3x = 3x Is an example of what property?


A. Reflexive Property

B. Symmetric Property

C. Identity Property

D. Associative Property

Answer:

SSS

Step-by-step explanation:

We can see that 2 sides are equal already, and because they share a side, that side is also equal. So, side side side.

Answer:

40°  

Step-by-step explanation:

65° + 75° = 140°

180° - 140° = 40°

Further explanation:

You add 65° and 75° you get 140°.

All triangles must equal 180°, you subtract 140° from 180° and that equals 40°.

Answer:

3

Step-by-step explanation:

The actual prime factors of 60 are 2, 3, and 5.

Answer:

3

Step-by-step explanation:

prime fatorizations are 2, 3, and 5

Answer:

No.

Step-by-step explanation:

Let's find out if 1 bag of soil is enough to fill 1 container.

Given:

2/5 of a bag fills 1/3s of a containter.

With the given, multiplying 2/5 by 2.5 represents one. Multiply 1/3 by 2.5 aswell.

Products:

1, and 2.5/3 or 5/6

1 bag can fill 5/6 of a container.

Therefore, 1 bag can't fill 1 container.

Answer:

5/3 is the slope. slope is the same thing as rate of change

Step-by-step explanation:

Answer:

-1/2

Step-by-step explanation:

In the equation y=mx+b..

y and x are the coordinates that go into your function

m is the slope

and b is the y intercept

looking at y=-1/2x-3 i can tell that -1/2 is in the place of m which is slope, and -3 is the y intercept.

a) The divergence of f = \(e^{xy\) i - cosy j + sin z²k is y \(e^{xy\) + sin y + 2z cos z², and the curl is 0.

b) The divergence of f = xi + yj - zk is 1, and the curl is 0.

a) To find the divergence and curl of the vector field f = \(e^{xy\) i - cosy j + sin z²k:

Divergence:

The divergence of a vector field f = P i + Q j + R k is given by the formula:

div(f) = ∇ · f = ∂P/∂x + ∂Q/∂y + ∂R/∂z

Given f = \(e^{xy\) i - cosy j + sin z²k, we can calculate the divergence as follows:

∂P/∂x = ∂/∂x(\(e^{xy\)) = y \(e^{xy\)

∂Q/∂y = ∂/∂y(-cosy) = sin y

∂R/∂z = ∂/∂z(sin z²) = 2z cos z²

Therefore, the divergence of f is:

div(f) = y \(e^{xy\) + sin y + 2z cos z²

Curl:

The curl of a vector field f = P i + Q j + R k is given by the formula:

curl(f) = ∇ × f = ( ∂R/∂y - ∂Q/∂z ) i + ( ∂P/∂z - ∂R/∂x ) j + ( ∂Q/∂x - ∂P/∂y ) k

Using the vector field f = \(e^{xy\) i - cosy j + sin z²k, we can calculate the curl as follows:

∂P/∂y = ∂/∂y(\(e^{xy\)) = x \(e^{xy\)

∂Q/∂z = ∂/∂z(-cosy) = 0

∂R/∂x = ∂/∂x(sin z²) = 0

∂R/∂y = ∂/∂y(sin z²) = 0

∂Q/∂x = ∂/∂x(-cosy) = 0

∂P/∂z = ∂/∂z(\(e^{xy\)) = 0

Therefore, the curl of f is:

curl(f) = (0 - 0) i + (0 - 0) j + (0 - 0) k

curl(f) = 0 i + 0 j + 0 k

curl(f) = 0

b) To find the divergence and curl of the vector field f = xi + yj - zk:

Divergence:

∂P/∂x = ∂/∂x(x) = 1

∂Q/∂y = ∂/∂y(y) = 1

∂R/∂z = ∂/∂z(-z) = -1

Therefore, the divergence of f function is:

div(f) = ∇ · f = 1 + 1 - 1 = 1

Curl:

∂P/∂y = ∂/∂y(x) = 0

∂Q/∂z = ∂/∂z(y) = 0

∂R/∂x = ∂/∂x(-z) = 0

∂R/∂y = ∂/∂y(-z) = 0

∂Q/∂x = ∂/∂x(y) = 0

∂P/∂z = ∂/∂z(x) = 0

Therefore, the curl of f is:

curl(f) = (0 - 0) i + (0 - 0) j + (0 - 0) k

curl(f) = 0 i + 0 j + 0 k

curl(f) = 0

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Answer:

6  ≥ 4 + x

Step-by-step explanation:

it wouldn't be any of those

Answer:

The dimensions of Scarlett's new rectangle would be 11.25 inches long by 5 inches wide.

To calculate this, we multiply both the length and width of the original rectangle by 125%, which is equivalent to multiplying by 1.25.

This gives us 9 x 1.25 = 11.25 for the new length, and 4 x 1.25 = 5 for the new width.

Answer: 11.25 and 5

Step-by-step explanation:

a 9x4 rectangle dilated by 125% is also saying;

9(1.25) * 4(1.25) = ?

Since you only need the dimensions, I'll leave it here

11.25 and 5

Answer:

xjxjxjzjzjxxjxjxjxjx

The game with 8 minutes of time-outs is 98 minutes long.

What is an algebraic expression?

An algebraic expression is a mathematical phrase that can contain numbers, variables, and operations such as addition, subtraction, multiplication, and division.

In this case, the algebraic expression that represents the length of the soccer game would be:

m = 90 + x

where m represents the total length of the game in minutes, 90 represents the fixed length of the game, and x represents the variable length of time-outs in minutes.

To find the length of the game with 8 minutes of time-outs, we substitute x = 8 into the expression:

m = 90 + 8 = 98

Therefore, the game with 8 minutes of time-outs is 98 minutes long.

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Laplace transform of the given function; n is a positive integer and a is a real constant.

Positive integer and a is a real constant. 12. f(t) = teat os \($F(s) =\frac{1}{(s-a)^2} \Rightarrow L f(t)=F(s)=\frac{1}{(s-a)^2}$\)

\($f(t)=t e^{a t}$\)

\($$\begin{aligned}& \quad \because L[t(t)]=F(s)=\int_0^{\infty} f(t) e^{-s t} d t \\& F(s)=\int_0^{\infty} t e^{a t} e^{-s t} d t \\& F(s)=\int_0^{\infty} t e^{-t(s-a)} \cdot d t \\& \because \int u v d t=u \int v-\int\left[\frac{d(u)}{d t} \times \int v d t\right] d t\end{aligned}$$\)

whir u and v is the function of t.

\($ \therefore F(s)=\left\{\frac{t e^{-f(s-a)}}{-(s-a)}\right\}_0^{\infty}-\int_0^{\infty} \frac{1 \times e^{-t(s-a)}}{-(s-a)} d t $\)

\($F(s) =\frac{-1}{(s-a)}\{0-0\}+\frac{1}{s-a} \int_0^{\infty} e^{-t(s-a)} d t $\)

\($ =0+\frac{1}{(s-a)} \int_0^{\infty} e^{-t(s-a)} d t $\)

\($ =\frac{1}{(s-a)} \times\left\{\frac{e^{-t(s-a)}}{-(s-a)}\right\}_0^{\infty} $\)

\($ =\frac{-1}{(s-a)^2}\left\{e^{-\infty}-e^0\right\} $\)

\($ =\frac{-1}{(s-a)^2}\{0-1\} $\)

\($F(s) =\frac{1}{(s-a)^2} \Rightarrow L f(t)=F(s)=\frac{1}{(s-a)^2}$\)

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x = 8

GDH = 126°

FDH = 54°

FDE = 74°

So we know that CDF is 43 and can write that down. Since DE bisects GDH, we can figure out what GDE and EDH are because they will be equivilent.

8x - 1 = 6x + 15

(add 1 to both sides & subtract 6x from both sides)

2x = 16

(divide both sides by 2)

x = 8

Now that 8 = 8, we can easily figure everything else out.

GDH Solve for one of the two-equation angles, I'm going to chose GDE.

8(8)-1 = 64 - 1 = 63

63 + 63 = 126 = GDH

FDH 160 - 43 - 63 = 54 = FDH

FDE 180 - 63 - 43 = 74 = FDE

(hopefully this is correct! There are more than one way to do it, this is how I did it. Have a nice day!)

Answer:

B. 432 feet

Step-by-step explanation:

36 yards * 3 = 108 feet

108 feet * 12 = 1296 inches

Given:

A car can travel 3.5 km on 30 litres of petrol.

To find:

The distance a car can cover if it has 50 litres of petrol in its tank.

Solution:

We have,

On 30 litres, a car can travel = 3.5 km

On 1 litre, a car can travel = \(\dfrac{3.5}{30}\) km

On 50 litres, a car can travel = \(\dfrac{3.5}{30}\times 50\) km

                                               = \(\dfrac{3.5}{3}\times 5\) km

                                               = \(\dfrac{17.5}{3}\) km

                                              \(\approx 5.83\) km

Therefore, a car can travel 5.83 km on 50 litres.

Step 2.1 code is given in the question. In step 2.2, we have to change the variables, m(t) and c(t) and plot the following equations:m(t) = 3cos(2π*700Hz*t)c(t) = 5cos(2π*11kHz*t)The modified code will be:Amplitude of message signal, Am = 3 Amplitude of carrier signal, Ac = 5 Frequency of message signal, fm = 700Hz Frequency of carrier signal, fc = 11kHz.

The amplitude modulation index is given as, mi = Am/Ac = 3/5 = 0.6The modulated signal is given as,s=Ac*(1+mi*cos(2*pi*fm*t)).*cos(2*pi*fc*t);The plot of the signals can be seen below:From the plots, we can see that the signal, s(t), faithfully represents the original message wave m(t). Hence, the correct option is (a) The signal, s(t), faithfully represents the original message wave m(t).

Step 2.3 requires us to plot the following equations:m(t) = 40cos(2π*300Hz*t)c(t) = 6cos(2π*11kHz*t)The modified code will be:Amplitude of message signal, Am = 40 Amplitude of carrier signal, Ac = 6 Frequency of message signal, fm = 300HzFrequency of carrier signal, fc = 11kHz The amplitude modulation index is given as, mi = Am/Ac = 40/6 > 1The modulated signal is given as,s=Ac*(1+mi*cos(2*pi*fm*t)).*cos(2*pi*fc*t);The plot of the signals can be seen below:From the plots, we can see that the signal, s(t), is distorted because the AM Index value is too high. Hence, the correct option is (a) The signal, s(t), is distorted because the AM Index value is too high.

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A bijection between two sets is constructed below and also proved that it is both one-one and onto.

The phrase "one-to-one function" should not be mistaken with "one-to-one correspondence," which is used to describe bijective functions, in which each element in the codomain is a precise mirror image of a single element in the domain.

Any function that can work with the operations of two algebraic structures is said to be a homomorphism between them. An injective homomorphism is also referred to as a monomorphism for any commonly occurring algebraic structures, particularly vector spaces.

Let t∈T

Then,

t=2k+1, for some k∈Z

Let s=3k

Then,

s∈S and f(s)=2(s/3)+1

=2k+1

=t

Therefore, for every t∈T there exists s∈S such that f(s)=t

Thus, f is onto.

Hence,

f:S  ----> T is a bijective mapping

⇒|S|=|T|

Now, we have to define a mapping f:S ---?T

By f(x)=2(x/3)+1, ∀x∈S

Given,

S={3k|k∈Z} and T={2k+1:k∈Z}

We have to prove:

|S|=|T|

Let x, y∈ S with f(x)=f(y)

Then,

2(x/3)+1=2(y/3)+1

2(x/3)=2(y/3)

(x/3)=(y/3)

x=y

So, f is one-one

Now, we have proved that f is both one-one and onto.

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1 yellow heart = 4

5 yellow hearts = 20

1 pink triangle = 4

5 pink triangles = 20

hope it helps...!!!

The solution to the problem 0.000027 / 0.000009 is 3 × 10⁻¹ in scientific notation.

To solve the problem 0.000027 / 0.000009, we can use scientific notation to make the calculations easier.

Step 1: Convert the numbers to scientific notation.

0.000027 can be written as 2.7 × 10⁻⁵ in scientific notation.
0.000009 can be written as 9 × 10⁻⁶ in scientific notation.

Step 2: Divide the numbers in scientific notation.

Dividing in scientific notation involves dividing the coefficients and subtracting the exponents.
2.7 ÷ 9 = 0.3
10⁻⁵ ÷ 10⁻⁶ = 10⁻⁵⁻⁽⁻⁶⁾ = 10⁻⁵⁺⁶ = 10¹ = 10

Step 3: Write the final answer in simplest form.

Combining the coefficient and the exponent, we get 0.3 × 10.
However, in scientific notation, the coefficient should be between 1 and 10.
So, we can simplify the answer to 3 × 10⁻¹.

The solution to the problem 0.000027 / 0.000009 is 3 × 10⁻¹ in scientific notation.

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Answer:

9

Step-by-step explanation:

Answer:

-11

Step-by-step explanation:

8-2x=30

2x=30-8

2x=22

x=22/-2

x=-11

Answer:

-11

Step-by-step explanation:

8-2x=30

-2x=22

-x=11

x=-11

It will take 3 hours and 53 minutes for the two drivers to be 150 miles apart.

Let d = the distance between the two drivers (in miles).

Let t = the time taken (in hours).

The speed of the first car is 50 mph and the speed of the second car is 40 mph.

We can use the formula d = r * t to solve the problem, where r is the rate of the car.

Since the cars are traveling towards each other, the total rate of the cars is the sum of their individual rates:

r = 50 mph + 40 mph = 90 mph

We know that the initial distance between the cars is 500 miles, and the distance they have to travel to be 150 miles apart is 350 miles.

Therefore, d = 350 miles

We can now plug the values into the formula to solve for t:

350 = 90 * t

t = 350/90 = 3.89 hours

Rounding down, it will take 3 hours and 53 minutes for the two drivers to be 150 miles apart.

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The value of B using Pythagoras theorem is 20 cm.

Pythagoras' theorem states that the square of the hypotenuse in a right- angle triangle is equal to the sum of the square of the two other sides.

Formula:

Make B the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, The value of B using Pythagoras theorem is 20 cm.

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If there are 342 more trees bearing red apples than trees bearing green apples, then the number of trees with green apples are 1336.

The 3/5 of fruit trees are orange trees, then 2/5 of the fruit trees are apple trees.

Let the total number of fruit trees be = x. Then we can write two equations based on the given information that, there are 4515 orange trees and there are 342 more red apple trees than green apple trees,

The equations are :

⇒ 3/5 x = 4515         ...equation(1)

⇒ x - 4515 = (G + 342) + G   ...equation(2)

Where G is the number of trees bearing green apples.

From equation(1), we can solve for x:

x = (4515)/(3/5) = 7525

Substituting this value of "x" into equation(2),

We get,

⇒ 7525 - 4515 = (G + 342) + G

⇒ 3010 = 2G + 342

⇒ 2668 = 2G

⇒ G = 1334.

Therefore, there are 1336 trees with green apples.

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The given question is incomplete, the complete question is

A fruit plantation has two types of fruit trees: apple trees and orange trees. 3/5 of the fruit trees are orange trees. There are 4515 orange trees on the plantation. The apple trees bear apples of two different colors. There are 342 more trees bearing red apples than trees bearing green apples.

How many trees with green apples are there?

The pre-images of 1 is x = 2,  the pre-image of -1 is x = 4.  pre-image of 7 is x = -4. and the pre-image of -5 is x = 8.

We have the mapping f(x) = x - 2x + 3 = -x + 3 defined on the set of real numbers R.

(a) To find the pre-image of 1, we need to solve for x such that f(x) = 1.

f(x) = -x + 3 = 1

-x = -2

x = 2

Therefore, the pre-image of 1 is x = 2.

(b) To find the pre-image of -1, we need to solve for x such that f(x) = -1.

f(x) = -x + 3 = -1

-x = -4

x = 4

Therefore, the pre-image of -1 is x = 4.

(c) To find the pre-image of 7, we need to solve for x such that f(x) = 7.

f(x) = -x + 3 = 7

-x = 4

x = -4

Therefore, the pre-image of 7 is x = -4.

(d) To find the pre-image of -5, we need to solve for x such that f(x) = -5.

f(x) = -x + 3 = -5

-x = -8

x = 8

Therefore, the pre-image of -5 is x = 8.

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Respuesta:

T₁₀ = 1/16

S₁₀ = 63,9375

Explicación paso a paso:

Dado el término de un médico de cabecera como 32, 16, 8, 4 ...

El enésimo término de un médico de cabecera se expresa como;

Tn = arⁿ⁻¹

a es el primer término

r es la razón común

n es el número de términos

Dado

a = 32

r = 16/32 = 8/16 = 4/8 = 1/2

n = 10 (ya que necesitamos el décimo término de la secuencia)

Sustituir en la fórmula;

Tn = arⁿ⁻¹

T₁₀ = 32 (1/2) ¹⁰⁻¹

T₁₀ = 32 (1/2) ⁹

T₁₀ = 32 (1/512)

T₁₀ = 32/512

T₁₀ = 1/16

Por lo tanto, el décimo término de la secuencia es 1/16.

La suma de un GP se expresa como se muestra;

Sₙ = a (1-rⁿ) / 1-r para r <1

S₁₀ = 32 (1- (1/2) ¹⁰) / 1-1 / 2

S₁₀ = 32 (1-1 / 1024) / 1/2

S₁₀ = 64 (1 - 1/1024)

S₁₀ = 64 (1023/1024)

S₁₀ = 63,9375

por lo tanto, la suma de los primeros diez términos es 63,9375

To find the distance between centers of circles W and Y, draw segments WY- and WS-, but lack information on YS, SZ, and angles, resulting in insufficient calculations.

To find the distance between the two centers of circles W and Y, we can use the hint provided.

1. Draw segment WY- connecting the centers of the two circles.
2. Draw segment WS- such that YS + SZ = YZ and WS- is perpendicular to YZ-.

Now, we have formed a right triangle WSY- with WS- as the hypotenuse and YS as one of the legs.

To find the distance between the two centers, we need to calculate the length of the hypotenuse WS-.

Unfortunately, we don't have enough information to determine the lengths of YS and SZ, or the measures of any angles. Therefore, we cannot determine the length of WS- or the distance between the two centers of the circles.

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\(\pi r^{2} =\\3,14*4^{2} \\3,14*16\\=50.24\)

Answer:

(a.) adjacent

Step-by-step explanation:

The angles are next to each other, making them adjacent angles.