You throw an orange out a window at a height of 12.00 meters
upwards at an angle of 32° to the horizontal at a velocity of 3.5
m/s. What is the maximum height that the orange will reach?

Answer:

3.33 m/s west

Explanation:

East is the positive direction.

400kg*20m/s + 800kg*-15m/s =(400kg+800kg)*v

-4000kgm/s=1200kg*v

v=-3.33

400kg*20m/s + 800kg*-15m/s =(400kg+800kg)*v. -4000kgm/s=1200kg*v and v=-3.33.

Collision, which is also known as impact, is the abrupt, powerful coming together in close proximity of two bodies, such as two pool cues, a golf club and a ball, a hammer and a nail, two railroad cars when linked, or a falling object and a floor.

Two factors—the force and the amount of time the items are in contact—affect the outcome of impact in addition to the characteristics of the two objects' materials.

A hard steel ball dropped on a steel plate will typically rebound to almost the same location from whence it was dropped, while a putty or lead ball would not.

Therefore, 400kg*20m/s + 800kg*-15m/s =(400kg+800kg)*v. -4000kgm/s=1200kg*v and v=-3.33.

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A rainbow that you view via a train window while riding will follow you as you travel forward. The rainbow won't be visible for very long because it will appear to move with you as the train travels along its course.

This occurs as a result of the sun, precipitation, and your eyes' angle constantly shifting as the train travels, which also causes the rainbow's position to change.

The rainbow won't be visible for very long because it will appear to move with you as the train travels along its course. This phenomena also affects other moving objects and landscapes, such as mountains, trees, and buildings, in addition to rainbows.

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A rainbow that you view via a train window while riding will follow you as you travel forward. The rainbow won't be visible for very long because it will appear to move with you as the train travels along its course.

explanation - If you view a rainbow out your window while riding in a train, you'll see that the rainbow moves along with you. As you move forward, the angle between the sun, your eyes, and the raindrops that create the rainbow changes, causing the rainbow to appear to move with you. However, if the train is moving too fast, you may soon pass by it, leaving it where you first saw it. therefore - its position appears relative to the viewer's location and angle of observation, hence option is B

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Trigonometry allows to find the result for the question about the height of the mountain is:

Trigonometry allows finding relationships between the angles of a right triangle.

         \(tan \theta = \frac{y}{x}\)  

Where θ is the angle, y the opposite leg (height) and x the adjacent leg (horizontal distance).

In the attachment we can see a diagram of the system. They indicate that for x  distance the angle is 14.67º  

         tan 14.67 = \(\frac{y}{x}\)  

At the other point the angle is 10.38º.

        tan 10.38 = \(\frac{y}{x+15860}\)

We look for the horizontal distance (x) with these equations.

        x tan 14.67 = (x + 15860) tan 10.38

        x tan 14.67 / tan 10.38 = x + 15860

        x 1,429 = x + 15860

        x 0.429 = 15860

        x = \(\frac{15680}{0.429}\)

        x = 36955.3 ft

We calculate for the height.

        y = x tan 14.67

        y = 36955.3 tan 14.67

        y = 9674.4 ft

In conclusion using trigonometry we can find the result for the height of the mountain is:

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a. The image includes galaxies that are elliptical, spiral, and irregular. b. Careful study of the image shows that the youngest galaxies were mostly irregular in shape.

e. We see the more distant galaxies as they were when they were quite young. c. The galaxies in this image are part of a large galaxy cluster, bound together by gravity is not a true statement. The Hubble Extreme Deep Field image is actually a composite of several images taken over a period of 10 years, capturing light from galaxies as far back as 13 billion years ago, showing a diverse range of galaxies in various stages of formation and evolution, but they are not part of a single galaxy cluster. d. Careful study of the image shows that all present-day galaxies are spirals is also not a true statement. While there are many spiral galaxies present in the image, there are also many elliptical and irregular galaxies, indicating a wide variety of galaxy types throughout the universe.

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It is possible to suspend an object at rest from its center of gravity, and gravity won't induce it to begin rotating no matter how it is positioned.  

Thus, The center of gravity of an object will be located somewhere along a vertical line that passes through the point of suspension if you suspend it from any point and allow it to come to rest.

The gravitational acceleration is (almost) constant near the surface of the earth, where the center of mass also lies.

A place that represents the average or typical location of an object's mass, as if all of the mass were contained there, is known as the center of mass (CM). The geometric center of a uniform sphere serves as its center of mass. The barycenter is another name for the CM.

Thus, It is possible to suspend an object at rest from its center of gravity, and gravity won't induce it to begin rotating no matter how it is positioned.  

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Answer:

31.2m/s

Explanation:

final velocity = initial velocity + acceleration • time

final velocity = 0 m/s + 6.58m/s/s • 4.74 s

final velocity = 31.2 m/s

False. Electric field lines cannot cross each other, regardless of whether the charges involved are positive or negative.
The electric field lines are a visual representation of the electric field created by charges. They indicate the direction and strength of the electric field at various points.

These lines originate from positive charges and terminate at negative charges, following the direction that a positive test charge would experience forces in the field.

The reason that electric field lines cannot cross is that at the point of intersection, there would be two different values for the electric field direction, which is not possible. The electric field has a unique direction at every point in space. If lines crossed, it would imply that a test charge at the crossing point would experience two different forces in different directions simultaneously, which is contradictory to the nature of electric fields.

In summary, electric field lines cannot cross each other, regardless of whether positive or negative charges are involved. This is because the electric field has a unique direction at every point, and crossing lines would result in contradictory information about the electric field's direction and strength.

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Answer:

shown below

Explanation:

1) P = F/A

P = 500 / 0.5

P = 1000N/m²

2) W = mg

W = 50 x 9.8

W = 490

P = F/A

P = 490 / 0.01

P = 49000N/m²

3) P = F/A

For E:

P = 40000 / 0.5

P = 80000N/m²

For W:

P = 600 / 0.0075

P = 80000N/m²

They're exerting the same amount of pressure on the ground

Answer:

they both exert the same pressure

Explanation:

Pressure is the ratio of force to area. It is given as:

\(P=\frac{F}{A}\) ,  where F is the force, P is pressure and A is area

1) For the cuboid, the area of the base placed on the ground (A) = 8 cm × 3 cm = 24 cm² = 0.0024 m². Therefore the pressure is:

\(P=\frac{F}{A}=\frac{60}{0.0024} =25000N/m^2=25KN/m^2\)

2) For the cube, the area of the base placed on the ground (A) = 4 cm × 4 cm = 16 cm² = 0.0016 m². Therefore the pressure is:

\(P=\frac{F}{A}=\frac{40}{0.0016} =25000N/m^2=25KN/m^2\)

Therefore, they both exert the same pressure.

2) all of their motion stops completely

Answer:

a their motion stops completely

Explanation:

Hope this helps :)

Charlotte is driving at a speed of \($63.4 {mi} / {h}$\), and she took her eyes off the road for \($3.31 {~s}$.\) We need to calculate how far she has traveled in feet during this time. Charlotte traveled 308 feet during this time.

To calculate the distance traveled by Charlotte in feet, we can use the formula;\($$distance=velocity×time$$\) First, we will convert the speed from miles per hour to feet per second. We know that;1 mile = 5280 feetand 1 hour = 60 minutes and 1 minute = 60 secondsSo,1 mile = 5280 feet and 1 hour = 60 minutes × 60 seconds = 3600 seconds

Therefore, 1 mile per hour = 5280 feet / 3600 seconds = $1.47 {ft} / {s}$Now, the velocity of the car is;$63.4 {mi} / {h} = 63.4 × 1.47 {ft} / {s} = 93.198 {ft} / {s}Next, we need to calculate the distance covered by the car during the time Charlotte looked at her phone for $3.31 {~s}. Therefore; distance = 93.198 {ft} / {s} × 3.31 {~s} = 308.039 \approx 308 {ft}

Therefore, Charlotte traveled $308 feet during this time.

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Answer:

v = 12.12 m/s      

Explanation:

It is given that,

Radius of circle, r = 30 m

The coefficient friction between tires and road is 0.5,

The centripetal force is balanced by the force of friction such that,

v = 12.12 m/s

So, the maximum speed with which this car can round this curve is 12.12 m/s. Hence, this is the required solution.

The atomic radius of copper is approximately 128 picometers (pm).

The atomic radius of an element is defined as half the distance between the nuclei of two identical adjacent atoms in a molecule. In the case of metallic copper, the copper atoms are arranged in a crystal lattice, and the distance between two adjacent copper atoms in the lattice is known as the interatomic distance or lattice parameter.

We are given that the distance between two adjacent copper atoms in metallic copper is 256 pm. Since this is the distance between the nuclei of two adjacent atoms, the sum of the atomic radii of the two copper atoms is equal to 256 pm.

Therefore, the atomic radius of copper can be calculated as follows:

Atomic radius of Cu = (interatomic distance between adjacent Cu atoms) / 2

Atomic radius of Cu = 256 pm / 2

Atomic radius of Cu = 128 pm

Hence, the atomic radius of copper is approximately 128 picometers (pm).

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Unit of electric field is V/m,where V is Volt and m is meter.Electric field is a vector quantity.

An electric field is the actual field that encompasses electrically charged particles and applies force on any remaining charged particles in the field, either drawing in or repulsing them. It likewise alludes to the actual field for an arrangement of charged particles. Electric fields start from electric charges and time-fluctuating electric flows. Electric fields and attractive fields are the two appearances of the electromagnetic field, one of the four principal communications (likewise called powers) of nature.

The electric field is characterized as a vector field that partners to each point in space the electrostatic (Coulomb) force per unit of charge applied on a tiny positive test charge very still at that point. The determined SI unit for the electric field is the volt per meter (V/m), which is equivalent to the newton per coulomb.

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Answer: divide the output force by the input force

Explanation: your welcome

The mechanical advantage which a simple machine provides can be calculated by dividing the output displacement by the input displacement. Thus, the correct option is B.

The mechanical advantage of a simple machine can be defined as the ratio of output force applied on the object to input force. Mechanical advantage is also the ratio of load overcame by a simple machine to the effort which is applied by that machine. The formula for mechanical advantage of a simple machine is given as:

M.A. = output force / input force

M.A. = Load / effort

Thus, the mechanical advantage of a simple machine depends both on the output force of the simple machine and the input force of the machine.

Therefore, the correct option is B.

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(a) The distance travelled by the object is  100 m.

(b) The displacement of the object in time interval between t = 0 s and t = 10 s is 60 m.

(a) The distance travelled by the object is calculated from the total area of the curve.

total distance = area of triangle 1 + area of triangle 2 + area of rectangle.

total distance = (¹/₂ x base x height)₁ +  (¹/₂ x base x height)₂ + length x width

total distance = (¹/₂ x 6 s x 20 m/s) +  (¹/₂ (8 - 6) 20) + (10 - 0)(10 - 8)

total distance =  60 m + 20 m + 20 m

total distance = 100 m

(b) The displacement of the object in time interval between t = 0 s and t = 10 s is calculated as follows;

displacement = final position - initial position

displacement =  (¹/₂ x base x height)₁ +  (¹/₂ x base x height)₂ + length x width

displacement = (¹/₂ x 6 s x 20 m/s) +  (¹/₂ (8 - 6) (-20)) + (10 - 0)(10 - 8)

displacement = 60 m - 20 m + 20 m = 60 m

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The final speed of the automobile would be 0.193 m/s.  

The decrease in energy of the transferred charge can be calculated using the formula:

ΔE = ∫vdt

here ΔE is the change in energy, v is the velocity of the charge, and t is the time of the transfer. In this case, the potential difference between the cloud and the ground is 1.24 x \(10^9\) V, and the quantity of charge transferred is 39.2 C.

The time of the transfer can be calculated as follows:

t = ΔQ / Q

t = 39.2 C / (1.602 x \(10^{-19\)C)

t = \(2.4 * 10^{-4\) s

The velocity of the charge can be calculated using the formula:

v = Δt / t

v =   \(2.4 * 10^{-4\)m/s

The decrease in energy of the transferred charge can be calculated using the formula:

ΔE = v x Δt

ΔE =  \(2.4 * 10^{-4\) m/s x  \(2.4 * 10^{-4\) s

ΔE = 0.000588 J

Therefore, the decrease in energy of the transferred charge is 0.000588 J.

If all the energy of the transferred charge could be used to accelerate a 1016 kg automobile from rest, the final speed of the automobile would be:

final speed = (Δ\(KE)^{(1/2)\)

here ΔKE is the change in kinetic energy of the automobile. Substituting the given values, we get:

final speed = \((0.000588 J)^{(1/2)\)

final speed = 0.193 m/s

Therefore, the final speed of the automobile would be 0.193 m/s.  

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The potential energy will be 180J

By going through the formula of potential energy that is U=mgh

where, U= Potential energy

m= mass

g= gravitational feild

h= height

Now as per the question,

Initial velocity, u = 6 m/s

Final velocity, v = 0 m/s

Acceleration due to gravity, g = -5 m/s²

(The negative sign implies that the object is moving downwards)

To find the value of Height, we need to use the relation,

v^2 - u^2 = 2gh

0 - 36 = -10h

h = 36/10 m

Height = 18/5 m

therefore, Potential Energy(U) = mgh

                                              = 10 × 5 × 18/5 J

                                              = 180 J

Therefore, the ball will have a potential energy of 180 J when it is at its highest point.

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The Momentum is the product of mass and velocity.

Momentum is a measure of an object's motion. It is defined as the product of an object's mass and its velocity. In physics, momentum is a conserved quantity, which means that the total momentum of a closed system remains constant unless acted upon by an external force.

Final momentum of Ax = 1 * 2 * cos 30 = 1.73 Kgm/s

Final momentum of Ay =  1 * 2 * sin 30 =1 Kg m/s

Final momentum of Bx = 1 * Vs * cos 30

Final momentum of By = 1 * Vy * sin 30

The velocity is then;

1 * 5 + 0 = (1 * 2) + (1 * vs)

5 = 2 + vs

Vs = 3 m/s

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The maximum acceleration will be 1.6m/s^2

Let a1 = 5.0m/s^2

the maximum acceleration of the truck alone. The force produced by the engine to accelerate the truck in this situation is

F = ma1

with m being the mass of the truck alone.

If we attach a bus of twice the mass of the truck, now the whole system (truck+bus) has a mass of (m+2m)=3m. And in this case, the force produced by the engine is

F = 3ma2

with a2 being the new acceleration.

The engine is always the same, so the force produced is still the same, so we can equalize F written in the first equation and in the second equation:

ma1 = 3ma2

and find a2, the new acceleration

a2 = ma1/3

a2 = 5/3 m/s^2

Therefore a2 = 1.6m/s^2

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Answer: Hot air is transferred through heat being radiated from a thermal burner.

The oven absorbs air from the environment and passes it through a thermal resistance (thermal burner) to heat it and then this hot air is the one that cooks the food.

Answer:

he is wronggg

Explanation:

The average rate at which the cable does work is 294,000 J/s.

The given parameters:

The average rate at which the cable does work is calculated as follows;

\(P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{3000 \times 9.8 \times 200}{20} \\\\P = 294,000 \ J/s\)

Thus, the average rate at which the cable does work is 294,000 J/s.

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Answer:

Explanation:

The mass of the object can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

From the question we have

\(m = \frac{44}{15.3} \\ = 2.875816...\)

We have the final answer as

Hope this helps you

Answer:

2.9

Explanation:

In the equation you get 2.88 but you round that to the nearest tenth so you get 2.9

Answer:

thanks for the ok points

Explanation:

please don't delete this

I'm sorry I can't answer your question ok bye

The wavelength of the visible light that is most strongly reflected from a soap bubble with a wall thickness of 290 nm thick is 770 nm, which corresponds to the color red and for wall thickness of 340 nm it is 903 nm, which corresponds to the color violet.

(a) To determine the wavelength of visible light that is most strongly reflected from a point on a soap bubble where its wall is 290 nm thick, we can use the formula for constructive interference in thin films: 2 * thickness * n = m * wavelength

Here wall thickness is 290 nm, n is the index of refraction (1.33), m is the order of interference (we will use m = 1 for the most strongly reflected color), and wavelength is the wavelength of the light in air.

Rearranging the formula to find the wavelength: wavelength = 2 * thickness of wall * n / m
wavelength = 2 * 290 nm * 1.33 / 1
wavelength ≈ 770 nm

This wavelength corresponds to the color red in the visible spectrum.

(b) To determine the wavelength of visible light most strongly reflected for a wall thickness of 340 nm, we can use the same formula:

wavelength = 2 *  thickness of wall * n / m
wavelength = 2 * 340 nm * 1.33 / 1
wavelength ≈ 903 nm

This wavelength corresponds to the color violet in the visible spectrum.

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The minimum voltage required to trigger a digital storage oscilloscope (DSO) to begin displaying a waveform is called the trigger voltage or trigger level.

This voltage threshold can be set by the user and is typically adjusted using a trigger control on the DSO.

A DSO is an electronic device used to capture, display, and analyze signals, typically in the form of voltage over time. It is designed to trigger and capture signals based on certain criteria, such as when the signal reaches a certain voltage level.

This minimum voltage required to trigger the DSO is known as the trigger voltage. The trigger voltage can be set by the user and is usually adjusted using a trigger control. Once the trigger level is reached, the DSO begins capturing the signal and displaying it on its screen.

The trigger voltage is an important parameter to consider when using a DSO. It enables the user to specify when the DSO should begin capturing a signal and helps ensure that only the desired signals are captured and displayed.

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Answer:

1 lb. is 453.592 grams

Explanation:

1lb is 453.592 grams

Waiting until the entire car that was just passed is visible in the rearview mirror is a prudent practice that enhances safety, provides a comprehensive view of the passed vehicle, and promotes smooth traffic flow.

When passing another vehicle, it is important for a driver to exercise caution and ensure a safe maneuver. Waiting until the entire car that was just passed is visible in the rearview mirror before turning back into the right-hand lane is a recommended practice for several reasons.

Firstly, waiting until the entire car is visible in the rearview mirror allows the passing driver to have a clear and complete view of the vehicle they have just overtaken. This ensures that they have accurately judged the distance and speed of the passed car, reducing the risk of a collision when merging back into the right-hand lane.

Secondly, waiting for the entire car to be visible in the rearview mirror provides an additional safety buffer. It allows the passing driver to account for any sudden changes in the passed car's speed or direction, which may not have been apparent during the overtaking maneuver.

Lastly, waiting for the entire car to be visible in the rearview mirror promotes smooth and efficient traffic flow. It minimizes the need for abrupt lane changes or unnecessary merging back into the right-hand lane, reducing the potential for confusion or disruption to other drivers on the road.

In conclusion, waiting until the entire car that was just passed is visible in the rearview mirror is a prudent practice that enhances safety, provides a comprehensive view of the passed vehicle, and promotes smooth traffic flow.

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The types of scales of measurement are important in statistics since they help to decide what statistical measures can be applied to the data. The nominal scale is the least precise scale, while the ratio scale is the most precise scale.

The scales of measurement of variables are defined as the various ways a variable can be measured or described. Below are the answers to the given question: - Eye color (blue, brown, hazel, green) - Nominal scale.- Grade on a test (A, B, C, D, F) - Ordinal scale. - Score on a Likert-type scale (1, 2, 3, 4, 5, 6, 7) - Interval scale. - A person's age measured in years - Ratio scale. - Age classification (infant, child, teen, young adult, adult, older adult) - Ordinal scale.
- Number of correct answers on a test - Ratio scale. - Nominal scale - A scale that describes variables that have distinct categories or names that are used to identify them. - Ordinal scale - A scale that describes variables that have categories that can be ranked in order of importance or magnitude. - Interval scale - A scale that describes variables with continuous and evenly spaced values that have an arbitrary zero point. - Ratio scale - A scale that describes variables with continuous and evenly spaced values that have a meaningful zero point.

The types of scales of measurement are important in statistics since they help to decide what statistical measures can be applied to the data. The nominal scale is the least precise scale, while the ratio scale is the most precise scale.

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Answer:

Mass, M = 4 kilograms.

Explanation:

Given the following data;

Kinetic energy = 50 J

Velocity = 5 m/s

To find the mass of the object;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

\( K.E = \frac{1}{2}MV^{2}\)

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Making mass the subject formula;

\( M = \frac{2K.E}{V^{2}}\)

Substituting into the equation, we have;

\( M = \frac{2*50}{5^{2}}\)

\( M = \frac{100}{25}\)

Mass, M = 4 kg