Answer:
The Transaction that to be entered in the Account would be:
Account payable A/c Dr. 130$
To Bank A/c 130$
Also,
Profit and Loss A/c Dr. 10$
To Foreign Exchange Fluctuation loss A/c 10$
Step-by-step explanation:
client received a bill as per question mentioned of 100 Euros on March 1 when the exchange rate is 1 Euro = 1.20 $,
Accordingly the price liable to be paid as on date 1 March is
100 Euro × 1.20= 120 $ .
Further, the client is agreed to pay the amount on the April 1 when the exchange rate stands out at 1.30 $, that specifies that the client now has to pay the extra price due to the exchange rate fluctuation i.e.
(1.30 - 1.20)$ = 0.10$ to the French vendor.
Therefore , the Transaction that to be entered in the Account would be:
Account payable A/c Dr. 130$
To Bank A/c 130$
Also,
Profit and Loss A/c Dr. 10$
To Foreign Exchange Fluctuation loss A/c 10$
3. Is this data linear or nonlinear? Explain how you know.*
Answer:
Non-linear
Step-by-step explanation:
Not consistently increasing
Use the Richter scale formula R = log (I / I0) to find the magnitude of an earthquake that has the following intensity. (a) 1,000 times that of I0 (b) 100,000 times that of I0
The magnitude of an earthquake that has the following intensity.
(a) 1,000 times that of I0 , R is 3.
(b) 100,000 times that of I0, R is 5.
What is ritcher scale?
The logarithm of the wave amplitude measured by seismographs is used to calculate the earthquake's Richter magnitude; adjustments are made to account for variations in the distances between different seismographs and the earthquake's epi-centre.
a) I = 1000. I₀
R = log(I / I₀)
= log(1000 I₀ / I₀)
= log(1000)
= log 10³
(i.e., log xⁿ = n log x)
= 3 log 10
R = 3
b) I = 100000 I₀
R = log(I / I₀)
= log(100000 I₀ / I₀)
= log(100000)
= log 10⁵
(i.e., log xⁿ = n log x)
= 5 log 10
R = 5
The magnitude of an earthquake that has the following intensity.
(a) 1,000 times that of I0 , R is 3.
(b) 100,000 times that of I0, R is 5.
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help me quickly please!!! what is the area of the composite figure if line AB is congruent to line BC which is congruent to line CD which is congruent to line DA which is congruent to DN?
(2pi+28)mm^2
(2pi+32)mm^2
(2pi+40)mm^2
(2pi+48)mm^2
======================================================
Work Shown:
Segments AB, BC, CD, DA, and DN are all the same length (4 units)
The semicircle has area of
A = (1/2)*pi*(radius)^2
A = 0.5*pi*2^2
A = 2pi
The square has area of
B = (side length)^2
B = 4^2
B = 16
The trapezoid has area of
C = (height)*(base1+base2)/2
C = (DN)*(CD+MK)/2
C = (4)*(4+8)/2
C = 24
Add up the results of A, B and C to get the total area
A+B+C = 2pi+16+24 = 2pi+40
The total area is 2pi+40 square mm
The area of the figure will be 2π + 40 mm². Then the correct option is C.
What is the area?The area of a two - dimensional figure is the area that its perimeter encloses. The quantity of unit squares that occupy a closed figure's surface is its region.
The figure is made by semicircle, square, and trapezium. Then the area is given as,
A = Area of a semicircle + Area of square + Area of trapezium
A = (π / 2) x r² + (AB)² + 1/2 x (CD + MK) x DN
A = (π / 2) x 2² + (2 x 2)² + 1/2 x (4 + 8) x 4
A = 2π + 16 + 24
A = 2π + 40 mm²
The area of the figure will be 2π + 40 mm². Then the correct option is C.
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mrs hough is building a raised garden next to her 13.5 ft fence so she only needs fencing to go around the other 3 sides. if the area of the garden is 121.5 sw ft how much fencing does she need
Mrs. Hough would need 31.5 feet of fencing for the other three sides of the garden.
To calculate the amount of fencing needed for Mrs. Hough's raised garden, we first need to determine the dimensions of the garden.
Since the garden is next to a 13.5 ft fence, we know that one side of the garden is 13.5 ft.
Let's assume the other two sides of the garden have lengths x and y.
The area of the garden is given as 121.5 sq ft, so we have the equation:
x × y = 121.5
To find the dimensions of the garden, we can solve this equation. One possible solution is x = 9 ft and y = 13.5 ft.
Therefore, the dimensions of the garden are 9 ft by 13.5 ft.
Now, to calculate the amount of fencing needed, we add up the lengths of the three sides (excluding the side next to the fence):
Fencing needed = x + y + x = 9 ft + 13.5 ft + 9 ft = 31.5 ft
Mrs. Hough would need 31.5 feet of fencing for the other three sides of the garden.
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The nth term of a series is represented by an=2^n/5^n+1 ⋅n . George correctly applies the ratio test to determine whether the series converges or diverges. Which statement reflects George's conclusion? From the ratio test, r = 0.4. The series diverges.
From the ratio test, r = 0.4. The series converges.
From the ratio test, r = 4. The series converges.
From the ratio test, r = 4. The series diverges.
Therefore, the correct statement reflecting George's conclusion is "From the ratio test, r = 0.4. The series converges."
The nth term of a series is represented by an=2^n/5^n+1 ⋅n.
George correctly applies the ratio test to determine whether the series converges or diverges.
The ratio test is a method used to check whether a series converges or diverges. The ratio test compares the nth term of a series to the (n + 1)th term of the series.
The ratio test can be applied to series with non-negative terms. From the given series, The nth term of a series is given by an=2^n/5^n+1 ⋅n By applying the ratio test, we get; an+1/an = [2^(n+1)/(5^(n+1) + 1)*(n + 1)] / [2^n / (5^n + 1)*n] an+1/an = [2^(n+1)*n / (5^(n+1) + 1)*n+1] * [(5^n + 1)*n / 2^n] an+1/an = (2n / (5n + 1)) * (5n + 1) / 2an+1/an = n / 5n + 1 Therefore, we have r = lim n→∞ | an+1/an |= lim n→∞ |n/5n+1| = 1/5 < 1 From the ratio test, r = 1/5. Since r < 1, the series converges.
Therefore, the correct statement reflecting George's conclusion is "From the ratio test, r = 0.4. The series converges."
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the ratio of peter's age to richard's age is $5:8.$ the ratio of john's age to peter's age is $7:12.$ none of the three are over $100$ years old. what is the sum of their ages?
The sum of Peter, Richard, and John's ages is 191.
We know that the ratio of Peter's age to Richard's age is = 5/8 --(i)
The ratio of John's age to Peter's age is = 7/12 --(ii)
Similarly, the ratio of John's age to Richard's age is = (5*7)/(8*12)= 35/96 -(iii)
Using the value of (i),(ii),(iii), we get -
Age of Peter = (5*12)/(8*12) = 60/96
= 60 years of age
Age of John = (7*5)/(12*5) = 35/60
=35 years of age
From the value of (iii), since no one is over 100 years of age, the age of Richard= 96 years of age
Hence the sum of their ages is = 96+35+60
= 191
Therefore, we know that the sum of their ages is 191.
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Find the slope of the line through the given pair of points. (-7, 16), (-18, 18)
Answer: -2/11
Step-by-step explanation:
Describe the lines below as parallel,
perpendicular, or neither.
2x - 5y = 25 and y= 5x+3
Answer:
Neither.
Step-by-step explanation:
First, we write 2x - 5y = 25 in slope-intercept form. That gets us y = 2/5x - 5. Now, we graph both the lines (check the image attached). Parallel means extending in the same direction, everywhere equidistant. Perpendicular means the relationship between two lines that meet at a right angle (90 degrees). As we can see in the screenshot, these lines don't fit any of these categories, so we put "neither."
The lines 2x - 5y = 25 and y = 5x + 3 are neither parallel nor perpendicular
What are lines and their slopes?We know lines have various types of equations, the general type is
Ax + By + c = 0, and the equation of a line in slope-intercept form is
y = mx + b.
Where slope = m and b = y-intercept.
the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.
Equations of two lines are given, They are 2x - 5y = 25 and y = 5x + 3.
Now, Writing them in slope-intercept form,
2x - 5y = 25.
- 5y = - 2x + 25.
y = (2/5)x - 5.
And,
y = 5x + 3.
Now, We know lines parallel to each other have the same slope, and lines perpendicular to each other have a slope that is negative reciprocal of each other.
Therefore the lines y = (2/5)x - 5 and y = 5x + 3 are neither parallel nor perpendicular.
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sin(90° - x) = sqrt3/2
ABCD is a parallelogram, E and F are the mid-points of AB and CD respectively. GH is any line intersecting AD, EF and BC at G,P and H respectively. Prove that GP=PH.
It has been proven that line segment GP is equal to line segment PH below.
What is a parallelogram?In Mathematics and Geometry, a parallelogram is a geometrical figure (shape) and it can be defined as a type of quadrilateral and two-dimensional geometrical figure that has two (2) equal and parallel opposite sides.
In this context, the statements and justifications to prove that line segment GP is equal to line segment PH include the following:
Point E and point F are the midpoints of line segments AB and CD (Given).
Since points E and F are the midpoints of line segments AB and DC:
AE = EB = AB/2 (definition of midpoint)
DF = FC = DC/2 (definition of midpoint)
AB = CD and AD = BC (opposite sides of a parallelogram are equal).
AE = EB = DF = FC = AB/2 (substitution property).
Since both AEFD and EBCF are parallelograms, we have:
AD║EF║BC
Therefore, P would be the midpoint of GH by line of symmetry:
GP = GH/2 (definition of midpoint)
PH = GH/2 (definition of midpoint)
GP = PH (proven).
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
a computer password is required to be 8 characters long. how many passwords are possible if the password requires 1 letter(s) followed by 7 digits (numbers 0-9), where no repetition of any letter or digit is allowed?
There will be 15724800 computer passwords possible with 1 letter followed by 7 digits without any repetition of letters or digits.
It is given to us that -
A computer password is required to be 8 characters long
The computer password requires 1 letter(s) followed by 7 digits
The 7 digits are from numbers 0-9.
It is also mentioned that there will be no repetition of any letter or digit
We know that,
The total number of English alphabets = 26 (from a-z)
The total number of digits = 10 (from 0-9)
Since it is given that the computer password has
1 letter followed by 7 digits without any repetition of any letters or digits
So, the number of computer passwords that are possible can be -
\(26*10*9*8*7*6*5*4\\= 15724800\) (1 letter and 7 digits with no repetition)
Thus, 15724800 computer passwords are possible that contains 1 letter followed by 7 digits where no repetition of any letter or digit is allowed.
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use cramer's rule to give the value of x for the solution set to the system of equations
[2x - 3y - 2z = -1 ]
3x - 3y - z = 2
2x - 2y - z = 2
a. x = 2 b. x = 6 c. The system does not have a solution. d. x=4 e. x=7 f. None of the above
The value of x for the solution set to the given system of equations is approximately -1.615. Thus, the answer is not one of the provided options.
To solve the system of equations using Cramer's Rule, we need to find the determinant of the coefficient matrix and the determinants obtained by replacing the column of the variable we want to solve with the column of constants.
The coefficient matrix A is:
| 2 -3 -2 |
| 3 -3 -1 |
| 2 -2 -1 |
The determinant of A, denoted as |A|, is calculated as follows:
|A| = 2((-3)(-1) - (-2)(-2)) - (-3)(3(-1) - (-2)(2)) + (-2)(3(-2) - (-3)(2))
= 2(3 - 4) - (-3)(-3 - 4) + (-2)(-6 - (-9))
= 2(-1) - (-3)(-7) + (-2)(3)
= -2 + 21 - 6
= 13
We replace the first column of A with the column of constants and calculate the determinant of this matrix, denoted as |A1|:
|A1| = |-1 -3 -2 |
| 2 -3 -1 |
| 2 -2 -1 |
|A1| = (-1((-3)(-1) - (-2)(-2))) - (2(-3(-1) - (-2)(2))) + (2(-3(-2) - (-2)(2)))
= (-1)(3 - 4) - 2(-3 + 4) + 2(-6 - 4)
= (-1)(-1) - 2(1) + 2(-10)
= 1 - 2 - 20
= -21
|A2| = | 2 -1 -2 |
| 3 2 -1 |
| 2 2 -1 |
|A2| = (2(2(-1) - (-2)(2))) - (3(2(-1) - (-2)(2))) + (2(3(-1) - 2(2)))
= 2(2 + 4) - 3(2 + 4) + 2(3 - 4)
= 2(6) - 3(6) + 2(-1)
= 12 - 18 - 2
= -8
x = |A1| / |A|
= -21 / 13
≈ -1.615
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- Solve for x. 7x + 6 – 5x + 10 = 4 *
Answer:
x= -6
Step-by-step explanation:
Answer:
X= -6
Step-by-step explanation:
7x+6−5x+10=4
Step 1: Simplify both sides of the equation.
7x+6−5x+10=4
7x+6+−5x+10=4
(7x+−5x)+(6+10)=4(Combine Like Terms)
2x+16=4
2x+16=4
Step 2: Subtract 16 from both sides.
2x+16−16=4−16
2x=−12
Step 3: Divide both sides by 2.
2x/2 = −12 /2
x=−6
An airplane traveling 450 mph in still air encounters a 50 mph headwind. How long to travel 1200 miles
"The time taken by the airplane to travel 1200 miles while encountering a 50 mph headwind is 3 hours."
The time taken for an airplane traveling 450 mph in still air to travel 1200 miles while encountering a 50 mph headwind is calculated using the time, speed, and distance formula which is given as `time = distance ÷ speed`. Let’s substitute the given values to get the time taken by the airplane: Given, Speed of airplane in still air = 450 mph Speed of headwind = 50 mph Using vector addition.
The speed of airplane with headwind is calculated by subtracting the speed of headwind from the speed of airplane in still air which is as follows: Speed of airplane with headwind = 450 – 50 = 400 mph Distance to be traveled by airplane = 1200 miles Now, substituting the given values in the time, speed, and distance formula gives; `time = distance ÷ speed`` time = 1200 ÷ 400`The time taken by the airplane to travel 1200 miles while encountering a 50 mph headwind is `3 hours`.
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use green's theorem to find the counterclockwise circulation and outward flux for the field f=(7x−4y)i (9y−4x)j and curve c: the square bounded by x=0, x=4, y=0, y=4.
The counterclockwise circulation around c is 12 and the outward flux through c is zero.
Green's theorem is a useful tool for calculating the circulation and flux of a vector field around a closed curve in two-dimensional space.
In this case,
we have a field f=(7x−4y)i+(9y−4x)j and
a square curve c bounded by x=0, x=4, y=0, y=4.
To find the counterclockwise circulation, we can use the line integral of f along c, which is equal to the double integral of the curl of f over the region enclosed by c.
The curl of f is given by (0,0,3), so the line integral evaluates to 12.
To find the outward flux, we can use the double integral of the divergence of f over the same region, which is equal to zero since the divergence of f is also zero.
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"27
A polynomial \( P \) is given. Find all zeros of \( P \), real and Complex. Factor \( P \) completely. \[ \begin{array}{l} P(x)=x^{4}+4 x^{2} \\ P(x)=x^{3}-2 x^{2}+2 x \\ P(x)=x^{4}+2 x^{2}+1 \\
The zeros of the given polynomials are as follows:
1. For \( P(x) = x^4 + 4x^2 \):
- Real zeros: \( x = 0 \) (multiplicity 2).
- Complex zeros: None.
2. For \( P(x) = x^3 - 2x^2 + 2x \):
- Real zeros: \( x = 0 \) (multiplicity 1) and \( x = 2 \) (multiplicity 1).
- Complex zeros: None.
3. For \( P(x) = x^4 + 2x^2 + 1 \):
- Real zeros: None.
- Complex zeros: \( x = i \) and \( x = -i \).
Factorization of the given polynomials:
1. For \( P(x) = x^4 + 4x^2 \):
\( P(x) \) can be factored as \( P(x) = x^2(x^2 + 4) \).
2. For \( P(x) = x^3 - 2x^2 + 2x \):
\( P(x) \) cannot be further factored since it is already in its simplest form.
3. For \( P(x) = x^4 + 2x^2 + 1 \):
\( P(x) \) can be factored as \( P(x) = (x^2 + 1)^2 \).
Explanation and calculation:
1. For \( P(x) = x^4 + 4x^2 \):
To find the zeros, we set \( P(x) = 0 \) and solve for \( x \):
\[ x^4 + 4x^2 = 0 \]
Factoring out a common factor of \( x^2 \), we get:
\[ x^2(x^2 + 4) = 0 \]
Setting each factor equal to zero, we have \( x^2 = 0 \) or \( x^2 + 4 = 0 \).
Solving these equations, we find the real zeros \( x = 0 \) (with multiplicity 2).
2. For \( P(x) = x^3 - 2x^2 + 2x \):
To find the zeros, we set \( P(x) = 0 \) and solve for \( x \):
\[ x^3 - 2x^2 + 2x = 0 \]
Factoring out a common factor of \( x \), we get:
\[ x(x^2 - 2x + 2) = 0 \]
Setting each factor equal to zero, we have \( x = 0 \) or \( x^2 - 2x + 2 = 0 \).
The quadratic equation \( x^2 - 2x + 2 = 0 \) does not have real solutions, so the only real zeros of \( P(x) \) are \( x = 0 \) and \( x = 2 \).
3. For \( P(x) = x^4 + 2x^2 + 1 \):
To find the zeros, we set \( P(x) = 0 \) and solve for \( x \):
\[ x^4 + 2x^2 + 1 = 0 \]
This equation can be recognized as a perfect square trinomial, which can be factored as:
\[ (x^2 + 1)^2 = 0
\]
Taking the square root of both sides, we have \( x^2 + 1 = 0 \).
Solving for \( x \), we find the complex zeros \( x = i \) and \( x = -i \).
The given polynomials have the following zeros:
1. \( P(x) = x^4 + 4x^2 \) has real zeros \( x = 0 \) (multiplicity 2).
2. \( P(x) = x^3 - 2x^2 + 2x \) has real zeros \( x = 0 \) (multiplicity 1) and \( x = 2 \) (multiplicity 1).
3. \( P(x) = x^4 + 2x^2 + 1 \) has complex zeros \( x = i \) and \( x = -i \).
The factored forms of the polynomials are:
1. \( P(x) = x^2(x^2 + 4) \)
2. \( P(x) = x(x^2 - 2x + 2) \)
3. \( P(x) = (x^2 + 1)^2 \)
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can U help me pwz owo
The median of the data set below is 3.7. Find the mean
1.1 1.7 2 k 4.3 6.4 7.9 8.6.
Hint: First find the missing values, K. Give an exact answer.
The missing value, k, is -6.1.To find the missing value, k, we need to determine the number in the data set that corresponds to the median.
The median is the middle value when the data set is arranged in ascending order. Since we have 8 numbers in the data set, the median will be the 4th value when arranged in ascending order.
Given that the median is 3.7, we can determine that the 4th value in the data set is also 3.7.
So, we can rewrite the data set in ascending order:
1.1, 1.7, 2, k, 3.7, 4.3, 6.4, 7.9, 8.6
The mean of a data set is the sum of all the values divided by the number of values.
To find the mean, we need to calculate the sum of all the values. We know that the median is 3.7, so the sum of the data set without the missing value, k, is:
1.1 + 1.7 + 2 + 3.7 + 4.3 + 6.4 + 7.9 + 8.6 = 35.7
Since there are 8 numbers in the data set (including the missing value, k), the sum of all the values including k is:
35.7 + k
To find the mean, we divide the sum by the number of values, which is 8:
Mean = (35.7 + k) / 8
Since we want the mean to be equal to the median, which is 3.7, we can set up the equation:
(35.7 + k) / 8 = 3.7
Now we can solve for k:
35.7 + k = 29.6
k = 29.6 - 35.7
k = -6.1
Therefore, the missing value, k, is -6.1.
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fill in the blank. In a 4x3x2x2 factorial experiment, you have ___ independent variables and potentially ___ main effect hypotheses.
4; 4
In a 4x3x2x2 factorial experiment, you have 4 independent variables and potentially 4 main effect hypotheses.
The 4 independent variables are represented by the four numbers in the experimental design
(i.e., 4 levels of variable A, 3 levels of variable B, 2 levels of variable C, and 2 levels of variable D).
The potentially 4 main effect hypotheses are one for each independent variable, which states that there is a significant effect of that independent variable on the outcome variable.
Factorial experiment:A factorial experiment includes multiple factors simultaneously, each consisting of two or more
levels. Many factors simultaneously influence what is studied in a factorial experiment, and
experimenters consider the main effects and interactions between factors.
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Lucy lives in Lowtown. On Saturday she will visit her friend Martha who lives in Midtown, and she
will arrive in time for lunch at 12:30
Her journey will consist of a 10-minute walk to Lowtown station, then a train ride to Midtown
station and finally a bus ride to Martha's house.
Trains leave Lowtown at 06:45 and then every 30 minutes until 21:15, taking 1 hour 20 minutes to
reach Midtown
Buses leave Midtown at 08:00 and then every 20 minutes until 21:00, arriving at Martha's house
12 minutes later
What is the latest time that Lucy can leave home so that she arrives at Martha's house in time for
lunch?
jackie wants to learn more about local college. which of the following is a statistical question jackie could ask?
A. does the collage have art classes
B. what is the address of the college
C. how old are the student's
D. does the collage have a women's soccer team
If a=4, b=6, and sina=3/5 in triangle abc, then sin b eqauls
If a=4, b=6, and sina=3/5 in triangle abc, then sin b equals: 9/10
To find sin(b) in triangle ABC, we can use the sine function in a right angle and the given information.
Given:
a = 4
b = 6
sin(a) = 3/5
We know that the sine of an angle in a right triangle is equal to the ratio of the length of the side opposite the angle to the length of the hypotenuse.
In triangle ABC, let's label the side opposite angle a as side c and the hypotenuse as side h.
sin(a) = c / h
Substituting the given values:
3/5 = 4 / h
To solve for h, we can cross-multiply:
3h = 5 * 4
3h = 20
h = 20 / 3
Now, we can use the sine function to find sin(b):
sin(b) = side opposite angle b / hypotenuse
sin(b) = 6 / (20 / 3)
sin(b) = 6 * (3 / 20)
sin(b) = 18 / 20
sin(b) = 9 / 10
Therefore, sin(b) equals 9/10.
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when 50 v is applied to four series resistors, 100 a flows. if r1 is , r2 is , and r3 is , what is the value of r4?
The value of resistor R4 is 0.5 minus the sum of resistors R1, R2, and R3.
We have,
To find the value of resistor R4, we can use Ohm's Law and the formula for calculating the total resistance in a series circuit.
In a series circuit, the total resistance (R_total) is the sum of the individual resistances:
R_total = R1 + R2 + R3 + R4
We are given that a voltage of 50 V is applied and a current of 100 A flows through the circuit.
Using Ohm's Law (V = I * R), we can calculate the individual voltage drops across each resistor:
V1 = I x R1
V2 = I x R2
V3 = I x R3
V4 = I x R4
Since the voltage across each resistor is equal to the total applied voltage (50 V), we can write the following equations:
V1 + V2 + V3 + V4 = 50
Substituting the voltage values using Ohm's Law:
(I x R1) + (I x R2) + (I x R3) + (I x R4) = 50
Simplifying the equation:
I x (R1 + R2 + R3 + R4) = 50
Substituting the given values for the current (I = 100 A) and resistors R1, R2, and R3:
100 x (R1 + R2 + R3 + R4) = 50
Solving for R4:
R1 + R2 + R3 + R4 = 50/100
R4 = 0.5 - (R1 + R2 + R3)
Therefore,
The value of resistor R4 is 0.5 minus the sum of resistors R1, R2, and R3.
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Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 3y = sin(x).
The constants a and b that satisfy the differential equation y'' + y' − 3y = sin(x) for the function y = a sin(x) + b cos(x) are a = -1/10 and b = -3/10.
What is the value of the constants a and bTo find constants a and b such that y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 3y = sin(x), we need to differentiate y twice and substitute into the differential equation.
First, we have:
y = a sin(x) + b cos(x)
y' = a cos(x) - b sin(x)
y'' = -a sin(x) - b cos(x)
Substituting into the differential equation, we get:
(-a sin(x) - b cos(x)) + (a cos(x) - b sin(x)) - 3(a sin(x) + b cos(x)) = sin(x)
Simplifying and grouping like terms, we get:
(-a - 3b) sin(x) + (a - 3b) cos(x) = sin(x)
Since sin(x) and cos(x) are linearly independent, their coefficients must be equal. Therefore, we have the following system of equations:
-a - 3b = 0
a - 3b = 1
Solving this system of equations, we get:
a = -1/10
b = -3/10
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Triangle P Q R is shown. Angle Q P R is a right angle. The length of hypotenuse Q R is 14.1 and the length of P R is 12.7. What is the measure of ∠R in △PQR? Round to the nearest degree. 26° 42° 45° 64°
Answer:
<R = 26degrees
Step-by-step explanation:
Making <R as the reference angle
Adjacent side = 12.7
Hypotenuse = 14.1
Cos <R = adj/hyp
Cos <R = 12.7/14.1
Cos <R = 0.9007
<R = arccos(0.9007)
<R =25.7
<R = 26degrees
Answer:
A. 26°
Step-by-step explanation:
I took it on EDG
instructor number of failures prof. a 13 prof. b 0 prof. c 11 prof. d 16 what are the .95 (5 percent risk of type i error) upper and lower control limits for the p-chart?
The Average proportional failure of the instructors is 0.10
From the question we are told that
Sample size 100
Instructor Number of Failures
Prof. A 13
Prof. B 0
Prof. C 11
Prof. D 16
Confidence level= 0.95
From Z table
Z=1.96
Generally proportion for failure is mathematically given as
proportion of failure = number of failure/ sample size
Prof A
Pa = 13/100
Pa = 0.13
Prof B
Pb = 0/100 = 0
Prof c
Pc = 11/100 = 0.11
Prof D
Pd = 16/100 = 0.16
Average proportional failure = (0.13 + 0.16 + 0.11 +0)/4 = 0.10
Therefore the Range is 0.0412 to 0.1588
Given the range 0.0412 to 0.1588 Prof B and Prof D are outside the Range making them the correct options
Therefore, the Average proportional failure of the instructors is 0.10
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Points C open parentheses negative 5 comma 8 close parentheses and D open parentheses 2 comma 5 close parentheses lie on line C D. If points C apostrophe and D apostrophe are created by translating points C and D left 6 units, what is the slope of line C apostrophe D apostrophe ?
We want to find the slope of the line that connects points C' and D'. We will find that the slope is -3/7.
First, we start with the points:
C = (-5, 8)D = (2, 5)Now we create points C' and D' by translating points C and D to the left by 6 units, this means that we need to subtract 6 in the x-value of each point, so we will have:
C' = (-5, 8) + (-6, 0) = (-5 - 6, 8) = (-11, 8)D' = (2, 5) + (-6, 0) = (2 - 6, 5) = (-4, 5)And we know that if a line passes through points (x₁, y₁) and (x₂, y₂) the slope is given by:
\(a = \frac{y_2 - y_1}{x_2 - x_1}\)
Then the slope that connects points C' and D' is:
\(a = \frac{5 - 8}{2 - (-5)} = \frac{-3}{7}\)
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Please help! offering 25 points, 5 stars, and a thanks. Ive asked this 3 times now
Answer:
17 quarters
Step-by-step explanation:
Let q = quarters
n = nickels
.25q + .05n = 5.90
we have 16 more nickels than quarters so add 16 quarters to make them equal
n = q+16
Substitute
.25q + .05( q+16) = 5.90
Distribute
.25q+.5q+.80=5.90
Combine like terms
.30q +.8 = 5.90
Subtract .8 from each side
.30q = 5.10
Divide each side by .3
.3q/.3 = 5.1/.3
q = 17
Answer:
Gisel have:
17
quarters
Step-by-step explanation:
1 nickel = 5 cents
1 quarter = 25 cents
1 dollar = 100 cents
5,90 dollars = 5,9*100 = 590 cents
then:
n = t + 16
5n + 25t = 590
n = quantity of nickels
t = quantity of quarters
5(t+16) + 25t = 590
5*t + 5*16 + 25t = 590
5t + 80 + 25t = 590
30 t = 590 - 80
30 t = 510
t = 510 / 30
t = 17
n = t + 16
n = 17 + 16
n = 33
Check:
5n + 25t = 590
5*33 + 25*17 = 590
165 + 425 = 590
i have 12 minutesuntil thisisdue
Answer:
AZ=8
AB=16
Step-by-step explanation:
3x-4=2x
-4=-x
x=4
3x-4
3(4) - 4
12-4
8
Help me fix this (image attached)
The value of x from given quadrilateral ABCD is 27°.
In the given quadrilateral ABCD, ∠A=3x+5, ∠B=2x+15, ∠C=4x and ∠D=4x-10.
We know that, the sum of interior angles of quadrilateral is 360°.
Here, ∠A+∠B+∠C+∠D=360°
3x+5+2x+15+4x+4x-10=360°
13x+10=360°
13x=350°
x=350/13
x=26.9
x≈27°
Therefore, the value of x from given quadrilateral ABCD is 27°.
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