Your client gets a bill from a French vendor for 100 euros on March 1 at an exchange rate of 1.2 dollars to the euro and pays on April 1 at an exchange rate of 1.3 dollars to the euro. What would you see in the Transaction Journal for the bill payment?

Answers

Answer 1

Answer:

The Transaction that to be entered in the Account would be:

Account payable A/c Dr.    130$

     To Bank A/c                              130$

Also,

Profit and Loss A/c Dr.            10$

  To Foreign Exchange Fluctuation loss A/c  10$

Step-by-step explanation:

client received a bill as per question mentioned of 100 Euros on March 1 when the exchange rate is 1 Euro = 1.20 $,

Accordingly the price liable to be paid as on date 1 March is

100 Euro × 1.20= 120 $ .

Further, the client is agreed to pay the amount on the April 1 when the exchange rate stands out at 1.30 $, that specifies that the client now has to pay the extra price due to the exchange rate fluctuation i.e.

(1.30 - 1.20)$ = 0.10$ to the French vendor.

Therefore , the Transaction that to be entered in the Account would be:

Account payable A/c Dr.    130$

     To Bank A/c                              130$

Also,

Profit and Loss A/c Dr.            10$

  To Foreign Exchange Fluctuation loss A/c  10$


Related Questions

3. Is this data linear or nonlinear? Explain how you know.*

3. Is this data linear or nonlinear? Explain how you know.*

Answers

Answer:

Non-linear

Step-by-step explanation:

Not consistently increasing

Use the Richter scale formula R = log (I / I0) to find the magnitude of an earthquake that has the following intensity. (a) 1,000 times that of I0 (b) 100,000 times that of I0

Answers

The magnitude of an earthquake that has the following intensity.

(a) 1,000 times that of I0 , R is 3.

(b) 100,000 times that of I0, R is 5.

What is ritcher scale?

The logarithm of the wave amplitude measured by seismographs is used to calculate the earthquake's Richter magnitude; adjustments are made to account for variations in the distances between different seismographs and the earthquake's epi-centre.

a) I = 1000. I₀

R = log(I / I₀)

= log(1000 I₀ / I₀)

= log(1000)

= log 10³

(i.e., log xⁿ = n log x)

= 3 log 10

R = 3

b) I = 100000 I₀

R = log(I / I₀)

=  log(100000 I₀ / I₀)

= log(100000)

= log 10⁵

(i.e., log xⁿ = n log x)

= 5 log 10

R = 5

The magnitude of an earthquake that has the following intensity.

(a) 1,000 times that of I0 , R is 3.

(b) 100,000 times that of I0, R is 5.

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help me quickly please!!! what is the area of the composite figure if line AB is congruent to line BC which is congruent to line CD which is congruent to line DA which is congruent to DN?
(2pi+28)mm^2
(2pi+32)mm^2
(2pi+40)mm^2
(2pi+48)mm^2

help me quickly please!!! what is the area of the composite figure if line AB is congruent to line BC

Answers

Answer: Choice C. 2pi+40 square mm

======================================================

Work Shown:

Segments AB, BC, CD, DA, and DN are all the same length (4 units)

The semicircle has area of

A = (1/2)*pi*(radius)^2

A = 0.5*pi*2^2

A = 2pi

The square has area of

B = (side length)^2

B = 4^2

B = 16

The trapezoid has area of

C = (height)*(base1+base2)/2

C = (DN)*(CD+MK)/2

C = (4)*(4+8)/2

C = 24

Add up the results of A, B and C to get the total area

A+B+C = 2pi+16+24 = 2pi+40

The total area is 2pi+40 square mm

The area of the figure will be 2π + 40 mm². Then the correct option is C.

What is the area?

The area of a two - dimensional figure is the area that its perimeter encloses. The quantity of unit squares that occupy a closed figure's surface is its region.

The figure is made by semicircle, square, and trapezium. Then the area is given as,

A = Area of a semicircle + Area of square + Area of trapezium

A = (π / 2) x r² + (AB)² + 1/2 x (CD + MK) x DN

A = (π / 2) x 2² + (2 x 2)² + 1/2 x (4 + 8) x 4

A = 2π + 16 + 24

A = 2π + 40 mm²

The area of the figure will be 2π + 40 mm². Then the correct option is C.

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mrs hough is building a raised garden next to her 13.5 ft fence so she only needs fencing to go around the other 3 sides. if the area of the garden is 121.5 sw ft how much fencing does she need

Answers

Mrs. Hough would need 31.5 feet of fencing for the other three sides of the garden.

To calculate the amount of fencing needed for Mrs. Hough's raised garden, we first need to determine the dimensions of the garden.

Since the garden is next to a 13.5 ft fence, we know that one side of the garden is 13.5 ft.

Let's assume the other two sides of the garden have lengths x and y.

The area of the garden is given as 121.5 sq ft, so we have the equation:

x × y = 121.5

To find the dimensions of the garden, we can solve this equation. One possible solution is x = 9 ft and y = 13.5 ft.

Therefore, the dimensions of the garden are 9 ft by 13.5 ft.

Now, to calculate the amount of fencing needed, we add up the lengths of the three sides (excluding the side next to the fence):

Fencing needed = x + y + x = 9 ft + 13.5 ft + 9 ft = 31.5 ft

Mrs. Hough would need 31.5 feet of fencing for the other three sides of the garden.

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The nth term of a series is represented by an=2^n/5^n+1 ⋅n . George correctly applies the ratio test to determine whether the series converges or diverges. Which statement reflects George's conclusion? From the ratio test, r = 0.4. The series diverges.
From the ratio test, r = 0.4. The series converges.
From the ratio test, r = 4. The series converges.
From the ratio test, r = 4. The series diverges.

Answers

Therefore, the correct statement reflecting George's conclusion is "From the ratio test, r = 0.4. The series converges."

The nth term of a series is represented by an=2^n/5^n+1 ⋅n.

George correctly applies the ratio test to determine whether the series converges or diverges.

The ratio test is a method used to check whether a series converges or diverges. The ratio test compares the nth term of a series to the (n + 1)th term of the series.

The ratio test can be applied to series with non-negative terms.  From the given series, The nth term of a series is given by  an=2^n/5^n+1 ⋅n  By applying the ratio test, we get; an+1/an = [2^(n+1)/(5^(n+1) + 1)*(n + 1)] / [2^n / (5^n + 1)*n] an+1/an = [2^(n+1)*n / (5^(n+1) + 1)*n+1] * [(5^n + 1)*n / 2^n] an+1/an = (2n / (5n + 1)) * (5n + 1) / 2an+1/an = n / 5n + 1 Therefore, we have r = lim n→∞ | an+1/an |= lim n→∞ |n/5n+1| = 1/5 < 1 From the ratio test, r = 1/5. Since r < 1, the series converges.

Therefore, the correct statement reflecting George's conclusion is "From the ratio test, r = 0.4. The series converges."

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the ratio of peter's age to richard's age is $5:8.$ the ratio of john's age to peter's age is $7:12.$ none of the three are over $100$ years old. what is the sum of their ages?

Answers

The sum of Peter, Richard, and John's ages is 191.

We know that the ratio of Peter's age to Richard's age is = 5/8 --(i)

The ratio of John's age to Peter's age is = 7/12 --(ii)

Similarly, the ratio of John's age to Richard's age is = (5*7)/(8*12)= 35/96 -(iii)

Using the value of (i),(ii),(iii), we get -

Age of Peter = (5*12)/(8*12) = 60/96

= 60 years of age

Age of John = (7*5)/(12*5) = 35/60

=35 years of age

From the value of (iii), since no one is over 100 years of age, the age of Richard= 96 years of age

Hence the sum of their ages is = 96+35+60

= 191

Therefore, we know that the sum of their ages is 191.

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Find the slope of the line through the given pair of points. (-7, 16), (-18, 18)​

Answers

Answer: -2/11

Step-by-step explanation:

Describe the lines below as parallel,
perpendicular, or neither.

2x - 5y = 25 and y= 5x+3

Answers

Answer:

Neither.

Step-by-step explanation:

First, we write 2x - 5y = 25 in slope-intercept form. That gets us y = 2/5x - 5. Now, we graph both the lines (check the image attached). Parallel means extending in the same direction, everywhere equidistant. Perpendicular means the relationship between two lines that meet at a right angle (90 degrees). As we can see in the screenshot, these lines don't fit any of these categories, so we put "neither."

Describe the lines below as parallel,perpendicular, or neither.2x - 5y = 25 and y= 5x+3

The lines 2x - 5y = 25 and y = 5x + 3 are neither parallel nor perpendicular

What are lines and their slopes?

We know lines have various types of equations, the general type is

Ax + By + c = 0, and the equation of a line in slope-intercept form is

y = mx + b.

Where slope = m and b = y-intercept.

the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.

Equations of two lines are given, They are 2x - 5y = 25 and y = 5x + 3.

Now, Writing them in slope-intercept form,

2x - 5y = 25.

- 5y = - 2x + 25.

y = (2/5)x - 5.

And,

y = 5x + 3.

Now, We know lines parallel to each other have the same slope, and lines perpendicular to each other have a slope that is negative reciprocal of each other.

Therefore the lines y = (2/5)x - 5 and y = 5x + 3 are neither parallel nor perpendicular.

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sin(90° - x) = sqrt3/2

sin(90 - x) = sqrt3/2

Answers

This will help if you don’t know how to use ask
sin(90 - x) = sqrt3/2

ABCD is a parallelogram, E and F are the mid-points of AB and CD respectively. GH is any line intersecting AD, EF and BC at G,P and H respectively. Prove that GP=PH.

Answers

It has been proven that line segment GP is equal to line segment PH below.

What is a parallelogram?

In Mathematics and Geometry, a parallelogram is a geometrical figure (shape) and it can be defined as a type of quadrilateral and two-dimensional geometrical figure that has two (2) equal and parallel opposite sides.

In this context, the statements and justifications to prove that line segment GP is equal to line segment PH include the following:

Point E and point F are the midpoints of line segments AB and CD (Given).

Since points E and F are the midpoints of line segments AB and DC:

AE = EB = AB/2  (definition of midpoint)

DF = FC = DC/2   (definition of midpoint)

AB = CD and AD = BC (opposite sides of a parallelogram are equal).

AE = EB = DF = FC = AB/2 (substitution property).

Since both AEFD and EBCF are parallelograms, we have:

AD║EF║BC

Therefore, P would be the midpoint of GH by line of symmetry:

GP = GH/2 (definition of midpoint)

PH = GH/2 (definition of midpoint)

GP = PH (proven).

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

ABCD is a parallelogram, E and F are the mid-points of AB and CD respectively. GH is any line intersecting

a computer password is required to be 8 characters long. how many passwords are possible if the password requires 1 letter(s) followed by 7 digits (numbers 0-9), where no repetition of any letter or digit is allowed?

Answers

There will be 15724800 computer passwords possible with 1 letter followed by 7 digits without any repetition of letters or digits.

It is given to us that -

A computer password is required to be 8 characters long

The computer password requires 1 letter(s) followed by 7 digits

The 7 digits are from numbers 0-9.

It is also mentioned that there will be no repetition of any letter or digit

We know that,

The total number of English alphabets = 26 (from a-z)

The total number of digits = 10 (from 0-9)

Since it is given that the computer password has

1 letter followed by 7 digits without any repetition of any letters or digits

So, the number of computer passwords that are possible can be -

\(26*10*9*8*7*6*5*4\\= 15724800\)  (1 letter and 7 digits with no repetition)

Thus, 15724800 computer passwords are possible that contains 1 letter followed by 7 digits where no repetition of any letter or digit is allowed.

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use cramer's rule to give the value of x for the solution set to the system of equations
[2x - 3y - 2z = -1 ]
3x - 3y - z = 2
2x - 2y - z = 2
a. x = 2 b. x = 6 c. The system does not have a solution. d. x=4 e. x=7 f. None of the above

Answers

The value of x for the solution set to the given system of equations is approximately -1.615. Thus, the answer is not one of the provided options.

To solve the system of equations using Cramer's Rule, we need to find the determinant of the coefficient matrix and the determinants obtained by replacing the column of the variable we want to solve with the column of constants.

The coefficient matrix A is:

| 2  -3  -2 |

| 3  -3  -1 |

| 2  -2  -1 |

The determinant of A, denoted as |A|, is calculated as follows:

|A| = 2((-3)(-1) - (-2)(-2)) - (-3)(3(-1) - (-2)(2)) + (-2)(3(-2) - (-3)(2))

   = 2(3 - 4) - (-3)(-3 - 4) + (-2)(-6 - (-9))

   = 2(-1) - (-3)(-7) + (-2)(3)

   = -2 + 21 - 6

   = 13

We replace the first column of A with the column of constants and calculate the determinant of this matrix, denoted as |A1|:

|A1| = |-1  -3  -2 |

       | 2  -3  -1 |

       | 2  -2  -1 |

|A1| = (-1((-3)(-1) - (-2)(-2))) - (2(-3(-1) - (-2)(2))) + (2(-3(-2) - (-2)(2)))

    = (-1)(3 - 4) - 2(-3 + 4) + 2(-6 - 4)

    = (-1)(-1) - 2(1) + 2(-10)

    = 1 - 2 - 20

    = -21

|A2| = | 2  -1  -2 |

       | 3   2  -1 |

       | 2   2  -1 |

|A2| = (2(2(-1) - (-2)(2))) - (3(2(-1) - (-2)(2))) + (2(3(-1) - 2(2)))

    = 2(2 + 4) - 3(2 + 4) + 2(3 - 4)

    = 2(6) - 3(6) + 2(-1)

    = 12 - 18 - 2

    = -8

x = |A1| / |A|

  = -21 / 13

  ≈ -1.615

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- Solve for x. 7x + 6 – 5x + 10 = 4 *

Answers

Answer:

x= -6

Step-by-step explanation:

Answer:

X= -6

Step-by-step explanation:

7x+6−5x+10=4

Step 1: Simplify both sides of the equation.

7x+6−5x+10=4

7x+6+−5x+10=4

(7x+−5x)+(6+10)=4(Combine Like Terms)

2x+16=4

2x+16=4

Step 2: Subtract 16 from both sides.

2x+16−16=4−16

2x=−12

Step 3: Divide both sides by 2.

2x/2   =  −12 /2

x=−6

An airplane traveling 450 mph in still air encounters a 50 mph headwind. How long to travel 1200 miles

Answers

"The time taken by the airplane to travel 1200 miles while encountering a 50 mph headwind is 3 hours."

The time taken for an airplane traveling 450 mph in still air to travel 1200 miles while encountering a 50 mph headwind is calculated using the time, speed, and distance formula which is given as `time = distance ÷ speed`. Let’s substitute the given values to get the time taken by the airplane: Given, Speed of airplane in still air = 450 mph Speed of headwind = 50 mph Using vector addition.

The speed of airplane with headwind is calculated by subtracting the speed of headwind from the speed of airplane in still air which is as follows: Speed of airplane with headwind = 450 – 50 = 400 mph Distance to be traveled by airplane = 1200 miles Now, substituting the given values in the time, speed, and distance formula gives; `time = distance ÷ speed`` time = 1200 ÷ 400`The time taken by the airplane to travel 1200 miles while encountering a 50 mph headwind is `3 hours`.

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use green's theorem to find the counterclockwise circulation and outward flux for the field f=(7x−4y)i (9y−4x)j and curve c: the square bounded by x=0, x=4, y=0, y=4.

Answers

The counterclockwise circulation around c is 12 and the outward flux through c is zero.

Green's theorem is a useful tool for calculating the circulation and flux of a vector field around a closed curve in two-dimensional space.

In this case,

we have a field f=(7x−4y)i+(9y−4x)j and

a square curve c bounded by x=0, x=4, y=0, y=4.

To find the counterclockwise circulation, we can use the line integral of f along c, which is equal to the double integral of the curl of f over the region enclosed by c.

The curl of f is given by (0,0,3), so the line integral evaluates to 12.

To find the outward flux, we can use the double integral of the divergence of f over the same region, which is equal to zero since the divergence of f is also zero.

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"27
A polynomial \( P \) is given. Find all zeros of \( P \), real and Complex. Factor \( P \) completely. \[ \begin{array}{l} P(x)=x^{4}+4 x^{2} \\ P(x)=x^{3}-2 x^{2}+2 x \\ P(x)=x^{4}+2 x^{2}+1 \\

Answers

The zeros of the given polynomials are as follows:

1. For \( P(x) = x^4 + 4x^2 \):

  - Real zeros: \( x = 0 \) (multiplicity 2).

  - Complex zeros: None.

2. For \( P(x) = x^3 - 2x^2 + 2x \):

  - Real zeros: \( x = 0 \) (multiplicity 1) and \( x = 2 \) (multiplicity 1).

  - Complex zeros: None.

3. For \( P(x) = x^4 + 2x^2 + 1 \):

  - Real zeros: None.

  - Complex zeros: \( x = i \) and \( x = -i \).

Factorization of the given polynomials:

1. For \( P(x) = x^4 + 4x^2 \):

  \( P(x) \) can be factored as \( P(x) = x^2(x^2 + 4) \).

2. For \( P(x) = x^3 - 2x^2 + 2x \):

  \( P(x) \) cannot be further factored since it is already in its simplest form.

3. For \( P(x) = x^4 + 2x^2 + 1 \):

  \( P(x) \) can be factored as \( P(x) = (x^2 + 1)^2 \).

Explanation and calculation:

1. For \( P(x) = x^4 + 4x^2 \):

  To find the zeros, we set \( P(x) = 0 \) and solve for \( x \):

  \[ x^4 + 4x^2 = 0 \]

  Factoring out a common factor of \( x^2 \), we get:

  \[ x^2(x^2 + 4) = 0 \]

  Setting each factor equal to zero, we have \( x^2 = 0 \) or \( x^2 + 4 = 0 \).

  Solving these equations, we find the real zeros \( x = 0 \) (with multiplicity 2).

2. For \( P(x) = x^3 - 2x^2 + 2x \):

  To find the zeros, we set \( P(x) = 0 \) and solve for \( x \):

  \[ x^3 - 2x^2 + 2x = 0 \]

  Factoring out a common factor of \( x \), we get:

  \[ x(x^2 - 2x + 2) = 0 \]

  Setting each factor equal to zero, we have \( x = 0 \) or \( x^2 - 2x + 2 = 0 \).

  The quadratic equation \( x^2 - 2x + 2 = 0 \) does not have real solutions, so the only real zeros of \( P(x) \) are \( x = 0 \) and \( x = 2 \).

3. For \( P(x) = x^4 + 2x^2 + 1 \):

  To find the zeros, we set \( P(x) = 0 \) and solve for \( x \):

  \[ x^4 + 2x^2 + 1 = 0 \]

  This equation can be recognized as a perfect square trinomial, which can be factored as:

  \[ (x^2 + 1)^2 = 0

\]

  Taking the square root of both sides, we have \( x^2 + 1 = 0 \).

  Solving for \( x \), we find the complex zeros \( x = i \) and \( x = -i \).

The given polynomials have the following zeros:

1. \( P(x) = x^4 + 4x^2 \) has real zeros \( x = 0 \) (multiplicity 2).

2. \( P(x) = x^3 - 2x^2 + 2x \) has real zeros \( x = 0 \) (multiplicity 1) and \( x = 2 \) (multiplicity 1).

3. \( P(x) = x^4 + 2x^2 + 1 \) has complex zeros \( x = i \) and \( x = -i \).

The factored forms of the polynomials are:

1. \( P(x) = x^2(x^2 + 4) \)

2. \( P(x) = x(x^2 - 2x + 2) \)

3. \( P(x) = (x^2 + 1)^2 \)

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can U help me pwz owo

can U help me pwz owo
can U help me pwz owo

Answers

Hey don’t bully I don’t know how to do this sorry :(

The median of the data set below is 3.7. Find the mean
1.1 1.7 2 k 4.3 6.4 7.9 8.6.
Hint: First find the missing values, K. Give an exact answer.

Answers

The missing value, k, is -6.1.To find the missing value, k, we need to determine the number in the data set that corresponds to the median.

The median is the middle value when the data set is arranged in ascending order. Since we have 8 numbers in the data set, the median will be the 4th value when arranged in ascending order.

Given that the median is 3.7, we can determine that the 4th value in the data set is also 3.7.

So, we can rewrite the data set in ascending order:

1.1, 1.7, 2, k, 3.7, 4.3, 6.4, 7.9, 8.6

The mean of a data set is the sum of all the values divided by the number of values.

To find the mean, we need to calculate the sum of all the values. We know that the median is 3.7, so the sum of the data set without the missing value, k, is:

1.1 + 1.7 + 2 + 3.7 + 4.3 + 6.4 + 7.9 + 8.6 = 35.7

Since there are 8 numbers in the data set (including the missing value, k), the sum of all the values including k is:

35.7 + k

To find the mean, we divide the sum by the number of values, which is 8:

Mean = (35.7 + k) / 8

Since we want the mean to be equal to the median, which is 3.7, we can set up the equation:

(35.7 + k) / 8 = 3.7

Now we can solve for k:

35.7 + k = 29.6

k = 29.6 - 35.7

k = -6.1

Therefore, the missing value, k, is -6.1.

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fill in the blank. In a 4x3x2x2 factorial experiment, you have ___ independent variables and potentially ___ main effect hypotheses.
4; 4

Answers

In a 4x3x2x2 factorial experiment, you have 4 independent variables and potentially 4 main effect hypotheses.

The 4 independent variables are represented by the four numbers in the experimental design

(i.e., 4 levels of variable A, 3 levels of variable B, 2 levels of variable C, and 2 levels of variable D).

The potentially 4 main effect hypotheses are one for each independent variable, which states that there is a significant effect of that independent variable on the outcome variable.

Factorial experiment:

A factorial experiment includes multiple factors simultaneously, each consisting of two or more

levels. Many factors simultaneously influence what is studied in a factorial experiment, and

experimenters consider the main effects and interactions between factors.

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Lucy lives in Lowtown. On Saturday she will visit her friend Martha who lives in Midtown, and she
will arrive in time for lunch at 12:30
Her journey will consist of a 10-minute walk to Lowtown station, then a train ride to Midtown
station and finally a bus ride to Martha's house.
Trains leave Lowtown at 06:45 and then every 30 minutes until 21:15, taking 1 hour 20 minutes to
reach Midtown
Buses leave Midtown at 08:00 and then every 20 minutes until 21:00, arriving at Martha's house
12 minutes later
What is the latest time that Lucy can leave home so that she arrives at Martha's house in time for
lunch?

Answers

She will need to leave lowtown at 7:00 to be able to get to Martha house for lunch
Hope this helps

jackie wants to learn more about local college. which of the following is a statistical question jackie could ask?
A. does the collage have art classes
B. what is the address of the college
C. how old are the student's
D. does the collage have a women's soccer team

Answers

the answer to this question is C
Hi! The answer to the question is C. because a statistical question is a question that can be answered by collecting data that vary. The only question that can be proved by data is number C. I hope this helped you, Goodluck :)

If a=4, b=6, and sina=3/5 in triangle abc, then sin b eqauls

Answers

If a=4, b=6, and sina=3/5 in triangle abc, then sin b equals: 9/10

To find sin(b) in triangle ABC, we can use the sine function in a right angle and the given information.

Given:

a = 4

b = 6

sin(a) = 3/5

We know that the sine of an angle in a right triangle is equal to the ratio of the length of the side opposite the angle to the length of the hypotenuse.

In triangle ABC, let's label the side opposite angle a as side c and the hypotenuse as side h.

sin(a) = c / h

Substituting the given values:

3/5 = 4 / h

To solve for h, we can cross-multiply:

3h = 5 * 4

3h = 20

h = 20 / 3

Now, we can use the sine function to find sin(b):

sin(b) = side opposite angle b / hypotenuse

sin(b) = 6 / (20 / 3)

sin(b) = 6 * (3 / 20)

sin(b) = 18 / 20

sin(b) = 9 / 10

Therefore, sin(b) equals 9/10.

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when 50 v is applied to four series resistors, 100 a flows. if r1 is , r2 is , and r3 is , what is the value of r4?

Answers

The value of resistor R4 is 0.5 minus the sum of resistors R1, R2, and R3.

We have,

To find the value of resistor R4, we can use Ohm's Law and the formula for calculating the total resistance in a series circuit.

In a series circuit, the total resistance (R_total) is the sum of the individual resistances:

R_total = R1 + R2 + R3 + R4

We are given that a voltage of 50 V is applied and a current of 100 A flows through the circuit.

Using Ohm's Law (V = I * R), we can calculate the individual voltage drops across each resistor:

V1 = I x R1

V2 = I x R2

V3 = I x R3

V4 = I x R4

Since the voltage across each resistor is equal to the total applied voltage (50 V), we can write the following equations:

V1 + V2 + V3 + V4 = 50

Substituting the voltage values using Ohm's Law:

(I x R1) + (I x R2) + (I x R3) + (I x R4) = 50

Simplifying the equation:

I x (R1 + R2 + R3 + R4) = 50

Substituting the given values for the current (I = 100 A) and resistors R1, R2, and R3:

100 x (R1 + R2 + R3 + R4) = 50

Solving for R4:

R1 + R2 + R3 + R4 = 50/100

R4 = 0.5 - (R1 + R2 + R3)

Therefore,

The value of resistor R4 is 0.5 minus the sum of resistors R1, R2, and R3.

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Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 3y = sin(x).

Answers

The constants a and b that satisfy the differential equation y'' + y' − 3y = sin(x) for the function y = a sin(x) + b cos(x) are a = -1/10 and b = -3/10.

What is the value of the constants a and b

To find constants a and b such that y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 3y = sin(x), we need to differentiate y twice and substitute into the differential equation.

First, we have:

y = a sin(x) + b cos(x)

y' = a cos(x) - b sin(x)

y'' = -a sin(x) - b cos(x)

Substituting into the differential equation, we get:

(-a sin(x) - b cos(x)) + (a cos(x) - b sin(x)) - 3(a sin(x) + b cos(x)) = sin(x)

Simplifying and grouping like terms, we get:

(-a - 3b) sin(x) + (a - 3b) cos(x) = sin(x)

Since sin(x) and cos(x) are linearly independent, their coefficients must be equal. Therefore, we have the following system of equations:

-a - 3b = 0

a - 3b = 1

Solving this system of equations, we get:

a = -1/10

b = -3/10

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Triangle P Q R is shown. Angle Q P R is a right angle. The length of hypotenuse Q R is 14.1 and the length of P R is 12.7. What is the measure of ∠R in △PQR? Round to the nearest degree. 26° 42° 45° 64°

Answers

Answer:

<R = 26degrees

Step-by-step explanation:

Making <R as the reference angle

Adjacent side = 12.7

Hypotenuse = 14.1

Cos <R = adj/hyp

Cos <R = 12.7/14.1

Cos <R = 0.9007

<R = arccos(0.9007)

<R =25.7

<R = 26degrees

Triangle P Q R is shown. Angle Q P R is a right angle. The length of hypotenuse Q R is 14.1 and the length

Answer:

A. 26°

Step-by-step explanation:

I took it on EDG

instructor number of failures prof. a 13 prof. b 0 prof. c 11 prof. d 16 what are the .95 (5 percent risk of type i error) upper and lower control limits for the p-chart?

Answers

The Average proportional failure of the instructors is 0.10

From the question  we are told that

Sample size 100  

Instructor    Number of Failures  

Prof. A         13

Prof. B         0

Prof. C         11

Prof. D         16

Confidence level= 0.95

From Z table

Z=1.96

Generally proportion for failure is mathematically given as

proportion of failure = number of failure/ sample size

Prof A

Pa = 13/100

Pa = 0.13

Prof B

Pb = 0/100 = 0

Prof c

Pc = 11/100 = 0.11

Prof D

Pd = 16/100 = 0.16

Average proportional failure = (0.13 + 0.16 + 0.11 +0)/4 = 0.10

Therefore the Range is 0.0412 to 0.1588

Given the range 0.0412 to 0.1588 Prof B and Prof D are outside the Range making them the correct options

Therefore, the Average proportional failure of the instructors is 0.10

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Points C open parentheses negative 5 comma 8 close parentheses and D open parentheses 2 comma 5 close parentheses lie on line C D. If points C apostrophe and D apostrophe are created by translating points C and D left 6 units, what is the slope of line C apostrophe D apostrophe ?

Answers

We want to find the slope of the line that connects points C' and D'. We will find that the slope is -3/7.

First, we start with the points:

C = (-5, 8)D = (2, 5)

Now we create points C' and D' by translating points C and D to the left by 6 units, this means that we need to subtract 6 in the x-value of each point, so we will have:

C' = (-5, 8) + (-6, 0) = (-5 - 6, 8) = (-11, 8)D' = (2, 5) + (-6, 0) = (2 - 6, 5) = (-4, 5)

And we know that if a line passes through points (x₁, y₁) and (x₂, y₂) the slope is given by:

\(a = \frac{y_2 - y_1}{x_2 - x_1}\)

Then the slope that connects points C' and D' is:

\(a = \frac{5 - 8}{2 - (-5)} = \frac{-3}{7}\)

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Please help! offering 25 points, 5 stars, and a thanks. Ive asked this 3 times now

Please help! offering 25 points, 5 stars, and a thanks. Ive asked this 3 times now

Answers

Answer:

17 quarters

Step-by-step explanation:

Let q = quarters

n = nickels

.25q + .05n = 5.90

we have 16 more nickels than quarters so add 16 quarters to make them equal

n = q+16

Substitute

.25q + .05( q+16) = 5.90

Distribute

.25q+.5q+.80=5.90

Combine like terms

.30q +.8 = 5.90

Subtract .8 from each side

.30q = 5.10

Divide each side by .3

.3q/.3 = 5.1/.3

q = 17

Answer:

Gisel have:

17

quarters

Step-by-step explanation:

1 nickel = 5 cents

1 quarter = 25 cents

1 dollar = 100 cents

5,90 dollars = 5,9*100 = 590 cents

then:

n = t + 16

5n + 25t = 590

n = quantity of nickels

t = quantity of quarters

5(t+16) + 25t = 590

5*t + 5*16 + 25t = 590

5t + 80 + 25t = 590

30 t = 590 - 80

30 t = 510

t = 510 / 30

t = 17

n = t + 16

n = 17 + 16

n = 33

Check:

5n + 25t = 590

5*33 + 25*17 = 590

165 + 425 = 590

i have 12 minutesuntil thisisdue

i have 12 minutesuntil thisisdue

Answers

Answer:

AZ=8

AB=16

Step-by-step explanation:

3x-4=2x

-4=-x

x=4

3x-4

3(4) - 4

12-4

8

I think that the answer is 8

Help me fix this (image attached)

Help me fix this (image attached)

Answers

The value of x from given quadrilateral ABCD is 27°.

In the given quadrilateral ABCD, ∠A=3x+5, ∠B=2x+15, ∠C=4x and ∠D=4x-10.

We know that, the sum of interior angles of quadrilateral is 360°.

Here, ∠A+∠B+∠C+∠D=360°

3x+5+2x+15+4x+4x-10=360°

13x+10=360°

13x=350°

x=350/13

x=26.9

x≈27°

Therefore, the value of x from given quadrilateral ABCD is 27°.

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