3. A car advertisement states that a certain car can accelerate from rest to 70 km/h in 7 seconds.
Find the car's average acceleration.

Answer:

Explanation:

Force = Mass*Acceleration

Remember this formula because its one of the most used formula in all of physics.

250N = 80kg*Acceleration

a = 3.125 m/s^2

There would definitely be friction because of the water, but since this says high school physics, you prolly can assume it to be negligible

Answer:

The length is \(s = 3.73 \ m\)

Explanation:

From the question we are told that

  The speed is  \(v = 3.054 \ m/s\)

  The acceleration \(a = -0.7762 m/s^2\)

   The time taken is  \(t = 1.51 \ s\)

Generally from kinematics equation the length of the inclined plane is mathematically represented as

         \(s =ut + \frac{1}{2} * at^2\)

=>      \(s = 3.054 *1.51 + \frac{1}{2} * (-0.7762) *(1.51)^2\)

=>   \(s = 3.73 \ m\)

Measurement of the distance traveled and the amount of time required to cover that distance are required in order to determine speed.

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The formula for angular velocity as a function of time when it rises linearly can be used to address this issue:

ωz(t) = ωz,0 + αz t

If t is time, z,0 is the angular acceleration at rest, and z is the starting angular velocity.

Applying the information provided, we have:

ωz,0 = -6.00 rad/s (initial angular velocity)

z (6.0 s) = +4.0 rad/s (final angular velocity)

t = 6.00 s (time elapsed) (time elapsed)

The angular acceleration z is what we're looking for.

Using the formula's supplied values as substitutes, we obtain:

-6.00 rad/s + z = +4.00 rad/s (6.00 s)

When we simplify and find z, we obtain:

Z = (5.00 rad/s - 6.0 rad/s)

/6.00 s = 1.67 rad/s^2

As a result, the wheel's angular acceleration is 1.67 rad/s2.

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Answer:

A

Explanation:

acceleration is defined as the rate of change of velocity with time

Answer:

y = 43.55 + 2.15t

Explanation:

We were told that in 1983, the per capita consumption was 37.1 pounds, and in 1989 it was 50 pounds.

If we assume t = 0 corresponds to year 1980. Then, for 1983 it will be t = 3 and for 1989,it will be t = 9.

Thus, expressing the information as ordered pairs, we have; (3,37. 1) and (9,50).

Let us now find slope of the linear function:

m1 = (y2 - y1)/(t2 - t1)

m1 = (50 - 37.1)/(9 - 3)

m1 = 2.15

So, we can find the linear equation as;

y - 37.1 = 2.15(t - 3)

y = 37.1 + 2.15t - 6.45

y = 43.55 + 2.15t

Answer:

to be turned into glycogen not wasted

Explanation:

Since the body has a lot of energy left it will turn that energy into glycogen which is a storage form of glucose which will when neccassary will be converted into glucose from the horomone glucagon and be given to the body to be used as energy so the energy is never wasted

Answer:

100,000 / 800,000 = 1 / 8    amount of sample after 12 hours

(1/2)^n = 1 / 8      after n half-lives 1/8 of sample will be left

n = 3

(D) is the correct answer - 1/2 half-life = 4 hours

The type of material has two effects on the parachute. The lighter the parachute, the slower it will descend. The heavier the parachute, the faster it will fall.

The parachute is slowed down by air resistance due to the material's big surface area. More air resistance and a slower parachute descent result from a larger surface area.

Since, the material affects how the parachute descended, it is essential that it be windproof, flexible, and light-weight. It must be able to resist environmental factors like high-altitude winds. While it takes longer to descend with lighter materials, it takes less time to descent with heavier ones. The material is basically chosen to be lighter or less heavy for this purpose.

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Answer:

(9.4 times / 8.5 minutes) x (1 minute / 60 seconds)

= (9.4) / (8.5 x 60) times/second

= 0.013 Hz .

Foundation: Use a deep and sturdy foundation that extends below the frost line and is anchored to bedrock. Consider foundations or caissons, which can better withstand lateral forces during an earthquake.

Structural System: Utilize a seismic-resistant structural system such as reinforced concrete or steel framing with appropriate bracing and cross-bracing configurations. Consider incorporating a moment-resisting frame or a shear wall system, which can provide enhanced lateral stability during seismic events.

Dampers and Isolators: Include seismic dampers or isolators in the structural system to absorb or dissipate seismic energy. These can be installed at various locations, such as between floors or in the foundation, to reduce the impact of seismic forces on the building.

Diaphragms: Strengthen diaphragms, which are horizontal structural elements such as floors and roofs, to improve their resistance to lateral loads during an earthquake. Consider using diaphragms made of materials such as cross-laminated timber (CLT) or steel decking, which can provide additional stiffness and strength.

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The album that is most frequently cited as the beginning of fusion is "In a Silent Way" by Miles Davis. Released in 1969, it is often regarded as a groundbreaking and influential work that marked a significant shift in jazz and the emergence of fusion music.

"In a Silent Way" showcased a departure from Davis' previous acoustic jazz sound and incorporated elements of electric instruments, studio production techniques, and improvisational freedom. The album blended jazz with elements of rock, funk, and electronic music, creating a unique and experimental sonic landscape. The musicians involved in the recording, including Wayne Shorter, Herbie Hancock, and John McLaughlin, went on to become key figures in the fusion genre. This album laid the foundation for future fusion developments, influencing artists across various genres. Its atmospheric, ethereal, and exploratory nature set the stage for the fusion movement of the 1970s, which further integrated jazz with elements of rock, funk, and other genres. "In a Silent Way" remains a pivotal work in the history of fusion, symbolizing the fusion of diverse musical styles and the limitless possibilities of blending genres in innovative and creative ways.

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Answer:

i dont know

Explanation:

Explanation:

key to this problem is the impulse-momentum theorem which states that the change in the momentum of an object is equal to the impulse applied into it.

J

=

Δ

p

,

where

J

is the impulse and

Δ

p

is the change in momentum. Basically, the impulse is the product of force and time duration, that is,

J

=

F

Δ

t

In this problem, the impulse would be the product of the force stopping the rock and

0.7

s

.

On the other hand, momentum

p

is the product of the mass

m

and velocity

v

. Therefore, the change in momentum is given by

Δ

p

=

m

2

v

2

−

m

1

v

1

.

Starting with the impulse-momentum equation, we have

J

=

Δ

p

F

Δ

t

=

m

2

v

2

−

m

1

v

1

Divide both sides by

Δ

t

,

we get

F

Δ

t

Δ

t

=

m

2

v

2

−

m

1

v

1

Δ

t

F

=

m

2

v

2

−

m

1

v

1

Δ

t

Finally, substitute the values and we get

F

=

(

2

kg

)

(

0

)

−

(

2

kg

)

(

6

m

s

)

(

0.7

s

)

F

≈

−

20

kg

m

s

2

Since

1

N

=

1

kg

m

s

2

,

then

F

≈

−

20

N

Therefore, using the correct significant figures (in this case, we need one significant figure since 2 kg, 6 m/s and 0.7 s all have one) in the final answer, we would need to have approximately

20

N

force to stop the rock in

0.7

s

.

Note: The negative sign is referring to the direction of the force opposite of the direction of the velocity

v

1

.

This phenomenon of motion in physics can be explained in the following manner,

In a tug-of-war the rope is pulled by the two competing teams simultaneously, each using an equal amount of force. The rope is pulled with equal force by both teams thanks to Newton's third law. If one team pushes harder, the other team will follow suit.

The power with which the teams press the ground determines whether one team wins or loses. The team that pushes the floor harder gets pushed back with identical intensity by the ground, causing them to stand up straight without losing their equilibrium.

As a result, the power by which the team pushes the floor determines who wins and who loses.

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Answer:

The center of mass is at -1.58 cm, that is towards the left of the origin, or towards the copper end.

Explanation:

Given information: Let the length of the rod is 2l = 100cm

Answer:

\(F_A =5.625*10^1^6N\)

Explanation:

From the question we are told that

50,000 years ago,

A giant 4.5 107-kg meteor

180-m-deep hole

20,000 m/s

Generally for this problem the energy change is given as

       \(\triangle E=\frac{1}{2} mv^2 +mgd\)

Having the potential and kinetic energy in place

Mathematically  solving for Average force\(F_A\)

       \(\triangle E=F_a*d\)

\(F_A =\frac{1/2* 4.5*10^7(20,000)^2-kg+4.5*10^7*9.81*160}{160}\)

Therefore Average force \(F_A\) is given by

\(F_A =5.625*10^1^6N\)

Answer:

(I). The Schwarzschild radius is \(2.94\times10^{8}\ km\)

(II). The Schwarzschild radius is 17.7 km.

(III). The Schwarzschild radius is \(1.1\times10^{-7}\ km\)

(IV). The Schwarzschild radius is \(7.4\times10^{-29}\ km\)

Explanation:

Given that,

Mass of black hole \(m= 1\times10^{8} M_{sun}\)

(I). We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Where, G = gravitational constant

M = mass

c = speed of light

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times1\times10^{8}\times1.989\times10^{30}}{(3\times10^{8})^2}\)

\(R_{g}=2.94\times10^{8}\ km\)

(II). Mass of block hole \(m= 6 M_{sun}\)

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times6\times1.989\times10^{30}}{(3\times10^{8})^2}\)

\(R_{g}=17.7\ km\)

(III). Mass of block hole m= mass of moon

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times7.35\times10^{22}}{(3\times10^{8})^2}\)

\(R_{g}=1.1\times10^{-7}\ km\)

(IV). Mass = 50 kg

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times50}{(3\times10^{8})^2}\)

\(R_{g}=7.4\times10^{-29}\ km\)

Hence, (I). The Schwarzschild radius is \(2.94\times10^{8}\ km\)

(II). The Schwarzschild radius is 17.7 km.

(III). The Schwarzschild radius is \(1.1\times10^{-7}\ km\)

(IV). The Schwarzschild radius is \(7.4\times10^{-29}\ km\)

The energy conservation allows to find the Schwarschild radius for several bodies of different masses are:

  1)  Black hole quasar is:  r = 2.9 10⁸ km

  2) Blsck hole supernove is:  r = 17.7 km

  3)  Mini black hole is:   r = 1.1 10⁻⁷ km

  4) Human body is:  r=  7 10⁻²⁹ km

The schwarschild radius is defined as the distance from a black hole center at radius  which the escape velocity is equal to the light speed, in some cases it is also called the event horizon.

Let's use Newton's second law where force is the universal law of attraction and acceleration is centripetal.

        F = ma

        F = \(G \frac{Mm}{r^2}\)        

Where F is the force, M the mass of the black hole, m the handle of the body, r the radius and v the speed of the body.

The energy of the gravitational field is

        F = \(- \frac{dU}{dr }\)  

         U = \(-G \frac{Mm}{r}\)  

Let's use conservation of energy

        Em₀ = K + U = ½ m v² -  \(G \frac{Mm}{r}\)  

In infinity the energy

        Em_f = 0

energy is conserved

       Em₀ = Em_f  

       ½ m v² - \(G \frac{Mm }{r}\)  = 0

       r = \(\frac{2GM}{v^2}\)

From the definition of the Schwarschild radius this speed is equal to the light speed

        v = c

        r = \(\frac{2GM}{c^2 }\)  

They ask to calculate the radius for several cases of different mass, claculate the constant value

      V = \(\frac{2 \ 6.67 \ 10^{-11} }{(3 \ 10^8) ^2 }\)  

      V =  1.482 10⁻²⁷

1) A black hole of mass M = 1 10⁸ \(M_{sum}\)

The tabulated mass of the sun is \(M_{sum}\) = 1.989 10³⁰ kg

Let's  substitute

        r =  1.482 10⁻²⁷   1 10⁸ 1.989 10³⁰

        r = 2.94 10⁸ km

With two significant figures

        r = 2.9 10⁸ km

2) A black hole of mass M = 6 \(M_{sum}\)

        r =  1.482 10⁻²⁷ 6 1.989 10-30

        r = 17.7 km

3) a mini black hole with the mass of the moon

    Tabulated mass of the moon M = 7.35 10²² kg

       r =  1.482 10⁻²⁷  7.35 10²²    

       r = 1.1 10⁻⁷ km

4) A person of M = 50 kg

    r =  1.482 10⁻²⁷ 50

    r=  7 10-29 km

In conclusion using the conservation of energy we can find the Schwarschild radius for several bodies of different masses are:

  1)  Black hole quasar is:  r = 2.9 10⁸ km

  2) Blsck hole supernove is:  r = 17.7 km

  3)  Mini black hole is:   r = 1.1 10⁻⁷ km

  4) Human body is:  r=  7 10⁻²⁹ km

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The initial oil-in-place (N) of a volumetric oil reservoir is a critical parameter used to estimate the total amount of oil that can be recovered from the reservoir. It represents the total volume of oil contained within the reservoir at the beginning of its production life.

The initial gas-in-place (G) of a volumetric gas reservoir is a critical parameter used to estimate the total amount of gas that can be recovered from the reservoir. It represents the total volume of gas contained within the reservoir at the beginning of its production life.To calculate the initial oil-in-place and gas-in-place, we need to use certain parameters such as the area of the reservoir, the thickness of the reservoir, the porosity of the reservoir, the initial oil or water saturation, and the formation volume factor. The formulas used to calculate the initial oil-in-place and gas-in-place are different, and the parameters used in each formula are specific to either an oil or gas reservoir.

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If F = 37 N, the static frictional force between the block and the table and the minimum force required to move it must be equal.

It is the force that regulates itself. The value of static friction varies from zero to the smallest force required to initiate motion. The formula for determining static friction is as follows: Normal Force divided by the static friction coefficient is static friction.

Although the maximum static friction will rise, the frictional force will always be the same as the weight in mg because friction cannot accelerate an object. Because FrN can take any value less than N to balance the weight, this is the case.

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The general equation of a circle in Cartesian coordinates is given by:

\((x - h)^2 + (y - k)^2 = r^2,\)

where (h, k) represents the coordinates of the center of the circle, and r represents the radius. Without the specific equation, we cannot determine if x and y satisfy it.

A circle is a two-dimensional geometric shape that is perfectly round and symmetrical. It is defined as a set of points that are equidistant from a central point called the center. The distance from the center to any point on the circle is called the radius, and it is the same for all points on the circle.

A circle is often represented by the symbol "⚪" or by writing its name. It is a fundamental concept in geometry and mathematics, and it has numerous properties and applications in various fields.

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Explanation:

D.

hope it's help

hi I'm new user

Answer:

D.

Explanation:

The answer should be D. Cause it makes more sense and the gamma decay process it goes from Unstable to stable.

I apologize if it is incorrect-
I hope it helps! Have a great day!

Anygays-

A front denotes the separation of two air masses with dissimilar characteristics in terms of temperature, wind, and moisture.

Distinguish between warm and cold fronts.

Both warm and cold fronts are intricate weather phenomena, necessitating a thorough explanation in order to fully comprehend their similarities and distinctions. A cold front develops on the edge of a cold air mass flowing into a warmer area, whereas a warm front develops on the edge of a warm air mass moving into a colder area. A cold front is often linked to a low-pressure system, whereas a warm front is linked to a high-pressure system.

Hence, the answer is both warm and cold front, since a front denotes the separation of two air masses with dissimilar characteristics in terms of temperature, wind, and moisture.

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Answer:

the number of protons.

Explanation:

the atomic number is the number of protons in the nucleus of an atom. the number of protons Define the identity of an element.

Explanation:

1) left ⬅️

2) into the page

3) upward ⬆️

4) right ➡️

5) downward ⬇️

Explanation:

u=24

v=0

a=-0.29

s=

v^2=u^2+2as

s=(v^2-u^2)/2a

s=(0-576)/0.58

s=-575.42