x - 4/3 ≤ 0 is equivalent to x ≥ 4/3, and they both represent the same set of values for x. My friend is correct.
Are the inequalities x ≤ 4/3 and -6x ≤ -8 equivalent?The relationship between two values that are not equal is defined by inequalities.
When we subtract 4/3 from both sides; x ≤ 4/3 can be rewritten as:
x - 4/3 ≤ 0
-6x ≤ -8 can be simplified by dividing both sides by -6 and reversing the inequality which gives:
x ≥ 4/3.
Full question "Your friend says that the inequalities x ≤ 4/3 and -6x ≤ -8 is your friend correct? Explain the reason"
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Rafael has two coupons for a phone.
Coupon A:
Coupon B:
$8 rebate on a $57 phone
20% off of a $57 phone
Choose the coupor that gives the lower price.
Then fill in the blank with the correct value.
Coupon A gives the lower price.
The price with coupon A is $] less than the price with coupon B.
Coupon B gives the lower price.
The price with coupon B is $] less than the price with coupon A.
lol
The circumference of a circle is 91.688 millimeters. what is the radius of the circle? use 3.14 for π. 29.2 mm 183.4 mm 14.6 mm 45.8 mm
Answer:
14.6mm
Step-by-step explanation:
The formula for finding the circumference of a circle is 2πr.
The circumference is 91.688 millimeters inorder to find the radius we have to do the opposite or inverse of multiplication which is division.
So we divide the circumference by 2 and pi which is 3.14 which will give us the radius
r = radius = 91.668 ÷ 3.14 ÷ 2 = 14.6
Answer: its c
Step-by-step explanation:
Suppose that you have $4,000 to invest. Which investment yields the greater return over a 10 year period: 7.22% compounded daily or 7.3% compounded quarterly? Find the total amount of the investment after 10 years if $4,000 is invested at 7.22% compounded daily.
The answer to the question of which investment yields the greater return over a 10-year period is that the investment at 7.22% compounded daily provides a higher return compared to the investment at 7.3% compounded quarterly.
Let's calculate the final amounts for each investment option.
First, let's calculate the final amount for the investment at 7.22% compounded daily:
A = $4,000 * (1 + 0.0722/365)^(365*10)
A = $4,000 * (1.0001986)^(3,650)
A ≈ $6,192.22
Therefore, after 10 years, the investment at 7.22% compounded daily would yield a total amount of approximately $6,192.22.
Now, let's calculate the final amount for the investment at 7.3% compounded quarterly:
A = $4,000 * (1 + 0.073/4)^(4*10)
A = $4,000 * (1.01825)^(40)
A ≈ $6,139.49
Therefore, after 10 years, the investment at 7.3% compounded quarterly would yield a total amount of approximately $6,139.49.
Comparing the results, we can see that the investment at 7.22% compounded daily provides a higher return, with a total amount of approximately $6,192.22, compared to the investment at 7.3% compounded quarterly, which yields a total amount of approximately $6,139.49.
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PLEASE HELP !!!!!!! I do not understand
Answer:
The second set or second one.
Step-by-step explanation:
(-1,1)
(-3,-1)
(-2,-4)
(2,-2)
The negative numbers becomes positive
The positive numbers becomes negative, if you compare the coordinates, before & after.
Hope this helps!
!!! HELP 20 PTS!!! Need help
Answer: 3ad^3
Step-by-step explanation: they have the same terms
If a segment is drawn perpendicular to a line, the point of intersection is called the ____ of the perpendicular.
Answer: Foot
Step-by-step explanation:
The point of intersection is called the foot of the perpendicular. I remember learning this in my Math class!
this is all my points
Mr. Torrey draws and labels a figure, as shown below. He asks a group of students to each
write an expression that is equivalent to the perimeter of the figure in terms of the given
side lengths.
The students’ expressions are shown below.
Brian: 8(2r + s)
Marissa: 2(4r) + 2(4s)
Clara: 2(5r + 3r) + 4(2s)
Alex: 24 × r × s
Part A
Which expressions are equivalent to the perimeter of the figure? List all of the correct
expressions. Show how you know the correct expressions are equivalent to each other.
Part B
Hanif says that 2(4s) + 4(3r) is also equivalent to the perimeter of the figure.
Is Hanif correct? Justify your answer by substituting values for r and s.
Step-by-step explanation:
your answer would be 685 that's your answer
Answer:
dont mind me im just trying get points, since this question already got answered. :)
Step-by-step explanation:
What is square root raised cosine?
SRRC is a pulse shaping filter used in digital communications to minimize intersymbol interference and improve the signal-to-noise ratio.
The square root raised cosine (SRRC) is a famous heartbeat molding channel utilized in computerized correspondences, especially in applications like advanced tweak and demodulation. It is intended to limit intersymbol obstruction (ISI) by restricting the data transmission of the sent sign while keeping a consistent envelope.
The SRRC channel is described by a reaction that is like the raised cosine channel, yet with a square root capability applied to the recurrence reaction. This outcomes in a smoother change between the passband and stopband, which assists with decreasing ISI and work on the sign to-clamor proportion.
The SRRC channel is usually utilized in correspondence frameworks that utilization quadrature sufficiency regulation (QAM) or stage shift keying (PSK) tweak plans, as it gives great ghastly control and heartbeat molding properties that are appropriate to these kinds of signs.
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How do I find the slope of the line?
Answer:
The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points.
Step-by-step explanation:
yeah
Answer:
Pick two points on the line and determine their coordinates. Determine the difference in y-coordinates of these two points (rise). Determine the difference in x-coordinates for these two points (run). Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).
I don't know if you want an example?
A base is labeled on the triangle below. B. C 7 * base Which line segment shows the height that corresponds to the given base of the triangle?
Answer: A
Step-by-step explanation:
Looks like A, since it's the altitude.
Please help with the two files below. Will give brainliest and 20 points. 10 points for each question.
Answer:
x = 108°∠BAC = 54°Step-by-step explanation:
There are a couple of angle relations that apply to these problems.
the measure of an arc is the same as the measure of the central angle it subtendsthe angle where chords cross is the average of the two arcs subtended.1.The measure of arc BC is given as 108°. The measure of central angle BXC is the same:
x = 108°
2.Angle BAC is the average of arcs BC and DF:
(BC +DF)/2 = BAC
((12x +15) +(9x -12))/2 = (10x +4)
Multiplying by 2 and collecting terms gives ...
21x +3 = 20x +8
x = 5 . . . . . . . . . . subtract 20x+3
∠BAC = 10x +4 = 10(5) +4
∠BAC = 54°
Question 5
Given the sequence, 35, 32, 29, 26, 23, ...
Find the following:
a1 =
Answer:
a1 = 2
Step-by-step explanation:
what does a1 mean?
35, 32 29, 26, 23, 20 , 17, 14, 11, 8, 5, (2)
a not-so-enthusiastic student has a predictable pattern for attending class. if the student attends class on a certain friday, then she is 2 times as likely to be absent the next friday as to attend. if the student is absent on a certain friday, then she is 4 times as likely to attend class the next friday as to be absent again. what is the long run probability the student either attends class or does not attend class? g
Therefore, the probability that the student attends class on a certain Friday is 1/2, and the probability that the student is absent is also 1/2. The long-run probability that the student either attends class or does not attend class is simply 1, since these are the only two possible outcomes.
Let's use A to represent the event that the student attends class on a certain Friday, and let's use B to represent the event that the student is absent on a certain Friday. We are asked to find the long-run probability that the student either attends class or does not attend class.
We can use the law of total probability and consider the two possible scenarios:
Scenario 1: The student attends class on a certain Friday
If the student attends class on a certain Friday, then the probability that she will attend class the next Friday is 1/3, and the probability that she will be absent is 2/3. Therefore, the probability that the student attends class on two consecutive Fridays is:
P(A) * P(A|A) = P(A) * 1/3
Scenario 2: The student is absent on a certain Friday
If the student is absent on a certain Friday, then the probability that she will attend class the next Friday is 4/5, and the probability that she will be absent again is 1/5. Therefore, the probability that the student is absent on two consecutive Fridays is:
P(B) * P(A|B) = P(B) * 4/5
The probability that the student attends class or is absent on a certain Friday is 1, so we have:
P(A) + P(B) = 1
Now we can solve for P(A) and P(B) using the system of equations:
P(A) * 1/3 + P(B) * 4/5 = P(A) + P(B)
P(A) + P(B) = 1
Simplifying the first equation, we get:
2/3 * P(B) = 2/3 * P(A)
P(B) = P(A)
Substituting into the second equation, we get:
2 * P(A) = 1
P(A) = 1/2
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System A is configured with 2 components with same reliability in series arrangement. Whereas System B is configured with 5 components with same reliability in parallel arrangement. Suppose the reliability of each components in the systems is 0.86. (i) Find the reliability of the System A and System B. Then find the reliability of a new system, System C if the system is configured by combinations of System A and System B in series arrangement. Write your answer in 5 decimal places. (ii) Find the reliability of another new system, System D if the system is configured by combinations of System A and System B in parallel arrangement. Recommend the best new system. Write your answer in 5 decimal places. (b) From past record it known that the population mean and standard deviation is equal to 15 and 2.5 respectively. To do a right-tailed tests 50 sample be chosen randomly and the sample mean found was equal to 15.50. (i) Test the hypothesis if the rejection region level is 1.6449. (ii) Then find the probability of making Type I error. (iii) Find the probability of making Type II error for this test if the population mean changed to 16 .
(i) The reliability of System A is 0.7396. The reliability of System B is 0.99991. The reliability of System C is 0.64325. The reliability of System D is 0.99991. (ii) The best new system would be System D, as it has the highest reliability of 0.99991.
(i) For System A, the reliability in a series arrangement is given by the product of the individual component reliabilities. Therefore, the reliability of System A is (0.86)*(0.86) = 0.7396.
For System B, the reliability in a parallel arrangement is given by the complement of the probability that all components fail. Since the components are independent, the reliability of System B is 1 - (1-0.86)^5 = 0.99991.
To find the reliability of System C, which is a series arrangement of System A and System B, we multiply their reliabilities: 0.7396 * 0.99991 = 0.64325.
To find the reliability of System D, which is a parallel arrangement of System A and System B, we use the same formula as for System B: 1 - (1-0.7396)*(1-0.99991)^5 = 0.99991.
(ii) The probability of making a Type I error is equal to the significance level, which is given as 1.6449. Therefore, the probability of making a Type I error is 0.05.
(iii) To find the probability of making a Type II error, we need additional information such as the sample size, the population standard deviation, and the desired significance level. Without these details, we cannot determine the probability of making a Type II error for this test.
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A dishonest shopkeeper uses a weighing machine which 900g as 1kg. If cost of per kg sugar is rs.40. How more money did the shopkeeper earned by selling 3kg sugar to the customer?
The dishonest shopkeeper used a weighing machine that considers 900 grams as 1 kilogram. By selling 3 kilograms of sugar, they earned Rs. 12 more than they should have.
In this problem, the dishonest shopkeeper used a weighing machine that takes 900 grams as 1 kilogram. Therefore, if a customer bought 1 kilogram of sugar, the shopkeeper would only give them 900 grams of sugar. However, the cost per kilogram of sugar is Rs. 40.
To find out how much more money the shopkeeper earned by selling 3 kilograms of sugar to the customer, we need to first find out how much sugar the customer actually received for 3 kilograms. The customer would have actually received 2.7 kilograms of sugar because the shopkeeper's weighing machine takes 900 grams as 1 kilogram.
So, the total cost of 2.7 kilograms of sugar would be (2.7 x 40) Rs. 108. The shopkeeper would have earned Rs. 12 more by using this dishonest method to sell 3 kilograms of sugar. This is because the shopkeeper would have sold 3 kilograms of sugar at the rate of 40 Rs./kg whereas the customer only received 2.7 kilograms of sugar.
Therefore, the shopkeeper earned Rs. 12 more than they should have by using this method.
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At a sale, the price of a washing machine
was reduced by 12% to $440. What was the original price of the washing machine?
Answer:
$500
Step-by-step explanation:
100-12=88
88/100=440/x
88x=100(440)
88x=44000
/88. /88
x=500
hopes this helps
Find the minimum value of the following equation:
(Please provide detailed explanations, no links)
Answer:
×=11
Step-by-step explanation:
2×-4×+27-5=0
-2×+22=0
-2×=-22
×=11
Use ab and b=24 to work out the value of these Questions
a) a+b =
b) ab=
c) b/a=
d) (a+b) to the power of 2=
#a
a+b
Insert the value=a+24(b)
#b
ab
=a(b)
Put the value=a*24
#c
b/a
Put the value=24/a
#d
(a+b) to the power of 2
Power means exponent (^)=(a+b)^2
Put the value=(a+24)²
=a²+576
Answer:
a) a + 24
b) 24a
c) 24/a
d) a² + 576
Step-by-step explanation:
Given that,
→ b = 24
a) Solution :
→ a + b
→ a + 24
b) Solution:
→ ab
→ a × 24
→ 24a
c) Solution:
→ b/a
→ 24/a
d) Solution:
→ (a + b)²
→ (a +24)²
→ a² + 576
(refer to figure 26, area 2.) the visibility and cloud clearance requirements to operate vfr during daylight hours over the town of cooperstown between 1,200 feet agl and 10,000 feet msl are
The visibility requirement is 3 statute miles, and cloud clearance requires maintaining 500 feet below, 1,000 feet above, and 2,000 feet horizontally from clouds during VFR daylight operations over Coopers Town.
Determine how to find the visibility and cloud clearance requirements to operate VFR?The visibility and cloud clearance requirements to operate VFR during daylight hours over the town of Coopers Town between 1,200 feet AGL and 10,000 feet MSL are as follows:
1. Visibility: The minimum visibility required is 3 statute miles.
2. Cloud clearance: Maintain a distance of at least 500 feet below, 1,000 feet above, and 2,000 feet horizontally from clouds.
According to VFR regulations, pilots flying during daylight hours must adhere to certain visibility and cloud clearance requirements for safety. The visibility requirement of 3 statute miles means that the pilot must have a clear horizontal view of at least 3 miles ahead.
This ensures sufficient visual reference to navigate and avoid other aircraft or obstacles.
Regarding cloud clearance, pilots must maintain a safe distance from clouds to ensure visibility and separation from potential hazards. The requirement is to remain at least 500 feet below clouds to avoid inadvertently entering them.
Additionally, pilots must maintain a minimum of 1,000 feet above clouds to prevent the risk of collision or reduced visibility due to cloud turbulence. Lastly, a horizontal separation of 2,000 feet from clouds helps ensure adequate maneuvering space and visual reference in relation to cloud formations.
These visibility and cloud clearance requirements help maintain safety and situational awareness for VFR operations during daylight hours over Coopers Town.
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Which is the best estimate of the difference between 6 7 8 678 and 2 1 8 218
Answer: C.5
Step-by-step explanation:
A painter will paint n walls with the same size andshape in a building using a specific brand of paint.The painter’s fee can be calculated by the expressionnKlh, where n is the number of walls, K is aconstant with units of dollars per square foot, l isthe length of each wall in feet, and h is the height ofeach wall in feet. If the customer asks the painter touse a more expensive brand of paint, which of thefactors in the expression would change?A) hB) lC) KD) n
K is the only factor that will change if the customer asks for a more expensive brand of paint.
The correct option is C.
What is geometrical figure?The figures used to represent geometric shapes in mathematics are those that show how commonplace items are shaped. Shapes are the outlines of objects in geometry that have surfaces, angles, and boundary lines.
According to the given information:n = number of walls
K = units of $/ft²
L = length of each wall in feet
h = height of each wall in feet
This equation shows that A and h will be used to determine the area of each wall.
The variable n is the number of walls,
n times the area of the walls will give the amount of area that will need to be painted.
The only remaining variable is K.
This represents the cost per square foot and is determined by the painter’s time and the price of paint.
K is the only factor that will change if the customer asks for a more expensive brand of paint
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What is the slope of the line on the graph?
Answer:
1/2
Step-by-step explanation:
The perimeter of the rectangle is 10. Find the value of x.
Answer:
Hi! Is there a picture?
Step-by-step explanation:
Answer:
The area equation to solve becomes \displaystyle x(x-4)=96, or \displaystyle x^{2}-4x-96=0. To factor, find two numbers the sum to -4 and multiply to -96. -12 and 8 will work: x2 ...
Someone please help me with these or at least tell me how it works
If the perimeter of RSTU is 72 and RV = 16,
find RT and UV
A diagram is provided, on which R S T U's perimeter is 72 and R V's is 16, RT= 32 and UV ≈ 8.2.
How to find the perimeter calculation?A diagram is provided, on which R S T U's perimeter is 72 and R V's is 16.
Finding R T and U V is our goal.
First, let's assume that the figure RSTU is a rhombus since its perimeter and one-half of a diagonal's length are both provided. RT is the result of adding the segments RV and VT.
RT=RV + VT
We are informed that the RV is sixteen. If RV and VT are congruent, then V T equals 16. So:
R T = 16 + 16 = 32
In order to determine the UV length, we must first determine the RU length. Since a rhombus's sides are the same length, we can divide its perimeter by four to determine
RU= Perimeter/ 4
If we simplify and replace Perimeter with 72, we get:
RU = 72 / 4
RU =18
Since UB is a member of the right triangle RUV created by the intersection of the diagonals, we can now use the Pythagorean theorem to determine its length. So:
U V²+ R V² = RU²
If R V = 16 and R U = 18, we obtain:
U V² + 16 ²= 18²
By way of summary, we have:
U V² + 256 = 324
U V² + 256 − 256 = 324 − 256
√ UV = √ 68
UV = 8.2462
UV ≈ 8.2
Our recommendations are as follows:
RT= 32
UV ≈ 8.2.
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URGENT: Which of the following shows the polynomial below written in descending order?
4x^2 - x + 8x^6 + 3 + 2x^10
A. 2x^10 + 4x^2 - x + 3 + 8x^6
B. 2x^10 + 8x^6 + 4x^2 - x + 3
C. 3 + 2x^10 + 8x6 + 4x^2 - x
D. 8x^6 + 4x^2 + 3 + 2x^10 - x
3. A leaking tap drips water at 0,5 ml/sec. Convert this rate to l/h.
Answer: 1.8 L/h
Step-by-step explanation:
To convert the rate of water dripping from a tap from millilitres per second (ml/sec) to litres per hour (L/h), we need to use conversion factors.
Step 1:
First, let's convert the rate from millilitres per second to litres per second.
There are 1000 millilitres in a litre, so we can divide the rate in millilitres per second by 1000 to get the rate in litres per second:
\(\LARGE \boxed{\textsf{0.5 ml/sec $\div$ 1000 = 0.0005 L/sec}}\)
Step 2:
We can convert the rate from litres per second to litres per hour. There are 3600 seconds in an hour, so we can multiply the rate in litres per second by 3600 to get the rate in litres per hour:
\(\LARGE \boxed{\textsf{0.0005 L/sec $\times$ 3600 = 1.8 L/h}}\)
Therefore, the rate of water dripping from the tap is 1.8 L/h.
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Present two different types of data, or variables, used in the health field. Examples could be blood pressure, temperature, pH, pain rating scales, pulse oximetry, % hematocrit, minute respiration, gender, age, ethnicity, etc.
Classify each of your variables as qualitative or quantitative and explain why they fall into the category that you chose.
Also, classify each of the variables as to their level of measurement--nominal, ordinal, interval or ratio--and justify your classifications.
Which type of sampling could you use to gather your data? (stratified, cluster, systematic, and convenience sampling)
In the health field, two different types of data or variables commonly used are qualitative and quantitative. Qualitative variables include gender, ethnicity, and pain rating scales, while quantitative variables include blood pressure, temperature, and age. These variables are classified based on their nature and level of measurement.
Qualitative variables are non-numerical in nature and describe characteristics or qualities. Examples like gender and ethnicity fall into this category because they represent attributes or categories that cannot be measured numerically. On the other hand, quantitative variables are numerical and represent quantities or measurements. Variables such as blood pressure, temperature, and age can be assigned numerical values and fall under this category.
In terms of the level of measurement, variables can be classified as nominal, ordinal, interval, or ratio. Nominal variables represent categories or groups without any inherent order. Examples like gender and ethnicity are nominal variables. Ordinal variables have a natural order or ranking, but the differences between values may not be equal. Pain rating scales can be considered ordinal variables since they have different levels of pain, but the difference between the levels may not be consistent. Interval variables have a consistent measurement scale with equal intervals between values, such as temperature. Finally, ratio variables have a true zero point and can be measured in ratios, such as age.
To gather data, different sampling techniques can be used depending on the research objectives and resources available. Stratified sampling involves dividing the population into distinct subgroups or strata and selecting samples from each stratum. Cluster sampling involves dividing the population into clusters or groups and selecting entire clusters at random. Systematic sampling involves selecting every nth element from a population list. Convenience sampling involves selecting the most readily available individuals. The choice of sampling technique will depend on factors such as the population size, homogeneity of subgroups, and feasibility of accessing the sample population.
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Given the side lengths, determine if the triangle is acute, obtuse, right, or not a triangle. 3.4, 3.3, 2.4
A sum of 60, 000/=was lent at simple interest and at the end of1 year and 8 months the total amount was 70, 000/=determine the rate of interest per annum
we know that a year has 12 months, so 1 year plus 8 more moths will be (12+8)/12 or 20/12 years, or 5/3 year.
\(~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$70000\\\ P=\textit{original amount deposited}\dotfill & \$60000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\to \frac{20}{12}\dotfill &\frac{5}{3} \end{cases} \\\\\\ 70000=60000[1+(\frac{r}{100})(\frac{5}{3})]\implies \cfrac{70000}{60000}=1+(\frac{r}{100})(\frac{5}{3})\)
\(\cfrac{7}{6}=1+\cfrac{5r}{300}\implies \cfrac{7}{6}=1+\cfrac{r}{60}\implies \cfrac{7}{6}-1=\cfrac{r}{60}\implies \cfrac{1}{6}=\cfrac{r}{60} \\\\\\ \cfrac{60}{6}=r\implies 10=r\)