15. The Stanford-Binet test was used during World War 1 to identify individuals for officer status.
True
False

Answers

Answer 1

Answer:

True.

Explanation:

The Stanford-Binet test was developed by Alfred Binet and Theodore Simon in 1905 to measure intelligence. It was first used during World War I to identify individuals for officer status in the United States Army. The test was later revised and is still used today as an intelligence test for children and adults.


Related Questions

3- Correct the following statements where necessary:
A balloon filled with helium rises vertically upward under the force exerted by air, but air does not exist.​

Answers

Because the weight of the helium gas is less than the weight of the air it has displaced from the volume of the balloon, the helium-filled balloon rises in the atmosphere.

What is helium?

Chemical element helium has the atomic number 2 and the symbol He. It is the first member of the noble gas group in the periodic table and is a colorless, odorless, tasteless, non-toxic, inert, monatomic gas. Its melting point at ordinary pressure is zero, and its boiling point is the lowest of all the elements.

Helium is most commonly used to fill balloons for celebrations and parades since it is a secure, non-flammable gas. Helium, however, is an essential component in numerous industries, including as national security, high-tech manufacturing, medical technology, and scientific research.

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. A drum is struck, producing a wave with a wavelength of 110 cm and a
speed of 2.42 × 104 m/s. What is the frequency of the wave?

Answers

Answer:

22 kHz or it could be 220000

A student pushes a 6.0-kg box to the right with a
constant force FSB. The box moves at a constant velocity. The box experiences a
friction force f from the floor.
a. What type of friction does the box experience? Explain your reasoning.
b. Identify the four forces acting on the box.

Answers

a. The box experiences static friction because the box is moving at a constant velocity. Static friction is the force that opposes the initiation of motion between two surfaces that are in contact and at rest relative to each other.

b. The four forces acting on the box are:

1. Force of gravity (weight), which acts downwards towards the center of the earth, and has a magnitude of mg, where m is the mass of the box and g is the acceleration due to gravity.

2. Normal force, which is the force exerted by the floor on the box, perpendicular to the surface of contact, and has a magnitude of mg when the box is at rest or moving at a constant velocity.

3. Force applied by the student, denoted as FSB, which is directed to the right and has a magnitude that is equal to or greater than the force of friction.

4. Force of friction, denoted as f, which opposes the motion of the box and is directed to the left, opposite to the direction of the applied force. The magnitude of the frictional force is equal to the magnitude of the force applied by the student, as long as the box is moving at a constant velocity.

What is the wavelength of a photon of EMR with a frequency of 2.43x10^16 Hz?7.59x1024 m1.23x10-8 m8.10x107 Hz1.23x1024 m

Answers

Given

The frequency is

\(n=2.43\times10^{16}Hz\)

To find

The corresponding wavelength

Explanation

We know the velocity of a photon of EMR is same as the velocity of light

Thus,

\(\begin{gathered} v=n\lambda \\ \Rightarrow\lambda=\frac{3\times10^8}{2.43\times10^{16}} \\ \Rightarrow\lambda=1.23\times10^{-8}m \end{gathered}\)

Conclusion

The required wavelength is

\(1.23\times10^{-8}m\)

Imagine a 15 kg block moving with a velocity of 20 m/s to the left. Calculate the Kinetic Energy of this block. Formula: Work with Units: Variables with units: Final Answer with units:

Answers

Answer:

3000 J (joules)

Explanation:

Use the formula for kinetic energy which is:

\( k.e = \frac{1}{2} mv ^{2} \)

Where m is the mass and v is the velocity. If we put the values into the formula we get: 0.5 * 15 * (20)*(20) = 3000J

A 5 kilograms bowling ball is dropped out a window. It hits the ground, and bounces upward. The velocity change of the ball is noted to be 15 m/s downward and 12 m/s upward. What is the contact time for the ball if the force applied on the ball from the ground is equal to 10 N?

Answers

Answer:

13.5

Explanation:

Mass: 5kg

Initial Velocity: -15

Final Velocity: 12

Force: 10

We can use the equation: Vf = Vi + at

We need to find acceleration, and we can use the equation, F=ma,

We have mass and the force so it would look like this, 10=5a, and 5 times 2 would equal 10, so acceleration would be 2.

Now we have all the variables to find time.

Back to Vf = Vi + at, plug the numbers in, 12 = -15 + 2(t)

Plugging them in into desmos gives 13.5 for time.

A new ride being built at an amusement park includes a vertical drop of 79.8 meters. Starting from rest, the ride vertically drops that distance before the track curves forward. If friction is neglected, what would be the speed of the roller coaster at the bottom of the drop?

Answers

Answer:

Approximately \(39.6\; {\rm m\cdot s^{-1}}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\).)

Explanation:

Under the assumptions, vertical acceleration of the vehicle during the ride would be equal to the gravitational field strength: \(a = g = 9.81\; {\rm m\cdot s^{-2}}\).

Apply the following SUVAT equation to find the velocity of the vehicle at the bottom of the drop:

\(v^{2} - u^{2} = 2\, a\, x\),

Where:

\(v\) is the final velocity at the bottom of the drop;\(u\) is the initial velocity at the beginning of the drop; \(u = 0\; {\rm m\cdot s^{-1}}\) since the vehicle started from rest;\(a = g = 9.81\; {\rm m\cdot s^{-2}}\) is the vertical acceleration of the vehicle during the drop;\(x = 79.8\; {\rm m}\) is the vertical displacement of the vehicle during the drop.

Rearrange this equation to find \(v\):

\(\begin{aligned}v &= \sqrt{u^{2} + 2\, a\, x} \\ &\approx \sqrt{0^{2} + 2\, (9.81)\, (79.8)} \; {\rm m\cdot s^{-1}} \\ &\approx 39.6\; {\rm m\cdot s^{-1}}\end{aligned}\).

Hence, the speed of this vehicle at the bottom of the drop would be approximately \(39.6\; {\rm m\cdot s^{-1}}\).

Respond to all of the following in a minimum of 175 words
- Visualization is a powerful tool to have in your motivation toolbox. For this week’s My Vision Board and Reflection Worksheet assignment, you will take time to visualize your goals, not just the outcome, but each step to get there. Do you see a relationship between the process and practice of visualizing and maintaining motivation? Explain how you perceive the relationship or lack of it.

-Self-discipline is taking personal responsibility of your willingness and desire to finish tasks and reach your goals. The readings discussed several ways to increase your level of self-discipline. Which of the strategies discussed this week do you think you will use to increase your level of self-discipline in your life? Share a bit about why you think those strategies will work best for you.

Answers

Visualizing your objectives aids in sustaining inspiration by making your ambitions more perceptible and attainable.

Why is this important?

By contemplating the actions required to reach a desired outcome, individuals can foster lucidity and guidance, thereby pleasing them with determination for moving forward. Additionally, focusing on the process of accomplishment through visualization helps divide the steps needed to attain those objectives, thus reducing their complexity, making it less menacing, and rendering them easier to achieve.

Various strategies towards increasing self-discipline were also proposed: setting apparent goals, creating schedules, sidestepping enticement, and practicing mindfulness amongst others.

Personally, I find that determining clear-cut aims and scheduling activities are the most productive tactics to pursue. This approach establishes definite targets and creates an environment that favors concentration whereby dedicating time for working towards set purposes becomes convenient.

This system constructs accountability while instilling discipline as daily progression is made toward target achievements during scheduled times - this encourages further motivation and commitment.

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Note that this prompt has to do with Vision Setting, motivation and Self Discipline.

What is the explanation for the above?

The connection between maintaining motivation and visualization is undeniable. Visualization involves the creation of a mental image that represents your desired outcome, allowing you to keep your eyes on the prize, which helps increase motivation levels.

Note that, breaking down the steps needed to achieve your goals through visualization can make the process less daunting while ensuring consistent progress towards success. Mental checkpoints where achievements are recognized further strengthen one's resolve, thus fueling motivation for even greater accomplishments.

Developing self-discipline is crucial and comes with various techniques for improving it. Optimizing productivity can sometimes be challenging for individuals like myself who struggle with distractions while working.

Fortunately, creating a detailed schedule has always been an effective solution for managing such situations. By factoring-in designated time slots within this timetable per individual tasks, focusing intently can be achieved without succumbing to environmental disturbances experienced in regular work environments.

To additionally promote personal drive during these sessions of focus-creation we should endeavor attainable objectives which will boost our overarching mission amid these intentional work segments.

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A crate with a mass of 35.0 kg is pushed with a horizontal force of 150 N. The crate moves at a constant speed across a level, rough surface a distance of 5.85 m

A crate with a mass of 35.0 kg is pushed with a horizontal force of 150 N. The crate moves at a constant

Answers

(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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please help oooooooo

please help oooooooo

Answers

Answer: Can't see clearly.

Explanation:

Nowton's third law refers to 'action reaction forces*. These forces are
always:

Answers

equal in magnitude but opposite in direction

Which of the following is NOT true about the mass of an object?

A)
Mass is measured in kilograms.
B)
Mass is a measurement of force.
C)
Mass is a measurement of the amount of matter in an object.
D)
Mass does not change based on your location.

Answers

Answer:

B) Mass is a measurement of force

Explanation:

Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.

Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105

. The figure illustrates the configuration.

A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.

Answers

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Which correctly describes latent heat?

A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid

Answers

Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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A fairgrounds ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has a 9.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose magnitude is 1.80 times that due to gravity

Answers

Answer:

13.37 rev/min

Explanation:

acceleration due to gravity (g) = 9.8 m/s², centripetal acceleration (\(a_c\)) = 1.8 * g = 1.8 * 9.8 m/s² = 17.64 m/s².

r = 9 m

Centripetal acceleration (\(a_c\)) is given by:

\(a_c=\frac{v^2}{r} \\\\v=\sqrt{a_c*r} \\\\v=\sqrt{17.64\ m/s^2*9\ m}\\\\v=12.6\ m/s\)

The velocity (v) is given by:

v = ωr;  where ω is the angular velocity

Hence:

ω = v/r = 12.6 / 9

ω = 1.4 rad/s

ω = 2πN

N = ω/2π = 1.4 / 2π

N = 0.2228 rev/s

N = 13.37 rev/min



Which statement describes a question that can guide the design of a

scientific investigation?

A. It asks about a cause-and-effect relationship between two

variables.

B. It asks about how the observations will be organized,

C. It asks about whether a controlled variable is necessary.

D. It asks about the preferred outcome of the investigation.

Answers

Answer:

The correct answer is:

It asks about a cause-and-effect relationship between two variables (A)

Explanation:

Scientific investigations are aimed as developing a hypothesis and proving the validity or not of the hypothesis developed. In order for these hypotheses to be tested, experiments must be done, and the experiments are designed based on the identification of a cause-and-effect relationship existing between two variables to be tested, where the "cause" is varied to various degrees and the "effect" of the variation is recorded. Therefore, knowing the cause-and-effect relationship will guide the experimental design, which will be aimed at manipulating the causes to see how these manipulations affect the second variable.

Answer:

A

Explanation:

An object of mass 1 kg is dropped from a table of height 1 m. If you represent the motion by drawing velocity and acceleration vectors of the object at 10 cm intervals below the table, which of the following statements are true?
The velocity vector at 50 cm is shorter than the one at 80 cm away from the table.
The acceleration vector is the same, both at 50 cm and 80 cm away from the table.

Answers

A 1 m-high table drops an object with a mass of 1 kg. This acceleration vector is identical at 50 cm and 80 cm distant the table if you depict the motion by sketching the object's velocities and accelerations vectors.

What are vectors of acceleration and velocity?

A vector quantity with direction is velocity. The velocity vector's direction is always parallel to the object's motion. Acceleration direction: The vector quantity of acceleration has a direction.

What are vectors of acceleration?

This acceleration vector, which represents the instantaneous acceleration, may be found by taking the velocity function's derivative with respect to time, as we saw in the previous chapter. The fact that they are essentially vector quantities is the only variation in either two or three dimensions.

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A basketball player jumps straight up for a ball. To do this, he lowers his body 0.250 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.960 m above the floor. (a) Calculate his velocity (in m/s) when he leaves the floor. 4.33 Correct: Your answer is correct. m/s (b) Calculate his acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.250 m.

Answers

Answer:

a. 3.73 m/s b. 27.8 m/s²

Explanation:

(a) Calculate his velocity (in m/s) when he leaves the floor.

Using the conservation of energy principles,

Potential energy gained by basketball player = kinetic energy loss of basket ball player

So, ΔU + ΔK = 0

ΔU = -ΔK

mg(h' - h) = -1/2m(v'² - v²)

g(h' - h) = -1/2(v'² - v²) where g = acceleration due to gravity = 9.8 m/s², h' = 0.960 m, h = 0.250 m, v' =0 m/s (since the basketball player momentarily stops at h' = 0.960 m) and v = velocity with which the basketball player leaves the floor

Substituting the values of the variables into the equation, we have

9.8 m/s²(0.960 m - 0.250 m) = -1/2((0 m/s)² - v²)

9.8 m/s²(0.710 m) = -1/2(-v²)

6.958 m²/s² = v²/2

v² = 2 × 6.958 m²/s²

v² = 13.916 m²/s²

v = √(13.916 m²/s²)

v = 3.73 m/s

(b) Calculate his acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.250 m.

Using v² = u² + 2as where u = initial speed of basketball player before lengthening = 0 m/s, v = final speed of basketball player after lengthening = 3.73 m/s, a = acceleration during lengthening and s = distance moved during lengthening = 0.250 m

So, making, a subject of the formula, we have

a = (v² - u²)/2s

Substituting the values of the variables into the equation, we have

a = ((3.73 m/s)² - (0 m/s)²)/(2 × 0.250 m)

a = (13.913 m²/s² - 0 m²/s²)/(0.50 m)

a = 13.913 m²/s²/(0.50 m)

a = 27.83 m/s²

a ≅ 27.8 m/s²

A student using a stopwatch finds that the time for 10 complete orbits of a ball on the end of a string is 25 seconds. The period of the orbiting ball is​

Answers

Answer:

T = 2.5 s

Explanation:

Given that,

Number of complete orbits = 10

Time, t = 25 seconds

We need to find the period of the orbiting ball. Let it is T. We know that number of oscillations per unit time is called frequency and the reciprocal of frequency is called period of the ball.

So,

\(T=\dfrac{t}{n}\\\\T=\dfrac{25}{10}\\\\T=2.5\ s\)

So, the period of the orbiting ball is equal to 2.5 seconds.

A 0.0780 kg lemming runs off a
5.36 m high cliff at 4.84 m/s. What
is its potential energy (PE) when it
lands?

Answers

The potential energy of the lemming when it lands is 0.9108672 J.

To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

Given:

Mass of the lemming (m) = 0.0780 kg

Height of the cliff (h) = 5.36 m

First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:

PE = mgh

PE = 0.0780 kg * 9.8 m/s² * 5.36 m

PE = 0.413616 J

Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.

Given:

Velocity of the lemming (v) = 4.84 m/s

Calculating the kinetic energy, we have:

KE = (1/2) * 0.0780 kg * (4.84 m/s)²

KE = 0.9108672 J

According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.

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It is important that a frame of reference

Answers

Answer:

enable us to take in a wide variety of information, and process it based on our past experience and values.

Explanation:

What is a pendulum?

A.)A pendulum is a grandfather clock.

B.)A pendulum is a mass suspended on the bottom of a string.

C.)A pendulum is several weights tied together and arranged in a circle.

D.) A pendulum is the time it takes for a bob to swing back and forth one time.

Answers

B) A pendulum is a mass suspended on the bottom of a string.

A pendulum is a simple mechanical device that consists of a mass (known as the bob) suspended from a fixed point by a string, wire, or rod. When the bob is pulled to one side and released, it swings back and forth under the influence of gravity, forming a regular pattern of motion. The time it takes for the pendulum to complete one full swing (i.e., from one extreme position to the other and back again) is known as its period. The period of a pendulum is affected by the length of the string and the strength of gravity. The longer the string, the longer the period, and the stronger the gravity, the shorter the period.Pendulums have a wide range of practical applications, such as timekeeping, as seen in grandfather clocks. They are also used in scientific experiments to measure time intervals and gravitational acceleration.

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You move a box 5 meters and perform 900 joules of work. How much force did you apply to the box?

Answers

You applied a force of 180 Newtons to move the box 5 meters and perform 900 Joules of work.


How much force is applied to the box?

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force.

It is equal to the force (F) applied multiplied by the distance (d) moved in the direction of the force.

The formula for work done is:

W = F × d

Rearranging the formula, we get:

F = W ÷ d

Given that;

Distance d = 5mWork W = 900JForce F = ?

Substituting the given values, we get:

F = W ÷ d

F = 900 J ÷ 5 m

F = 180 N

Therefore, the force applied is 180 Newtons.

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why does pure water increase in volume when heated​

Answers

Answer:

Pure water increases in volume when heated due to the phenomenon of thermal expansion. When water is heated, the kinetic energy of its molecules increases, causing them to move faster and spread out. This increased molecular movement leads to an increase in the average distance between water molecules, resulting in an expansion of the water.

Explanation:

.......

Which statement is true about the theory of plate tectonics and the theory of continental drift?

A) The theory of plate tectonics proves the theory of continental drift completely wrong.

B) The theory of plate tectonics tells exactly where the continents were before Pangaea divided.

C) The theory of plate tectonics gives the method by which continents can move as part of plates.

D) The theory of plate tectonics does not explain how continental movements could occur.

Answers

The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

What is theory of plate tectonics and the theory of continental drift ?

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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A box is being pushed to the left across a flat and rough surface. Which is a correct description of the forces acting on the box?

A.
The only force acting on the box is the pushing force.
B.
A force is pushing the box to the left, and the force of friction is also pushing the box to the left.
C.
The only force acting on the box is the force of friction.
D.
A force is pushing the box to the left, and the force of friction is pushing the box to the right.

Answers

A force is pushing the box to the left, and the force of friction is also pushing the box to the left. Hence option B is correct.

What is friction?

Friction is defined as the force preventing sliding solid surfaces, fluid layers, and material components from moving relative to one another. When two bodies come into touch and move in relation to one another, they experience friction, a resistive force.

A heavy box that you push will push back at you with an equal and opposite force, thus the harder you push, the stronger the reaction will be until you push hard enough to start the box sliding. An external force known as friction acts counter to the direction of motion.

Thus, a force is pushing the box to the left, and the force of friction is also pushing the box to the left. Hence option B is correct.

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The diagram shows an electromagnet made with copper wire, a steel nail,
and a 1.5 V battery. Which change would make this electromagnet weaker?

A. Reverse the direction of the battery

B. Rap more coils around the nail

C. Replace the steel nail with a wooden stick

D. Replace the battery with a 3V battery

Correct answer is C

Answers

If an electromagnet is made with copper wire, a steel nail, and a 1.5 V battery then replacing the steel nail with a wooden stick would make this electromagnet weaker, therefore the correct answer is option C.

What is electromagnetic force?

It is a type of force that occur between electrically charged particles. The electromagnetic force is the combination of all the electrical and magnetic forces generated by any charged particle.

As given in the problem statement diagram shows an electromagnet made with copper wire, a steel nail, and a 1.5 V battery, then we have to find out which change would make this electromagnet weaker,

Hence, By replacing the steel nail with a wooden stick would make this electromagnet weaker, therefore the correct answer is option C.

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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?

Answers

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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If the instantaneous voltage at a given moment in the circuit RL is V=VmaxSIN(150), then the instantaneous current at the...... same instant I=Imaxsin​

Answers

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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Sometimes a website with the extension ".com" is reliable, and sometimes it
is not. Which of the following characteristics might suggest that a site is
presenting biased information?

Answers

Characteristics that suggest biased information on a website include extreme language, lack of sources or references, advertising/ sponsorship, lack of balance/diversity, and author/publisher bias.

Biased information refers to information that is presented in a partial, one-sided, or prejudiced manner. It is characterized by an intentional or unintentional skew in the presentation of facts, with the aim of promoting a particular agenda, viewpoint, or belief. Biased information may be presented in a way that is misleading, inaccurate, or incomplete, and can be found in various forms of media, including news articles, advertisements, political propaganda, and social media posts. It is important to be aware of biased information and to seek out multiple sources of information in order to form an accurate and well-rounded understanding of a topic.

There are several characteristics that might suggest that a website is presenting biased information, including:

1. Extreme or emotionally charged language: Websites that use overly emotional or sensational language are often trying to manipulate readers' emotions rather than presenting objective information.

2. Lack of sources or references: Websites that do not provide sources or references to back up their claims may be presenting biased or false information.

3. Advertising or sponsorship: Websites that are heavily sponsored by a particular company or organization may be biased towards that company's interests.

4. Lack of balance or diversity: Websites that only present one perspective or point of view may be biased towards that perspective.

5. Author or publisher bias: Websites that are authored or published by individuals or organizations with a known bias towards a particular topic may be presenting biased information.

Therefore, Characteristics that suggest biased information on a website include extreme language, lack of sources or references, advertising/ sponsorship, lack of balance/diversity, and author/publisher bias.

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