11. A population of bacteria triples every week in a laboratory. The number of
bacteria is modeled by the expression 900 3*, where x is the number of weeks
after a scientist measures the population size. When x = -2, what does the value
of the expression represent?

The relationship between the two variables is positive and nonlinear.

Relationship can vary in terms of its nature and characteristics.

When considering the possible relationships, four scenarios can arise: negative and nonlinear, positive and linear, negative and linear, and positive and nonlinear.

Negative and nonlinear relationship: In this scenario, the two variables exhibit a negative correlation, meaning that as one variable increases, the other decreases.

Additionally, the relationship is nonlinear, suggesting that the rate of change is not constant. Instead, it may vary across different values of the variables.

Positive and linear relationship: This situation indicates a positive correlation between the variables, implying that as one variable increases, the other also increases.

The relationship is linear, meaning that the rate of change remains constant. This implies a consistent linear pattern in the data.

Negative and linear relationship: This scenario suggests a negative correlation between the variables, where an increase in one variable corresponds to a decrease in the other.

The relationship is linear, indicating a constant rate of change.

Positive and nonlinear relationship: In this case, the two variables exhibit a positive correlation, meaning that as one variable increases, the other also increases.

However, the relationship is nonlinear, indicating that the rate of change varies across different values of the variables.

Overall, the nature of the relationship between two variables can significantly impact the interpretation and analysis of data, highlighting the importance of understanding the specific characteristics of the relationship when examining their interactions.

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Using the concept of percentages the total earning of Cara can be found to be $4200.

Percentage is a number expressed as a fraction of 100. The % sign means to divide the number by 100.

Cara's earning = commission + basic salary

basic salary = $1800 (this is constant)

commission = 6% of $40000

= (6/100)*40000

= $2400

Cara's earning = 1800 + 2400

Hence, her earning is $4200

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Answer:

12

Step-by-step explanation:

bc u said that every by 12 that is only allow for every by 12 so its 12 ir 4

We can solve the problem by using the probability binomial distribution model. The formula is:

Recall that:

Given:

number of samples(n) = 8

x = 3

8% of all major bridges in that city will have ratings of 4 or below implying that the probability of a bridge having a rating of 4 or below is 0.08.

Hence,

The probability that in a random sample of 8 major bridges in the city, at least 3 will have an inspection rating of 4 or below in 2020 would be:

Probability of at most 2 can be reduced to:

Evaluating the expression, we have:

The probability that at least 3 will have a rating of 4 and below:

Answer:

0.02110

Answer:

b = -3

Step-by-step explanation:

Using the graph, when x=2

y = -3

Answer:

Option C

Step-by-step explanation:

your x values cannot repeat for the function

So in Option C x values are not repeating

The amount that will accumulate by the end of the sixth and final payment is approximately $41,666.60.

To calculate the accumulated amount by the end of the sixth and final payment, we can use the future value of an ordinary annuity formula:

Future Value = Payment × Future Value of an Ordinary Annuity Factor

The payment is $5,800, and the interest rate is 9%. Since the payments are made at the end of each year, we can use the future value table for an ordinary annuity at 9%.

Looking up the factor for 6 years at 9% in the future value table, we find it to be 7.169858.

Now we can calculate the accumulated amount:

Future Value = $5,800 × 7.169858 = $41,666.60

Therefore, the amount that will accumulate by the end of the sixth and final payment is approximately $41,666.60. The correct answer is not among the options provided.

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The correlation between your daily calorie intake and your GPA is not likely to be immediately apparent, and it would require further investigation to determine whether there is a positive or negative correlation, or no linear relationship between the two variables.

It is difficult to predict the correlation between your daily calorie intake and your GPA as they are not obviously related variables. However, it is possible that there may be a weak or indirect relationship between the two variables.

          If a person is consuming a well-balanced diet with the right amount of nutrients, vitamins, and minerals, they may have the energy and focus necessary to perform well academically. In this case, there may be a positive correlation between calorie intake and GPA. Alternatively, if a person is consuming an excessive amount of calories from unhealthy foods, they may be more likely to experience health problems that could impact their academic performance. In this case, there may be a negative correlation between calorie intake and GPA.

      On the other hand, there may be no direct linear relationship between the two variables, and other factors such as sleep, stress, exercise, and overall health may have a greater impact on academic performance than daily calorie intake.

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1.) The value of X would be = 3cm. That is option A.

2.). The value of X (in cm) would be = 4cm. That is option B.

For question 1.)

Given that ∆ABC≈∆PQR

Scale factor = larger dimension/smaller dimension

= 6/4.5 = 1.33

The value of X= 4÷ 1.33 = 3cm

For question 2.)

To calculate the value of X the formula that should be used is given as follows:

PB/PB+BR = AB/AB+QR

where;

PB= 3.2

BR = 4.8

AB = 2

QR= X

That is;

3.2/4.8+3.2= 2/2+X

3.2(2+X) = 2(4.8+3.2)

6.4+3.2x = 16

3.2x= 16-6.4

X= 12.8/3.2 = 4cm.

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To find the probability distribution for Y, the number of errors detected by the auditor, we can use the binomial distribution formula. The binomial distribution is used when there are only two possible outcomes, success or failure, and each trial is independent.

In this case, the probability of success (detecting an error) is 5% or 0.05, and the probability of failure (not detecting an error) is 1 - 0.05 = 0.95.

a. To find the probability distribution for Y, we can use the formula for the binomial distribution:

P(Y = y) = (nCk) * p^k * (1-p)^(n-k)

where n is the number of trials (3 in this case), k is the number of successes (errors detected), p is the probability of success (0.05), and (nCk) is the combination formula.

For y = 0:
P(Y = 0) = (3C0) * (0.05)^0 * (0.95)^(3-0) = (1) * (1) * (0.95)^3 = 0.857375

For y = 1:
P(Y = 1) = (3C1) * (0.05)^1 * (0.95)^(3-1) = (3) * (0.05) * (0.95)^2 = 0.135375

For y = 2:
P(Y = 2) = (3C2) * (0.05)^2 * (0.95)^(3-2) = (3) * (0.05)^2 * (0.95)^1 = 0.007125

For y = 3:
P(Y = 3) = (3C3) * (0.05)^3 * (0.95)^(3-3) = (1) * (0.05)^3 * (0.95)^0 = 0.000125

So the probability distribution for Y is:
Y = 0 with probability 0.857375
Y = 1 with probability 0.135375
Y = 2 with probability 0.007125
Y = 3 with probability 0.000125

b. To construct a probability histogram for p(y), you can create a bar graph where the x-axis represents the number of errors detected (Y) and the y-axis represents the probability (P(Y = y)). Each bar will have a height corresponding to the probability.

c. To find the probability that the auditor will detect more than one error, we need to calculate the sum of the probabilities for Y = 2 and Y = 3:

P(Y > 1) = P(Y = 2) + P(Y = 3) = 0.007125 + 0.000125 = 0.00725

Therefore, the probability that the auditor will detect more than one error is 0.00725.

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Answer:

BC = 6

Step-by-step explanation:

Look at two corresponding sides that have both lengths given.

They are AB = 4 and XY = 3.

We need BC, and its corresponding side YZ = 4.5.

We can use a proportion.

BC/YZ = AB/XY

a/4.5 = 4/3

3a = 4.5 * 4

a = 1.5 * 4

a = 6

Answer: BC = 6

Answer:

the answer is 5

Step-by-step explanation:

it is right jk

Answer:

Step-by-step explanation:

We know area of a rectangle is xy where x and y are its dimensions.

A=xy

If we factor the area we will get the dimensions.

A=15k^4+35k^3+20k^2

(this can be factored in many ways to produce the same area, the answer choices you are given can be any given combination of factors.)

A=15k^4+15k^3+20k^3+20k^2

A=15k^3(k+1)+20k^2(k+1)

A=(15k^3+20k^2)(k+1) (this is one way)

A=5k(3k^2+4k)(k+1)

A=(3k^2+4k)(5k^2+5k) (and another way)

Either expression would give you width and length (or length and width) as they all produce the area of the original equation.

Answer:

65 feet

Step-by-step explanation:

Let x be the length of the expansion to the north, and y be the width of the expansion to the east.

The current patio has an area of 30 * 30 = 900 square feet.

The total area of the expanded patio will be 2500 square feet.

So, we need to find values of x and y that satisfy the following two conditions:

The area of the expanded patio is 2500 square feet:

xy = 2500

The expanded patio has walls on two sides, so it can only expand to the north and east:

x + 30 = y

We can solve the second equation for x:

x = y - 30

Substitute this expression for x in the first equation:

(y - 30)y = 2500

Simplifying this equation:

y^2 - 30y - 2500 = 0

We can solve for y using the quadratic formula:

y = (30 ± sqrt(30^2 + 4*2500)) / 2

y = (30 ± sqrt(10000)) / 2

y = (30 ± 100) / 2

Since y must be positive, we can ignore the negative solution:

y = (30 + 100) / 2 = 65

Substitute this value for y in the equation x + 30 = y:

x + 30 = 65

x = 35

Therefore, the expansion to the north should be 35 feet, and the expansion to the east should be 65 feet.

Answer:

Step-by-step explanation:

4 Numbers Given, 1,8,6,4

Numbers start counting from 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ..... and so on

Here we can see that 1 is the first  Number.

Thus 1 is the Smallest Integer( Number ) in the given series.

The calculation of the 99% confidence interval is 26.57 and 33.43.

We are given that;

Standard deviation = 20

Number of convicted criminals= 225

Now,

1. Calculate the standard error of the mean using the formula:

\($$SE = \frac{SD}{\sqrt{N}}$$\) where SE is the standard error,

SD is the standard deviation and N is the sample size. In this case, SD = 20 and N = 225,

\(so $$SE = \frac{20}{\sqrt{225}} = \frac{20}{15} = 1.33$$\)

2. Calculate the 95% confidence interval using the formula:

\($$\bar{x} \pm z_{\alpha/2} \times SE$$ where $\bar{x}$ is the sample mean, $z_{\alpha/2}$\) is the critical value for a given confidence level and SE is the standard error.

In this case,

\($\bar{x} = 30$, $z_{\alpha/2} = 1.96$ for 95% confidence level and SE = 1.33, so $$30 \pm 1.96 \times 1.33 = 30 \pm 2.61 = (27.39, 32.61)$$\)

This means that we are 95% confident that the true population mean of years worked by white collar criminals is between 27.39 and 32.61.

3. Calculate the 99% confidence interval using the same formula but with a different critical value:

\($$\bar{x} \pm z_{\alpha/2} \times SE$$ In this case, $z_{\alpha/2} = 2.58$\)

for 99% confidence level and everything else remains the same,

\(so $$30 \pm 2.58 \times 1.33 = 30 \pm 3.43 = (26.57, 33.43)$$\)

Therefore, by percentage the answer will be 26.57 and 33.43.

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The equation will be changed into = f(x)= 32

What is a "Simple Equation"?

The link between two expressions on either side of the sign is represented by a mathematical equation.

                             One variable and an equal sign are typically present. Like this: 2x - 4 Equals 2.

We have LHS = RHS (left hand side = right hand side) in every mathematical equation.

To determine the value of an unknown variable that represents an unknown quantity, equations can be solved.

 the function f (x) = 2(4)

                       f(x)= 32

A statement is not an equation if it has no "equal to" sign.

A mathematical statement called an equation includes the sign "equal to" between two expressions with equal values.

Hence, The equation will be changed into = f(x)= 32

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The weight distribution of newborn African lions may not necessarily follow a normal distribution, and the actual percentages can vary based on the specific data available.

To determine the percentage of newborn African lions that weigh less than 3 pounds and the percentage that weigh more than 3.8 pounds, we would need statistical data on the weight distribution of newborn African lions. Since we don't have that information, we cannot provide the exact percentages.

However, if we assume that the weights of newborn African lions follow a normal distribution, we can use the properties of the standard normal distribution to make an estimation.

For the percentage of newborn African lions weighing less than 3 pounds:

We would need to know the mean and standard deviation of the weight distribution to calculate the Z-score for a weight of 3 pounds and then find the corresponding percentage using a standard normal distribution table. Without this information, we cannot provide an accurate estimation.

For the percentage of newborn African lions weighing more than 3.8 pounds:

Similarly, we would need the mean and standard deviation of the weight distribution to calculate the Z-score for a weight of 3.8 pounds and find the corresponding percentage using a standard normal distribution table. Without the required information, we cannot provide a specific estimation.

Please note that the weight distribution of newborn African lions may not necessarily follow a normal distribution, and the actual percentages can vary based on the specific data available.

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Test statistic Z= 0.13008 < 1.96 at 0.10 level of significance.

The null hypothesis is accepted.

There is no significant difference between the attractiveness ratings given by the three groups of girls.

Surveyed two random samples of 390 men and 360 women who were tested.

first sample percentage,

p1 = 360 ÷ 390 = 0.9230

second sample percentage,

p2 = 47 ÷ 52 = 0.9030

There is no change, according to the null hypothesis the percentage of males who have positive tests is significantly from the percentage of women who have positive tests.

Different Hypotheses:

There is a discrepancy in the percentage of schoolgirls who heard about a male with stylish clothes, a great automobile, or a confident demeanor across the three groups that were randomly allocated.

Z = (p1 - p2) ÷ √(PQ((1 ÷ n1) + (1 ÷ n2)))

where

p = (n1p1 + n2p2) ÷ n1 + n2

p = 0.920

Z = (0.9230 - 0.9030) ÷ √(0.9230((1 ÷ 390) + (1 ÷ 52)))

Test statistic Z =  0.13008

Level of significance = 0.10

The critical value Z₀.₁₀ = 1.645

Test statistic Z=0.13008 < 1.645 at 0.1 level of significance

The null hypothesis is accepted.

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Yes, 1212 divided by 3 = 404.

Answer:

Step-by-step explanation:

Sum the digits. The result must be divisible by 3.

1+2+1+2=6

6:3=2

YES

We have:

Let x = unknown number

15% by x = 9 or

And solve for x:

Answer: the number is 60

The solution set to the given inequalities from the graph in the form (x,y) is (-1, 2)

In mathematics, inequality arises when two mathematical expressions or two numbers are compared that are not equal. Generally, inequalities may be either numerical or algebraic, or a mixture of both.

Linear inequalities require at least one linear algebraic expression, here the polynomial is of one degree and is compared with another algebraic expression of a degree less than or equal to 1.

In the given question, we are to graph the following linear inequalities

x + y > 1

-x + y < 3

The solution set to the given inequalities by plotting their graph shows that (x,y) is (-1, 2)

The points in each shaded region of the graph are:

(0, 3)  The point is a solution to either inequality

(0, 1)   The point is a solution to one of the inequality

(-3, 0)  The point is  not a solution to either inequality

(-1, 2)   The point is a solution to either inequality

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Answer:

-30

Step-by-step explanation:

Since the diver went down 30 feet it would be -30 from where they started

The probability that a card drawn at random from an ordinary deck of 52 playing cards is: (a) An ace is 1/13. (b) A jack of hearts is 1/52. (c) A three of clubs or a six of diamonds is 1/26. (d) A heart is 1/4. (e) Any suit except hearts is 3/4. (f) A ten or a spade is 4/13. (g) Neither a four nor a club is 10/13.

We will find the probability of the given situations.

a) An aceThere are 4 aces in the deck.

Therefore, the probability of drawing an ace is given by

P(Ace) = 4/52 = 1/13

b) A jack of hearts

There is only one jack of hearts in the deck.

Therefore, the probability of drawing a jack of hearts is given by

P(Jack of hearts) = 1/52

c) A three of clubs or a six of diamonds

There is one three of clubs and one six of diamonds in the deck.

Therefore, the probability of drawing a three of clubs or a six of diamonds is given by

P(Three of clubs or six of diamonds) = 2/52 = 1/26

d) A heart

There are 13 hearts in the deck.

Therefore, the probability of drawing a heart is given by

P(Heart) = 13/52 = 1/4

e) Any suit except hearts

There are 39 cards that are not hearts in the deck.

Therefore, the probability of drawing any suit except hearts is given by

P(Any suit except hearts) = 39/52 = 3/4

f) A ten or a spade

There are 16 cards that are either tens or spades.

Therefore, the probability of drawing a ten or a spade is given by

P(Ten or spade) = 16/52 = 4/13

g) Neither a four nor a club

There are 12 cards that are either fours or clubs.

Therefore, the probability of drawing neither a four nor a club is given by

P(Neither four nor club) = 40/52 = 10/13

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Answer:

The one in the top left corner I THINK

Step-by-step explanation:

It is on baisically the same line and makes the most sense to ME.

DO NOT PICK ME IF YOU ARE NOT SURE!!!

Answer: