.
3) There is no time interval in which no force acts on the object.
(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.
In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.
Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2
Acceleration, a = slope= 20/3 m/s^2
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.
Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.
(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.
The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:
Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.
Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.
(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.
Therefore, there is no time interval in which no force acts on the object.
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DesCribed briefly the method you would take in location the position of an object A defined by an ordered pair of value (8,4)
Answer:
Explanation:
The method that I will use to locate the position of an object of ordered pair of value (8, 4) is known as the graphical method. The ordered pair of value (8, 4) is known as the coordinates. In graphical method, the coordinate will be located on the Cartesian plane having both x and y axis. The graph will be a 2-dimensional graph with y-axis being along the vertical and the x-axis along the horizontal.
The coordinates (8, 4) means that the value of x is +8 and the value of y is +4. To locate the point P(8, 4) on the graph, we will have to locate both points on the positive x and y axis respectively and then mark out their point of intersection. This point of intersection will be the position of the object defined as ordered pair of value (8,4).
Which planet has rings and less gravity than Saturn?
Answer: Neptune
Explanation:
Explanation:
neptune is correct
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A 2.0 kg object is raised a vertical distance of 3.0 m. What is the resulting change in
a
gravitational potential energy? Round your answer to the nearest whole number.
Answer:
gpe gained = 60J
Explanation:
gravitational potential energy = mass * gravity * height
gpe = 2 kg * 10 N * 3 m
gpe = 60J
A -9.00 μC point charge and +7.00 μC point charge are placed along the x-axis at x = 0.000 m and x = 0.4 m, respectively. Where must a third charge be placed along the x-axis (relative to the origin) so that it does not experience any net electric force due to the other two charges? The position on the x-axis is in meters and use three significant digits.
Answer:
x₃ = 0.397 m
Explanation:
For this exercise we use the vector sum of the forces, where the force is electric given by the Coulomb equation
F = \(k \frac{q_1q_2}{r^2}\)
We also use that charges of the same sign repel and charges of a different sign attract.
In this case the force between load 1 and 3 has one direction and the force between 2 and 3 has the opposite direction, in the exercise they ask that the force on load 3 be zero
∑ F = F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
we write the expressions of the forces, the distances are
r₁₃ = (x₁-x₃) ²
r₂₃ = (x₂ - x₃) ²
\(k \frac{q_1 \ q_3}{(x_1-x_3)^2} = k \frac{q_2 \ q_3}{(x_2-x_3)^2 }\)
x₁ = 0 m
\(\frac{q_1}{x_3^2 } = \frac{q_2 }{(x_2 - x_3)^2 }\)
q₁ (x₂ - x₃) ² = q₂ x₃²
\(\sqrt{\frac{q_1}{q_2} }\) (x₂ -x₃) = x₃
we substitute the values
\(\sqrt\frac{9}{7} }\) (0.4 -x₃) = x₃
x₃ (1 + \(\sqrt{9/7}\)) = \(\sqrt{9/7}\) 0.4
x₃ (1.13389) = 0.453557
x₃ = 0.453557 / 1.13389
x₃ = 0.397 m
A proton is released from rest at the positive plate of a parallel-plate capacitor. It crosses the capacitor and reaches the negative plate with a speed of 45000 m/s.
What will be the final speed of an electron released from rest at the negative plate?
Express your answer to two significant figures and include the appropriate units
V=_________
Answer:
2.1x10^6m/s
Explanation:
One electron has a charge of –1.602e-19 C
mass of electron is 9.1e-31 kg
mass of proton is 1.6726e−27 kg
mass ratio is 1.6726e−27 / 9.1e-31 = 1838
The force is constant, F
distance is constant, d
a = F/m
a increases by a factor 1838, as m decreases by that factor
a = a₀1838
v₀² = 2a₀d
v² = 2a₀d1838
v²/v₀² = 2a₀d1838 / 2a₀d = 1838
v² = 1838v₀² = 1838(45000)²
v = 45000√1838 = 2.1e6 m/s
What is the difference between the conservation of mechanical energy and the no conservation of mechanical energy?
Conservation of mechanical energy only holds in a frictionless environment where all collisions are perfectly elastic. It shows that the sum of the kinetic and potential energies of an isolated system becomes a time-independent constant.
Energy conservation states that the sum of all energies not only kinetic and potential but also heat chemical energy etc. in an isolated system is constant. The former is a special case of the latter, and the latter is a universal law, but it is often inapplicable because it must account for all of the observable universes.
According to the law of conservation of mechanical energy the total mechanical energy of the system is conserved. That is, energy is neither created nor destroyed. The internal transformation from one form to another is possible only if the forces acting on the system are of a conservative nature. Mechanical energy is not conserved unless non-conservative forces are acting as friction and other dissipative forces directly convert work or ME into thermal energy.
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One of the possible criteria of Schizophrenia is hallucinations.
Select one:
O True
O False
What is the electric potential at a point midway between two charges, -5.37 microC and -4.11 microC, separated by 8.43 cm?
Given:
q1 = -5.37 microC
q2 = -4.11 microC
d = 8.43 cm
To find:
The electric potential at a point midway between two charges.
Explanation:
The potential V is given by:
\(V=\frac{{q}}{{{4\pi\epsilon_0d}}}\)The charge q1 is at a distance of 4.215 cm from the midpoint.
The potential due to charge q1 is:
\(V_1=\frac{q1}{4\pi\epsilon_0d}=\frac{-5.37\times10^{-6}\text{ C}\times9\times10^9\text{ Nm}^2\text{/C}^2}{4.215\times10^{-2}\text{ m}}=-1146619.21\text{ V}=-1.146\times10^6\text{ V}\)The charge q2 is at a distance of 4.215 cm from the midpoint.
The potential due to the charge q2 is:
\(V_2=\frac{q_2}{4\pi\epsilon_0d}=\frac{-4.11\times10^{-6}\text{ C}\times9\times10^9\text{ Nm}^2\text{/C}^2}{4.215\times10^{-2}\text{ m}}=-877580.07\text{ V}=-0.877\times10^6\text{ V}\)The electric potential V at a midpoint is:
\(V=V_1+V_2=-1.146\times10^6\text{ V}-0.877\times10^6\text{ V}=-2.023\times10^6\text{ V}=-2.023\text{ MV}\)Final answer:
The electric potential at a point midway between the given two charges is -2.023 MV.
You push on a box and are unable to move it. What
force opposes your push?
Static friction
Sliding friction
Roling friction
Air resistance
Answer:
Static Friction!
The concept of static friction refers to the forces that keep an object at rest on a surface. They can be caused by people trying to move it on a surface, without actually causing any movement between the object and the surface.
2. If your body is dry, the resistance it offers to the flow of electrical current is about____ K ohm.
O A. 200
O B. 50
O C. 100
O D. 125
Answer:
The resistance of human body is around 100,000 ohm.
= 100 Kohm.
option C is correct one.
#5) Which of the following procedures would make
the biggest increase to gravitational force between two
identical objects?
A) Increasing the masses and increasing the distance
between the two objects.
B) Decreasing the masses and decreasing the distance
between the two objects.
C) Increasing the mass and decreasing the distance
between the two objects.
D)Decreasing the masses and increasing the distance
between the two objects.
Answer:
C) Increasing the mass and decreasing the distance
Explanation:
Since the equation for gravitational force is Fg = (Gm₁m₂)/r² where m₁ and m₂ are the masses of the objects and r is the distance between them, increasing the masses and decreasing the distance will produce a larger Fg.
Hope this helps. I'm not great at explaining. I'm new to Brainly
Thanks
Mrs. J . weighs 557 N. what is her mass?
Answer:
The mass of the person is 56.83 kg
Explanation:
W= 557 N
We know that acceleration due to gravity (g)= 9.8 m/s^2
Now,
W= mass * acceleration due to gravity
557=m * 9.8
m= 557/9.8
m= 56.83
Answer:
her mass is 55.7 Kg.
Explanation:
Weight = Mass × Acceleration
N =ma [a= g for gravitational force acting down word]
N=Mg
find M so make mass become the subject therefore,
Mass = force / gravitational acceleration [let g=10m/s^2]
m=557 / 10
m= 55.7 kg
2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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In a few sentences, describe why abstinence is the best choice to prevent the consequences of sexual activity. (health)
Answer:
Abstinence is the best choice to prevent the consequences of sexual activity because you're putting yourself at lower risk to encounter STD's and STI's. Abstinence also prevents you from getting pregnant.
Explanation:
I got 100% on Edge.
Complete abstinence is the best choice to prevent the consequences of sexual activity because this prevents any type of sexual contact and STDs.
What is Abstinence?Abstinence is a self-enforced restraint from the indulging in bodily activities which are widely experienced as giving pleasure to people. Most frequently, abstinence refers to sexual abstinence, however it can also mean abstinence from alcohol, drugs, food, etc.
Complete abstinence is the only way which can guarantee protection against the infection with sexually transmitted diseases. This means avoiding all the types of intimate genital contact. Someone who is practicing complete abstinence does not have any type of intimate sexual contact. So, there is no risk of getting an STD.
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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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The tires of a 1500 kg car are 0.600m in diameter and the coefficient la of friction with the road and the surface are
Static friction: 0.800
Kinetic friction: 0.600
Assuming that the weight is evenly distributed on the four wheels, calculate the maximum torture that can be exerted by the engine onto a driving wheel without spinning
Answer:
\(1765.8\; {\rm N\cdot m}\), assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\) and that the vehicle is on a level surface.
Explanation:
The weight of this \(m = 1500\; {\rm kg}\) vehicle is \(m\, g = (1500)\, (9.81)\; {\rm N} = 14715\; {\rm N}\).
Under the assumptions, the normal force from the ground on this vehicle would be equal to its weight, \(14715\; {\rm N}\). Since this normal force would be evenly split between the wheels, the normal force on each wheel would be \(3678.75\; {\rm N}\).
As long as the wheels aren't spinning or slipping, friction between the wheels and the ground is considered "static". This type of friction is the same as that on a box that is stationary on a slope (static), and not the same as the friction on a box sliding along the slope (kinetic).
To find the maximum static friction on each wheel, multiply normal force by the coefficient of static friction \(\mu_{\text{s}}\):
\((0.800)\, (3678.75\; {\rm N}) = 2943\; {\rm N}\).
At a distance of \(r = 0.600\; {\rm m}\) from the axis of rotation, the maximum torque on each wheel from static friction would be:
\((2943\; {\rm N})\, (0.600\; {\rm m}) = 1765.8\; {\rm N\cdot m}\).
Evaporation of sweat requires energy and thus take excess heat away from the body. Some of the water that you drink may eventually be converted into sweat and evaporate. If you drink a 20.0-ounce bottle of water that had been in the refrigerator at 3.8 °C, how much heat is needed to convert all of that water into sweat , knowing 1ml contains 0.03 ounces? (Note: Your body temperature is 36.6 °C. For the purpose of solving this problem, assume that the thermal properties of sweat are the same as for water.)
Answer:
The amount of heat required is \(H_t = 1.37 *10^{6} \ J \)
Explanation:
From the question we are told that
The mass of water is \(m_w = 20 \ ounce = 20 * 28.3495 = 5.7 *10^2 g\)
The temperature of the water before drinking is \(T_w = 3.8 ^oC\)
The temperature of the body is \(T_b = 36.6^oC\)
Generally the amount of heat required to move the water from its former temperature to the body temperature is
\(H= m_w * c_w * \Delta T\)
Here \(c_w \) is the specific heat of water with value \(c_w = 4.18 J/g^oC \)
So
\(H= 5.7 *10^2 * 4.18 * (36.6 - 3.8)\)
=> \(H= 7.8 *10^{4} \ J \)
Generally the no of mole of sweat present mass of water is
\(n = \frac{m_w}{Z_s}\)
Here \(Z_w\) is the molar mass of sweat with value
\(Z_w = 18.015 g/mol\)
=> \(n = \frac{5.7 *10^2}{18.015}\)
=> \(n = 31.6 \ moles \)
Generally the heat required to vaporize the number of moles of the sweat is mathematically represented as
\(H_v = n * L_v\)
Here \(L_v\) is the latent heat of vaporization with value \(L_v = 7 *10^{3} J/mol\)
=> \(H_v = 31.6 * 7 *10^{3} \)
=> \(H_v = 1.29 *10^{6} \ J \)
Generally the overall amount of heat energy required is
\(H_t = H + H_v\)
=> \(H_t = 7.8 *10^{4} + 1.29 *10^{6}\)
=> \(H_t = 1.37 *10^{6} \ J \)
when the mass of an object increases, the forcé of gravity
Answer:
increace
Explanation:
they are both going up
1. A kid jumps straight up at 7.20 m/s. How long will he remain in the air?
The time takes the kid to remain in the air is 0.735 s.
What is time?Time is the duration of an events. The s.i unit of time is seconds.
To calculate how long the kid will be in the air, we use the formula below.
Formula:
t = (v-u)/g.................................... Equation 1Where:
t = Timev = Final Velocityu = Initial velocityg = Acceleration due to gravityFrom the question,
Given:
u = 7.20 m/sv = 0 m/sg = -9.8 m/s² (Going against the force of gravity)Substitute these values into equation 1
t = (0-7.20)/-9.8t = -7.20/-9.80t = 0.735 secondsHence, the time is 0.735 s.
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Two tiny objects with equal charges of 7.25 μC are placed at the two lower corners of a square with sides of 0.201 m, as shown.
Find the electric field at point B, midway between the upper left and right corners. If the direction of the electric field is upward, enter a positive value. If the direction of the electric field is downward, enter a negative value. answer in N/C
The electric field at point B, located at the midpoint between the upper left and right corners of the square, can be approximated as 3.244 x \(10^6\) N/C in the upward direction.
To find the electric field at point B, we can consider the contributions from the two charges placed at the lower corners of the square. Since the charges are the same and the distance to point B is the same for both charges, the magnitudes of the electric fields produced by each charge will be equal.
First, let's calculate the magnitude of the electric field produced by one of the charges at point B using Coulomb's Law:
Electric field due to a point charge (E) = (k * q) / \(r^2\)
Where:
- k is the electrostatic constant, approximately equal to 8.99 x 10^9 \(10^9\)N \(m^2/C^2\)
- q is the charge of the object, 7.25 μC (7.25 x \(10^-^6\) C)
- r is the distance from the charge to point B, which is half the length of the square's side, 0.201 m / 2 = 0.1005 m
Plugging in the values, we have:
E = (8.99 x \(10^9 N m^2/C^2\) * 7.25 x \(10^-^6\) C) / (0.1005 \(m)^2\)
E ≈ 1.622 x \(10^6\) N/C
Since the electric fields from the two charges at the lower corners have equal magnitudes and point in the same direction (upward), the total electric field at point B is twice the magnitude of the individual electric field:
Electric field at point B = 2 * E ≈ 2 * 1.622 x \(10^6\) N/C
Electric field at point B ≈ 3.244 x \(10^6\) N/C
Therefore, the electric field at point B, midway between the upper left and right corners of the square, is approximately 3.244 x \(10^6\)N/C upward.
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