Your new job pays you $18/hr and your first gross pay is $936. How many hours did you work that week?​

Moving average = (5,334 + 5,953 + 6,201) / 3, Moving average ≈ 5,829.3 (rounded to one decimal place). Since it is not provided in the given data, we cannot calculate these scores.

Step 1:

To calculate the three-period moving average for the next time period, we take the average of the profits from the previous three months:

Moving average = (5,334 + 5,953 + 6,201) / 3

Moving average ≈ 5,829.3 (rounded to one decimal place)

Step 2:

To calculate the MAD, MSE, and MAPE scores for the three-period moving average, we need the actual values for the next time period. Since it is not provided in the given data, we cannot calculate these scores.

Step 3:

To determine the exponentially smoothed forecast for the next time period using a smoothing constant α of 0.35, we use the formula:

Forecast = Previous period's forecast + α * (Actual - Previous period's forecast)

Here, the previous period's forecast is the last available profit value (6,024), and the actual value is not given. Therefore, we cannot calculate the exponentially smoothed forecast.

Step 4:

Similarly, without the actual values for the next time period, we cannot calculate the MAD, MSE, and MAPE scores for the exponentially smoothed forecast.

Step 5:

Since we were unable to calculate the MAPE scores for both forecasts, we cannot determine which forecast is best based on the MAPE scores.

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Answer:

Step-by-step explanation:

1.you are supposed the most recent 3 to calculate the three period moving average so it would go as follows: 6024+6312+7519/3=6618.3333 rounded to 6618.3

2.n/a

3. 6218.4

4.MAD       MSE                         MAPE

 521.23481 554624.05283 8.46559%

5.Exponential smoothing, because the MSE score is the lowest.

To determine the coordinates of the vertices of the reflected figure, we can use a reflection matrix that represents reflection over the x-axis. The reflection matrix is:

\(\sf\:\begin{bmatrix} 1 & 0 \\ 0 & -1 \\ \end{bmatrix} \\\)

Let's apply this reflection matrix to each vertex of the triangle RST to find the coordinates of the reflected vertices:

For vertex R(-3, 7):

\(\sf\:\begin{bmatrix} 1 & 0 \\ 0 & -1 \\ \end{bmatrix} \begin{bmatrix} -3 \\ 7 \\ \end{bmatrix} = \begin{bmatrix} -3 \\ -7 \\ \end{bmatrix} \\\)

So the reflected coordinates for vertex R are (-3, -7).

For vertex S(5, 3):

\(\sf\:\begin{bmatrix} 1 & 0 \\ 0 & -1 \\ \end{bmatrix} \begin{bmatrix} 5 \\ 3 \\ \end{bmatrix} = \begin{bmatrix} 5 \\ -3 \\ \end{bmatrix} \\\)

So the reflected coordinates for vertex S are (5, -3).

For vertex T(6, -5):

\(\sf\:\begin{bmatrix} 1 & 0 \\ 0 & -1 \\ \end{bmatrix}\begin{bmatrix} 6 \\ -5 \\ \end{bmatrix} = \begin{bmatrix} 6 \\ 5 \\ \end{bmatrix} \\\)

So the reflected coordinates for vertex T are (6, 5).

Now, let's graph the pre-image (triangle RST) and the image (reflected triangle) on the same coordinate grid:

Pre-image (Triangle RST):

Image (Reflected Triangle):

You can plot these points on a coordinate grid and connect them to form the triangles.

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\textcolor{red}{\underline{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Answer:

14m + 5

Step-by-step explanation:

Answer:

14m+5

Step-by-step explanation

combining like terms when you add

11m + 3m

and

1 + 4

Answer:

12.04

Step-by-step explanation:

the distance between two points in the x-axis

15-3 = 12

the distance between two points in the y-axis

7-6=1

using Pythagorean theory

a²+b²=c²

12²+1²=c²

144+1=c²

145=c²

√145=√c²

12.04=c

The distance of the hiker of a linear function.

The true statement is (d) The y-intercept is (0, 2), and the 2 represents the number of miles  from the car at the start of this time period.

From the graph, we can see that the graph crosses the y-axis at: (0,2)

This means that, the y-intercept is (0,2), and 2 represents the number of miles, he started with.

Hence, the correct statement is (d)

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The probability of the family having 8 girls is very small, as it is 1/256. This is equivalent to the chance of flipping a coin with heads 8 times in a row.

The probability of a family having 8 girls is incredibly low. This is because the probability of each child being a girl is the same as the probability of each child being a boy, so the odds of all 8 children being girls is 1/2 to the power of 8, or 1/256. This is equivalent to the odds of flipping a coin 8 times and getting heads every time.

However, if it is known that the family has at least one girl, the probability of the family having 8 girls increases slightly. This is because the probability of at least one girl existing eliminates some of the possible outcomes of the family having all boys.

Since there are 8 total children, and 7 of them must be girls in order for the family to have 8 girls, the probability of the family having 8 girls can be calculated by taking the probability of one girl (1/2) and then multiplying it by itself 7 times (1/2 to the power of 7). This gives a probability of 1/128, which is twice as likely as the probability of the family having 8 girls without knowing that at least one girl exists.

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Enzo's net worth = Enzo's assets - Enzo's liabilities. The resulting number is his net worth.

Enzo's net worth = (Enzo's cash + Enzo's investments + Enzo's property + Enzo's other assets) - (Enzo's loans + Enzo's credit card debt + Enzo's other liabilities)

Enzo's net worth is calculated by subtracting his liabilities from his assets. Enzo's assets include cash, investments, property and other assets he may own. His liabilities include any loans he has taken out, any credit card debt, and any other liabilities he may have. To find Enzo's net worth, you would add up all of his assets and subtract from that all of his liabilities. The resulting number is his net worth.

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We can conclude from this data that the mean commute time in the US is less than half an hour.

To determine whether we can conclude that the mean commute time in the U.S. is less than half an hour based on this sample, we need to conduct a hypothesis test.

Let's assume the null hypothesis that the mean commute time in the U.S. is equal to or greater than 30 minutes. The alternative hypothesis would be that the mean commute time in the U.S. is less than 30 minutes.

We can use a one-sample t-test to test this hypothesis. The t-test statistic can be calculated as:

t = (sample mean - hypothesized mean) / (sample standard deviation / \(\sqrt{sample size}\))

Substituting the given values, we get:

t = (28.9 - 30) / (19 / \(\sqrt{240}\))

t = -1.82

Using a t-distribution table with 239 degrees of freedom (sample size minus one), we can find the p-value associated with this t-value. The p-value is the probability of obtaining a t-value as extreme or more extreme than the one observed, assuming the null hypothesis is true.

The p-value is found to be 0.034. This means that if the null hypothesis were true, we would observe a sample mean as extreme or more extreme than 28.9 only 3.4% of the time.

Assuming a significance level of 0.05, we can reject the null hypothesis if the p-value is less than 0.05. Since the p-value is less than 0.05, we can conclude that there is evidence to suggest that the mean commute time in the U.S. is less than 30 minutes.

However, it is important to note that this conclusion is based on a sample of 240 people and may not necessarily reflect the true population mean. Further research with a larger sample size may be necessary to confirm this conclusion with more confidence.

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The company packs "3" clay pots and "4" plastic pots for maximum packing in one shipment. This will require the fewest shipments.

or,

The company packs "2" clay pots and "6" plastic pots for maximum packing in one shipment. This will require the fewest shipments.

Let, the number of clay flower pots - "c"

the number of plastic flower pots is "p".

We can write:

\(2\leq c + p\leq 8\)

Also,

Weight of clay pot = 15 pounds

Weight of plastic pot = 7.5 pounds

Max Weight of Shipment = 100 pounds

Weight of container = 20 pounds

The weight of Packing material inside the container = 1 pound

Thus, the maximum weight of pots will be less than

                               = 100 - (20+1) = 100 - 21 = 79

We can write another inequality:

\(1.5c + 7.5p < 79\)

To assure the first inequality, we have points,

c = 0, p = 8

p =0, c = 8

c = 1, p = 7

etc. and so on...

So,

The company packs "3" clay pots and "4" plastic pots for maximum packing in one shipment. This will require the fewest shipments.

or,

The company packs "2" clay pots and "6" plastic pots for maximum packing in one shipment. This will require the fewest shipments.

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The complete question is:

A gardening company sells clay flower pots and plastic flower pots. There must be at least 2 pots in each shipment, but there cannot be more than 8 in a shipment. Additionally, the shipment must weigh less than 100 pounds. Each shipment container weighs 20 pounds, and there is 1 pound of packing material. A clay flower pot weighs 15 pounds, whereas a plastic flower pot weighs 7.5 pounds. The company wants to fill each shipment as full as it can get when they send shipments to garden supply stores. There is a similar demand for each type of pot. What is the best solution for the company if they want to ship the fewest shipments? Justify your reasoning.

The table of values that represents exponential decay is (c)

From the question, we have the following parameters that can be used in our computation:

The table of values

An exponential function is represented as

y = abˣ

Where

Rate = b

When the rate is less than 1, then the table represents a decay

i.e when y reduces as x increases

The table that has the above features is the table (c)

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Answer:

x=20 the angles are 80 and 100

Step-by-step explanation:

those types of angels are supplementary, so we can set up an equation like this: 5x+4x=180

We'll get x=20, then we can put 20 into each angle to find out its measure:)

5(20)=100

4(20)=80

Answer:  80%

Step-by-step explanation:

devide 53 by 66 then you would get your answer in a decimal form which then you move the decimal two places to the left and thats your answer in percent form

hope this helps :)

Answer:

3-2

Step-by-step explanation

Answer:

x=1/7 or 0.14

Step-by-step explanation:

first you distribute: 8-6x+2=x+9

next combine like terms (8 and 2): -6x+10=x+9

then subtract 1x from both sides: -7x+10=9

then subtract 10 from both sides: -7x=-1

divide both sides by -7: x=1/7 or 0.14

Answer:

  7360 ft·lb

Step-by-step explanation:

You want the work done by a 320-lb gorilla climbing to a height of 23 feet.

Work is the product of force and distance:

  W = (weight)·(height) = (320 lb)(23 ft) = 7360 ft·lb

The gorilla does 7360 ft·lb of work.

__

Additional comment

Time comes into play when you want the power involved. If the climbing is done in 10 seconds, the power required is about 1.34 horsepower. (1 hp = 550 ft·lb/s)

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Answer:

6 days

Step-by-step explanation:

Given that Reilly works every other day (This means that she works every 2 days) while Samantha works every third day. Today both of them are working together.

The next day none of them will be working, on the second day only Reilly would be working, on the third day only Samantha would be working, on the fourth day only Reilly would be working, on the fifth day none will be working and on the sixth day both Reilly and Samantha would be working.

This is the same as finding the least common multiple (LCM) of 2 days and 3 days which is 6 days

Answer:

right triangles only

Step-by-step explanation:

Answer:

5:05

6

10

Step-by-step explanation:

3:30 + 1 hour = 4:30

4:30 + 35 mins = 5:05 pm

5 days per 1 gallon, 30 days for :

30/5 = 6

500/50 = 10

To construct a truth table for the expression `(x+y′)(x′+z′)(y′+z)`, follow the steps given below:

Step 1: Write the given expression, `(x+y′)(x′+z′)(y′+z)`.

Step 2: List out all possible combinations of the given variables in a table. There are three variables x, y and z, so there will be 2³ = 8 combinations. Let's list them as follows: x=0, y=0, z=0 x=0, y=0, z=1 x=0, y=1, z=0 x=0, y=1, z=1 x=1, y=0, z=0 x=1, y=0, z=1 x=1, y=1, z=0 x=1, y=1, z=1

Step 3: Evaluate the expression `(x+y′)(x′+z′)(y′+z)` for each combination of variables, and write the output values in the truth table. To do this, substitute the given variable values in the expression and then simplify to get the output.

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Answer:

63*

Step-by-step explanation:

The first thing you need to do is find the value of x. What I did for this was trial and error. I tried a number, and if it was too big, I tried a smaller one. If you add up all of the angles, it should equal up to 180*, so I kept on doing this until I added up to 180.

The answer I got was x=8, so I plugged this into the equation for A and solved. 9x8 is 72, and 72-9 is 63.

Therefore, 63 is the correct answer.

Answer:

Hey Will its me sienna

Step-by-step explanation:

Therefore, the average lateness using the earliest due date criterion is 2. The corect option is not one of the given options (A, B, C, or D).

To calculate the average lateness using the earliest due date criterion, we need to first determine the sequence in which the jobs should be processed. The earliest due date (EDD) criterion schedules jobs in the order of increasing due dates, so we will arrange the jobs in this order:

c, a, e, b, d

The table below shows the processing time, due date, and completion time of each job, as well as the lateness (completion time - due date) for each job:

Job Processing Time Due Date Completion Time Lateness

c 4 4 4 0

a 2 7 6 -1

e 5 15 11 -4

b 8 16 19 3

d 10 17 29 12

To calculate the average lateness, we add up the lateness values for all jobs and divide by the total number of jobs:

Average lateness = (0 + (-1) + (-4) + 3 + 12) / 5

= 2

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The constant of proportionality is the slope.

The slope is the change in Y over the change in x. (Y2 -y1) / (x2 -x1)

From a table use two set of values (x,y) subtract two y values from each other and then subtract the two corresponding x values from each other. Depending on the size of the table it’s a Leah a good idea to use the first and last set of values from the table.

From a graph locate two points on the line that you can get an accurate x and y value and subtract the two y values and the two x values: (y2 -y1) / (x2-x1).

From a written description there should be a reference two two different points, using the two referenced point subtract them like in the directions given above.

using exponents, On simplifying the equation, we get =4m+8.

The PEMDAS order of operations must be followed when you want to simplify a mathematical equation without using parenthesis (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction). There are no parenthesis in the expression, so you may start looking for exponents. If it does, first make that simpler.

Work simplification is to develop better work processes that boost output while cutting waste and costs.

Simplifying an expression is the same as solving a mathematical issue. When you simplify an equation, you essentially try to write it as simply as you can. There shouldn't be any more multiplication, dividing, adding, or deleting to be done when the process is finished.

Given equation,

m-(8-3m)

=m-8+3m

=4m+8

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Answer:

a. x = 10

b. x = 3/5

c. x = 16

d. x = 21/32

Step-by-step explanation:

a - 2x/3 + (x+3)/3 = 11

b - 3/x + 6/x = 15

c - x/2 + x/8 = 10

d - 4/x + 5/4x = 8

Apologies for the long explanations--it's not something I do very well.

The following parts can be solved by the concept of Sets.

(a) KnF is definitely compact and closed.

(b) Fc U Kc is definitely closed, but not necessarily compact.

(c) K\F is definitely closed, but not necessarily compact.

(d) KnFc is definitely neither compact nor closed.

(a) KnF:

Since K is compact and F is closed, their intersection KnF is also closed, as the intersection of any finite number of closed sets is closed. Moreover, since K is compact, every open cover of K has a finite subcover, and thus, KnF is compact by the finite intersection property.

(b) Fc U Kc:

Fc is closed since the complement of a closed set is open, and Kc is closed since K is compact (and thus, closed) and the complement of a closed set is open. The union of two closed sets is also closed, so Fc U Kc is closed. However, Kc may not be compact, so Fc U Kc is not necessarily compact.

(c) K\F:

K\F is closed because it is the complement of the open set F. However, K\F may not be compact, as K itself may not be compact. For example, if K is the real line and F is the open interval (0,1), then K\F is not compact.

(d) KnFc:

KnFc is neither compact nor closed. To see that it is not compact, consider the sequence {x_n} in K given by x_n = (1 + 1/n, 0). This sequence converges to the point (1, 0), which is outside of K, but every term of the sequence is in K. Thus, K is not closed. On the other hand, since F is closed, Fc is open and contains K, so KnFc is not closed either.

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Michael’s child is going to college in 13 years. If he saves $ 7,000 a year at 9% compounded annually. Therefore,  the amount available for Peter's child education will be $147,330.55.

Given that Michael is saving $7,000 per year for his child's education which will occur in 13 years. If the interest rate is 9% compounded annually,

The problem of finding the amount of money Michael will have saved in 13 years is a compound interest problem.

In this case, the formula for calculating the future value of the annuity is: $FV = A[(1 + r)n - 1] / r

where: FV is the future value of the annuity, A is the annual payment,r is the annual interest rate, and n is the number of payments.

Using the above formula; the future value of Michael's savings is:

FV = 7000[(1 + 0.09)^13 - 1] / 0.09= 7000(1.09^13 - 1) / 0.09= 147,330.55

Therefore, the amount available for Peter's child education will be $147,330.55.

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(i) Euler's method: At x = 0.05, y ≈ 1.05, At x = 0.1, y ≈ 1.107, At x = 0.15, y ≈ 1.174

(ii) Fourth-order Runge-Kutta method: At x = 0.05, y ≈ 1.05 , At x = 0.1, y ≈ 1.107, At x = 0.15, y ≈ 1.174

(i) Euler's Method:

Euler's method is a simple numerical method for approximating solutions to differential equations. It uses the formula:

yᵢ₊₁ = yᵢ + h * f(xᵢ, yᵢ),

where yᵢ is the approximate value of y at xᵢ and f(x, y) is the given differential equation.

Let's start by calculating the approximate solution using Euler's method.

Step size, h = 0.05

At x = 0.05:

x₀ = 0

y₀ = 1

Using the given differential equation: dy/dx = 2x + eˣʸ

We have: f(x, y) = 2x + eˣʸ

Using Euler's method:

x₁ = x₀ + h = 0 + 0.05 = 0.05

y₁ = y₀ + h * f(x₀, y₀)

   = 1 + 0.05 * (2(0) + e^(0*1))

   = 1 + 0.05 * (0 + e^0)

   = 1 + 0.05 * (0 + 1)

   = 1 + 0.05

   = 1.05

At x = 0.1:

x₂ = x₁ + h = 0.05 + 0.05 = 0.1

y₂ = y₁ + h * f(x₁, y₁)

 \(= 1.05 + 0.05 * (2(0.05) + e^(0.05*1.05)) = 1.05 + 0.05 * (0.1 + e^(0.0525))\)

   = 1.05 + 0.05 * (0.1 + 1.05383959925)

   = 1.05 + 0.05 * (1.15383959925)

   = 1.107691979963

At x = 0.15:

x₃ = x₂ + h = 0.1 + 0.05 = 0.15

y₃ = y₂ + h * f(x₂, y₂)

  \(= 1.107691979963 + 0.05 * (2(0.1) + e^(0.1*1.107691979963)) = 1.107691979963 + 0.05 * (0.2 + e^(0.1107691979963))\)

   = 1.107691979963 + 0.05 * (0.2 + 1.12281597877)

   = 1.107691979963 + 0.0661407989385

   = 1.173832778901

Approximate solution using Euler's method:

At x = 0.05, y ≈ 1.05

At x = 0.1, y ≈ 1.107

At x = 0.15, y ≈ 1.174

(ii) Fourth-order Runge-Kutta Method:

The fourth-order Runge-Kutta method is a more accurate numerical method

for approximating solutions to differential equations. It uses the formula:

k₁ = h * f(xᵢ, yᵢ)

k₂ = h * f(xᵢ + h/2, yᵢ + k₁/2)

k₃ = h * f(xᵢ + h/2, yᵢ + k₂/2)

k₄ = h * f(xᵢ + h, yᵢ + k₃)

yᵢ₊₁ = yᵢ + (k₁ + 2k₂ + 2k₃ + k₄)/6

Let's calculate the approximate solution using the fourth-order Runge-Kutta method.

Step size, h = 0.05

At x = 0.05:

x₀ = 0

y₀ = 1

k₁ = 0.05 * f(x₀, y₀)

   = 0.05 * (2(0) + e^(0*1))

   = 0.05 * (0 + e^0)

   = 0.05 * (0 + 1)

   = 0.05

k₂ = 0.05 * f(x₀ + 0.05/2, y₀ + k₁/2)

   = 0.05 * f(0 + 0.025, 1 + 0.025/2)

   = 0.054123529771

k₃ = 0.05 * f(x₀ + 0.05/2, y₀ + k₂/2)

   = 0.05 * f(0 + 0.025, 1 + 0.054123529771/2)

   = 0.05 * (1.08260731316)

   = 0.054130365658

k₄ = 0.05 * f(x₀ + 0.05, y₀ + k₃)

   = 0.05 * f(0 + 0.05, 1 + 0.054130365658)

   = 0.05 * (1.15381700056)

   = 0.057690850028

y₁ = y₀ + (k₁ + 2

k₂ + 2k₃ + k₄)/6

   = 1 + (0.05 + 2(0.054123529771) + 2(0.054130365658) + 0.057690850028)/6

   = 1 + (0.05 + 2(0.054123529771) + 2(0.054130365658) + 0.057690850028)/6

   = 1.04999993086

At x = 0.1:

x₁ = x₀ + h = 0 + 0.05 = 0.05

k₁ = 0.05 * f(x₀, y₁)

   = 0.05 * (2(0.05) + e^(0.05*1.04999993086))

   = 0.05 * (1.15382091332)

   = 0.057691045666

k₂ = 0.05 * f(x₀ + 0.05/2, y₁ + k₁/2)

   = 0.05 * f(0 + 0.025, 1.04999993086 + 0.057691045666/2)

   = 0.05 * f(0.025, 1.076845501196)

   = 0.05 * (1.08293606756)

   = 0.054146803378

k₃ = 0.05 * f(x₀ + 0.05/2, y₁ + k₂/2)

   = 0.05 * f(0 + 0.025, 1.04999993086 + 0.054146803378/2)

   = 0.05 * (0.05 + 1.03297648754)

   = 0.05 * (1.08297648754)

   = 0.054148824377

k₄ = 0.05 * f(x₀ + 0.05, y₁ + k₃)

   = 0.05 * f(0 + 0.05, 1.04999993086 + 0.054148824377)

   = 0.05 * f(0.05, 1.104148755237)

   = 0.

05 * (2(0.05) + e^(0.05*1.104148755237))

   = 0.05 * (1.15636272702)

   = 0.057818136351

y₂ = y₁ + (k₁ + 2k₂ + 2k₃ + k₄)/6

   = 1.04999993086 + (0.057691045666 + 2(0.054146803378) + 2(0.054148824377) + 0.057818136351)/6

   = 1.04999993086 + (0.057691045666 + 2(0.054146803378) + 2(0.054148824377) + 0.057818136351)/6

   = 1.10730401829

At x = 0.15:

x₂ = x₁ + h = 0.1 + 0.05 = 0.15

k₁ = 0.05 * f(x₁, y₂)

   = 0.05 * (2(0.1) + e^(0.1*1.10730401829))

   = 0.066134153561

k₂ = 0.05 * f(x₁ + 0.05/2, y₂ + k₁/2)

   = 0.05 * f(0.1 + 0.025, 1.10730401829 + 0.066134153561/2)

   = 0.05 * (1.40252551209)

   = 0.070126275604

k₃ = 0.05 * f(x₁ + 0.05/2, y₂ + k₂/2)

   = 0.05 * f(0.1 + 0.025, 1.10730401829 + 0.070126275604/2)

   = 0.05 * f(0.125, 1.13726868037)

   = 0.05 * (1.40260973286)

   = 0

.070130486643

k₄ = 0.05 * f(x₁ + 0.05, y₂ + k₃)

   = 0.05 * f(0.1 + 0.05, 1.10730401829 + 0.070130486643)

   = 0.05 * (1.49307437508)

   = 0.074653718754

y₃ = y₂ + (k₁ + 2k₂ + 2k₃ + k₄)/6

   = 1.10730401829 + (0.066134153561 + 2(0.070126275604) + 2(0.070130486643) + 0.074653718754)/6

   = 1.17379707103

Approximate solution using the fourth-order Runge-Kutta method:

At x = 0.05, y ≈ 1.05

At x = 0.1, y ≈ 1.107

At x = 0.15, y ≈ 1.174

Therefore, the approximate solutions using Euler's method and the fourth-order Runge-Kutta method at x = 0.05, 0.1, and 0.15 are as follows:

Euler's method:

At x = 0.05, y ≈ 1.05

At x = 0.1, y ≈ 1.107

At x = 0.15, y ≈ 1.174

Fourth-order Runge-Kutta method:

At x = 0.05, y ≈ 1.05

At x = 0.1, y ≈ 1.107

At x = 0.15, y ≈ 1.174

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If last week Salazar played 13 more tennis games than Perry and they played a combined total of 53 games, then Salazar played a total of 33 games.

Let the total number of games played by Perry be x.

It is given that, Salazar played 13 more tennis games than Perry.

⇒ Total games played by Salazar = x + 13

Also, Salazar and Perry played a combined of 53 games.

Hence, total number of tennis games played by Salazar and Perry = 53

⇒ Games played by Salazar + Games played by Perry = 53

⇒  x + (x + 13) = 53

2x + 13 = 53

2x = 53 - 13

2x = 40

x = 40 / 2

x = 20

Therefore, total number of games played by Salazar = x+13

= 20 + 13

= 33

Thus, Salazar played total 33 games.

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