You will pilot your drone through a series of obstacles. While doing so one of your rescue team members will document the time it takes you to fly from one obstacle to the next. That data will be populated in the following table:

My data table

(position) (distance) (time) (type of maneuver)

(Start to obstacle 1) (13’6”) (9 seconds) (around)

(obstacle 1 to obstacle 2) (31’1”) (20 seconds) (under)

(Obstacle 2 to obstacle 3) (27’3”) (38 seconds) (Precision landing)

(Obstacle 3 to End) (35’6”) (13 seconds) (Precision landing)



You will now present your data using three visual tools. You may create these illustrations using any tools you like Import pictures of your work into this performance task.

I only need someone to do me a graph for Position - Velocity Graph

The approximate number of wavelengths of light that can travel in one direction within a retroreflecting bead that has a diameter of 5 ×\(10^-^5\) m is 167.

This calculation is based on the formula n = L/λ, where n is the number of wavelengths, L is the length of the object, and λ is the wavelength of light. To calculate the wavelength of light, we use the formula c = λf, where c is the speed of light and f is the frequency of light.

In this problem, we are given the diameter of the retroreflecting bead, which is assumed to be spherical. Therefore, its length is equal to its diameter, which is 5 × \(10^-^5\)m. We are also given the speed of light, which is 3 × \(10^8\) m/s, and an approximation of the frequency of light, which is \(10^1^5\) Hz.

Using the formula c = λf, we can solve for the wavelength of light:

λ = c/f = (3 ×\(10^8\) m/s)/\((10^1^5\)Hz) = 3 ×\(10^-^7\)m

Finally, we can use the formula n = L/λ to calculate the approximate number of wavelengths of light that can travel in one direction within the retroreflecting bead:

n = L/λ = (5 ×\(10^-^5\) m)/(3 ×\(10^-^7\) m) = 166.67 ≈ 167

Therefore, the approximate number of wavelengths of light that can travel in one direction within a retroreflecting bead that has a diameter of 5 ×\(10^-^5\) m is 167.

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To describe the graph we need to explain the specific concepts mentioned below:

a. The relationship between variables on a graph refers to how one variable changes in response to the other. This can be positive (both variables increase or decrease together), negative (one variable increases while the other decreases), or no relationship (no discernible pattern between the two variables).

b. A graph can be classified as linear or nonlinear based on the shape of the relationship between the variables. A linear graph forms a straight line, indicating a constant rate of change between the variables. A nonlinear graph has a curve or irregular shape, indicating a variable rate of change between the variables.

c. An example of a graph could be a scatter plot of people's ages (x-axis) and their monthly income (y-axis). If the points form a straight line with a positive slope, it would indicate a linear relationship, meaning that as people's ages increase, their income generally increases as well.

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Here's the fact that you need to know:

"The AREA under a speed/time graph is the distance traveled during the time covered by the graph."

Now ... What's the area of that nice trapezoid on the graph ?

Hint: Area of a trapezoid is

(1/2) • (height) • (base-1 + base-2)

Answer: The  Answer Is A

Explanation:

The approximate radius of the black hole is 2.96 km (approximately) according to Newton's formulation of gravity.

According to Newton's formulation of gravity,

black hole is a region of space with an intense gravitational force that prevents anything, including light, from escaping.

The mass of a black hole determines the strength of its gravitational force.According to Newton's formulation of gravity, the radius of a black hole is given by

r = 2GM/c²

Where:r = radius of the black hole

G = gravitational constant

M = mass of the black holec = speed of light in vacuum

Given that the total mass of the black hole is

1x Mo (where Mo = mass of the Sun), that is, M = Mo = 1.98 × 10³⁰ kg

Therefore,r = 2GM/c²= 2 × 6.67 × 10⁻¹¹ × 1.98 × 10³⁰ / (3 × 10⁸)²= 2.96 × 10³ m= 2.96 km (approx)

The approximate radius of the black hole is 2.96 km (approximately) according to Newton's formulation of gravity.

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Answer:

If you try to lift up a weight in a swimming pool and then try to lift the same weight on the edge of the pool, it feels much lighter in the water.

This was supposed to have been first explained by the Greek scientist Archimedes. He said that the water gives an upward force or upthrust on any object in it.

You can weigh an object in air and then in water and actually work out the upthrust, it is the difference between the two readings. For this reason the upthrust is often called the loss in weight of the object.

Answer:

d. sexual reproduction

Explanation:

A single cell divides to make two cells and these two cells then divide to: we call this process "cell division" and "cell reproduction," and there are two ways cells divide—mitosis and meiosis. This is all part of sexual reproduction.

(a) The mass of the car is approximately X kilograms. (b) The weight of the car is approximately Y newtons.

To find the mass of the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. The formula can be rearranged as follows:

Net force = mass × acceleration

Given that the net force is 5000.0 N and the acceleration is determined by the change in velocity over time, we can convert the final velocity from km/h to m/s:

Final velocity = 95.9 km/h = (95.9 × 1000) m / (60 × 60) s = Z m/s

Using the formula for acceleration:

Acceleration = (Final velocity - Initial velocity) / time

Substituting the values for the final velocity, initial velocity (which is 0 since the car starts from rest), and time (9.9 s), we can solve for the acceleration. Once we have the acceleration, we can rearrange the equation for net force to find the mass of the car.

To calculate the weight of the car, we need to use the equation:

Weight = mass × gravitational acceleration

The gravitational acceleration on Earth is approximately 9.8 m/s². By multiplying the mass of the car (found in the previous step) by the gravitational acceleration, we can determine the weight of the car in newtons.

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Explanation is in the file

tinyurl.com/wpazsebu

Answer: 20

Explanation:

Answer:

Explanation:

W = FΔx so filling in:

12 = F(30) so

F = .4N

Answer:

about 4 km

Explanation:

15 minutes is a quarter of an hour, so you divide 16km by 4 to get your answer

The velocity after 2 seconds is 26 m/s. It takes 11.50 seconds to reach a velocity of 40m/s.

Given the equation s(t) = 6t + 5t²

Let's find the velocity after 2 seconds.

(a) Velocity = (ds)/(dt)

Differentiating s(t) with respect to t, we get; ds(t) / dt = 6 + 10t

At t = 2,ds(t) / dt = 6 + 10t = 6 + 10(2) = 26m/s

Therefore, the velocity after 2 seconds is 26 m/s.

(b) We are to find how long it takes for the velocity to reach 40m/s. We know that the initial velocity of the ball, u = 6m/s. Acceleration = gsinθ = 9.81 x sin (angle of inclination) = 9.81 x 0.3 = 2.943 m/s²From the first equation of motion, v = u + at

We know v = 40m/s, u = 6m/s, a = 2.943m/s² and t is what we are to find, hence the equation becomes;40 = 6 + 2.943(t)t = (40 - 6) / 2.943t = 11.50s

Therefore, it takes 11.50 seconds to reach a velocity of 40m/s.

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Answer:

\(a=0.1\ m/s^2\)

Explanation:

Given that,

Initial velocity, u = 0

Final velocity, v = 2 m/s

Time, t = 20 s

We need to find the acceleration of the swimmer. The acceleration of an object is equal to the change in velocity per unit time. It can be given by :

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{2\ m/s}{20\ s}\\\\a=0.1\ m/s^2\)

So, her average acceleration of the swimmer is \(0.1\ m/s^2\).

Answer:

An unbalanced force can change an object's motion. An unbalanced force acting on a still object could make the object start moving. An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving

Explanation:

hope this helps :)

Answer:

Explanation:

Acceleration is the time rate of change, or the rate, of the velocity. Therefore, the slope y/x of a speed vs time graph would give the acceleration. If the acceleration is said to be positive, the graph would be a straight line that is at a constant increase over time.

The Maximum current in inductor is 0.1681A , where frequency , RMS current , voltage are calculated.

Theory-

Principle-

Calculations-

I=0.552H

v=120 v

k=21.517

w=1m/s

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Answer:

Explanation:

En la historia de la ciencia se han dado auténticas barbaridades. Pruebas con animales que hoy no perdonaría nadie, o investigaciones de conducta con personas como la de la cárcel de Stanford, que se han saldado como una especie de pasado incómodo sobre los límites de la experimentación. Sin embargo, pocos se pueden acercar por su carácter perturbador al denominado experimento de Little Albert o Pequeño Albert: El salvaje intento por probar con un bebé que las fobias pueden ser condicionadas y aprendidas. Y lo que es peor, conseguirlo.

Esta idea surgió de la mente de John Broadus Watson, reconocido padre de la rama conductista de la psicología, que desde 1913 había comenzado a probar en animales sus tesis. Estas bebían directamente del los estudios de Iván Pavlov, fisiólogo ruso que ganó el Nobel en 1904 por sus estudios sobre el sistema digestivo, pero que también sentó precedentes sobre la psicología.

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Answer:

periscope, an optical instrument used in land and sea warfare, submarine navigation, and elsewhere to enable an observer to see his surroundings while remaining under cover, behind armor, or submerged.

Explanation:

The kinetic energy of the system does not change.

When two horseshoe magnets are placed next to each other, then they either attract or repel each other, depending on the position of their poles. if the poles are opposite they attract, if they are same they repel with other.

In case, if the poles of two horseshoe magnets are attracted to each other, indicating poles are opposite to each other. when the magnets are brought together then the work must be done to oppose the magnetic field between poles. This increases the potential energy of the system.

However, the question is about the kinetic energy of the system, which is related to the motion of the objects in the system. In this case, once the magnets are brought together they attract each other, they will have zero potential. Therefore, the kinetic energy will not change.

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Answer:

90

Explanation:

The bottom number on the element is the number of protons and the top number is the total of the protons + neutrons

Given:

Need to find :

Calculation:

Gauss law :- ø = q/Eₒ

1. For small sphere:- ø1 = q/Eₒ

2. For large sphere :- ø2 = q/Eₒ

=> ø1/ø2 = (q/Eₒ)/(q/Eₒ)

=> ø1/ø2 = 1/1

Ratio of flux is 1:1

Eris is an icy object that orbits in the Kuiper Belt and is more massive than Pluto. It is currently considered the largest known dwarf planet in our solar system.

Pluto is a dwarf planet in our Solar System located in the Kuiper Belt, a region of space beyond the orbit of Neptune that is home to many other icy objects. Pluto was discovered in 1930 by American astronomer Clyde Tombaugh, and for several decades it was considered the ninth planet in our Solar System. However, in 2006 the International Astronomical Union redefined the criteria for what constitutes a planet, and Pluto was reclassified as a "dwarf planet."

Pluto is small compared to the other planets in our Solar System, with a diameter of approximately 2,377 kilometers (1,477 miles). It has a highly eccentric orbit that takes it as close as 4.4 billion kilometers (2.7 billion miles) from the Sun at its closest approach (perihelion) and as far as 7.4 billion kilometers (4.6 billion miles) at its furthest distance (aphelion). Pluto's orbit is also tilted at an angle of about 17 degrees to the plane of the Solar System, which is much more inclined than the orbits of the eight planets.

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The frequency of the pendulum swing is changed by a factor of 0.577 Hz.

The frequency of the pendulum swing is inversely proportional to the square root of the mass on a simple pendulum. Therefore, if the mass is tripled, the square root of the mass will be doubled.

The frequency of the pendulum is proportional to the square root of the mass, so if the mass is tripled, the frequency will be halved.

The period of a simple pendulum, T is given by the formula; T= 2π(l/g)¹/²Where; l is the length of the pendulum and g is the acceleration due to gravity.Taking the period of the pendulum to be T1 when the mass is m1, and T2 when the mass is tripled to 3m1;T1 = 2π(l/g)¹/²T2 = 2π(l/3gm1)¹/²The ratio of T2/T1 is;T2/T1 = (2π(l/3gm1)¹/²) / (2π(l/g)¹/²)T2/T1 = (g/3g)¹/²T2/T1 = (1/3)¹/²T2/T1 = 0.577.

This means that when the mass is tripled, the frequency of the pendulum swing is reduced to 0.577 of its original value. Therefore, the frequency of the pendulum swing is changed by a factor of 0.577.

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The change in the frequency of the pendulum swing when you triple the mass of the bob is by a factor of 1, meaning there is no change in frequency.

To answer your question, let's first understand the terms and the relationship between mass and frequency in a simple pendulum. Terms:
1. Bob: The weight at the end of the pendulum.
2. Mass: The amount of matter in an object, in this case, the bob.
3. Frequency: The number of oscillations (back and forth movements) per unit time, usually measured in hertz (Hz).

Now, the frequency (f) of a simple pendulum is given by the formula:

f = (1/2π) × √(g/L)

where g is the acceleration due to gravity (approximately 9.81 m/s²) and L is the length of the pendulum.

As you can see from the formula, the mass of the bob does not affect the frequency of the pendulum swing. Therefore, even if you triple the mass of the bob, the frequency will remain unchanged.

So, the change in the frequency of the pendulum swing when you triple the mass of the bob is by a factor of 1, meaning there is no change in frequency.

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The distance of the screen is 3433.33 mm dimensions of the image are approximately -120 mm (height) by -80 mm (width).

(a) Calculating the distance of the screen (d₂):

\(\frac{1}{d_{2} }\) = \(\frac{1}{f} -\frac{1}{d_{1} }\)

\(\frac{1}{d_{2} }\) = \(\frac{1}{100} -\frac{1}{103}\)

\(\frac{1}{d_{2} }\)= (103 - 100)/(100 × 103)

\(\frac{1}{d_{2} }\)= 3/(100 × 103)

d₂ = (100 ×103)/3 ≈ 3433.33 mm

Therefore, the screen is approximately 3433.33 mm away from the lens.

(b) Calculating the dimensions of the image:

magnification (m) = -d₂/d₁ = h'/h = w'/w

m = -d₂/d₁ = h'/h = w'/w

h' = m × h = -d₂/d₁ × h

h' = (-3433.33 mm / 103 mm) × 36.0 mm ≈ -120 mm

w' = m ×w = -d₂/d₁ × w

w' = (-3433.33 mm / 103 mm) * 24.0 mm ≈ -80 mm

The negative sign indicates that the image is inverted.

Therefore, the dimensions of the image are approximately -120 mm (height) by -80 mm (width).

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Answer:

These deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline). This process is known as thermohaline circulation.

Explanation:

Potential difference of electron which is moving with speed of 5.00×105 m/s is 0.7109 V and Initial kinetic energy is 11.375 × 10∧-20 eV

Potential difference, also known as the external effort required to move a charge from one position to another in an electric field, is said to be the difference with in energy which electric charges have between 2 points in a circuit. Volts are used to measure it. Voltage is another name for potential difference (Pd. ), which is measured in volts (V).

Given -

Speed of electron = 5.00×105 m/s

We know that

K.E = e × V

Potential difference = K.E / e

= 11.375 × 10∧-20 / 1.6 × 10∧-19

= 0.7109 V

Initial kinetic energy = 1/2 ×m × v²

= 1/2 × 9.1×10∧-31 × (5×10∧5)∧2

= 11.375 × 10∧-20 eV

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Answer: ZERO

Explanation:

zero

The acceleration of a car that travels in a straight line at a constant speed of 100 km/h is zero. Average acceleration = (change in velocity)/(time it takes). Since the car's change in velocity is zero, its acceleration is zero.

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(a) The final angular velocity of the flywheel after 3 complete revolutions is 4.96 rad/s.

(b) The time taken for the flywheel to make 3 complete revolutions is 5.93 s.

The final angular velocity of the flywheel after 3 complete revolutions is determined by applying third kinematic equation as shown below;

θ = 2π (rad/rev) x (3 rev) = 18.85 rad

ωf² = ωi² + 2αθ

ωf² = (1.4)² + 2(0.6)(18.85)

ωf² = 24.58

ωf = √24.58

ωf = 4.96 rad/s

The time taken for the flywheel to make 3 complete revolutions is calculated as follows;

ωf = ωi + αt

t = (ωf  - ωi)/α

t = (4.96 - 1.4)/0.6

t = 5.93 s

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