Zinc is most readily found in protein-rich foods such as shellfish, meats, poultry, and dairy products. Vegetarian sources such as legumes and whole grains offer zinc; however, their ______
A. Oxylate
B Phytate
C fiber
D. Nitrigen

the change in Gibbs energy is 5.2 J/mol, and the reaction is non-spontaneous under these conditions.

To calculate the change in Gibbs energy, we can use the equation:

ΔG = ΔH - TΔS

ΔH - change in enthalpy,

ΔS - change in entropy,

T - temperature in Kelvin.

at 188 K, ΔH = 2380 J/mol and ΔS = 12.6 J/mol K

ΔG = (2380 J/mol) - (188 K)(12.6 J/mol K)

ΔG = 2380 J/mol - 2374.8 J/mol

ΔG = 5.2 J/mol

The positive value of ΔG indicates that the reactants are more stable than the products and that energy must be added to the system to drive the reaction forward.

Therefore, the change in Gibbs energy is 5.2 J/mol, and the reaction is non-spontaneous under these conditions.

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Answer:

are gases at room temperature

usually do not react with other elements

are in a group called the noble gases

are nonmetals

Explanation:

The elements in group 18 or group O are the inert elements. They have completely outermost shell and are not reactive. Every atom reacts with another in order to be like the noble gases.

It should be noted that group 17 elements are very reactive compared to the group O elements.

Answer:

Give them each one so all of you is 8

Explanation:

I hope it helps:)

Fred and Florence have a combined total of 14 markers. Meaning, the amount of markers between all three is 24. If Maggie gives one marker to Fred and one marker to Florence, then each of them will have 8 markers.

Nanomaterials, whether natural, engineered, organic, or inorganic, offer various applications across industries. However, their environmental health and safety impacts need to be carefully evaluated and managed to mitigate any potential risks.

Understanding their properties, fate, and behavior in different environments is crucial for responsible development, use, and disposal of nanomaterials.

Natural Nanomaterials:

Examples: Carbon nanotubes (CNTs) derived from natural sources like bamboo or cotton, silver nanoparticles in natural colloids, clay minerals (e.g., montmorillonite), iron oxide nanoparticles found in magnetite.

Uses: Natural nanomaterials have various applications in medicine, electronics, water treatment, energy storage, and environmental remediation.

Environmental health and safety impacts: The environmental impacts of natural nanomaterials can vary depending on their specific properties and applications. Concerns may arise regarding their potential toxicity, persistence in the environment, and possible accumulation in organisms. Proper disposal and regulation of their use are essential to minimize any adverse effects.

Engineered Nanomaterials:

Examples: Gold nanoparticles, quantum dots, titanium dioxide nanoparticles, carbon nanomaterials (e.g., graphene), silica nanoparticles.

Uses: Engineered nanomaterials have widespread applications in electronics, cosmetics, catalysis, energy storage, drug delivery systems, and sensors.

Environmental health and safety impacts: Engineered nanomaterials may pose potential risks to human health and the environment. Their small size and unique properties can lead to increased toxicity, bioaccumulation, and potential ecological disruptions. Safe handling, proper waste management, and risk assessment are necessary to mitigate any adverse effects.

Organic Nanomaterials:

Examples: Nanocellulose, dendrimers, liposomes, organic nanoparticles (e.g., polymeric nanoparticles), nanotubes made of organic polymers.

Uses: Organic nanomaterials find applications in drug delivery, tissue engineering, electronics, flexible displays, sensors, and optoelectronics.

Environmental health and safety impacts: The environmental impact of organic nanomaterials is still under investigation. Depending on their composition and properties, they may exhibit varying levels of biocompatibility and potential toxicity. Assessments of their environmental fate, exposure routes, and potential hazards are crucial for ensuring their safe use and minimizing any adverse effects.

Inorganic Nanomaterials:

Examples: Quantum dots (e.g., cadmium selenide), metal oxide nanoparticles (e.g., titanium dioxide), silver nanoparticles, magnetic nanoparticles (e.g., iron oxide), nanoscale zeolites.

Uses: Inorganic nanomaterials are utilized in electronics, catalysis, solar cells, water treatment, imaging, and antimicrobial applications.

Environmental health and safety impacts: Inorganic nanomaterials may have environmental impacts related to their potential toxicity, persistence, and release into ecosystems. Their interactions with living organisms and ecosystems require careful assessment to ensure their safe use and minimize any negative effects.

Understanding their properties, fate, and behavior in different environments is crucial for responsible development, use, and disposal of nanomaterials.

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The  prokaryotic cell and eukaryotic cell both contain the ribosomes. The Ribosomes are the non - membrane bound organelles.

The Eukaryotic cells contain the membrane - bound the organelles, such as the nucleus, the endoplasmic reticulum, the mitochondria while the prokaryotic cells do not contain the nucleus, endoplasmic and the mitochondria but the ribosome is the organelle that can be seen in the  both the prokaryotic cell and the eukaryotic cell.

The Prokaryotic and the eukaryotic ribosomes that is perform by the same functions that is the protein synthesis, however, the eukaryotic ribosomes are the much larger than the prokaryotic cell.

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Using the Arrhenius plot, it take  0.71661423 seconds for determination 5 to clock at 75℃. .

y = mx +b  → - 6593.7x + 21.234

ln(k') = m(1/T) + b

ln(k’) = - 6593.7 (1/75+273.15) + 21.234

ln(k’) ≈ 2.29  → e^2.29 = 9.87

k’ = 9.87

ln[S₂O₈²-] =  ln[S₂O₈²-]₀ - k'(t)

ln (0.033333)  = ln (0.0375) - 9.87 (t)  

-3.4011974 = -3.283414346 - 9.87 (t)  

-0.1178830407 = -9.87 (t)

t = 0.0119435705 in minutes  

0.0119435705 x 60 = 0.71661423 seconds  

Thus,  it would  take  0.71661423 seconds for determination 5 to clock at 75℃. .

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Answer:

Mitosis

Explanation:

Answer:

The atomic number of sodium is 11 (Z=11). The electronic configuration of sodium can be written as 2, 8, 1. Therefore, valence electron in sodium is 1 and it needs to lose 1 electron from the outermost orbit to attain octet. Hence, the valency of sodium is 1.

Explanation:

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Answer:

I think it's fungus or plant cell

Answer:

Plant cell

Explanation:

Chloroplast are only found in plant cells

To convert 100 ml of sodium hydroxide solution with a pH of 13.00 to a sodium hydroxide solution with a pH of 12.00, one method would be to dilute the solution with distilled water.

By diluting the solution, the concentration of hydroxide ions (OH-) will decrease, thus reducing the pH of the solution. The exact amount of distilled water needed to reach a pH of 12.00 will depend on the original concentration of the sodium hydroxide solution. However, you can add small amounts of distilled water to the solution and measure the pH after each addition until the desired pH is reached. It's important to note that the conversion of sodium hydroxide solution from pH 13.00 to 12.00 involves a significant decrease in the concentration of hydroxide ions, and care should be taken when handling strong alkaline solutions.

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\(Fe(OH)3- > Fe2O3- > Fe- > FeCl2- > Fe(OH)2\), represents a set of possible chemical reactions that Fe(OH)3, or iron(III) hydroxide, can undergo.

In the first reaction, Fe(OH)3 is converted into Fe2O3, or iron(III) oxide, through the process of thermal decomposition. This reaction occurs when Fe(OH)3 is subjected to high temperatures, causing it to break down into Fe2O3 and water vapor.

In the second reaction, Fe2O3 is reduced to Fe, or elemental iron, through the process of electrolysis. This reaction involves passing an electric current through a solution of Fe2O3, causing the Fe2O3 to be reduced to Fe at the cathode and oxygen to be produced at the anode.

In the third reaction, Fe is converted into FeCl2, or iron(II) chloride, through the process of chlorination. This reaction involves adding chlorine gas to a solution of Fe, causing the Fe to be converted into FeCl2 and hydrogen gas.

In the fourth reaction, FeCl2 is converted into Fe(OH)2, or iron(II) hydroxide, through the process of acidification. This reaction involves adding an acid to a solution of FeCl2, causing the FeCl2 to be converted into Fe(OH)2 and hydrochloric acid.

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The correct question is:

Explain this chemical reaction \(Fe(OH)3- > Fe2O3- > Fe- > FeCl2- > Fe(OH)2\)

The reaction with S_N₂mechanism is likely to be faster than the reaction with S_N₂ mechanism. This is because the carbocation intermediate formed in S_N₁ mechanism is more stable.

The pair of reactions given below is:

CH₃Cl + NaOH→CH₃OH + NaCl

CH₃I + NaOH→CH₃OH + NaI

The type of substitution mechanism:

The first reaction involves S_N₁ mechanism (unimolecular nucleophilic substitution). The second reaction involves S_N₂ mechanism (bimolecular nucleophilic substitution).

Prediction of the reaction that will occur at a faster rate:

The reaction with S_N₁ mechanism is likely to be faster. The rate of this reaction mainly depends on the stability of the carbocation intermediate formed after the initial step. In this case,CH₃Cl reacts to form a tertiary carbocation which is more stable than the primary carbocation formed in CH₃I.

Drawing the correct organic product:

CH₃Cl + NaOH→CH₃OH + NaCl

CH₃I + NaOH→CH_3OH + NaI

CH₃C reacts with NaOHin an S_N₁ mechanism to produceCH₃OH and NaCl.


CH₃ reacts withNaOH in an S_N₂mechanism to produce CH₃OH and NaCI.


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Answer:

2. Chemical tests to distinguish between unlabelled samples of the following solutions and their expected observations are:

a) Sodium sulfate and calcium nitrate: Add dilute hydrochloric acid to the unknown solution. Calcium nitrate will produce a white precipitate while sodium sulfate will not produce any precipitate.

b) Sodium sulfate and sodium nitrate: Add silver nitrate solution to the unknown solution. Sodium nitrate will produce a white precipitate of silver chloride while sodium sulfate will not react.

c) Strontium nitrate and strontium hydroxide: Add dilute hydrochloric acid to the unknown solution. Strontium hydroxide will produce a white precipitate while strontium nitrate will not produce any precipitate.

d) Barium chloride and lithium chloride: Add a few drops of dilute sulfuric acid to the unknown solution, followed by a few drops of a solution of potassium dichromate. Barium chloride will produce a green color while lithium chloride will not show any color.

3. Compound A giving a lilac flame test color and producing a white precipitate when added to a solution of barium chloride indicates the presence of potassium ion (K+). Therefore, compound A is most likely potassium chloride (KCl).

The correct order of acid strengths (largest to smallest) is: 4) HNO₃ > HCIO₂ > HBrO > HCIO

The  acid strength of an acid is determined by its ability to donate a hydrogen ion (H+). The more readily an acid donates its hydrogen ion (H+ ion), the stronger it is.

In option 1, HCIO is listed as the strongest acid, but this is incorrect. HNO₃ is a stronger acid than HCIO.

In option 2, HBrO is listed as the strongest acid, but this is also incorrect. HNO₃ is still the strongest acid.

Option 3 has HCIO listed as a stronger acid than HBrO, which is incorrect. HBrO is a stronger acid than HCIO.

Option 5 has HClO₂ listed as the strongest acid, which is also incorrect. HNO₃ is still the strongest acid.

Therefore, option 4 is the correct order of acid strengths, with HNO₃ being the strongest acid, followed by HCIO₂, HBrO, and HCIO in decreasing order of strength.

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Answer:

It is D.

Explanation:

Reactants are the starting substances of a chemical reaction, while products are the substances produced from a reaction.

In a chemical reaction, the starting substances are called reactants, and the substances produced from the reaction are called products. Reactants are the substances that are transformed or changed during the reaction, while products are the substances that are formed as a result of the chemical reaction.

For example, in the chemical reaction where hydrogen gas reacts with oxygen gas to form water, the reactants are hydrogen and oxygen, and the product is water.

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To calculate the mass of CH4N2O dissolved,

we need to follow these steps:

1. Determine the freezing point depression:
ΔTf = T(freezing point of pure X) - T(freezing point of solution) = -0.10°C - (-2.1°C) = 2°C

2. Calculate the molality (m) of the solution using the freezing point depression constant (Kf) and the freezing point depression (ΔTf):
ΔTf = Kf × m
m = ΔTf / Kf = 2°C / 2.85°C·kg/mol = 0.7018 mol/kg

3. Find the moles of CH4N2O in the solution:
moles of CH4N2O = molality × mass of solvent (in kg)
moles of CH4N2O = 0.7018 mol/kg × 0.600 kg = 0.4211 mol

4. Calculate the mass of CH4N2O using its molar mass (60.06 g/mol):
mass of CH4N2O = moles × molar mass = 0.4211 mol × 60.06 g/mol = 25.29 g

Rounded to 2 significant digits,

the mass of CH4N2O dissolved is 25 g.

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The edge length of the unit cell is 407 pm

A unit cell is the smallest representation of an entire crystal structure

A face centered cubic structure is one in which there is an atom on each face of the unit cell and one atom at each corner of the unit cell.

So, for a face centered unit cell of atomic radius, r and edge length, a, we have that

(4r)² = a² + a²

16r² = 2a²

8r² = a²

Taking square root of both sides, we have

a = (2√2)r

So, for a silver atom with atomic radius 144 pm, the edge length a is

a = (2√2)r

a = (2√2)144 pm

a = 288√2 pm

a = 407.3 pm

a ≅ 407 pm

The edge length of the unit cell is 407 pm

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Answer:

photosynthesis

Explanation:

photosynthesis is the process by which green plants and some other organisms trap sunlight ( light energy ) using chlorophyl synthesises it and in the presence of carbon dioxide produces their food (glucose) and gives oxygen as a byproduct.

Answer:

photosynthesis

Explanation:

i just took the quiz with that question

Hydration of alkynes with h3o typically requires a mercury catalyst is a false statement.

Alkynes are first hydrated by the addition of the first water molecule. But this initial hydration event results in the formation of an enol, an alcohol joined to a vinyl carbon.

Enols instantly go through a particular kind of isomerization process termed tautomerization to create carbonyl groups, such as aldehydes or ketones. With the understanding that aldehydes occur on terminal alkyne carbons, this reaction is referred to as "enol-keto" tautomerization to make things straightforward.

Similar to hydration (adding water) of alkenes, hydration of alkynes necessitates the use of a potent acid, typically sulfuric acid with a mercuric sulfate catalyst.

Therefore,  Hydration of alkynes with h3o typically requires a mercury catalyst is a false statement.

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Visible corrosion, or other degradation of a container, may indicate that a container is undergoing chemical energy.

What is corrosion? Corrosion is a destructive phenomenon that causes the loss of material from the surface of a solid due to chemical reactions with the surrounding environment.

The oxidation of metals in the presence of air, water, or acids is the most well-known instance of corrosion.

What is degradation?

The method of breaking down or decomposing is known as degradation. Degradation can occur in various ways, including natural and man-made causes, and can have severe environmental and economic consequences.

Polymer degradation, for example, causes the breakdown of the material's physical and chemical properties as a result of the impacts of certain environmental factors.

What are the containers?

Containers are equipment that is intended to store items, including goods, raw materials, and items, or transmit them from one location to another, such as storage containers, shipping containers, and bulk containers. There are various types of containers for different purposes and industries, and they come in various shapes, sizes, and materials.

How is a container undergoing chemical energy?

Visible corrosion, or other degradation of a container, may indicate that a container is undergoing chemical energy. When containers are subjected to harsh environments, such as high temperatures or humid environments, they may deteriorate or corrode over time, resulting in material loss or structural damage. As a result, it is critical to take care of containers and inspect them regularly to ensure that they are in good condition.

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Answer:

O

Explanation:

O is in the red which says nonmetal

The equilibrium vapor pressure with respect to water (eow) is 259.9 Pa. assume that saturation vapor pressure is same as equilibrium vapor pressure.

Therefore, the RH at the frost point is  

RH = (eow / saturation vapor pressure) × 100

= (259.9 Pa / 259.9 Pa) × 100

= 100%

b) At T = -11 °C, we need to compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi) to determine if ice particles will form. From the given table, at T = -11 °C, the equilibrium vapor pressure with respect to water (eow) is 237.7 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 165.3 Pa.

The air is supersaturated with respect to ice, and the presence of Kaolinite particles can provide surfaces for water droplets to condense onto, leading to the formation of ice particles.

c) At T = -12 °C, we compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi). From the given table, at T = -12 °C, the equilibrium vapor pressure with respect to water (eow) is 217.3 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 181.2 Pa.

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Answer:

the answer is c

Explanation:

Answer:

neutron

Explanation:

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