The speed of sound in air a) at 30°C is approximately 346.13 m/s. b) The time it takes for the fan to hear the crack of the bat after seeing the ball hit is approximately 0.346 seconds.
a) To calculate the speed of sound in air at 30°C, we can use the formula:
v = √(γRT)
Where:
v is the speed of sound,
γ is the adiabatic index for air (approximately 1.4),
R is the gas constant for air (approximately 287 J/(kg·K)), and
T is the temperature in Kelvin (30 + 273.15).
Plugging in the values, we have:
v = √(1.4 * 287 * (30 + 273.15))
≈ √(1.4 * 287 * 303.15)
≈ √(123501.99)
≈ 346.13 m/s
b) To calculate the time it takes for the fan to hear the crack of the bat, we can use the formula:
t = d/v
Where:
t is the time,
d is the distance between the fan and the home plate (120 m), and
v is the speed of sound in air.
Plugging in the values, we have:
t = 120 m / 346.13 m/s
≈ 0.346 seconds
Therefore, the fan hears the crack of the bat approximately 0.346 seconds after seeing the ball hit the bat.
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The pr interval begins at the first sign of the p wave and ends at the first sign of the next deflection, which is called the:__________.
The PR interval in an electrocardiogram (ECG) represents the time it takes for the electrical impulse to travel from the atria (depicted by the P wave) to the ventricles. It begins at the first sign of the P wave and ends at the first sign of the next deflection, which is called the QRS complex.
The QRS complex represents the depolarization of the ventricles, which results in ventricular contraction and the pumping of blood out of the heart. It consists of three main deflections: Q, R, and S waves.
The Q wave is the first downward deflection after the P wave, the R wave is the first upward deflection after the Q wave, and the S wave is the second downward deflection following the R wave.
The PR interval is important in assessing the conduction time through the atrioventricular (AV) node, which connects the atria and ventricles. Abnormalities in the PR interval can indicate conduction abnormalities or disturbances in the electrical pathways of the heart.
In summary, the PR interval in an ECG begins at the first sign of the P wave and ends at the first sign of the QRS complex, which represents the depolarization of the ventricles.
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just wanna make sure im right
Look at the graph. During what interval is the object decelerating?
A) 0-1s
B)5-20s
C) 20-4
D)40-50s
Answer:
D
Explanation:
because the slope decreases
Answer:
Should be D the correct answer
Explanation:
Can the magnitude of a vector ever (a) be equal to one of its components, or (b) be less than one of its components? 9. Can a particle with constant speed be accelerating? What if it has constant velocity?
Answer:
a) the other components are zero, in the direction of one of the coordinate axes
b) the magnitude is less than the value of one of its components, it must occur when the vector is in some arbitrary direction
9) constant velocity the acceleration must necessarily be zero,
constant speed can be accelerated since it may be changing the direction of the velocity vector
Explanation:
Vectors are quantities that have modulo (scalar) direction and sense.
a) If in a vector its magnitude is equal to one d its components implies that the other components are zero, therefore the vector must be in the direction of one of the coordinate axes
b) if the magnitude is less than the value of one of its components, it must occur when the vector is in some arbitrary direction, other than the direction of the axes, that is
R² = x² + y²
where R is the magnitude of the vector e x, and are the components
9) When a particle has a constant velocity, the acceleration must necessarily be zero,
v = vo + a t
The bold letters indicate vectors If a = 0 implies that v = vo
If a particle has constant speed it can be accelerated since it may be changing the direction of the velocity vector, this type of acceleration has the name of centripetal acceleration
in the string problem, two strings hang from the ceiling but are too far apart to allow a person to hold one and walk to the other. in what way do most participants overlook the screwdriver in the problem, thus preventing a successful solution?
Most participants overlook the screwdriver in the problem, thus preventing a successful solution is by failing to consider that the screwdriver can be used as a weight.
About Two string problem :An investigation of the role played by experience in problem solving was conducted using the two-string problem (Maier, 1931). In the "two string problem," participants are directed to tie two threads together after seeing them dangling from the ceiling. The approach calls for the employment of objects that are close to where the strings reside. One string can swing by using a hammer as a weight, for instance.
What are string problems?A Problem String is a series of affiliated problems intentionally sequenced to help scholars construct fine connections so that important strategies come their natural instincts. This important tutoring tool is aimed to help scholars mentally construct fine connections
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16. For this table of data, how should the y-axis be labeled (with units)?
mass (kg)
3.2
4.6
6.1
6.2
7.4
9.
10.4
10.9
newtons (m/s)
31.381
45.1 111
59.821
60.801
72.569
89.241
101.989
106.892
Oms'
mass (kg)
O newtons
O kg
mass
O newtons (m/s?)
Answer:
The y-axis should be labelled as W in Newtons (kg·m/s²)
Explanation:
The given data is presented here as follows;
Mass (kg) \({}\) Newtons (kg·m/s²)
3.2 \({}\) 31.381
4.6 \({}\) 45.1111
6.1 \({}\) 59.821
7.4 \({}\) 72.569
9 \({}\) 89.241
10.4 \({}\) 101.989
10.9 \({}\) 106.892
From the table, it can be seen that there is a nearly linear relationship between the amount of Newtons and the mass, as the slope of the data has a relatively constant slope
Therefore, the data can be said to be a function of Weight in Newtons to the mass in kilograms such that the weight depends on the mass as follows;
W(m) in Newtons = Mass, m in kg × g
Where;
g is the constant of proportionality
Therefore, the y-axis component which is the dependent variable is the function, W(m) = Weight of the body while the x-axis component which is the independent variable is the mass. m
The graph of the data is created with Microsoft Excel give the slope which is the constant of proportionality, g = 9.8379, which is the acceleration due to gravity g ≈ 9.8 m/s²
We therefore label the y-axis as W in Newtons (kg·m/s²)
I need help!!!!
Please and thank u!
Answer:
False
True
False
True
False
True
Explanation:
If a ball is thrown straight up into the air with an initial velocity of $60{ft} /{s}$, its height in feet after $t$ second is given by $y=60 t-16 t^2$. Find the average velocity (include units, help (units)) for the time period begining when $t=2$ seconds and lasting
(i) 0.5 seconds
Avenge velocity:
(ii) 0.1 seconds
Average velocity:
(iii) 0.01 seconds
Average velocity:
Finally based on the above results, guess what the instantaneous velocity of the ball is when $t=2$. Average velociry:
The instantaneous velocity of the ball is when $t=2$ is 32 ft/s so the average velocity: 32 ft/s.
The given function is $y=60t-16t^2$. We need to find the average velocity of the ball for the time period beginning when $t=2$ seconds and lasting. The average velocity is calculated by dividing the distance travelled by the time taken. The average velocity for the time period beginning when $t=2$ seconds and lasting 0.5 seconds is calculated as follows:
Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Here, $y_2$ is the value of the function when $t=2.5$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.5)-16(2.5)^2=45$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.5$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{45-32}{0.5}]$Average velocity = $[\frac{13}{0.5}]$Average velocity = $26$ ft/sNow, for the time period beginning when $t=2$ seconds and lasting(ii) 0.1 seconds. Here, $y_2$ is the value of the function when $t=2.1$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.1)-16(2.1)^2=31.84$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.1$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{31.84-32}{0.1}]$Average velocity = $[-1.6]$ ft/s(iii) 0.01 seconds. Here, $y_2$ is the value of the function when $t=2.01$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.01)-16(2.01)^2=31.9364$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.01$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{31.9364-32}{0.01}]$Average velocity = $[-6.36]$ ft/s
Finally based on the above results, we can guess that the instantaneous velocity of the ball is when $t=2$ is 32 ft/s. hence, Average velocity: 32 ft/s.
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What is the meaning of the word solar in the article "Fire Up the Sun"?
relating to electricity
caused by the sun
caused by heat
relating to power
Answer:
B) Caused by the Sun
Explanation:
If you look at a picture of a solar system, you will see the sun in the middle. The sun is the powerhouse of the solar system. So that means that the sun is the biggest star and can provide enough light to reach earth and keep it lit.
The meaning of the word solar in the article "Fire Up the Sun" is caused by the sun so, option B is correct.
What is sun?The sun is the star that the earth and the other planets in the solar system orbit. With more than 99 percent of the system's total mass, it is the dominant body. A portion of the tremendous quantity of energy coming from the Sun powers the light and heat that keep Earth habitable for life.
The sun is in the center of a solar system if you look at a picture of one. The solar system's center of gravity is the sun. This indicates that the sun is the largest star and that it can illuminate the earth and keep it bright.
The Sun is a G2 V star, which means that it has a surface temperature of roughly 5,800 kelvins (K), making it the second-hottest star in the yellow G class.
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Powers of 10
For each of the following the power of 10 in standard form.
1. 102
2. 105
3. 10-3
4. 101
5. 1010
6. 100
7. 10-2
8. 10-8
9. 104
10.10-1
For each of the following write the number as a power of 10.
1. 1000
2. 10
3. 0.1
4. 10000000
5.1
6. 100
7. 0.00001
8. 0.001
9. 10000
10. 0.000000001
Answer:
es inglés plis españolejjdkdjdd
What does echolocation and ultrasonic imaging have in common?
Answer:.
They both rely on "reflected" sound waves.
Jibari walks 40. 0 meters east in 120. 0 seconds. He then walks 30. 0 meters west in 60. 0 seconds. What is his average velocity for the trip??
Answer:
0.389 meters per second
Explanation:
1. Get your knowns
a. 40 meters per 120 seconds
b. 30 meters per 60 seconds
2. Add
Total distance = 40 meters + 30 meters = 70 meters
Total time = 120 seconds + 60 seconds = 180 seconds
3. Divide
Average velocity = 70 meters / 180 seconds
= 7 meters / 18 seconds
= 0.388... meters per second
Select the correct answer. Why does a solid change to liquid when heat is added? A. The spacing between particles decreases. B. Particles lose energy. C. The spacing between particles increases. D. The temperature decreases.
Answer:
The right answer is c because when we heat solid object the molecule will start lose attraction on object
Explanation:
brain list
2. 1. 2 Temperature decrease A. Increase. B. Decrease. C. Increase then decrease. D. Remain the same. (2) 2. 2 If the material is allowed to change in size, what kind of stress will be induced in it? A. Compression stress. B. Tension stress. C. No stress will be induced. D. Shear stress. 2. 1. 2 Temperature decrease A. Increase. B. Decrease. C. Increase then decrease. D. Remain the same. (2) 2. 2 If the material is allowed to change in size, what kind of stress will be induced in it? A. Compression stress. B. Tension stress. C. No stress will be induced. D. Shear stress
2.1.2) When temperature decreases, the material may decrease in size, 2.2) If a material is allowed to change in size, it experiences compression stress.
2.1.2 Temperature decrease: When the temperature of a material decreases, one possible effect is that the material may decrease in size. This happens because when the temperature decreases, the molecules in the material slow down and move closer together.
2.2 If a material is allowed to change in size, it can experience different types of stress. One type of stress that can be induced is compression stress. Compression stress occurs when a force is applied to the material, causing it to be squeezed or compressed.
Another type of stress that can be induced when a material changes in size is tension stress. Tension stress occurs when a force is applied to the material, causing it to be stretched or elongated. This happens because the material is trying to resist the force and return to its original size.
In some cases, when a material changes in size, no stress may be induced.
Finally, shear stress is another type of stress that can be induced when a material changes in size.
In summary, when a material changes in size, it can experience compression stress, tension stress, shear stress, or no stress depending on the external forces acting upon it.
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How do i exist (serious question, i'm in the dark abyss of nothing please help)
a 15-kg block is on a frictionless ramp that is inclined at 20° above the horizontal. it is connected by a very light string over an ideal pulley at the top edge of the ramp to a hanging 19-kg block, as shown in the figure. the string pulls on the 15-kg block parallel to the surface of the ramp. find the magnitude of the acceleration of the 19-kg block after the system is gently released?
Hi there!
Since the string is light and there is no friction in the pulley, the acceleration of the system is equal to the acceleration of both blocks.
We can begin by summing the forces of each block:
Block on incline:
- Force of gravity (in the negative direction away from the acceleration)
- Force of Tension
∑F = -M₁gsinФ + T
Block hanging:
- Force of gravity (Positive, in direction of acceleration)
- Force of Tension (Negative, opposite from acceleration)
∑F = M₂g - T
Sum both of these net forces for each block:
∑Fт = -M₁gsinФ + T - T + M₂g
∑Fт = -M₁gsinФ + M₂g
Divide by the mass to solve for acceleration:
\(a = \frac{-M_1gsin\theta+M_2g}{M_1+M_2}\)
Plug in the given values:
\(a = \frac{-(15)(9.81)(sin20)+19(9.81)}{15+19} = 4.002 m/s^2\)
The magnitude of the acceleration of the 19-kg block is 4.0 m/\(s^{2}\).
The 15-kg block is accelerating down the ramp, and the 19-kg block is accelerating up. The string connecting the two blocks is taut, so it must be applying a force to both blocks. The force of the string on the 15-kg block is equal to the force of the string on the 19-kg block.
Let's call the force of the string on the 15-kg block T. We can use Newton's second law to write two equations for the acceleration of the two blocks:
For the 15-kg block: T - mg sin(θ) = 15a
For the 19-kg block: T = 19a
where:
m is the mass of the block
g is the acceleration due to gravity
θ is the angle of the ramp
a is the acceleration of the block
Plugging the second equation into the first equation, we get:
19a - mg sin(θ) = 15a
Solving for a, we get:
a = (mg sin(θ)) / (4m)
= (15 kg * 9.8 m/\(s^{2}\) * sin(20°)) / (4 * 15 kg)
= 4.0 m/\(s^{2}\)
Therefore, the magnitude of the acceleration of the 19-kg block is 4.0 m/\(s^{2}\).
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The speed of a sound wave depends on....
A: both the medium's temperature and the density of the medium
B: the density of the medium
C: the medium's temperature
D: the frequency
hen we see ourselves as dynamic beings, looking for ways to engage in activities using our abilities and expressing our personalities, we are reflecting on the _____________ theory.
Answer:
Then we see ourselves as dynamic beings, looking for ways to engage in activities using our abilities and expressing our personalities, we are reflecting on the Humanistic Theory
Explanation:
Humanistic theory emphasizes the inherent worth of the individual, the centrality of human values, and the creative, active nature of human beings. This approach encourages people to strive for self-realization and self-actualization, recognizing their capacity for dynamic growth and self-determination. Psychologists like Carl Rogers and Abraham Maslow contributed significantly to this school of thought.
A student fills a plastic bottle full of water. There are two holes one at the bottom and second at the half way up. Why water comes out at right angles to the bottle.
PLZ ANSWER
Answer:
Due to the direction of force due to pressure.
Explanation:
Let there be two small holes having area, \(a\) , at points A and B in the bottle filled with water as shown in the figure \((i)\). Water comes out at the right angles to the wall of the bottle as shown in figure \((ii)\).
From Newton's second law, the acceleration of an object is always in the direction of net applied force.
We know that pressure, \(P\), on any surface due to fluid acts perpendicular to the surface, so, the force due to pressure,\(F=Pa\), will also be perpendicular to the surface as shown in the diagram\((iii)\).
So, the direction of the acceleration of the water element at that point will be perpendicular to the bottle surface which leads to the change in velocity of the water element in the same direction.
That's why water comes out at right angles to the surface of the bottle.
determine the rankine active coefficient for an angle of
internal friction of 45 deg. Round off to three decimal places
will give an upvote after i check the answer, thanks a lot!
The Rankine active coefficient for an angle of internal friction of 45 degrees is 0.500.
The Rankine active coefficient of an angle of internal friction of 45 degrees is 0.500. To determine the Rankine active coefficient, the following formula is used:
Rankine active coefficient = tan²(45° + φ/2) / tan²(45° - φ/2)
Where:φ is the angle of internal friction
Substituting φ = 45° into the formula,
Rankine active coefficient = tan²(45° + 45°/2) / tan²(45° - 45°/2)
= tan²(67.5°) / tan²(22.5°)
= 2.414 / 0.242
= 9.956 rounded off to three decimal places
= 0.500
Therefore, the Rankine active coefficient for an angle of internal friction of 45 degrees is 0.500.
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This graph shows how the potential energy of a reaction system changes
over time. Which statement is true for this system?
Potential energy
A
B
Reaction progress
C
A. The potential energy at point A represents the activation energy.
B. The potential energy of the products is greater than the potential
energy of the reactants.
C. The potential energy of the products is lower than the potential
energy of the reactants.
D. The potential energy at point C represents the activation energy.
The potential energy of the products is lower than the potential
energy of the reactants. Hence, option (C) is correct.
What is potential energy of reactants?The energy that is stored in a reaction and used to help a compound break its bond when a chemical reaction is taking place.
In the presence of activation energy, the bonds in the reactants in the reaction mixture split, releasing energy and forming the product.
Hence, the potential energy of the products is lower than the potential
energy of the reactants. Option (C) is correct.
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What are sport skills sometimes referred to as?
a skill-related fitness
b. performance skills
c. health-related fitness
d. physical fitness
Find the fundamental period (To) and frequency (Wo) of the following signal:
student submitted image, transcription available below
The fundamental period (To) of a signal is the smallest T for which it repeats. Frequency (Wo) is the reciprocal of To. Example: To = 0.5s, Wo = 2Hz.
The fundamental period (To) of a periodic signal is the smallest positive value of T for which the signal repeats itself exactly. The frequency (Wo) of a periodic signal is the reciprocal of the fundamental period,
Wo = 1/To.
To find the fundamental period and frequency of a signal, we need to analyze its waveform.
First, let's identify the period of the signal. The period is the horizontal distance between two adjacent peaks (or troughs) of the waveform. If the signal repeats itself exactly, it is periodic.
Once we have identified the period, we can calculate the fundamental period (To) by measuring the distance between two adjacent peaks (or troughs) and taking the smallest positive value.
To calculate the frequency (Wo), we can use the formula Wo = 1/To. Here's an example to illustrate this process:
Let's say the signal waveform repeats itself every 2 seconds. This means the period is 2 seconds.
To calculate the fundamental period (To), we measure the distance between two adjacent peaks (or troughs) and find it to be 0.5 seconds.
Therefore, the fundamental period (To) is 0.5 seconds.
To calculate the frequency (Wo), we use the formula Wo = 1/To. In this case, Wo = 1/0.5 = 2 Hz. So, the fundamental period (To) of the signal is 0.5 seconds and the frequency (Wo) is 2 Hz.
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does 3.60 x 10 ⁻² have 2 significant figures
Answer:
Number of Significant Figures: 2
The Significant Figures are 3 6
Explanation:
= 3.60 × 102
(scientific notation)
= 3.60e2
(scientific e notation)
= 360 × 100
(engineering notation)
(one)
= 360
(real number)
Answer the following
Answer: There is nothing here
Explanation: Could you please add a picture or something
Write the differences between normal forces and tension with suitable examples.
A Normal Force is a force applied in the direction perpendicular to the surface that the force is applied to. An example of this is putting pressure directly down on a table with your hand.
A Tension Force is a force applied in the opposite direction of the object the force is applied to. Tension Forces usually are applied by springs, ropes, and wires. An example of this is a wrecking ball hanging from a crane. There is a Tension Force on the wrecking ball holding it up in the air.
These forces are different from one another based on their directions that the forces are applied. Forces are vectors, so their magnitude is determined by the amount of force applied and their direction. Tension Force can be a Normal Force, but Normal Forces are not always Tension Forces.
A 20 N force is necessary to stretch a spring 0.5 m. What is the spring constant of this spring?
Answer: The spring constant of a given spring is \(40 N/m\).
Explanation:
Given,
Force (F) = 20N
The displacement of the spring\(= x = 0.5 m\)
To find: Spring constant (k) = ?
As we know that,
Hook's law states that,
\(F = k\) · \(x\)
Therefore, \(k = \frac{F}{x}\)
\(k = \frac{20}{0.5}\)
\(k = \frac{(20)(10)}{5}\)
\(k = 40 N/m\)
Hence, The spring constant of a given spring is \(40 N/m\).
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State the Doppler Effect in words.
Answer:
the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the source of the wave. When the observer is moving towards the source, the waves are compressed and the frequency increases (called a blue shift). Conversely, when the observer is moving away from the source, the waves are stretched and the frequency decreases (called a red shift). This phenomenon can be observed in sound waves, light waves, and other types of waves.
Answer: an increase (or decrease) in the frequency of sound, light, or other waves as the source and observer move toward (or away from) each other
Explanation:
Rafael swings a baseball bat with a force of 25 N. The baseball bat exerts a force of 5 N on the baseball. What is the mechanical advantage of the baseball bat? The mechanical advantage of the baseball bat is
Answer:
0.2
Explanation:
Mechanical Advantage is defined as the ratio of force output with respect to the force input. Thus,
MA = output / input
MA = 5 / 25
MA = 1/5
MA = 0.2
Since this value is less then one. Even though it's tagged a mechanical advantage, in reality it would be mechanical disadvantage.
Therefore, we can say that the mechanical advantage of the baseball bat is 0.2
Answer:
0.2
Explanation:
A negative charge is placed at the center of a ring of uniform positive charge. What is the motion (if any) of the charge
The negative charge placed at the center of a ring of uniform positive charge will experience an attractive force towards the positive charges, causing it to oscillate back and forth along a diameter of the ring.
When a negative charge is placed at the center of a ring of uniform positive charge, it experiences a net attractive force due to the positive charges. However, since the positive charges are uniformly distributed along the ring, the attractive forces from opposite sides of the ring cancel each other out, resulting in no net force in the radial direction.
The negative charge is free to move only along a diameter of the ring, oscillating back and forth as it experiences the attractive forces from the positive charges. This motion continues as long as the charges remain undisturbed and no other forces act upon the system.
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