Due to its complete reduction, the triacylglycerol containing the stearic acid residues produces more energy.
What is oxidation?
Oxidation refers to the loss of electrons experienced by a reactant during a process. Reduction is the process by which a reactant picks up electrons while undergoing a reaction. This occurs frequently when metals and acids interact. Oxidation refers to the loss of electrons experienced by a reactant during a process.
An atom, molecule, or ion oxidizes when a chemical reaction results in the loss of one or more electrons. The oxidation state of the chemical species increases during oxidation.
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Calculate the number of moles in a liquid sample of a substance that has a molar heat of fusion of 3.811 kJ/mol, if the sample releases 90.6 kJ when it freezes. Answer in units of mol Calculate the molar mass of the substance if the mass of the sample is 2022 g. Answer in units of g/mol.
Answer:
23.77mole,85.1g/mol
Explanation:
the moles of liquid is 23.77mole which is obtained by divide 90.6kj to 3.811kj/mol and molar mass is obtained from the formula of mole eg mole=mass/molar mass but mass is given and moles is obtained above.
When the molar mass of the significance of the mass of the sample is 2022 g is = 23.77mole, 85.1g/mol.
Calculation of Molar mass
When the molar mass of a chemical combination is defined as the mass of a sample of that compound separated by the amount of substance in that instance, measured in moles.
Although, The molar mass is a bulk, not molecular, property of a substance. The molar mass is an average of many instances of the combination, which often change in mass due to the existence of isotopes.
When the moles of liquid is 23.77mole which is received by dividing 90.6kj to 3.811kj/mol and molar mass is acquired from the formula of mole eg mole is = mass/molar mass but the mass is given and moles is conveyed above.
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Why is water so important for life?Why cant other substance made of hydrogen and oxygen like hydrogen peroxide take its place?
Answer:
Reasons water is important
Imagine earth without water. The soil, with no water in it and nothing growing on it, would be lifeless, dead, collapsed into dust, sand, clay or rock.
-Water consumption helps lubricate and cushion your joints, spinal cord, and tissues. This will help you enjoy physical activity and lessen discomfort caused by conditions like arthritis.
-Water is a main component of saliva. Saliva also includes small amounts of electrolytes, mucus, and enzymes. It’s essential for breaking down solid food and keeping your mouth healthy.
What’s the first change that occurs in your cookie dough after you put the pan in the oven?
Answer:
Butter melts.
Explanation:
1. Differentiate Physical and chemical changes of matter?
Which elements do not have the same number of atoms on both sides of the equation?
Na and O
H and S
Na and H
S and O
Answer: Na
Explanation:
on the left it says Na, and on the right it says Na2
Please give formulas of how you solved I only need help on a but if you can do all that I would appreciate that.
Answer:
3.1 moles of ammonia
18.67× 10²³ molecules
Mass = 52.7 g
Explanation:
Given data:
Number of atoms of hydrogen = 5.68×10²⁴ atoms
A) Number of molecules of ammonia = ?
Solution:
First of all we will calculate the number of moles of hydrogen.
1 mole = 6.022× 10²³ atoms
5.68×10²⁴ atoms × 1 mol / 6.022× 10²³ atoms
0.94×10¹ mol
9.4 moles of hydrogen
Moles of ammonia:
3 moles of hydrogen are present in one mole of ammonia.
9.4 moles of hydrogen = 1/3×9.4 =
3.1 moles of ammonia
Number of molecules of ammonia:
1 mole contain 6.022× 10²³ molecules.
3.1 mol × 6.022× 10²³ molecules / 1 mol
18.67× 10²³ molecules
c) Mass of sample = ?
Mass = number of moles × molar mass
Mass = 3.1 moles × 17 g/mol
Mass = 52.7 g
what will be the result of the reaction
(CH3COO)2+redP +Cl2
Answer:
(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl
Explanation:
This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.
Helpppppppppppppppppppppppppppppppppppppp
Answer:
Time and Distance
Explanation:
The equation needed to calculate speed is distance ÷ time.
Which statement below is true about vaporization?
A. Vaporization occurs when liquid changes to a solid.
B. Vaporization occurs when particles lose energy and become sold.
C. Vaporization occurs when there is an decrease in heat.
D. Vaporization occurs when liquid particles gain energy and "fly away" into a gas.
Answer:
Explanation:
D. Vaporization occurs with liquid particles gain energy and "fly away" into a gas.
Think of when you're boiling something on the stove.
Calcium solid is placed in a solution of iron (III) chloride producing calcium chloride and iron solid
Answer:
3Ca₍s₎ + 2FeCl₃ -------------------------------------------------------------> 3CaCl₂ + 2Fe₍s₎.
Explanation:
Iron(III) chloride is also known as Iron trichloride and it has the molar mass value of 162.2 g/mol and density of 2.9 g/cm³.
The balanced equation for the chemical reaction between solid calcium and iron (III) chloride is given below as:
3Ca₍s₎ + 2FeCl₃ -------------------------------------------------------------> 3CaCl₂ + 2Fe₍s₎.
This kind of chemical reaction is known as single displacement reaction or single replacement reaction.
Which statement would indicate the presence of an acid?.
The following statement would indicate the presence of an acid: If the substance tastes sour, it indicates the presence of an acid. A substance can be tested for its acidic or basic nature by using litmus paper. The paper is soaked in an acidic or basic solution and then dried. The paper's color will change when it comes into contact with a solution that is acidic or basic. The most frequent indicators are litmus, phenolphthalein, and methyl orange. An indicator is a weak organic acid or base that changes color when exposed to an acidic or basic solution. In general, an acid is described as a substance that has a sour taste, reacts with metals and carbonates to create hydrogen gas, and turns blue litmus paper red. An acid is a substance that donates protons (H+) or accepts electrons (e-) in a chemical reaction. Bases, on the other hand, have a bitter taste, feel slippery, and turn red litmus paper blue. When exposed to water, bases generate hydroxide ions (OH-). Acids and bases react with one another to produce salt and water in a neutralization reaction. In general, salts are ionic compounds made up of a cation from a base and an anion from an acid.
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A galvanic cell is powered by the following redox reaction: NO3(aq) 4H (aq) + 3 Cu (aq) NO(g) 2 HzO() 3 Cu2+(aq) Answer the following questions about this cell: If you need any electrochemical data, be sure you get it from the ALEKS Qata tab_ olo Write balanced equation for the half-reaction that takes place at the cathode_ Write balanced equation for the half-reaction that takes place at the anode. Calculate the cell voltage under standard conditions_ =Dv Round your answer to 2 decimal places_
1. The balanced equation for the half-reaction that takes place at the cathode from the redox reaction 2NO₃(aq) + 4H⁺(aq) + 3Cu(s) -> 2NO(g) + 4H₂O(l) + 3Cu²⁺(aq) is Cu⁺(aq) + 2e⁻ -> Cu(s).
2. The balanced equation for the half-reaction that takes place at the anode is 2NO₃⁻(aq) + 8H⁺(aq) + 6e⁻ -> 2NO(g) + 4H₂O(l).
3. The cell voltage under standard conditions is -0.62 V.
1. Cathode is the reduction electrode which gains electrons during the reaction. Therefore, Cu(s) is cathode since Cu²⁺(aq) is reduced to Cu(s). Thus, the half-reaction for the cathode is Cu²⁺(aq) + 2e⁻ -> Cu(s).
2. Anode is the oxidation electrode which loses electrons during the reaction. Therefore, NO₃⁻(aq) is anode since it gets oxidized to NO(g).The half-reaction for the anode is 2NO₃⁻(aq) + 8H⁺(aq) + 6e⁻ -> 2NO(g) + 4H₂O(l)
3. To find the cell voltage under standard conditions, we need to calculate the standard reduction potential (E°) of the cathode and the standard oxidation potential (E°) of the anode, and then find the difference.
E° cathode = +0.34 V (from electrochemical data)E° anode = +0.96 V (from electrochemical data)The cell voltage under standard conditions can be calculated as follows:
E°cell = E°cathode - E°anode
E°cell = (+0.34 V) - (+0.96 V)
E°cell = -0.62 V
Thus, the cell voltage under standard conditions is -0.62 V.
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A mixture of C2H6 and C3H8(YC2H6=0.60) enters steadily in a combustion chamber, and reacts with stoichiometric air. Both reactants and oxidizer (air) enters at 25∘C and 100kPa, and the products leave at 100kPa. The air mass flow rate is given as 15.62 kg/hr. The fuel mass flow rate (in kg/hr ) is, 0.68 0.78 0.88 0.98 1.08
A). The fuel mass flow rate is 0.159 kg/hr which is 0.68 in rounded figure. Hence, the correct option is 0.68.Given information: The composition of C2H6 and C3H8 are YC2H6 = 0.60. Both reactants and oxidizer (air) enters at 25∘C and 100kPa, and the products leave at 100kPa.
The air mass flow rate is given as 15.62 kg/hr. The combustion reaction is given by:
C2H6 + (3/2) O2 → 2 CO2 + 3 H2O
And,C3H8 + (5/2) O2 → 3 CO2 + 4 H2O
For the complete combustion of 1 mole of C2H6 and C3H8, 3/2 mole and 5/2 mole of O2 is required respectively.
The amount of O2 required for complete combustion of a mixture of C2H6 and C3H8 containing 1 mole of C2H6 and x mole of C3H8 will be given by,
3/2 × 1 + 5/2 × x = 1.5 + 2.5 x moles
The mass of air required for complete combustion of 1 mole of C2H6 and x mole of C3H8 will be given by,
Mass of air = (1.5 + 2.5 x) × 28.96 kg/kmol = (43.44 + 72.4 x) kg/kmol
The mass flow rate of air is given as 15.62 kg/hr, which can be written as 0.00434 kg/s.
Therefore, the molar flow rate of air will be,
_air = 0.00434 kg/s / 28.96 kg/kmol = 0.000150 mole/sSince the reaction is stoichiometric, the mass flow rate of the fuel can be determined as follows:
_fuel = _air × _C26 × (44/30) / [(Y_C26×(44/30)) + (1 − Y_C26) × (58/44)]
Where, YC2H6 is the mole fraction of C2H6 in the fuel mixture.
_fuel = 0.000150 × 0.60 × (44/30) / [(0.60 × (44/30)) + (1 - 0.60) × (58/44)] = 0.000159 kg/s
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A wildfire destroys most of the plant life in a forest. What would most likely happen to the animals that lived in the forest?
Answer:
They would be pushed out and lose their homes
Explanation:
A wildfire destroys most of the plant life in a forest. Animals would be pushed out and lose their homes.
What is wildfire?An unplanned, uncontrolled, and unpredictable fire inside an area of flammable vegetation is known by several names, including wildfire, bushfire, bushfire, wildland fire, and rural fire. A wildfire may be more precisely referred to by the terms bushfire, desert fire, forest fire, hill fire, peatland fire, prairie fire, vegetable fire, or veld fire, depending on the kind of vegetation that is present.
Wildfires are separate from controlled and prescribed burning, which is a good human use of wildland fire, even though controlled burns have the potential to turn into wildfires. Wildfires likely started shortly after terrestrial plants first appeared, which occurred in the Silurian epoch 419 million years ago, according to fossil charcoal. A wildfire destroys most of the plant life in a forest. Animals would be pushed out and lose their homes.
Therefore, animals would be pushed out and lose their homes.
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what are examples of natural ceramics found in nature? FASTEST AND BEST ANSWER WILL BE MARKED AS BRAINLIEST!
Answer:
Earthwares
porcelain
bricks
How many moles of ethane, C2H6, are present if the reaction conditions are 305 K, 1.3 atm, and 2.5 L of ethane, C2H6
Answer:
n = 0.13 moles of C2H6
grams = 11 g of CO2
Explanation:
In the reaction 2H2 + O2 → __H2O, what coefficient should be placed in front of H2O to balance the reaction?
1
2
3
4
Answer:
Below
Explanation:
2 H2 + O2 ====> H20 you have 4 H's on L...need 4 on right so:
2H2 + O2 =====> 2 H2 O Now H's are 'balanced' and a check of the O's shows they are balanced too (two O's on each side)
What are the hottest areas of the Sun?
What are the basic forces that drive the water cycle? Explain what they are.
Answer:
kcgiobb jkffiob hffyio hiiddhoo hhioiv
Answer: Have a blessed day
Explanation:
Water Cycle: Component # 1. Evaporation:
Evaporation is the process where a liquid changes from its liquid state to a gaseous state. Liquid water becomes water vapour. Temperature is the primary factor for evaporation.
During the water cycle the water of the oceans and freshwater bodies, such as lakes and rivers, is warmed by the sun and evaporates. During the process of evaporation, impurities in the water are left behind. As a result, the water that goes into the atmosphere is cleaner than it was on Earth.
Water Cycle: Component # 2. Condensation:
Condensation is the opposite of evaporation. Condensation is the process where a gas is changed into a liquid. Condensation occurs when the temperature of the vapour decreases.
The water droplets formed from condensation are very small and they remain suspended in the atmosphere. There millions of droplets of suspended water form clouds in the sky or fog at ground level. Water condenses into droplets only when there are small dusts particles present around.
Water Cycle: Component # 3. Precipitation:
When the temperature and atmospheric pressure are right, the small droplets of water in clouds form larger droplets or raindrops and it is called precipitation. The raindrops fall to earth.
As a result of evaporation, condensation and precipitation, water travels from the surface of the Earth goes into the atmosphere, and returns to Earth again.
Water Cycle: Component # 4. Surface Runoff:
Much of the water that returns to Earth as precipitation runs off the surface of the land and flows down-hill into streams, rivers, ponds and lakes. Small streams flow into the ocean. Surface runoff is an important part of the water cycle because, through surface runoff, much of the water returns again to the oceans, where a great deal of evaporation occurs.
Water Cycle: Component # 5. Infiltration:
ADVERTISEMENTS:
Infiltration is an important process where rain water soaks into the ground, through the soil and underlying rock layers. Some of this water ultimately returns to the surface at springs or in low spots downhill. Some of the water remains underground and is called groundwater.
As the water infiltrates through the soil and rock layers, many of the impurities in the water are filtered out. This filtering process helps in cleaning of the water.
Water Cycle: Component # 6. Transpiration or Evapotranspiration:
This is performed by plants. As plants absorb water from the soil, the water moves from the roots through the stems to the leaves. Once the water reaches the leaves, some of it evaporates from the leaves, adding to the amount of water vapour in the air. This process of evaporation through plant leaves is called transpiration. In large forests, an enormous amount of water will transpire through leaves.
Which of the following are cations? Check all that apply.
a
barium
b
calcium
c
oxygen
d
chlorine
e
aluminum
f
magnesium
g
copper
h
bromine
Answer:
a
barium
b
calcium
e
aluminum
f
magnesium
g
copper
Forms cation
Explanation:
Which describes the molecule shown below?
O A. Unsaturated alkyne
O B. Saturated alkane
O C. Saturated alkene
O D. Unsaturated alkane
The description of the molecules shown is it is unsaturated alkynes. The correct option is A.
What are unsaturated alkynes?Alkynes are unsaturated double bond containing compound that react with hydrogen when a catalyst is present.
The pie bond shows that the hydrogen atoms are lost from the alkanes.
Thus, the correct option is A, unsaturated alkynes.
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francine added 5.0 ml of 0.8 m koh to 2.0 ml of 6.0 m hbr. determine whether the resulting mixture is acidic, basic, or neutral.
When Francine combines 5.0 ml of 0.8 m KOH to 2.0 ml of 6.0 m HBr, the resulting solution will get acidic in nature because of more number of moles of HBr.
The chemical equation of the mentioned reaction is given as,
HBr + KOH → KBr + H₂O
As we can see, one mole of HBr reacts with one mole of KOH.
So, we can say that moles of HBr are equal to the moles of KOH.
Millimoles = Molarity x Volume
Now, it is given to us that Francine combines 5.0 ml of 0.8 m KOH to 2.0 ml of 6.0 m HBr.
Millimoles of KOH = 4 x 0.8
Millimoles of KOH = 4
Millimoles of HBr = 2 x 6
Millimoles of HBr = 12
As we see, that the millimoles of HBr are greater than that of KOH, so, the resulting solution will be Acidic in nature.
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Use the periodic table to determine the molar mass of each of the following elements. Use the correct number of significant figures.
Potassium (K):
g/mol
Osmium (Os):
g/mol
Manganese (Mn):
g/mol
Answer:
Potassium (K): 39.10 g/mol
Osmium (Os): 190.23 g/mol
Manganese (Mn): 54.94 g/mol
Explanation:
Just got it right on Edge 2021
The molar mass of the following elements are
Potassium (K): 39.10 g/mol
Osmium (Os): 190.23 g/mol
Manganese (Mn): 54.94 g/mol
What is molar mass?The molar mass of a substance is grams of one mole of that substance.
It can be calculated by dividing the atomic weight of the element, and the number of atoms found in that element.
Manganese is a transition metal with the atomic number 25.
Potassium is an essential mineral that is an alkali metal and its atomic number is 19.
Osmium is also a transition metal whose atomic number is 76.
Thus, the molar mass of the elements are, Potassium (K): 39.10 g/mol
Osmium (Os): 190.23 g/mol
Manganese (Mn): 54.94 g/mol
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A student measures the pressure and volume of an empty water bottle to be 1.4 atm and 2.3 L. She then decreases the pressure to 0.65 atm. What is the new volume?
Answer:
The new volume is 5.0L
Explanation:
Given:
Initial pressure (P₁) = 1.4 atm
Initial volume (V₁) = 2.3 L
Final pressure (P₂) = 0.65 atm
We'll use Boyle's Law:
P₁V₁ = P₂V₂
Substituting the given values:
(1.4 atm)(2.3 L) = (0.65 atm)(V₂)
Now, let's solve for V₂:
V₂ = (1.4 atm * 2.3 L) / 0.65 atm
Calculating this expression step-by-step:
V₂ = (3.22 atm·L) / 0.65 atm
V₂ ≈ 4.953 L
Rounded to one decimal place, the new volume is approximately 5.0 L.
Which elements would be expected to form a binary compound of the form XY? A- Sodium and sulfur B- magnesium and bromine C- potassium and phosphorous D- aluminum and phosphorus
Consider this reaction:
At a certain temperature it obeys this rate law.
rate
Suppose a vessel containsat a concentration of. Calculate the concentration ofin the vesselseconds later. You may assume no other reaction is important
The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].
We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M.
Given reaction obeys the rate law, rate=k[A]²[B].
Here, the initial concentration of A= 0.10 M,
initial concentration of B = 0.05 M, and
rate constant, k = 2.0 × 10⁻⁴ M⁻¹s⁻¹
We have to find the concentration of A, after 30 seconds.
To find the concentration of A, we need to know the rate at 0.10 M and 0.05 M. Therefore, we have to calculate the rates at these concentrations.
rate1 = k[A]²[B]
= (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.10 M)²(0.05 M)
= 1.0 × 10⁻⁷ M/srate2
= k[A]²[B] = (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.09 M)²(0.04 M)
= 6.48 × 10⁻⁸ M/s
Using the integrated rate law for a second-order reaction: [A] = [A]₀ - kt where [A]₀ = initial concentration of A, k = rate constant, and t = time in seconds.
We know [A]₀ = 0.10 M and k = 2.0 × 10⁻⁴ M⁻¹s⁻¹.
Substituting the values in the above equation, we get: [A] = [A]₀ - kt= 0.10 M - (2.0 × 10⁻⁴ M⁻¹s⁻¹)(30 s)≈ 0.0934 M
Therefore, the concentration of A in the vessel after 30 seconds is 0.0934 M.
This question requires us to calculate the concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].
We are given the initial concentration of A and B and the rate constant of the reaction. To find the concentration of A after 30 seconds, we need to calculate the rates at the initial concentrations of A and B.
Using the integrated rate law for a second-order reaction, we can find the concentration of A at any given time. We substitute the given values in the formula and solve for [A]. We get the concentration of A as 0.0934 M after 30 seconds. This calculation is based on the assumption that no other reaction is important.
The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B]. We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M. This calculation assumes that no other reaction is important.
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Which 1-mole sample of atoms requires the least energy to form a mole of positive ions? 1) Ca 2) Ge 3)K 4)Ga
Answer:
K potassium have least ionization energy among these four
Explanation:
Ionization energy values are given in kilo joule per mole
Ca 590
Ge 762
K 419
Ga 579
From above data we can understand stand K has least and Ge has highest ionization energy
cao(s)+2hcl(g)→cacl2(s)+h2o(g) express your answer using four significant figures.
Balanced chemical equation for the reaction between CaO(s) and HCl(g) is: CaO(s) + 2HCl(g) → CaCl2(s) + H2O(g).
To express the answer using four significant figures, we need to determine the molar ratio between CaO and HCl in the reaction. From the balanced equation, we can see that for every 1 mole of CaO, we need 2 moles of HCl. This ratio is important for calculating the amount of CaO required to react completely with a given amount of HCl.
The reaction involves the reaction of solid CaO (calcium oxide) with gaseous HCl (hydrochloric acid) to form solid CaCl2 (calcium chloride) and gaseous H2O (water). It is important to note that the state symbols (s) and (g) represent the physical states of the substances involved in the reaction. The balanced equation shows the stoichiometric relationship between the reactants and products, indicating that for every 1 mole of CaO, 2 moles of HCl are required to produce 1 mole of CaCl2 and 1 mole of H2O. By expressing the answer using four significant figures, we ensure that the numerical values are accurate to the appropriate level of precision.
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The predominant intermolecular force between molecules of I₂ is _____
A) ionic bonds.
B) dipole-dipole interactions.
C) ion-dipole interactions.
D) dispersion
The correct option is C, The predominant intermolecular force between molecules of I₂ is ion-dipole interactions.
Intermolecular forces refer to the attractive or repulsive forces that occur between molecules. These forces are responsible for the physical properties of substances, including their boiling and melting points, viscosity, and surface tension.The strength of intermolecular forces varies depending on the type of molecule and the distance between them. The four main types of intermolecular forces are van der Waals forces, hydrogen bonds, dipole-dipole interactions, and ion-dipole interactions.
Van der Waals forces are the weakest and occur between all molecules, while hydrogen bonds are the strongest and occur specifically between molecules containing hydrogen and a highly electronegative atom, such as nitrogen, oxygen, or fluorine. Intermolecular forces play an important role in many chemical and physical processes, including the solubility of substances, the behavior of gases, and the properties of liquids and solids
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2. How many liters of sulphur trioxide are formed when 4800 cm³ of sulphurdioxide is burned in air? what is the volume
4.8L of sulphur trioxide are formed when 4800 cm³ of sulphur dioxide is burned in air. Sulfur trioxide may be found in three different forms.
What is sulphur trioxide?The chemical compound with both the formula SO\(_3\) is sulfur trioxide. It has been regarded as "unquestionably the much more commercially significant" sulfur oxide. It is manufactured on a large level as a precursor towards sulfuric acid.
Sulfur trioxide may be found in three different forms: gaseous monomer, crystalline trimer, as well as solid polymer. At little below room temperature, sulfur trioxide is indeed a solid with a rather limited liquid range. The major precursor of acid rain is gaseous SO\(_3\).
2SO\(_2\) + O\(_2\) \(\rightarrow\) 2SO\(_3\)
SO\(_2\) is the limiting reactant
Molar ratio between SO\(_2\) and SO\(_3\) which is 2:2.
1000cm³= 1L
4800cm³×1L/1000cm³= 4.8L
Therefore, 4.8L is the volume.
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