2. In extraction of caffeine from tea, CaCO3 (pKa of HCO3- is 10.3) is used to convert tannin to glucose and calcium salt of gallic acid. Explain why glucose is not in its salt form but gallic acid is. Assuming pKa of -OH of glucose is 12, and pKa of -OH of gallic acid is 9.5 and pKa of -COOH of gallic acid is 4.5.

Answers

Answer 1

In the extraction of caffeine from tea, CaCO3 (pKa of HCO3- is 10.3) is used to convert tannin to glucose and a calcium salt of gallic acid. The glucose is not in its salt form but gallic acid is.

This can be explained as follows: When CaCO3 reacts with the tannins present in tea, it converts the tannins to glucose and a calcium salt of gallic acid. The calcium salt of gallic acid is a water-insoluble compound and precipitates out of the solution. On the other hand, glucose is a water-soluble compound and remains in the solution. This is why glucose is not in its salt form but gallic acid is. Additionally, the pKa values of glucose, gallic acid, and its derivatives also contribute to their solubility behavior in the given extraction process.

The pKa values of glucose, gallic acid, and its derivatives help in understanding how these compounds behave in the given extraction process. For example, the pKa of the -OH of glucose is 12, which means it has a higher tendency to remain in the water-soluble form as H+ is not easily released from the -OH group. Similarly, the pKa of the -OH of gallic acid is 9.5, which also indicates that it will remain in the water-soluble form as H+ is not easily released from the -OH group. The pKa of the -COOH group of gallic acid is 4.5, which means that in the given extraction process, it will lose its proton and form a salt with calcium ions. This salt of gallic acid is insoluble in water and precipitates out of the solution. Therefore, only gallic acid is in its salt form in the extraction process.

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Related Questions

If 80 g of magnesium react with 100 g of sulphur, how many grams of magnesium sulphide are formed

Answers

Approximately 175.3 grams of magnesium sulfide are formed. To determine the number of grams of magnesium sulfide formed, we need to first determine the limiting reactant.

To do this, we calculate the number of moles for each reactant. The molar mass of magnesium is 24.31 g/mol, and the molar mass of sulfur is 32.06 g/mol.

For magnesium, we have:
80 g / 24.31 g/mol = 3.29 mol

For sulfur, we have:
100 g / 32.06 g/mol = 3.12 mol

From the calculation, we can see that sulfur is the limiting reactant, as it produces fewer moles than magnesium.

The balanced equation for the reaction between magnesium and sulfur is:
Mg + S --> MgS

According to the balanced equation, one mole of magnesium reacts with one mole of sulfur to form one mole of magnesium sulfide.

Since sulfur is the limiting reactant, we can conclude that 3.12 moles of magnesium sulfide are formed.

To determine the mass of magnesium sulfide formed, we can multiply the number of moles of magnesium sulfide by its molar mass. The molar mass of magnesium sulfide is 56.30 g/mol.

So, the mass of magnesium sulfide formed is:
3.12 mol x 56.30 g/mol = 175.3 g

Therefore, approximately 175.3 grams of magnesium sulfide are formed.

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Limestone is a naturally occurring form of calcium carbonate. The correct formula for
limestone is
O CaCO3
Ca3(CO3)2
*O Ca(CO3)2
O Ca2CO3

Answers

CaCO3 hhhhhhhhhhhhhh

I do not quite understand this, anyway someone can help? I'll give brainliest to the correct answer!

I do not quite understand this, anyway someone can help? I'll give brainliest to the correct answer!

Answers

To solve for number one we must follow these steps:

m = 703.55 g − 345.8 g

m = 357.75 g

Then we solve for the density-

d = 357.75 g / 225 mL

d = 1.59 g/mL

Answer for number 5) 1.59 g/mL

Density= Mass/Volume

therefor- Mass = 65.14g and Volume = 35.4mL

Density = 65.14g/35.4 mL = 1.84 g/mL

Answer for number 6) 1.84 g/mL

Question 7-

g = (0.8765 g/mL)(250.0 mL) = 219.1 g

Answer: 219.1 g

Question 8-

Density = mass/volume

Mass = 1587g

4.5cm x 5.2cm x 6cm = 140.4 cubic-cm

Volume = 140.4 cubic-cm

Mass/volume = 1587/140.4 = 11.3 g/cm^3

Answer: 11.3 g/cm^3

Question 9:

First calculate the volume of iron

49.10mL − 45.50mL = 3.60mL

Density = mass/volume;

density = 28.5g/3.60 mL= 7.92 g/mL

Answer: 7.92 g/mL

Question 10:

Volume = 2500.0g / 10.5g/cm3 = 238.095cm^3

Now we round up the answer to 238cm^3

Answer: 238cm^3

I hope this helped!

A 10% bleach solution for disinfecting countertops can be prepared by: a. weighing the bleach and the water b. weight to volume percentage c. adding 10 mL bleach to 90 mL water d. adding 10 mL bleach to 990 mL water

Answers

Answer:

The correct answer is - c. adding 10 mL bleach to 90 mL water.

Explanation:

To prepare a effective disinfecting solution to clean the countertops is a bleasce solution of 10% solution of bleach. The ten percent of the bleach solution means there are one volve of bleach and 9 volume of clean water in this solution.

So, preparing the 1/10 or ten percent solution is where adding 10 ml of bleach which is diluted to 90 ml clean water. This diluted solution can be use as disinfecting solution.

what is the major organic product obtained from the addition reaction of hcl to 3-methyl-1-butene? group of answer choices 1-chloro-2-methylbutane 1-chloro-3-methylbutane 2-chloro-2-methylbutane 2-chloro-3-methylbutane 1-chloropentane

Answers

The major organic product obtained from the addition reaction of HCl to 3-methyl-1-butene is 2-chloro-3-methylbutane. Option d is correct.

The reaction mechanism involves the electrophilic addition of HCl to the double bond of the 3-methyl-1-butene, leading to the formation of a carbocation intermediate. The H⁺ ion from HCl acts as an electrophile, attacking the double bond and forming a carbocation on the tertiary carbon. The chloride ion then acts as a nucleophile, attacking the carbocation and forming the final product.

The addition of HCl to the double bond results in the formation of two possible carbocation intermediates, one on the primary carbon and the other on the tertiary carbon. However, the more stable tertiary carbocation intermediate is formed faster and is favored under the reaction conditions. The chloride ion then attacks the tertiary carbocation, resulting in the formation of the product, 2-chloro-3-methylbutane. Option d is correct.

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For the balanced equation shown below, if the reaction of 91.3 grams of C3H6 produces a 73.3% yield, how many grams of CO2 would be produced?

2C3H6+9O2=>6CO2+6H2O

Answers

Answer: The answer is 233.3 g

Explanation: The problem is, do you trust me?

Why type of data must be plotted on a graph for the slope of the line to represent density?

Answers

Answer:

you need data that has at least one independent variable in order to plot a graph for a slope of the line

Explanation:

the citric acid cycle is classed as a reductive pathway as it produces reduced electron carriers. true or false

Answers

The statement "The citric acid cycle is classed as a reductive pathway as it produces reduced electron carriers" is true.

The citric acid cycle, also known as the Krebs cycle or the tricarboxylic acid cycle, is a central metabolic pathway in cellular respiration. This pathway generates reduced electron carriers, specifically NADH and FADH2, which are essential for the production of energy through the electron transport chain.

In the citric acid cycle, acetyl-CoA, derived from carbohydrates, fats, or proteins, is combined with oxaloacetate to form citrate. Through a series of enzyme-catalyzed reactions, citrate is then converted back to oxaloacetate, releasing two molecules of carbon dioxide and generating three molecules of NADH, one molecule of FADH2, and one molecule of ATP or GTP. The reduced electron carriers, NADH and FADH2, transport high-energy electrons to the electron transport chain, where they ultimately contribute to the production of ATP via oxidative phosphorylation.

In conclusion, the citric acid cycle is indeed a reductive pathway as it produces reduced electron carriers, NADH and FADH2, which are crucial for cellular energy production. This pathway is a key component of cellular respiration and plays an essential role in generating energy for various cellular processes.

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10.0 grams of argon and 20.0 grams of neon are placed in a 1200.0 ml container at 25.0 C The partial pressure of neon is atm. A) 0.700 B) 8.70 C) 20.4 D) 3.40 E) 5.60 9) Consider the following reaction at equilibrium: 2002 (g) ? 2CO (g) + O2 (g) ?1°=-514k) Le Chatelier's principle predicts that adding O2 (g) to the reaction container will A) increase the partial pressure of CO (g) at equilibrium B) decrease the partial pressure of CO2 (9) at equilibrium C) increase the partial pressure of CO2 (g) at equilibrium D) decrease the value of the equilibrium constant E) increase the value of the equilibrium constant 0) The purpose of the salt bridge in an electrochemical cell is to A) provide a source of ions to react at the anode and cathode. B) provide oxygen to facilitate oxidation at the anode. C) provide a means for electrons to travel from the anode to the cathode. D) maintain electrical neutrality in the half-cells via migration of ions. E) provide a means for electrons to travel from the cathode to the anode.

Answers

D). The total pressure of the gas mixture is given as 1.04 atm. The amount of neon and argon is given as 20.0 g and 10.0 g respectively. We can use the formula;PAr = XAr × PTandPN= XN × PTWhere,PAr = partial pressure of argonXAr = mole fraction of argonPN= partial pressure of neonXN= mole fraction of neonPT= total pressure of the mixture.

Since we have to calculate the partial pressure of neon, we have to find the mole fraction of neon first.The mole fraction of neon (XN) can be calculated as:XN= number of moles of neon/total number of molesNumber of moles of neon can be calculated as:20.0gNe= molar mass of neon = 20.18 g/mol= 0.991 moles of neonNumber of moles of argon can be calculated as:10.0gAr= molar mass of argon = 39.95 g/mol= 0.250 moles of argonTotal number of moles in the mixture = 0.991 + 0.250= 1.241 moles of the mixtureMole fraction of neon = 0.991/1.241= 0.798The mole fraction of argon can be calculated as:XAr= 1 - XN= 1 - 0.798= 0.202Partial pressure of neon can be calculated as:PN= XN × PT= 0.798 × 1.04= 0.830 atmTherefore, the partial pressure of neon is 0.830 atm.

The balanced chemical reaction is given as:2CO(g) + O2(g) ⇌ 2CO2(g) The equilibrium constant (K) can be written as:K= [CO2]2/([CO]2[O2])If we add more oxygen to the reaction container, according to Le Chatelier's principle, the system will shift in the direction to reduce the excess of the added component. Thus, the concentration of O2 will decrease, and the concentration of CO and CO2 will increase, in order to maintain the equilibrium.The partial pressure of CO2 will increase, and the partial pressure of CO will also increase. However, the partial pressure of O2 will decrease. Thus, option (C) is the correct answer.Question 3The purpose of the salt bridge in an electrochemical cell is to maintain electrical neutrality in the half-cells via migration of ions. The salt bridge consists of an inverted U-tube containing an electrolyte, which allows the flow of ions between the half-cells. It completes the electrical circuit and balances the charges produced in the anode and cathode half-cells.  

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The primary way in which the amount of carbon dioxide in the atmosphere can be increased is by ____.

Answers

the burning of fossil fuels

When mixing 5.0 moles of HZ acid with water up to complete a volume of 10.0 L, it is found that at
reach equilibrium, 8.7% of the acid has become hydronium. Calculate Ka for HZ. (Note: Do not assume is disposable. )a. 1.7×10^−3
b. 9.5×10^−2
C. 2.0×10^−2
d. 4.1×10^−3
e. 3.8×10^−3
f. 5.0×10^−1

Answers

therefore the correct option is d) 4.1×10⁻³.

Given that the initial concentration of HZ is 5.0 moles and at equilibrium, 8.7% of the acid has become hydronium.

The concentration of HZ that has not reacted is (100% - 8.7%) = 91.3%.

The final concentration of HZ is 5.0 × 0.913 = 4.565 moles.

The final concentration of the hydronium ion is 5.0 × 0.087 = 0.435 M.HZ ⇌ H+ + Z-Ka

= [H+][Z]/[HZ]Ka

= [H+][Z]/[HZ]

= [0.435]² / 4.565

= 0.041

Which is the same as 4.1 × 10-3.

We know that HZ is an acid that will partially ionize in water to give H+ and Z-.

The chemical equation for this reaction can be written as HZ ⇌ H+ + Z-.

The acid dissociation constant (Ka) of HZ is the equilibrium constant for the reaction in which HZ ionizes to form H+ and Z-.Thus, Ka = [H+][Z]/[HZ].

The given problem is a typical example of the dissociation of a weak acid in water. We are given the initial concentration of HZ and the concentration of hydronium ions at equilibrium.

To find the equilibrium concentration of HZ, we can use the fact that the total amount of acid is conserved.

At equilibrium, 8.7% of HZ has dissociated to give hydronium ions.

This means that 91.3% of the original HZ remains unreacted.

Therefore, the concentration of HZ at equilibrium is 5.0 × 0.913 = 4.565 M.

The concentration of hydronium ions at equilibrium is 5.0 × 0.087 = 0.435 M.

Using the equation Ka = [H+][Z]/[HZ], we can substitute the values of the concentrations and the equilibrium constant into the equation and solve for Ka.

Ka = [H+][Z]/[HZ]

= [0.435]² / 4.565

= 0.041 or 4.1 × 10-3.

The answer is d) 4.1 × 10-3.

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Given subsets A and B of Ω, identify all sets in σ(A,B).

Answers

The sets in σ(A,B) are the smallest σ-algebra that contains both A and B.

In probability theory and measure theory, a σ-algebra is a collection of subsets of a given set Ω that satisfies certain properties. The notation σ(A,B) represents the smallest σ-algebra that contains both subsets A and B. This means that σ(A,B) consists of all possible subsets that can be formed by taking the union, intersection, and complement of sets in A and B.

To understand this concept better, let's consider an example. Suppose we have a set Ω = {1, 2, 3, 4} and two subsets A = {1, 2} and B = {2, 3}. The σ-algebra σ(A,B) would include the empty set, the set Ω itself, as well as other subsets such as {1}, {2}, {3}, {1, 2}, {2, 3}, and {1, 2, 3}. It would also include their complements, for example, the complement of {1} would be {2, 3, 4}.

The σ-algebra σ(A,B) is important in probability theory as it allows us to define probability measures and study various properties of events and random variables. By identifying all the sets in σ(A,B), we can determine the range of events that can be analyzed within this framework.

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Will give brainliest

process name of liquid bromine to bromine vapor

Answers

Answer:

evaporation, vaporisation, boiling if change occurs at boiling point

Explanation:

Please mark brainliest

Diffusion is the name of process that , happens in liquids and solids ( Atomic diffusion ) as well although in solids it is a very slow process.ln liquids it is quicker, imagine putting a drop of dye into a bowl of clear water, after a while all the water will be colored.

Brown fumes of bromine vapour spread through the whole glass jar because of phenomenon of diffusion in the glass jar.

The gasses gases show the property of moving continuously in the air that's why Brown fumes of bromine vapour spread through the glass jar.




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The chemical equation S + 02 - S02 is an example of which type of reaction?
Single displacement
Combination
Double displacement

Answers

This example is a type of combination

g sio2 is a(n) covalent network solid. ki is a(n) -- solid. ti is a(n) -- solid. c6h12o6 is a(n) -- solid.

Answers

The kinds of the solids are;

SiO2 - Covalent network solid

C6H12O6 - Covalent solid

KI - Ionic solid

What is a covalent network solid?

A covalent network solid, often referred to as a network covalent solid or just a network solid, is a category of solid material in which the atoms that make up the material are strongly covalently linked to one another, forming an extended three-dimensional network structure.

Covalent network solids are kept together by a dense network of covalent bonds, as opposed to molecular or ionic solids, which are held together by weaker intermolecular forces or ionic interactions, respectively.

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What is the Pauli Exclusion Principle?
An atomic orbital can only hold a maximum of 2 electrons, each with opposite spins
An atomic orbital can hold a minimum of 6 electrons, each with opposite spins
An atomic orbital can hold a maximum of 6 electrons, each with the same spin
An atomic orbital can hold a minimum of 2 electrons, each with opposite spins

Answers

Pauli Exclusion Principle, states that an atomic orbital can only hold maximum of 2 electrons, each with opposite spins. So, the correct choice is option (a).

The Pauli Exclusion Principle is a quantum mechanical principle that states that no two electrons in the same atom can have the same value for all four quantum numbers. That is no more than two electrons in can occupy the same orbital, and two electrons in the same orbital in must have opposite spins.

Austrian, Wolfgang Pauli proposed this idea in 1925. After reading a paper on quantum states in 1924, Pauli decided to add a fourth value to the classical three values used to describe the state of electrons. Two other scientists, Samuel Goudsmit and George Uhlenbeck, defined the fourth quantum quantity as the electron's spin. So option (a) is the correct option.

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Complete question:

What is the Pauli Exclusion Principle?

a) An atomic orbital can only hold a maximum of 2 electrons, each with opposite spins.

b) An atomic orbital can hold a minimum of 6 electrons, each with opposite spins

c) An atomic orbital can hold a maximum of 6 electrons, each with the same spin

d) An atomic orbital can hold a minimum of 2 electrons, each with opposite spins

If you recall from unit 2, there are three kinds of mixtures - solutions, colloids and suspension. A solution iss different from the other two because ___

Answers

The particles of the solution is smaller than that of the colloids and suspension.

How are solutions different from colloids and suspensions?

Solution has the smallest particle, and the particles of solution are uniformly distributed and too small in which light can difficultly scatter. Colloids have larger particles than the solution and colloids can scatter light but do not settle out. Suspensions have the largest particles from both solution and colloids. Particles in solution is tinier than that of colloids. The particles in solution can not be seen in microscope, while the particles in colloids can be seen with the microscope.

So we can conclude that: The particles of the solution is smaller than that of the colloids and suspension.

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Yoshi divided the mass of a rubber stopper by its volume. Using this calculation, Yoshi found the
of the stopper
A
force
B
density
С.
weight
D
buoyancy

Answers

B. Density

Density = mass/volume because it’s basically the concentration of mass. How much matter takes up the space. If you pack more matter into less space, it is more dense.

what is the role of oxygen in the functioning of the electron transport chain? write a reaction that summarizes the fate of the oxygen?

Answers

The role of oxygen in the functioning of the electron transport chain (ETC) is to act as the final electron acceptor.

It accepts electrons at the end of the electron transport chain, which allows the ETC to continue operating and generate ATP through oxidative phosphorylation.

During aerobic respiration, oxygen combines with electrons and protons to form water in the following reaction:

1/2 O2 + 2 H+ + 2 e- → H2O

This reaction summarizes the fate of oxygen as it accepts electrons and protons from the ETC. The oxygen molecules are reduced to form water, which is a byproduct of aerobic respiration.

This process is crucial for the efficient production of ATP in aerobic organisms. Without oxygen as the final electron acceptor, the electron transport chain would not be able to function properly, leading to a decrease in ATP production and an impairment of cellular energy metabolism.

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When 60.0 g of carbon is burned in 160.0 g of oxygen, 220.0 g of carbon dioxide is formed. what mass of carbon dioxide is formed when 60.0 g of carbon is burned in 750.0g of oxygen?

Answers

When 60.0 g of carbon is burned in 160.0 g of oxygen, 220.0 g of carbon dioxide is formed. 60.0 g mass of carbon dioxide is formed when 60.0 g of carbon is burned in 750.0g of oxygen.

To solve this problem, we can use the concept of stoichiometry and the balanced chemical equation for the combustion of carbon to form carbon dioxide. The balanced equation is as follows:

C + O₂ → CO₂

According to the equation, one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide.

Calculate the number of moles of carbon and oxygen in the given scenario:

Molar mass of carbon (C) = 12.01 g/mol

Molar mass of oxygen (O₂) = 32.00 g/mol (16.00 g/mol × 2)

Number of moles of carbon = Mass of carbon / Molar mass of carbon

Number of moles of carbon = 60.0 g / 12.01 g/mol = 4.998 mol (rounded to three decimal places)

Number of moles of oxygen = Mass of oxygen / Molar mass of oxygen

Number of moles of oxygen = 750.0 g / 32.00 g/mol = 23.438 mol (rounded to three decimal places)

Since the balanced equation shows a 1:1 ratio between carbon and carbon dioxide, we can infer that 4.998 moles of carbon will produce 4.998 moles of carbon dioxide.

Now, using the molar mass of carbon dioxide (44.01 g/mol), we can calculate the mass of carbon dioxide produced:

Mass of carbon dioxide = Number of moles of carbon dioxide × Molar mass of carbon dioxide

Mass of carbon dioxide = 4.998 mol × 44.01 g/mol = 219.92 g (rounded to two decimal places)

Therefore, when 60.0 g of carbon is burned in 750.0 g of oxygen, approximately 219.92 g of carbon dioxide is formed.

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How many grams of sugar (C12H22011) is needed to make a 1.3 L solution that is 0.13 M?

Answers

The answer for this question would be 150
150...........................

Four examples of STIS​

Answers

Answer:

Chlamydia, gonorrhoeah, syphilis, and trichomoniasis

Explanation:

Answer:

The four examples of STIS

i)Chlamydiaii)Gonorrhoeaiii)Syphilisiv) Trichomoniasis


Activity 2: My Characteristics
Directions: After exploring the amazing asteroids, comets, and meteors, test yourself if you
can compare and differentiate the three: comets, meteors, and asteroids. Below are some
characteristics of comets, meteors, and asteroids (1-15).
Choose from the following (A-G), and write the letters before each characteristic in your
activity notebook.
A. if it refers to comets
B. if it refers to meteors
C. if it refers to asteroids
D. both comets and meteors
E. if it refers to both meteors and asteroids
F. if it refers to both asteroids and comets
G. if it refers to all (comets, meteors, and asteroid)
Characteristics:
1. Progress across the sky very slowly
2. Known as falling stars or shooting stars
3. Remnants of the formation of the solar system
4. They glow as they enter the earth's atmosphere
5. Reflect sunlight
6. Rocky composition
7. Orbit the sun in highly elliptical orbits s
8. Minor planets
9. Mostly found between Mars and Jupiter
10. Can reach 150 million km in length
11. Most have slightly elliptical orbits
12. The result from the collision of asteroids
13. Streak across the sky very fast
14. Come in all sizes and shapes
15. Icy object

Answers

Answers:

ABGBFEACCAGEBGA

Explanation:

Progress across the sky very slowly - This characteristic refers to cometsKnown as falling stars or shooting stars - This characteristic refers to meteorsRemnants of the formation of the solar system - This characteristic refers to all (comets, meteors, and asteroid)They glow as they enter the earth's atmosphere - This characteristic refers to meteorsReflect sunlight - This characteristic refers to both asteroids and cometsRocky composition - This characteristic refers to both meteors and asteroidsOrbit the sun in highly elliptical orbits - This characteristic refers to cometsMinor planets - This characteristic refers to asteroidsMostly found between Mars and Jupiter - This characteristic refers to asteroidsCan reach 150 million km in length - This characteristic refers to cometsMost have slightly elliptical orbits - This characteristic refers to all (comets, meteors, and asteroid)The result from the collision of asteroids - This characteristic refers to both meteors and asteroidsStreak across the sky very fast - This characteristic refers to meteorsCome in all sizes and shapes - This characteristic refers to all (comets, meteors, and asteroid)Icy object - This characteristic refers to comets

Why are we pulled to the center of the Earth and not into the much larger sun?

Answers

Answer:

The sun's gravity pulls on the earth, and the earth pulls back on the sun at the same time. This is why the center of the solar system is not the center of the sun. As one gravitational body gets bigger than the other, it circles closer to the center of the system (shown in red).

Explanation:

hope this helps...

The earth is known to be falling towards the sun as a result of intense gravity. The earth is known to have plenty of sideways momentum and due to this sideways momentum, the earth is often falling towards the sun and missing it.

The reason we are pulled to the center of the Earth and not into the much larger sun by gravity is that all objects with mass, like our Earth, do bend and curve the fabric of the universe referred to as spacetime.

At most, the gravity from the sun result in our planet moving in a curved, elliptical path. but, the planets are moving fast enough so that they are not pulled into the sun.

The sun has a more weaker gravity and as it loses mass, it causes the Earth to slowly move away from it.

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What can you conclude about the reactivity of metals as you move down a column or group in the periodic table.

Answers

Answer:

Reactivity increases down the group

Explanation:

This is because metals reaction involves loss of an electron from an occupied orbital.

As we go down the group the relative nuclear charge decreases due to an additional orbit leading to ease in loss of an electron

Due to ease in loss of electrons down the group metals become more reactive down the group

Enter the masses of these particles in kilograms. Express the masses of proton and neutron to six significant figures. Express the mass of electron to two significant figures. Enter your answers in kilograms.

Answers

The masses of proton ( in kilogram) = 1.67262 × 10−27 kg ( six significant figure).

The masses of neutron ( in kilogram) = 1.67493 × 10−27 kg  (six significant figure)The masses of electron ( in kilogram) = 9.1× 10−31 kg  (two significant figure)

Proton is a stable subatomic particle with symbols p, H+ or 1H+ and a positive charge of +1 e elementary charge. Its mass is slightly less than that of a neutron.

A neutron is a subatomic particle (symbol n or n⁰ ) with a neutral charge and a mass slightly greater than that of a proton. Protons and neutrons form the nucleus. Electrons, protons, and neutrons are the elementary particles that make up atoms. Atoms consist of a central nucleus containing neutrons and protons. Electrons revolve around the nucleus. Electrons are negatively charged, protons are positively charged, and neutrons are neutral. The electron mass is the mass of the rest electron, also known as the invariant mass of the electron.

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You check the air pressure in your car tires on Monday morning and the pressure
reads 765 mmHg. A cold front drops the temperature considerably overnight. You
check your tire pressure Tuesday morning and the pressure reads 740 mmHg.
Using what you've learned about the properties of gases, what causes this change
in pressure?

Answers

In warmer weather gases tend to expand and take up more room, thus increasing pressure. but in colder weather they will condense or contract and take up less space, therefore lowering the pressure of the tire in this situation.

The product of the pressure and the volume of one mole of a gas is equal to the product of the absolute temperature and the universal gas constant.

Answers

The rule that states the absolute temperature of a gases and the universal gas standard are equivalent to the product of the volume and the pressure of a single gram of an ideal gas.

What is an example of temperature in chemistry?

The associated with the motion energy of atoms or molecules as in system is measured by temperature. The water droplets in a hot cup coffee move more quickly than the hydrogen atoms in a cup of iced tea because the average kinetic energy of hot coffee is higher.

What factors in chemistry affect temperature?

The addition of energy (heating), which raises the temperature, increases the movement of atoms and molecules. By removing energy (cooling), atoms and molecules slow down and the temperature drops as a result.

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SOMEONE HELP PLS ILL GIVE BRAINLIEST AND 19 PT

SOMEONE HELP PLS ILL GIVE BRAINLIEST AND 19 PT

Answers

Sample left = 6.25 g

The percentage = 6.25%

Further explanation

Given

t1/2 = half-life = 3.8 days

t = decay time = 15.2 days

No = initial sample = 100 g

Required

Nt = final sample left

The percentage

Solution

General formulas used in decay:  

\(\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}\)

Input the value :

\(\tt N_t=100.\dfrac{1}{2}^{15.2/3.8}\\\\N_t=100.\dfrac{1}{2}^4\\\\N_t=6.25~g\)

The percentage : Nt/No

6.25 : 100 = 6.25%

the receptor sites of receiving neurons have been observed to increase following long-term potentiation ...

Answers

The receptor sites of receiving neurons have been observed to increase following option C: long term potentiation.

The process of long-term potentiation (LTP), which involves continuous synaptic strengthening, results in a sustained increase in signal transmission between neurons. In terms of synaptic plasticity, it is a significant process. LTP recording is a well-known cellular model for the investigation of memory.

LTP is common in cortical and hippocampal networks and demonstrates a number of characteristics needed for a large capacity information storage device. Learning is facilitated by pharmacological substances that promote LTP development, whereas learning is facilitated by pharmacological agents that inhibit LTP formation or gene mutations that interfere with LTP.

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Complete question is:

The receptor sites of receiving neurons have been observed to increase following: Answer

retrieval failure.

stress.

long-term potentiation.

imagination inflation.

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